Answer:
the answer is 75% hope that helps
Step-by-step explanation:
i did the test and i got it right
The required percentage of the data values falls between the values of 27 and 45 in the data set shown is 75%.
What is a box plot?A straightforward method of expressing statistical data on a plot in which a rectangle is drawn to represent the second and third quartiles, with a vertical line inside to indicate the median value. Horizontal lines on both sides of the rectangle show the lower and upper quartiles.
Based on the box-and-whisker plot, we can see that the majority of the data values fall between the values of 32 and 45, and the median value is 36.
To find the percentage of data values that fall between 27 and 45, we can estimate by visually analyzing the plot. Since the whiskers go from 27 to 48, we can assume that all data values between 27 and 48 are included. Then, we need to estimate how much of the data falls between 32 and 45, which is the range of the box.
Since the box takes up most of the range of values between 32 and 45, we can estimate that around 75% of the data values fall within this range. Therefore, the percentage of data values that fall between 27 and 45 can be estimated as around 75%.
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When conducting a significance test to determine if there is a difference between two treatments, with a quantitative response variable, treatments are given to different experimental units, we summarize the data by: Group of answer choices computing the proportion of the sample that reacted better to treatment one than treatment two. computing the mean and standard deviation of each treatment group separately. computing the difference in the responses for each experimental unit under both treatments, and then finding the mean and standard deviation of the differences. computing the difference in the proportion of the sample that reacted better to treatment one and the proportion of the sample that reacted better to treatment two.
Final answer:
To summarize data in a significance test for two different treatments with a quantitative response variable, the mean and standard deviation for each treatment group are computed separately to look for statistically significant differences.
Explanation:
When conducting a significance test to determine if there is a difference between two treatments with a quantitative response variable, and treatments are given to different experimental units, we summarize the data by computing the mean and standard deviation of each treatment group separately. This approach involves comparing the two sets of data from the treatment groups to see if there is a statistically significant difference in their means, which could suggest an effect of the treatments. This methodology is part of inferential statistics, where researchers use the collected sample data to make inferences about the population from which the sample was drawn.
A cheeseburger franchise uses 11 different buns, 4 different cheeses, 3 types of lettuce, and 4 types of tomatoes. Takes 10 minutes to eat each cheeseburger. How long will it take to eat all of the possible cheeseburgers
Answer:
2.2
Step-by-step explanation:
It would take 15840 min to eat all of them that means 264 hours or 11 days
lol why you need this info?
Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 transactions at random, she found that the average amount spent was $ 41.15 . She then computed a 90 % confidence interval to be between $ 38.01 and $ 44.29 .
Answer:
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The 90% confidence interval for this case would be (38.01, 44.29) and is given.
The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .
And the best option would be:
The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29
Step-by-step explanation:
Assuming this complete question: Which statement gives a valid interpretation of the interval?
The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.
There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.
There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.
The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
The 90% confidence interval for this case would be (38.01, 44.29) and is given.
The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .
And the best option would be:
The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29
We intend to estimate the average driving time of a group of commuters. From a previous study, we believe that the average time is 42 minutes with a standard deviation of 9 minutes. We want our 90 percent confidence interval to have a margin of error of no more than plus or minus 3 minutes. What is the smallest sample size that we should consider
Answer:
The minimum sample size required is 25 so that margin of error is no more than 3 minutes.
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 42 minutes
Standard Deviation, σ = 9 minutes.
We want to build a 90% confidence interval such that margin of error is no more than 3 minutes.
Formula for margin of error:
[tex]z_{critical}\times \dfrac{\sigma}{\sqrt{n}}[/tex]
[tex]z_{critical}\text{ at}~\alpha_{0.10} = 1.64[/tex]
Putting values, we get.
[tex]z_{critical}\times \dfrac{\sigma}{\sqrt{n}}\leq 3\\\\1.64\times \dfrac{9}{\sqrt{n}}\leq 3\\\\\dfrac{1.64\times 9}{3}\leq \sqrt{n}\\\\4.92\leq \sqrt{n}\\\Rightarrow n\geq 24.2064\approx 25[/tex]
Thus, the minimum sample size required is 25 so that margin of error is no more than 3 minutes.
3.- In a certain desert region the average number of persons who become seriously ill each year from eating a certain poisonous plant each year is 3.2, determine what is the probability that at least 5 people will become seriously ill in two years (hint: this is a rare event and can be modeled using a Poisson distribution)
Answer:
[tex]P(X\geq 5)=1-P(X<5)=1-P(X\leq 4)=1-[P(X=0)+P(X=1)+P(X=2) +P(X=3) +P(X=4)][/tex]
Using the pmf we can find the individual probabilities like this:
[tex]P(X=0)=\frac{e^{-6.4} 6.4^0}{0!}=0.001662[/tex]
[tex]P(X=1)=\frac{e^{-6.4} 6.4^1}{1!}=0.010634 [/tex]
[tex]P(X=2)=\frac{e^{-6.4} 6.4^2}{2!}=0.034029 [/tex]
[tex]P(X=3)=\frac{e^{-6.4} 6.4^3}{3!}=0.072595 [/tex]
[tex]P(X=4)=\frac{e^{-6.4} 6.4^4}{4!}=0.116151 [/tex]
And replacing we got:
[tex] P(X \geq 5) =0.76493[/tex]
Step-by-step explanation:
Previous concepts
Let X the random variable that represent the number of people that will become sereiosly ill in two years. We know that [tex]X \sim Poisson(\lambda)[/tex]
The probability mass function for the random variable is given by:
[tex]f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...[/tex]
And f(x)=0 for other case.
For this case the value for [tex]\lambda[/tex] would be:
[tex]\lambda = 3.2 \frac{ills}{year} *2 years = 6.4[/tex]
For this distribution the expected value is the same parameter [tex]\lambda[/tex]
[tex]E(X)=\mu =\lambda[/tex]
On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:
[tex]P(X\geq 5)=1-P(X<5)=1-P(X\leq 4)=1-[P(X=0)+P(X=1)+P(X=2) +P(X=3) +P(X=4)][/tex]
Using the pmf we can find the individual probabilities like this:
[tex]P(X=0)=\frac{e^{-6.4} 6.4^0}{0!}=0.001662[/tex]
[tex]P(X=1)=\frac{e^{-6.4} 6.4^1}{1!}=0.010634 [/tex]
[tex]P(X=2)=\frac{e^{-6.4} 6.4^2}{2!}=0.034029 [/tex]
[tex]P(X=3)=\frac{e^{-6.4} 6.4^3}{3!}=0.072595 [/tex]
[tex]P(X=4)=\frac{e^{-6.4} 6.4^4}{4!}=0.116151 [/tex]
And replacing we got:
[tex] P(X \geq 5) =0.76493[/tex]
Answer:
The probability that at least 5 people will become seriously ill in two years is 0.7649.
Step-by-step explanation:
The question mentions that this problem can be modeled using the Poisson distribution so, we will use the formula:
P(X=x) = [(e^-λt)*(λt^x)]/x!
where λ = average number of occurrences per year
t = no. of years
x = number of people
We need to determine P(X≥5) so first we will calculate the probabilities at X=0,1,2,3,4 and subtract them from the total probability i.e. 1 to find P(X≥5).
We have λ = 3.2, t=2 years hence λt = (3.2)(2) = 6.4. So,
P(X=0) = [(e^(-6.4)*(6.4^0)]/0! = 0.00166
P(X=1) = [(e^(-6.4)*(6.4^1)]/1! = 0.01063
P(X=2) = [(e^(-6.4)*(6.4^2)]/2! = 0.03403
P(X=3) = [(e^(-6.4)*(6.4^3)]/3! = 0.07259
P(X=4) = [(e^(-6.4)*(6.4^4)]/4! = 0.011615
P(X≥5) = 1 - P(X<5)
= 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4)]
= 1 - (0.00166 + 0.01063 + 0.03403 + 0.07259 + 0.011615)
= 1 - 0.23506
P(X≥5) = 0.7649
The probability that at least 5 people will become seriously ill in two years is 0.7649.
A videotape store has an average weekly gross of $1,158 with a standard deviation of $120. Let x be the store's gross during a randomly selected week. If this is a normally distributed random variable, then the number of standard deviations from $1,158 to $1,360 is:
Answer:
The number of standard deviations from $1,158 to $1,360 is 1.68.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 1158, \sigma = 120[/tex]
The number of standard deviations from $1,158 to $1,360 is:
This is Z when X = 1360. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1360 - 1158}{120}[/tex]
[tex]Z = 1.68[/tex]
The number of standard deviations from $1,158 to $1,360 is 1.68.
Subtract 6 from me. Then multiply by 2. If you subtract 40 and then divide by 4 you get 8. What number am I?
Answer:
42
Step-by-step explanation:
work backwards And use the opposite operation
start with 8 x 4 = 32 + 40 = 72/2 = 36 + 6 = 42
A shipping company handles containers in three different sizes: (1) 27 ft3 (3 × 3 × 3), (2) 125 ft3, and (3) 512 ft3. Let Xi (i = 1, 2, 3) denote the number of type i containers shipped during a given week. With μi = E(Xi) and σi2 = V(Xi), suppose that the mean values and standard deviations are as follows:
μ1 = 230 μ2 = 240 μ3 = 120
σ1 = 11 σ2 = 12 σ3 = 7
Assuming that X1, X2, X3 are independent, calculate the expected value and variance of the total volume shipped.
Answer:
Expected value of the total volume shipped = 97,650 ft³
Variance of the total volume shipped = 15,183,265
Standard deviation = 3896.6 ft³
Step-by-step explanation:
The mean of number of type 1, 2 and 3 containers in a week
μ₁ = 230, μ₂ = 240, μ₃ = 120
The standard deviations for the number of type 1, 2 and 3 containers in a week
σ₁ = 11, σ₂ = 12, σ₃ = 7
When independent distributions are combined, the combined mean and combined variance are given through the relation
Combined mean = Σ λᵢμᵢ
(summing all of the distributions in the manner that they are combined)
Combined variance = Σ λᵢ²σᵢ²
(summing all of the distributions in the manner that they are combined)
Volume of each container type
λ₁ = 27 ft³
λ₂ = 125 ft³
λ₃ = 512 ft³
Distribution of total volume shipped
= 27X₁ + 125X₂ + 512X₃
Expected value = Combined Mean = 27μ₁ + 125μ₂ + 512μ₃
= (27×230) + (125×240) + (512×120) = 590
Combined Variance = 27²σ₁² + 125²σ₂² + 512²σ₃²
= (27² × 11²) + (125² × 12²) + (512² × 7²)
= 88,209 + 2,250,000 + 12,845,056
= 15,183,265
Standard deviation = √(15,183,265) = 3896.6 ft³
Hope this Helps!!!
Let U ={1,2,3,4,5,6,7}, A={1,2,3,4}, and B ={1,2,4}. Find the set A intersection B
Answer:
its c I just id the test
Step-by-step explanation:
The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machines claims that breakdowns of its new, improved model are easier to fix. To test this claim, sample of 73 breakdowns of the new model were observed, resulting in a mean repair time of 88.8 minutes and a standard deviation of 26.6 minutes. Use significance level α = 0.05. State clearly what are your null and alternative hypothesis, show your work, and state your conclusion.
Answer:
[tex]t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349[/tex]
[tex]p_v =P(t_{(72)}<-1.349)=0.0908[/tex]
If we compare the p value and the significance level given [tex]\alpha=0.05[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.
Step-by-step explanation:
Data given and notation
[tex]\bar X=88.8[/tex] represent the sample mean
[tex]s=26.6[/tex] represent the sample standard deviation for the sample
[tex]n=73[/tex] sample size
[tex]\mu_o =93[/tex] represent the value that we want to test
[tex]\alpha=0.05[/tex] represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
[tex]p_v[/tex] represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:
Null hypothesis:[tex]\mu \geq 93[/tex]
Alternative hypothesis:[tex]\mu < 93[/tex]
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
[tex]t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349[/tex]
P-value
The first step is calculate the degrees of freedom, on this case:
[tex]df=n-1=73-1=72[/tex]
Since is a one side test the p value would be:
[tex]p_v =P(t_{(72)}<-1.349)=0.0908[/tex]
Conclusion
If we compare the p value and the significance level given [tex]\alpha=0.05[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.
The null hypothesis is that the mean repair time for the new model is equal to the mean repair time for the previous model. The alternative hypothesis is that the mean repair time for the new model is less than the mean repair time for the previous model. By performing a one-sample t-test, we compare the sample mean repair time to the population mean repair time. Using the calculated t-statistic and the critical t-value, we determine whether to reject or fail to reject the null hypothesis.
Explanation:The null hypothesis, denoted as H0, states that the mean repair time for the new model of copying machine is equal to the mean repair time for the previous model (93 minutes). The alternative hypothesis, denoted as H1, states that the mean repair time for the new model is less than 93 minutes.
To test these hypotheses, we can perform a one-sample t-test. Using the given sample data, we calculate the t-statistic as:
t = (sample mean - population mean) / (sample standard deviation / sqrt(sample size))
Using the t-distribution table or a calculator, we find the critical t-value at a significance level of 0.05 and degrees of freedom (sample size - 1). If the calculated t-statistic is less than the critical t-value, we reject the null hypothesis and conclude that the new model has a lower mean repair time. Otherwise, we fail to reject the null hypothesis.
In this case, the calculated t-statistic is:
t = (88.8 - 93) / (26.6 / sqrt(73)) ≈ -1.34
With 72 degrees of freedom, the critical t-value at α = 0.05 is -1.666. Since the calculated t-statistic (-1.34) is greater than the critical t-value (-1.666), we fail to reject the null hypothesis. Therefore, we do not have sufficient evidence to conclude that the new model of copying machine has a significantly lower mean repair time than the previous model.
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Solve for c
7c + 3 - 7c = 3c - 9
Answer:
4=c
Step-by-step explanation:
7c + 3 - 7c = 3c - 9
Combine like terms
7c-7c+3 = 3c-9
3 = 3c-9
Add 9 to each side
3+9 = 3c-9+9
12 = 3c
Divide each side by 3
12/3 = 3c/3
4 =c
Answe
c=−4/3
Step-by-step explanation:
A survey of an urban university (population of 25,450) showed that 883 of 1,112 students sampled supported a fee increase to fund improvements to the student recreation center. Using the 95% level of confidence, what is the confidence interval for the proportion of students supporting the fee increase
Answer:
The confidence interval for the proportion of students supporting the fee increase
( 0.77024, 0.81776)
Step-by-step explanation:
Explanation:
Given data a survey of an urban university (population of 25,450) showed that 883 of 1,112 students sampled supported a fee increase to fund improvements to the student recreation center.
Given sample size 'n' = 1112
Sample proportion 'p' = [tex]\frac{883}{1112} = 0.7940[/tex]
q = 1 - p = 1- 0.7940 = 0.206
The 95% level of confidence intervals
The confidence interval for the proportion of students supporting the fee increase
[tex](p-z_{\alpha } \sqrt{\frac{pq}{n} } ,p + z_{\alpha } \sqrt{\frac{pq}{n} } )[/tex]
The Z-score at 95% level of significance =1.96
[tex](0.7940-1.96\sqrt{\frac{0.7940 X 0.206}{1112} } ,0.7940 + 1.96 \sqrt{\frac{0.7940 X 0.206}{1112} } )[/tex]
(0.7940-0.02376 , 0.7940+0.02376)
( 0.77024, 0.81776)
Conclusion:-
The confidence interval for the proportion of students supporting the fee increase
( 0.77024, 0.81776)
What is the solution to the following system?
3x+10y-12z=40
x-5y=0
x-4z=0
9514 1404 393
Answer:
(x, y, z) = (20, 4, 5)
Step-by-step explanation:
The last two equations allow y and z to be expressed in terms of x, so we have ...
3x +2(5y) -3(4z) = 40
3x +2(x) -3(x) = 40
x = 20 . . . . . . . . . . . . divide by the coefficient of x
y = 20/5 = 4
z = 20/4 = 5
The solution is (x, y, z) = (20, 4, 5).
what is y?
2y + 3 = 19
Answer:
y = 8
Step-by-step explanation:
2y + 3 = 19
2y = 19 - 3
2y = 16
y = 16/2
y = 8
Hopefully this help u
Answer: y = 8
Step-by-step explanation: To solve for y, we must first isolate the term containing y which in this problem is 2y.
Since 3 is being added to 2y, we subtract 3 from
both sides of the equation to isolate the 2y.
On the left, the +3 and -3 cancel
out and on the right, 19 - 3 is 16.
So we have 2y = 16.
Now we can finish things off by just dividing
both sides of the equation by 2.
On the left the 2's cancel and on
the right, 16 divided by 2 is 8.
So y = 8.
The material for constructing the base of an open box costs 1.5 times as much per unit area as the material for constructing the sides. For a fixed amount of money C, find the dimensions of the box of largest volume that can be made.
The problem is an Optimization problem in Calculus that is solved by representing the volume of the open box in terms of a single variable using the fixed cost. With the volume equation, we can use calculus to find the optimal dimensions.
Explanation:The question is about maximizing the volume of an open box given a fixed cost and considering that the base of the box is 1.5 times as expensive as the sides. This problem comes under the branch of mathematics known as Optimization in Calculus. The volume V of an open box (a box without a top) is given by the product of its length, width, and height (V = lwh).
In this problem, the total cost is fixed, hence, the sum of the cost of the base and the cost of the sides is a constant. We can say that cost = C = (Base Cost) + (Sides Cost) = 1.5lw + 2.0lh + 2.0wh. We can express the width w in terms of l and h using the cost equation, and then substitute in the volume equation to write V in terms of a single variable. This enables the use of calculus to optimize the volume. It is beyond the scope of this answer to give a complete solution, but essentially, you would differentiate to obtain an equation, and solve for the optimal dimensions.
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The net of a triangular pyramid. The base is D, and the sides are A, B, and C.
The net of the triangular pyramid shows the four faces of the pyramid labeled A, B, C, and D. Use the drop-down menus to complete the statements.
The base area is the total area of .
The lateral area is the total area of .
The surface area is the total area of .
Answer:
The base area is the total area of D
The lateral area is the total area of A, B, and C
The surface area is the total area of A, B, C, and D.
Answer:
(d) the base area is the total area
Explain: because i got it right on the test
Which statement is true
A. (X,y) (x-7,y+2) represents a translation 7 units down and 2 units to the right
B. (X,y) (-x,-y) represents a rotation 180° clockwise
C. (X,y) (x+3.5,y+3.5) represents a dilation wuth a scale factor of 3.5
D. (X,y) (-x, y) represents a reflection over the x axis
Answer:
B
Step-by-step explanation:
this is true because if you rotate 180 degrees on a graph both the x and y will always become their opposite.
1,050,200
What is the number between 1 and 10
what is 2/3 plus 1/6
Answer:
5/6
Step-by-step explanation:
2/3=4/6
4/6+1/6=5/6
Answer:
That would be 5/6
Step-by-step explanation:
You multiply the denominator and the numerator by 2 to get a common denominator of 6. You add the 4 to the 1 to get 5/6
A car manufacturer sent out survey cards to owners who had purchased new cars. The survey card only had boxes to check for replies, and no places to write additional comments. What is a possible result of the design of the comment cards?
A.
The results cannot be examined because comment cards were used.
B.
The owners who filled out the cards may not express their true opinion.
C.
People would refuse to fill out the cards.
D.
Not enough cards would be returned.
Answer: I think the answer is B. I don't fully understand the question but it seems like that would be the answer. You might double check though.
Step-by-step explanation:
Identify the correlation in the scatterplot.
Positive correlation
Negative correlation
No correlation
Answer:
B
Step-by-step explanation:
Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five students who recently took the exam are 570, 620, 710, 540 and 480. We want to find a 95% confidence interval of the population mean of SAT math scores. Calculate the point estimate.
Answer:
The mean calculated for this case is [tex]\bar X=584[/tex]
And the 95% confidence interval is given by:
[tex]584-2.776\frac{86.776}{\sqrt{5}}=476.271[/tex]
[tex]584+2.776\frac{86.776}{\sqrt{5}}=691.729[/tex]
So on this case the 95% confidence interval would be given by (476.271;691.729)
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
In order to calculate the mean and the sample deviation we can use the following formulas:
[tex]\bar X= \sum_{i=1}^n \frac{x_i}{n}[/tex] (2)
[tex]s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}[/tex] (3)
The mean calculated for this case is [tex]\bar X=584[/tex]
The sample deviation calculated [tex]s=86.776[/tex]
In order to calculate the critical value [tex]t_{\alpha/2}[/tex] we need to find first the degrees of freedom, given by:
[tex]df=n-1=5-1=4[/tex]
Since the Confidence is 0.95 or 95%, the value of [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that [tex]t_{\alpha/2}=2.776[/tex]
Now we have everything in order to replace into formula (1):
[tex]584-2.776\frac{86.776}{\sqrt{5}}=476.271[/tex]
[tex]584+2.776\frac{86.776}{\sqrt{5}}=691.729[/tex]
So on this case the 95% confidence interval would be given by (476.271;691.729)
Final answer:
The point estimate of the population mean of SAT math scores, calculated from the sample scores (570, 620, 710, 540, and 480), is 584.
Explanation:
The subject of this question is Mathematics, specifically focusing on statistics and the SAT examination scores. To calculate the point estimate for the given simple random sample of SAT Mathematics test scores (570, 620, 710, 540, and 480), we need to find the sample mean. This can be done by adding all the scores together and dividing by the number of students in the sample, which is five in this case.
Point Estimate calculation:
Add all the scores together: 570 + 620 + 710 + 540 + 480 = 2920
Divide by the number of students: 2920 / 5 = 584
The point estimate of the population mean of SAT math scores is 584.
A) A club is considering changing its bylaws. In an initial straw vote on the issue, 24 of the 40 members of the club favored the change and 16 did not. A committee of six is to be chosen from the 40 club members to devote further study to the issue. a) How many committees of six can be formed from the club membership
Answer:
38,38,380
Step-by-step explanation:
GIVEN: A club is considering changing its laws. In an initial straw vote on the issue, [tex]24[/tex] of the [tex]40[/tex] members of the club favored the change and [tex]16[/tex] did not. A committee of six is to be chosen from the [tex]40[/tex] club members to devote further study to the issue.
TO FIND: How many committees of six can be formed from the club membership.
SOLUTION:
Total number of members [tex]=40[/tex]
Total members to be chosen [tex]=6[/tex]
To select committee of [tex]6[/tex] members from [tex]40[/tex] [tex]=^{40}C_6[/tex]
[tex]=\frac{40!}{34!6!}[/tex]
[tex]=38,38,380[/tex]
Hence 38,38,380 different committee can be formed.
A national survey of 1000 adult citizens of a nation found that 15% dreaded Valentine's Day. The margin of error for the survey was 6.2 percentage points with 85% confidence. Explain what this means.
Answer:
We are 85% confident that the proportion of adults who dreaded valentines day is within the range of 8.8% to 21.2%.
Step-by-step explanation:
Proportion of adults who dreaded valentines day = 15% = 0.15
The margin of error with 85% confidence = 6.2% = 0.062
The confidence interval is given by
p ± margin of error
0.15 ± 0.062
Lower limit = 0.15 - 0.062
Lower limit = 0.088
Lower limit = 8.8%
Upper limit = 0.15 + 0.062
Upper limit = 0.212
Upper limit = 21.2%
So it means that we are 85% confident that the proportion of adults who dreaded valentines day is within the range of 8.8% to 21.2%.
Suppose there are two independent economic factors, M1 and M2. The risk-free rate is 4%, and all stocks have independent firm-specific components with a standard deviation of 49%. Portfolios A and B are both well diversified. Portfolio Beta on M1 Beta on M2 Expected Return (%) A 1.6 2.4 39 B 2.3 -0.7 9
Answer:
E(rP) = 4% + 5.50% x β(M1) + 10.92% x β(M2)
Step-by-step explanation:
let us recall from the following statement:
The two independent economic factors are M1 and M2
Th risk free rate = 4%
The standard deviation of all stocks of independent firm specific components is =49%
P = portfolios for A and B
Now,
What is the expected relationship of return-beta
The Expected return-beta relationship E(rP) = % + βp₁ + βp₂
E(rA) = 4% + 1.6 * M1 + 2.4* M2 = 39%
E(rB) = 4% + 2.3 * M1 + (-0.7)* M2 = 9%
Therefore
Solving for M1 and M2 using excel solver, we have M1 = 5.50% and M2 = 10.92%
E(rP) = 4% + 5.50% x β(M1) + 10.92% x β(M2)
The question pertains to finance and investment analysis. It emphasizes the CAPM model, which combines systematic risk measured by beta and market risk premium to calculate expected returns on portfolios. It also highlights that diversification reduces firm-specific risks.
Explanation:The question deals with the concept of portfolio return, beta coefficients, and firm-specific risk, which are important aspects of finance and investment analysis. The expected return on portfolios A and B, can be calculated using the CAPM model, which states that expected return equals the risk-free rate plus the portfolio's beta (which measures systematic risk) multiplied by the market risk premium (difference between the expected market return and the risk-free rate). To compute this, the beta coefficients need to be multiplied with their respective economic factors, and the results obtained are added together.
For portfolio A, the expected return would be calculated like this: Return = Risk-Free rate + β1*M1 + β2*M2 = 4 + (1.6 * M1) + (2.4 * M2).
For portfolio B, the calculation would be similar: Return = Risk-Free rate + β1*M1 + β2*M2 = 4 + (2.3 * M1) - (0.7 * M2). The negative beta on M2 indicates that the portfolio's return would decrease when M2 increases, hence it has an inverse relationship with the portfolio return. The independent firm-specific component would not affect the return as per the assumption that the portfolios are well diversified; diversification reduces, but not completely eliminates, the firm-specific risk.
Learn more about Portfolio Return here:https://brainly.com/question/32359578
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write 7.630 in word form.
Answer:
seven and six hundred thirty thousandths
Step-by-step explanation:
the decimal point is when you say and when reading it
The representation of 7.630 in word form is; Seven and six hundred thirty thousandths.
How to identify the place value of a digit in a number?The place values on left of decimal point start as ones, tens, hundreds, and so on.
The place value on right of decimal point starts from point and goes to right as tenths, hundreths and so on
The tens means multiply by 10
The tenth means tenth part of that digit which is that digit divided by 10
Place value of decimal numbers;
The given number is; 7.630
The given number can be written as;
7 and 0.630
Hence, the number can be pronounced as Seven and 630 thousandths.
However, we have,
Seven and six hundred thirty thousandths.
Hence, The representation of 7.630 in word form is; Seven and six hundred thirty thousandths.
Read more on place value;
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A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selected nine students. Their mean age was 19.1 years with a sample standard deviation of 1.5 years. What is the 99% confidence interval for the population mean?
A. [0.44,3.80]
B. [14.23,23.98]
C. [17.42,20.78]
D. [17.48,20.72]
Answer:
[tex]19.1-3.355\frac{1.5}{\sqrt{9}}=17.42[/tex]
[tex]19.1+3.355\frac{1.5}{\sqrt{9}}=20.78[/tex]
And the best option would be:
C. [17.42,20.78]
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
[tex]\bar X=19.1[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s=1.5 represent the sample standard deviation
n=9 represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
In order to calculate the critical value [tex]t_{\alpha/2}[/tex] we need to find first the degrees of freedom, given by:
[tex]df=n-1=9-1=8[/tex]
Since the Confidence is 0.99 or 99%, the value of [tex]\alpha=0.01[/tex] and [tex]\alpha/2 =0.005[/tex], and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that [tex]t_{\alpha/2}=[/tex]
Now we have everything in order to replace into formula (1):
[tex]19.1-3.355\frac{1.5}{\sqrt{9}}=17.42[/tex]
[tex]19.1+3.355\frac{1.5}{\sqrt{9}}=20.78[/tex]
And the best option would be:
C. [17.42,20.78]
One side of a right triangle is 10 centimeters. The longest side of the triangle is 26 centimeters. What is the length, in centimeters, of the other side of the triangle?
Triangle ABC is similar to Triangle FGH. What is the value of x in centimeters?
Given:
Given that the triangle ABC is similar to triangle FGH.
We need to determine the value of x.
Value of x:
Since, the triangles are similar, then their sides are proportional.
Thus, we have;
[tex]\frac{AC}{FH}=\frac{AB}{GF}=\frac{BC}{GH}[/tex]
Let us consider the proportion [tex]\frac{AB}{GF}=\frac{BC}{GH}[/tex] to determine the value of x.
Substituting AB = 9 cm, GF = 13.5 cm, BC = 15 cm and GH = x, we get;
[tex]\frac{9}{13.5}=\frac{15}{x}[/tex]
Cross multiplying, we get;
[tex]9x=15 \times 13.5[/tex]
[tex]9x=202.5[/tex]
[tex]x=22.5 \ cm[/tex]
Thus, the value of x is 22.5 cm
Hence, Option F is the correct answer.
Answer:
22.5
Step-by-step explanation:
{83,73,83,59,24,12,43, 83, 59}
What is the mean, median, mode, and range for the set
Look at the attached picture⤴
Hope it will help uh...:)
Answer:
Mean: 57.667
Median: 59
Mode: 83
Range: 71
Explanation
Mean = sum of values / number of values
[tex]\frac{x1+x2...xn}{n}[/tex] = [tex]\frac{83+73+83+59+24+12+43+83+59}{9}[/tex] = 57.667Median = middle number
values sorted smallest to largest: 12, 24, 43, 59, 59, 73, 83, 83, 83 = 59Mode = number that occurs most often
There are 3 83s, so 83 is the mode = 83Range = largest number minus smallest number
83 - 12 = 71