What would the total bill be of painting the costs $44.80 with the tax rate of 6%?

Final answer:

The surface area of a cylinder with a given radius of 3 cm and height of 18.2 cm is calculated using the formula 2πr(height + r), which results in approximately 400.1 square centimeters.

Explanation:

The question asks to find the surface area of a cylinder with a radius of 3 cm and a height of 18.2 cm, using 3.14 for pi. The formula for the surface area of a cylinder is 2πr(height + r), where r is the radius, and the height is the vertical dimension of the cylinder.

Plugging in the given values:

We get: Surface Area = 2 * 3.14 * 3 * (18.2 + 3) = 2 * 3.14 * 3 * 21.2 = 400.1 cm²

Therefore, the surface area of the cylinder, rounded to the nearest tenth, is 400.1 square cm.

Answer: The correct answer is 8

A polynomial of one-variable is given by following expression :-

[tex] Ax^n + Bx^{n-1} +Cx^{n-2}+Dx^{n-3}+Ex^{n-4}+..... [/tex]

where A, B, C, D, E are the coefficients of terms in the polynomial and x is variable of the equation.

A is the leading coefficient and it can not be zero i.e. A≠0.

n is the degree of the polynomial.

It says to write a trinomial in one variable of degree 5.

Trinomial means only three terms with non-zero coefficients, and degree 5 means n = 5.

There could be many answers, but an example of "trinomial of degree 5" would be :-

[tex] Ax^5 + Bx^4 + Cx^3 [/tex]

[tex] 3x^5 + 5x^4 + 2x^3 [/tex]

A trinomial in one variable of degree 5 in standard form is [tex]\( ax^5 + bx^3 + cx \),[/tex] where [tex]\( a \), \( b \), and \( c \)[/tex] are non-zero coefficients and [tex]\( a \neq 1 \)[/tex].

A trinomial is a polynomial with three terms. The degree of a polynomial is the highest power of the variable that appears in the polynomial with a non-zero coefficient. Since we are asked to write a trinomial of degree 5, the highest power of the variable x must be 5.

The standard form of a polynomial lists its terms in descending order of their degrees. Therefore, the first term of our trinomial must be [tex]\( ax^5 \),[/tex] where a is a non-zero coefficient, and [tex]\( a \neq 1 \)[/tex] to ensure that the coefficient is explicit.

Since we want a trinomial, we need two more terms. The next term should have a lower degree, and since we're dealing with a degree 5 polynomial, the next possible lower odd degree is 3 (we choose an odd degree to maintain the trinomial structure with distinct powers). This gives us the second term [tex]\( bx^3 \),[/tex] where b is also a non-zero coefficient.

The third and final term of our trinomial must have a degree lower than 3. The next possible lower odd degree is 1, which gives us the term [tex]\( cx \),[/tex] where c is again a non-zero coefficient.

Putting it all together, we have the trinomial [tex]\( ax^5 + bx^3 + cx \)[/tex] as the standard form of a degree 5 polynomial with three terms.

In this exercise we have to use the knowledge of quadrilaterals to calculate the measures of each side of the square, in this way we can say that it will be valid:

[tex]ZX = WY = 6[/tex]

Given in the exercise that each the value of:

The diagonals  of a square are congruent, and bisect each other, that will help to find:

[tex]WT=3\\ ZX = WY = 2(WT) = 6[/tex]

See more about square at brainly.com/question/13747846

Answer:

The answer above is the correct answer

To factor an expression, you need to analyze it and find a common variable or expression on the expression given. In this expression, you can observe that the expression x^2 – 7 is common to the two terms. You need to factor it out from the both of them.

4x (x^2 – 7) + 3 (x^2 – 7)

(x^2 – 7) (4x + 3)

This is already the complete factor of the expression.

Look at the picture.

Answer:

A'(-1, 1), B'(-2, 1), C'(-2, 2), D'(-1, 3)

Answer:

A' = (-1,3)   -  A = (3,11)

B' = (-2,2)  -  B = (2,2)

C' = (-2,1)  -  C = (1,2)

D' = (-1,1)  -   D = (1,1,)

Step-by-step explanation:

We have the polygon ABCD transformed to the polygon A'B'C'D' with the co-ordinates,

A' = (-1,3), B' = (-2,2), C' = (-2,1) and D' = (-1,1).

Since, the polygon is rotated 90 counterclockwise about the origin.

The co-ordinates (x,y) of ABCD will change to (-y,x) for A'B'C'D'.

So, we will change the co-ordinates (-y,x) of A'B'C'D' to (x,y) which gives the co-ordinates of ABCD.

That is,

Take the y-value to the 1st position and x-value to the second multiplied by negative sign.

Thus, we have,

A' = (-1,3)   ------------------  A = (3,1)

B' = (-2,2)   ------------------ B = (2,2)

C' = (-2,1)   ------------------ C = (1,2)

D' = (-1,1)   ------------------- D = (1,1,)

Answer: x=Y^2-6y+50

For APEX

Answer:

x=y^2-6y+50 i need to have more than characters so hdgyhejdufcyhgedhwbsnjdeufhdebwjnkdeufyhedgbw

we know that

A positive number minus a negative number is equal a positive number

so

we have

[tex]5,783-(-500,500)=5,783+500,500=506,283[/tex]

therefore

the answer is

A positive number

We need to find the area of the regular polygon as shown in the image.

Now in a regular hexagon the line joining the center and the vertex of a hexagon have the same length as the length of each side. (Refer the attached image)

[tex]10 \sqrt3cm=10 \times 1.732=17.32 cm[/tex]

A regular hexagon is made up of 6 equilateral triangles inside which means all the sides are of the same length.

Now, we know that the length of a side of an equilateral triangle is [tex]10 \sqrt 3[/tex] cm. So the area of one equilateral triangle is:

[tex]\frac{\sqrt 3}{4} \times (a)^2[/tex]

Where, 'a' is the side length of the equilateral triangle.

Therefore,  area [tex]= \frac{\sqrt 3}{4} \times (10 \sqrt3)^2= \frac{\sqrt 3}{4} \times 100 \times 3=75 \sqrt3[/tex] square centimeters.

Now that we have the area of one equilateral triangle and there are 6 of them in a regular hexagon we can find the area of hexagon.

So, the area of given regular polygon is [tex]=6 \times 75 \sqrt 3=450 \sqrt 3 cm^2[/tex].

The equation of a line that is perpendicular to the given line is                 y = -4/3x + c.

The equation of a line means an equation in x and y whose solution set is a line in the (x,y) plane. The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term.

For the given situation,

The equation of a line is y = 3/4x - 1/2 ------ (1)

The general form of equation of line in slope intercept form is

[tex]y=mx+c[/tex]

On comparing the equation 1 with general form,

Slope of the line, [tex]m=\frac{3}{4}[/tex]

Then, the slope of the line perpendicular to the given line is [tex]\frac{-1}{m}[/tex]

⇒ [tex]\frac{-1}{m}=\frac{-1}{\frac{3}{4} }[/tex]

⇒ [tex]\frac{-1}{m}=\frac{-4}{3}[/tex]

No points were defined that this 'normal' should pass through, so its intercepts are indeterminate.

Thus the equation of line in slope intercept form is

[tex]y=\frac{-4}{3}x+c[/tex]

Hence we can conclude that the equation of a line that is perpendicular to the given line is y = -4/3x + c.

Learn more about equation of a line here

https://brainly.com/question/1548429

#SPJ2

The correct answer is option B. -1.5.

To calculate the z-score for a wide receiver who dropped 13 footballs over the course of a season, we use the z-score formula:

z = (X - μ) / σ

where:

Substitute the values into the formula:

z = (13 - 16) / 2

This simplifies to:

z = -3 / 2 = -1.5

Therefore, the z-score for a wide receiver who dropped 13 footballs is B. -1.5.

Answer:

The answer is A