When 38.0 g of N2 is reacted with H2 and 40.12 g of NH3 are produced, what is the percent yield?

Answer:

hydrogen

Explanation:

Answer : The final pressure of the gas is, [tex]2.47\times 10^3mmHg[/tex]

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 545 mmHg

[tex]P_2[/tex] = final pressure = ?

[tex]V_1[/tex] = initial volume = 775 mL

[tex]V_2[/tex] = second volume = 171 mL

Now put all the given values in the above equation, we get:

[tex]545mmHg\times 775mL=P_2\times 171mL[/tex]

[tex]P_2=2470.03mmHg=2.47\times 10^3mmHg[/tex]

Therefore, the final pressure of the gas is, [tex]2.47\times 10^3mmHg[/tex]

Answer:

Explanation:

SO3 (g) + NO (g) U SO2 (g) + NO2 (g)

occurs under these conditions. Calculate the value of the equilibrium constant, Kc, for the above reaction.

SO3 (g) + NO (g) U SO2 (g) + NO2 (g)

Initial (M) 2.00 2.00 0 0

Change (M) −x −x +x +x

Equil (M) 2.00 − x 2.00 − x x x

2 2 c 3

2

c 2

[SO ][NO ]

[SO ][NO]

(2.00 )

=

= −

K

x K

x

Since the problem asks you to solve for Kc, it must indicate in the problem what the value of x is. The concentration of

NO at equilibrium is given to be 1.30 M. In the table above, we have the concentration of NO set equal to 2.00 − x.

2.00 − x = 1.30

x = 0.70

Substituting back into the equilibrium constant expression:

2c 2 2c 2

(2.00 )

(0.70)

(2.00 0.70)

= − = −

x KxK

Kc = 0.290

Answer:

128g of Li, will react in this reaction

Explanation:

Before to start working, we need the reaction:

N₂ and Li react, in order to produce Li₃N (lithium nitride)

N₂ + 6Li → 2Li₃N

1 mol of nitrogen reacts with 6 moles of lithium

We convert the mass of N₂ to moles → 86.1 g . 1 mol/ 28g = 3.075 moles

1 mol of N₂ reacts with 6 mol of Li

Therefore, 3.075 moles of N₂ will react with 18.4 moles of Li

We conver the moles to mass → 18.4 mol . 6.94g / 1mol = 128 g

Answer:

1,000 -  2,000

Explanation:

Just look at the bar graph. The bar ends at about 1,500 which is between 1,000 - 2,000. That is the only valid answer for this problem.

The frequency of individuals with doctorates who work in the field of physical science is 0-1,000.

Physical science is a branch of natural science that studies non-living systems and the fundamental principles governing the physical world. It encompasses physics and chemistry, exploring the properties and behavior of matter and energy. Physics delves into the nature of space, time, motion, and force, addressing phenomena from the smallest particles to the vastness of the cosmos.

Chemistry, on the other hand, focuses on the composition, structure, properties, and changes of matter. Together, these disciplines provide a comprehensive understanding of the physical universe, forming the basis for technological advancements and contributing to our comprehension of the fundamental laws that govern the natural world.

Covalent network solids often have the highest melting points. These solids are characterized by a network of covalent bonds that extend throughout the material, creating a very stable and strong structure.

Materials with high melting points typically have strong intermolecular forces. In the case of covalent network solids, such as diamond (pure carbon) or silicon carbide, each atom is bonded to several others in a lattice structure, creating an incredibly strong bond throughout the entire structure. This extensive network of strong bonds requires a large amount of energy to break apart, thus resulting in very high melting points. Molecular solids, where molecules are held together by weaker forces such as van der Waals forces, generally have much lower melting points because these intermolecular forces are much easier to overcome. Ionic solids also have high melting points, but not typically as high as covalent network solids, due to the nature of ionic bonds which are strong, but localized between individual pairs of ions rather than throughout the entire structure.

Answer:

Eukaryote vote me brainleist

Explanation:

Answer:

0.2 mol

Explanation:

Use the given values to find the molar mass.  The molar mass is 40 g/mol.

23 + 16 + 1 = 40

Using the molar mass, convert grams to moles.

(8 g)/(40 g/mol) = 0.2 mol

You have 0.2 mol of sodium hydroxide.

Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure  = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂  = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

Answer:

The pressure will increase by a factor of 2 and is now 1664 torr

Explanation:

The question says for us to assume that temperature is constant. Now, since we are given pressure and volumw, we will use Boyle's law which is a law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature i.e V ∝ 1/P

Thus, PV = K

Where K is a constant.

So,

P₁•V₁ = P₂•V₂ = k

Where:

P₁ = Initial pressure

V₁ = Initial volume

P₂ = Final pressure

V₂ = Final volume = V₁/2

From the question, P₁ = 832 torr ; we are told that volume is decreased by 2,thus, V₂ = V₁/2

Now, we want to find out what will happen to the pressure P₂.

Let's make P₂ the subject;

P₁•V₁ = P₂•V₂

Thus, P₂ = (P₁•V₁)/V₂

Plugging in the relevant values to obtain ;

P₂  = (P₁•2V₁)/V₁

V₁ will cancel out and we have;

P₂  = 2P₁

Now, we are given that P₁ = 832 torr, Thus,

P₂ = 2P₁ = 2× 832 torr = 1664 torr

The rate of effusion of gas B is 728.32 m/s

Explanation:

Given:

Mass of A, m₁ = 46 g/mol

Rate of effusion of A, R₁ = 515 m/s

Mass of B, m₂ = 92 g/mol

Rate of effusion of B, R₂ = ?

We know:

[tex]\frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1} }[/tex]

Substituting the value we get:

[tex]\frac{515}{R_2} = \sqrt{\frac{92}{46} } \\\\\frac{515}{R_2} = \sqrt{2} \\\\R_2 = \frac{515}{\sqrt{2} } \\\\R_2 = 728.32 m/s[/tex]

Therefore, the rate of effusion of gas B is 728.32 m/s

Answer:

B. A disease wipes out several plant species.

Explanation:

This will be the most detrimental to the environment as it will decrease oxygen levels and many animals will lose their shelter.

- everything else happens every year and is common and normal.

A disease wiping  out several plant species will most likely cause the sustainability of an ecosystem to weaken.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Answer: 1.1g of copper

Explanation: We begin by writing the balanced reaction equation.

So we have : Cu(s) + 2AgNO3 (aq) ------> Cu(NO3)2 (aq) + 2Ag (s)

Molar mass of AgNO3 = 107.87 + 14.01 + 3(16.0) = 169.88g/mol, for 2 moles we then have 2 x 169.88 =339.76g.

Atomic mass of Copper = 64g approximately

From the equation the following deductions can be made:

339.76g of AgNO3 reacts with 64g of copper

5.65g of AgNO3 would react with 64/ 339.76 x 5.65 =1.062 approx 1.1g of copper.

Answer:

we need 1.06g of Cu to react with 5.65g of AgNO₃

Explanation:

C u +2 AgNO₃ = Cu(NO₃ )₂ + 2 Ag

the mole ratio between Copper and silver nitrate is 1:2  meaning we need  2 moles of silver nitrate for every mole of copper that takes part in the reaction.

the molar mass of Cu  is 63.55

the molar mass of AgNO₃ is 107.8682+ 14 + (16x3) = 107.8682+ 14 + 48=  169.87682≈169.88g

for every 63.55 g of Cu reaction with  2(169.88g of AgNO₃)= 339.736g of AgNO₃

if x grams of Cu react with 5.65 grams of AgNO₃

63.55g= 339.736g

x = 5.65g

cross multiply

339.736x = 5.65 x 63.55 = 359.0575

x = 359.0575/339.736 = 1.05687210069≈1.06

we need 1.06g of Cu to react with 5.65g of AgNO₃

Answer : The correct option is, (C) C to Fe

Explanation :

The given chemical reaction is:

[tex]2Fe_2O_3+3C\rightarrow 4Fe+3CO_2[/tex]

By the stiochiometry we can say that, 2 moles of [tex]Fe_2O_3[/tex] react with 3 moles of C to gives 4 moles of Fe and 3 moles of [tex]CO_2[/tex].

From the balanced chemical reaction we conclude that,

As, 3 moles of C produces 4 moles of Fe

So, 1 mole of C produces [tex]\frac{4}{3}[/tex] moles of Fe

That means, the moles of ratio of C to Fe is 4 : 3

Therefore, the correct option is (C) C to Fe

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂

The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

Answer:

Excess Vinegar

Explanation:

You will have excess vinegar

Answer:

I think b if not then c hopefully this helps

Answer:

All helium atoms have two protons, and no other elements have atoms with two protons. In the case of helium, the atomic number is 2. The atomic number of an element is usually written in front of and slightly below the element's symbol, like in the Figure below for helium.

Answer:

2037 L

Explanation:

Step 1:

The balanced equation for the reaction involving the burning of propane. This is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Determination of the number of mole in 1kg of propane (C3H8).

Mass of C3H8 = 1kg = 1000g

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Number of mole = Mass/Molar Mass

Number of mole of C3H8 = 1000/44

Number of mole of C3H8 = 22.73 moles

Step 3:

Determination of the number of mole of water produced by burning 1 kg of propane (C3H8). This is illustrated below:

From the balanced equation above,

1 mole of C3H8 boiled 4 moles of H2O.

Therefore, 22.73 moles of C3H8 will produce = 22.73 x 4 = 90.92 moles of H2O.

Step 4:

Determination of the volume of H2O. This is illustrated below:

1 mole of a gas occupy 22.4L.

Therefore, 90.92 moles of H2O will occupy = 90.92 x 22.4 = 2037 L.

Therefore, 2037 L of water is boiled by burning 1kg of propane (C3H8)

Answer: heating the canister

Answer:

heating the canister

Explanation:

Answer:

a) 13.2 moles [tex]2H_{2}O[/tex]

b) 79.33 grams of [tex]2H_{2}O[/tex]

Explanation:

First, we'll need to balance the equation

[tex]H_{2(g)} + O_{2(g)}[/tex] → [tex]H_{2}O_{(g)}[/tex]

There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.

[tex]H_{2(g)} + O_{2(g)}[/tex] → [tex]2H_{2}O_{(g)}[/tex]

Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the ([tex]H_{2}[/tex]) on the left.

[tex]2H_{2(g)} + O_{2(g)}[/tex] → [tex]2H_{2}O_{(g)}[/tex]

The equation is now balanced.

a) This can be solved with a simple mole ratio.

4.6 moles [tex]O_{2}[/tex] × [tex]\frac{2 moles H_{2}O}{1 mole O_{2}}[/tex] = 13.2 moles [tex]2H_{2}O[/tex]

b) This problem is solved the same way!

2.2 moles [tex]H_{2}[/tex] × [tex]\frac{2 moles H_{2}O}{2 moles H_{2}}[/tex] = 2.2 moles [tex]2H_{2}O[/tex]

However, this problem wants the mass of [tex]2H_{2}O[/tex], not the moles.

The molecular weight of [tex]2H_{2}O[/tex] is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,

4(1.008) + 2(15.999) = 36.03 g/mol

2.2 moles [tex]2H_{2}O[/tex] × [tex]\frac{36.03 g}{1 mol}[/tex] = 79.33 grams of [tex]2H_{2}O[/tex]

Answer:

M = 16.8 M

Explanation:

Data: HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

[tex]M=\frac{moles}{solution volume}[/tex]

The data is replaced in the given equation:

[tex]M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}[/tex]

Answer:

The correct answer is 16.8 M

Explanation:

The molarity (M) of a solution is the number of moles of solute in 1 liter of solution. The HNO₃ solution contains 12.6 moles of solute (in this case the solute is HNO₃) in 0.75 liters. In order to find the molarity, we have to divide the number of moles into the volume in liters as follows:

M = 12.6 moles/0.75 L = 16.8 moles/L = 16.8 M

Answer: nuclear

Explanation:

Nuclear energy resource causes the most safety concerns. Therefore, option C is correct.

Nuclear energy is the energy contained within an atom's nucleus, or core. Nuclear energy can be used to generate electricity, but it must be liberated from the atom first.

Nuclear power is a zero-emission source of clean energy. Fission, the process of splitting uranium atoms to produce energy, is used to generate power. The heat produced by fission is used to generate steam, which spins a turbine to generate electricity without emitting the harmful byproducts that fossil fuels do.

Coal, oil, and gas are by far the most significant contributors to global climate change, accounting for more than 75% of global greenhouse gas emissions and nearly 90% of total carbon dioxide emissions.

Thus, option C is correct.

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The two solutions AgNO3 and K2CrO4 react to give a precipitate along with an aqueous solution of KNO3. Hence, after the reaction is complete, KNO3 remains in the solution.

When the two aqueous solutions AgNO3 and K2CrO4 react, they produce solid silver chromate Ag2CrO4 as a precipitate and leave potassium nitrate KNO3 in the solution. The reaction is balanced as 2AgNO3 (aqueous) + K2CrO4 (aqueous) -> Ag2CrO4 (s) + 2KNO3 (aqueous). As the reaction proceeds, silver ions (Ag+) and chromate ions (CrO42-) combine to form the precipitate, leaving potassium ions (K+) and nitrate ions (NO3-) in the solution. Hence, after the reaction, the solution consists of KNO3 because it remains aqueous, with 1.00 M K+ and 1.00 M NO3-.

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Answer:

Succinate oxidation to fumarate The following reactions transform succinate to regenerate oxalacetate. The first of these reactions is carried out by an oxidation catalyzed by succinate dehydrogenase. The hydrogen acceptor is FAD, since the free energy change is insufficient to allow NAD to interact. The final product is fumarate.

Explanation:

The condensation reaction of GDP + Pi and the hydrolysis of Succinyl-CoA involve the H2O necessary to balance the equation.

Explanation:

A non-renewable energy source (also called a finite source) is a natural resource that cannot be readily replaced by natural means at a quick pace enough to keep up with consumption.

An example is a carbon-based fossil fuel.

Answer:

C. An energy source that cannot be reused or replaced

Explanation:

non-renewable = cannot be renewed

Answer:

The standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s) is -0.744 V

Explanation:

Here we have

1. Cr³⁺  + e − ⟶ Cr²⁺ E⁰₁ = − 0.407 V

2. Cr²⁺ + 2 e − ⟶ Cr ( s ) E⁰₂  = − 0.913 V

To solve the question, we convert, the E⁰ values to ΔG as follows

ΔG₁ = n·F·E⁰₁ and ΔG₂ = n·F·E⁰₂

Where:

F = Faraday's constant in calories

n = Number of e⁻

ΔG₁ = Gibbs free energy for the first reaction

ΔG₂ = Gibbs free energy for the second half reaction

E⁰₁  = Reduction potential for the first half reaction

E⁰₂ = Reduction potential for the second half reaction

∴ ΔG₁ = 1 × F × − 0.407 V

ΔG₂ = 2 × F  × − 0.913 V

ΔG₁  + ΔG₂  = F × -2.233 V which gives

ΔG = n × F × ΔE⁰ = F × -2.233 V  

Where n = total number of electrons ⇒ 1·e⁻ + 2·e⁻ = 3·e⁻ = 3 electrons

We have, 3 × F × ΔE⁰ = F × -2.233 V

Which gives ΔE⁰ = -2.233 V /3 = -0.744 V.

The standard reduction potential for the reduction half‑reaction of Cr(III) to Cr(s) is found by the summation of the standard reduction potentials of the half-reactions involved, giving -1.32V.

To calculate the standard reduction potential for the reduction half-reaction of Cr(III) to Cr(s), we first need to understand that a redox reaction is a sum of an oxidation half-reaction and a reduction half-reaction. In the given half-reactions, the first is for Cr3+ being reduced to Cr2+ and the second one is for Cr2+ being reduced to Cr(s).

From the given standard reduction potentials, the 1st reaction has E°1 = -0.407 V and the 2nd reaction has E°2 = -0.913 V. Therefore, to get from Cr3+ to Cr(s), we add both these half-reactions together, which also means we add their potentials together. The sum gives us the potential for the entire reaction, which is E°total = E°1 + E°2 = (-0.407V) + (-0.913V) = -1.32V.

Thus, the standard reduction potential for the reduction half-reaction of Cr(III) to Cr(s) is -1.32V.

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Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

Answer: 4M

Explanation:

Answer:

2.4 litters of water are required.

Explanation:

Given data:

Mass of LiF = 19.6 g

Molarity of solution = 0.320 M

Volume of water used = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 19.6 g/ 26 g/mol

Number of moles = 0.75 mol

Volume required:

Molarity = number of moles/ volume in L

Now we will put the values in above given formula.

0.320 M = 0.75 mol /  volume in L

Volume in L = 0.75 mol  /0.320 M

     M = mol/L

Volume in L = 2.4 L

2.36 liters of water is needed to dissolve 19.6 grams of LiF to create a 0.320 M solution.

To determine the volume of water needed to create a 0.320 M solution of LiF, we can use the formula:

[tex]\[ C = \frac{n}{V} \][/tex]

where [tex]C[/tex] is the concentration in moles per liter, [tex]n[/tex] is the number of moles of the solute, and [tex]V[/tex] is the volume of the solution in liters. We can rearrange this formula to solve for [tex]\( V \):[/tex]

[tex]\[ V = \frac{n}{C} \][/tex]

First, we need to calculate the number of moles of LiF:

[tex]\[ n = \frac{\text{mass of LiF}}{\text{molar mass of LiF}} \][/tex]

The molar mass of LiF is approximately 25.94 g/mol (6.94 g/mol for Li and 19 g/mol for F). Now we can calculate the number of moles of LiF:

[tex]\[ n = \frac{19.6 \text{ g}}{25.94 \text{ g/mol}} \][/tex]

[tex]\[ n \approx 0.755 \text{ mol} \][/tex]

Now that we have the number of moles, we can use the concentration to find the volume:

[tex]\[ V = \frac{0.755 \text{ mol}}{0.320 \text{ M}} \][/tex]

[tex]\[ V \approx 2.36 \text{ L} \][/tex]