People living in the Amazon Rain Forest want to clear the forest of vegetation and create farmland so they can grow crops. How will clearing away vegetation affect soil erosion

No, the law of conservation of mass does not hold true in this case.

The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction. However, in this case, the mass of the silver residue (2.16 g) is less than the mass of the silver carbonate (2.76 g). This means that some mass was lost during the reaction.

The most likely explanation for the lost mass is that it was converted into carbon dioxide gas. When silver carbonate decomposes, it produces silver metal and carbon dioxide gas. The carbon dioxide gas is not visible, so it is easy to miss.

We can calculate the amount of mass that was lost by subtracting the mass of the silver residue from the mass of the silver carbonate.

Mass lost = 2.76 g - 2.16 g = 0.6 g

This calculation shows that 0.6 g of mass was lost during the reaction. This is a violation of the law of conservation of mass.

The law of conservation of mass does not hold true in this case because some mass was lost during the reaction. The most likely explanation for the lost mass is that it was converted into carbon dioxide gas.

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Answer:

The electric potential (volts) divided by the current (amperes) equals the resistance (ohms).

Explanation: That is the formula to find the resistance based on the Ohm's laws.

Answer:

Speed, v = 140 m/s      

Explanation:

It is given that,

Wavelength, λ = 35 meters

Frequency of the wave, υ = 4 Hz

The speed of the wave is the product of the frequency and the wavelength of the wave.

Mathematically, it can be written as :

v = υ λ

v = 35 m × 4 Hz

v = 140 m/s

So, the speed of the wave is 140 m/s

Hence, this is the required solution.

Answer:

I am pretty sure the answer is "66N"

Explanation:

I've seen a lot of results on the internet saying the same thing

If this is not the answer, I am truly sorry and you can message me so that I can delete the question.

Have a good day!

Answer:

The Answer Is (D.)

Explanation:

In rotational motion, tangential speed is proportional to the radius. Thus, if you're halfway between the center and the rim of a Ferris wheel, your speed would be half that of the rim's speed. So, the tangential speed halfway to the center from the rim would be 5 m/s assuming the outer rim speed is 10 m/s.

The concept you're asking about is related to tangential speed and its relationship to the radius in rotational motion. In the case of a Ferris wheel, or any rotating body, the tangential speed is defined as the angular velocity times the radius. Therefore, if the radius is halved (a point halfway from the center to the outer rim), the tangential speed at the new point will also be halved assuming a constant angular velocity. Thus, in your example, if the tangential speed at the outer rim is 10 m/s, the speed halfway to the center will be 5 m/s.

This is because the properties of a rotating body dictate that the tangential speed increases linearly with the radius from the axis of rotation, in the case of a constant angular velocity. Hence, the farther away from the center of rotation, the faster the tangential speed, and vice versa.

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The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel with an outer rim speed of 10 m/s would be 5 m/s.

The tangential speed at a position halfway from the center to the outer rim of a Ferris wheel is half of the tangential speed at the outer rim. In this case, the initial tangential speed at the outer rim is given as 10 m/s, so the tangential speed at halfway to the rim would be 5 m/s. This is because tangential speed is directly proportional to the radius in uniform circular motion, and if the radius is halved, so is the tangential speed.

Answer:

current time the voltage. Hope this helps:-)

Explanation:

1. The kinetic energy of the train is 5400000 J

2. The tallest hill the train can climb is 45.92 m

1. Determination of kinetic energy of the train

Mass (m) = 12000 Kg

Velocity (v) = 30 m/s

The kinetic energy of the train can be obtained as follow:

KE = ½mv²

KE = ½ × 12000 × 30²

KE = 6000 × 900

2. Determination of the height of the hill the train can climb

Energy (E) = 5400000 J

Mass (m) = 12000 Kg

Acceleration due to gravity (g) = 9.8 m/s²

E = mgh

5400000 = 12000 × 9.8 × h

5400000 = 117600 × h

Divide both side by 117600

h = 5400000 / 117600

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Answer:

true

Explanation:

true

The distance covered by the car until it comes to a stop is 71.6 m.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given parameters:

Initial speed of the car; v = 22 m/s.

The car stops after time t = 6.5 s.

The distance covered by the car after the driver brakes, until it comes to a stop; s = ?  

So, deceleration of the car = ( initial speed - final speed)/time

= ( 22 m/s - 0 m/s )/6.5 s

= 3.38 m/s².

So, by using v² = u² - 2as in this decelerated motion; we get:

⇒ 0² = 22² - 2×3.38×s

⇒ s = 22²/(2×3.38) =  71.6 m.

Hence,  the distance covered by the car after the driver brakes, until it comes to a stop is 71.6 m.

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Answer:

495km to the southeast is the correct answer.

Explanation:

The answer is A) It transforms kinetic energy into electrical energy.

To find the electric force between the charged glass and rubber balls, we use Coulomb's Law with Coulomb's constant, the charges in Coulombs, and the distance in meters to calculate the force.

The student has asked to find the electric force between a glass ball with a charge of 3.5     µC and a rubber ball with a charge of -4.5 µC when they are 5 cm apart. To calculate this, we can use Coulomb's Law, which states that the electric force (F) between two point charges is directly proportional to the product of the magnitudes of the charges (q1 and q2), and inversely proportional to the square of the distance (r) between them. The formula is represented as:

F = k * |q1 * q2| / r₂

Here, k is Coulomb's constant (8.988 x 10^9 N·m^2/C²), q1 and q2 are the charges in Coulombs, and r is the distance in meters. For the glass and rubber ball, q1 is 3.5 µC (or 3.5 x 10^-6 C) and q2 is -4.5 µC (or -4.5 x 10⁻⁶ C), and the distance r is 5 cm (or 0.05 m). Plugging in these values, we get:    

F = (8.988 x 10⁹ N·m²/C₂) * |(3.5 x 10⁻⁶ C) * (-4.5 x 10⁻⁶ C)| / (0.05 m)²

After calculation, the result is the magnitude of the electric force exerted between the two charges.

Answer

34 N

Explanation.

I think the question is not complete.. It should be "A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction? 30 N 34 N 55 N 65 N"

We should find the horizontal component of the force 65 N.

Since 65 N is at an angle of 58° to the horizontal, we are required to find the horizontal force.

cosФ = adjacent/hypotenuse

let x be the net required (the component of 65N)

cos 58 = x/65

x = 65 × cos 58

= 34.44 N

Answer:

The answer is 34 N

Explanation:

Hope this helped!!!

The wavelength in water is approximately 4.41 times larger than the wavelength in air.

In order to calculate the ratio of the wavelengths in water and in air, we need to use the formula:

ratio = speed of sound in water / speed of sound in air

Given that the speed of sound in water is 1500 m/s and the speed of sound in air is 340 m/s, we can substitute these values into the formula: ratio = 1500 m/s / 340 m/s = 4.41

Therefore, the wavelength in water is approximately 4.41 times larger than the wavelength in air.

The wavelength in water is approximately 4.4 times larger than in air.

To find the wavelength of a sound wave in a given medium, one can use the formula:

[tex]\[ \lambda = \frac{v}{f} \][/tex]

where [tex]\( \lambda \)[/tex] is the wavelength, [tex]\( v \)[/tex] is the speed of sound in the medium, and [tex]\( f \)[/tex] is the frequency of the sound wave.

Given that the frequency [tex]\( f \)[/tex] of the sound wave is 100.0 Hz, we can calculate the wavelength in water and in air using their respective speeds.

First, calculate the wavelength in water:

[tex]\[ \lambda_{\text{water}} = \frac{v_{\text{water}}}{f} = \frac{1,500 \text{ m/s}}{100.0 \text{ Hz}} = 15 \text{ m} \][/tex]

Next, calculate the wavelength in air:

[tex]\[ \lambda_{\text{air}} = \frac{v_{\text{air}}}{f} = \frac{340 \text{ m/s}}{100.0 \text{ Hz}} = 3.4 \text{ m} \][/tex]

To find out how many times larger the wavelength in water is compared to the wavelength in air, we divide the wavelength in water by the wavelength in air:

[tex]\[ \text{Ratio} = \frac{\lambda_{\text{water}}}{\lambda_{\text{air}}} = \frac{15 \text{ m}}{3.4 \text{ m}} \approx 4.4 \][/tex]

Answer:

b.  electroscope.

Explanation:

-A magnet is an object that creates a magnetic field around it and has two poles.

-An electroscope is an instrument that helps to find out if there is a charge in an object.

-A generator is an object that produces electrical energy.

-A conductor is an object that allows to transmit energy.

According to this, the answer is that an instrument that can detect the presence of an electric charge is an electroscope.

Final answer:

In badminton, a shot that sends the birdie high and deep to the backcourt is called a clear. It's a defensive move to create more playing space and opportunities.

Explanation:

A shot in badminton that is hit high and deep into the opponent’s backcourt is known as a clear. This type of shot is a defensive move, intended to give the player hitting the clear more time to return to a ready position and to push the opponent to the rear of their court, potentially creating opportunities for future aggressive plays. The clear can be performed as either a forehand or backhand stroke depending on the player's position and the shuttlecock's trajectory.

Final answer:

The kinetic energy of a 1000 kg roller coaster car moving at a speed of 20.0 m/s is calculated using the formula KE = ½ mv², resulting in KE = 200,000 J or 2.00 × 10⁵ J.

Explanation:

The question requires us to calculate the kinetic energy of a 1000 kg roller coaster car that is moving with a speed of 20.0 m/s. The kinetic energy (KE) of an object can be found using the formula KE = ½ mv², where m is the mass of the object and v is its velocity. Inserting the given values into the formula, we get:

KE = ½ (1000 kg) (20.0 m/s)

KE = ½ (1000 kg) (400 m²/s²)

KE = (500 kg) (400 m²/s²)

KE = 200,000 J or 2.00 × 10⁵ J

The roller coaster car possesses 200,000 joules of kinetic energy at the given speed.

It would take 9 minutes and 37 seconds for a 1.51 × 10⁴ Watts steam engine to do 8.72 × 10⁶ J of work.

The efficiency of an Indian can be defined as the ratio of the total useful work done by the engine to the total heat absorbed by the engine.

It can be represented in the form of percentages or in terms of fractions as well.

As given in the problem we have to find out how long it takes a 1.51 × 10⁴ Watts  steam engine to do 8.72 × 10⁶ J of work,

Power of the steam engine = work done by the engine/time

                                              =8.72 × 10⁶ / 1.51 × 10⁴

Thus, It would take 9 minutes and 37 seconds for a 1.51 × 10⁴ W steam engine to do 8.72 × 10⁶ J of work.

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The creation of ice can result in physical weathering by expanding and exerting pressure on its surroundings, causing rocks to break apart or structures to crack or collapse.

When water freezes, it expands in volume and exerts pressure on its surroundings. This expansion can cause physical weathering by breaking down rocks or damaging structures such as containers or pipes. For example, when water seeps into the cracks of a rock and freezes, the expanding ice can widen the cracks and eventually break apart the rock. Similarly, water that freezes in a container can exert enough pressure to cause it to crack or even collapse.

The speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s. This is found by equating the potential energy stored in the spring to the kinetic energy of the toy head and solving for the speed.

The question is regarding the use of the principles of conservation of energy and Hooke's Law in the context of a jack-in-the-box toy. Consider that energy is conserved, we can set the potential energy equal to the kinetic energy. The potential energy stored in the spring while it is compressed is given by the formula PE = 0.5*k*x², where k is the spring constant and x is the distance the spring is compressed. In this case, PE = 0.5*80N/m*(0.08m)² = 0.256 J.

When the spring is released and returns to its natural length, this energy is converted into kinetic energy for the toy head. The kinetic energy is given by KE = 0.5*m*v² where m represents mass and v stands for speed. Setting this equal to the potential energy from above and solving for v, we get v = sqrt((2*0.256J)/(0.05kg)) = sqrt(10.24) m/s = approximately 3.2 m/s.

Therefore, the speed of the toy head when the spring returns to its normal length is approximately 3.2 m/s.

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A meteor is the bright streak of light observed when a meteoroid enters and burns up in Earth's atmosphere, due to friction and heat, often colloquially referred to as a shooting star. Larger pieces that reach the ground are known as meteorites. These events are quite common as countless cosmic dust particles enter the atmosphere daily.

A bright streak of light that results when a meteoroid burns up in the Earth's atmosphere is known as a meteor. This phenomenon occurs because as a meteoroid enters the atmosphere at high speeds, often up to 30,000 meters per second, the air in front of it is compressed. The intense heat from this compression and the resulting friction causing the meteoroid to incandesce, creating the visible streak of light we see in the sky, often described as a shooting star.

Most meteoroids are small pieces of rocky or metallic debris from asteroids or comets that enter Earth's atmosphere and burn up completely before reaching the ground. On occasion, larger pieces survive their fiery journey through the atmosphere and land on Earth, which are then called meteorites. It's fascinating to note that meteor sightings are quite common, as millions of these tiny particles enter the Earth's atmosphere daily, producing the brief flashes of light known as meteors.