When atoms are split, from which part of the atom is the energy released?


nucleus


electrons


isotopes

Final answer:

The net ionic equation for the reaction between solid chromium(III) hydroxide and nitrous acid is Cr(OH)3(s) + 3 H+(aq) → Cr3+(aq) + 3 H2O(l), after removing the spectator nitrate ions.

Explanation:

The question involves writing a net ionic equation for the reaction between solid chromium(III) hydroxide and nitrous acid. To start, write down the full balanced molecular equation:

Cr(OH)3(s) + 3 HNO2(aq) → Cr(NO3)3(aq) + 3 H2O(l)

Now write the full ionic equation:

Cr(OH)3(s) + 3 H+(aq) + 3 NO2⁻(aq) → Cr3+(aq) + 3 NO2⁻(aq) + 3 H2O(l)

Notice that the nitrate ions (NO2⁻) are present on both sides of the equation and thus are spectator ions. Removing the spectator ions gives us the net ionic equation:

Cr(OH)3(s) + 3 H+ (aq) → Cr3+ (aq) + 3 H2O(l)

It's important to verify that both sides of the equation are balanced with respect to both charge and mass. The equation above satisfies this requirement, with three positive charges on both sides and the same number of each type of atom on each side.

Final answer:

The net ionic equation for the reaction of solid chromium (iii) hydroxide with nitrous acid is Cr(OH)₃(s) + 3 HNO₂(aq) → Cr₃+(aq) + 3 NO₂−(aq) + 3 H₂O(l).

Explanation:

The net ionic equation for the reaction of solid chromium (iii) hydroxide with nitrous acid is:

Cr(OH)₃(s) + 3 HNO₂(aq) → Cr₃+(aq) + 3 NO₂−(aq) + 3 H₂O(l)

First, solid chromium (iii) hydroxide reacts with nitrous acid to form chromium ions, nitrite ions, and water.

In this reaction, the hydroxide ions combine with the hydrogen ions from the acid to produce water, and chromium (iii) hydroxide dissolves to leave behind chromium ions in solution.

Since chromium (iii) hydroxide is a weak base and does not dissociate into ions in its solid state, it is included as a whole compound in the net ionic equation. The nitrite ions and chromium ions remain in solution, indicating a chemical change has occurred.

Charcoal is black because it absorbs all the wavelengths of light, not reflecting any back to the eye. This is due to its porous structure and numerous carbon atoms.

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Answer:

Na+

Explanation:

Atoms may loose or gain electrons in order to attain octate.

Chemical species obtained after loosing or gaining electrons are called ions.

When an element losses electrons, positively charged ion is formed.

When an element gains electrons, negatively charged ion is formed.

Among the given, only Na+ carry a positive charge, rest are neutral.

Therefore, Na+ is an ion.

The radon is the decay byproduct of radium which emits alpha rays to convert into the lead or polonium. The alpha particles have less penetration inside the cell than the beta particle or gamma rays and have the more dangerous effect than these other days. In the environment, the high presence of radon enters into the lungs through breathing and start to decay. In their decay, it emits alpha rays, which acts as the carcinogenic agent in the body.

Final answer:

To calculate the number of moles of a gas sample in a 5.0 L container at 373 K and 203 kPa, one uses the Ideal Gas Law. By substituting the appropriate values into the equation and solving for 'n', the calculation yields approximately 0.328 moles of the gas under the specified conditions.

Explanation:

The question asks how many moles of a gas sample are in a 5.0 L container at 373 K and 203 kPa. To find the number of moles of gas, we use the Ideal Gas Law, which is PV = nRT. In this formula, P is the pressure (in kPa), V is the volume (in liters), n is the number of moles, R is the ideal gas constant (8.314 J/(mol·K) or 8.314 L·kPa/(mol·K)), and T is the temperature (in Kelvin).

First, we convert the pressure into kPa since R is given in L·kPa/(mol·K). The pressure is already in kPa. Then, we solve for 'n' (number of moles):

P = 203 kPa

V = 5.0 L

R = 8.314 L·kPa/(mol·K)

T = 373 K

Using the Ideal Gas Law:

n = PV / RT = (203 kPa × 5.0 L) / (8.314 L·kPa/(mol·K) × 373 K)

n = ​1015 / ​3093.402 = ​0.328 mol

Thus, under the given conditions, the 5.0 L container holds approximately 0.328 moles of the gas sample.

[tex]\boxed{{\text{22}}{\text{.69 g}}}[/tex] of methanol must be burned to produce 541 kJ of heat.

Further explanation:

Combustion reaction:

It is the reaction in which the reactant reacts with molecular oxygen to form carbon dioxide and a water molecule. Molecular oxygen acts as the oxidizing agent in these reactions. A large amount of heat is released and therefore combustion reactions are exothermic in nature.

The change in enthalpy that occurs due to the formation of one mole of the compound from its constituent elements is called the standard enthalpy of formation. It is represented by [tex]\Delta {H_{{\text{rxn}}}}[/tex] and its units are kJ/mol.

The combustion of methanol occurs as follows:

[tex]{\text{C}}{{\text{H}}_3}{\text{OH}}+\frac{3}{2}{{\text{O}}_2}\to{\text{C}}{{\text{O}}_2}+2{{\text{H}}_{\text{2}}}{\text{O}}[/tex]

The value of [tex]\Delta {{\text{H}}_{{\text{reaction}}}}[/tex] is -764 kJ/mol. This indicates the heat produced when one mole of methanol is combusted. The negative sign means the heat is released during the process.

The number of moles of methanol [tex]\left( {{\text{C}}{{\text{H}}_3}{\text{OH}}} \right)[/tex] required in the given reaction is calculated as follows:

[tex]\begin{aligned}{\text{Moles of C}}{{\text{H}}_3}{\text{OH}}&=\left({541{\text{ kJ}}} \right)\left( {\frac{{{\text{1 mol}}}}{{764{\text{ kJ}}}}}\right)\\&=0.708{\text{ mol}}\\\end{aligned}[/tex]

The formula to calculate the mass of methanol [tex]\left( {{\text{C}}{{\text{H}}_3}{\text{OH}}} \right)[/tex] is as follows:

[tex]{\text{Mass of C}}{{\text{H}}_3}{\text{OH}}=\left({{\text{Moles of C}}{{\text{H}}_3}{\text{OH}}}\right)\left({{\text{Molar mass of C}}{{\text{H}}_3}{\text{OH}}}\right)[/tex]          ...... (1)

The number of moles of [tex]{\text{ C}}{{\text{H}}_3}{\text{OH}}[/tex] is 0.708 mol.

The molar mass of [tex]{\text{ C}}{{\text{H}}_3}{\text{OH}}[/tex] is 32.04 g/mol.

Substitute these values in equation (1).

[tex]\begin{aligned}{\text{Mass of  C}}{{\text{H}}_3}{\text{OH}}&=\left({{\text{0}}{\text{.708 mol}}} \right)\left({\frac{{{\text{32}}{\text{.04 g}}}}{{{\text{1 mol}}}}}\right)\\&=22.688{\text{ g}}\\&\approx {\text{22}}{\text{.69 g}}\\\end{aligned}[/tex]

Therefore the mass of methanol burned is 22.69 g.

Learn more:

1. Calculate [tex]\Delta {\text{H}}[/tex] for the reaction using Hess law: https://brainly.com/question/11293201

2. Calculate the hydroxide ion concentration: https://brainly.com/question/11293214

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: methanol, CH3OH, combustion, 746 kJ, 541 kJ, mass of CH3OH, molar mass of CH3OH, 22.69 g, moles of CH3OH.

Answer:

_+_

Explanation:

Answer: N2o4 - N2 + 202

Explanation:

The number of atoms of any element in the given chemical formula is the number that is written on the food of the symbol of that element. The total number of atoms of oxygen in given molecule is 9.033  ×10²³.

Atom is the smallest particle of any matter. Atom combines to form element and element combine to form molecule or compound. Atom can be further divided into electron, protons and neutrons.

1 molecule of given molecule contain 5 atoms of oxygen

Molar mass of N₂O₅= 108.01 g/mol

given mass of  N₂O₅=32.4 g

Number of moles of N₂O₅= given mass÷molar mass =0.3mol

Number of atoms= 0.3 ×6.022×10²³

Number of atoms=1.8066 ×10²³

total number of atoms=5×1.8066 ×10²³

                                    =9.033  ×10²³atoms of oxygen

Thus the total number of atoms of oxygen in given molecule is 9.033  ×10²³.

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Final answer:

approximately 9.033 x 10^23 oxygen atoms.

Explanation:

Calculating the Number of Oxygen Atoms in 32.4 g of N2O5

To determine the number of oxygen atoms in 32.4 g of N2O5, we first need to understand the concept of moles and how it relates to the mass of a substance. N2O5 has a molecular mass of 108.02 amu. This means one mole of N2O5 weighs 108.02 grams and contains Avogadro's number of molecules. Using the equation for calculating moles, where n is the number of moles, m is the mass of the substance in grams, and M is the molar mass of the substance in g/mol, the formula is:

n = m / M

Substituting the given values:

n = 32.4 g / 108.02 g/mol ≈ 0.3 moles of N2O5

Since each molecule of N2O5 contains 5 oxygen atoms, we multiply the number of moles of N2O5 by 5 and then by Avogadro's number (6.022 x 1023) to get the total number of oxygen atoms:

Total oxygen atoms = 0.3 moles x 5 x 6.022 x 1023 ≈ 9.033 x 1023 oxygen atoms

Explanation:

Number of Ca atom = 1

Number of S atom = 1

Number of O atom = 6

Number of H atom = 2

Number of Ca atom = 2 × 6 = 12

Number of H atom = 2 × 10 = 20

Number of O atom = 2 × 5 = 10

Number of Al atom = 2

Number of Cl atom = 1

Number of O atom = 5

Number of H atom = 5

The answers a (apex)

The right answer is the salts precipate out of solution.

There are two types of current evaporites:

* the evaporites of free water, coming from the evaporation of a body of water;

* capillary evaporites resulting from the precipitation of the salts of an intertitle brine in the pores of a sediment.

The formation of evaporites is favored by the arid climate and the confinement of the environment. Nevertheless temperate but very windy coastal areas are also the seat of a strong evaporation.

In the current salt marshes, the confinement of the body of water is accompanied by an intense biological activity: insect larvae, algae, bacteria.

To calculate the number of moles of H2O formed, determine the moles of CH3OH involved in the reaction, convert the volume of CH3OH to mass using its density, convert the mass of CH3OH to moles using its molar mass, and use the balanced chemical equation to determine the stoichiometry between CH3OH and H2O.

To calculate the number of moles of H2O formed, we first need to determine the number of moles of CH3OH and O2 involved in the reaction.

1. Convert the volume of CH3OH to mass using its density:

Mass of CH3OH = Volume of CH3OH x Density = 50.0 mL x 0.850 g/mL = 42.5 g

2. Convert the mass of CH3OH to moles using its molar mass:

Moles of CH3OH = Mass of CH3OH / Molar mass of CH3OH = 42.5 g / 32.04 g/mol = 1.327 mol

3. Use the balanced chemical equation to determine the stoichiometry between CH3OH and H2O:

1 mol of CH3OH produces 2 mol of H2O

Therefore, 1.327 mol of CH3OH will produce 2 x 1.327 = 2.654 mol of H2O

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The solution follows as;

Given:

CuSO4 – 9.70 (weight)

Water / H2O – 12.98 – 9.70 = 3.28 (weight)

Molecular weight of CuSO4 – 160

Molecular weight of H2O – 18

To solve;

= weight of CuSO4 x MW of CuSO4

= 970 / 160

= 328/x*18

= 6x = 18

= x – 3

= CuSO4*3H2O

Final answer:

The predominant intermolecular force in (CH3)2NH is hydrogen bonding, a strong type of dipole-dipole interaction that occurs due to the presence of highly electronegative nitrogen atoms.

Explanation:

The predominant intermolecular force in (CH3)2NH is hydrogen bonding. This is a special type of dipole-dipole interaction that occurs when hydrogen is bonded to a highly electronegative atom such as nitrogen (N). In (CH3)2NH, the hydrogen atoms attached to the nitrogen can form hydrogen bonds with the nitrogen atoms of adjacent molecules because nitrogen is one of the three most electronegative elements capable of forming hydrogen bonds, along with oxygen (O) and fluorine (F). While London dispersion forces are also present, they are generally weaker than hydrogen bonds and are not the predominant force in this compound.

This means that you need to add 1 gallon of water to 1 gallon of pure antifreeze to obtain a solution that is 75% antifreeze. To obtain a solution that is 75% antifreeze, you need to add 1 gallon of water to 1 gallon of pure antifreeze.

To obtain a solution that is 75% antifreeze, you need to determine how much water should be added to 1 gallon of pure antifreeze.

Let's assume that the final volume of the solution, after adding water, remains at 1 gallon.

The amount of antifreeze in the solution can be calculated using the equation:

Amount of antifreeze = Volume of antifreeze / Total volume of solution

Since the volume of the antifreeze is 1 gallon (given) and the total volume of the solution is also 1 gallon (assuming), we can calculate:

Amount of antifreeze = 1 gallon / 1 gallon = 1

This means that you need to add 1 gallon of water to 1 gallon of pure antifreeze to obtain a solution that is 75% antifreeze.

Answer: Potential energy of products is less than the potential energy of the reactants.

Explanation:

Exothermic reactions are defined as the reactions which releases heat. The release in heat is due to the difference in the potential energy of the reactants and the products.

For these reactions, the potential energy of the products is less than the potential energy of the reactants. Total enthalpy change of the reaction is given by the equation:

[tex]\Delta H_{rxn}=\sum H_{products}-\sum H_{reactants}[/tex]

For exothermic reaction, [tex]\Delta H_{rxn}[/tex] is negative.

For the reaction of baking soda and vinegar, the equation follows:

[tex]NaHCO_3+CH_3COOH\rightarrow CH_3COONa+CO_2+H_2O+\text{ energy}[/tex]

As, the energy is written at the product side, this means that the reaction between baking soda an=d vinegar is an exothermic reaction.

Answer:

Metals are malleable due to the layers of atoms which can move over each other. Ionic crystals are made of rigid lattice structures

Explanation:

The molecular structure of metals consists of metallic ions in a sea of de-localized electrons. The ions are closely packed in a regular arrangement. The layers of ions are held together due to the electrostatic forces between the ions and electrons. The layers of ions are not bonded to each other directly, which allows them to move when force is applied. This is why metals are malleable

Ionic crystals are strongly bonded lattice structures with oppositely charged ions strongly attracted to each other. As the ions are bonded directly to each other, the application of a force has the potential to break existing bonds, making the structure brittle.

Answer:C

Explanation:

Answer: C) 154 g

I did the assignment already, it's correct.

To calculate the initial velocity of a rock thrown 1.8 meters in the air, we use the vertical motion equation, resulting in an initial velocity of approximately 5.94 m/s.

To find out how fast a rock was thrown 1.8 meters in the air, we can use the physics of projectile motion and the equations of motion under the influence of gravity. Given that the height reached by the rock is 1.8 meters, we can use the equation for vertical motion:

h = vi2 / (2g),

where h is the maximum height (1.8 meters), vi is the initial velocity we want to calculate, and g is the acceleration due to gravity (9.8 m/s2). Rearranging the formula to solve for the initial velocity gives us:

vi = sqrt(2gh).

Plugging in the values, we get:

vi = sqrt(2 * 9.8 m/s2 * 1.8 m) = sqrt(35.28) ≈ 5.94 m/s.

Thus, the rock was thrown upwards with an initial velocity of approximately 5.94 m/s.

Using the kinematic equation v^2 = u^2 + 2as, the initial velocity (u) at which the rock was thrown into the air is found to be approximately 5.94 m/s.

To calculate the initial velocity at which a rock is thrown into the air, we can use the kinematic equations for projectile motion. Since air resistance is negligible, we'll apply the equation for an object under uniform acceleration due to gravity.

The equation we use is v^2 = u^2 + 2as, where:

Rearranging the equation to solve for the initial velocity (u), we get:

u = √(v^2 - 2as)

Plugging in the known values:

u = √(0^2 - 2*(-9.8 m/s^2)*(1.8 m))

u = √(0 + 35.28)

u = √35.28

u = 5.94 m/s

The rock was thrown with an initial velocity of approximately 5.94 m/s.