What is the value of 60 tens?

Answers

Answer 1

[tex] {10}^{6} [/tex]
Answer 2
It would  be 600.

You would multiply 60 times 10.

Hope it helped!:)



Related Questions

Is the figure on the right congruent to the sample figure? Explain.

Answers

Yes it is. This can be proved with all the basic congruence theorems, like SSSS, SASS, SSAS, ASAS, and much more

what is a solution to the equation 6t=114

Answers

The solution to the equation 6t=144 is 19.

Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.

Answers

Fermat's little theorem states that
[tex]a^p[/tex]≡a mod p

If we divide both sides by a, then
[tex]a^{p-1}[/tex]≡1 mod p
=>
[tex]a^{17-1}[/tex]≡1 mod 17
[tex]a^{16}[/tex]≡1 mod 17

Rewrite
[tex]a^{1000000}[/tex] mod 17  as
[tex]=(a^{16})^{62500}[/tex] mod 17
and apply Fermat's little theorem
[tex]=(1)^{62500}[/tex] mod 17
=>
[tex]=(1)[/tex] mod 17

So we conclude that
[tex]a^{1000000}[/tex]≡1 mod 17

By applying Fermat's Little Theorem, we can find the least positive residue of [tex]2^{1000000[/tex] modulo 17. Using the repeated squaring method, we calculate that [tex]2^{16[/tex] is congruent to 1 modulo 17. Therefore, [tex]2^{1000000[/tex] is also congruent to 1 modulo 17.

Fermat's Little Theorem states that if p is a prime number and a is any positive integer that is not divisible by p, then a raised to the power of p-1 is congruent to 1 modulo p. In this case, we need to find the least positive residue of 2 raised to the power of 1000000 modulo 17.

First, we need to find the value of 2 raised to the power of 16 modulo 17, since 17 is a prime number. Using the repeated squaring method, we can calculate:

[tex]2^2[/tex] = 4 (mod 17)

[tex]2^4[/tex] = [tex](2^2)^2[/tex] = [tex]4^2[/tex] = 16 (mod 17)

[tex]2^8[/tex] = [tex](2^4)^2[/tex] = [tex]16^2[/tex] = 1 (mod 17)

[tex]2^{16[/tex] = [tex](2^8)^2[/tex] = [tex]1^2[/tex] = 1 (mod 17)

Now, we can find the value of [tex]2^{1000000[/tex] modulo 17 using the fact that [tex]2^{16[/tex] is congruent to 1 modulo 17:

[tex]2^{1000000[/tex] = [tex](2^{16})^{62500[/tex] x [tex]2^0[/tex] = [tex]1^{62500[/tex] x 1 = 1 (mod 17)

Therefore, the least positive residue of [tex]2^{1000000[/tex] modulo 17 is 1.

Find the orbital period (in years) of an asteroid whose average distance from the sun is 10 au.

Answers

The orbital period (in years) of an asteroid whose average distance from the sun is 10 AU is 212314723 years.

What is Orbital period ?

Orbital period of a body is the the time taken by a body to cover one circular path around the central object under whose influence it is following circular path.

Given is a asteroid moving around the sun.

Mean distance from the Sun [x] = 10 AU = 1.496 x 10¹² m.

Assume that the time period of the asteroid is T.

The formula to calculate the orbital period around the sun is -

T²/ R³ = 4π²/GM[s]

Where -

R is the mean distance from sun.

G is the universal Gravitation constant.

M[s] is the mass of Sun.

Substituting the values, we get -

T² = (1.496 x 10¹² x 4 x 3.14 x 3.14)/(6.673 x 10⁻¹¹ x 1.98 x 10³⁰)

T² = (59 x 10¹²)/(13.2 x 10⁻¹⁹)

T² = 4.45 x 10 x 10³⁰

T² = 44.5 x 10³⁰

T = √44.5 x √10³⁰

T = 6.7 x 10¹⁵ seconds

In years, the time period will be -

T = 212314723 years (approx.)

Therefore, the orbital period (in years) of an asteroid whose average distance from the sun is 10 AU is 212314723 years.

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If a particular utility burned 5.40 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide was emitted?

Answers

For this case what you must do is the following rule of three:
 5.40 million tons ----> 100%
 x -------------------------> 2%
 Clearing x we have:
 x = (2/100) * (5400000)
 x = 108000
 Answer:
 108000 tons of sulfur dioxide was emitted

Can you guys help me figure this out ?

Answers

we have that

1 the side opposite ∡L is NM-------------- > is true

2 the side opposite ∡N is ML-------------- > is true

3 the hypotenuse is NM------------> is false
because the hypotenuse is the side NL

4 the hypotenuse is the side NL---------- > is true

5 the side adjacent ∡L is NM-------------> is false
because the sides adjacent are ML and NL

6 the side adjacent ∡N is ML-------------> is false
because the sides adjacent are NM and NL

A certain car costs $11,595 before taxes are added. Taxes are $860 and license tags cost $95. What is the overall tax rate (to the nearest tenth)?



0.8%


7.4%


8.2%


12.1%

Answers

For this case the total taxes are given by:
 [tex]860 + 95 = 955 [/tex]
 Then, we can make the following rule of three:
 11595 ---------> 100%
 955 ------------> x
 From here, we clear the value of x.
 We have then:
 [tex]x = (955/11595) * (100) [/tex]
 x = 8.2%
 Answer:
 
The overall tax rate (to the nearest tenth) is:
 
8.2%

Answer:

8.2%

Step-by-step explanation:

o-ware

8x-2=46 what is this

Answers

Add 2: 8x=48
Divide 8: x=6
The answer is x=6
If you need me to explain message me
Hope this helps

Evaluate these quantities.
a.−17 mod 2
b.144 mod 7
c.−101 mod 13
d.199 mod 19

Answers

Modular arithmetic is used to find the remainder when dividing the first number by the second number you can divide the term then multiply the  (or use the mod function of a graphing calculator with the first term first in the ordered pair and the second in the second term.

-17/2 = 8.5   2*.5 =1
a. 1
-144/7 = -20 5/7 . 4/7 *7 = 4
b. 4
-101/13 =
c. 3
199/19=
d.9

Final answer:

The modulo operator determines the remainder of a division operation. For the given expressions, the results are a. 1, b. 4, c. 2, d. 6

Explanation:

The question is asking to evaluate several expressions using the modulo operation. Modulo is a mathematical operation that finds the remainder or signed remainder of a division, after one number is divided by another (called the modulus). Here's how we can solve each:

a. −17 mod 2 = 1 (Because when -17 is divided by 2, the remainder is 1) b. 144 mod 7 = 4 (Because when 144 is divided by 7, the remainder is 4) c. −101 mod 13 = 2 (Because when -101 is divided by 13, the remainder is 2) d. 199 mod 19 = 6 (Because when 199 is divided by 19, remainder is 6)

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Which is the next term in this pattern ?
January, February, April, July,___
-August
-November
-October
-December

Answers

the answer is october
November 
would be correct rate me brainliest

If a ball is dropped near the surface of the earth, then the distance it falls is directly proportional to the square of the time it has fallen. A ball is dropped over the edge of a vertical cliff and falls 39.2 meters in two seconds. Determine the distance (in meters) the ball would have dropped in 3.5 seconds.

Answers

ABOUT 143.2 meters im pretty sure

Answer: 120 m

Explanation:

1) That the distance fallen is directly proportion of the square of the time, means:

distance = k * t^2 => k = distance / t^2

2) Use it for the two set of data given:

a)  39.2 m, 2 s => k = 39.2 m / (2 s)^2

b) x, 3.5 s => k = x / (3.5 s)^2

3) Equal the two expressions for k:

39.2 m / (2s)^2 = x / (3.5s)^2

=> x = 30.2 m * (3,5s)^2 / (2s)^2 = 39.2m * 12.25 / 4 = 120.05m = 120 m

How can I solve this please:
Solve for q: (4q - 6n)/(3m) = f

Answers

(4q-6n) /(3m) =f
4q-6n=f(3m)
4q=3fm+6n
q=(3fm+6n)/4




General Idea:

Solving for a variable means getting that variable by itself by UNDOING whatever is done to it. We need to perform reverse operation to UNDO.

Applying the concept:

[tex] \frac{4q-6n}{3m}=f\\ \\ To \; undo \; 3m\; in\; the \; denominator \; 3m, \; MULTIPLY \; 3m\; on\; both\; sides [/tex]

[tex] 3m \times \frac{4q-6n}{3m}=f \times 3m\\ \\ 4q-6n=3mf\\Add \; 6n \; both\; sides\\ \\ 4q-6n+6n=3mf+6n\\ Combine \; like\; terms\\ \\ 4q=3mf+6n\\Divide \; 4\; on\; both\; sides\\ \\ \frac{4q}{4} =\frac{3mf+6n}{4} \\ Simplify\; fraction\; in\; left\; sides\\ \\ q=\frac{3mf+6n}{4} [/tex]

Conclusion:

[tex] Solving \; the \; equation \; \frac{4q-6n}{3m}=f \; for q, \; we get...\\ \\q=\frac{3mf+6n}{4} [/tex]

A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 20 miles per gallon of gas. During one particular week, the two cars went a combined total of 2025 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of the two cars that week?

Answers

Hello,

Let's assume a the number of miles done by the 1 vehicule (35 mi/gal)
2025-a is the number of miles done by the 2nd vehicule (20 mi/gal)

[tex] \dfrac{a}{35} + \dfrac{2025-a}{20} =75\\\\ 4a+(2025-a)*7=10500\\\\ -3a=10500-7*2025\\\\ 3a=-3675\\\\ a=1225(miles)\\\\ [/tex]

The gas consumption of the 1 vehicule is 1225/35=35 (gallons)
The gas consumption of the 2 vehicule is 75-35=40 (gallons)


are you able to classify polygons by their sides and angles

Answers

Many of these shapes, or polygons, can be described as flat closed figures with 3 or more sides. Polygons are two-dimensional objects, not solids. Polygons are classified and described by the number of sides, the kind of angles, and whether any of the sides are the same length (or congruent).

Polygons can be classified by their sides and angles using formulas and definitions like regular polygons with equal sides and angles.

Polygons can be classified by their sides and angles. A regular polygon has equal sides and equal angles, such as an equilateral triangle or a square. The sum of interior angles in any polygon can be calculated using the formula 180 * (n - 2) degrees where n is the number of sides.

based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why ΔLMN ≈ΔOPQ?

Check all that apply.

A. LL
B. LA
C. SAS
D. HL
E. ASA
F. AAS

Answers

I believe the answer would be LA and AAS

HL congruence theorems or postulates used to prove ΔLMN ≈ΔOPQ.

What is Congruency?

Congruent figures have sides that are the same length and angles that are the same measurement. In other words, congruent figures are those in which one figure superimposes another.

If two line segments have the same length, they are said to be congruent. If two angles have the same measure, they are said to be congruent. If the matching sides and angles of two triangles are equal, they are said to be congruent.

We have two Triangles as ΔLMN and ΔOPQ

As, per the figure both triangles are Right angles Triangle.

Also, LM = OP

MN = PQ

LN = OQ

and, the hypotenuse of both triangles also Equal.

Thus, both triangle are Congruent using HL theorem.

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An American car company has designed a new high fuel efficiency vehicle that is rated at 55 miles per gallon. The company plans to export the car to Europe and must advertise the fuel efficiency in SI units. What is the fuel usage rate in kilometers per liter?

Answers

The fuel usage would be approx. 23 km. per liter. The exact number would be 23.3829 km. per liter.

5(×-4)+3×-9×=6-(2×+5)+8×

Answers

5x-20+3x-9x=6-2x-5+x

-x-20=1+6x

-x-6x=1+20

-7x=21

X=-3
Assuming the × signs are actually x's-

5(x - 4) + 3x - 9x = 6 - (2x + 5) + 8x

Apply the distributive property.

5(x - 4) + 3x - 9x = 6 - (2x + 5) + 8x
5x - 20 + 3x - 9x = 6 - 2x + 5 + 8x

Combine like terms.

5x - 20 + 3x - 9x = 6 - 2x + 5 + 8x
              -1x - 20 = 1 + 6x

Add 20 to both sides.

-1x - 20 = 1 + 6x
       -1x = 21 + 6x

Subtract 6x from both sides.

-1x = 21 + 6x
-7x = 21

Divide both sides by -7.

-7x = 21
   x = -3

Answer:
x = -3

I hope this answers your question!

On average how many words can 400 turtles type in 400 minutes?

Answers

I think the answer would be 4000. Since everything else i half of the original equasion. I don't normaly answer math question but I saw the problem and needed to know why this existed. Hope this helps. (Wait can turtles even type... Or read?)

What is the solution to the system of equations graphed below

Answers

The point where the lines intersect is the point that satisfies both equations.

It is (1, 5), selection C.

Answer:

Option C is correct

(1, 5)

Step-by-step explanation:

A system of equations contains two or more than two linear equations that divide two or more unknowns.

To find a solution for the system of equations,

we must find a value from the graph that is true for all equations in the given system.

We know that:

If the graphs of the equations intersect,

then there is one solution that is true for both equations.

Given the graph.

There are two lines

Equation of Blue line : y = -x+6

Equation of Red line = y = 2x+3

Since, the graph of two lines y = -x+6 and  y = 2x+3 intersects which means there is one solution that satisfies the both equation.

Therefore, the solution to the system of equations graphed is, (1, 5)

What is the volume of the figure below if a = 3.9 units, b = 5.7 units, and c = 3 units?

A.157.95 cubic units
B.351.351 cubic units
C.124.605 cubic units
D.113.49 cubic units

Answers

3.9+3.9 = 7.8

7.8 * 3.9 * 3 = 91.26

5.7 * 3.9 * 3 = 66.69

66.69 + 91.26 = 157.95

 Answer is A

A basketball player makes 40% of his shots from the free throw line. suppose that each of his shots can be considered independent and that he throws 3 shots. let x = the number of shots that he makes. what is the probability that he makes 2 shots or less?

Answers

The probability of making 2 or fewer shots is 0.936.

_____
P(≤2) = 1-P(3) = 1-(0.4)^3 = 1 -0.064 = 0.936

Using the binomial distribution, it is found that there is a 0.936 = 93.6% probability that he makes 2 shots or less.

-------------------

For each throw, there are only two possible outcomes. Either the player makes it, or he misses it. The probability of making a throw is independent of any other throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.

In this question:

The player makes 40% of the shots, thus [tex]p = 0.4[/tex]3 shots, thus [tex]n = 3[/tex]

The probability of making 2 or less is the probability that he does not make all of them, that is:

[tex]P(X < 3) = 1 - P(X = 3)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{3,3}.(0.4)^{3}.(0.6)^{0} = 0.064[/tex]

[tex]P(X < 3) = 1 - P(X = 3) = 1 - 0.064 = 0.936[/tex]

0.936 = 93.6% probability that he makes 2 shots or less.

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14m+m+17m−9m if m=30

Answers

Answer:

  690

Step-by-step explanation:

Put 30 where m is in the expression and do the arithmetic. Or, simpify the expression first, then do the same.

  14·30 +30 +17·30 -9·30 = 420 +30 +510 -270 = 690

Simplifying first, you have ...

  14m +m +17m -9m = m(14 +1 +17 -9) = 23m

  23·30 = 690

Final answer:

To solve the equation 14m + m + 17m - 9m when m=30, substitute the value of m in the equation and follow order or operations. The result is 960.

Explanation:

To solve for the given problem involving the variable m, simply substitute the value of m into the equation. The equation given is 14m + m + 17m - 9m. Substituting 30 for m in the equation gives us: 14(30) + 30 + 17(30) - 9(30). To solve this, use the order of operations principle, which states that multiplication and division should be performed before addition and subtraction.

First, perform the multiplication: 420 + 30 + 510 - 270. Next, add and subtract from left to right: 960. Thus, if m = 30, then 14m + m + 17m - 9m = 960.

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Please help and explain questions 20-22

Answers

Hello!

The formula for circumference is [tex] 2\pi r[/tex] and the formula for area of a circle is [tex] \pi r^{2} [/tex]. Armed with these formulas, we can begin to find the circumferences and areas of the circles.

20. 
C = [tex]2 \pi r [/tex]
C = [tex]2 \pi (6.5)[/tex]
C = [tex]13 \pi [/tex]
C = 13(3.14)
C = 40.8

A = [tex] \pi r^{2} [/tex]
A = [tex] \pi (6.5)^{2} [/tex]
A = [tex] \pi (42.25)[/tex]
A = 132.7

The circumference of the circle is 40.8 in and the area of the circle is 132.7 in².

21.
[Since we are given the diameter for this problem, to find the circumference, we no longer need to multiply the radius by 2 as in [tex]2 \pi r[/tex] because the diameter is the radius × 2. For [tex] \pi r^{2} [/tex] we do need to divide the diameter by 2.]

C = [tex]15.7 \pi [/tex]
C = 49.3

A = [tex] \pi r^{2} [/tex]
A = [tex] \pi (7.85)^{2} [/tex]
A = [tex]61.62 \pi [/tex]
A = 193.5

The circumference of the circle is 49.3 in and the area of the circle is 193.5 in².

And that is all there is to it. I hope this helps you! (:

Find the sum of the first 30 terms of the sequence. a_(n)=4n+1

Answers

we know that
a(n)=4n+1
To find the sum of the first n terms of an arithmetic series
use the formula
Sn=n(a1 + an)/2
a1--------------> is the first term
an--------------> is the last term
n--------------- > is the number of terms
we have that
a1------------> 4*(1)+1=5
a30----------> 4*(30)+1=121
n------------- > 30
S30=30*(5 + 121)/2=1890

the answer is 1890


Steven has 14 steel balls of equal weight. If he puts 9 of them in one pan of a pan balance and the rest along with a weight of 20 grams in the other pan, the pans balance each other. What is the weight of one steel ball?

Answers

9x = 5x+20

4x = 20

x = 20/4 = 5

 each one weighs 5 grams

Answer:

Step-by-step explanation:

What is the area of this triangle? A=bh2

A 24 in²
B 30 in²
C 48 in²
D 96 in²

Answers

Area of triangles is half the base times height. This formula would be (1/2)(8)(6). So the answer is 24.

Answer:

a 24

Step-by-step explanation:

bonnie had 6 bags of 6 gel pens. she wanted to give the same number of gel pens to 9 friends. how many gel pens did each friend get?

Answers

Each friend got 4 pens.
Hope that helps!
Each friend gets 4 pens ! You would do 6 times 6 which is 36 then divided by 9 which equals 4

write the equation of the line with the following chracteristics
perpendicular to y=1/2x+3 through (9,1)

Answers

If the line is perpendicular to y = 1/2x + 3, the slope will be the opposite sign of the reciprocal.
1/2 → opposite sign is (-) reciprocal is (2) → slope of ⊥ = -2

Now let's find the b → by substituting the values for y, m, and x in y = mx + b
1 = -2(9) + b
1 = -18 + b
19 = b

The equation is y = -2x + 19
or 2x + y = 19

NEED HELP ASAP:
Suppose you pay $24 for a pair of shoes that has been discounted 20%. What is the original price of the shoes? Show how you identify what you are looking for, set up an equation, arrive at your answer, and check your work. Then clearly state your answer.

Answers

The discount rate is 20% so 100% - 20% = 80% of the original price is the final price (before taxes)

x = original price before discount
y = price after discount (before taxes)

y = 80% of x
y = 0.80*x
24 = 0.80*x
24/0.80 = x
30 = x
x = 30

The original price of the shoes was $30


The heights of fully grown English oak (also known as Brown oak) trees are normally distributed with a mean of 95 feet and a standard deviation of 10 feet. What proportion of fully grown English oak trees are taller than 110 feet?

Answers

Standard normal distribution formula is
   z = (x - μ) / σ
μ = 95
σ =10
   z = (110-95) / 10
      = 1.5
the probability z>1.5 using the standardization table = 0.0668
P(z > 1.5) = 0.0668

Final answer:

Using the z-score calculation and the standard normal distribution, approximately 6.68% of fully grown English oak trees are taller than 110 feet.

Explanation:

To find the proportion of fully grown English oak trees taller than 110 feet, given that the heights are normally distributed with a mean of 95 feet and a standard deviation of 10 feet, we first calculate the z-score for a height of 110 feet. The z-score is calculated using the formula: z = (X - μ) / σ, where X is the value of interest (110 feet), μ is the mean (95 feet), and σ is the standard deviation (10 feet).

By substituting the given values: z = (110 - 95) / 10 = 1.5. This z-score represents the number of standard deviations 110 feet is above the mean. To find the proportion of trees taller than 110 feet, we consult the standard normal distribution table or use a calculator that provides the area to the right of the z-score, which corresponds to the proportion we seek.

The standard normal distribution table or a calculator shows that the proportion of the area under the curve to the right of a z-score of 1.5 is approximately 0.0668.

Thus, about 6.68% of fully grown English oak trees are taller than 110 feet.

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