Which of the following best describes a chord?

Answer:

c = 13.1

Step-by-step explanation:

* Lets explain how to solve the problem

- In Δ ABC

# ∠A is opposite to side a

# ∠B is opposite to side b

# ∠C is opposite to side c

- The sine rule is:

# [tex]\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}[/tex]

* Lets solve the problem

- In Δ ABC

∵ m∠A = 57°

∵ m∠B = 37°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 57° + 37° + m∠C = 180°

∴ 94° + m∠C = 180° ⇒ subtract 94° from both sides

∴ m∠C = 86°

- Lets use the sine rule to find c

∵ a = 11 and m∠A = 57°

∵ m∠C = 86°

∵ [tex]\frac{sin(57)}{11}=\frac{sin(86)}{c}[/tex]

- By using cross multiplication

∴ c sin(57) = 11 sin(86) ⇒ divide both sides by sin(57)

∴ [tex]c=\frac{11(sin86)}{sin57}=13.1[/tex]

* c = 13.1

Answer:

Fig A

Step-by-step explanation:

in fig A, we can see that the subset that represents "trees", lies inside the subset that "has leaves". Hence in figure A, we can say that "All trees have leaves" or "if it is a tree, it has leaves"

in fig B however, we see that "has leaves" is inside of "trees", this means that the area in-between  "has leaves" and "tree" represents the subset that there are trees without leaves. This is in contradiction to the statement "if it is a tree, it has leaves", hence this is not the answer.

Answer

A

Step-by-step explanation:

hope this helps :)

Answer:

The length of each piece of cloth =1/12 yard

Step-by-step explanation:

Number of pieces = 5

Carlos cut 5/12 of a yard of cloth

Length of each piece = ?

To find the length of each piece simply divide 5/12 by 5.

Length of each piece of cloth = 5/12/5

Length of each piece of cloth =5/12 * 1/5

Length of each piece of cloth=1/12

Therefore the length of each piece of cloth =1/12 yard....

Answer:

the answer is a

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [ a, b ] = [ 3, 5 ]

From the table of values

f(b) = f(5) = 32

f(a) = f(3) = 8

Hence

average rate of change = [tex]\frac{32-8}{5-3}[/tex] = [tex]\frac{24}{2}[/tex] = 12

Answer:

The average rate of change is [tex]12[/tex]

Step-by-step explanation:

Given:

Interval; x = 3 to x = 5

We'll represent these by

x1 = 3

x2 = 5

The corresponding y values are:

When x = 3, y = 8

When x = 5, y = 32

This will also be represented

y1 = 8

y2 = 32

Average rate of change is then calculated as follows

[tex]m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]

Where m represent average rate of change

By Substitution, we have

[tex]m = \frac{32 - 8}{5 - 3}[/tex]

[tex]m = \frac{24}{2}[/tex]

[tex]m = 12[/tex]

Hence, the average rate of change is [tex]12[/tex]

Intersection of two sets E and F is set G which contains elements x that are common to set E and set F.

[tex]G=E\cap F=\{x; x\in E\wedge x\in F\}[/tex]

Here G is,

[tex]G=\{-2,6\}[/tex]

Union of two sets E and F is a set H which contains all elements x that occur in set E or set F.

[tex]H=E\cup F=\{x; x\in E\vee x\in F\}[/tex]

Hence,

[tex]H=\{-2,-1,2,3,5,6,7\}[/tex]

Hope this helps.

r3t40

The intersection of sets E and F: E ∩ F = {-2, 6}

The union of sets E and F: E U F = {-2, -1, 2, 3, 5, 6, 7}

[tex]\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-5}{4-(-3)}\implies \cfrac{-7}{4+3}\implies \cfrac{-7}{7}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=1[x-(-3)]\implies y-5=1(x+3) \\\\\\ y-5=x + 3\implies y=x+8[/tex]

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d)[tex] {( \frac{1}{3} x - y) }^{2} = ({ \frac{1}{9}x }^{2} - \frac{2}{3} xy + {y}^{2} )[/tex]

e)

[tex](0.25 - a) ^{2} = (0.25^{2} - (2)(0.25)a + {a}^{2} ) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = ( \frac{1}{16} - \frac{1}{2} a + {a}^{2} )[/tex]

f)

[tex] {( \frac{2x}{3} - \frac{1}{2} )}^{2} = ( \frac{4 {x}^{2} }{9} - \frac{2x}{3} + \frac{1}{4} )[/tex]

Step-by-step explanation:

Considering Lisa's yard is allowing the dog to run around a circumscribed circle with a ray of 4 5/6 feet then the maximum of the area that he could cover is the area of that circle A= 3.14×(4 5/6)^2/2

Not being able to see the drawing, I assume that if the area of the yard has a value below the value described above then the dog would run around the yard untill the rope's fully swirled around the tree or untill Lisa comes home

Answer:

A) (x-3) is not a factor of x^3+4x^2+2

Step-by-step explanation:

(x-3) is a factor of f(x)=x^3+4x^2+2 if f(3)=0. This is by factor theorem.

So let's check it.

f(x)=x^3+4x^2+2

f(3)=3^3+4(3)^2+2

f(3)=27+4(9)+2

f(3)=27+36+2

f(3)=63+2

f(3)=65

Since f(3) doesn't equal 0, then x-3 is not a factor.

Answer:

A. (x-3) is not a factor

Step-by-step explanation:

You can find if (x-3) is a factor of the polynomial by dividing the polynomial by (x-3) by using long division or synthetic division.

Long division:                          

          x^2+x+3

(x-3)/x^3+4x^2+0x+2

      -(x^3-3x^2)

                 x^2+0x

                -(x^2-3x)

                         3x+2

                        -(3x-9)

                               -7  

Here you can see that (x-3) is not a factor of the polynomial because when you divide x^3 + 4x^2 + 2 by (x-3), there is a remainder of -7

Synthetic Division (A shortcut version of long division just to see if there is a remainder and if the supposed factor is really a factor) :

3          1            4           0           2    

           -           3           21          63

           1            7           21          65

As seen before (x-3) is not a factor of the polynomial because there is a remainder.  If 65 were 0, the (x-3) would be a factor of the polynomial.

Answer:

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}x-3y=6&\text{multiply both sides by (-2)}\\2x+2y=4\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+6y=-12\\2x+2y=4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad8y=-8\qquad\text{divide both sides by 8}\\.\qquad\qquad y=-1\\\\\text{Put the value of y to the first equation:}\\\\x-3(-1)=6\\x+3=6\qquad\text{subtract 3 from both sides}\\x=3[/tex]

Answer: y = -1 and x = 3

Step-by-step explanation:

x - 3y = 6 --------(1)

2x + 2y = 4 -------(2)

we multiply (1) by 2

2x - 6y = 12 --------(3)

(3) - (1)

-8y = 8

y = -1

Putting y = -1 into equation (1)

x - 3 (-1) = 6

x + 3 =6

collect the like term

x = 6 - 3

x = 3

Therefore x= 3 and y = -1

Answer:

Assuming you have [tex]f(n)=0.4f(n-1)+12[/tex] with [tex]f(1)=4[/tex], the answer is f(2)=13.6.

Step-by-step explanation:

I think that says [tex]f(n)=0.4f(n-1)+12[/tex] with [tex]f(1)=4[/tex].

Now we want to find [tex]f(2)[/tex] so replace n with 2:

This gives you:

[tex]f(2)=0.4f(2-1)+12[/tex]

[tex]f(2)=0.4f(1)+12[/tex]

[tex]f(2)=0.4(4)+12[/tex]

[tex]f(2)=1.6+12[/tex]

[tex]f(2)=13.6[/tex]

Answer:

13.6 (Answer C)

Step-by-step explanation:

I think you meant  f(n) = 0.4 * f(n-1) + 12, where * represents multiplication.

Then f(2) = 0.4 * (4) + 12, or 1.6 + 12, or 13.6.

[tex]-2(k+3) < -2k - 7\\-2k-6<-2k-7\\-6<-7\\k\in\emptyset[/tex]

Answer:

No solutions

Step-by-step explanation:

-2(k+3) < -2k - 7

Distribute the -2

-2k-6 < -2k - 7

Add 2k to each side

-2k+2k-6 < -2k+2k - 7

-6 < -7

This is always false, so the inequality is never true

There are no solutions

Answer:

Quotient: x^4+7x^3-2x^2-9x-3

Remainder: -10

Step-by-step explanation:

x5 + 15x+ + 54x3 – 25x2– 75x – 34 by x + 8.

Since the exponents are arranged in descending order so, 15x^4

x^5 + 15x^4+ + 54x^3 – 25x^2– 75x – 34 by x + 8

The division is shown in figure attached.

Quotient: x^4+7x^3-2x^2-9x-3

Remainder: -10

Answer:

The value of sum is 1323

Step-by-step explanation:

First of all we will find the value of n:

The value of n can be determined by the following formula:

an = a1 + (n - 1)d

where an= 113

a1= 13

d=5

Difference between the values = d=5

Now put the values n the formula:

113=13+(n-1)5

113=13+5n-5

Solve the like terms:

113=8+5n

Move constant to the L.H.S

113-8=5n

105=5n

Divide both sides by 5

21=n

Now put these values in the formula to find the sum:

Sn = n/2(a1 + an)

S21=21/2(13+113)

S21=21/2(126)

S21=21(63)

S21=1323

The value of sum is 1323....

Answer:

[tex]\frac{\pi}{4}[/tex]

[tex]\frac{5\pi}{6}[/tex]

Step-by-step explanation:

The answer uses the unit circle and that sine and cosecant are reciprocals.

The first choice doesn't even fit the criteria that [tex]x[/tex] is between [tex]0[/tex] and [tex]2\pi[/tex] (inclusive of both endpoints) because of the [tex]x=\frac{-7\pi}{6}[/tex].

Let's check the second choice.

[tex]\csc(\frac{\pi}{4})=\frac{2}{\sqrt{2}} \text{ since } \sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}[/tex].

[tex]\csc(\frac{\pi}{4})>1 \text{ since } \frac{2}{\sqrt{2}}>1[/tex]

[tex]\csc(\frac{\pi}{2})=1 \text{ since } \sin(\frac{\pi}{2})=1[/tex] which means [tex]\csc(\frac{\pi}{2})=1[/tex] which is not greater than 1.

So we can eliminate second choice.

Let's look at the third.

[tex]\csc(\frac{5\pi}{6})=2 \text{ since } \sin(\frac{5\pi}{6})=\frac{1}{2}[/tex] which means [tex]\csc(\frac{5\pi}{6})>1[/tex].

[tex]\csc(\pi)[/tex]  isn't defined because [tex]\sin(\pi)=0[/tex].

So we are eliminating 3rd choice now.

Let's look at the fourth choice.

[tex]\csc(\frac{7\pi}{6})=-2 \text{ since } \sin(\frac{7\pi}{6})=\frac{-1}{2}[/tex] which means [tex]\csc(\frac{7\pi}{6})<1[/tex] and not greater than 1.

I was looking at the rows as if they were choices.

Let me break up my choices.

So we said [tex]x=-\frac{7\pi}{6}[/tex] doesn't work because it is not included in the inequality [tex]0\le x \le 2\pi[/tex].

How about [tex]x=0[/tex]?  This leads to [tex]\csc(0)[/tex] which doesn't exist because [tex]\sin(0)=0[/tex].

So neither of the first two choices on the first row.

Let's look at the second row again.

We said [tex]\frac{\pi}{4}[/tex] worked but not [tex]\frac{\pi}{2}[/tex]

Let's look at the choices on the third row.

We said [tex]\frac{5\pi}{6}[/tex] worked but not [tex]x=\pi[/tex]

Let's look at at the last choice.

We said it gave something less than 1 so this choice doesn't work.

Answer:x=pi/4 and x=5pi/6

Step-by-step explanation:

on edge just did it

Answer: 40% or 2/5

Step-by-step explanation:

10 total marbles

6 yellow

4 red

Probability of blindly picking a red marble is 4/10 or 2/5 which can be written as 40%

The probability of picking a red marble from a bag containing 10 marbles, where 4 are red, is 4 out of 10 or 0.4.

The question asks about the probability of picking a red marble from a bag containing 6 yellow marbles and 4 red marbles, totaling 10 marbles. To calculate the probability, you divide the number of favorable outcomes (picking a red marble) by the number of possible outcomes (total marbles). In this case, the probability of picking a red marble is 4 out of 10, which can be simplified to 2 out of 5 or 0.4.

Answer:

Option C (28.0°)

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the three sides are given and one unknown angle has to be calculated. Therefore, cosine rule will be used. The cosine rule is:

a^2 = b^2 + c^2 - 2*b*c*cos(A°).

The question specifies that a=13, b=21, and c=27. Plugging in the values:

13^2 = 21^2 + 27^2 - 2(21)(27)*cos(A°).

Simplifying gives:

-1001 = -1134*cos(A°)

Isolating cos(A°) gives:

cos(A°) = 0.88271604938

Taking cosine inverse on the both sides gives:

A° = arccos(0.88271604938). Therefore, using a calculator, A° = 28.0 (correct to one decimal place).

This means that the Option C is the correct choice!!!

For this case we have that by definition, the cosine theorem states that:

[tex]a ^ 2 = b ^ 2 + c ^ 2-2bc * Cos (A)[/tex]

According to the data we have:

[tex]a = 13\\b = 21\\c = 27[/tex]

Substituting we have:

[tex]13 ^ 2 = 21 ^ 2 + 27 ^ 2-2 (21) (27) * Cos (A)\\169 = 441 + 729-1134 * Cos (A)\\169 = 1170-1134 * Cos (A)\\169-1170 = -1134 * Cos (A)\\-1001 = -1134 * Cos (A)\\Cos (A) = \frac {1001} {1134}\\Cos (A) = 0.8827\\A = arc cos (0.8827)\\A = 28.03[/tex]

Answer:

Option C

Answer:

B.  3 and 4

Step-by-step explanation:

In order to find the numbers between which √11 lies, let us first guess the nearest perfect squares to √11. These are 9 and 16. Where 9 comes just before 11 and 16 comes just after 11. Now we have to write all three of them in ascending order.

√9 , √11  ,  √16

also

√9= 3 and √16 = 4

and

√9 < √11 < √16

3 < √11 < 4

hence we can see that √11 must lies between 3 and 4  

Answer:

B.3 and 4

Step-by-step explanation:

3x3=9

4x4=16

so, 11 goes between 3 and 4

I just gave myself a bad rating because I did not want you guys to get the answer wrong because I posted an answer that was wrong and forgot that I could edit so now that I fixed it is a safe answer

Answer:

9÷2+4

Step-by-step explanation:

Answer:

[tex]h(x)=+-\sqrt{\frac{x+4}{9} }[/tex]

Step-by-step explanation:

Hello

I think  I can help you with this

Let

[tex]y = 9x^{2}-4\\h(x)=y^{-1}[/tex]

to find the inverse of y([tex]y^{-1}[/tex])

Step 1

switch x and y

[tex]y = 9x^{2}-4\\\\x= 9y^{2}-4[/tex]

Step 2

Now solve the equation for y (isolating y)

[tex]x= 9y^{2}-4\\Add\ 4\ to\ both\ sides\\x+4= 9y^{2}-4+4\\x+4=9y^{2}\\divide\ each\ side\ by\ 9\\\frac{x+4}{9} =\frac{9y^{2}}{9}\\\\x+4=y^{2} \\[/tex]

[tex]h(x)=+-\sqrt{\frac{x+4}{9} }[/tex]

Have a great day

Answer:

[tex]\large\boxed{(f+g)(x)=4^x+17x-1}[/tex]

Step-by-step explanation:

[tex](f+g)(x)=f(x)+g(x)\\\\f(x)=4^x+12x,\ g(x)=5x-1\\\\(f+g)(x)=(4^x+12x)+(5x-1)=4^x+17x-1[/tex]

Answer:

(a,b)

Step-by-step explanation:

simply we find the midpoint of AC and the midpoint of Bd by dividing over 2

Answer:

We choose D.

Step-by-step explanation:

Let the midpoint is O

We will use Angle-SIde-Angle principle to prove that the diagonals of a rectangle bisect each other.

Have a look at the two triangles: AOB and DOC, they are congruent because:

So we can conclude that: OB = OB  when two triangles: AOB and DOC are congruent.

Similar, apply for the two triangles: AOD and BOC are congruent so we have OA = OC .

=> It proves that the point O simultaneously is the midpoint and intersection point for the diagonals.

=> The midpoint of AC is ([tex]\frac{2a+ 0}{2}[/tex] , [tex]\frac{0 + 2b}{2}[/tex] ) = (a, b), we choose D.

[tex]\huge{\boxed{(x-2, y+4)}}[/tex]

[tex]x_1 \bf{-2} =x_2[/tex]

[tex]y_1 \bf{+4} =y_2[/tex]

This means that the answer is the subtract [tex]2[/tex] from the [tex]x[/tex] and add [tex]4[/tex] to the [tex]y[/tex], which is represented as [tex]\boxed{(x-2, y+4)}[/tex]

Also, thank you for posting your first question, and welcome to the community! If you have any questions, don’t hesitate to reach out to me!

The translation that maps (3,-4) to its image (1,0) is given by:

(x, y) ⇒ (x - 2, y + 4)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, rotation, reflection and dilation.

Translation is the movement of a point either up, down, left or right.

If a point A(x, y) is moved a units left and b units up, the new point is at A'(x - a, y + b).

The translation that maps (3,-4) to its image (1,0) is given by:

(x, y) ⇒ (x - 2, y + 4)

Find out more at: https://brainly.com/question/18303818

The correct rule that describes the composition of transformations mapping AABC to AA"B"C" is:

- Ro. 900 ◦ T-6, -2(x, y)

Here's a step-by-step explanation:

1. "Ro. 900" stands for a 900 degrees counterclockwise rotation.

2. "T-6, -2" represents a translation of 6 units to the left and 2 units down.

3. When these transformations are applied in sequence to the original figure AABC, you first rotate it 900 degrees counterclockwise and then translate it 6 units to the left and 2 units down, resulting in the figure AA"B"C".

This rule combines rotation and translation to map AABC to AA"B"C". This composition of transformations is what leads to the desired outcome.

The complete question is : Which rule describes composition of transformations that maps ABC to A"B"C"?

Answer:

Explanation:

Angles may be named by three letters, each represented a point on each of the angle's ray or by the vertex.

The angle EAD is the angle A (the letter of the center is the vertex).

In this case it is indicated the measure of the angle on the diagram using a small square.

The small square is a conventional symbol to indicate that the angle is 90°, which is named right angle. That determines that the rays, segments or lines meet perpendicularly.

That is one fourth (1/4) of the complete circle (1/4 × 360° = 90°).

By using the dagram, the measure of the given angle include the following:

m∠EAD = 90°

In Mathematics and Euclidean Geometry, a right angle is a type of angle that is formed in a triangle by the intersection of two (2) straight lines at 90 degrees.

Generally speaking, a perpendicular bisector can be used to bisect or divide a line segment exactly into two (2) equal halves, in order to form a right angle that has a magnitude of 90 degrees at the point of intersection;

In this context, we can logically deduce that segment AE is the perpendicular bisector of diameter ED in circle A. Therefore, the measure of angle EAD must be 90 degrees;

m∠EAD = 90°

Answer:

Option A

Step-by-step explanation:

The domain must be

[a,∞)

That means that x must have as an argument a square root, because, it cannot take negative arguments for real numbers (a>0)

√(x-a)

x-a≥0

x ≥ a

The only possible option is

Option A.

Please take a look at the attached graph

Answer:

a=192

b=96

c=64

d=48

Step-by-step explanation:

So we have [tex]a+b+c+d=400[/tex] where [tex]a,b,c,[/tex] and [tex]d[/tex] are integers.

We also have [tex]a=2b[/tex]and [tex]a=3c[/tex]and [tex]a=4d.[/tex]

[tex]a=2b[/tex] means [tex]a/2=b[/tex]

[tex]a=3c[/tex] means [tex]a/3=c[/tex]

[tex]a=4d[/tex] means [tex]a/4=d[/tex]

Let's plug those in:

[tex]a+b+c+d=400[/tex]

[tex]a+\frac{a}{2}+\frac{a}{3}+\frac{a}{4}=400[/tex]

Multiply both sides by 4(3)=12 to clear the fractions:

[tex]12a+6a+4a+3a=4800[/tex]

Combine like terms:

[tex]25a=4800[/tex]

Divide both sides by 25:

[tex]a=\frac{4800}{25}[/tex]

Simplify:

[tex]a=192[/tex].

Let's go back and find [tex]b,c,d[/tex] now.

b is half of a so half of 192 is 96 which means b=96

c is a third of a so a third of 192 is 64 which means c=64

d is a fourth of a so a fourth of 192 is 48 which means d=48

So

a=192

b=96

c=64

d=48

Answer:

a=192

b=96

c=64

d=48

Step-by-step explanation:

hope this helps

Answer:

720

Step-by-step explanation:

permutation formula=

n!/(n-r)!

There are 720 different starting position configurations possible for the 6 starting players of a volleyball team that follows the rule.

We have

To determine the number of different starting position configurations for a volleyball team with 6 players, we can use the concept of permutations.

Since each player has a unique designated position on the court, we can think of this as arranging 6 distinct objects (the players) in 6 distinct positions (the court positions).

The number of possible arrangements can be calculated using the formula for permutations, denoted as "n P r," which represents the number of ways to select and arrange r objects from a set of n objects.

In this case, we want to arrange 6 players in 6 positions, so we can calculate 6 P 6:

6 P 6 = 6!

Using the formula for factorial:

6! = 6 * 5 * 4 * 3 * 2 * 1

= 720

Therefore,

There are 720 different starting position configurations possible for the 6 starting players of a volleyball team that follows the rule of having exactly 6 players on the court, each with a unique designated position.

Learn more about permutations here:

https://brainly.com/question/32683496

#SPJ2

Answer:

false

Step-by-step explanation:

if you do 4/4 it is 1 which is odd

Answer:

No, the result is not always even.

Step-by-step explanation:

No, this is not necessary.

There is no general rule that states that an even number divided by another even number will always be an even number.

Few example are:

[tex]\frac{6}{2}=3[/tex]

[tex]\frac{10}{2}=5[/tex]

[tex]\frac{60}{4}=15[/tex]

Answer:

B and C

Step-by-step explanation:

- The answer in the attached file