Which element is an actinoid?

Answer:

The rate of oxygen consumption by muscle and brain cells will decrease. The MT-ND5 mutation causes a buildup of lactic acid which occurs as a result of glycolysis not entering the Krebs cycle and instead entering fermentation. Because it is not entering the krebs cycle, there is no oxygen being consumed.

Explanation:

The MT-ND5 mutation potentially disrupts mitochondrial function, decreasing the rate of oxygen consumption in muscle and brain cells. Introducing a NADH-like vitamin may increase the activity of the affected NADH dehydrogenase enzyme, thereby restoring oxygen consumption and ATP production.

The MT-ND5 mutation would likely affect the rate of oxygen consumption by disrupting mitochondrial function in both muscle and brain cells. Mitochondria are responsible for cellular respiration where oxygen is consumed to create ATP, a high-energy compound. Any mutation disrupting this process would likely decrease the rate of oxygen consumption.

As the MT-ND5 mutation affects the NADH dehydrogenase enzyme, it impedes the electron transport chain which is critical for ATP production. The researcher's hypothesis is that introducing a vitamin similar to NADH could potentially increase the enzyme's activity. As NADH plays a crucial role in transferring electrons in the electron transport chain, increasing NADH or a similar compound could restore or enhance the function of the enzyme, thereby potentially increasing ATP production and oxygen consumption.

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Yes, you can use the given information to calculate the solubility of substance X in water at 26 degrees Celsius. You would do this by dividing the mass of X (0.36 kg) by the volume of the water (3.00 L), resulting in a solubility of approximately 120 g/L.

1. Yes, you can calculate the solubility of X in water at 26 degrees Celsius with the information provided. The reason being solubility is defined as the maximum quantity of a substance that can be dissolved in a given amount of solvent at a certain temperature.

2. To calculate the solubility, you would take the mass of the compound dissolved (0.36 kg or 360 g) and divide it by the volume of water in which it was dissolved (3.00 L).
Solubility = (360 g / 3.00 L) ≈ 120 g/L. Hence, the solubility of X at 26° C is approximately 120 g/L, to two significant figures.

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Answer:

See explaination

Explanation:

An electrochemical cell is a device capable of either generating electrical energy from chemical reactions or using electrical energy to cause chemical reactions.

See attachment for the step by step solution of the given problem.

Answer:

CN⁻(aq) + H⁺(aq) → HCN(l)

Explanation:

The reactants are aqueous solutions:

NaCN(aq) and HBr(aq)

When you mix these compounds you make pure HCN (l)

The molecular equation is:

NaCN(aq) + HBr(aq) → NaBr(aq) + HCN(l)

When you dissociate the reactants, you have:

Na⁺(aq) +CN⁻(aq) + H⁺(aq) + Br⁻(aq) → Na⁺(aq) + Br⁻(aq) + HCN(l)

Sodium bromide, it is a salt, that can also be dissociated in the solution

To make, the net ionic equation you remove the repeated ions

CN⁻(aq) + H⁺(aq) → HCN(l)

The net ionic equation for the reaction between sodium cyanide and hydrobromic acid, resulting in sodium bromide and hydrocyanic acid, is CN-(aq) + H+(aq) → HCN(aq). This equation only includes the reacting species.

The reaction between sodium cyanide (NaCN) and hydrobromic acid (HBr) results in the formation of sodium bromide (NaBr) and hydrocyanic acid (HCN). This can be written as a chemical equation: NaCN(aq) + HBr(aq) → NaBr(aq) + HCN(aq). The net ionic equation for the reaction is: CN-(aq) + H+(aq) → HCN(aq). This equation represents only the species that are involved in the reaction and doesn't include the spectator ions (in this case, Na+ and Br-).

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Answer:

The answer is -791.5 kJ (option c)

Explanation:

You know:

SO₂ (g) → S (s) + O₂ (g) ΔH°rxn = +296.8 kJ

2 SO₂ (g) + O₂ (g) → 2 SO₃ (g) ΔH°rxn = -197.8 kJ

You must add them to obtain the desired equation:

2 S(s) + 3 O₂(g) → 2 SO₃(g) ΔH°rxn = ?

You want to calculate the ∆H (heat of reaction) of the combustion reaction, that is, the heat that accompanies the entire reaction. The calculation is made using Hess's law. This law states: when the reactants are converted to products, the enthalpy change is the same, regardless of whether the reaction is carried out in one step or in a series of steps.

In Hess's law he explains that the enthalpy changes are additive, ΔHneta = ΣΔHr and contains three rules:

The sum of the fitted equations should give the problem equation. In this case:

2*( S(s) +  O₂(g)  → SO₂ )     To obtain the desired reaction, this equation must be inverted, so the enthalpy value is also inverted.  It must also be multiplied by 2, then the whole equation is multiplied, both reactants and products and the value of the enthalpy.  So ΔH°rxn = (-296.8 kJ)*2= -593.6 kJ

2 SO₂(g) + O₂(g) → 2 SO₃ (g)               ΔH°rxn = -197.8 kJ

____________________________________________________

2 S(s) + 3 O₂(g) → 2 SO₃(g)    ΔH°rxn =  -791.4 kJ ( Enthalpies are added algebraically)

The answer is -791.5 kJ (option c)

The value of ΔH°rxn for the 2S(s) + 3O₂(g) → 2SO₃(g) is -791.4 kJ.

Enthalpy of the reaction tells about the amount of heat released or absorbed during any chemical reaction.

Given that,

2SO₂(g) + O₂(g) → 2SO₃(g)               ΔH°rxn = -197.8 kJ

SO₂(g) → S(s) + O₂(g)                         ΔH°rxn =  296.8 kJ

To obtain the required reaction first we have to invert the second equation and multiply that by 2 and then add with the left hand side as well as the right hand side of the reaction, we get:

2S(s) + 3O₂(g) → 2SO₃(g)

ΔH°rxn of the reaction will be calculated as-

ΔH°rxn = -2(296.8 kJ) + (-197.8 kJ)

ΔH°rxn = -791.4 kJ

Hence, option (C) is correct i.e. -791.4 kJ.

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Answer:

The balanced chemical equation is given as:

[tex]2Mg(s)+O_2(g)\rightarrow 2MgO(s)[/tex]

Explanation:

When magnesium metal burns in presence of oxygen it gives white color powdered compound called magnesium oxide.

The balanced chemical equation is given as:

[tex]2Mg(s)+O_2(g)\rightarrow 2MgO(s)[/tex]

According to reaction, 2 moles of magnesium metal when reacts with 1 mole of oxygen gas it gives 2 moles of  solid magnesium oxide.

Answer:

lemon juice

Explanation:

lemons are acidic.

Answer:

the answer is lemon.

Explanation:

Answer : The moles of [tex]NH_3[/tex] formed are, 22.3 moles.

Explanation : Given,

Moles of [tex]N_2H_4[/tex] = 16.72 mol

The given chemical reaction is:

[tex]3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)[/tex]

From the balanced chemical reaction, we conclude that:

As, 3 moles of [tex]N_2H_4[/tex] react to give 4 moles of [tex]NH_3[/tex]

So, 16.72 moles of [tex]N_2H_4[/tex] react to give [tex]\frac{4}{3}\times 16.72=22.3[/tex] moles of [tex]NH_3[/tex]

Therefore, the moles of [tex]NH_3[/tex] formed are, 22.3 moles.

Answer:

114 K

Explanation:

Given data

We can calculate the temperature at which the student collected the oxygen using the ideal gas equation.

[tex]P \times V = n \times R \times T\\T = \frac{P \times V}{n \times R} = \frac{0.500atm \times 0.629L}{0.0337mol \times 0.0821atm.L/mol.K} = 114 K[/tex]

The oxygen gas was collected at 114 K.

Answer:

The temperature is 114 K or -159ºC

Explanation:

We must use the ideal gas equation to calculate the temperature in K:

P x V = n x R x T

⇒ T = (P x V)/(n x R)

We have to introduce the data expressed in the adequate units:

V = 629 ml x 1 L/1000 ml= 0.629 L

n = 0.0337 moles

P = 0.500 atm

R = 0.082 L.atm/K.mol (it is the gas constant)

T = (P x V)/(n x R) = (0.500 atm x 0.629 L)/(0.0337 mol x 0.082 L.atm/K.mol)

T = 113.8 K ≅ 114 K

Thus, the temperature is 114 K or -159ºC.

Answer: The concentration of acetic acid in the vinegar is 0.585 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]CH_3COOH[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.

We are given:

[tex]n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1871M\\V_2=31.26mL[/tex]

Putting values in above equation, we get:

[tex]1\times M_1\times 10.0=1\times 0.1871\times 31.26\\\\M_1=0.585M[/tex]

Thus the concentration of acetic acid in the vinegar is 0.585 M

The concentration of acetic acid in the vinegar solution is 0.585 M. This was determined by calculating the moles of acetic acid using the volume and molarity of the NaOH solution necessary to neutralize the acetic acid and then applying the definition of molarity.

In a titration of acetic acid (found in vinegar) with sodium hydroxide, the point at which all the acetic acid has been neutralized by the sodium hydroxide is called the equivalence point. The number of moles of sodium hydroxide used will be equal to the number of moles of acetic acid in the solution.

From the given data of the sodium hydroxide solution volume (31.26 mL) and molarity (0.1871 M), the moles of NaOH can be calculated as follows: Moles of NaOH = Volume (L) x Molarity = 0.03126 L x 0.1871 mol/L = 0.00585 mol

This is equal to the moles of acetic acid in the 10 mL sample of vinegar. Hence the molarity (and therefore the concentration) of acetic acid in vinegar is given by: Molarity = Moles / Volume (L) = 0.00585 mol / 0.01 L = 0.585 M

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Answer:

D) The water is releasing energy as its temperature decreases, and that energy is absorbed by the surroundings.

Explanation:

When the temperature decreases it loses energy to the surroundings. When water cools and then freezes to ice it becomes a solid which has a lower energy compared to liquid and gas. Solid is more compact and little or no collision occurs between its particles.

This means energy was lost during the process of freezing to ice. The energy lost is normally absorbed by the surrounding environment.

Final answer:

The water releases energy as it cools and turns to ice, which is absorbed by the surroundings. This describes an exothermic process where the heat flow involves energy leaving the system and increasing the entropy of the surroundings. Thus, option D is correct.

Explanation:

When water cools from 10 °C and freezes to become ice, the correct description of the heat flow between the system and the surroundings is that the water is releasing energy as its temperature decreases, and that energy is absorbed by the surroundings. So the best answer is D) The water is releasing energy as its temperature decreases, and that energy is absorbed by the surroundings.

This process of cooling and freezing is exothermic, which means heat is exiting the system. During the phase change from liquid to solid, the temperature remains constant at the melting/freezing point, and the heat energy released due to the formation of a more structured lattice of ice molecules is absorbed by the surroundings. This results in an increased entropy in the surroundings which compensates for the decreased entropy of the system (water turning into ice).

Answer:

a. NH₃(g) + HCl(g) →  NH₄Cl(s)

b. HCl is the limiting reagent

c. 7.35 g of NH₄Cl

d. 0.039 moles of NH₃ remains after the reaction is complete (0.663 grams of ammonia)

Explanation:

First of all, we define the reaction where the reactants are the ammonia and the hydrogen chloride. The product is the ammonium chloride.

NH₃(g) + HCl(g) →  NH₄Cl(s)

First of all, we need to determine the limiting reactant. As the ratio is 1:1, the compound that has the lowest mol, will be the limiting.

3 g / 17g/mol = 0.176 moles NH₃

5 g / 36.45 g/mol = 0.137 moles HCl (limiting reactant)

For 0.176 moles of ammonia, we need the same of HCl, but we have 0.137 moles. We convert the moles to mass, in order to know how many grams of NH₄Cl are produced → 0.137 mol . 53.45 g /1mol = 7.32 g

As ratio is 1:1, and the limiting reagent is the HCl, after the reaction goes complete, some ammonia remains. This is because, the ammonia is the excess reagent.

0.176 mol - 0.137 moles = 0.039 moles of NH₃ remains after the reaction is complete; we convert the moles to mass → 0.039 mol . 17 g /mol = 0.663 g are left over in the reaction mixture.

Final answer:

The balanced chemical equation for the reaction between ammonia and hydrogen chloride to form ammonium chloride is NH3(g) + HCl(g) → NH4Cl(s). Ammonia is the limiting reagent in the given mixture, and the theoretical yield of ammonium chloride is 9.42 g. No excess reactant will be left over after the reaction.

Explanation:

Chemical Reaction Between Ammonia and Hydrogen Chloride

When ammonia gas (NH3) combines with hydrogen chloride gas (HCl), solid ammonium chloride (NH4Cl) is formed. The balanced chemical equation for this reaction is:

NH3(g) + HCl(g) → NH4Cl(s).

Limiting Reagent and Yield

In a reaction mixture with 3.0 g of ammonia and 5.0 g of hydrogen chloride, to find the limiting reagent we must compare the mole ratio of the reactants to their stoichiometric ratio in the balanced equation. Using molar masses (NH3: 17.03 g/mol, HCl: 36.46 g/mol), we find that:

NH3: 3.0 g × (1 mol / 17.03 g) ≈ 0.176 moles

HCl: 5.0 g × (1 mol / 36.46 g) ≈ 0.137 moles

The stoichiometry of the reaction is 1:1, so ammonia is the

limiting reagent

because we have fewer moles of it relative to HCl.

The mass of ammonium chloride formed is based on the limiting reagent. Since all of the ammonia will react, the theoretical yield of NH4Cl is the moles of NH3 times the molar mass of NH4Cl (53.49 g/mol):

0.176 moles × 53.49 g/mol ≈ 9.42 g of NH4Cl.

Excess Reactant Left Over

To determine the amount of excess reactant left over, we subtract the number of moles of HCl that reacted (equivalent to the moles of NH3) from the initial moles of HCl:

0.137 moles HCl - 0.176 moles NH3 = -0.039 moles HCl (not possible, indicating no excess HCl remains).

Answer:

See explaination

Explanation:

Molar absorptivity, also known as the molar extinction coefficient, is a measure of how well a chemical species absorbs a given wavelength of light.

It is commonly used in chemistry and should not be confused with the extinction coefficient, which is used more often in physics.

Please kindly check attachment for the step by step solution of the given problem.

Answer:

Correct option: C

Explanation:

As given in the question that distance between two ions are same in all cases hence r is same for all.

potential energy:

[tex]P.E =\frac{k\times q_{1} \times q_{2}}{r}[/tex]

therefore potential energy depend on the two charge muliplication

so higher the charge multiplication higer will be the potential energy.

magnitude of charge multiplication follow as:

a. 1

b. 2

c. 6

d. 4

e. 2

in option C it is higher

so correct option is C

Final answer:

The ion pair with the greatest electrostatic potential energy among the given pairs is Al+3 - O-2, as it has the highest product of charges according to Coulomb's Law. Option C is correct.

Explanation:

The electrostatic potential energy between two ions is determined by Coulomb's Law, which states that the energy is proportional to the product of the charges of the ions divided by the distance between them. With all distances being equal, the pair with the greatest product of charges would have the highest electrostatic potential energy. Thus, we can compare the products of charges for each pair:

Therefore, the ion pair Al+3 - O-2 has the greatest electrostatic potential energy because the product of their charges (6) is the largest.

Answer:

27.3 kJ/mol

Explanation:

You would use the Arrhenius Equation to solve this problem.

[tex]ln(\frac{k_{2} }{k_{1} } )=\frac{E_{a} }{R} (\frac{1}{T_{1} } -\frac{1}{T_{2} } )[/tex]

Plug the rate constants into k1 and k2.  Plug the temperatures into T1 and T2. R is a constant and is equal to 8.314.  Solve for Ea.

Your answer should be 27,303.03 J/mol or 27.3 kJ/mol.

Hope this helps! <3

The activation energy will be equal to "12.40 kJ/mol". To understand the calculation, check below.

According to the question,

For 1st order, rate constant = 0.060 s⁻¹

Temperature, T₁ = 298 K

                       T₂ = 331 K

Increased rate constant = 0.18s⁻¹

We know the formula,

→ ln k = ln A - [tex]\frac{E_a}{RT}[/tex]

By substituting the rate constant value,

  ln 0.06 = ln A - [tex]\frac{E_a}{298 \ R}[/tex] ...(equation 1)

  ln 0.18 = ln A - [tex]\frac{E_a}{318 \ R}[/tex] ...(equation 2)

From "equation 1 and 2", we get

Activation energy, 1.09 = [tex]\frac{83 \ E_a}{113538 \ R}[/tex]

                                  [tex]E_a[/tex] = 12.40 kJ/mol

Thus the above answer is correct.

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There is 1 carbon atom in 5K2CO3.

To determine the number of carbon (C) atoms in 5K2CO3, we need to consider the molecular formula of potassium carbonate (K2CO3). The formula indicates that there are 2 potassium (K) atoms, 1 carbon (C) atom, and 3 oxygen (O) atoms per molecule.

Since there is only 1 carbon atom in the formula, regardless of the coefficient 5 in front, there will always be 1 carbon atom in 5K2CO3.

Therefore, there is 1 carbon atom in 5K2CO3.

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Answer:

According to Le Chatelier's principle, increasing the reaction temperature of an exothermic reaction causes a shift to the left and decreasing the reaction temperature causes a shift to the right.

Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

1. for an exothermic reaction, on increasing the temperature, there is a shift in equilibrium to the left and formation of the product is favoured.

2. if the temperature of the system is decreased, the equilibrium shifts to right and the formation of the reactants is favoured.

3. if the reaction temperature is kept constant, the system is at equilibrium and there is no shift to the right nor to the left.

Answer:

Increasing temperature = balance will shift to the left

Decreasing temperature = balance will shift to the right

Explanation:

Step 1: Data given

The increase or decrease in temperature can have an influence on the position of the equilibrium.

If the temperature is increased, the system will ensure that less heat is released. So the balance will shift to the left.

When the temperature drops, however, the system will produce more heat: the balance will shift to the right.

Step 2: The balanced equation

C6H12O6(s) + 6O2(g) ⇌ 6CO2(g) + 6H2O(g)

This is an endothermic reaction

Step 3: Increasing the temperature

If the temperature were increased, the heat content of the system would increase.

In exothermic reactions, increase in temperature decreases the K value. This means less products will be formed. The balance will shift to the left.

Step 4: Decreasing the temperature

If the temperature were decreased, the heat content of the system would increase.

In exothermic reactions, decrease in temperature increases the K value. This means more products will be formed, less reactants. The balance will shift to the right.

Answer:

W = +1624J

Explanation:

V1 = 33.0L

V2 = 61.0L

P = 58 atm

Work = force * distance (∇x)

Work = F.∇x

But force = pressure * area

F = P.A

Work = P.∇x.A

Work = P∇v

Work = P (V₂ - V₁)

Work = 58 * (61 - 33)

Work = 58 * 28

Work = 1624J

The work done is +1624J

Answer:

See explaination

Explanation:

Exothermic reactions are reactions or processes that release energy, usually in the form of heat or light.

Hence when heat is sent out or released we have an Exothermic reaction.

Check attachment for further detailed solution to the given problem.

Answer:

C) 0.0532

Explanation:

Stoichiometry is an important concept in chemistry which helps us to use the balanced chemical equations to calculate the amount of reactants and products. Here the mass of 'Fe' produced from 0.0257 g Al is 0.0532 g.

Chemical Stoichiometry refers to the quantitative study of the reactants and products involved in a chemical reaction. Here we make use of the ratios from the balanced equation to calculate the amount of reactants and products.

The number of moles of 'Al' = Given mass / Molar mass

Molar mass of 'Al' = 27 g/mol

n = 0.0257 / 27 = 9.5 × 10⁻⁴ moles

Here the balanced reaction is:

Fe₂O₃  + 2 Al → Al₂O₃ + 2 Fe

using the mole ratio to determine the moles of Fe

The mole ratio of Al:Fe is 2:2 = 1:1

So the moles of Fe is also =  9.5 × 10⁻⁴ moles

The mass of iron is:

Mass = moles  x molar mass of Fe

Molar  mass of Fe=  56 g/mol

Mass=   9.5 × 10⁻⁴ x 56  =0.0532  grams

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Answer:

The value of Δ [tex]H_{rxn}[/tex] for the reaction =  463 [tex]\frac{KJ}{mol}[/tex]

Explanation:

[tex]q_{rxn} = - q_{sol}[/tex]

[tex]q_{rxn} = H_{rxn}[/tex]

Δ [tex]H_{rxn}[/tex] = - [tex]q_{sol}[/tex] ------ (1)

We know that

[tex]q_{sol} = m c ( T_{2} - T_{1} )[/tex]

[tex]q_{sol} =[/tex] (1)(100) × 4.18 × (32.8 - 25.6)

[tex]q_{sol} =[/tex]  3010 J = 3.01 Kilo Joule

From equation (1)

Δ [tex]H_{rxn}[/tex]  = 3.01 Kilo Joule

No. of moles

[tex]N = \frac{m}{M}[/tex]

m = 0.158 gm & M = 24.31  gm Mg

No. of moles    

[tex]N = \frac{0.158}{24.31}[/tex]

N = 0.0065

Therefore

Δ [tex]H_{rxn}[/tex]  = [tex]\frac{3.01}{0.0065}[/tex]

Δ [tex]H_{rxn}[/tex]  =  463 [tex]\frac{KJ}{mol}[/tex]

This is the value of Δ [tex]H_{rxn}[/tex] for the reaction.

The molality of the solution is 0.67 m, which is calculated using the moles of solute and mass of the solvent. The molar mass of the solute would depend on additional data such as osmotic pressure and temperature, and requires using the van't Hoff equation.

Calculating Molality and Molar Mass

To calculate the molality of a solution, which is the number of moles of solute per kilogram of solvent, you can use the formula:

Molality (m) = Moles of solute \/ Mass of solvent in kilograms

According to the given information, we have 0.20 moles of solute dissolved in 0.300 kg of solvent. Therefore, using the formula, we get:

Molality = 0.20 mol \/ 0.300 kg = 0.67 m (molal)

To determine the molar mass of a solute B from the given osmotic pressure, temperature, and the amount of solute (0.200 g) dissolved in a known molar volume (0.0180 L/mol) of solvent (1.00 mol), use the van't Hoff factor (i = 1 for non-electrolytes) and the equation:

y = i * (M/R * T)

Where,

n = number of moles of solute

R = gas constant (0.0821 L atm mol^-1 K^-1)

T = temperature in Kelvin

y = osmotic pressure of the solution

From the osmotic pressure formula, we can rearrange to solve for n, and then use the mass of the solute to find the molar mass:

n = y * V/(R * T)

and

Molar mass = mass of solute \/ n

The molar mass calculation will depend on more specific data such as the osmotic pressure and temperature data provided in your hypothetical variation of this exercise. To complete the calculation, one would need to work through the osmotic pressure formula with the given measurements (0.640 atm at 298 K).

Answer:

(A) 0.129 M

(B) 0.237 M

Explanation:

(A) The reaction between potassium hydrogen phthalate and barium hydroxide is:

Where A⁻ is the respective anion of the monoprotic acid (KC₈H₄O₄⁻).

We convert mass of phthalate to moles, using its molar mass:

Now we convert mmol of HA to mmol of Ba(OH)₂:

Finally we calculate the molarity of the Ba(OH)₂ solution:

(B) The reaction between Ba(OH)₂ and HCl is:

So the moles of HCl that reacted are:

And the molarity of the HCl solution is:

Answer:

1.37 x [tex]10^6[/tex] CFU/mL

Explanation:

First, the dilution factor needs to be calculated.

Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of [tex]10^{-4}[/tex].

Next is to divide the colony forming unit from the dilution by the dilution factor:

   137/[tex]10^{-4}[/tex] = 137 x [tex]10^4[/tex]

In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.

   137 x [tex]10^4[/tex]/1 = 1.37 x [tex]10^6[/tex]

Hence, the CFU/ml present in the original E. coli sample is 1.37 x [tex]10^6[/tex].

cfu/ml = (no. of colonies x dilution factor) / volume of culture plate

Answer:

The correct answer is 0.61 ml

Explanation:

Nitric acid is a strong acid. That means that it dissociates completely in water as follows:

HNO₃ → H⁺ + NO₃⁻

As the dissociation is complete, the concentration of H⁺ ions is equal to the initial concentration of the acid (HNO₃). Thus, the pH can be calculated from the initial concentration of the acid:

pH= -log [H⁺] = -log  [acid]

We want a nitric acid solution with a pH of 2.0. so we first calculate the concentration of acid we need:

2.0 = -log [acid]

10⁻²=  [acid]

The chemist has a stock solution with C= 9.0 M and he/she wants a solution with C= 1 x 10⁻² M and V= 550 ml. We use the equation that relates the initial concentration and volume (Ci and Vi, respectively) of a solution with the final concentration and volume (Cf and Vf, respectively):

Ci x Vi = Cf x Vf

⇒ Vi= (Cf x Vf)/Ci = (1 x 10⁻² M x 550 ml)/9.0 M = 0.611 ml

Summarizing, the chemist must measure 0.611 ml of concentrated solution (9.0 M), add it to the flask and fill the flask to the mark until 550 ml in order to obtain a nitric acid solution with a pH of 2.0.

Answer:

[tex][SO_2Cl_2] = 0.09983 M[/tex]

Explanation:

Write the balance chemical equation ,

[tex]SO_2Cl_2((g) = SO_2(g) + Cl_2(g)[/tex]

initial concenration of [tex]SO_2Cl_2((g) =0.1M[/tex]

lets assume that degree of dissociation=[tex]\alpha[/tex]

concenration of each component at equilibrium:

[tex][SO_2Cl_2] = 0.1-0.1\alpha[/tex]

[tex][SO_2] = 0.1\alpha[/tex]

[tex][Cl_2] = 0.1\alpha[/tex]

[tex]Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}[/tex]

[tex]Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}[/tex]

as [tex]\alpha[/tex] is very small then we can neglect  [tex]1-\alpha[/tex]

therefore ,

[tex]Kc ={0.1\alpha \times \alpha}[/tex]

[tex]\alpha =\sqrt{\frac{Kc}{0.1}}[/tex]

[tex]\alpha = 1.73 \times 10^{-3}[/tex]

Eqilibrium concenration of [tex][SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173[/tex]

[tex][SO_2Cl_2] = 0.09983 M[/tex]

Answer:

okay so to tell the story short:

Explanation:

over the years farmers in agriculture businesses have decide to use safer chemicals. because since people have been getting food poisoning and been getting sick. but now farmer businesses now use some chemicals that have very low toxicity. When pesticides were first introduced, farmers were using chemicals that were very toxic. but then that's when they realised that the they had to be removed from the application and today they have been replaced with better and healthier ones just like (glyphosate.)

Answer:

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Explanation:

Solubility of solute at 20°C = 32.2 g/100 grams of water

Solute soluble in 1 gram of water = [tex]\frac{32.2}{100}g=0.322 g[/tex]

Mass of solute in soluble in 56.0 grams of water:

[tex]0.322\times 56.0=18.032 g[/tex]

Solubility of solute at 30°C = 70.2g/100 grams of water

Solute soluble in 1 gram of water = [tex]\frac{70.2}{100}g=0.702 g[/tex]

Mass of solute in soluble in 56.0 grams of water:

[tex]0.702 \times 56.0=39.312 g[/tex]

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C

Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g

Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g

Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:

39.312 g - 18.032 g = 21.28 g

21.28 grams solute can be added if the temperature is increased to 30.0°C.

Final answer:

By comparing the solubility at two different temperatures, an additional 21.280 g of solute can be dissolved in 56.0 g of water when the temperature increases from 20.0 °C to 30.0 °C.

Explanation:

Understanding how temperature influences solubility is crucial when trying to determine the concentration of a solute that can be dissolved in a solvent at different temperatures. According to the data provided, the solubility of a solute in water at 20.0 °C is 32.2 g per 100 g of water and at 30.0 °C it increases to 70.2 g per 100 g of water.

To calculate the additional amount of solute that can be dissolved when the solution temperature is raised from 20.0 °C to 30.0 °C, we should first calculate the solubility in 56.0 g of water at both temperatures:

So, 18.032 g of solute can be dissolved in 56.0 g of water at 20.0 °C.

So, 39.312 g of solute can be dissolved in 56.0 g of water at 30.0 °C.

The difference between these two amounts (39.312 g - 18.032 g) gives us the additional amount of solute that can be added at the higher temperature:

Additional solute = 39.312 g - 18.032 g = 21.280 g

Therefore, an additional 21.280 g of solute can be added to the solution when the temperature is raised from 20.0 °C to 30.0 °C without reaching saturation.

Answer:

option C. Ca(HCO3)2

Explanation:

did it on edg

Answer:

answer c

Explanation:

Answer:

3.13g

Explanation:

First, we'll begin by writing a balanced equation between the reaction of gaseous ethane with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, let us calculate the mass of C2H6 and the mass of O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

The mass of C2H6 that reacted from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 7 x 32 = 224g

Now, to calculate the left over mass of ethane (C2H6), let us first calculate the mass of ethane (C2H6) that will react with 22g of oxygen(O2). This can be achieved by doing the following:

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, Xg of C2H6 will react with 22g of O2 i.e

Xg of C2H6 = (60 x 22)/224

Xg of C2H6 = 5.89g

From the calculations above, 5.89g will react completely with 22g of O2.

The left over mass of C2H6 can be obtained as follow:

Mass of C2H6 from the question = 9.02g

Mass of C2H6 that reacted = 5.89g

The left over mass of C2H6 =?

The left over mass of C2H6 = Mass of C2H6 - mass of C2H6 that reacted

Left over mass of C2H6 = 9.02 - 5.89

Left over mass of C2H6 = 3.13g