What is the side length of a cube with a volume of 0.008 m3?

Answer:2/10 is equal to

any even number has to have a half like 2 4 6 8

2 is half of 4      1 is half of 2      4 is half of 8     and so on

the fractiom is shaded into 2/10

5/10

your wecs                              :0              ;)

Answer:

its false, i did the test

Step-by-step explanation:

Since RSTW is a rhombus, the area of ∆WXT is equal to 18√3 square units.

In Mathematics and Geometry, the length of the hypotenuse (longest side) of a 30°-60°-90° triangle is double (twice) the length of the shorter leg (adjacent side), and the length of the longer leg (opposite side) of a 30°-60°-90° triangle is √3 times the length of the shorter leg (adjacent side):

Hypotenuse = 12 units.

Adjacent side = 12/2 = 6 units.

For the value of x, we have;

Opposite side = √3 × adjacent side

x = √3 × 6

x = 6√3 units.

Now, we can determine the area of triangle WXT;

Area of triangle = 1/2 × base × height

Area of ∆WXT = 1/2 × XT × WX

Area of ∆WXT = 1/2 × 6 × 6√3

Area of ∆WXT = 18√3 square units.

Complete Question:

If RSTW is a rhombus, what is the area of ∆WXT?

Answer:

A) is the answer

Step-by-step explanation:

it worked

Using trigonometry, Claire is approximately 19.42 feet away from Marisa, given their angles of elevation and the hoop's height.

Using trigonometry, we can find the distance between Claire and Marisa:

[tex]\[ \text{Let } h \text{ be the height of the basketball hoop.} \][/tex]

[tex]\[ \text{Distance}_{\text{Claire}} = \frac{h}{\tan(35°)} \][/tex]

[tex]\[ \text{Distance}_{\text{Marisa}} = \frac{h}{\tan(25°)} \][/tex]

[tex]\[ \text{Distance}_{\text{Claire-Marisa}} = \text{Distance}_{\text{Claire}} - \text{Distance}_{\text{Marisa}} \][/tex]

[tex]\[ \text{Distance}_{\text{Claire-Marisa}} = \frac{h}{\tan(35°)} - \frac{h}{\tan(25°)} \][/tex]

[tex]\[ \text{Distance}_{\text{Claire-Marisa}} = h \times \left( \frac{1}{\tan(35°)} - \frac{1}{\tan(25°)} \right) \][/tex]

Given [tex]\( h = 10 \)[/tex] feet:

[tex]\[ \text{Distance}_{\text{Claire-Marisa}} = 10 \times \left( \frac{1}{\tan(35°)} - \frac{1}{\tan(25°)} \right) \][/tex]

[tex]\[ \text{Distance}_{\text{Claire-Marisa}} \approx 19.42 \text{ feet} \][/tex]

So, Claire and Marisa are standing approximately 19.42 feet apart.

Answer:

62.4 hours

Step-by-step explanation:

For P:

Number of hours off on 10 hours of working=0.4

Number of hours on 2080 hours of working=2080/10*0.4

=83.2 hours

For S:  

Number of hours off on 100 hours of working=7

Number of hours on 2080 hours of working=2080/100*7

=145.6 hours

The difference between the vacation hours of P and S is of 62.4 hours. S will get more hours of vacation.  

the difference in vacation hours between the two friends is 62.4 vacation hours.

For company P:

We know that 10 working hours give 0.4 vacation hours. So, to find vacation hours for 2080 hours, we can set up the following proportion:

[tex]\frac{10}{0.4} = \frac{2080}{vacation\ hours\ of 2080\ working\ hours}[/tex]

Solving this we get:

[tex]vacation\ hours\ of\ 2080\ working\ hours = \frac{0.4 \times 2080}{10} = 0.04 \times 2080 = 83.2\ days[/tex]

Now for company S:

We know that 100  working hours give 7 vacation hours. So, to find vacation hours for 2080 hours, we can set up the following proportion:

[tex]\frac{100}{7} = \frac{2080}{vacation\ hours\ of 2080\ working\ hours}[/tex]

Solving this we get:

[tex]vacation\ hours\ of\ 2080\ working\ hours = \frac{7 \times 2080}{100} = 0.07 \times 2080 = 145.6\ days[/tex]

Finally, find the difference in vacation hours:

[tex]Difference = 145.6 - 83.2 = 62.4\ vacation\ hours[/tex]

Therefore, the difference in vacation hours between the two friends is 62.4 vacation hours.

Final answer:

The expression 27x^2z/-3x^2z^6 simplifies to -9/z^5, so the simplified exponent on the variable z is -5.

Explanation:

When simplifying the expression 27x^2z/-3x^2z^6, we divide the coefficients and apply the laws of exponents. This means we divide 27 by -3 and subtract the exponents of like terms with variables of the same base.

27/-3 equals -9, and for the variables we subtract the exponents, for x^2 we have x^2/x^2 which simplifies to x^0 and for z we have z^1/z^6, simplifying to z^(1-6) which is z^-5. However, because negative exponents denote division by that variable to the positive exponent, z^-5 represents 1/z^5.

The final simplified expression is -9/z^5. Thus, the exponent on the variable z when the expression 27x^2z/-3x^2z^6 is completely simplified is -5.

There were [tex]\(38\)[/tex] votes for blue and [tex]\(13\)[/tex] votes for green.

Let's break it down step by step:

1. Votes for Blue:

  Initially, [tex]\(5/8\)[/tex] of the votes were for blue. Let's denote the total number of votes as [tex]\(T\).[/tex]

  So, the number of votes for blue initially is [tex]\(5/8\) of \(T\)[/tex], which is [tex]\((5/8) \times T\)[/tex].

2. Remaining votes after blue:

  After blue votes are accounted for, the remaining votes are [tex]\(T - (5/8) \times T = (3/8) \times T\).[/tex]

3. Votes for Green:

  [tex]\(5/9\)[/tex] of the remaining votes are for green. So, the number of votes for green is [tex]\((5/9) \times (3/8) \times T\)[/tex].

4. Votes for Red:

  The remaining votes after blue and green are accounted for are 48 votes.

To find the solution, we need to set up equations based on the information given:

Equation 1: Votes for blue + Votes for green + Votes for red = Total votes

Equation 2: Votes for green = \(5/9\) of remaining votes

Equation 3: Votes for red = 48

Let's solve these equations:

Equation 1:

[tex]\[\frac{5}{8}T + \frac{5}{9} \times \frac{3}{8}T + 48 = T\][/tex]

Equation 2:

[tex]\[\frac{5}{9} \times \frac{3}{8}T = \frac{15}{72}T = \frac{5}{24}T\][/tex]

Now, let's substitute the value of [tex]\(T\)[/tex] from Equation 3 into Equation 1:

[tex]\[\frac{5}{8} \times \frac{48}{5} + \frac{5}{9} \times \frac{3}{8} \times \frac{48}{5} + 48 = \frac{48}{8} + \frac{15}{24} \times \frac{48}{5} + 48 = 6 + 3 \times 2 + 48 = 60\][/tex]

So, we have [tex]\(T = 60\).[/tex]

Now, let's find the number of votes for blue and green:

Votes for blue:

[tex]\[\frac{5}{8} \times 60 = 37.5\][/tex]

Votes for green:

[tex]\[\frac{5}{24} \times 60 = 12.5\][/tex]

Since we can't have half votes, we round 37.5 to 38 and 12.5 to 13.

So, there were [tex]\(38\)[/tex] votes for blue and [tex]\(13\)[/tex] votes for green.

The correct question is:

5/8 of the votes were for blue. 5/9 of the remaining votes were for green and the remaining 48 votes were for red. How many votes were for blue? How many votes were for green?

Answer:

im sorry i dont get it

Step-by-step explanation:

since y+y=y^2 also they following

Answer:

Volume of rectangular prism = [tex]\frac{65}{4}=16\frac{1}{4}=16.25[/tex]

Step-by-step explanation:

Given :   A rectangular prism has a length of [tex]1\frac{1}{4}[/tex]  centimeters, a width of 4 centimeters, and a height of  [tex]3\frac{1}{4}[/tex] centimeters.

We have to find the volume of prism.

We know,

Volume of rectangular prism = length ×  width × height

Given : Length = [tex]1\frac{1}{4}[/tex] centimeters =  [tex]\frac{5}{4}[/tex]

Width = 4 centimeters, and

height = [tex]3\frac{1}{4}[/tex]  centimeters = [tex]\frac{13}{4}[/tex]

Thus, Volume of rectangular prism = [tex]\frac{5}{4}\times 4\times \frac{13}{4}[/tex]

Simplify, we have,

Volume of rectangular prism = [tex]\frac{65}{4}=16\frac{1}{4}=16.25[/tex]

The volume of the given rectangular prism is 0.143184 cubic meters (m³).

The formula of the volume of a rectangular prism is:

Volume = Length × Width × Height

Given the dimensions:

Length = 114 cm

Width = 4 cm

Height = 314 cm

First, multiply the length and the width:

Length × Width = 114 cm × 4 cm = 456 cm²

Next, multiply this result by the height:

456 cm² × 314 cm = 143,184 cm³

Therefore, the volume of the rectangular prism is:

143,184 cm³

Now, to convert this into cubic meters (m³), note that 1 m³ = 1,000,000 cm³:

Volume in m³ = 143,184 cm³ ÷ 1,000,000 = 0.143184 m³

So, the volume of the prism is 0.143184 m³.

To memorize your timetables, you can use mnemonic techniques, break down the tables into smaller chunks, and practice regularly.

Multiplication tables, also known as timetables, can be challenging to memorize. However, there are several strategies that you can use to make the process easier. One effective method is to create mnemonics, which are memory aids that help you associate numbers with images or phrases. For example, you can associate the number 9 with the shape of a cat's tail, and whenever you see the number 9 in a multiplication problem, you can visualize a cat's tail to help you remember the answer.

Another useful strategy is to break down the tables into smaller, more manageable chunks. Start by memorizing the tables for numbers 0-5, and once you feel comfortable with them, move on to the tables for numbers 6-10. By tackling smaller chunks, you can avoid overwhelming yourself and improve your retention.

Finally, practice regularly and consistently. The more you review the timetables, the more familiar they will become. Consider using online resources, flashcards, or interactive games to make the practice sessions more engaging and enjoyable. Over time, with practice and perseverance, you will gradually memorize your timetables.

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A square can be divided into two right-angled triangles with one line, but it can't be divided into two obtuse triangles because none of the angles in a square is more than 90 degrees.

No, it is not possible for Kateri to divide the square into two obtuse triangles by drawing just one line. An obtuse triangle is a triangle that has an angle greater than 90 degrees. However, a square is made up of four 90-degree angles. Therefore, when a square is divided into two triangles with one line, the maximum degrees any angle in resulting triangles would get is 90, hence they would be right-angled triangles and not obtuse triangles.

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