When preparing the diazonium salt, the solution is tested with potassium iodide-starch paper. a positive test is the immediate formation of a blue color. what is the ki-starch paper testing for ? explain?

The wavelength of a hockey of mass 0.17kg traveling at a speed of37 m/s can be calculated by using De Broglie's equation and it comes out to be  1.05m×10⁻³⁴m.

The De Broglie's equation is an equation which shows that a particle has a wave length and hence particle can show wave nature. Any matter can have two nature one is particle nature and other is wave nature.

The wave nature in a particle was given by De Broglie Particle nature of a matter can be described by the phenomenon of black body radiation. Photoelectric effect two shows particle nature nature of light.

Mathematically,

[tex]{\lambda}=\frac{h}{mv}[/tex]

where,

[tex]{\lambda}[/tex]=wavelength=?

m=mass of hockey=0.17kg

h=Plank's constant

v=velocity of hockey=37 m/s

Substituting all given values in the equation

[tex]\lambda[/tex]= (6.626×10⁻³⁴)÷(0.17kg ×37 m/s )=1.05m×10⁻³⁴m

Thus the wavelength of motorcycle is 1.05m×10⁻³⁴m.

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Answer:

The answer is smooth and Involuntary.

Explanation:

Smooth muscles are involuntary which means they automatically do a function without the brain telling it to.

If you cut the height of an object in half, its gravitational potential energy (GPE) will also halve.

If you cut the height of an object in half, its gravitational potential energy (GPE) will also halve.

GPE is determined by the height of the object and its mass. When you cut the height in half, the GPE is reduced by half because the potential energy is directly proportional to the height.

For example, if a book has a certain GPE at a certain height, cutting the height in half will result in the book having half the GPE it had before.

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The percent yield of CO2 is calculated by dividing the actual yield (28.16 g of CO2) by the theoretical yield determined from the stoichiometry of the balanced chemical equation and the limiting reactant, and then multiplying by 100 to get the percentage.

The question asks for the percent yield of CO2 produced from the reaction of C8H18 with O2. First, we need to consider the balanced chemical equation:

Therefore, the percent yield can be calculated by dividing the actual yield of CO2 (28.16 g) by the theoretical yield (calculated in step 4), and then multiplying by 100 to get a percentage.

The molar solubility of CaSO4 in a solution containing 0.100 M Na2SO4 is 2.4 x 10−4 M, calculated using the Ksp value and the concentration of sulfate ions due to the common ion effect.

The molar solubility of CaSO4 in a solution containing 0.100 M Na2SO4 can be calculated using the solubility product constant (Ksp) and the concept of common ion effect. The solubility product expression for CaSO4 can be written as Ksp = [Ca²+ ][SO4²−]. Since the sodium sulfate solution already contains sulfate ions, we will consider the concentration of [SO4²−] as 0.100 M given in the question. The equation simplifies to Ksp = [Ca²+]*0.100. Therefore, the molar solubility is [Ca²+]= Ksp/0.100 which is 2.4 x 10−5/0.100 = 2.4 x 10−4 M. This suggests that in a 0.100 M Na2SO4 solution, additional CaSO4 would start precipitating when the [Ca²+] reaches 2.4 x 10−4 M.

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The molar solubility of CaSO₄ in a solution containing 0.100 M Na₂SO₄, with a Ksp of 2.4 × 10⁻⁵ is 2.4 × 10⁻⁴ M, which is lower than in pure water due to the common ion effect.

Calculating the molar solubility of calcium sulfate (CaSO₄) in a solution containing 0.100 M sodium sulfate Na₂SO₄ given the solubility product constant (Ksp) for CaSO₄ is 2.4 × 10⁻⁵.

Because Na₂SO₄ dissociates into 2 Na⁺ and 1 SO₄²⁻ in solution, the concentration of SO₄²⁻ due to Na₂SO₄ is 0.100 M. Since the solution is already saturated with sulfate ions, the molar solubility of CaSO₄ will be different from its solubility in pure water. The common ion effect will reduce the solubility of CaSO₄ in the solution.

To find the molar solubility of CaSO₄, let's set up the equation based on the Ksp expression:

Ksp = [Ca²⁺] [SO₄²⁻]

Since the concentration of SO₄²⁻ from Na₂SO₄ is already 0.100 M, and the Ksp for CaSO₄ is 2.4 × 10⁻⁵, the molar solubility of CaSO₄ in this solution is calculated as:

Ksp = (s) × (0.100 M)

2.4 × 10⁻⁵ = (s) × (0.100 M)

s = 2.4 × 10⁻⁴ M

Therefore, the molar solubility of CaSO₄ in a 0.100 M Na₂SO₄ solution is 2.4 × 10⁻⁴M.

The colors of the compounds in the beakers could potentially be: [CoF6]3– (green), [Co(NH3)6]3+ (yellow-orange), and [Co(CN)6]3– (red), although colors can vary based on different conditions.

The question asks us to identify the compounds present in three beakers based on the color of the solution. While this is generally impossible to answer with absolute certainty without more information or additional tests, we can make a fair guess based on some known color-characteristics of these compounds.

[CoF6]3– is generally green due to the color of the Cobalt(III) ion.

[Co(NH3)6]3+ is usually yellow to orange in color.

FInally, [Co(CN)6]3– commonly has a strong red color.

Note that in reality, actual colors can vary depending on concentration, temperature, and other factors.

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Bombardment of uranium-235 with a neutron produces tellurium-135, three neutrons, and molybdenum-98.

When uranium-235 (U-235) is bombarded with a neutron, it first forms U-236, which is unstable.

This unstable isotope undergoes nuclear fission, resulting in the production of tellurium-135 (Te-135), three neutrons, and another element, which we need to determine.

In fission reactions, the sum of the atomic masses and the number of protons must be equal on both sides of the equation.

Here’s the reaction:

U-235 + neutron ⟶ Te-135 + 3 neutrons + X

Starting with 235 (U-235) + 1 (neutron) = 236 mass units total.

The mass of Te-135 is 135 units.

Since three neutrons (3 x 1 = 3 units) are produced, the remaining mass is:

236 - 135 - 3 = 98 units.

Since tellurium (Te) has an atomic number of 52, and assuming the fission product balances the protons and neutrons in the equation, the remaining fission product is molybdenum-98 (Mo-98) with an atomic number of 42.

Completing the equation:

U-235 + neutron ⟶ Te-135 + 3 neutrons + Mo-98.

For light 3 to function, switch D does not have to be on. This diagram shows a parallel circuit that provides more than one way for the current to return to the power source.

The equilibrium constant is a number that shows the extent to which reactants are converted into products. The equilibrium constant of the reaction is 0.76.

The equilibrium constant is a number that shows the extent to which reactants are converted into products.

We know that to obtain the equilibrium constant; K = k1/k-1 where;

k-1 = rate constant of reverse reaction

k1 = rate constant of forward reaction.

Hence;

K = 297 l·mol–1·min–1/393 l·mol–1·min–1

K = 0.76

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Molten barium chloride is separetes:
BaCl₂(l) → Ba(l) + Cl₂(g), 
but first ionic bonds in this salt are separeted because of heat: 
BaCl₂(l) → Ba²⁺(l) + 2Cl⁻(l).

Reaction of reduction at cathode(-): Ba²⁺(l) + 2e⁻ → Ba(l).

Reaction of oxidation at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.

The anode is positive and the cathode is negative.

The electrolysis of molten barium chloride involves reduction of barium ions and oxidation of chloride ions, requiring two electrons to move through the circuit for one unit of the reaction.

During the electrolysis of molten barium chloride (BaCl2), barium ions (Ba2+) are reduced at the cathode, and chloride ions (Cl-) are oxidized at the anode. The half-reactions, showing the movement of electrons through the circuit, are as follows:

The overall cell reaction is obtained by combining the half-reactions and balancing the electrons:

Ba2+(l) + 2Cl-(l) → Ba(l) + Cl2(g)

For each mole of barium ions reduced, two electrons are involved in the transfer. Similarly, for each mole of chlorine gas produced, two electrons are given up by chloride ions. As such, there would be two electrons that moved through the circuit for one unit of the reaction to occur.

During a redox reaction, the number of electrons gained is equal to the number of electrons lost, demonstrating the law of conservation of charge.

In an oxidation-reduction reaction, also known as a redox reaction, the number of electrons gained is equal to the number of electrons lost. This principle is known as the law of conservation of charge which states that the total charge before a reaction must equal the total charge after the reaction.

So, when one substance loses electrons (oxidation), another must gain them (reduction). Therefore, the correct answer is A) equal to the number of electrons lost.

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To calculate the new pressure of a gas when the temperature changes and volume remains constant, we apply Gay-Lussac's Law, which involves converting temperatures to Kelvin and using the relationship P1/T1 = P2/T2.

The student's question involves calculating the pressure of a sample of gas when the temperature is changed while keeping the volume constant. This is a typical problem you might encounter in a chemistry class when discussing gas laws, specifically relating to Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its absolute temperature, provided that the volume remains constant.

Since the volume is constant, we can use the Gay-Lussac's Law formula: P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature, respectively. Remember to convert temperatures to Kelvin. Initially, we have P1 = 100.0 torr and T1 = (27.0 + 273.15) K. The final temperature is T2 = (127 + 273.15) K. Solving for P2, we get the final pressure.

Answer :The correct answer for (C₄H₁₀ )₃ N is C) TERTIARY AMINE .

The substitution level of nitrogen in amine or in simple words , description of carbon atoms attached to a given nitrogen in any amine is of 4 types :

1 ) Primary amine :

When the given nitrogen is attached to only one carbon then substitution level is known as PRIMARY amine.

Example : CH₃NH₂ : The nitrogen is attached to only one carbon (CH₃) . Hence it is primary amine

2) Secondary amine :

When the given nitrogen is attached to two carbons .

Example : (CH₃)₂NH : The nitrogen is attached to two carbon ( CH₃)₂ , hence it is secondary amine .

3) Tertiary amine :

When the given nitrogen is attached to three carbon atom .

Example : (CH₃)₃NH : The nitrogen is attached to 3 carbons atoms (CH₃)₃ . Hence it is a tertiary amine

4) Quaternary amine : when the nitrogen attached to 4 carbon atoms and amine posses a positive charge on it , its is known as quaternary amine .

Example : (CH₃)₄N⁺ : The nitrogen is attached to 4 carbons and nitrogen . hence it is quaternary amine .

(Image attached )

The given compound is (C₄H₁₀ )₃ N has 3 groups of C₄H₁₀ attached to N , means 3 carbons attached to N , ( image attached ) . Hence it can be said that (C₄H₁₀ )₃ N is TERTIARY AMINE .

Hence correct option is C) Tertiary amine .

Nuclear reaction: ¹⁶O + p⁺ → ¹³N + α (alpha particle).
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.
When oxygen-16 gain one proton, atomic mass is 17, but when lose alpha particle atomic mass reduces by four to 13.

Final answer:

The synthesis of benzylamine from toluene involves an oxidation step to convert toluene to benzaldehyde followed by reductive amination with an amine such as methylamine to yield the desired benzylamine.

Explanation:

To propose a reasonable synthesis to get benzylamine from toluene involves several steps. Initially, toluene can be oxidized to benzaldehyde through the oxidation reaction. This would typically involve a reaction with an oxidizing agent like KMnO4 in an aqueous base or CrO3 with acidic conditions. Once benzaldehyde is obtained, the next step is to convert it into benzylamine. This can be achieved by the reductive amination process, where benzaldehyde can react with an amine such as methylamine and then be reduced, often using a reducing agent like NaBH4 or H2 with a catalyst. To ensure that the amine added is solely the benzyl amine desired, the N-alkylation can be controled through the choice of appropriate reagents and conditions.

One possible method would utilize methylamine in the presence of a reductive agent to convert the aldehyde group to the desired primary amine. The overall reaction from toluene to benzylamine would likely proceed with good to high yields, assuming that the correct reaction parameters and purification techniques are employed.

Final answer:

A reaction is spontaneous under standard conditions at all temperatures when ΔH° is negative and ΔS° is positive, leading to a negative Gibbs free energy change (ΔG°).

Explanation:

For a reaction to be spontaneous under standard conditions at all temperatures, the signs of ΔH° (ΔH degree) and ΔS° (ΔS degree) must be negative and positive, respectively. According to the Gibbs free energy equation, ΔG° = ΔH° - TΔS°, where T represents the absolute temperature in Kelvin. If ΔH° is negative (exothermic reaction) and ΔS° is positive (increase in entropy), the Gibbs free energy change (ΔG°) will always be negative, indicating that the reaction is spontaneous. Conversely, if ΔH° were positive and ΔS° negative, ΔG° would be positive and the reaction non-spontaneous at all temperatures.

Answer:

Answer is B

Explanation:

The substances with greater molar entropy in each case are: NO2(g), CH3OCH3(l), and HBr(g), due to factors such as number of atoms, molecule complexity and being heavier gases.

In predicting the substance with greater molar entropy in each pair, we have to consider the number of molecules and atoms, phase of matter and complexity of molecules. Here are the predicted substances:

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Answer:

The correct answer is 1. Moseley started his investigations by reviewing the work of those who contributed to the previous versions of the table.

Explanation:

Henry Gwyn Jeffreys Moseley was a British physicist. His most important scientific contribution was the proof of the correctness of the concept of atomic numbers in chemistry.

In 1913, using X-ray spectroscopy, he found a systematic relationship between the wavelength and the atomic number. Previously, it was assumed that the atomic number was an arbitrary number based on the order of the atomic masses, but had to be changed to bring an element into the right place in the periodic table. Moseley's discovery showed that atomic numbers had an experimentally measurable basis. In addition, he showed that there were gaps in numbers 43, 61 and 75 (known today as the radioactive elements technetium and promethium, as well as the stable but rare rhenium). His work was further proof of the then controversial atomic theory.