Which box plot represents the data?

135, 149, 156, 112, 134, 141, 154, 116, 134, 156

The approximate surface area of the sphere will be 707 yd^2

The steps are as follow:

r = 7.5 yd

Surface area of sphere = 4πr^2

Surface area of sphere = 4*π*(7.5)^2

Surface area of sphere = 706.85 yd^2

Surface area of sphere = 707 yd^2

So the approximate surface area of the sphere will be 707 yd^2

Learn more about sphere here:

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For a better understanding of the explanation provided here kindly go through the file attached.

Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.

Now, we know that the total angle in radians covered by a cosine in a given period is [tex] 2\pi [/tex] and the period given in the question is t=3 seconds. Therefore, the angular velocity, [tex] \omega [/tex] of the mentioned system will be:

[tex] \omega=\frac{2\pi}{3} [/tex]

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

[tex] d=-9cos(\frac{2\pi}{3})t [/tex]

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.

Answer: B.

Step-by-step explanation:

answer on edge

Answer:

[tex](x,y)\rightarrow (-x,-y)[/tex]

Step-by-step explanation:

We are asked to find the the algebraic rule describes the 180° counterclockwise rotation about the origin .

We know that when we rotate a point 180° counterclockwise rotation about the origin , the x and y-coordinates change their sign.

[tex](x,y)\rightarrow (-x,-y)[/tex]

Therefore, our required rule is [tex](x,y)\rightarrow (-x,-y)[/tex].

The area that a dog can roam, attached to a 49-foot rope at the corner of a 42x51 foot garden, was initially calculated as a quarter-circle's area with mistakes acknowledged in the approach. The correct calculation involves more intricate geometrical considerations, considering the question's unique constraints.

To determine the area that a dog can wander, given it's attached to a 49-foot rope fastened to the outside corner of a fenced-in garden measuring 42 feet by 51 feet, we need to consider the shape of the area the dog can cover. The dog can cover a quarter-circle around each of two adjacent sides of the garden and a semi-circle along the side opposite the corner where the rope is fastened, provided the rope's length exceeds the garden's dimensions on those sides.

Calculating the area involves adding the areas of these three parts:

Therefore, the total area that the dog can wander is effectively the area of a quarter-circle with a radius of 49 feet. This can be calculated as:

Area = 1/4 * π * (49)^2 square feet

Calculating this gives an area of 1884.96 square feet (rounded to two decimal places).

However, upon reevaluation, it's clear that a mistake was made in the initial explanation; the correct approach is to consider not just a quarter-circle but also the additional areas the rope covers beyond the garden's dimensions.

The exact area that the dog can wander is [tex]{2401\pi} \)[/tex] square feet.

Identify the radius: The radius of the circle that the dog can wander is the length of the rope, which is 49 feet.

Calculate the area of the circle: Use the formula for the area of a circle, [tex]\( A = \pi r^2 \)[/tex], where [tex]\( r = 49 \)[/tex] feet.

[tex]\[ A = \pi \times 49^2 \][/tex]

Compute [tex]\( 49^2 \)[/tex]:

[tex]\[ 49^2 = 2401 \][/tex]

Multiply to find the area:

[tex]\[ A = \pi \times 2401 \][/tex]

The exact area that the dog can wander is [tex]{2401\pi} \)[/tex] square feet.

This calculation confirms that the dog can wander an area of [tex]\( 2401\pi \)[/tex] square feet within the fenced-in garden while attached to the 49-foot rope.

Calculate the cost per apple for large and small baskets, $0.39 per apple is the closest estimate.

To estimate the cost per apple, one must calculate the price of each apple in the large and small baskets, then average these amounts, resulting in approximately 44 cents per apple.

To find the cost per apple:

Calculate the cost per apple in the large basket: $22.95 / 59 apples = $0.39 per apple.

Calculate the cost per apple in the small basket: $8.95 / 18 apples = $0.50 per apple.

Compare the two costs: $0.39 is the closest estimate of the cost per apple.

Answer:

Ok so ppl it just A

Step-by-step explanation:

To solve this problem, we must first subtract 4 from both sides of the inequality. This gives us -2 ≥ -v. Next divide both sides by -1. Remember, when you divide by a negative in an inequality, it becomes necessary to flip the direction of the inequality symbol. Therefore, the answer to the inequality is 2 ≤ v, which is equivalent to v ≥ 2.

Lance rolls a die 5 times

In a six sided dice, the even numbers are 2, 4  and 6. So 3 even numbers

the probability that he rolls an even number = [tex]\frac{3}{6} = \frac{1}{2}[/tex]

the probability that he rolls an even number all five times

= [tex]\frac{1}{2} *\frac{1}{2} * \frac{1}{2} * \frac{1}{2} * \frac{1}{2}= \frac{1}{32}[/tex]

So answer is [tex]\frac{1}{32}[/tex]

Answer:

The correct option is C.

Step-by-step explanation:

In a dot plot, the number of dots above a number represents the frequency of that number.

From the given dot plot it is clear that number of dots for group R is 21 and the time taken by the students of groups R are

45, 50, 50, 55, 60, 60, 70, 75, 80, 85, 90, 90, 95, 100, 100, 105, 110, 110, 115, 120, 120

The average of the data is

[tex]Average=\frac{\sum x}{n}[/tex]

[tex]Average=\frac{45+50+50+55+60+60+70+75+80+85+90+90+95+100+100+105+110+110+115+120+120}{21}[/tex]

[tex]Average=\frac{1785}{21}[/tex]

[tex]Average=85[/tex]

From the given dot plot it is clear that number of dots for group S is 17 and the time taken by the students of groups S are

50, 55, 60, 60, 65, 70, 70, 80, 90, 90, 95, 100, 105, 110, 110, 115, 120

[tex]Average=\frac{50+55+60+60+65+70+70+80+90+90+95+100+105+110+110+115+120}{17}[/tex]

[tex]Average=\frac{1445}{17}[/tex]

[tex]Average=85[/tex]

The average time of both groups are same.

Since both groups show about the same average time, therefore the correct option is C.

To solve this problem, we are going to use a proportion, letting the variable x represent the unknown number of cups of oatmeal that we need.

1.5 cups/36 cookies = x cups/60 cookies

To simplify a proportion like this, we can use cross-multiplication. This means multiplying the numerator of one fraction by the denominator of the other fraction and setting it equal to the product of the other numerator and denominator. This is modeled below:

(36)(x) = (1.5)(60)

To simplify, we begin by multiplying out each side.

36x = 90

Finally, we divide both sides of the equation by 36.

x = 2.5

This means that we need 2.5 cups of oatmeal to make the cookies.

Hope this helps!

Final answer:

The inequality representing the number of karate classes Theo can take is c ≤ 17, considering his budget after buying a dogi and the cost per class.

Explanation:

The question asks us to find the inequality that represents the number of karate classes, c, Theo can take given his budget scenario. Theo budgets $154 for his karate classes and spends $12 on a dogi. This leaves Theo with $154 - $12 = $142 for classes. Since each class costs $8, we divide the remaining budget by the cost per class to find the maximum number of classes he can take:

$142 ÷ $8 = 17.75.

Since Theo cannot attend a fraction of a class, we round down to 17. The inequality representing the number of classes Theo can take would be c ≤ 17, where c is the number of classes Theo can attend.

The inequality that represents the number of classes, [tex]\( c \)[/tex], that Theo can take is:

[tex]\[ 8c + 12 \leq 154 \][/tex]

To derive this inequality, we start by considering the total amount Theo has budgeted for karate classes, which is $154. From this budget, Theo has already spent $12 on purchasing a karate uniform. Therefore, the remaining amount available for attending the classes is [tex]\( 154 - 12 \)[/tex].

Now, each karate class costs $8, so the total cost for attending [tex]\( c \)[/tex] classes is [tex]\( 8c \)[/tex]. To ensure that Theo does not exceed his budget, the total cost including the uniform should be less than or equal to $154.

Hence, the inequality that represents this situation is:

[tex]\[ 8c + 12 \leq 154 \][/tex]

This inequality states that the cost of the uniform plus the cost of the classes must be less than or equal to Theo's budget. Solving for [tex]\( c \)[/tex] will give us the maximum number of classes Theo can attend without exceeding his budget.

What is the product of 2.31 and 0.21?

Solution:

We need to find 2.31*0.21

Let us first find 231*21, then we would consider decimals

231*1=231

231*2=462

So, 231*21=231+4620=4851

So, we get 231*21=4851

But, we need to find, 2.31*0.21

There are two numbers after decimal in 2.31 (3 and 1). and, there are two numbers after decimal in 0.21(2 and 1)

So, In result of, 2.31*0.21 there must be four digits after decimal.

As, 231*21=4851

So, 2.31*0.21=0.4851 (four digits after decimal)

Answer:0.4851