[tex]\boxed{{\text{22}}{\text{.69 g}}}[/tex] of methanol must be burned to produce 541 kJ of heat.
Further explanation:
Combustion reaction:
It is the reaction in which the reactant reacts with molecular oxygen to form carbon dioxide and a water molecule. Molecular oxygen acts as the oxidizing agent in these reactions. A large amount of heat is released and therefore combustion reactions are exothermic in nature.
The change in enthalpy that occurs due to the formation of one mole of the compound from its constituent elements is called the standard enthalpy of formation. It is represented by [tex]\Delta {H_{{\text{rxn}}}}[/tex] and its units are kJ/mol.
The combustion of methanol occurs as follows:
[tex]{\text{C}}{{\text{H}}_3}{\text{OH}}+\frac{3}{2}{{\text{O}}_2}\to{\text{C}}{{\text{O}}_2}+2{{\text{H}}_{\text{2}}}{\text{O}}[/tex]
The value of [tex]\Delta {{\text{H}}_{{\text{reaction}}}}[/tex] is -764 kJ/mol. This indicates the heat produced when one mole of methanol is combusted. The negative sign means the heat is released during the process.
The number of moles of methanol [tex]\left( {{\text{C}}{{\text{H}}_3}{\text{OH}}} \right)[/tex] required in the given reaction is calculated as follows:
[tex]\begin{aligned}{\text{Moles of C}}{{\text{H}}_3}{\text{OH}}&=\left({541{\text{ kJ}}} \right)\left( {\frac{{{\text{1 mol}}}}{{764{\text{ kJ}}}}}\right)\\&=0.708{\text{ mol}}\\\end{aligned}[/tex]
The formula to calculate the mass of methanol [tex]\left( {{\text{C}}{{\text{H}}_3}{\text{OH}}} \right)[/tex] is as follows:
[tex]{\text{Mass of C}}{{\text{H}}_3}{\text{OH}}=\left({{\text{Moles of C}}{{\text{H}}_3}{\text{OH}}}\right)\left({{\text{Molar mass of C}}{{\text{H}}_3}{\text{OH}}}\right)[/tex] ...... (1)
The number of moles of [tex]{\text{ C}}{{\text{H}}_3}{\text{OH}}[/tex] is 0.708 mol.
The molar mass of [tex]{\text{ C}}{{\text{H}}_3}{\text{OH}}[/tex] is 32.04 g/mol.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Mass of C}}{{\text{H}}_3}{\text{OH}}&=\left({{\text{0}}{\text{.708 mol}}} \right)\left({\frac{{{\text{32}}{\text{.04 g}}}}{{{\text{1 mol}}}}}\right)\\&=22.688{\text{ g}}\\&\approx {\text{22}}{\text{.69 g}}\\\end{aligned}[/tex]
Therefore the mass of methanol burned is 22.69 g.
Learn more:
1. Calculate [tex]\Delta {\text{H}}[/tex] for the reaction using Hess law: https://brainly.com/question/11293201
2. Calculate the hydroxide ion concentration: https://brainly.com/question/11293214
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Thermodynamics
Keywords: methanol, CH3OH, combustion, 746 kJ, 541 kJ, mass of CH3OH, molar mass of CH3OH, 22.69 g, moles of CH3OH.
Kasterville is a rapidly growing city. Which of the following situations will most likely have a positive impact on the resources available to Kasterville? A. Factories dump wastewater directly into nearby rivers. B. Builders cut down trees to build homes without replanting new ones. C. Most people water their lawns every day to keep them green. D. Most people are careful to recycle all glass, metal, and plastic.
Answer: D
Explanation:
The equation 2c3h7oh(g) + 9o2(g)→6co2(g) + 8h2o(g) is an example of which type of reaction?
the answer is combustion
The given equation represents a combustion reaction. The organic gas combines with atmospheric oxygen to form carbon dioxide and water .
What is combustion?Combustion is a type of reaction, in which gaseous reactants combines with atmospheric oxygen to form carbon dioxide and water. In combustion reaction heat energy is released by the reaction system.
The reaction from which a heat energy is released is called an exothermic reaction. Thus, combustion is an exothermic reaction. The reaction in which heat is absorbed the system is called endothermic reaction.
In the given reaction, 2 moles of propanol reacts with 9 moles of oxygen forming 6 moles of carbon dioxide and 8 moles of water. This reaction is an example of combustion.
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What is the Lewis dot structure of BeO
All chemical reactions involve a transfer of energy true or false
Answer:
true
Explanation:
Which statement about the orinoco river is true.
A. IT FLOWS THROUGH ECUADOR
B. IT IS SECOND LONGEST RIVER IN SOUTH AMERICA
C. IT FLOWS THROUGH VENEZUELA
D. IT EMPTIES INTO THE PACIFIC OCEAN
Answer:
C. IT FLOWS THROUGH VENEZUELA
Explanation:
correct asnwer
explain why it is often milder in areas such as coastal Maryland while areas such as Kansas or Iowa have more extremes in temperature?
Final answer:
Coastal areas like Maryland have milder climates due to the moderation by nearby ocean water, which has a stable temperature that influences the air temperature over land. In contrast, inland areas such as Kansas and Iowa experience more extreme temperatures due to their distance from the ocean's moderating effects and greater influence from continental air masses.
Explanation:
The location of an area relative to the coast significantly influences its climate due to the effects of oceanality and continentality. Coastal Maryland, being near the Atlantic Ocean, experiences milder conditions because the temperature of ocean water remains relatively stable throughout the year, moderating the air temperature over the land. In contrast, inland areas such as Kansas and Iowa are subject to more extreme temperatures due to their distance from the ocean's moderating influence, leading to significantly warmer summers and colder winters.
Ocean water has a high heat capacity, which means it absorbs and releases heat more slowly than land, resulting in a smaller range of temperature fluctuations. This heat inertia is why coastal areas tend to have more moderated climates. For example, airflow from the ocean keeps San Francisco's climate mild and more constant throughout the year, while Salt Lake City, which is an inland city at approximately the same latitude, experiences greater temperature variation.
In summary, coastal regions are influenced by the temperature of the nearby ocean, which changes little with the seasons. This results in a milder climate with less variation between summer and winter temperatures. Conversely, inland regions are more subject to continental air masses, leading to a larger range in temperatures and more extreme seasonal conditions.
Addition of a benzopyrene adduct is the result of what type of reaction?
which element would be a positive ion in a compound: Sr or Te
The element that would be a positive ion in a compound between Sr and Te would be Sr.
How to determine the charge on ionsElements form positive or negative ions based on the number of valence electrons their atoms contain and the tendency to either donate these electrons to form bonds or accept more electrons to form bonds.
The donation of acceptance of electrons will enable atoms to form an octet structure.
The number of valence electrons in Sr atoms is 2. In order to form an octet when bonding, these 2 electrons are readily donated rather than accepting more electrons. Thus, Sr ions are usually [tex]Sr^{2+[/tex].
The number of valence electrons in Te atoms is 6. Hence, instead of donating these electrons to form an octet, it will rather accept 2 more electrons. Thus, Te ions are usually [tex]Te^2^-[/tex].
In other words, Sr would be the positive ion in a compound.
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Final answer:
Strontium (Sr) would form a positive ion in a compound since it is an alkaline earth metal that readily loses electrons to become a cation, whereas tellurium (Te) tends to gain electrons to form an anion.
Explanation:
Between the elements strontium (Sr) and tellurium (Te), Sr would typically form a positive ion in a compound. This is because Sr is an alkaline earth metal and is found in Group 2 of the periodic table, where elements readily lose electrons to form cations with a +2 charge. On the other hand, Te is a metalloid in Group 16, known for gaining electrons to form anions with a -2 charge. Compounds are neutral, which means that the total number of positive charges must balance the total number of negative charges.
Additionally, Sr is lower down in its group than Ca, making it easier to remove an electron from Sr than from Ca. Hence, Ca has the higher ionization energy (IE) compared to Sr. When considering a potassium ion (K+), it would also be harder to remove an electron because it already has a positive charge. Therefore, the IE of K+ is significantly higher, especially since the next electron to be removed would come from a different electron shell.
Pellets of calcium chloride are spread on a sidewalk covered in water that is 36°c. under which circumstance will the calcium chloride dissolve faster? it rains, increasing the amount of water on the sidewalk. sand is sprinkled on the sidewalk. the water cools to a temperature of 33°c. people walking on the sidewalk crush the calcium chloride pellets. the air pressure increases as the weather changes.
Answer:
people walking on the sidewalk crush the calcium chloride pellets.
Explanation:
When calcium chloride pellets are crushed with feet it increases the surface area of the calcium chloride. As the surface area increase the number of collision between the reactant molecules increases. Here the reactant molecules are calcium chloride ions and water molecules. In the process of dissolution the calcium chloride ions get hydrated by the dipoles of the water molecules. As the frequency of collision increases it lowers the activation energy or threshold barriers to start a reaction.
If you don't reply with an actual answer I will report it and you will be reported and itll give me back my points
1.If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12
liters, what is the temperature?
2.If I have an unknown quantity of gas at a pressure of 121.6 kPa, a
volume of 31 liters, and a temperature of 87 0C, how many moles of
gas do I have?
3.If I contain 3 moles of gas in a container with a volume of 60 liters and
at a temperature of 400 K, what is the pressure inside the container?
4.If I have 7.7 moles of gas at a pressure of 0.09 atm and at a temperature
of 56 0C, what is the volume of the container that the gas is in?
5.If I have 17 moles of gas at a temperature of 67 0C, and a volume of
88.89 liters, what is the pressure of the gas?
Use Dalton’s Law of Partial Pressures and Grahams law of effusion to solve
the following problems:
6.At a certain temperature, molecules of methane gas, CH4 have an average
velocity of 0.098 m/s. What is the average velocity of carbon dioxide
molecules at this same temperature?
7.7.) Find the relative rate of diffusion for the gases chlorine, Cl2 and ethane,
C2H6.
8.495 cm3 of oxygen gas and 877 cm3 of nitrogen gas, both at 25.0 °C and
114.7 kPa, are injected into an evacuated 536 cm3 flask. Find the total
pressure in the flask, assuming the temperature remains constant.
A soda has a volume of 560 ml and a density of 3.2g/ml. what is the mass?
Answer: Mass of the substance is 1.792 kg
Explanation: Density of a substance is defined as the mass contained per unit volume.
[tex]Density=\frac{mass}{volume}[/tex]
Given:
Volume = 560 ml
Density = 3.2 g/ml
[tex]Mass=Density\times volume[/tex]
[tex]Mass=3.2g/ml\times 560ml=1792g[/tex]
Mass of the substance is 1792 g or 1.792 kg.
What is the experimental molar heat of combustion?
Explanation:
Molar heat combustion:
Molar heat of combustion is defined as heat released when 1 mole of substance is burnt under the action of oxygen gas to give water and carbon-dioxide.It is measured in kiloJoules (kJ) per mole.This heat of energy can be positive or negative.
If the enthalpy is positive than the reaction is said to be an endothermic reaction.If the enthalpy is negative than the reaction is said to be an exothermic reaction.The molar heat of combustion is illustrated as the heat discharged when one mole of the component is burnt by reacting with oxygen gas to provide carbon dioxide and water. It is determined in kJ per mole. This heat of energy can be negative or positive. In case if the enthalpy is negative than the reaction is considered as an exothermic reaction, and if the enthalpy is positive than the reaction is considered as an endothermic reaction.
What does the suffix -ide indicate when naming an ionic compound?
What mineral has the least hardness according to the scale?
which describes the force between two magnets winter south poles are almost touching
If the half-life of a radioactive isotope is 5,000 years, how much of the radioactive isotope in a specimen will be left after 10,000 years?
Final answer:
After two half-lives of 5,000 years each, only 25% of the original radioactive isotope would remain.
Explanation:
If the half-life of a radioactive isotope is 5,000 years, after 10,000 years, two half-lives will have passed. According to exponential decay, after the first half-life, 50% of the original isotope remains. After the second half-life, another half of this remaining amount will have decayed, leaving only 25% of the original isotope. We can use the expression (1/2)n, where 'n' is the number of half-lives, to calculate the remaining amount of the isotope. In this case, it would be (1/2)2 = 1/4 or 25%.
What is the IMA of the following pulley system?
2
3
4
5
Option D: 5
IMA is Ideal Mechanical advantage, for pulley system it is equal to the number of ropes present in the system. At ideal conditions, it is equal to the number of times, input force is getting multiplied. For example, If a pulley uses two ropes, its required mechanical force to displace the load will be divided into two or the distance that should be pulled will be multiplied by two (keeping total energy constant).
In the pulley system in diagram, there are total of 5 ropes in the system that is total strand that lead directly to the load thus, IMA for this pulley system will be 5.
A 250 mL sample of a .125 M solution of NaOH contains _____g of NaOH
What is the equilibrium associated with ka3 for h3po4?
The equilibrium associated with [tex]\text{K}_{a3}[/tex] for [tex]\text{H}_3\text{PO}_4[/tex] is as follows:
[tex]\boxed{\text{HPO}^{2-}_{4}(aq)+\text{H}_{2}\text{O}(l)_{\rightleftharpoons}^{{K}_{a3}}\text{PO}^{3-}_{4}(aq)+\text{H}_{3}\text{O}^{+}(aq)}[/tex]
Further Explanation:
Acids are substances that can donate hydrogen ion [tex]\text{H}^{+}[/tex] or proton in their aqueous solutions.
Classification of acids:
1. Monoprotic acids
Acids that are capable to donate single proton in solutions are monoprotic acids. For example, HCl is a monoprotic acid due to its tendency to donate only one proton in solutions.
2. Polyprotic acids
Acids that are capable to donate more than one proton in aqueous solutions are called polyprotic acids. For example, [tex]\text{H}_2\text{SO}_4[/tex] and [tex]\text{H}_3\text{PO}_4[/tex] are all polyprotic acids.
Acid strength is measured with the help of dissociation constant. Itis denoted by [tex]\text{K}_a[/tex]. Since [tex]\text{H}_3\text{PO}_4[/tex] contains three hydrogens in it, it can donate three hydrogen ions in solutions so it is triprotic acid.
Dissociation of [tex]\text{H}_3\text{PO}_4[/tex] occurs as follows:
[tex]\begin{aligned}\text{H}_3\text{PO}_4(aq)+\text{H}_2\text{O}(l)_{\rightleftharpoons}^{K_{a1}}\text{H}_2\text{PO}^{-}_{4}(aq)+\text{H}_3\text{O}^{+}(aq)\\\text{H}_2\text{PO}^{-}_{4}(aq)\text{H}_2\text{O}(l)_{\rightleftharpoons}^{K_{a3}}\text{HPO}^{2-}_{4}(aq)+\text{H}_{3}\text{O}^{+}(aq)\\\text{HPO}^{2-}_{4}(aq)+\text{H}_{2}\text{O}(l)_{\rightleftharpoons}^{K_{a3}}\text{PO}^{3-}_{4}(aq)+\text{H}_{3}\text{O}^{+}(aq)\end{aligned}[/tex]
Where,
[tex]{{\text{k}}_{{\text{a1}}}}[/tex] is the first dissociation constant of [tex]{{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex].
[tex]{{\text{k}}_{{\text{a2}}}}[/tex] is the second dissociation constant of [tex]{{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex].
[tex]{{\text{k}}_{{\text{a3}}}}[/tex] is the third dissociation constant of [tex]{{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex].
The expression of [tex]{{\text{k}}_{{\text{a3}}}}[/tex] for [tex]{{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}}[/tex] is as follows:
[tex]{{\text{k}}_{{\text{a3}}}} = \dfrac{{\left[ {{\text{PO}}_4^{3 - }} \right]\left[ {{{\text{H}}_{\text{3}}}{{\text{O}}^ + }} \right]}}{{\left[ {{\text{HPO}}_4^{2 - }} \right]}}[/tex]
Learn more:
Calculation of equilibrium constant of pure water at 25°C: https://brainly.com/question/3467841 Complete equation for the dissociation of [tex]{\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}[/tex] (aq): https://brainly.com/question/5425813
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Equilibrium
Keywords: acids, monoprotic acid, polyprotic acid, hydrogen ions, ka3, H3PO4, acid strength, dissociation constant, first dissociation constant, second dissociation constant, third dissociation constant.
Find the half-life of an element which decays by 3.415% each day.
The half-life of an element that decays by 3.415% each day is approximately 20.27 days.
Explanation:The half-life of an element can be calculated using the formula:
half-life = (ln(2)) / (decay constant)
where the decay constant is the rate at which the element decays per time period. In this case, the element decays by 3.415% each day. To find the decay constant, we convert the percentage to a decimal by dividing it by 100:
decay constant = 0.03415
Now we can calculate the half-life:
half-life = (ln(2)) / (0.03415)
A calculator can be used to find the value of ln(2), which is approximately 0.693:
half-life = 0.693 / 0.03415 = 20.27 days
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Which substance produced in the laboratory is used as a post exposure preventative measure against rabies?
When ammonium nitrate is dissolved in water, energy is absorbed from the surroundings, causing a decrease in the resulting solution's temperature. Which of the following best describes this type of reaction?
Which gas law has assumptions of a fixed amount and temperature of a gas
Please help with a chem question thank you!
The wavelength of light in the infrared region is 4.257 × 10-7 cm. What is the frequency of this light?
"which common material is an example of a polymer?"
The answer is plastic...
Hope this helps.
Which of the following best explains why you sanded the copper wire before burning it?
to create less friction between the copper and the tongsto make sure that copper metal was exposed on the surface of the wireto make the copper wire flammableto weaken the copper wire so it would be more reactive
Answer: Option (b) is the correct answer.
Explanation:
When copper wire is place into the atmosphere or anywhere then there is possibility that some oxide layer or impurity must have deposited over its surface.
So, when we sanded copper wire then these impurities get removed and copper metal gets exposed onto the surface.
Thus, we can conclude that you sanded the copper wire before burning it to make sure that copper metal was exposed on the surface of the wire.
Answer:
B. to make sure that copper metal was exposed on the surface of the wire
Explanation:
Right on Edgen.
Using the example reaction aA + bB → cC + dD write the potential first order and second order rate laws
Final answer:
The potential first-order rate law is rate = k[A] or rate = k[B], and the potential second-order rate law is rate = k[A][B].
Explanation:
The potential first-order rate law for the given reaction aA + bB → cC + dD is rate = k[A] or rate = k[B]. This means that the rate of the reaction is directly proportional to the concentration of either reactant A or reactant B.
The potential second-order rate law for the given reaction is rate = k[A][B]. This indicates that the rate of the reaction depends on the product of the concentrations of both reactant A and reactant B.
What mass of KBr (in grams) should you use to make 150.0 mL of a 1.70 M solution of KBr?
Final answer:
To make 150.0 mL of a 1.70 M KBr solution, you need 30.33 grams of KBr. This is calculated by multiplying the molarity (1.70 M), the volume in liters (0.150 L), and the molar mass of KBr (119.00 g/mol).
Explanation:
To calculate the mass of KBr needed to make 150.0 mL of a 1.70 M solution, we need to use the formula:
Mass (g) = Molarity (M) × Volume (L) × Molar Mass (g/mol)
First, convert the volume from milliliters to liters by dividing by 1000:
150.0 mL = 0.150 L
Next, find the molar mass of KBr, which is the sum of the atomic masses of potassium (K) and bromine (Br). Potassium has an atomic mass of 39.10 g/mol, and bromine has an atomic mass of 79.90 g/mol:
Molar Mass of KBr = 39.10 g/mol + 79.90 g/mol = 119.00 g/mol
Now, we can calculate the mass of KBr:
Mass of KBr = 1.70 M × 0.150 L × 119.00 g/mol = 30.33 grams
Therefore, you should use 30.33 grams of KBr to make the solution.
Which of the following gases will diffuse most quickly at a given temperature?
Gas A; MW = 14.28 g/mol
Gas B; MW = 26.92 g/mol
Gas C; MW = 39.95 g/mol
Gas D; MW = 108.60 g/mol
The gas that is having lowest density will diffuse faster than other gases. As lesser denser will diffuse more quickly than the one which is more denser. Density is directly proportional to mass of the substance that is more mass of the substance is , more denser it will be. So here the Gas A is having lesser molecular weight than the other gases so it will diffuse more quickly than the other gases.
Gas A; MW = 14.28 g/mol