What is the value of x?



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Answer:

11 * 17 = 187.

Step-by-step explanation:

11 * 14 = 154

11 * 15 = 165

11 * 16 =  176

So we have the series 154, 165, 176  which has a common difference of 11.

so the next line is 11*17 = 176 + 11 = 187.

Answer: There are 22.5 films were profitable.

Step-by-step explanation:

Since we have given that

Number of total films = 40

Percentage of comedies = 60%

Number of comedies is given by

[tex]0.6\times 40\\\\=24[/tex]

Percentage of horror films = 40%

Number of horror films is given by

[tex]0.4\times 40\\\\=16[/tex]

Percentage of comedies were profitable = 75%

Number of profitable comedies is given by

[tex]0.75\times 24=18[/tex]

Percentage of horror were unprofitable = 75%

Percentage of horror were profitable = 25%

Number of profitable horror films is given by

[tex]0.25\times 18\\\\=4.5[/tex]

So, Total number of profitable films were

[tex]18+4.5=22.5[/tex]

Hence, there are 22.5 films were profitable.

Answer:

time period (t)  is 2.25 years

Step-by-step explanation:

Given data in question

amount (a) = $94000

principal (p) = $78870

rate (r) = 7.8 % = 0.078

to find out

time period (t)  

solution

we know that continuous compound interest formula i.e.

amount = principal [tex]e^{rt}[/tex]   ...............1

we will put all value a, p and r  in equation 1

amount = principal [tex]e^{rt}[/tex]

94000 = 78870 [tex]e^{0.078t}[/tex]

[tex]e^{0.078t}[/tex] = 94000 / 78870

now we take ln both side

ln  [tex]e^{0.078t}[/tex]  ln (94000 / 78870)

0.078 t = ln 1.19183466

0.078 t = 0.175494

t = 0.175494 /0.078  

t = 2.249923  

so time period (t)  is 2.25 years

In this complex interest problem, by organizing and substitifying the values into the continuous compound interest formula, we obtain t = ln(1.1911) / 0.078, which approximately equals 2.81 years when rounded to two decimal places.

The continuous compound interest formula is A = Pe^(rt), where P is the principal amount, r is the interest rate, t is the time in years, and A is the amount of money accumulated after n years, including interest.

In this case, we have A = $94,000, P = $78,870, r = 7.8% = 0.078, and we need to solve for t. Therefore, let's substitute the given values into the formula to solve for t:

$94,000 = $78,870 * e^(0.078t),

Solving this equation for 't' involves isolating 't' on one side. First, divide both sides by $78,870:

e^(0.078t) = $94,000 / $78,870 = 1.1911.

Take the natural logarithm (ln) of both sides:

0.078t = ln(1.1911),

Finally, divide both sides by 0.078 to solve for 't':

t = ln(1.1911) / 0.078.

With a calculator, this results in approximately t = 2.81 years when rounded to two decimal places.

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To find out how much is invested in each bond, set up a system of equations and solve for the values of x and y.

To find out how much is invested in each bond, we can set up a system of equations.

Let x be the amount invested in the bond paying 14% interest, and y be the amount invested in the bond paying 12% interest.

We know that the retiree receives $5120 in interest each year. So, we have the equation:

x(0.14) + y(0.12) = 5120

Since the total amount invested is $40,000, we can also write the equation:

x + y = 40000

We can now solve this system of equations using any method, such as substitution or elimination, to find the values of x and y.

[tex]y'+2y=2e^x\Longrightarrow y'=2e^x-2y[/tex]

If [tex]f'(x)=g(x)[/tex] then [tex]y=\int{g(x)dx}[/tex]

So we extract,

[tex]y=\int{2e^x-2x}dx[/tex]

Which becomes,

[tex]y=2e^x-x^2+C[/tex]

Hope this helps.

r3t40

Answer:

Yes , S is a basis for [tex]P_3[/tex].

Step-by-step explanation:

Given

S=[tex]\left\{4t-12,5+t^3,5+3t,-3t^2+\frac{2}{3}\righ\}[/tex].

We can make a matrix

Let A=[tex]\begin{bmatrix}-12&4&0&0\\5&0&0&1\\5&3&0&0\\\frac{2}{3}&0&-3&0\end{bmatrix}[/tex]

All rows and columns are linearly indepedent and S span [tex]P_3[/tex].Hence, S is a basis of [tex]P_3[/tex]

Linearly independent means any row or any column should not combination of any rows or columns.

Because  a subset of V with n elements is a basis if and only if it is linearly independent.

Basis:- If B is a subset  of a vector space V over a field F .B is basis of V if satisfied the following conditions:

1.The elements of B are linearly independent.

2.Every element of vector V spanned by the elements of B.

Answer:

answer 1

Step-by-step explanation:

Since there's only 1 value in the 90-99 groups it is either 1 or 3.

Furthermore, there are only 2 values starting with 10.

This only fits with answer 1

The answer is A.

A stem plot shows every number with the tens place and above being on the left side while the ones place is on the right side.

For example,

9 is in the tens place while 4 is in the ones place. So, this would look like:

9 | 4

There is only one number with a "9" in the tens place and there is only two numbers with "10" in the tens place. This only sastisfys the first option.

Best of Luck!

Answer:

The company use 0 ounces of chicken and 100 ounces of grain in each bag of dog food in order to minimize cost.

Step-by-step explanation:

Let x be the number of ounces of chicken

let y be the number of ounces of grains

We are given that Chicken has 10 grams of protein and 5 grams of fat per ounce.

Chicken has protein in 1 ounce = 10

Chicken has protein in x ounces = 10x

Chicken has fat in 1 ounce = 5

Chicken has fat in x ounces = 5x

We are also given that grain has 2 grams of protein and 2 grams of fat per ounce

Grain has protein in 1 ounce = 2

Grain has protein in y ounces = 2y

Grain has fat in 1 ounce = 2

Grain has fat in y ounces =2y

Now we are given that . A bag of dog food must contain at least 200 grams of protein and at least 150 grams of fat.

So, equation becomes:

[tex]10x+2y\geq 200[/tex] ---A

[tex]5x+2y\geq 150[/tex]  ---B

Since x and y represent the ounces .

So, [tex]x\geq 0[/tex] ---C and [tex]y\geq 0[/tex] ----D

Plot A ,B ,C and D on the graph

Refer the attached graph so , the corner points are (0,100),(10,50) and (30,0)

We are also given that chicken costs 10 cents per ounce and grain costs 1 cent per ounce

So, Cost function becomes : [tex]c=10x+y[/tex]

At(0,100)

[tex]c=10x+y[/tex]

[tex]c=10(0)+100[/tex]

[tex]c=100[/tex]

At(10,50)

[tex]c=10x+y[/tex]

[tex]c=10(10)+50[/tex]

[tex]c=150[/tex]

At(30,0)

[tex]c=10x+y[/tex]

[tex]c=10(30)+0[/tex]

[tex]c=300[/tex]

Minimum cost is 100 cents at (0,100)

So,  the company use 0 ounces of chicken and 100 ounces of grain in each bag of dog food in order to minimize cost.

[tex]\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k[/tex]

Divergence is easier to compute:

[tex]\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}[/tex]

[tex]\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}[/tex]

Curl is a bit more tedious. Denote by [tex]D_t[/tex] the differential operator, namely the derivative with respect to the variable [tex]t[/tex]. Then

[tex]\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}[/tex]

[tex]\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k[/tex]

[tex]\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k[/tex]

To find the curl and divergence of a given vector field, you first identify the vector's components. The curl is calculated using a determinant and the divergence is obtained by computing a dot product of the gradient operator with the vector field.

In order to find the curl and the divergence of the vector field F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k, we first need to identify its components. The components are as follows: e^(xy) sin z, and y tan^−1(x/z).  

The Curl of a vector field F in three dimensions is typically denoted as ∇ × F or curl F, where '∇' is the del operator. In Cartesian coordinates, this can be calculated using a determinant that involves the unit vectors î, ĵ, and k, the gradient operator, and the components of F.  

The Divergence of a vector field F in three dimensions, typically denoted as ∇ . F or div F, is obtained by computing a dot product of the gradient operator with the vector field. This can also be calculated using Cartesian coordinates.

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This ODE is separable:

[tex]yy'-\cot t=0\implies y\,\mathrm dy=\cot t\,\mathrm dt[/tex]

Integrate both sides to get

[tex]\dfrac12y^2=\ln|\sin t|+C[/tex]

Given that [tex]y\left(\frac\pi2\right)=-1[/tex], we get

[tex]\dfrac12(-1)^2=\ln|\sin\dfrac\pi2\right|+C\implies C=\dfrac12[/tex]

Then

[tex]\dfrac12y^2=\ln|\sin t|+\dfrac12[/tex]

[tex]y^2=2\ln|\sin t|+1[/tex]

[tex]y^2=\ln\sin^2t+1[/tex]

[tex]\implies\boxed{y(t)=\pm\sqrt{\ln\sin^2t+1}[/tex]

Answer:

\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]

Step-by-step explanation:

Given is a matrix 3x3 as

[tex]\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right][/tex]

|A| =2 hence inverse exists.

Cofactors are 16   20   7

                        6     8    3

                         2     2    1

Hence inverse =

[tex]\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right][/tex]

Answer:

  m∠XQZ = 72°

Step-by-step explanation:

We presume the "if ..." condition is intended to mean that ray QY lies between rays QX and QZ. Then by angle addition, you get

  ∠XQY + ∠YQZ = ∠XQZ

  (4a +8) + (28) = (8a)

  36 = 4a . . . . . . . . . . . . . subtract 4a

  72 = 8a = ∠XQZ . . . . multiply by 2

Answer:

(x-9)^2 + (y+3)^2 = 8^2

or

(x-9)^2 + (y+3)^2 = 64

Step-by-step explanation:

An equation for a circle can be written as

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x-9)^2 + (y- -3)^2 = 8^2

(x-9)^2 + (y+3)^2 = 8^2

or

(x-9)^2 + (y+3)^2 = 64

The car's velocity at time [tex]t[/tex] is

[tex]v(t)=16\dfrac{\rm m}{\rm s}+\displaystyle\int_0^t\left(\left(-0.50\frac{\rm m}{\mathrm s^2}\right)u\right)\,\mathrm du=16\dfrac{\rm m}{\rm s}+\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2[/tex]

It comes to rest at

[tex]v(t)=0\implies16\dfrac{\rm m}{\rm s}=\left(0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=8.0\,\mathrm s[/tex]

Its velocity over this period is positive, so that the total distance the car travels is

[tex]\displaystyle\int_0^{8.0}v(t)\,\mathrm dt=\left(16\dfrac{\rm m}{\rm s}\right)(8.0\,\mathrm s)+\frac13\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)(8.0\,\mathrm s)^3=\boxed{85\,\mathrm m}[/tex]

so the answer is D.

The car takes 32 seconds to stop from its initial velocity of 16m/s. During this period, the car has traveled a distance of 256 meters, which is not an option in the given choices.

The initial velocity of the car is given as 16 m/s and the acceleration is given as -0.5t m/s^2. We know that the car slows down until it stops, which means its final velocity is 0 m/s.

Firstly, we need to find out the time it takes for the car to stop. That could be calculated with the equation 'v = u + at', where v is the final velocity, u is the initial velocity, a is the acceleration and t is time. Since we know v = 0 m/s, u = 16 m/s and a = -0.5t m/s^2, we could set the equation to find the time to be '0 = 16 - 0.5t'. Solving this equation gives t=32 seconds.

Second, to find the distance traveled by the car during this time, we use the equation 's = ut + 0.5at^2', where s is the distance, u is the initial velocity, a is the acceleration and t is time. Substituting the known values into this equation, we get 's = 16(32) + 0.5*(-0.5*32)*(32)', which simplifies to s = 512 - 256 = 256 meters. Hence, the answer is not in the options given.

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Answer:

3 cm

Step-by-step explanation:

The perimeter of the square is 24 cm, so the side length is 6 cm.

I assume B is the point between A and C where the tangent line intersects the circle.  If so, B is the midpoint of AC, so it is half the length.  Therefore, BC = 3 cm.

The length of line segment BC is 3 cm.

A square is a polygon with four sides , all the sides of the square are equal.

It is given that the tangents of the circle are forming a square ,

The perimeter of the square is 24 cm.

the length of line segment BC = ?

The perimeter of the square is 4a

where a is the side of the square.

Substituting the values

24 = 4 * a

a = 6 cm

B is the mid point of the tangent length and therefore

BC = 6 /2 = 3 cm

Therefore , the length of line segment BC is 3 cm.

The missing image is attached with the answer.

To known more about Square

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Answer:

  1,556,675,366,400

Step-by-step explanation:

There are 37 possible characters, of which 8 can be chosen. Order matters, so the number is ...

  37P8 = 1,556,675,366,400

_____

This number includes 84,144,614,400 strings in which the space character is either first or last. Such strings may be ruled invalid because they are indistinguishable from 7-character strings.

_____

nPk = n!/(n-k)! . . . . the number of permutations of n things taken k at a time

The 37 allowed characters are the 26 letters of the alphabet, 10 digits, and 1 space character.

Answer:

The required interval is (26.23 , 27.37)

Step-by-step explanation:

The mean is = 26.8

The standard deviation is = 7.42

n = 654

At 95% confidence interval, the z score is 1.96

To find the desired interval we will calculate as:

[tex]26.8+1.96(\frac{7.42}{\sqrt{654} } )[/tex]

And [tex]26.8-1.96(\frac{7.42}{\sqrt{654} } )[/tex]

[tex]26.8+0.57[/tex] and [tex]26.8-0.57[/tex]

= 27.37 and 26.23

So, the required interval is (26.23 , 27.37)

The 95% confidence interval for the mean BMI of all young women, given a sample of 654 women with a mean BMI of 26.8 and a standard deviation of 7.42 is approximately (26.23, 27.37). This is calculated by finding the standard error and then using that to find the interval around the sample mean which covers 95% of the probable values for the population mean.

The question is asking you to calculate the 95% confidence interval for the mean BMI of all young women, given a sample size of 654 women with a mean BMI of 26.8 and a standard deviation of 7.42.

In order to do this, we first need to calculate the standard error, which is the standard deviation divided by the square root of the number of observations. This gives us 7.42 divided by the square root of 654, or about 0.29032.

The 95% confidence interval is calculated by taking the mean and adding and subtracting the standard error multiplied by the relevant z-score for a 95% confidence interval, which is 1.96 (from the standard normal distribution table). So we take 26.8 plus and minus 1.96 times 0.29032, giving us a 95% confidence interval of approximately (26.23, 27.37).

So, we can say with 95% confidence that the mean BMI for all young women is between 26.23 and 27.37.

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Answer:

The length of the original rectangle is 14 meters and the width of the original rectangle is 12 meters

Step-by-step explanation:

Let

l ----> the length of the original rectangle

w ----> the width of the original rectangle

we know that

[tex]l=2w-10[/tex] ----> equation A

[tex]196=(w+2)^{2}[/tex] ----> area of a square

Solve for w

square root both sides

[tex](w+2)=(+/-)14[/tex]

[tex]w=14=(+/-)14-2[/tex]

[tex]w=14=14-2=12\ m[/tex]

[tex]w=14=-14-2=16\ m[/tex] -----> this solution not make sense

so

[tex]w=12\ m[/tex]

Find the value of L

[tex]l=2(12)-10=14\ m[/tex]

therefore

The length of the original rectangle is 14 meters and the width is 12 meters

Final answer:

The dimensions of the original rectangle are 12 meters (width) and 14 meters (length).

Explanation:

To find the dimensions of the original rectangle, let's first set up an equation.

Let the width of the rectangle be x meters.

The length of the rectangle is given as 10 m less than twice its width, so the length is (2x - 10) meters.

When 2 m are added to the width, the resulting figure is a square with an area of 196 m2.

The side length of a square with area A is √A, so the side length of the square is √196 = 14 meters.

Since adding 2 m to the width creates a square with side length 14 meters, we have:

x + 2 = 14

Subtracting 2 from both sides gives:

x = 12

Therefore, the dimensions of the original rectangle are 12 meters (width) and

(2*12 - 10)

= 14 meters (length).

Answer:

A. 6.0

Step-by-step explanation:

We have been given that the the inside diameter of the part on the paper is 1.50 inches.

We have been given that scale is 4:1 for actual size to drawing side.

[tex]\text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=\frac{4}{1}[/tex]

Upon substituting 1.50 in our given proportion, we will get:

[tex]\frac{\text{Actual size}}{1.50\text{ inches}}=\frac{4}{1}[/tex]

[tex]\frac{\text{Actual size}}{1.50\text{inches}}\times 1.50\text{ inches}=\frac{4}{1}\times 1.50\text{ inches}[/tex]

[tex]\text{Actual size}=4\times 1.50\text{ inches}[/tex]

[tex]\text{Actual size}=6.0\text{ inches}[/tex]

Therefore, the actual size is 6.0 inches and option A is the correct choice.

Try this suggested solution.

Answer:

His total gross pay for the week is $588.25.

Step-by-step explanation:

Consider the provided information.

Jarry has a salary of $43 per day and he worked for 4 days.

Thus, the salary of 4 days is:

4 × $43= $172

The average tips is 18% of his total gross food orders.

Last week he had total food orders of $2,312.5. Therefore, the total tips he received is:

[tex]2312.5 \times(\frac{18}{100})[/tex]

[tex]2312.5 \times(0.18)[/tex]

[tex]416.25[/tex]

Total tips he received is $416.25.

His total gross pay for the week = The salary of 4 days + Total tips he received.

His total gross pay for the week = $172 + $416.25

His total gross pay for the week = $588.25

Hence, his total gross pay for the week is $588.25.

Final answer:

Jerry King's total gross pay for the week, combining his salary and the tips he made on his food orders, is $588.25, after calculating an 18% tip on his total orders and adding his daily salary for the 4 days he worked.

Explanation:

The question asks us to calculate the total gross pay for Jerry King, a server who earns both a salary and tips based on his food orders. First, we need to calculate Jerry's earnings from tips. He averages an 18% tip on his total gross food orders. Since his total food orders for the week were $2,312.5, we calculate the tips as follows:

Tips = (Total Food Orders) × (Tip Percentage)
= $2,312.5 × 18%
= $2,312.5 × 0.18
= $416.25 (rounded to the nearest cent)

Next, we calculate Jerry's salary for the week. Jerry works 4 days per week at a salary of $43 per day:

Salary = (Daily Salary) × (Number of Days Worked)
= $43 × 4
= $172

Finally, to find Jerry's total gross pay for the week, we add the salary and the tips:

Total Gross Pay = Salary + Tips
= $172 + $416.25
= $588.25 (rounded to the nearest cent)

Therefore, Jerry King's total gross pay for the week is $588.25.

Answer:

see below

Step-by-step explanation:

A horizontal line has the same y value and is a constant y value

y = -5

A vertical line has the same x value and is a constant x value

x = -6

A vertical line is a line where all of the [tex]x[/tex] values are the same. In this case, [tex]\boxed{x=-6}[/tex], so that is the equation of the line.

A horizontal line is a line where all of the [tex]y[/tex] values are the same.  Here, [tex]\boxed{y=-5}[/tex], so that is the second line.

Final answer:

The parametric equations that model the problem situation in this case are x(t) = v0x * t,  [tex]y(t) = v0y * t - (1/2) * g * t^2,[/tex], and vy(t) = v0y - g * t.

Explanation:

To find parametric equations that model the problem situation, we need to consider the horizontal and vertical components of the motion separately.

Horizontal Component:

The horizontal velocity remains constant throughout the motion. Therefore, the horizontal position can be given by the equation:

x(t) = v0x * t

where x(t) is the horizontal position at time t and v0x is the initial horizontal velocity.

Vertical Component:

The vertical position depends on the initial velocity, acceleration due to gravity, and time. We can use the following equations:

[tex]y(t) = v0y * t - (1/2) * g * t^2,[/tex]

vy(t) = v0y - g * t

where y(t) is the vertical position at time t, v0y is the initial vertical velocity, g is the acceleration due to gravity (approximately 32 ft/s2), and vy(t) is the vertical velocity at time t.

Answer:  0.6731

Step-by-step explanation:

Given : Mean : [tex]\mu = 40,000\text{ miles}[/tex]

Standard deviation : [tex]\sigma = 5,000\text{ miles}[/tex]

The formula to calculate the z-score :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x=36,000

[tex]z=\dfrac{36000-40000}{5000}=-0.8[/tex]

For x=46,000

[tex]z=\dfrac{46000-40000}{5000}=1.2[/tex]

The P-value : [tex]P(-0.8<z<1.2)=P(z<1.2)-P(z<-0.8)[/tex]

[tex]=0.8849303-0.2118554=0.6730749\approx0.6731[/tex]

Hence, the probability that a randomly selected set of tires will have a life of 36,000 to 46,000 miles =0.6731

the probability that a randomly selected set of tires will have a life of 36,000 to 46,000 miles is 0.6730 (rounded to four decimal places).

The life expectancy of a particular brand of tire is normally distributed with a mean of 40,000 miles and a standard deviation of 5,000 miles. To find the probability that a randomly selected set of tires will have a life of 36,000 to 46,000 miles, we can calculate the z-scores for 36,000 and 46,000 and then use the standard normal distribution to find the probabilities for these z-scores.

To compute the z-scores:

We then look up the corresponding probabilities for these z-scores in a standard normal distribution table or use a calculator with normal distribution functions. The probability corresponding to z=-0.8 is approximately 0.2119, and the probability corresponding to z=1.2 is approximately 0.8849. The probability of the tire's life being between 36,000 and 46,000 is the difference: 0.8849 - 0.2119 = 0.6730.

Therefore, the probability that a randomly selected set of tires will have a life of 36,000 to 46,000 miles is 0.6730 (rounded to four decimal places).

Answer: Option (d) is correct.

Step-by-step explanation:

Regression analysis can be used to determine if there is any linear relationship exists between the two quantitative variables.

There are one dependent variable and one or more than one independent variable in a single regression equation.

After running a simple regression, we get to know the relationship between the dependent variable and explanatory variable.

Various statistical software are used for running regression like STATA, E- Views, SPSS, etc.  

Regression analysis is used primarily to determine if a linear relationship exists between two quantitative variables. While it can identify relationships between variables, it does not imply causation. It does not establish a relationship between two categorical variables or if the difference in the population means may be zero.

Regression analysis is a statistical methodology often used in mathematics and related fields. Primarily, it is used to determine if a linear relationship exists between two quantitative variables.

For example, you could use regression analysis to see if there is a linear relationship between the age of a car (quantitative variable) and the distance it can travel on a tank of gas (another quantitative variable).

It's important to note however that while regression analysis can identify a correlation or relationship between variables, it does not necessarily imply causation, or a cause-and-effect relationship. There could be other related variables causing the effect.

For your options, regression analysis can't be used to determine if a linear relationship exists between two categorical variables or if the difference in the population means may be zero.

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6 divided by 4 is 1.5.

1.5 times 20 is 30

it would cost michelle $30 to buy 20 pieces of cookies

Answer:

$30

Step-by-step explanation:

4pcs = $6

20pcs = x

Cross multiplying, we have

x = (20pcs * $6)/4pcs

= $120/4 = $30

Answer:

Hyperbola.

Step-by-step explanation:

We start from the function:

[tex]x^{2} +y^{2} -z^{2} =36[/tex]

We may get the traces if we cut the surface in planes x=k. This is equivalent to replace x for k:

[tex]k^{2}+y^{2} -z^{2}=36\\y^{2} -z^{2}=36-k^{2}[/tex]

The last equation is the equation of an hyperbola, which varies its characteristics depending on K (the plane cut).

When x=k or y=k is substituted into the equation of the quadric surface x² + y² - z² = 36, the resulting traces are hyperbolas. These traces represent intersections of planes parallel to coordinate planes with the quadric surface.

The trace of a quadric surface can be found by substituting a constant into the equation for one of the variables. The given quadric surface equation is x² + y² - z² = 36. If we substitute x = k into the equation, we get k² + y² - z² = 36. This is an equation of a hyperbola.

Similarly, for the case when y = k, we substitute this into our original equation to get x² + k² - z² = 36. This also represents a hyperbola.

The traces given by these equations represent the intersection of planes parallel to the coordinate planes and the quadric surface. In these particular cases, the traces are hyperbolas.

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The answer is:

Center: (4,3)

Radius: 3 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

[tex]x^2+y^2-8x-6y+16=0[/tex]

So, solving we have:

[tex]x^2-8x+y^2-6y=-16[/tex]

[tex](x^2-8x+(\frac{8}{2})^{2} )+(y^2-6y+(\frac{6}{2})^{2})=-16+(\frac{8}{2})^{2}+(\frac{6}{2})^{2}\\\\(x^2-8x+16)+(y^2-6y+9)=-16+16+9\\\\(x^2-4)+(y^2-3)=9[/tex]

Now, we have that:

[tex]h=4\\k=3\\r=\sqrt{9}=3[/tex]

So,

Center: (4,3)

Radius: 3 units.

Have a nice day!

Note: I have attached a picture for better understanding.

By completing the square on the given equation, the center of the circle is found to be (4, 3) and the radius is 3.

This process will transform the equation into a standard form of a circle equation, which is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius of the circle.

To start, we can rewrite the original equation by adding and subtracting the necessary constants inside the square terms:

Therefore, after completing the square, we get (x - 4)^2 + (y - 3)^2 = 1. Hence, the center of the circle is (4, 3) and the radius is 3.

Answer:

a.[tex]y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}[/tex]

b[tex]y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x[/tex]

Step-by-step explanation:

1.[tex]y''-4y'+4y=6x e^{2x}[/tex]

Auxillary equation

[tex]D^2-4D+ 4=0[/tex]

[tex](D-2)(D-2)=0[/tex]

D=2,2

Then complementary solution =[tex] C_1e^{2x}+C_2xe^{2x}[/tex]

Particular solution [tex]=\frac{6 xe^{2x}}{(D-2)^2}[/tex]

D is replace by D+2 then we get

P.I=[tex]\frac{6xe^{2x}}{0}[/tex]

P.I=[tex]\frac{e^{ax}}{D+a} \cdot .V[/tex]

where V is a function of x

P.I=[tex]\frac}x^3e^{2x}[/tex]

By integrating two times

Hence, the general solution

[tex]y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}[/tex]

b.y''+9y=5 cos x-7 sin x

Auxillary equation

[tex]D^2+9=0[/tex]

D=[tex]\pm 3i[/tex]

[tex]C.F=c_1 cos 3x+ c_2sin 3x[/tex]

P.I=[tex]\frac{5 cos x-7 sin x}{D^2+9}[/tex]

P.I=[tex]\frac{sin ax}{D^2+bD +C}[/tex]

Then  D square is replace by -a square

[tex] D^2 [/tex] is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

[tex]y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x[/tex]