What steps are involved in converting potential energy to kinetic energy

Answer:

Boyle's Law

Explanation:

Robert Boyle in his experiment explained the relationship between the volume and the pressure of a gas. In his experiments, he discovered that the volume of a gas is inversely proportional to the pressure at constant temperature. This implies that as the volume of the gas increase, the pressure decreases and as the volume of the gas decrease, the pressure will increase.

Now applying this concenpt to the the plunger of a bicycle pump, you will discover that as the pressure of in the plunger increase, the volume of air inside the chamber is decreasing as it is send out to pump the flat tyre. This clearly indicates inverse proportionality between pressure and volume as explained by Boyle's law.

Therefore, the plunger of a bicycle pump clearly indicates Boyle's law in action.

The operation of a bicycle pump illustrates Boyle's Law. This law states that in a closed system at constant temperature, the volume and pressure of a gas are inversely proportional - as one increases, the other decreases.

The situation you described is an application of Boyle's Law, a concept in physics. Boyle's Law states that the pressure and volume of a gas have an inverse relationship when held at a constant temperature. This means that as the volume of gas decreases, like when you push down the plunger of a bicycle pump, the pressure increases.

When the plunger is pushed down, the volume inside the pump decreases, thereby increasing the pressure. This high-pressure air then moves from an area of high pressure (inside the pump) to an area of low pressure (the flat tire), resulting in air being pumped into the tire.

A practical example aiding understanding is a deflated tire. As we start pumping air into it, its volume first increases with not much increase in pressure. However, once the tire is filled to a point where the walls resist further expansion, pressure increases as more air is pumped in. Therefore, Boyle's Law explains the mechanics of a bicycle pump and similar systems pretty well.

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Answer:

the answer is ture

Explanation:

because the energy substances must absorb in order to change from liquid to gas

Answer:

Explanation:

Given that,

Mass of counterweight m= 4kg

Radius of spool cylinder

R = 8cm = 0.08m

Mass of spool

M = 2kg

The system about the axle of the pulley is under the torque applied by the cord. At rest, the tension in the cord is balanced by the counterweight T = mg. If we choose the rotation axle towards a certain ~z, we should have:

Then we have,

τ(net) = R~ × T~

τ(net) = R~•i × mg•j

τ(net) = Rmg• k

τ(net) = 0.08 ×4 × 9.81

τ(net) = 3.139 Nm •k

The magnitude of the net torque is 3.139Nm

b. Taking into account rotation of the pulley and translation of the counterweight, the total angular momentum of the system is:

L~ = R~ × m~v + I~ω

L = mRv + MR v

L = (m + M)Rv

L = (4 + 2) × 0.08

L = 0.48 Kg.m

C. τ =dL/dt

mgR = (M + m)R dv/ dt

mgR = (M + m)R • a

a =mg/(m + M)

a =(4 × 9.81)/(4+2)

a = 6.54 m/s

Answer:

a) τnet = 3.1392 N-m

b) L = (0.48 Kg-m)*v

c) a = 6.54 m/s²

Explanation:

Given

m = 4 Kg

R = 8 cm = 0.08 m

M = 2 Kg

a) τnet = ?

b) L = ?

c)  a = ?

Solution

a) We use the formula

τnet = R*m*g*Sin 90°

τnet = 0.08 m*4 Kg*9.81 m/s²*(1)

τnet = 3.1392 N-m

b) We apply the equation

L= R*m*v + R*M*v = R*(m + M)*v

then

L = (0.08 m)*(4 Kg + 2 Kg)*v = (0.48 Kg-m)*v

c) We use the relation

τ = dL/dt = d((0.48 Kg-m)*v)/dt = (0.48 Kg-m)*dv/dt

τ = (0.48 Kg-m)*a

then

τ/(0.48 Kg-m) = a

⇒   a = 3.1392 N-m/((0.48 Kg-m)

a = 6.54 m/s²

Answer:

T

Explanation:

momentum=mass×velocity

The momentum of an object is equal to the mass of the object times the velocity of the object which is true.

In Mechanics, momentum is calculated as the combination of an object's weight and speed. It has both a magnitude and a direction, making it a vector quantity. If an entity has weight m and speed v, then its momentum is given by,

p = mv

Where 'p' is the momentum, 'm' is the mass, and 'v' is the velocity.

Mass in motion is a definition of momentum. All things have mass, thus when something moves, it has momentum because its mass is in motion. The amount of momentum an object possesses depends on two factors: how much and how quickly the material is moving.

It is correct to say that an object's momentum is equal to its mass times its velocity.

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Answer:

57.16

Explanation:

The minimum weight of the ballast required to bring the CG of the aircraft within the given range is approximately 15.2 lbs. This is calculated using the weight of the aircraft, the distances the CG needs to move and the distance from the CG to the location where the ballast is placed.

The subject matter of this problem is physics, specifically dealing with the concept of Centres of Gravity (CG). In order to find the minimum weight of the ballast required to bring the CG within the given CG range, we first need to establish how far the current CG is from the lower limit of the range. That is 32.0 - 30.5 = 1.5 inches. We can assume that the weight required to move the CG 1 inch can be found using the formula: (Weight of aircraft X Distance CG needs to move) / Distance from CG to ballast. So, in this case, the minimum ballast weight will be: (4954 lbs * 1.5 inches) / (162 inches - 30.5 inches). Carrying out the calculations, this gives us a ballast weight of approximately 15.2 lbs.

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Answer:

D. Alaska is in the half of Earth that's illuminated longer by sunlight.

Explanation:

Alaska is closer to the north poll than Florida causing longer day during the summer because Alaska is facing the sun (roughly) 20 hours out of the day.

The change in gravitational potential energy of the book is 9.81 J.

The change in gravitational potential energy is calculated as follows:

ΔGPE = m * g * Δh

where:

In this case, the mass of the book is 2 kg, the acceleration due to gravity is 9.81 m/s², and the change in height is 0.5 m (2 m - 1.5 m).

Therefore, the change in gravitational potential energy is:

ΔGPE = 2 kg * 9.81 m/s² * 0.5 m = 9.81 J

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The energy transferred out of the system as heat is 3950 J, or in scientific notation, [tex]\rm \( 3.95 \times 10^3 \, \text{J} \)[/tex]

The amount of energy q required to change the temperature of a substance can be calculated using the formula:

[tex]\rm \[ q = m \cdot C \cdot \Delta T \][/tex]

Where:

m is the mass of the substance

C is the specific heat capacity of the substance

[tex]\rm\( \Delta T \)[/tex] is the change in temperature

Given that the change in temperature is from the system's current temperature to [tex]\( 0^\circ \text{C} \)[/tex], which is -T in Kelvin, and the specific heat capacity C is typically given in [tex]\rm \( \text{J/g}^\circ \text{C} \)[/tex], we can express the formula as:

[tex]\rm \[ q = m \cdot C \cdot (-T) \][/tex]

Given that the energy is to be expressed in joules, we need to use the SI unit for mass (kilograms) and convert the specific heat capacity to [tex]\rm \( \text{J/kg}^\circ \text{C} \)[/tex]

The conversion factor from [tex]\rm \( \text{J/g}^\circ \text{C} \)[/tex] to [tex]\( \text{J/kg}^\circ \text{C} \)[/tex] is 1000 since [tex]\( 1 \, \text{g} = 0.001 \, \text{kg} \)[/tex]:

[tex]\rm \[ C_{\text{SI}} = C_{\text{g}} \cdot 1000 \][/tex]

Now, we can use the formula to calculate q.

Given:

m (mass of the substance) = [tex]\rm \( 4.70 \, \text{kg} \)[/tex] (assuming mass)

C (specific heat capacity) = [tex]\rm \( 4.18 \, \text{J/kg}^\circ \text{C} \)[/tex]

T (temperature change) = [tex]\rm \( 0^\circ \text{C} - 20^\circ \text{C} = -20^\circ \text{C} \)[/tex]

Substitute the values:

[tex]\rm \[ q = (4.70 \, \text{kg}) \cdot (4.18 \, \text{J/kg}^\circ \text{C}) \cdot (-20^\circ \text{C}) \]\\\\rm q = -3949.6 \, \text{J} \][/tex]

Since the answer is expected in kilojoules (kJ), convert the value from joules to kilojoules:

[tex]\rm \[ q = -3949.6 \, \text{J} \\= -3.9496 \, \text{kJ} \][/tex]

Now, express the result with the correct number of significant figures:

[tex]\rm \[ q = -3.95 \, \text{kJ} \][/tex]

Since the question asks for the energy transferred out of the system as heat, take the absolute value:

[tex]\rm \[ q_{\text{abs}} = 3.95 \, \text{kJ} \\= 3950 \, \text{J} \][/tex]

Therefore, the energy transferred out of the system as heat is 3950 J, or in scientific notation, [tex]\rm \( 3.95 \times 10^3 \, \text{J} \)[/tex]

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To calculate the energy transfer in joules, we need the specific heat capacity of the substance, its mass, and the initial temperature. The formula for this is q = mcΔT. Without these values, we cannot provide a specific numerical answer.

To calculate how much energy needs to be transferred out of the system as heat in order to lower its temperature to 0°C, you would need more information. A key factor of this calculation is the specific heat capacity of the substance in the system, as well as its mass. The formula for heat transfer is q = mcΔT, where m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Without the values of m and c as well as the initial temperature, it is not possible to provide a numerical answer in joules.

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Answer:

Yellow, green, polka dot and white jerseys

Explanation:

Tour de France is the biggest bicycle race in the world held at France over a period of 23 days. At the end of each day of racing they give to the certain riders FOUR different colored jerseys:

At the end of the competition, the total points are counted and the different jerseys are given to the overall winners.

Answer:

(a) Tension on both side of wire

[tex]T_1=46.706 N[/tex]

[tex]T_2=51.710 N[/tex]

(b) acceleration of the Box

[tex]a = 3.336 \frac{m}{sec^2}[/tex]

(c) The horizontal and vertical components

Horizontal component [tex]T_1=46.706 N[/tex]

Vertical Component  =130.19 N

Explanation:

Refer attached figure for details.

[tex]T_1\ \&\ T_2\ are\ tensions\ in\ the\ string\ and\ a\ is\ the\ acceleration\ of\ the\ masses.[/tex]

Applying Newton's 2 law of motion for 14 kg block in horizontal direction

[tex]T_1 = 14\ a[/tex]-----------(i)

Similarly, applying Newton's 2 law of motion for 8 kg block in vertical direction

[tex]8 g - T_2 =8 a[/tex]-----(ii)

Consider the case of pulley,

[tex]\tau_e_x_t= I\alpha--------(iii)\\\\Where,\\\tau_e_x_t =Torque\ acting\ on\ the\ pulley\\I=moment\ of\ inertia\ of\ pulley\\\alpha= angular\ acceleration[/tex]

where,

[tex]I= \frac{MR^2}{2} (for\ pulley\ disk)[/tex]

[tex]I=\frac{3\cdot0.5^2}{2} =0.375\ kgm^2[/tex] (since mass of the pulley = 3 kg & Radius = 0.5 m)

&[tex]\tau_e_x_t= Net\ force \cdot Distance\ from\ application\ point[/tex]

Hence [tex]\tau_e_x_t = (T_2-T_1) \cdot \frac{1}{2} = 0.375\cdot\alpha[/tex]

[tex]T_2-T_1=0.75\cdot\alpha[/tex]--------(iv)

Relation between linear acceleration (a) and angular acceleration (α) is as follows,

[tex]a = R\alpha=0.5\cdot\alpha \ (R\ is \ radius\ of \ pulley)[/tex]

[tex]\alpha=2a[/tex]--------------------(v)

Putting the value of (v) in to (iv)

[tex]T_2 -T_1= 1.5 a[/tex]---------(vi)

adding equation (i),(ii) & (vi) gives

8g =22 a + 1.5 a

[tex]a = 3.336 \frac{m}{sec^2}[/tex]

now putting the value of a in equation (i) & (ii) we get

[tex]T_1=46.706 N[/tex]

[tex]T_2=46.706 +1.5 \cdot 3.336[/tex] = 51.710 N

(a) Hence Tension on both side of wire

[tex]T_1=46.706 N[/tex]

[tex]T_2=51.710 N[/tex]

(b) acceleration of the Box

[tex]a = 3.336 \frac{m}{sec^2}[/tex]

(c) The horizontal and vertical components

Horizontal component [tex]T_1=46.706 N[/tex]

Vertical Component = [tex]T_2+8\cdot g[/tex] =51.710 + 8 x 9.81 =130.19 N

Answer:

Tension, T1 = 46.2 N and T2 = 52 N, where as acceleration = 3.3 ms^-2.

Forces on the pulley are 46.2 N , 81.4 N horizontal and vertical

respectively.

Explanation:

Given:

Mass of the box on rest,[tex]m_1[/tex] = 14 kg

Mass of the attached box,[tex]m_2[/tex] = 8 kg

Mass of the pulley, [tex]m_3[/tex] = 3 kg

Diameter of the pulley, [tex]d[/tex] = 1 m

Radius of the pulley, [tex]r[/tex] = 0.5 m

Here we will be using the concept of net force ([tex]F_n_e_t[/tex]),net torque ([tex]\tau_n_e_t[/tex]) and acceleration of the pulley .

A FBD is attached with.

Lets find the tension on the wire using Fnet.

⇒ [tex]T_1=m_1(a)[/tex]                                                                                       ...for m1

⇒ [tex]m_2g-T_2=m_2(a)[/tex] can be written as [tex]T_2=m_2g-m_2(a)[/tex]                ...for m2

Considering clockwise torque as negative and anticlockwise torque as positive.

Moment of inertia (I) of the disk/pulley = [tex]\frac{m_3r^2}{2}[/tex] and [tex]\alpha=\frac{a}{r}[/tex] .

Now using net torque on the pulley we can say that.

⇒ [tex](T_2-T_1)r=I\alpha[/tex]

⇒ [tex](T_2-T_1)r=\frac{m_3r^2}{2}\times \frac{a}{r}[/tex]

⇒ [tex](T_2-T_1)=\frac{m_3a}{2}[/tex]

⇒ Plugging T1 and T2 .

⇒ [tex]m_2g-m_2a-m_1a=\frac{m_3a}{2}[/tex]

⇒ Isolating a from the rest.

⇒ [tex]m_2g=\frac{m_3a}{2}+m_2a+m_1a[/tex]

⇒ [tex]m_2g=a\ [\frac{m_3}{2}+m_2+m_1][/tex]

⇒ [tex]\frac{m_2g}{\frac{m_3}{2} +m_2+m_1} =a[/tex]

⇒ Plugging the numeric value

⇒ [tex]\frac{(8\times 9.8)}{(\frac{3}{2} +8+14)} =a[/tex]

⇒ [tex]3.3 =a[/tex]

⇒ Acceleration = 3.3 [tex]ms^-^2[/tex]

So,

(a).

Tension in the wire

⇒ [tex]T_1=m_1(a)=14\times 3.3 =46.2\ N[/tex]

⇒ [tex]T_2=m_2g-m_2(a)=8(9.8-3.3)=52\ N[/tex]

(b).

The acceleration of the box is 3.3 ms^-2.

(c).

Forces on the pulley.

Horizontal force, [tex]P_H[/tex] = [tex]T_1[/tex] = [tex]46.2\ N[/tex]

Vertical force,[tex]P_V[/tex] = [tex]T_2+m_3g[/tex] = [tex]52+3(9.8)[/tex] = [tex]81.4\ N[/tex]

The values are as follows:

Tension as T1 = 46.2 N and T2 = 52 N ,where as acceleration =3.3 ms^-2.

Forces on the pulley are 46.2 N , 81.4 N horizontal and vertical

respectively.

Answer:

A thin wire has a higher resistance than a thick wire

A short wire has a lower resistance than a long wire

A warm wire has a higher resistance than a cool wire

Explanation:

Here we have the formula for resistance by diameter given as follows

[tex]R = \frac{4 \times \rho \times l}{\pi } \times \frac{1}{d^2}[/tex]

Where:

R = Resistance

ρ = Resistivity of the wire

l = Length of the wire

d = Diameter of the wire

a. Therefore, since resistance is inversely proportional to diameter of the wire, a thin wire

A thin wire produces a higher resistance value than a thicker wire with larger diameter, d

b. Also as resistance is directly proportional to the length of the wire, a long wire has a higher resistance value than a short wire

c. The formula for resistance of a wire with temperature is as follows;

[tex]R_T = R_0 \times [1 + \alpha \times (T - T_{20})][/tex]

Where:

R₀ = Copper resistance at 20°

[tex]R_T[/tex] = Copper resistance at temperature T

T = Copper conductor temperature

T₂₀ = 20°

α = Copper coefficient of resistivity

Therefore, as the temperature increase, the resistance increases.

Answer:

thin wire has  

✔ more

 resistance than a thick wire.

A short wire has  

✔ less

 resistance than a long wire.

A warm wire has  

✔ more

 resistance than a cool wire.

Explanation:

Answer:

6 m/s²

Explanation:

We know that the force acting on an object varies directly with the acceleration. The force, F, and acceleration, a, are related by:

F = m * a

Where m is the mass of the object

We then need to find the mass of the object before we can find its acceleration when the force is 30 m/s².

Therefore, when the force is 20 N and the acceleration is 4 m/s²:

20 = m * 4

=> m = 20/4 = 5 kg

The mass of the object is 5 kg. Hence, we can find the acceleration of the object when the force is 30 N

30 = 5 * a

=> a = 30/5 = 6 m/s²

The acceleration of the object is 6 m/s²

Answer:

6m/s²

Explanation:

According to Newton's second law

Force F acting on an object varies directly with the object's acceleration a. Mathematically it is expressed as

F = ma where;

m is the mass of the object

F is the applied force

a is the acceleration

Let m be constant

m = F/a

If a force of 20 N acts on a certain object with an acceleration of 4m/s²

m = 20/4

m = 5kg

If the force is changed to 30 N, its new acceleration can be gotten using the previous formula.

F = ma

a = F/m

a = 30/5 (since mass is kept constant)

a = 6m/s²

Answer:

When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line

Answer:

The magnitude of change in momentum of the ball is [tex]97.5 m[/tex] and impulse is also [tex]97.5 m[/tex]

Explanation:

Given:

Velocity of a pitched ball [tex]v _{i} = 47[/tex] [tex]\frac{m}{s}[/tex]

Velocity of ball after impact [tex]v_{f} = -50.5[/tex] [tex]\frac{m}{s}[/tex]

From the formula of change in momentum,

  [tex]\Delta P = m (v_{f} -v_{i} )[/tex]

Here mass is not given in question,

Mass of ball is [tex]m[/tex]

Change in momentum is given by,

[tex]\Delta P = m (-50.5 -47)[/tex]

[tex]\Delta P = -97.5 m[/tex]

Magnitude of change in momentum is

[tex]\Delta P = 97.5 m[/tex]

And impulse is given by

 [tex]J = \Delta P[/tex]

[tex]J = -97.5 m[/tex]

So impulse and

Therefore, the magnitude of change in momentum of the ball is [tex]97.5 m[/tex] and impulse is also [tex]-97.5 m[/tex]

Answer:

Magnetic compass

Explanation:

A magnetic field is a field that describes the magnetic effect of electric charges in a relative motion.

Magnetic field allows magnets to interact without contact. The principle involved in the function of the compass is that a magnetic field exerts a force on any moving charge and can be measured and detected by this effect.

Answer:

Magnetic compass

Explanation:

The magnetic compass is the most familiar compass type. It functions as a pointer to "magnetic north", the local magnetic meridian, because the magnetized needle at its heart aligns itself with the horizontal component of the Earth's magnetic field

Compasses are mainly used in navigation to find direction on the earth. This works because the Earth itself has a magnetic field which is similar to that of a bar magnet (see the picture below). The compass needle aligns with the Earth's magnetic field direction and points north-south.

Answer:

The two word term is "ICE SHOVES"

Explanation:

An ice shove also known as ice surge, ice heave, ivu, or shoreline ice pileup is simply a surge of ice which occurs from an ocean or large lake and drops on the shore. These ice shoves are usually caused by ocean currents, strong winds, or temperature differences which tend to push the ice to the shore. The ice shoves can create ice piles up to 12 metres high and more.

Ice shoves has been recorded in at least three lakes in the past years. They are Lake Dauphin (Manitoba, Canada), Mille Lacs Lake (Minnesota), Lake Winnebago (Wisconsin), etc.

Answer:

ICE SHOVE

Explanation:

An Ice Shove is a situation or phenomenon that occurs when the wind carries or pushes melting ice from frozen lakes down to the lake shore.

Agents involved in the pushing of melting ice down to the lake shore includes: currents in the ocean, very strong winds as well as variations and fluctuations in the temperature of the lake.

Ice shoves can result in a pile up and accumulation of ice on the lake shore to be at about 30-40 feet high.

Ice shoves can result in negative effects in the lives of living organisms. Such negative effects includes:

a. Damages to the shoreline of the lakes

b. Damages to the habitats of any living organisms by the lake.

c. Damages to structures (buildings) that can be found at the lake shore.

Answer:

[tex]2.7\cdot 10^{16} J[/tex]

Explanation:

We can approximate the hurricane as a rotating uniform cylinder, so its energy is the rotational kinetic energy, given by:

[tex]E=\frac{1}{2}I\omega^2[/tex] (1)

where

I is the moment of inertia

[tex]\omega[/tex] is the angular velocity

The moment of inertia of a cylinder rotating about its axis is

[tex]I=\frac{1}{2}MR^2[/tex]

where

M is the mass

R is the radius

So formula (1) can be written as

[tex]E=\frac{1}{2}(\frac{1}{2}MR^2)\omega^2=\frac{1}{4}MR^2\omega^2[/tex] (2)

For an object in rotation, the linear speed at the edge is related to the angular velocity by

[tex]v=\omega R[/tex]

So we can rewrite (2) as

[tex]E=\frac{1}{4}Mv^2[/tex]

where we have:

[tex]v=100 km/h = 27.8 m/s[/tex] is the speed at the edge of the hurricane

We have to calculate the mass of the cylinder. We have:

[tex]R=88 km = 88,000 m[/tex] (radius)

[tex]h=4.4 km = 4400 m[/tex] (height)

So the volume is

[tex]V=\pi R^2 h = \pi (88,000)^2 (4400)=1.07\cdot 10^{14} m^3[/tex]

The density is

[tex]\rho = 1.3 kg/m^3[/tex]

So the mass is

[tex]M=\rho V=(1.3)(1.07\cdot 10^{14})=1.39\cdot 10^{14} kg[/tex]

Therefore, the energy is

[tex]E=\frac{1}{4}(1.39\cdot 10^{14})(27.8)^2=2.7\cdot 10^{16} J[/tex]

If we do the simple equation of 4,000J subtracted by 2,500J  we can easily see that the energy that wasn't useful or wasted is 1,500J

Answer:

4000J transfer and 2500J stored which means you have an energy produce power equals to 6500J. Therefore take 6500J and subtract it with 4000J transfer and there you left with 2500J. so the question is, how much energy is wasted? about 4000 of your energy is been transfer which means it moves out of the original source.

Explanation:

Answer:

α = - 0.00148 rad/s^2

Explanation:

Given:-

- The number of blades, n = 7

- The angular speed of blades, w = 0.5 rad/s

- The diameter of golf ball, d = 9.0 x 10^-2 m

- The speed of the ball, v = 0.1 m/s

Find:-

What is the angular acceleration of the windmill?

Solution:-

- We first need to visualize the ball "just passing" through between two successive blades. First we will determine the time taken (t) for the golf-ball to just pass the blades i.e it travelled a distance equal to its diameter (d) with given speed (v) to avoid the blades.

                                      d = v*t

                                      t = d / v

                                      t = 0.09 / 0.1

                                      t = 0.9 s

- It takes t = 0.9s for the golf-ball to just pass the windmill. The same amount of time is taken by the windmill blade to cover an arc distance (s) that is equivalent to the diameter of the ball (d) which is also the width of empty space between two successive blades. The angle (θ) between each blade - denoting empty space can be determined by the seeing that all 7 blades are equally spaced in a circle. So:

                                    θ = 2π / 2*n

                                    θ = π / 7

                                    θ = 0.44879 rads

- So the angular speed of the windmill blade (wf) when the ball passes through can be determined by the formula:

                                    wf = θ / t

                                    wf = 0.44879 / 0.9

                                    wf = 0.49866 rad/s

- Now we will use the first rotational kinematics equation of motion with constant angular acceleration ( α ) as follows:

                                   wf = wi + α*t

- Solve for  ( α ) :

                                    α = ( wf - wi ) / t

- Plug in the values and evaluate ( α ):

                                    α = ( 0.49866 - 0.5 ) / 0.9

                                    α = - 0.00148 rad/s^2

the answer is -183 degree celcius

Answer:

90= C+273

C=273-90= - 183

Answer:

True

Explanation:

This can be done when the output gear is rotating in a counterclockwise direction. The initial direction of the clockwise gear changes when it comes in contact with the counter clockwise rotating gear. This will thus cause the motor to change its direction due to the counter clockwise rotating gear.

Answer:

Common stock

Explanation:

Common stock is also regarded to as shares in which dividends are paid to the holders according to how profitable the organization is.

Common stock is a type of equity security and it is also the least considered in the case of bankruptcy due to its variability and the probability of stockholders not getting anything because of the debtor being insolvent.

Answer:

1.2 A

Explanation:

We are given that

Time, dt=78 ms=[tex]78\times 10^{-3}s[/tex]

[tex]1 ms=10^{-3} s[/tex]

[tex]I_s=4.1mA=4.1\times 10^{-3} A[/tex]

[tex]1 mA=10^{-3}A[/tex]

[tex]R=12\Omega[/tex]

[tex]M=3.2mH=3.2\times 10^{-3} H[/tex]

We have to find the change in the primary current.

[tex]V_s=I_sR=4.1\times 10^{-3}\times 12=49.2\times 10^{-3} V[/tex]

[tex]V_s=M\frac{dI}{dt}[/tex]

[tex]dI=\frac{V_sdt}{M}=\frac{49.2\times 10^{-3}\times 78\times 10^{-3}}{3.2\times 10^{-3}}[/tex]

[tex]dI=1.2 A[/tex]

Final answer:

Another term for a Lewis structure diagram is an 'electron-dot diagram,' which represents the valence electrons of an atom as dots around the element's symbol and is used to visualize the bonding and non-bonding electrons in molecules.

Explanation:

Another term for a Lewis structure diagram is an electron-dot diagram. A Lewis structure diagram is a representation that shows the valence electrons of an atom as dots around the symbol of the element. The dots represent the number of valence electrons present in the atom and are arranged around the chemical symbol in a specific manner with a maximum of two dots on one side. For instance, the Lewis diagram for hydrogen would consist of the symbol 'H' with one dot next to it, representing its single valence electron.

The Lewis diagram is also referred to as a Lewis dot diagram and is used to visualize the bonding between atoms as well as non-bonding valence electrons. When atoms bond, the shared electrons are represented by lines, and lone pairs are depicted by dots surrounding the atoms. These diagrams help in predicting the shape of molecules and the arrangement of atoms.

Answer: slipping on a patch of ice (A)

Explanation: there is direct contact when you slip on a patch of ice: your body, and the ice. all of the other answers are either non contact, or it is not solid to solid (wind, water). hope that makes sense :)

Kepler's Third Law helps calculate the period of satellites orbiting Earth based on their radius, aiding in various applications.

Kepler's Third Law: The period of an orbiting object is related to the radius of its orbit. Using the formula n²a³ = GM (where n is the mean motion, a is the semi-major axis, and GM is the product of the gravitational constant and the Earth's mass), we can calculate the period of the satellite's circular orbit.

Calculations: For a satellite at an altitude of 20,200 km above Earth's surface (a = 26,578 km), with GM = 3.986005 x 10¹⁴ m³/s², the period T comes out to be 43,122 seconds.

Application: Understanding Kepler's laws helps in determining crucial parameters for artificial satellites orbiting Earth, aiding in satellite communication, weather observation, and other scientific endeavors.

Answer: higher temperature increases reaction rates for both endothermic and exothermic reactions

Explanation: i took the test

The wrong statement with the student's reasoning is Higher temperature increases reaction rates for both endothermic and exothermic reactions. Hence option A is correct.

When the reactant absorbs heat energy from the surroundings to form products is called an endothermic reaction. When the heat is absorbed from the surroundings, the system remains cooler and the enthalpy of the system increases.

When the energy is released in the form of heat to form the product is called an exothermic reaction. In this reaction, the temperature of the substance increases due to the release of heat, and the enthalpy of the system decreases.

If the temperature increases the reaction rates increase in the exothermic reaction and it decreases in the endothermic reaction. Hence, increases in temperature increases the reaction rates for both endothermic and exothermic reactions is wrong.

Hence, the ideal solution is A.

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The process of removing heat from a place where it is not wanted and transferring that heat to a place where it makes little or no difference is known as B) refrigeration.

The evaporator in a refrigeration device must be chillier than the refrigerated space for the purpose to take in heat. The boiling factor of a refrigerant ought to be low sufficient at atmospheric strain to preserve the machine stress above 0 PSIG when working at low temperatures.

The evaporator can be thought of as a “warmness sponge.” Vapor is more dense than liquid and, because the liquid refrigerant boils, it has a tendency to sink. The handiest area wherein the refrigerant vapor is superheated is within the evaporator.

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The hydrostatic force on one end of the trough can be found using the formula F = pghA, where p is the density of the liquid, g is the acceleration due to gravity, h is the height of the liquid, and A is the area of the end of the trough. In this case, the ends of the trough are equilateral triangles with sides 4m long.

To find the hydrostatic force on one end of the trough, we can use the formula F = pghA, where F is the force, p is the density of the liquid, g is the acceleration due to gravity, h is the height of the liquid, and A is the area of the end of the trough. Since the ends of the trough are equilateral triangles, each side has a length of 4m. The area of an equilateral triangle is given by A = sqrt(3)/4 * s^2, where s is the length of the side. In this case, A = sqrt(3)/4 * (4m)^2 = 4sqrt(3)m^2. Plugging in the values, we have F = (835kg/m^3)*(9.8m/s^2)*h*(4sqrt(3)m^2).