Answer:
4
Step-by-step explanation:
Question- what is two plus two
Answer- 2+2=4
If ST≅SV and m∠SUT=68°, what is m∠TUV?
Answer:
136
Step-by-step explanation:
Take 68 x 2 since the side lengths are equal.
Given the properties of isosceles triangle, where congruent sides have equal opposite angles, and that the given angle ∠SUT = 68°, it implies that ∠TUV also equals 68°.
Explanation:The question involves the principles of geometry, specifically the properties of angles and congruent lines. Given that ST≅SV and m∠SUT = 68°, it means that these two line segments are equal in length and that the angle of SUT is 68 degrees.
Since ST and SV are congruent in an isosceles triangle, the angles opposite these sides are equal. Hence, the measure of ∠SUT and ∠TUV are equal. We know m∠SUT = 68°, so therefore, m∠TUV = 68°.
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| 3. Find the Area of the triangle.
8.6 yd
10.9 yd
Given:
The base of the triangle = 8.6 yd
The height of the triangle = 10.9 yd
To find the area of the triangle.
Formula
The area of a triangle with b as base and h as height is
[tex]A=\frac{1}{2}bh[/tex]
Now,
Taking, b= 8.6 and h = 10.9 we get,
[tex]A=\frac{1}{2}(8.6)(10.9)[/tex] sq yd
or, [tex]A= 46.87[/tex] sq yd
Hence,
The area of the given triangle is 46.87 sq yd.
Answer:
46.87 yd^2
Step-by-step explanation:
The area of the triangle is given by
A = 1/2 bh
A = 1/2 (8.6)(10.9)
A =46.87 yd^2
What is the Pythagorean Therom
Answer:
its a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides.
Formula:
[tex]a^{2} + b^{2} = c^{2}[/tex]
19. EL CONDENADO A MUERTE. En los tiempos de la antigüedad la gracia o el castigo se dejaban frecuentemente al azar. Así, éste es el caso de un reo al que un sultán decidió que se salvase o muriese sacando al azar una papeleta de entre dos posibles: una con la sentencia "muerte", la otra con la palabra "vida", indicando gracia. Lo malo es que el Gran Visir, que deseaba que el acusado muriese, hizo que en las dos papeletas se escribiese la palabra "muerte". ¿Cómo se las arregló el reo, enterado de la trama del Gran Visir, para estar seguro de salvarse? Al reo no le estaba permitido hablar y descubrir así el enredo del Visir.
Answer:
English plz
Step-by -step explanation:
what dose this say
El condenado sobrevivió al destruir una de las 'papeletas de muerte' sin leerla, y utilizar la ley del Sultán a su favor para afirmar que su 'papeleta de muerte' destruida era la 'papeleta de vida'.
Explanation:El reo aseguró su supervivencia actuando de manera astuta. Sabiendo que ambas papeletas tenían la palabra muerte, decidió escoger una y, sin leerla, la destruyó por completo. Entonces solicitó que se leyera la papeleta restante, si en la papeleta restante dice muerte, entonces es obvio que la papeleta que destruyó debía tener la sentencia de vida, ya que según el Sultán, el Gran Visir hizo dos papeletas diferentes. De esta manera, aunque el Gran Visir deseaba que obtuviera la sentencia de muerte, el reo se salvó por su astucia sin necesidad de revelar el complot del Visir.
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What’s the first step to solve the equation x-6=14
To solve the equation x - 6 = 14, the first step is to isolate the variable 'x'. You do this by adding 6 to both sides of the equation, which results in x = 14 + 6. Therefore, 'x' equals 20.
Explanation:The subject of this question is Mathematics, and it is focusing on solving a basic algebraic equation: x - 6 = 14. When you are asked to solve an equation, you're figuring out what numbers you can replace the variable with to make the equation true. In this case, the variable is 'x', and your goal is to find what number 'x' stands for. The first step to solve the equation is to isolate 'x'. This means you want 'x' to stand alone on one side of the equation. To accomplish this, you need to perform the same operation on both sides of the equation to maintain equality. Here, you would add 6 to both sides of the equation (opposite of subtracting 6), which simplifies to: x = 14 + 6. So, 'x' equals 20.
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equation of the line through (-10,3) and (-8 -8)
Answer:
(-8-3)/(-8+10)= -11/2
y - 3 = -11/2(x+10)
y-3=-11/2x-55
y=-11/2x-52
Step-by-step explanation:
Sunhee had four plastic shapes a square, a circle, and a pentagon in how many ways can she line up the four shapes of the circle cannot be next to the square
There are 12 valid arrangements for Sunhee to line up the four plastic shapes so that the circle is not next to the square.
In how many ways can Sunhee line up four plastic shapes (a square, a circle, and a pentagon) if the circle cannot be next to the square?
To solve this problem, we can count the total number of ways to arrange the shapes and then subtract the cases where the circle is next to the square.
1. Total ways to arrange the shapes:
There are 4 shapes, so there are 4! = 24 ways to arrange them.2. Cases where the circle is next to the square:Consider the circle and square together as one unit. We now have 3 units (circle and square, pentagon, and an empty spot).The circle and square can be arranged within this unit in 2! = 2 ways.The total number of ways the four shapes can be arranged with the circle next to the square is 2! × 3! = 12 ways.3. Subtract the cases where the circle is next to the square from the total:24 total ways - 12 ways = 12 ways to line up the shapes with the circle not next to the square.A common design for a mountain cabin is an A-frame
cabin. A-frame cabins are fairly easy to construct and
the steeply pitched roof line is perfect for helping snow
fall to the ground during heavy winters. Determine the
angle ( between the two sides of the roof of an A-frame
cabin if the sides are both 26 feet long and the base of
the cabin is 24 feet wide.
Answer:
54.98 degrees.
Step-by-step explanation:
In the diagram, the sides of the A-Frame are lengths AB and BC. The width of the cabin is length BC. We are to determine the measure of the angle at B, i.e. the angle between the two sides of the roof.
Using Cosine Rule:
[tex]b^2=a^2+c^2-2acCos B\\Cos B=\dfrac{b^2-a^2-c^2}{-2ac} \\B=arcCos(\dfrac{b^2-a^2-c^2}{-2ac} )\\a=26, b=24, c=26\\B=arcCos(\dfrac{24^2-26^2-26^2}{-2*26*26} )\\=arcCos 0.5739\\B=54.98^0[/tex]
The angle in between the two sides of the roof is 54.98 degrees.
To find the angle between the two sides of the roof of an A-frame cabin, we can use trigonometry and the Pythagorean theorem. The angle is approximately 22.33°.
Explanation:To determine the angle between the two sides of the roof of an A-frame cabin, we can use trigonometry. Since the sides of the roof are both 26 feet long and the base of the cabin is 24 feet wide, we can consider the A-frame cabin as a right triangle. The roof line forms the hypotenuse of the triangle, and the sides of the triangle represent the rafters of the A-frame roof.
Using the Pythagorean theorem, we can find the height of the triangle (which is the distance from the base of the cabin to the point where the roof meets): h^2 = 26^2 - 12^2 = 676 - 144 = 532.
Taking the square root of both sides gives us h ≈ 23.07 feet.
Now, we can determine the angle by using trigonometric functions.
The sine function relates the opposite side (the height) to the hypotenuse (the roof line). So, sin(θ) = h / 26, where θ is the angle we want to find. Solving for θ gives us θ ≈ 22.33°.
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a circle with the radius of 1 cm sits inside a 11cm by 12cm rectangle.What is the area of the shaded region?
Answer:
128.86 square cm
Step-by-step explanation:
Area of shaded region = Area of rectangle - Area of circle
[tex] = 11 \times 12 - \pi {r}^{2} \\ = 132 - 3.14 \times {1}^{2} \\ = 132 - 3.14 \\ = 128.86 \: {cm}^{2} \\ [/tex]
Answer:
128.86
Step-by-step explanation:
CAN SOMEONE HELP ME PLEASEEEplease and thank u
Answer:
C,H,I..............
Bill Connors, a quality control manager at a Menlo Park Electronics Company, knows his company has been making surge protectors with a 10% rate of defective units. Bill decides to test 20 randomly selected surge protectors to see how many are defective. Let X represent the mumber f defective unit nth . Asminnpndenc answer the folowing :a) What type of probability distribution does X have (include the value(s) of any parameters)? b) What is the probability that more than one surge protector is defective? c) What is the probability that the number of defective surge protectors is between three and five? d) How many surge protectors would you expect to be defective? e) Find the standard deviation X.
Answer:
a) Binomial distribution, with n=20 and p=0.10.
b) P(x>1) = 0.6082
c) P(3≤X≤5) = 0.3118
d) E(X) = 2
e) σ=1.34
Step-by-step explanation:
a) As we have a constant "defective" rate for each unit, and we take a random sample of fixed size, the appropiate distribution to model this variable X is the binomial distribution.
The parameters of the binomial distribution for X are n=20 and p=0.10.
[tex]X\sim B(0.10,20)[/tex]
b) The probability of k defective surge protectors is calculated as:
[tex]P(x=k) = \binom{n}{k} p^{k}q^{n-k}[/tex]
In this case, we want to know the probability that more than one unit is defective: P(x>1). This can be calculated as:
[tex]P(x>1)=1-(P(0)+P(1))\\\\\\P(x=0) = \binom{20}{0} p^{0}q^{20}=1*1*0.1216=0.1216\\\\P(x=1) = \binom{20}{1} p^{1}q^{19}=20*0.1*0.1351=0.2702\\\\\\ P(x>1)=1-(0.1216+0.2702)=1-0.3918=0.6082[/tex]
c) We have to calculate the probability that the number of defective surge protectors is between three and five: P(3≤X≤5).
[tex]P(3\leq X\leq 5)=P(3)+P(4)+P(5)\\\\\\P(x=3) = \binom{20}{3} p^{3}q^{17}=1140*0.001*0.1668=0.1901\\\\P(x=4) = \binom{20}{4} p^{4}q^{16}=4845*0.0001*0.1853=0.0898\\\\P(x=5) = \binom{20}{5} p^{5}q^{15}=15504*0*0.2059=0.0319\\\\\\P(3\leq X\leq 5)=P(3)+P(4)+P(5)=0.1901+0.0898+0.0319=0.3118[/tex]
d) The expected number of defective surge protectors can be calculated from the mean of the binomial distribution:
[tex]E(X)=\mu_B=np=20*0.10=2[/tex]
e) The standard deviation of this binomial distribution is:
[tex]\sigma=\sqrt{np(1-p)}=\sqrt{20*0.1*0.9}=\sqrt{1.8}=1.34[/tex]
Find product (7m+8)(4m +1)
Step-by-step explanation:
[tex](7m + 8)(4m + 1) \\ = 7m(4m + 1) + 8(4m + 1) \\ = 28 {m}^{2} + 7m + 32m + 8 \\ \purple { \bold{= 28 {m}^{2} + 39m + 8}}[/tex]
write an equation for the amount of money, m that will be collected if b boxes of chocolate are sold.
Answer:
m = b(t)
t= the price per box
Answer:
m = ?b
Step-by-step explanation:
m = total
b = number of boxes sold
? = price of chocolate
6x + 3y - 9 when x = 6, y = 9
Answer:
54
Step-by-step explanation:
6(6)+3(9)-9
=54
Answer:
54
Step-by-step explanation:
First, since it's given the x and y values, you need to plug them in.
6(6) + 3(9) - 9
36 + 27 - 9
63 - 9
54
Lola is using a one-sample t-t- test for a population mean, µμ , to test the null hypothesis, H0:µ=40 mg/dLH0:μ=40 mg/dL , against the alternative hypothesis, H1:µ>40 mg/dLH1:μ>40 mg/dL . Her results are based on a simple random sample of size n=15 . The value of the one-sample t-t- statistic is t=1.457 .
If Lola requires her results to be statistically significant at significance level of a 0.10, what can she conclude and why?
a. Because the exact p-value is unknown, she cannot make a conclusion.
b. She should not reject the null hypothesis because p > 0.10.
c. She should not reject the null hypothesis because p< 0.10.
d. She should reject the null hypothesis because p< 0.10,
e. She should not reject the null hypothesis because 0.10< p < 0.05.
Answer:
d. She should reject the null hypothesis because p < 0.10.
Step-by-step explanation:
We have a t statistic, so let's solve for the P-value on our calculators. (tcdf on a TI-84 calculator is 2nd->VARS->6.)
tcdf(left bound, right bound, degrees of freedom)
Our left bound is t=1.457. Our right bound is infinity, because we're interested in the hypothesis µ>40 mg/dL. We use 999 to represent infinity in the calculator.Our degrees of freedom is n-1 = 15-1 = 14.tcdf(1.457,999,14) = .084
.084 < P-value of .10, so we reject the null hypothesis.
Lola's conclusion should be "She should reject the null hypothesis because p< 0.10". Option D is correct.
Given information:
Lola is using a one-sample t-test for a population mean, µ, to test the null hypothesis.
[tex]\mu=40[/tex]
Sample random size is, [tex]n=15[/tex].
The value of the one-sample t-statistic is [tex]t=1.457[/tex].
The left bound will be [tex]t=1.457[/tex] and the value of [tex]n-1[/tex] will be 15-1=14.
Now, use the calculator to find the value of p. The found value of p will be,
[tex]p=0.084[/tex]
So, the value of p is less than 0.1.
Therefore, Lola's conclusion should be "She should reject the null hypothesis because p< 0.10". Option D is correct.
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Jack bought 4 dozen eggs at k10 per dozen. 6 eggs were broken .what percent of his money goes waste?
Step-by-step explanation:
I hope this is what you need
PLEASE MAKE ME BRAINLIEST
A radioactive substance decays at a rate proportional to the amount (mass) that is present. Denote the proportionality constant by the letter r. Suppose we start with 1 kg of the substance. (a) (1pt) Write the differential equation and initial condition for the mass m(t) of the substance as a function of time t (measured in hours). (b) (1pt) Find the solution as a function of t and r. (c) (1pt) Suppose that, one hour later, 0.8 kgs remain. Find The constant r. (d) (1pt) Suppose we measure time in minutes. Find the differential equation for m(s), if s denotes time in minutes.
Answer:
a) The differential equation is: [tex]\frac{dm}{dt} =r\,m[/tex]
with initial condition: [tex]m(0)=1\,\,kg[/tex]
b) m(t) =\,1\,\,kg\,\,e^{r\,t}
c) r=-0.22314
d) Same differential equation, but the solution function would have a different value for "r" resultant from dividing by 60:[tex]\frac{ln(0.8)}{60} =r\\r=-0.003719[/tex]
Step-by-step explanation:
Part a)
The differential equation is: [tex]\frac{dm}{dt} =r\,m[/tex]
with initial condition: [tex]m(0)=1\,\,kg[/tex]
Part b)
The solution for a function whose derivative is a multiple of the function itself, must be associated with exponential of base "e":
[tex]m(t) =\,A\,e^{r\,t}[/tex] with [tex]A = m(0) = 1\,\,kg[/tex]
So we can write the function as: [tex]m(t) =\,1\,\,kg\,\,e^{r\,t}[/tex]
Part c)
To find the constant "r", we use the information given on the amount of substance left after one hour (0.8 kg) by using t = 1 hour, and solving for "r" in the equation:
[tex]m(t) =\,1\,\,kg\,\,e^{r\,t}\\m(1) =\,1\,\,kg\,\,e^{r\,(1)}\\0.8\,\,kg=\,1\,\,kg\,\,e^{r\,(1)}\\0.8=e^{r\,(1)}\\ln(0.8)=r\\r=-0.22314[/tex]
where we have rounded the answer to the 5th decimal place. Notice that this constant "r" is negative, associated with a typical exponential decay.
Part d)
The differential equation if we measure the time in minutes would be the same, but its solution would have a different constant "r" given by the answer to the amount of substance left after 60 minutes have elapsed:
[tex]m(t) =\,1\,\,kg\,\,e^{r\,t}\\m(1) =\,1\,\,kg\,\,e^{r\,(60)}\\0.8\,\,kg=\,1\,\,kg\,\,e^{r\,(60)}\\0.8=e^{r\,(60)}\\\frac{ln(0.8)}{60} =r\\r=-0.003719[/tex]
A Rhombus with diagonal 1 equal to 5 ft and diagonal 2 equal to 8 ft
Answer:
Area = 20 ft²
Step-by-step explanation:
Area of a thrombus
½ × d1 × d2
½ × 5 × 8
20
Answer:
20 ft squared
Step-by-step explanation:
The area of a rhombus can be calculated by multiplying its diagonals by each other and then halving that product: A = [tex]\frac{1}{2} d_1d_2[/tex]
Here, we know that [tex]d_1[/tex] = 5 and [tex]d_2[/tex] = 8. So, we have the equation: A = [tex]\frac{1}{2} *5*8=(1/2)*40=20[/tex]
Thus, the area is 20 ft squared.
Hope this helps!
4x - 2y =7
X + 2y =3
What are x and y ??
4x - 2y = 7
x + 2y = 3
5x = 10
x=2 and y=0
Answer:
{x,y} = {2,1/2}
Step-by-step explanation:
Solve by Substitution :
1. Solve equation [2] for the variable x
[2] x = -2y + 3
2. Plug this in for variable x in equation [1]
[1] 4•(-2y+3) - 2y = 7
[1] - 10y = -5
3.Solve equation [1] for the variable y
[1] 10y = 5
[1] y = 1/2
By now we know this much :
x = -2y+3
y = 1/2
4.Use the y value to solve for x
x = -2(1/2)+3 = 2
Solution :
{x,y} = {2,1/2}
Recall the survey you took during the first week of class. One of the questions was “do you agree that it is inappropriate to speak on a cellphone while at a restaurant?” Of the 1913 females that responded to the survey, 1729 agreed with this statement. Of the 1276 males that responded to this survey, 1111 agreed with this statement. Test to see if there is any difference between males and females with respect to how they feel about this issue. Use a significance level of .05.
State the appropriate null and alternative hypotheses.
Calculate the test statistic and report the p-value.
State your conclusion in context of the problem.
Based only on the results of the hypothesis test, would you expect a 95% confidence interval to include 0? Explain.
Calculate and interpret a 95% confidence interval for the difference between males and females.
Answer:
[tex]a) \ H_o:\hat p_f=\hat p_m\\\ \ \ H_a:\hat p_f\neq \hat p_m\\\\b) z\ test=2.925, \ p\ value(two-tail)=0.003444\\\\\\[/tex]
c) Reject H_o since there is sufficient evidence to suggest that there is difference between males and females with respect to how they feel about this issue.
d. No. Interval does not include zero
e. [tex]CI=[0.01044<(\hat p_f-\hat p_m)<0.05576[/tex]
We are 95% confident that the proportional difference lies between the [0.010444,0.05576] interval.
Step-by-step explanation:
a. The null hypothesis is that there is no difference between males and females with respect to how they feel about this issue:
[tex]H_o:p_m=p_f[/tex]
-The alternative hypothesis is that there is some difference between males and females with respect to how they feel about this issue:
[tex]H_a:p_m\neq p_f[/tex]
where [tex]p_m, \ p_f[/tex] is the proportion of males and females respectively.
b. The proportion of males and females in the study can be calculated as follows:
[tex]\hat p=\frac{x}{n}\\\\\hat p_f=\frac{1729}{1913}=0.9038\\\\\hat p_m=\frac{1111}{1276}=0.8707[/tex]
[tex]\hat p=\frac{x_f+x_m}{n_m+n_f}=\frac{1111+1729}{1276+1913}=0.8906[/tex]
#We then calculate the test statistic using the formula:
[tex]z=\frac{(\hat p_f-\hat p_m)}{\sqrt{\hat p(1-\hat p)(\frac{1}{n_f}+\frac{1}{n_m})}}\\\\\\=\frac{(0.9038-0.8707)}{\sqrt{(0.8906\times0.1094)(\frac{1}{1913}+\frac{1}{1276})}}\\\\\\=2.9250\\\\\therefore p-value=0.001722\\[/tex]
[tex]\# The \ two \ tail \ p-value \ is\\\\=0.01722\times 2\\\\=0.003444[/tex]
c. Since p<0.05:
[tex]p<0.05\\\\0.00344<0.05\\\\\therefore Reject \ H_o[/tex]
Hence, we Reject the Null Hypothesis since there is sufficient evidence to suggest that there is difference between males and females with respect to how they feel about this issue
d. The 95% confidence interval can be calculated as below:
[tex]CI=(p_f-p_m)\pm z_{\alpha/2}\sqrt{\frac{\hat p_m(1-\hat p_m)}{n_m}+\frac{\hat p_f(1-\hat p_f)}{n_f}}\\\\=(0.9038-0.8707)\pm 1.96\sqrt{0.00008823+0.000045449}\\\\=0.03310\pm 0.02266\\\\=[0.01044,0.05576][/tex]
Hence, the confidence interval does not include 0
e. The 95% confidence interval calculated from above is :
[tex]0.01044<(p_f-p_m)<0.05576[/tex]
Hence, we are 95% confident that the proportional difference will fall between the interval [tex]0.01044<(\hat p_f-\hat p_m)<0.05576[/tex]
The radius of a circle is 9 miles. What is the length of a 180° arc?
Final answer:
The length of a 180° arc in a circle with a radius of 9 miles is 9π miles, which is half of the circle's total circumference.
Explanation:
The radius of a circle is the distance from the center to any point on the circle, and the arc length is the distance measured along the circumference of the circle that corresponds to a particular angle. In our case, to calculate the length of a 180° arc, we first need the circumference of the circle, which can be found using the formula 2πr (where r is the radius), and then we find the proportion of the circumference that corresponds to a 180° angle, or half a circle.
The circumference of a circle with a radius of 9 miles is given by:
Circumference = 2π × 9 miles = 18π miles.
Since 180° is half of a full 360° rotation, the arc length for 180° will be half of the circumference:
Arc Length for 180° = ½ × 18π miles = 9π miles.
A chemist examines 15 sedimentary samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.670 cc/cubic meter with a standard deviation of 0.0616.
a. Determine the 80% confidence interval for the population mean nitrate concentration. Assume the population is approximately normal. Round your answer to three decimal places.
b. Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
(a) The 80% confidence interval for the population mean nitrate concentration is (0.648, 0.692).
(b) The critical value of t that should be used in constructing the 80% confidence interval is 1.345.
Step-by-step explanation:
Let X = nitrate concentration.
The sample mean nitrate concentration is, [tex]\bar x=0.670[/tex] cc/cubic meter.
The sample standard deviation of the nitrate concentration is, [tex]s=0.0616[/tex].
It assumed that the population is approximately normal.
And since the population standard deviation is not known, we will use a t-interval.
The (1 - α)% confidence interval for population mean (μ) is:
[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}[/tex]
(a)
The critical value of t for α = 0.20 and degrees of freedom, (n - 1) = 14 is:
[tex]t_{\alpha/2, (n-1)}=t_{0.20/2, (15-1)}=t_{0.10, 14}=1.345[/tex]
*Use a t-table for the critical value.
Compute the 80% confidence interval for the population mean nitrate concentration as follows:
[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}[/tex]
[tex]=0.670\pm 1.345\times \frac{0.0616}{\sqrt{15}}[/tex]
[tex]=0.670\pm 0.022\\=(0.648, 0.692)\\[/tex]
Thus, the 80% confidence interval for the population mean nitrate concentration is (0.648, 0.692).
(b)
The critical value of t for confidence level (1 - α)% and (n - 1) degrees of freedom is:
[tex]t_{\alpha/2, (n-1)}[/tex]
The value of is:
α = 0.20
And the degrees of freedom is,
(n - 1) = 15 - 1 = 14
Compute the critical value of t for confidence level 80% and 14 degrees of freedom as follows:
[tex]t_{\alpha/2, (n-1)}=t_{0.20/2, (15-1)}[/tex]
[tex]=t_{0.10, 14}\\=1.345[/tex]
*Use a t-table for the critical value.
Thus, the critical value of t that should be used in constructing the 80% confidence interval is 1.345.
In one common system for finding a grade-point average, or GPA:
A=4, B=3, C=2, D=1, F=0
The GPA is calculated by multiplying the number of credit hours for a course and the number assigned to each grade, and then adding these products. Then divide the sum by the total number of credit hours. Because each course grade is weighted according to the number of credits of the course, GPA is also called a weighted mean. Calculate the GPA for this transcript:
Sociology: 3cr: A, Biology: 4cr: C, Music 1cr: B, Math 4cr:B, English 3cr: C
Answer:
The GPA for this transcript is:
GPA = 2.73
Step-by-step explanation:
A=4, B=3, C=2, D=1, F=0
Sociology: 3cr: A, Biology: 4cr: C, Music 1cr: B, Math 4cr:B, English 3cr: C
Total number of credit hour = 3 + 4 + 1 + 4 + 3 = 15
Product for each course = the number of credit hours for a course * the number assigned to each grade
Sociology = 3 * 4 = 12
Biology = 4 * 2 = 8
Music = 1 * 3 = 3
Math = 4 * 3 = 12
English = 3 * 2 = 6
Total product = 12 + 8 + 3 + 12 + 6 = 41
GPA = Sum of product / Total credit hour
GPA = 41 / 15 = 2.7333333
GPA = 2.73
Answer:
The results is 2.73.
Step-by-step explanation:
First let's make the calculations for each course;
For Sociology, an A (which is 4) for 3 credits equals to 12.
For Biology, a C (which is 2) for 4 credits equals to 8.
For Music, a B (which is 3) for 1 credit equals to 3.
For Math, a B (which is 3) for 4 credits equals to 12.
For English, a C (which is 2) for 3 credits equals to 6.
If we sum them all up, we find the results to be 41 and the total credits to be 15 for the 5 courses.
Lastly we should divide 41/15 which will be equal to 2.73 which is the GPA.
I hope this answer helps.
emily is 60 inches tall. fernando is 3/4 of emily's height and jasmine is 8/9 of fernando's height. how tall are fernanado and jasmine?
Answer:
fernando is 45 inches tall, and jasmine is 40 inches tall
Step-by-step explanatin
60 divided by 3/4 is 45, 45 divided by 8/9 is 40
Fernando is 45 inches tall, and Jasmine is 40 inches tall.
Emily is 60 inches tall. Fernando is 3/4 of Emily's height:
(60 inches x 3/4 = 45 inches).
Jasmine is 8/9 of Fernando's height:
(45 inches x 8/9 = 40 inches).
Find f such that f'(x) = 5x² + 9x - 7 and f(0) = 8.
Answer:
[tex]\frac{5}{3}x^3+\frac{9}{2}x^2-7x+8\\[/tex]
Step-by-step explanation:
Integrate your function with respect to x to get the non-differentiated form.
[tex]\int(5x^2+9x-7)dx=\frac{5}{3}x^3+\frac{9}{2}x^2-7x+c\\[/tex]
Plug in your known value of x to get your value for your constant
[tex]f(0) = 8\\ \frac{5}{3}(0^3)+\frac{9}{2}(0^2)-7(0)+c = 8 \\c=8[/tex]
This gives you your function to be
[tex]\frac{5}{3}x^3+\frac{9}{2}x^2-7x+8\\[/tex]
To find f such that f'(x) = 5x² + 9x - 7 and f(0) = 8, integrate the given function and solve for the constant of integration using the given condition. The resulting equation is f(x) = (5/3)x³ + (9/2)x² - 7x + 8.
Explanation:To find f such that f'(x) = 5x² + 9x - 7 and f(0) = 8, we need to integrate f'(x) to find the equation for f(x). Let's find the antiderivative of 5x² + 9x - 7, which is (5/3)x³ + (9/2)x² - 7x + C. To determine the value of C, we can use the given condition f(0) = 8. Substituting x = 0 into the equation, we get 8 = (5/3)(0)³ + (9/2)(0)² - 7(0) + C. Solving for C, we find that C = 8. Therefore, the equation for f(x) is f(x) = (5/3)x³ + (9/2)x² - 7x + 8.
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Which graph represents the solution set of the inequality Negative 14.5 less-than x?
A. A number line going from negative 15 to negative 11. An open circle is at negative 13.5. Everything to the right of the circle is shaded.
B. A number line going from negative 15 to negative 11. A closed circle is at negative 14. Everything to the right of the circle is shaded.
C. A number line going from negative 15 to negative 11. An open circle is at negative 14.5. Everything to the right of the circle is shaded.
D. A number line going from negative 15 to negative 11. A closed circle is at negative 15. Everything to the right of the circle is shaded.
The solution of the inequality -14.5 < x represents graph which is correct option C
What is inequality?
Inequality is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is not equal.
-14.5 < x
x > -14.5
A number line going from negative 15 to negative 11. An open circle is at negative 14.5. Everything to the right of the circle is shaded.
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A ski resort gets an average of 2,000 customers per weekday with a standard deviation of 800 customers. Assume the underlying distribution is normal. Use an appropriate normal transformation to calculate the probability a ski resort averages more than 3,000 customers per weekday over the course of four weekdays.
Answer:
0.62% probability that a ski resort averages more than 3,000 customers per weekday over the course of four weekdays
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
[tex]\mu = 2000, \sigma = 800, n = 4, s = \frac{800}{\sqrt{4}} = 400[/tex]
Trobability a ski resort averages more than 3,000 customers per weekday over the course of four weekdays.
This is 1 subtracted by the pvalue of Z when X = 3000. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{3000 - 2000}{400}[/tex]
[tex]Z = 2.5[/tex]
[tex]Z = 2.5[/tex] has a pvalue of 0.9938
1 - 0.9938 = 0.0062
0.62% probability that a ski resort averages more than 3,000 customers per weekday over the course of four weekdays
A recent study examined hearing loss data for 1981 U.S. teenagers. In this sample, 369 were found to have some level of hearing loss. News of this study spread quickly, with many news articles blaming the prevalence of hearing loss on the higher use of ear buds by teens. At MSNBC (8/17/2010), Carla Johnson summarized the study with the headline: "1 in 5 U.S. teens has hearing loss, study says." To investigate whether this is an appropriate or a misleading headline, you will conduct a test of significance with the following hypotheses: Null: π = 0.20 Alternative: π ≠ 0.20
Answer:
There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.
P-value=0.12
Step-by-step explanation:
We have to perform a test of hypothesis on the proportion.
The claim is that the proportion of US teens that have some level of hearing loss differs from 20%.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi=0.20\\\\H_a:\pi\neq0.20[/tex]
The significance level is assumed to be 0.05.
The sample, of size n=1981, has 369 positive cases. Then, the proportion is:
[tex]p=X/n=369/1981=0.186[/tex]
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.2*0.8}{1981}}=\sqrt{ 0.000081 }= 0.009[/tex]
Now, we can calculate the statistic z:
[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.186-0.20+0.5/1981}{0.009}=\dfrac{-0.014}{0.009}=-1.556[/tex]
The P-value for this two-tailed test is:
[tex]P-value=2*P(z<-1.556)=0.12[/tex]
The P-value is below the significance level, so the effect is not significant. The null hypothesis failed to be rejected.
There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.
Since -0.700 falls within this range (-1.96 to 1.96), you fail to reject the null hypothesis (H0). This means that there is not enough evidence to conclude that the true proportion of U.S. teens with hearing loss is different from 0.20.
To investigate whether the headline "1 in 5 U.S. teens has hearing loss, study says" is appropriate or misleading, you can conduct a hypothesis test based on the given hypotheses:
Null Hypothesis (H0): π = 0.20 (The true proportion of U.S. teens with hearing loss is 0.20, or 20%.)
Alternative Hypothesis (H1): π ≠ 0.20 (The true proportion of U.S. teens with hearing loss is not equal to 0.20.)
Here, π represents the population proportion of U.S. teenagers with hearing loss.
To test these hypotheses, you can perform a hypothesis test for a population proportion using a significance level (alpha), such as 0.05 (5%). You can use the z-test for proportions to determine whether the observed proportion of hearing loss in the sample significantly differs from the claimed proportion of 0.20.
The test statistic for the z-test for proportions is calculated as:
z= (p−π)/√(π(1−π)/n)
Where:
p is the sample proportion (369 out of 1981 in this case).
π is the hypothesized population proportion (0.20).
n is the sample size (1981).
Calculate the sample proportion:
p= 369/1981 ≈0.186
Now, calculate the test statistic
z= (0.186−0.20)/√(0.20(1−0.20)/1981)
Calculate the standard
SE=√(0.20(1−0.20)/1981)≈0.020
Now, calculate
z≈ (0.186−0.20)/0.020 ≈−0.700
Now, you can find the critical values for a two-tailed test at a 95% confidence level (alpha = 0.05). You can use a standard normal distribution table or calculator to find the critical z-values. For a two-tailed test with alpha = 0.05, the critical z-values are approximately -1.96 and 1.96.
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Given f(x) = x² - 10x + 22, what is the range of f?
Answer:
[-3, ∞)
Step-by-step explanation:
There are many ways to find the range but I will use the method I find the easiest.
First, find the derivative of the function.
f(x) = x² - 10x + 22
f'(x) = 2x - 10
Once you find the derivative, set the derivative equal to 0.
2x - 10 = 0
Solve for x.
2x = 10
x = 5
Great, you have the x value but we need the y value. To find it, plug the x value of 5 back into the original equation.
f(x) = x² - 10x + 22
f(5) = 5² - 10(5) + 22
= 25 - 50 +22
= -3
Since the function is that of a parabola, the value of x is the vertex and the y values continue going up to ∞.
This means the range is : [-3, ∞)
Another easy way is just graphing the function and then looking at the range. (I attached a graph of the function below).
Hope this helped!
Answer:
The correct answer is B
Step-by-step explanation:
What is the final transformation in the composition of transformations that maps pre-image GHJK to image G’H”J”K”?
Answer:
B on edge 2020
Step-by-step explanation:
Applying [tex]\[M_f = M_n \cdot M_{n-1} \cdot ... \cdot M_3 \cdot M_2 \cdot M_1\][/tex] final transformation matrix to the pre-image GHJK [tex](\(P\))[/tex], we get the image G'H''J''K''.
To determine the final transformation that maps the pre-image GHJK to the image G'H''J''K'', we need to break down the transformations and apply them in the correct order.
Let's assume there are several transformations involved, such as translations, rotations, reflections, or dilations. Each transformation can be represented by a matrix or a set of rules.
Let's denote the initial pre-image GHJK as [tex]\(P\).[/tex] The series of transformations can be represented as [tex]\(T_1 \cdot T_2 \cdot T_3 \cdot ... \cdot T_n\)[/tex], where [tex]\(T_1\) to \(T_n\)[/tex] are individual transformations.
To find the final transformation, we need to multiply the matrices representing these transformations in the reverse order. If [tex]\(M_1, M_2, M_3, ..., M_n\)[/tex] are the matrices representing [tex]\(T_1, T_2, T_3, ..., T_n\)[/tex]respectively, the final transformation matrix [tex]\(M_f\)[/tex] would be:
[tex]\[M_f = M_n \cdot M_{n-1} \cdot ... \cdot M_3 \cdot M_2 \cdot M_1\][/tex]
Applying this final transformation matrix to the pre-image GHJK [tex](\(P\))[/tex], we get the image G'H''J''K''.
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