Which equation has the following characteristics?

if the ratio of sides is 2:3, the ratio of the perimeters will be the same

   2             16

-------  =    ---------

3                 P

Using cross product  2*P = 3*16

                                    2P = 48

                                    P = 24 inches

Answer:

A.(0, –5)

Step-by-step explanation:

Answer:

b second option

Step-by-step explanation:

just did on edge

Answer:

B

Step-by-step explanation:

Just did it

Answer: Hello mate!

first, let's do a list with all the things we know about this problem:

Both trains depart at the same time; we can define this time as t = 0 in hours.

the velocity of train A is 50mph

the velocity of train B is 60mph

both trains travel in opposite directions.

the initial distance between both trains is equal to 330 miles:

we want to know when the trains will meet each other:

The trains will meet each other when the sum of their traveled distance is equal to the initial separation between them.

the distance traveled by the train A is equal to his velocity multiplied by the time that passed since it departed.

this is: Da(t) = (50*t)mi

and the distance for the train B is: Db(t) = (60*t)mi

then, as we know, the trains will meet when Da(t) + Db(t) = 330mi

then 50*t + 60*t = 330

110*t = 330

t = 330/110 = 3h

the trains will meet 3 hours after they departed.

The answer should be true

Hope it helps

The midpoint of a line segment using paper folding constructions yes it is true.

Comparable to mirroring one side of a plane in a crease, folding paper. So, to fold is to map one half of a plane onto another while also creating a crease.

The steps used to create a mid-point are given below:-

1. The top of the paper lies in itself; hence, we can say that the line segment lies in itself.

2. You have a new line at the centre of the paper. The point at the top of this centre line is the midpoint of the line segment.

3. The edges that lie on each other translate to the endpoints lying on each other.

Therefore, the midpoint of a line segment using paper folding constructions yes it is true.

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The answer is c. have a good day

To simplify the given polynomial expression, distribute coefficients to terms within each parentheses, combine like terms, and simplify further to obtain the simplified form of the expression: 14x^2 - 14x - 15.

To simplify the given polynomial expression, we'll start by distributing the coefficients to the terms within each parentheses:

Now, we'll combine like terms and simplify further:

Therefore, the simplified form of the given polynomial expression is 14x^2 - 14x - 15.

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y = 6 it a horizontal line. The line parallel to horizontal line is horizontal line with the equation y = a.

The line passing through the point (3, 4) → y = 4.

Therefore your answer is : y = 4.

Answer:

y = 4.

Step-by-step explanation:

I checked :)

Add 5 to both sides.

x−5+5≥9+5

Answer: x≥14

We have the equations: l = 2b and 2l + 2b = 228;

Then, 4b + 2b = 228;

6b = 228;

b = 228/6;

b = 38 (breadth);

l = 2·38;

l = 76 (length);

[tex]f(x)=\dfrac{2}{3}x+3\\\\f(12)\to\text{put x = 12 to the equation of a function}\\\\f(12)=\dfrac{2}{3}\cdot12+3=\dfrac{2}{1}\cdot4+3=8+3=11\\\\Answer:\ f(12)=11[/tex]

Answer:

11

Step-by-step explanation:

All we have to do is divide 120 by 15

120 ÷ 15 = 8

Therefore, it will take 8 hours to drive 120 miles at a speed of 15 mph

Hope this helps

-AaronWiseIsBae

15miles = 60minutes

divide 15 by 120 which equals 8

8 times 60 equals 480

your answer should be 8 hours

[tex]8x > -32\qquad|\text{divide both sides by 8}\\\\x > -4\\-----------------------------------\\\\6x\leq-48\qquad|\text{divide both sides by 6}\\\\x\leq-8\\\\Answer:\ c)\ x > -4\ or\ x\leq-8[/tex]

Answer,

Explanation,

All they are asking you to do is input the numbers, "2.5" & "-14.6" into the eqation.

So, let's do that.

-2.5 - |-14.6|

Now, all you have to do is simplify,

-2.5 - |-14.6| = -17.1

Hope this helps :-)

Answer:

4/9 probability

Step-by-step explanation:

Imagine winning something, there's 3 possible prizes that you get to choose from and get to keep let's say 4 days? These all written on the paper that you must pull from a box.

Your three prizes are

             D1    D2   D3    D4

1. a car

2. a bike

3. skateboard.

Now if you can imagine a grid and you mark 1 dot in each day we'll end up with 12 slots total.

Let's say you don't want a skateboard you rather have a car or a bike. We need to figure out of the 12 possibility (assuming all are equal) What's the possibility of you pulling out anything BUT a skateboard?

You want at least 3 days in either or. So we must find P = (Days without skateboard)

We know it's all equal outcomes, you're going to get 1 day of that 1 item.. soo..

p (DWS) = _____

                 12 outcomes

Now you want how many days MORE THAN 3, can you use anything but the skateboard?

You have 3 & 4 days with a car...

You have 3 or 4 days with a bike.. Which gives us 4 of the days we do want!

Giving your final problem the looking like this .. P(DWS) = 4/9

In respects/C to KhanAcademy.

Answer:

4/9 probrabitaty

Step-by-step explanation:

Answer:

12.5

Step-by-step explanation:

Last month, Carrie had 14 coins.

The value of 5 is hundredths

please write the complete question for answer

Here we are given the expression:

[tex]x^{2}+18[/tex]

Now let us equate it to zero to find x first,

[tex]x^{2}+18=0[/tex]

Now subtracting 18 from the other side,

[tex]x^{2}=-18[/tex]

taking square root on both sides,

So we will get two values of x as ,

[tex]x=3\sqrt{-2}[/tex]

[tex]x=-3\sqrt{-2}[/tex]

Now we can write square root -1 as i,

So our factors become,

[tex]x=3i\sqrt{2}[/tex]

[tex]x=-3i\sqrt{2}[/tex]

Answer:

The final factored form becomes,

[tex](x+3i\sqrt{2})(x-3i\sqrt{2})[/tex]

Answer:

[tex](x+3i\sqrt{2})(x-3i\sqrt{2})[/tex]

Step-by-step explanation:

1. You must apply the Quadratic formula, which is:

[tex]x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}[/tex]

2. Substitute values:

[tex]a=1\\b=0\\c=18[/tex]

[tex]x=\frac{-0+/-\sqrt{0^{2}-4(1)(18)} }{2(1)}\\x=\frac{+/-\sqrt{-72}}{2}\\x=\frac{+/-6i\sqrt{2}}{2}\\x=+/-3i\sqrt{2}[/tex]

3. Finally, you obtain:

[tex](x+3i\sqrt{2})(x-3i\sqrt{2})[/tex]

To solve this problem you must think in this way.

First we see that function y is greater than 3-x, conclusion is the following

shaded area must be above function. That condition is satisfied by the graph 3 and 4.

Then we write inequality in the slope form  y> -x+3.

We see that the coefficient of direction is -1 (negative) which mean that the graph is decreasing. That condition is satisfied by the graph No 4.

The correct answer is graph number 4 ( or D.)

Good luck!!!

The new number of chairs produced per month is 7125

To find the amount of decrease:

Calculate 5% of 7500 chairs: 7500 x 0.05 = 375.

The decrease is 375 chairs.

To find the new number of chairs produced:

Subtract the decrease from the original amount: 7500 - 375 = 7125.

The new number of chairs produced per month is 7125

answer=2x=12,x=6

2z+4=0,z=-2

Answer: answer=2x=12,x=6

2z+4=0,z=-2

Step-by-step explanation:

Answer:

A. It is the total cost for entertainment and cleaning.

Step-by-step explanation:

If we look at the information it says:

Facility rental is dependent upon number of hours we are renting the facility for.

Linen, food, and decoration also depends upon the number of attendees. Also, the table decorations depend upon the number of attendee.

The things that are independent of the number of attendees are entertainment and cleaning fee. These are fixed charges.

So, the total cost for entertainment and cleaning are the constants in the expression. This is the amount that will remain constant regardless of the number of attendees.

[tex]24 > -3r\geq-9\ \ \ \ |\text{change the signs}\\\\-24 < 3r\leq9\ \ \ \ |\text{divide both sides by 3}\\\\\boxed{-8 < r\leq3}[/tex]

Inequalities are used to represent unequal expressions.

The solution to [tex]24>-3r \ge -9[/tex] is [tex]-8<r \le 3[/tex]

Given

[tex]24>-3r \ge -9[/tex]

Divide through by -3

[tex]\frac{24}{-3}>\frac{-3r}{-2} \ge \frac{-9}{-3}[/tex]

Negative division changes the inequality sign

So, we have:

[tex]-8<r \le 3[/tex]

Hence, the solution to [tex]24>-3r \ge -9[/tex] is [tex]-8<r \le 3[/tex]

See attachment for the graph of [tex]-8<r \le 3[/tex]

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First we have to see which is the right angle.  This triangle has its legs oriented parallel to the axes. (-3,-1) and (1,-1) form the horizontal leg, (1,-1) and (1,2) the vertical leg.  

So the right angle vertex is (1,-1) and the hypotenuse endpoints are (-3,-1) and (1,2)

The length is given by

[tex]d = \sqrt{ (1 - -3)^2 + (2 - -1)^2} = \sqrt{4^2+3^2}=\sqrt{25} = 5[/tex]

This is a 3/4/5 right triangle.

Answer: 5

a) The cost of goods available for sale is $16,800.

b) The calculated values for the cost of goods sold under the FIFO and LIFO methods match the values obtained using the formulas, proving their accuracy.

(a) Beginning Inventory:

100 units at $8 per unit = $800

Purchases:

Feb. 20:

600 units at $9 per unit

= $5,400

May 5: 500 units at $10 per unit

= $5,000

Aug. 12: 400 units at $11 per unit

= $4,400

Dec. 8: 100 units at $12 per unit

= $1,200

Total Cost of Goods Available for Sale

= $800 + $5,400 + $5,000 + $4,400 + $1,200

= $16,800

Therefore, the cost of goods is $16,800.

(b) Given the sales of 1,500 units,

FIFO (First-In, First-Out):

The ending inventory consists of the most recent purchases.

Ending Inventory (FIFO):

Dec. 8: 100 units at $12 per unit

= $1,200

Cost of Goods Sold (FIFO):

Beginning Inventory: 100 units at $8 per unit = $800

Feb. 20: 600 units at $9 per unit

= $5,400

May 5: 500 units at $10 per unit

= $5,000

Aug. 12: 200 units at $11 per unit

= $2,200

Total Cost of Goods Sold (FIFO):

$800 + $5,400 + $5,000 + $2,200

= $13,400

LIFO (Last-In, First-Out):

Ending Inventory (LIFO):

Beginning Inventory: 100 units at $8 per unit = $800

Feb. 20: 400 units at $9 per unit = $3,600

Cost of Goods Sold (LIFO):

May 5: 500 units at $10 per unit

= $5,000

Aug. 12: 400 units at $11 per unit

= $4,400

Dec. 8: 100 units at $12 per unit

= $1,200

Total Cost of Goods Sold (LIFO):

= $5,000 + $4,400 + $1,200

= $10,600

Average-Cost:

Total Cost of Goods Available for Sale: $16,800

Total Units Available for Sale:

Beginning Inventory: 100 units

Feb. 20: 600 units

May 5: 500 units

Aug. 12: 400 units

Dec. 8: 100 units

Total Units Available for Sale:

= 100 + 600 + 500 + 400 + 100

= 1,700 units

Average Unit Cost:

= Total Cost of Goods Available for Sale / Total Units Available for Sale

= $16,800 / 1,700 units

= $9.882 per unit

Ending Inventory:

Remaining Units: 1,700 units - 1,500 units (sold)

= 200 units

Ending Inventory = Remaining Units x Average Unit Cost

= 200 units x $9.882

= $1,976.40

Cost of Goods Sold (Average-Cost):

Total Cost of Goods Available for Sale - Ending Inventory

$16,800 - $1,976.40 ≈ $14,823.60

Therefore, under the average-cost method:

Ending Inventory ≈ $1,976.40

Cost of Goods Sold ≈ $14,823.60

Compare the calculated values with the cost of goods sold formulas.

FIFO Cost of Goods Sold:

Beginning Inventory: 100 units at $8 per unit

= $800

Feb. 20: 600 units at $9 per unit

= $5,400

May 5: 500 units at $10 per unit

= $5,000

Aug. 12: 200 units at $11 per unit

= $2,200

Total Cost of Goods Sold (FIFO):

= $800 + $5,400 + $5,000 + $2,200

= $13,400

LIFO Cost of Goods Sold:

May 5: 500 units at $10 per unit

= $5,000

Aug. 12: 400 units at $11 per unit

= $4,400

Dec. 8: 100 units at $12 per unit

= $1,200

Total Cost of Goods Sold (LIFO):

= $5,000 + $4,400 + $1,200

= $10,600

The match the values obtained using the formulas, proving their accuracy.

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The question attached here seems to be incomplete, the complete question is:

Vista Company Inc. had a beginning inventory of 100 units of Product RST at a cost of $8 per unit. During the year, purchases were:

Feb. 20  600 units at $9

Aug. 12 400 units at $11

May 5  500 units at $10

Dec. 8  100 units at $12

Vista Company uses a periodic inventory system. Sales totaled 1,500 units.

Instructions

(a) Determine the cost of goods available for sale.

(b) Determine the ending inventory and the cost of goods sold under each of the assumed cost flow methods (FIFO, LIFO, and average-cost). Prove the accuracy of the cost of goods sold under the FIFO and LIFO methods. (Round average unit cost to three decimal places.)

To find the total variable cost for 6 jackets, calculate the average variable cost per jacket from the 7 jackets and multiply by 6. Other given economic scenarios involve calculating firm profits, break-even points, and shutdown points based on provided cost structures and market conditions.

The question relates to determining the total variable cost of 6 jackets, based on the given information that 7 jackets have a total variable cost of $300. Without specific details on how the costs change with each additional jacket, a direct calculation is not possible. However, if we assume that the variable cost per jacket is consistent, we can calculate the average variable cost per jacket by dividing the total variable cost for 7 jackets by 7, which is roughly $42.86. We would then multiply this average variable cost by 6 to find the total variable cost for 6 jackets.

For the firm with a total fixed cost of $1,000, a total cost of $4,200, and an output of 500 units, the total variable cost is $3,200. Similarly, for the firm with a total fixed cost of $1,200, a total cost of $4,000, and an output of 1,000 units, the total variable cost is $2,800. This information helps to determine the firm's break-even and shutdown price points.