What is the specific heat of copper if a 105 g sample absorbs 15200 joules and the change in temperature is 377 0C ? (Draw a temperature time graph)

Answer:

7.3 atm

Explanation:

- Use the formula P1V1 = P2V2

- Rearrange formula and then plug in values.

- Hope this helped! Let me know if you need more help or a further explanation.

Answer:

68.6 m

Explanation:

Speed is defined as distance covered per unit time and expressed as

S=d/t

Where d is distance and t is speed.

Making d the subject of the above formula then

d=st

Substituting 343 m/s dor s and 0.200 s for s then

d=343*0.2=68.6 m

Therefore, the distance is 68.6 m

The distance that should be far is your  school from the firehouse is 68.6 m

Here speed refers to the distance covered per unit

Speed = distance / time

So,

Distance = speed * time

d=343*0.2

=68.6 m

Therefore, we can conclude that the distance is 68.6 m

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Answer:

the correct answer would be "C"

Explanation:

Answer:

C

Explanation:

Answer:

c

Explanation:

got it right on edg

Answer: decrease I believe

Explanation:

Answer:

b. is always a weak electrolyte.

Explanation:

Such compounds of low solubility dissociates partly and hence cannot be strong electrolytes

Answer:

See explanation below for answer.

Explanation:

Newton's third law of motion states that, for every action, there is an equal and opposite reaction.

In the scenario presented above, we can see that for every time the child pushes against the ground, the ground also pushes against the child with opposing but equal force, that corresponds to the force that the child has pushed against it with.

This action and reaction is what enables the child to be able to jump the rope.

Therefore, the action is the child pushing against the ground, the reaction is manifested in the jump, as the ground pushes against the child with equal force.

Newton's Third Law of Motion is exemplified by the forces involved when a child jumps rope: the action is the downward force exerted by the child and the reaction is the equal and opposite upward force from the ground, demonstrating that forces always come in action-reaction pairs.

Newton's Third Law of Motion is illustrated when a child jumps rope. The action in this scenario is the force the child exerts downward on the ground through their feet. In response, there is a reaction force, which is the ground pushing the child upward with an equal and opposite force. This interaction allows the child to lift off the ground and demonstrates that for every action, there is an equal and opposite reaction. This principle explains why the child is able to jump into the air; without the ground pushing back, the child would not move upward.

In a broader sense, Newton's third law emphasizes the interaction between two objects and confirms that forces come in pairs; an action force and a reaction force. These forces are always equal in magnitude but opposite in direction. The third law is critical in understanding how motion and forces work together. It applies to all situations involving forces, not just when a child is jumping rope but also in various everyday actions and complex scientific phenomena.

The answer is

(A) radon, neon, calcium

Answer:

600.6L

Explanation:

Step 1:

The balanced equation for the reaction.

3CO + Fe2O3 --> 2Fe + 3CO2

Step 2:

Determination of the number of moles in 1001g of Fe.

This is illustrated below:

Mass of Fe = 1001g

Molar Mass of Fe = 56g/mol

Number of mole =?

Number of mole = Mass/Molar Mass

Number of mole of Fe = 1001/56

Number of mole of Fe = 17.875 mole

Step 3:

Determination of the number of mole of CO that reacted during the process.

This is illustrated below:

3CO + Fe2O3 --> 2Fe + 3CO2

From the balanced equation above,

3 moles of CO produced 2 moles of Fe.

Therefore, Xmol of CO will produce 17.875 moles of Fe i.e

Xmol of CO = (3 x 17.875)/2

Xmol of CO = 26.8125 moles

Step 4

Determination of the volume occupied by 26.8125 moles of CO at stp.

1 mole of a gas occupy 22.4L at stp.

Therefore 26.8125 moles of CO will occupy = 26.8125 x 22.4 = 600.6L

Therefore, 600.6L of CO is needed to produce 1001g of Fe

Answer:

[tex]V=602L[/tex]

Explanation:

Hello,

In this case, for the given chemical reaction:

[tex]3 CO + Fe_2O_3 \rightarrow 2 Fe + 3 CO_2[/tex]

In such a way, for the 1,001 g of iron, we compute the required moles of carbon monoxide by using the 2:3 mole ratio:

[tex]n_{CO}=1,001gFe*\frac{1molFe}{55.845gFe}*\frac{3molCO}{2molFe} \\\\n_{CO}=26.89molCO[/tex]

Finally, we use the ideal gas equation to compute the volute at STP conditions (1atm and 273K):

[tex]V=\frac{nRT}{P}=\frac{26.89mol*0.082\frac{atm*L}{mol*K}*273K}{1atm} \\\\V=602L[/tex]

Best regards.

Answer:

cartilage

Explanation:

The flexible connective tissue shown in blue in the shoulder joint is cartilage, which provides support and cushioning between bones.

The flexible connective tissue in the shoulder joint is primarily cartilage. Cartilage is a tough and resilient tissue that covers the ends of bones where they meet in a joint, providing a smooth surface for low-friction movement. In the shoulder, it is found in the glenoid cavity of the scapula (shoulder blade) and the head of the humerus (upper arm bone).

This articular cartilage naturally reduces friction and cushions the joint during various movements like arm rotation and lifting. While cartilage plays a crucial role in the shoulder joint's flexibility and function, it can be susceptible to wear and tear, leading to conditions like osteoarthritis.

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Answer:

vector

Explanation:

a vector is an organism that transmits a pathogen from organism to organism.

C. H₃O⁺ is a Bronsted Lowry base.

Explanation:

Any substance that accepts hydrogen ions or (H⁺) ions or protons during any chemical reaction is termed as a Bronsted Lowry base.

Here HCl donates a proton so it is not a Bronsted Lowry base.

HCO is also not a Bronsted Lowry base.

H₃O⁺ is a Bronsted Lowry base because it accepts H⁺ ion from one of its reactant.

H₃PO₄ is also not a Bronsted Lowry base.

So option C. H₃O⁺ is a Bronsted Lowry base.

Out of the given options, H3PO4 is a Brønsted-Lowry base because it can accept a proton to form its conjugate acid.

The Brønsted-Lowry theory defines an acid as a substance that donates a proton (H+) and a base as a substance that accepts a proton. Based on this definition, out of the options given, D- H3PO4 is a Brønsted-Lowry base because it can accept a proton to form its conjugate acid. The other options, A- HCl, B- HCO, and C- H3O+, are all Brønsted-Lowry acids because they can donate a proton.

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Answer:

LIthium vegetable oil

D. matter

mass is the amount of matter in an object

volume is the amount of space an object takes up

(they are easy to mix up)

The object, a bowl of mixed fruit, is a mixture because it combines different types of fruit. In chemistry, mixtures are made by combining two or more different materials without causing a chemical reaction. Hence, the distinct properties of each type of fruit in the mixture are maintained.

The object in question here - a bowl of mixed fruit - is considered a mixture. In chemistry, a mixture is a substance made by combining two or more different materials in such a way that no chemical reaction occurs. Therefore, because the bowl contains different types of fruit, it qualifies as a mixture rather than a pure substance.

A pure substance, on the contrary, would consist of a single type of particle. An example of a pure substance would be something like a bowl of pure water, because it only contains water molecules.

So, to put it simply, Jack's bowl of mixed fruit is a mixture because it's composed of different types of fruit that have not chemically reacted with one another. The object demonstrates one of the key attributes of mixtures: its components maintain their individual properties.

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Answer:  

*Neutral 1

* Beneficial 2

*harmful 3

Explanation:

it's actually an answer

A mutation that causes a human to have eleven toes is  neutral, mutation that causes a desert snake to have sand-colored scales is beneficial and mutation that causes a person to have too much sugar in her blood is harmful.

A difference from the typical DNA sequence at a certain gene locus. But even though the phrase is commonly associated with criticism, mutations variation can affect cell activity in ways that are negative, positive, or neutral. The words "variant" and "mutation" are occasionally used interchangeably.

Base substitutions, deletions, and insertions are the three different kinds of DNA mutations.

Thus, a mutation that causes a human to have eleven toes is  neutral, mutation that causes a desert snake to have sand-colored scales is beneficial and mutation that causes a person to have too much sugar in her blood is harmful.

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106.78 J of heat is required by the iron sample.

Explanation:

We have to find the amount of heat required using the formula,

q = m × c × ΔT

where q is the heat absorbed

m is mass of the metal in grams = 4.33 g

c = specific heat of iron = 0.450 J/g °C

ΔT = change in temperature = 79.8° C - 25°C = 54.8° C

Plugin the values in the above formula, we will get,

q = 4.33 g × 0.450 J/g° C × 54.8° C

 = 106.78 J

So 106.78 J of heat is required by the sample of iron.

The heat required to raise the temperature of a 4.33-g sample of iron from 25.0°C to 79.8°C, with a specific heat of 0.450 J/g°C, is 106.074 joules.

To calculate the amount of heat required to raise the temperature of a sample, you can use the formula q = mcΔT, where q is the heat in joules, m is the mass of the substance in grams, c is the specific heat capacity (J/g°C), and ΔT is the change in temperature in degrees Celsius (°C).

For the given 4.33-g sample of iron with a specific heat of 0.450 J/g°C, raising the temperature from 25.0°C to 79.8°C, the heat can be calculated as follows:

q = (4.33 g) × (0.450 J/g°C) × (79.8°C - 25.0°C)

q = (4.33 g) × (0.450 J/g°C) × (54.8°C)

q = 106.074 J

The heat required to raise the temperature of the iron sample is therefore 106.074 joules.

Answer:

8.11g

Explanation:

Given parameters:

Molarity of aqueous solution = 0.3M

total volume  = 0.15L

Molecular weight of glucose  = 180.6g/mol

Unknown:

Mass of glucose needed in the solution = ?

Solution:

To solve this problem, we need to understand molarity.

Molarity is the number of moles of solute in a given volume of solution. In this problem, the solute here is the glucose and the solvent is water.

      Molarity  = [tex]\frac{number of moles of solute}{volume of solution}[/tex]

A solution is made up of solute and solvent.

   now, let us solve for the number of moles of the solute which is glucose;

   Number of moles of glucose  = molarity x volume of solution;

                                                      = 0.3 x 0.15

                                                      = 0.045mole

Now to find the mass of glucose;

        mass of glucose  = number of moles x molar mass

             input the parameters;

         Mass of glucose  = 0.045  x 180.16 = 8.11g

To determine the amount of glucose needed for the solution, we calculate the number of moles of glucose in the solution and then use the molecular weight of glucose to convert this to grams. Thus, 8.107 g of glucose is necessary for the solution.

To figure out how much glucose we need, we'll have to use molarity, which measures the concentration of a solution. The molarity is defined as the number of moles of solute (in this case, glucose) per liter of solution.

Therefore, we first find the number of moles in the 0.150 L solution by multiplying 0.300 M by 0.150 L, which gives us 0.045 moles of glucose. Then, we multiply this by the molecular weight of glucose, which is 180.16 g/mol. Therefore, to create the solution, we'd need 8.107 g of glucose.

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Answer:

Data:

mass of solute: 35g of NaCl

m.mass of solute: 58g/mol

volume of solution: 501mL

Molarity=?

Explanation:

501ml = 0.5dm3

M= g of solute/m.mass of solute*vol of solution

M= 35/58*0.5

M=1.20

Answer: -241.82 kj

Explanation:

answer: -241.82 then 483.64

Explanation:

Answer:

First one is : London dispersion

Second one is: London dispersion

Third One is : dipole-dipole

Fourth one is : induced dipole

Explanation:

Answer:

Molecular Weight of gas = 44.418 grams/mole

Explanation:

PV = nRT = (mass/f.wt.)RT => f.wt. = mass·R·T/P·V

mass = 0.435g

R = 0.08206·L·atm/mol·K

T = 100°C = 372K

P = (765/760)Atm = 1.01Atm

V = 297ml = 0.297L

f.wt. = (0.435g)(0.08206L·Atm/mol·K)(372K)/(1.01Atm)(0.297L) = 44.418 grams/mole

0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.

Explanation:

Data given:

Initial volume of NaCl, V1 = 20 ml

initial molarity of the NaCl solution = 2M

Final volume of the NaCl solution = 250 ml

final molarity of the diluted solution = ?

from the information given, the formula for dilution used is:

Minitial Vinitial = Mfinal Vfinal

putting the values in the rearranged equation:

V final = [tex]\frac{Minitial Vinitial }{Vfinal}[/tex]

V final = [tex]\frac{20 X 2}{250}[/tex]

Mfinal = 0.16 M

Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.

The concept of molarity dilution is applied to find the concentration of a solution after dilution. This is done using the formula M1V1=M2V2. The final diluted concentration of the NaCl solution is determined to be 0.16 M.

This question relates to the concept of molarity dilution, which in chemistry is given by the equation M1V1=M2V2. Here:

Plugging our given values into the equation, we have (2.00 M)(20.0 mL)=(M2)(250.0 mL). To solve for M2, we divide both sides by 250.0 mL, obtaining M2 = (2.00 M)(20.0 mL) / 250.0 mL = 0.16 M.

Therefore, the concentration of the solution after dilution is 0.16 M.

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Answer : The final volume will be, 84.4 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 760 torr

[tex]P_2[/tex] = final pressure = 120 kPa = 900 torr   (1 kPa = 7.5 torr)

[tex]V_1[/tex] = initial volume = 100 mL

[tex]V_2[/tex] = final volume = ?

Now put all the given values in the above equation, we get:

[tex]760torr\times 100mL=900torr\times V_2[/tex]

[tex]V_2=84.4mL[/tex]

Therefore, the final volume will be, 84.4 mL

Answer:

taste buds

Explanation:

Answer:2.27 J

Explanation:Because that’s what it was in ck12 so ion got no explanation

Answer3

:

Explanation:

Answer:

Manganese

Explanation:

Using rules you will find the location on 3d^5 because you subtract one level when in the d block

Final answer:

Manganese (Mn) has the electron configuration [Ar]4s² 3d⁵. It is a transition metal in the fourth period and seventh group of the periodic table.

Explanation:

The element that has the electron configuration of [Ar]4s² 3d⁵ is manganese (Mn). This configuration indicates that the element has two electrons in the 4s orbital and five electrons in the 3d orbital, following argon's stable noble gas electron configuration. Manganese is located in the fourth period and in the seventh group of the transition metals in the periodic table.

Answer:

35.0 kPa

Explanation:

As pressure decreases, the volume of a gas increases at a given temperature., so since the balloon got bigger, the new pressure must be less than 103kPa

Assuming the temperature does not change, use Boyles Law

P1V1 = P2V2

(103kPa) (1750L) = P2 (5150L)

P2 = (103)(1750) / 5150

The pressure of the gas is inversely proportional to the volume of the gas. The pressure of the balloon at 5150 L is 35.0 kPa.

Boyle's Law states the relationship between the initial pressure and volume to the final pressure and the volume. It is given as,

[tex]\rm P_{1}V_{1} = \rm P_{2}V_{2}[/tex]

Given,

The initial pressure of the weather balloon = 10.3 kPa

The initial volume of the weather balloon = 1750 L

The final pressure of the weather balloon =?

The final volume of the weather balloon = 5150 L

Substituting values in the above equation:

[tex]\begin{aligned} \rm P_{2} &= \rm \dfrac{P_{1}V_{1}}{V_{2}}\\\\&= \dfrac{103 \times 1750}{5150}\\\\&= 35 \;\rm kPa\end{aligned}[/tex]

Therefore, the final pressure decreases with an increase in volume.

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2. a. Approximately 0.0208 L of the 1.20 M AgNO3 solution is needed to precipitate all the chloride ions.

b. Approximately 2.70 g of AgCl should precipitate.

To find out how much AgNO3 solution is needed to precipitate all the chloride ions, we need to determine the amount of chloride ions present in the HCl solution and then use stoichiometry to find the amount of AgNO3 required.

Part a: Volume of AgNO3 solution needed

1. Calculate moles of Cl⁻ ions in the HCl solution:

Given:

- Volume of HCl solution = 250.0 mL = 0.250 L

- Concentration of HCl solution = 0.100 M

[tex]\[ \text{Moles of } \text{Cl⁻} = \text{Concentration} \times \text{Volume} \][/tex]

[tex]\[ \text{Moles of } \text{Cl⁻} = 0.100 \, \text{mol/L} \times 0.250 \, \text{L} = 0.025 \, \text{mol} \][/tex]

2. Use stoichiometry to find the moles of AgNO3 required:

From the balanced chemical equation:

[tex]\[ \text{AgNO3(aq)} + \text{HCl(aq)} \rightarrow \text{AgCl(s)} + \text{HNO3(aq)} \][/tex]

It's a 1:1 molar ratio between AgCl and Cl⁻ ions. So, moles of AgNO3 required = moles of Cl⁻ ions.

[tex]\[ \text{Moles of AgNO3} = 0.025 \, \text{mol} \][/tex]

3. Calculate the volume of 1.20 M AgNO3 solution:

Given:

- Concentration of AgNO3 solution = 1.20 M

[tex]\[ \text{Moles of AgNO3} = \text{Concentration} \times \text{Volume} \][/tex]

[tex]\[ 0.025 \, \text{mol} = 1.20 \, \text{mol/L} \times \text{Volume} \][/tex]

[tex]\[ \text{Volume} = \frac{0.025 \, \text{mol}}{1.20 \, \text{mol/L}} \][/tex]

[tex]\[ \text{Volume} ≈ 0.0208 \, \text{L} \][/tex]

Part b: Mass of AgCl precipitated

1. Calculate moles of AgCl precipitated:

From the stoichiometry, the moles of AgCl precipitated will be equal to the moles of Cl⁻ ions, which is 0.025 mol.

2. Calculate the mass of AgCl precipitated:

Given:

- Molar mass of AgCl = [tex]\( 107.87 \, \text{g/mol} \) (atomic masses: Ag = \( 107.87 \, \text{g/mol} \), Cl = \( 35.45 \, \text{g/mol} \))[/tex]

[tex]\[ \text{Mass of AgCl} = \text{Moles of AgCl} \times \text{Molar mass of AgCl} \][/tex]

[tex]\[ \text{Mass of AgCl} = 0.025 \, \text{mol} \times 107.87 \, \text{g/mol} \][/tex]

[tex]\[ \text{Mass of AgCl} \approx 2.70 \, \text{g} \][/tex]