Which are isotopes? an atom that has an atomic number of 20 and a mass number of 42 is an isotope of an atom that has which are isotopes? an atom that has an atomic number of 20 and a mass number of 42 is an isotope of an atom that has an atomic number of 20 and a mass number of 40. an atomic number of 21 and a mass number of 42. 22 protons and 20 neutrons. 22 neutrons and 20 protons?

Answers

Answer 1
Isotopes have the same atomic number or same number Protons, but different mass number or neutrons.

You can say atomic number or protons.

22 neutrons 20 protons
atomic number 20 and a mass number 40
Atomic number 20 and mass # 42
Answer 2

Explanation:

Isotopes are defined as the species which contain same number of protons but different number of neutrons.

As the sum of all the protons present in an atom is known as atomic number. Whereas the sum of total number of protons and neutrons is known as atomic mass.

Hence, isotopes are also defined as atoms with same atomic number but different atomic mass.

For example, an atom that has an atomic number of 20 and a mass number of 42 will contain the following number of neutrons.

                 Mass number = no. of protons + no. of neutrons

                            42 = 20 + no. of neutrons

                 no. of neutrons = 42 - 20

                                            = 22

So, isotope of this atom could be [tex]^{40}_{20}A[/tex]. This means that an element with atomic number of 20 and a mass number of 40.

Thus, we can conclude that an atom that has an atomic number of 20 and a mass number of 42 is an isotope of an atom that has an atomic number of 20 and a mass number of 40.

Since, both of them contains same number of protons but different number of neutrons.


Related Questions

_______ is the change of state of a substance from solid to vapor without passing through the liquid state.

Answers

sublimation is the change of state of a substance from solid to vapor without passing thru the liquid state.

If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, which of these choices shows a hydrogen bond?
-O...H-C-
-N...H-O-
-C...H-F-
H-H

Answers

Generally, a hydrogen bond can be characterized as a proton shared by two lone electron pairs. It occurs when a hydrogen (H) atom, covalently bound to a highly electronegative atom such as nitrogen (N), oxygen (O), or fluorine (F), experiences the electrostatic field of another highly electronegative atom nearby.

   Among the choices in the bond (-N...H-O) one side of the Hydrogen is bonded to a highly electronegative atom with a lone pair (-N) and the other side is directly bonded with a highly electronegative atom (O-).

    So -N...H-O- shows a hydrogen bond.
Final answer:

The correct option that shows a hydrogen bond is -N...H-O-, as it fits the criterion of hydrogen being covalently bonded to a highly electronegative atom (N) and attracted to a lone pair on another electronegative atom (O) in a neighboring molecule.

Explanation:

If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, the choice that shows a hydrogen bond is -N...H-O-. This is because hydrogen bonds are a type of dipole-dipole interaction that occurs when a hydrogen atom is covalently bonded to a highly electronegative atom, such as nitrogen (N), oxygen (O), or fluorine (F), and is attracted to a lone pair of electrons on an atom in a neighboring molecule.

Hydrogen bonds are particularly strong among dipole-dipole interactions, although they are much weaker compared to a covalent bond. Therefore, the correct answer is the one where hydrogen is bonded to nitrogen (which is highly electronegative) and is attracted to oxygen from another molecule, hence forming a hydrogen bond.

SHOW WORK!!!!!!!
a) how many meters are there in 5 kilometers.
b) Find the number of milligrams in 0.5 kilograms.
c) Convert 5 meters to kilometers.
d) Find the number of millimeters in 6.98 centimeters.
e) how many meters are equal to 2700. millimeters.

Answers

a) there are 5000 meters in 5 kilometers 
-  m = 5/0.0010000

b) there are 500000 milligrams in 0.5 kilograms
- 0.5 kg × 1000000

c) 0.005 kilometers
- km = 5/1000.0

d) 69.8 centimeters
- 6.98cm × 10

e) 2.7 meters
- m = 2700/1000.0

What characteristic property did arrhenius attribute to acids and bases?

Answers

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons (H⁺).
For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).
An Arrhenius base is a substance that dissociates in water to form hydroxide ions (OH⁻). 
For example sodium hydroxide: NaOH(aq) → Na⁺(aq) + OH⁻(aq).

what type of rock is sandstone

Answers

sandstone is considered a sedimentary rock. because it is a mixture of multiple particles and smaller pieces held together

Sandstone is a type of sedimentary rock. It is formed when sand particles are compacted and cemented together over time. These processes typically occur in sedimentary basins where sand accumulates through various natural actions such as water or wind transportation.

Sandstone forms through a geological process known as lithification. Initially, sand grains are deposited in a variety of earth environments, such as beaches, deserts, or the beds of rivers and oceans. Over time, these grains become buried under layers of more sediment. As the sediment builds up, the weight from the layers above exerts pressure, causing the sand grains to compact tightly. Meanwhile, minerals like silica or calcite present in the water flowing through the spaces between the grains can act as a natural cement, binding the particles together to form a solid rock. Thus, the unique characteristics of sandstone reflect the conditions in which it formed, including the size and composition of the sand grains, and the nature of the cement. Sandstones are particularly noteworthy as they can also serve as reservoirs for water, oil, and gas due to their porosity and permeability.

Which is an advantage of using chemical indicators?

A. They are inexpensive to use.
B. They have very limited use.
C. They require the use of electricity.
D. They change color at specific temperatures.,

Answers

A. They are inexpensive to use. Most of the chemical indicators are not expensive and can be used conveniently. Litmus paper is and example for chemical indicator. it is very cheap and anyone can procure it. The paper can be used to check acidic and basic nature of solvents.

Answer: The answer is A....... they are inexpensive to use  

Explanation: got it right on Edge

Word equation for Cu(s)+O2(g)=CuO(s)

Answers

Answer:

Copper solid plus oxygen gas giving solid cupric oxide

Explanation:

The given reaction is:

[tex]Cu(s) +O2(g)\rightarrow CuO(s)[/tex]

The balanced equation is:

[tex]2Cu(s) +O2(g)\rightarrow 2CuO(s)[/tex]

The formula name of the reactants and products are:

Cu (s) = copper in the solid phase

O2 (g) = oxygen in the gas phase

CuO (s) = copper (II) oxide or cupric oxide

The word equation would be:

Copper solid plus oxygen gas giving solid cupric oxide

Word equations are the representation of the element names in the place of symbols. Copper (s) + Oxygen (g) → Cupric oxide (s) is the word equation for Cu(s) + O₂(g) → CuO(s).

What is a word equation?

The reaction in which the molecules are added to give one or more compounds and also undergoes increases in oxidation number of the species are called oxidative addition reaction.

The chemical reaction given is,

[tex]\rm Cu (s) + O_{2} (g) \rightarrow CuO(s)[/tex]

The equation can be balanced as:

[tex]\rm 2Cu (s) + O_{2} (g) \rightarrow 2CuO(s)[/tex]

The word or the chemical names of the reactants and products are given as:

Cu (s) = copper (solid phase)

[tex]\rm O_{2} (g)[/tex] = oxygen (gas phase)

CuO (s) = cupric oxide or copper (II) oxide

Inserting the chemical names in the reaction:

[tex]\rm Copper (s)+ Oxygen (g) \rightarrow \rm Cupric\; oxide (s)[/tex]

Therefore, [tex]\rm Copper (s)+ Oxygen (g) \rightarrow \rm Cupric\; oxide (s)[/tex]  is the word equation.

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Which best describes the reducing agent in the reaction below?
Cl2(aq)+2Br-(aq)-------->2Cl-(aq)+Br2(aq)

A.Bromine (Br) loses an electron, so it is the reducing agent.
B.Bromine (Br) gains an electron, so it is the reducing agent.
C.Chlorine (Cl) loses an electron, so it is the reducing agent.
D.Chlorine (Cl) gains an electron, so it is the reducing agent.

Answers

Hi.

First you should know the definition and role of a reducing agent. A reducing agent is a substance in a chemical reaction which causes reduction of the other substance by losing electrons.

In the given chemical reaction following changes are occuring:
a) Chlorine is gaining electrons as it is being transformed from neutral atom to negative ion.
b) Bromine is losing electrons as it is being transformed from negative ion to neutral atom

Chlorine is gaining electrons so it is being reduced. Bromine is giving or losing electrons and is reducing the chlorine atoms so Bromine is the reducing agent.

Hence option A is correct. Bromine is losing electrons, so it is the reducing agent.  

Answer:

A on edg is the correct answer

Explanation:

What is the difference between anthropocentrism and biocentric views of the environment

Answers

Anthropocentrism vs. Thus, nothing in the environment is valuable for its own sake, but only for the benefit that it brings to humans. By contrast, biocentrism is the viewthat we have direct moral obligations to things in the environment for their own sake, irrespective of their impact on human interests.

Explanation:

Biocentrism is the thought of considering all the living beings in the bio diversity and the nature to be the main source  and aims at the well being of all as a whole.

         While anthropocentrism or homocentrism or sometimes called as altruistic is the philosophical thought that human beings are the most significant  or important entities in this world and all should strive for the over all development in the interest of the humans.

                Biocentric is more life centered while anthropocentrism is more human centered.

in the reaction mg(s)+2hcl(aq)→mgcl2(aq)+h2(g) + MgCl2 (aq) how many grams of hydrogen gas will be produced from 125.0 milliliters of a 6.0 M HCI in an excess of Mg

Answers

The reaction 
Mg(s) + 2HCl(aq) = MgCl2(aq) + H2(g) +MgCl2 
Moles of HCl used will be;
 = 0.125 l × 6.0 M
 = 0.75 moles 
The mole ratio of HCl to H2 is 2:1
Therefore; moles of Hydrogen is 0.75/2 = 0.375 mole
Molecular mass of hydrogen is 2 g
Hence; the mass of hydrogen = 2 × 0.375 = 0.75 g
Answer:

0.756g

Explanation:


I am assuming that 6.0MHCl is a typo, and that it should be 6.0molL−1HCl , since that makes sense in the equation.


First we have to find the amount of HCl in the solution. We use the formula n=cV where n is the amount of substance in moles, c is the concentration of the solution in moles per liter, and V is the volume of the substance in liters.


n(HCl)=6.0molL−1×0.125L=0.75mol


Then we find out how many moles of hydrogen gas (H2 ) are produced. In the formula we see 2HCl , and H2 . This means there is 1 mole of H2 for every 2 moles of HCl so to find the amount of H2 we use:


n(H2)=12×0.75mol=0.375mol


Now we find the molar mass of the H2 molecules, by adding together the atomic weights of the constituent molecules. In this case: 1.008+1.008=2.016 . Then we use the formula m=nM where m is the mass of the substance in grams, and M is the molar mass of the substance in grams per mole.


m(H2)=0.375mol×2.016gmol−1=0.756g

Write a formula for the compound that forms from potassium and chromate.

Answers

Hello!

The compound that forms from potassium and chromate is Potassium Chromate (K₂CrO₄)

This compound has a yellow lime color and is used in enamels, leather finishes, stainless steels and for the identification of silver ion in a silver nitrate solution. It is a powerful oxidizing agent and is produced by the treatment of potassium chromate with potassium hydroxide. It is a very toxic compound an is a known carcinogenic agent.

Have a good day!

Final answer:

The formula for the compound that forms from potassium and chromate is K2CrO4, and the balanced equation for its dissolution in water is K2CrO4(s) → 2K+(aq) + CrO42-(aq) with the solubility product expression as Ksp = [K+]2 × [CrO42-].

Explanation:

The compound that forms from potassium and chromate has the formula K2CrO4. When this compound dissolves in water, it dissociates into ions. The balanced chemical equation representing the dissolution of potassium chromate is:

K2CrO4(s) → 2K+(aq) + CrO42-(aq)

The solubility product expression (Ksp) for this dissolution can be written as follows:

Ksp = [K+]2 × [CrO42-]

The relationship signifies the product of the squared concentration of potassium ions and the concentration of chromate ions is constant at a given temperature. This equilibrium expression is vital in predicting the solubility behavior of the compound in aqueous environments, guiding our understanding of its potential to form precipitates based on ion concentrations in solution.

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#1: In the electromagnetic spectrum, which of the following types of radiation has less energy than visible light?
A. microwaves

B. ultraviolet

C. X rays

D. gamma rays
**my answer: A. microwaves

Answers

A microwaves. X Rays, gamma rays, and UV light all have higher frequencies, shorter wave lengths, and higher energy than visible light. However, microwaves have lower frequencies, longer wave lengths, and lower energy than visible light.

Microwaves have lower energy than visible light in the electromagnetic spectrum. Infrared radiation is used by heat-sensitive cameras to detect heat loss, and is also the type of radiation that can be felt as heat by our skin. Radio waves have the longest wavelengths and hence the lowest energy within the electromagnetic spectrum.

The answer to the question 'which of the following types of radiation has less energy than visible light?' is A. microwaves. Microwaves are part of the electromagnetic spectrum with longer wavelengths and thus lower energy than visible light. In contrast, ultraviolet (B), X-rays (C), and gamma rays (D) all have shorter wavelengths and higher energy than visible light. The electromagnetic spectrum ranges from radio waves, which have the longest wavelengths and lowest energy, to gamma rays, which have the shortest wavelengths and highest energy. Microwaves are in between these two extremes but still have lower energy compared to visible light.

Answering question 3, the waves used to show heat loss with heat sensitive cameras are A- Infrared radiation. Infrared waves are emitted as heat by objects and can be detected by thermal cameras to show heat patterns.

For question 4, the rays that can be felt as heat are B- Infrared Radiation. These are the same waves that are commonly used in heat sensing devices and contribute to the natural warmth felt from sunlight.

Question 2 asks about electromagnetic waves with the longest wavelengths; the answer here is D- radio waves. They are at the opposite end of the spectrum compared to gamma rays, with the lowest frequencies and energy levels.

For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?
You do not need to look up any values to answer this question.
Check all that apply.
Check all that apply.
C(s,graphite)+O2(g)→CO2(g)
Li(s)+12F2(l)→LiF(s)
CO(g)+12O2(g)→CO2(g)
BaCO3(s)→BaO(s)+CO2(g)
2Li(s)+F2(g)→2LiF(s)
Li(s)+12F2(g)→LiF(s)

Answers

inal answer:

The reaction C(s, graphite) + O2(g) → CO2(g) is the one where ΔH°rxn equals the ΔH°f of the product, CO2(g), because it forms carbon dioxide from its constituent elements in their standard states. Option A

Explanation:

For an element or compound, the enthalpy change (ΔH) of a reaction that forms it from its elements in their standard states is called the standard enthalpy of formation (ΔH°f).

Therefore, ΔH°rxn is equal to ΔH°f for a reaction that produces a compound directly from its constituent elements in their most stable forms at 1 atm pressure and 25°C (298 K). Examining the provided reactions, the one that fits this description is:

C(s, graphite) + O2(g) → CO2(g)

This reaction forms carbon dioxide (CO2) directly from its elements, carbon in the form of graphite (the most stable form of carbon at standard conditions) and oxygen gas, both of which are in their standard states. Thus, ΔH°rxn for this reaction is equivalent to the ΔH°f of carbon dioxide.

Other reactions listed may be formation reactions, but they introduce compounds like fluorine in liquid form (F2(l)), which is not the standard state of fluorine at 25°C; hence, they do not meet the criteria. Option A

What is always true of a weak acid ?

Answers

the answer is d per me

Answer: D. it only partially dissociates in solution.

Explanation:

Strong acid is defined as the acid which completely dissociates when dissolved in water. They have low pH. These releases [tex]H^+[/tex] ions in their aqueous states.

[tex]HNO_3(aq.)\rightarrow H^+(aq.)+NO_3^-(aq.)[/tex]

Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases [tex]H^+[/tex] ions in their aqueous states.

[tex]CH_3COOH\rightleftharpoons CH_3COO^-+H^+[/tex]

Thus the correct option is it only partially dissociates in solution.

Who wants a metal?
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?

Both have the same molar mass.
Both have the same number of ions.
Both are made up of 6.02 x 10^23 molecules.
Both are made up of 6.02 x 10^23 formula units.,

Answers

Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?

A. Both have the same molar mass.

B. Both have the same number of ions.

C. Both are made up of 6.02 mc014-1 1023 molecules.

D. Both are made up of 6.02 mc014-2 1023 formula units.

The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D

Answer: Option (d) is the correct answer.

Explanation:

A formula unit is basically empirical formula of a compound which tells us how  many atoms of one element are combining with how many atoms of another element.

For example, empirical formula of sodium chloride is NaCl. So, basically it shows that one atom of sodium is reacting with one atom of chlorine.

Also according to Avogadro, there are [tex]6.022 \times 10^{23}[/tex] atoms present in 1 mole of each substance.

Thus, we can conclude that both are made up of [tex]6.022 \times 10^{23}[/tex] formula units best compares 1 mol of sodium chloride to 1 mol of aluminum chloride.

what astronomical equiptment did hypatia use?

Answers

Hypatia used an astrolabe.

A mothball, composed of naphthalene (c10h8), has a mass of 1.64 g . part a how many naphthalene molecules does it contain?

Answers

Answer is: 7,5·10²¹ naphthalene molecules.
m(C₁₀H₈) = 1,64 g.
n(C₁₀H₈) = m(C₁₀H₈) ÷ M(C₁₀H₈).
n(C₁₀H₈) = 1,64 g ÷ 128,17 g/mol.
n(C₁₀H₈) = 0,0125 mol.
N(C₁₀H₈) = n(C₁₀H₈) · Na.
N(C₁₀H₈) = 0,0125 mol · 6,022·10²³ 1/mol.
N(C₁₀H₈) = 7,5·10²¹.
Na - Avogadro number.

turn the word equation into a chemical balanced equation.

Potassium chlorate breaks down into potassium chloride and oxygen gas

Answers

(2)KClO3 = (2)KCl + (3)O2

you have 2 Potassium Chlorates for every 2 Potassium Chlorides and 3 Oxygen

"each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei" and is radioactive is:

Answers

The answer is Isotope. Isotopes; each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element. For example, carbon-12, carbon-13 and carbon-14 are three isotopes of the element carbon with mass numbers 12,13 and 14 respectively. 

why are more massive atoms smaller?

Answers

As you move from left to right across a period, the number of protons in the nucleus increases. The electrons are thus attracted to the nucleus more strongly, and the atomic radius is smaller

Please HELP ASAP HELP Think about the order of planets starting with the one closest to the sun, and moving outward. What two planets can be found on either side of Earth? A) Venus and Mars B) Mercury and Mars C) Venus and Mercury D) Mercury and Jupiter

Answers

your answer should be choice B:mercury and mars hope I helped
the answer is A. venus and mars being the 2nd and 4th planet

Calculate the external pressure that must be applied to seawater, 1.14 M total ion concentration at 10 degrees C if the maximum concentration allowed in the product water is 176 mg/L. Assume that all the dissolved salts in the product water is sodium chloride.

So, I know that I need to subtract the ion concentrations before using the pi=MRT formula, but I can't figure out how to convert mg/L into molarity. Please help!

Answers

C = 1.14 M , T = 10 + 273.15 = 283.15 K   salt concentration = 176 mg /L NaCl
π total = CRT = 1.14 x 0.0821 x 283.15 = 26.5 atm
mass of NaCl = 176 mg = 0.176 g
Molarity = [tex] \frac{0.176}{57.96} x \frac{1}{1L} = 3.0366 x 10^{-3} M [/tex]
maximum concentration allowed C = 3.0366 x 10⁻³ M
π max. conc. = 2 x 3.0366 x 10⁻³ x 0.0821 x 283.15 = 0.141 atm
π external = π total - π max. conc.
                 = 26.5 - 0.141 = 26.3 atm

If you have exactly 2.00 moles each, of two different substances, then which of the following must be true about the two samples? They have the same mass. They have the same weight. They have the same number of particles. Both b and c.

Answers

1 mole of any substance contains 6.022 x 10²³ molecules. however the masses of moles may vary between elements. The molar masses of different elements vary. e.g.; Na molar mass is 23 g/mol whereas Mg molar mass is 24 g/mol.
1 mol of Na weights 23 g whereas 1 mol of Mg weighs 24g.
If 2 substances have same number of moles, their masses may vary depending on the molar masses of the elements but the number of particles of both substances are the same.
correct answer is they have the same number of particles

If you have 2.00 moles each of two different substances, then they have the same number of particles.

What are moles?

In the International System of Units, Mole is the base unit of the amount of any substance.

If two compounds have the same number of moles, their masses may differ based on the molar masses of the elements.

Both substances have the same number of particles.

Thus, the correct option is B, They have the same number of particles.

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Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of:

Answers

Covalent bonds form between hydrogen and oxygen atoms in a water molecule as a result of - Sharing of electrons between atoms.

The oxidation number of hydrogen in sodium hydride (NaH)

Answers

The oxidation number should be -1

In sodium hydride (NaH), the oxidation number of hydrogen is -1, which is an exception to its usual +1 state, as it forms an ionic bond with sodium.

The oxidation number of hydrogen is typically +1, but in compounds known as metal hydrides, such as sodium hydride (NaH), the oxidation number for hydrogen is -1. This is due to hydrogen forming an ionic bond with the metal sodium, resulting in the hydride ion (H-). Since NaH is an ionic compound, we assign sodium (Na) an oxidation number of +1, which is characteristic for metals in Group IA. Consequently, to balance the charge, hydrogen must have an oxidation number of -1 in NaH, making it an exception to the typical +1 oxidation state of hydrogen when covalently bonded to nonmetals.

What's the difference between cracking and pyrolysis? (in organic chemistry).,

Answers

In chemistry, the difference between cracking and pyrolysis is significant. Cracking is defined as the thermal decomposition such as the production of petrol or gasoline that is from crude petroleum. While pyrolysis is the decomposition due to heat without the presence of reagents such as oxygen.

A sample of a compound of mercury and bromine with a mass of 0.389 g was found to contain 0.111 g bromine. its molecular mass was found to be 561. what are its empirical and molecular formulas?

Answers

Hello!

1) To get the empirical formula, we'll need to do the following:

First, we'll need to determine the mass of mercury (Hg) using the following equation:

[tex]mHg=mTotal-mBr=0,389 g - 0,111 g = 0.278 g Hg[/tex]

Now, we calculate the moles of each atom, using atomic masses:

[tex]molesHg=0,278gHg* \frac{1 mol Hg}{200,592gHg}= 0,001386 molHg \\ \\ molesBr=0,111gBr* \frac{1 mol Br}{79,904gBr}= 0,001389 molBr[/tex]

To finish, we express the formula using the moles, and dividing each amount by the lower one (0,001386 mol):

[tex]Hg _{ \frac{0,001386}{0,001386} } Br_{\frac{0,001389}{0,001386}} =Hg_1Br_1=HgBr[/tex]

2) To calculate the molecular formula, well need to do the following:

First, we calculate the molecular mass of the empirical formula:

[tex]MMHgBr= AM Hg + AM Br= 200,592 g/mol + 79,904 g/mol \\ \\ =280 gHgBr/mol[/tex]

Now, we divide the molecular mass of the compound between the molecular mass of the empirical formula to know how many empirical formulas are in the molecular formula:

[tex]\frac{561g/mol}{280g/mol}=2 [/tex]

To finish, we multiply the coefficients in the empirical formula by the number we just calculated to get the molecular formula:

[tex]Hg_{1*2} Br_{1*2}=Hg_2Br_2 [/tex]

Have a nice day!

The empirical formula of the given compound is [tex]\boxed{{\text{HgBr}}}[/tex].

The molecular formula of the given compound is [tex]\boxed{{\text{H}}{{\text{g}}_2}{\text{B}}{{\text{r}}_2}}[/tex] .

Further explanation:

Empirical formula:

It is atom’s simplest positive integer ratio in compound. It may or may not be same as that of molecular formula. For example, the empirical formula of sulfur dioxide is [tex]{\text{SO}}[/tex] .

Molecular formula:

It is chemical formula that indicates total number and kinds of atoms in molecule. For example, molecular formula of sulfur dioxide is [tex]{\text{S}}{{\text{O}}_2}[/tex] .

Step 1: Mass of mercury (Hg) is to be calculated. This is done by using equation (1).

Since the given compound consists of only mercury and bromine. So the mass of mercury is calculated as follows:

[tex]{\text{Mass of mercury}}\left({{\text{Hg}}}\right)={\text{Mass of compound}} - {\text{Mass of bromine}}\left({{\text{Br}}}\right)[/tex]

…… (1)

The mass of the compound is 0.389 g.

The mass of bromine is 0.111 g.

Substitute the values in equation (1).

[tex]\begin{aligned}{\text{Mass of mercury}}&={\text{0}}{\text{.389 g}} - {\text{0}}{\text{.111 g}}\\&={\text{0}}{\text{.278 g}}\\\end{aligned}[/tex]

Step 2: The moles of mercury and bromine are to be calculated.

The formula to calculate the moles of mercury is as follows:

[tex]{\text{Moles of Hg}} = \frac{{{\text{Given mass of Hg}}}}{{{\text{Molar mass of Hg}}}}[/tex]                               …… (2)

The given mass of Hg is 0.278 g.

The molar mass of Hg is 200.59 g/mol.

Substitute these values in equation (2).

[tex]\begin{aligned}{\text{Moles of Hg}}&=\left( {{\text{0}}{\text{.278 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{200}}{\text{.59 g}}}}}\right)\\&=0.0013859\\&\approx{\text{0}}{\text{.001386 mol}}\\\end{gathered}[/tex]

The formula to calculate the moles of bromine is as follows:

[tex]{\text{Moles of Br}} = \frac{{{\text{Given mass of Br}}}}{{{\text{Molar mass of Br}}}}[/tex]                           …… (3)

The given mass of Br is 0.111 g.

The molar mass of Br is 79.90 g/mol.

Substitute these values in equation (3).

[tex]\begin{aligned}{\text{Moles of Br}}&=\left({{\text{0}}{\text{.111 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{79}}{\text{.90 g}}}}}\right)\\&= 0.0013892\\&\approx{\text{0}}{\text{.001389 mol}}\\\end{gathered}[/tex]

Step 4: The moles of mercury and bromine are to be written with their corresponding subscripts.

So the preliminary formula becomes,

[tex]{\text{Preliminary formula of the compound}}={\text{H}}{{\text{g}}_{0.001386}}{\text{B}}{{\text{r}}_{0.001389}}[/tex]

Step: Each of the subscripts is divided by the smallest subscript to get the empirical formula.

In this case, the smallest one is 0.001386. So the empirical formula of the compound is written as follows:

[tex]\begin{aligned}{\text{Empirical formula of the compound}}&={\text{H}}{{\text{g}}_{\frac{{0.001386}}{{0.001386}}}}{\text{B}}{{\text{r}}_{\frac{{0.001389}}{{0.001386}}}}\\&={\text{H}}{{\text{g}}_1}{\text{B}}{{\text{r}}_{1.002}}\\&\approx {\text{HgBr}}\\\end{aligned}[/tex]

Therefore the empirical formula of the compound is [tex]{\mathbf{HgBr}}[/tex] .

Step 6: The empirical formula mass of the compound is to be calculated. This is done by using equation (4).

[tex]{\text{Empirical formula mass of HgBr}}=\left( 1 \right)\left({{\text{Atomic mass of Hg}}}\right) + \left(1\right)\left({{\text{Atomic mass of Br}}}\right)[/tex]

…… (4)

Substitute 200.59 g/mol for the atomic mass of Hg and 79.90 g/mol for the atomic mass of Br in equation (4).

[tex]\begin{aligned}{\text{Empirical formula mass of HgBr}}&=\left( 1 \right)\left({{\text{200}}{\text{.59 g/mol}}}\right) + \left( 1 \right)\left( {{\text{79}}{\text{.90 g/mol}}}\right)\\ &= 280.49\;{\text{g/mol}}\\\end{gathered}[/tex]

Step 7: The molar mass of the compound is divided by its empirical formula mass to get a whole number. The formula for this is as follows:

[tex]{\text{Whole - number multiple}} = \frac{{{\text{Molar mass of compound}}}}{{{\text{Empirical formula mass}}}}[/tex]                        …… (5)

Substitute 560 g/mol for the molar mass of the compound and 280.49 g/mol for the empirical formula mass of the compound in equation (5).

[tex]\begin{aligned}{\text{Whole - number multiple}}& = \frac{{{\text{560 g/mol}}}}{{{\text{280}}{\text{.49 g/mol}}}}\\&= 1.99\\&\approx2\\\end{aligned}[/tex]

Step 8: The empirical formula is multiplied by the whole number multiple to get the molecular formula. So the molecular formula of the compound is [tex]{\mathbf{H}}{{\mathbf{g}}_{\mathbf{2}}}{\mathbf{B}}{{\mathbf{r}}_{\mathbf{2}}}[/tex] .

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Stoichiometry of formulas and equations

Keywords: empirical formula, Hg, Br, HgBr, Hg2Br2, subscript, moles of Br, moles of Hg, mass of Hg, mass of Br, molecular formula, 2, preliminary formula.

I need Chemistry help (Connections Unit 6 Lesson 3)

1. A sample of gold (Au) has a mass of 35.12 g.
a. Calculate the number of moles of gold (Au) in the sample and record in
Table 1. Show your work.
b. Calculate the number of atoms of gold (Au) in the sample and record
in Table 1. Show your work.
2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.
a. Calculate the number of moles of C12H22O11 contained in the sample
and record in Table 1. Show your work.

Answers

1) Number of moles = mass of Au/ molar mass of Au
 Mass = 35.12g and molar mass = 196.699.
  Number of moles = 35.12/196.699 = 0.178

 2) The number of atoms or molecules in one mole of a substance, equal to 6.023 * 10^23.
 Hence it follows there are 6.0233 * 10^23 * 0.178 = 1.0702 * 10^23 atoms. 3) Number of moles of sucrose = mass/molar mass.
  Molar mass of C12H22O11 = (12*2) + (1*22) + (16 * 11) = 24 + 22 + 176 = 222
 Number of moles = 1.202/222 = 0.0054

Answer:

For 1a: The number of moles of gold are 0.178 moles.

For 1b: There are [tex]1.071\times 10^{23}[/tex] atoms of gold.

For 2: The number of moles of [tex]C_{12}H_{22}O_{11}[/tex] are 0.0035 moles.

Explanation:

To calculate the number of moles, we use the following formula:

[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]     .....(1)

For 1a:

We are given:

Given mass of Au = 35.12g

Molar mass of Au = 196.97 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of Gold}=\frac{35.12g}{196.97g/mol}=0.178moles[/tex]

Hence, the number of moles of gold are 0.178 moles.

For 1b:

To calculate the number of atoms in 0.178 moles of gold, we follow mole concept.

According to mole concept:

1 mole of an element contains [tex]6.022\times 10^{23}[/tex] number of atoms.


So, 0.178 moles of gold will contain [tex]0.178\times 6.022\times 10^{23}=1.071\times 10^{23}[/tex] atoms.

Hence, there are [tex]1.071\times 10^{23}[/tex] atoms of gold.

For 2:

We are given:

Given mass of [tex]C_{12}H_{22}O_{11}[/tex] = 1.202g

Molar mass of [tex]C_{12}H_{22}O_{11}[/tex] = 342 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of }C_{12}H_{22}O_{11}=\frac{1.202g}{342g/mol}=0.0035moles[/tex]

Hence, the number of moles of [tex]C_{12}H_{22}O_{11}[/tex] are 0.0035 moles.

what is this ch3ch2ch2ch2ch2ch3 ???

Answers

ch3ch2ch2ch2ch2ch3 Is called Hexane, it is a colorless liquid hydrocarbon
Final answer:

CH3CH2CH2CH2CH2CH3 represents Hexane, a chemical compound in the alkane family, which are hydrocarbons with only single bonds. Hexane has six carbon atoms and 14 hydrogen atoms.

Explanation:

The formula CH3CH2CH2CH2CH2CH3 represents a compound called Hexane. It follows a chain structure with six carbon atoms and 14 hydrogen atoms. The prefix 'hex-' denotes six, indicating six carbon atoms, and '-ane' denotes a single bond between the carbon atoms. The molecule is classified as an alkane, a member of a group of hydrocarbons (compounds made up of hydrogen and carbon) in which there are only single bonds. Alkanes are also known as saturated hydrocarbons.

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Which of the compounds, c3h8, mgcl2, zn(no3)2, ocl2, are expected to exist as molecules?

Answers

The answer is C3H8 and OCl2  they are molecular compounds. MgCl2 is an ionic compound while Zn(NO3)2 is an inorganic chemical compound. 
Molecular compounds are covalent compounds in which the elements share electrons via covalent bonds. They are inorganic compounds that take the form of discrete molecules, for example water and carbon dioxide.

Explanation:

A molecular compound is a compound in which atoms share electrons with each other and thus, forms covalent bonds. As a result, molecular compounds are covalent compounds.

In the compound [tex]C_{3}H_{8}[/tex], since hydrogen atom has only one electron and carbon atom has 4 electrons in its valence shell. So, in order to completely fill its octet both carbon and hydrogen will share electrons with each other.

Therefore, [tex]C_{3}H_{8}[/tex] is a covalent compound. Hence, it is also a molecular compound.

In [tex]MgCl_{2}[/tex], magnesium being a metal has excess of electrons and chlorine being a non-metal has deficiency of electrons. Thus, magnesium donates its two electrons to both the chlorine atoms and forms an ionic bond.

Hence, [tex]MgCl_{2}[/tex] is an ionic compound. Thus, it is not a molecular compound.

In [tex]OCl_{2}[/tex], both oxygen and chlorine are non-metals. Hence, they have deficiency of electrons. As a result, both oxygen and chlorine will share electrons in order to complete their octet.

So, there will be formation of covalent bonds. Thus, [tex]OCl_{2}[/tex] is a molecular compound.

[tex]Zn(NO_{3})_{2}[/tex] is an inorganic compound and dissolves in water to form ions of [tex]Zn^{2+}[/tex] and [tex]NO^{-}_{3}[/tex]. Hence, [tex]Zn(NO_{3})_{2}[/tex] is an ionic compound.

Thus, we can conclude that out of the given options, [tex]C_{3}H_{8}[/tex] and [tex]OCl_{2}[/tex] exists as molecules.

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