Which of the following best describes magnetic fields?
A. Magnetic fields need a conductor.
B. Magnetic fields are always found in insulators.
C. Magnetic fields have north and south magnetic poles.
D. Magnetic fields must have only positive charges.

Answers

Answer 1

Answer:

C

Explanation:

Because the north and the south pole are like the earth if they didn't attracted  we would all die.

Answer 2

Magnetic fields have north and south magnetic poles. This statement best describes magnetic fields. So, option(C) is correct.

What is magnetic field?

In the presence of a magnet, an electric current, or a shifting electric field, there is a vector field called a magnetic field where magnetic forces can be seen.

Electric charges in motion and the intrinsic magnetic moments of elementary particles connected to the fundamental quantum characteristic known as spin create a magnetic field.

As parts of the electromagnetic force, one of the four fundamental forces of nature, magnetic field and electric field are interdependent.

In magnetic field, there always be a north pole and a south pole because magnetic monopole doesn't exists. So, option (C) is correct.

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Related Questions

On which of the following planets or celestial bodies will the mass of the object be the greatest?

The Earth because it has the greatest mass and therefore the largest force of gravity.
The Moon because it has the lowest mass and the weakest force of gravity.
Its mass will be the same on all because mass is constant, no matter the gravity.
Jupiter because it has the greatest mass and therefore the greatest force of gravity.

Answers

The object's MASS will be the same on all because mass is constant,
no matter the gravity.

The object's WEIGHT will be greatest on Jupiter, because Jupiter has
the greatest mass and therefore the greatest force of gravity.

Answer:

Its mass will be the same on all because mass is constant, no matter the gravity

Explanation:

Inertial property of an object is its mass. Mass is a changeless quantity since it is the amount of matter contained in an object. When an object is on the surface of the earth or any other celestial body, it is influenced by the pull of gravity of that planet . Then it experiences the gravitational force which is called as weight , commonly.

It is weight that changes when an object is taken from one place to another . But it is mass that remains constant.

In each of the four situations described below, something is being heated. in which case is the heating caused by radiation?

a. a heat lamp keeps a hamburger warm.

b. cooking an egg in a skillet.

c. hot air pouring from a heat vent.

d. melting ice on your sidewalk by pouring hot water on it.

Answers


a. a heat lamp keeps a hamburger warm.

In the case of a heat lamp keeping a hamburger warm, the heating is caused by radiation (Option A).

What is heat transfer?

Heat transfer is the process through which internal energy from one material is transferred to another.

A heat lamp emits thermal radiation, which is a form of electromagnetic radiation in the infrared part of the spectrum. This radiation travels through the air and is absorbed by the hamburger, causing it to heat up. The heat lamp is a source of radiant heat and the hamburger is being heated by the transfer of energy by radiation.

In the case of cooking an egg in a skillet (Option B), the heating is caused by conduction.

In the case of hot air pouring from a heat vent (Option C), the heating is caused by convection.

In the case of melting ice on your sidewalk by pouring hot water on it (Option D), the heating is caused by conduction.

Thus, the heat lamp keeps a hamburger warm, the heating is caused by radiation.

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Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media. Frank says that light travels through diamond with the greatest frequency. Lisa says that light travels through air with the greatest frequency. Which best describes the accuracy of these statements? a.Frank is correct because light travels through diamond at the slowest speed, and speed and frequency have an inverse relationship. b.Lisa is correct because light travels through air at the fastest speed, and speed and frequency have a direct relationship. c.Neither person is correct because light does not change frequency when it travels through different media. d. Both people are correct because light has both an inverse and a direct relationship with frequency, depending on the media.

Answers

The correct answer is
c) Neither person is correct because light does not change frequency when it travels through different media

In fact, light changes both wavelength and speed when it travels through different media, but the frequency remains the same.

Neither person is correct because light does not change frequency when it travels through different media.

Describe where to look on the Periodic Table to find elements which have similar reactivity and other properties. Give an example of three elements that have those similarities.

Answers

In the Periodic Table, elements with similar reactivity and similar properties are found under the same column.
In fact, elements in the same columns are said to be in the same "group", and they have the same number of valence electrons, i.e. the same number of electrons in the outermost shell. This is the main characteristics that determine how an element reacts with other elements.
For instance, Litium (Li), sodium (Na) and potassium (K) are all in the first group, and they both have 1 valence electrons. This means they can easily give away this electron to an atom of another element forming bonds with it, and therefore they have high reactivity. Instead, elements of the 8th group are called "noble gases", and they all have similar properties: they all have the outermost shell full of eletrons, so they have zero valence electrons and so they have little or no reactivity at all. Example of elements in this group are Neon (Ne) and Argon (Ar).

imagine that a tank is filled with water the hight of the liquid column is 7 meters and the area is 1.5 sq meters (m™). what's the force of gravity acting on the column of water.

Answers

Answer - 12,900 Newtons

Explanation

First, we find the volume of the water
Volume = Area * Heinght
= 1.5 m² x 7 m
=  10.5 m³
 
Covert the volume to liters
1 m³ of water = 1000  liters
10.5 m³ of water = 10.5 m³ * 1000 liters liter/m³
= 10,500 liters
 
Use the volume of water to calculate the mass
1 liter of water weighs 1 kg
10,500 liters of water = 10,500 * 1 kg/liter
= 10,500 kg
 
Now, we can calculate the force of gravity on the water
Force of gravity on the water = Weight of the water
Weight = Mass * Acceleration
 
Mass = 10,500kg
Acceleration (due to gravity) = 9.8 m/s²

Force of gravity on the water
= Weight of the water
= Mass * Acceleration
= 10,500 kg * 9.8 m/s²
 = 102,900 Newtons 

In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the A. cathode. B. anode. C. grid. D. deflecting plate.

Answers

A. cathode
Best guess

Answer:

C) The answer is grid .

Explanation:

Grid lies between cathode and anode with varying volts . It controls the no of

electrons reaching screen. It is kept closer to cathode which emits electrons.There may be more than one control grid.  

Which correctly lists the outer planets from the least number of moons to the greatest number of moons?

a)Neptune, Uranus, Jupiter, Saturn
b)Saturn, Jupiter, Uranus, Neptune
c)Jupiter, Neptune, Uranus, Saturn
d)Uranus, Neptune, Jupiter, Saturn

Answers

There are two planets with no moons, Mercury and Venus. After that the order is Earth (1), Mars (2), Neptune (14), Uranus (27), Saturn (62), and Jupiter (67).

so its A

d) Uranus, Neptune, Jupiter, Saturn

Hope this helped!

Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. In addition, suppose that a dominant allele (L) codes for long eyelashes and a recessive allele (l) codes for short eyelashes. If two individuals heterozygous for both traits (tail color and eyelash length) mate, what's the probability of the phenotypic combinations of the offspring?
A. 9:3:3:1 ratio (9 polka-dot tails and short eyelashes, 3 polka-dot tails and long eyelashes, 3 solid tails and short eyelashes, 1 solid tail and long eyelash)
B. 1:1 ratio (half are polka-dot tails and long eyelashes; half are solid tails and short eyelashes)
C. 1:1 ratio (half are polka-dot tails and short eyelashes; half are solid tails and long eyelashes)
D. 9:3:3:1 ratio (9 polka-dot tails and long eyelashes, 3 polka-dot tails and short eyelashes, 3 solid tails and long eyelashes, 1 solid tail and short eyelash)
Please help♥

Answers

When you put that into a Punnett square you first use the FOIL method because this is a dihybrid case where two traits are considered. This will be the resulting Punnett square:


           PL      Pl        pL       pl

PL    PPLL   PPLl   PpLL   PpLl

Pl     PPLl    PPll     PpLl    Ppll

pL    PpLL    PpLl    ppLL   ppLl

pl     PpLl     Ppll      ppLl    ppll

Now based on the Punnett square above, you can get the ratio. Remember that the dominant trait will always be expressed when you count phenotype combinations so as long as there is a capital letter in the combination, it will always be the one expressed. 

So there are 9 polka dot, long eyelashes(PL), 3 polka dot, short eyelashes (Pl), 3 solid color, long eyelashes (pL), 1 solid short eyelashes(pl).

So your answer is D. 9:3:3:1 ratio

A diver with a mass of 70.0 kg stands motionless at the top of a diving platform 3.0 m high. The diver’s initial vertical speed is zero. What is the diver’s potential energy relative to the water surface?

Answers

The answer is 2,058J. 

You can solve for the potential energy using the formula:

[tex]PE=mgh[/tex]

Where:
PE= potential energy
m= mass
g= 9.8m/s² (This is constant. This is acceleration due to gravity because the diver is positioned above the surface of the Earth.)
h= height

The given in your problem are the following:
m = 70kg
h = 3.0 m
g = 9.8m/s² (Again this is constant)

Just plug in your given in the formula and solve:
[tex]PE=mgh[/tex]
           [tex]=(70kg)(9.8m/s^{2})(3.0m)[/tex]
           [tex]=2,058kg.m^{2}/s^{2} or 2,058J[/tex]

Final answer:

The diver's potential energy relative to the water surface, calculated using the formula PE = mgh with given values, is 2058 Joules.

Explanation:

To calculate the diver's potential energy relative to the water surface, we use the formula for gravitational potential energy, which is PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s2), and h is the height above the reference point (in this case, the water surface).

Given a diver with a mass of 70.0 kg standing 3.0 m high above the water, the calculation would be as follows:

PE = (70.0 kg) * (9.8 m/s2) * (3.0 m) = 2058 Joules.

Therefore, the diver's potential energy relative to the water surface is 2058 Joules.

Which is not true of the weak nuclear force?

A. It is a repellent force.

B. It acts over a shorter range than the strong nuclear force.

C. It is an attractive force.

D. It is weaker than the strong nuclear force.

Answers

The answer is A. The weak nuclear force is usually an attractive force, and the other two answer choices are, indeed, true of the weak nuclear force.

Answer: Option (A) is the correct answer.

Explanation:

A force that helps in binding protons and neutrons together in a nucleus is known as nuclear force. It is known that neutrons have no charge whereas protons have positive charge and like charges repel each other but due to the strong nuclear force which over powers the repulsion force between protons, they are held together in a nucleus.

A weak nuclear force is weaker than the strong nuclear force. Also, it acts over a shorter range than the strong nuclear force. A weak nuclear force is also attractive in nature.

But a weak nuclear force is not repellent in nature.

Thus, we can conclude that a weak nuclear force is a repellent force is not true.

When an object is moving with uniform circular motion, the centropetal acceleration of the object?

Answers

Yes this is possible if the speed is changing. An object moves in a circular path at a constant speed. I hope this helps my friend.

Answer:

The correct answer is "is directed toward the center of motion".

Explanation:

When an object moves in a uniform circular motion, the centrifugal acceleration of the object is directed toward the center of the motion. This acceleration is the only acceleration of the object experiences when it has constant velocity on a circular path. This causes the body to be attracted to the center of the trajectory by a centripetal force that prevents the body from entering a rectilinear trajectory.

Have a nice day!

How can an electron in an atom lose energy to go from a higher energy level to a lower energy level? select one:
a. it exchanges gravitational potential energy for kinetic energy.
b. it loses gravitational potential energy.
c. it releases a photon equal in energy to its own energy drop.
d. it absorbs a photon equal in energy to its own energy drop.
e. it loses kinetic energy?

Answers

i belive that the answer is b. 

Water's heat of fusion is 80 cal/g. Its specific heat is 1.0 cal/g degrees celsius, and its heat of vaporization is 540 cal/g.
A canister is filled with 330g of ice and 100g of liquid water, both at 0 degrees celsius. The canister is placed in an oven until all the water has boiled off and the canister is empty. How much energy in calories was absorbed?

Answers

First, write out the process of heat absorption: 
 Ice --(heat of fusion)--> Water at 0 degreesC --(specific heat)--> Water at 100 degrees C --(heat of vaporization)--> steam 
 (330 g ice)(80 cal/g) = 26,400 cal
 Now there are 430 g of liquid water at 0 degrees C. 
 (430 g liquid water)(1 cal/gC)(100 C - 0 C) = 43,000 cal
 (430 g liquid water)(540 cal/g) = 232,200 cal 
 In total, 
 26,400 + 43,000 + 232,200 = 3 x 10^5 cal

Starting the moon's cycle with the new moon phase, what phase will it be in after about a week?

Answers

The waxing crescent moon I believe 

when you snap your wrist open, the frisbee ____
A. Flips.
B. Tumbles.
C. Spins.
D.Flops.

Answers

D. should be your answer

Vast, circular to elliptical dark-colored, smooth areas of the moon are known as ________.

Answers

These areas are known as "maria", plural of mare (latin word for "sea").  These are basically vast basaltic plains, formed by volcanic eruptions thousands and milion of years ago. Their darker color with respect to other areas of the moon's surface is due to their iron-rich composition.

Suppose a star the size of our Sun, but of mass 8.0 times as great, were rotating at a speed of 1.0 revolution every 12 days. If it were to undergo gravitational collapse to a neutron star of radius 12 km, losing 3/4 of its mass in the process, what would its rotation speed be? Assume the star is a uniform sphere at all times.

(a) Assume that the thrown-off mass carries off no angular momentum, in rev/s

(b) Assume that the thrown-off mass carries off its proportional share (3/4) of the initial angular momentum, in rev/s

Answers

You have two different phases of the star: 1 the Sun-like phase and 2 the neutron star phase. The given quantities are:
r₁ = r(Sun) = 695700km
m₁ = 8 Msun
f₁ = 1 rev / 12 days
m₂ = [tex] \frac{1}{4} [/tex]·m₁

First thing, you need to transform the frequency in units of revolution/seconds
f₁ = 1 rev / (12·24·60·60) = 1 rev / 1036800 s

and then into angular velocity through the formula
ω₁ = 2πf = 6.06E-6 rad/s

a) If the angular momentum stays the same: L₁ = L₂
where L = I·ω    
and the momentum of inertia I is given by I = m·r²

Therefore, substituting we have:
m₁·r₁²·ω₁ = m₂·r₂²·ω₂

And we can find:

ω₂ = [tex] \frac{r1²w1}{0.25r2²} [/tex]

(remember m₂=[tex] \frac{1}{4} [/tex]·m₁ so we can cancel out the two m₁)

We obtain:
ω₂ = (695700²·6.06E-6)/(0.25·12²) = 81473.1 rad/s

we can transform it back into frequency:
f₂ = ω₂/2π = 1 rev / 12967 s = 7.7e-5 rev/s

b) If L₂ = [tex] \frac{1}{4} [/tex]·L₁
we do expect an angular velocity 4 times smaller.
Using the same formulas as above:

[tex] \frac{1}{4} [/tex]·m₁·r₁²·ω₁ = [tex] \frac{1}{4} [/tex]·m₁·r₂²·ω₂

ω₂ = [tex] \frac{r1²w1}{r2²} [/tex] =
     = [(695700²·6.06E-6)(12²) = 20368 rad/s

and 

f₂ = 1 rev / 3242 s = 3.08e-4 rev/s



(a) The final angular velocity [tex](\(\omega_2\))[/tex] of the neutron star is approximately [tex]\(1.42 \times 10^{-5}\)[/tex] rad/s.

(b) The final angular velocity [tex](\(\omega_2'\))[/tex] of the neutron star is approximately [tex]\(3.54 \times 10^{-6}\)[/tex] rad/s.

**(a) Assume that the thrown-off mass carries off no angular momentum:**

1. Calculate the initial moment of inertia [tex](\(I_1\)):[/tex]

[tex]\[I_1 = \frac{2}{5} \cdot (8 \cdot \text{mass of the Sun}) \cdot (\text{radius of the Sun})^2\][/tex]

  The mass of the Sun is approximately [tex]\(2 \times 10^{30}\)[/tex] kg, and the radius of the Sun is approximately 6.96 x [tex]10^8[/tex] meters. Calculate [tex]\(I_1\): \[I_1 = \frac{2}{5} \cdot (8 \times 2 \times 10^{30} \text{ kg}) \cdot (6.96 \times 10^8 \text{ m})^2\][/tex]

  This gives [tex]\(I_1 \approx 3.06 \times 10^{40}\) kg m^2.[/tex]

2. Calculate the initial angular velocity [tex](\(\omega_1\)):[/tex]

  The rotation period is 12 days, which is equivalent to [tex]\(12 \times 24 \times 60 \times 60\)[/tex] seconds. Calculate

[tex]\(\omega_1\): \[\omega_1 = \frac{2\pi}{12 \times 24 \times 60 \times 60} \text{ rad/s}\][/tex]

  This gives [tex]\(\omega_1 \approx 1.99 \times 10^{-7}\) rad/s.[/tex]

3. Calculate the initial angular momentum [tex](\(L_1\)): \[L_1 = I_1 \cdot \omega_1 = (3.06 \times 10^{40}\, \text{kg·m²}) \cdot (1.99 \times 10^{-7}\, \text{rad/s})\][/tex]

  This gives [tex]\(L_1 \approx 6.11 \times 10^{33}\) kg m^2/s.[/tex]

4. Calculate the final moment of inertia [tex](\(I_2\)):[/tex]

  The final radius of the neutron star is 12 km, which is equivalent to 12,000 meters. Calculate [tex]\(I_2\):[/tex]

[tex]\[I_2 = \frac{2}{5} \cdot (3/4 \cdot \text{mass of the Sun}) \cdot (12,000 \text{ m})^2\] \[I_2 = \frac{2}{5} \cdot (3/4 \cdot 2 \times 10^{30}\, \text{kg}) \cdot (12,000\, \text{m})^2\][/tex]

  This gives [tex]\(I_2 \approx 4.32 \times 10^{38}\)[/tex] kg·m².

5. Use the conservation of angular momentum [tex](\(L_1 = L_2\))[/tex] to find the final angular momentum [tex](\(L_2\)): \[L_2 = L_1 = 6.11 \times 10^{33}\, \text{kg·m²/s}\][/tex]

6. Calculate the final angular velocity [tex](\(\omega_2\))[/tex] of the neutron star:

[tex]\[\omega_2 = \frac{L_2}{I_2} = \frac{6.11 \times 10^{33}\, \text{kg·m²/s}}{4.32 \times 10^{38}\, \text{kg·m²}}\][/tex]

  This gives [tex]\(\omega_2 \approx 1.42 \times 10^{-5}\)[/tex] rad/s.

**(b) Assume that the thrown-off mass carries off its proportional share (3/4) of the initial angular momentum:**

1. Calculate the final angular momentum [tex](\(L_2'\))[/tex] considering that 3/4 of the initial angular momentum is carried away by the mass that is thrown off during the collapse:

[tex]\[L_2' = (1 - \frac{3}{4}) \cdot L_1 = (1 - 0.75) \cdot 6.11 \times 10^{33}\, \text{kg·m²/s}\][/tex]

  This gives [tex]\(L_2' \approx 1.53 \times 10^{33}\, \text{kg·m²/s}\).[/tex]

2. Calculate the final angular velocity [tex](\(\omega_2'\))[/tex] of the neutron star:

[tex]\[\omega_2' = \frac{L_2'}{I_2} = \frac{1.53 \times 10^{33}\, \text{kg·m²/s}}{4.32 \times 10^{38}\, \text{kg·m²}}\][/tex]

  This gives [tex]\(\omega_2' \approx 3.54 \times 10^{-6}\)[/tex] rad/s.

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From the graph find the cars speed 5 seconds into the journey

Answers

I think it would be 15 miles per hour because if you look at the graph, the line falls on the 15 right at 5 seconds.
Hope this helps!

How much force is required to accelerate a 2kg mass at 3 m/s2? answer key?

Answers

F = ma so u can plug in the given numbers and solve:

F = (2)(3)

Using Newton's second law of motion, the force required to accelerate a 2kg mass at 3 m/s² is 6 Newtons.

To calculate the force required to accelerate a 2kg mass at 3 m/s², we can use Newton's second law of motion, which states that the force is equal to mass times acceleration (F = m imes a). Therefore, the force (F) required is:

F = 2kg imes 3 m/s² = 6 N

This means that a force of 6 Newtons is needed to accelerate the 2kg mass at the specified rate.

This is a large, rocky body found in space. It often orbits the sun in a belt between Mars and Jupiter.

Answers

Final answer:

Asteroids are rocky bodies in space that mostly orbit the Sun within the asteroid belt, located between Mars and Jupiter. They vary in size and are classified by composition as C-type, S-type, or M-type. The largest asteroid and dwarf planet in this belt is Ceres.

Explanation:

The large, rocky bodies that are often found orbiting the sun in a belt between Mars and Jupiter are known as asteroids. The region where most asteroids are found is called the asteroid belt, and this area extends from 2.2 to 3.3 AU from the Sun. Asteroids are mainly remnants of the initial solar system that existed before the planets formed, ranging from a few centimeters to hundreds of kilometers in size. While most asteroids reside within the asteroid belt, they are spread out with significant empty space between them, making navigation for spacecraft like Galileo and Cassini feasible.

Asteroids are classified into different types: C-type (carbonaceous), S-type (stony), and M-type (metallic). The largest known asteroid is Ceres, which is also classified as a dwarf planet. Understanding asteroids is important for planetary defense as well as for exploring the solar system's past.

Which statement accurately compares the weight of an object on these two planets

Answers

"An object weighs about two times as much on Jupiter as on Neptune." Hope this helps :)

Which of the following statements is true about a current-carrying wire in a magnetic field? @Somy
A. Reversing the current direction will cause the force deflecting the wire to be parallel to the magnetic field.

B. Reversing the current direction will cause the force deflecting the wire to be perpendicular to the magnetic field but in the opposite direction.

C. Reversing the current direction will not affect the force deflecting the wire.

Answers

B. Reversing the current direction will cause the force deflecting the wire to be perpendicular to the magnetic field but in the opposite direction.

2. Lower latitudes tend to have __________. (Points : 1)
lower average temperatures than higher latitudes
the same temperatures as higher latitudes
higher average temperatures than higher latitudes
you can't compare temperatures without including pressure data

Answers

Option c. higher average temperatures than higher latitudes
 Explanation:
 Lower latitudes are also called tropics which is the area of the globe which lies in 0 to 30 degrees of the equator. The region nearer to the equator is hotter as it is direct to the rays of the sun and higher latitudes (60 to 90 degrees) is the polar region which are the regions away from the equator and this the sun's rays falls slantly on those regions and they experience cold temperature whereas tropical region is warmer.

Answer:

Higher average temperatures then higher latitudes. I TOOK THE TEST!

Explanation:

A solid steel sphere of density 7.86 g/cm3 and mass 1 kg spin on an axis through its center with a period of 2.3 s. given vsphere = 4 3 π r3 , what is its angular momentum? answer in units of kg m2 /s.

Answers

The solution for this problem is:

density = mass / volume 
7860 = 1 / ((4/3) pi r^3) 
r^3 = 1 / (7860 * 4/3*pi) 
r = (1 / (7860 * 4/3*pi))^(1/3)

= 0.067 m 

Inertia = (2/5)mr^2

= (2/5) x 1 x 0.067^2

= 0.0017956 kg-m^2 

1/2.3 = 0.4348 rev/s 

0.4348 x 2pi = 2.732 rad/s 

Angular momentum = Inertia x rad/s 

0.0017956 x 2.732 = 0.00490557 kg m^2/s





Which of these alkali metals has the largest atomic radius?
A) Cs
B) Fr
C) Li
D) Na

Answers

B is true
because it has 7 orbits(just like the picture)so it has the largest atomic radius

Answer:

B

Explanation:

Fr

A ball is dropped from the roof of a building. the mass of the ball is 3.0 kg. what is the potential energy of the ball in the instant that it is exactly 18.0 meters above the ground?

Answers

According to given condition there is no height(m) given from roof of building to the ground, there height given 18 m at a point above the ground.                         So, h=18m  ,                mass=3kg     ,         g=9.8m/s2                                                                      P.E=mgh                                                                                                                P.E=(3)(9.8)(18)                                                                                                      P.E=529J
                                      

What voltage would be measured across the 45 ohm resistor?

Answers

You would find the potential difference aka voltage, but more specifically it would be just the voltage that the resistor uses and not the whole circuit.

But if you want the voltage value it’s V=IR so whatever the current is multiply it by the 45 ohm resistor value

Answer:

C) 9.0 volts

Explanation:

A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (3.30 m, 5.20 m) while a constant force acts on it. the force has magnitude 9.70 n and is directed at a counterclockwise angle of 111.° from the positive direction of the x axis. how much work is done by the force on the coin during the displacement?

Answers

Work = force x distance x cos (theta) where theta is the angle between the force and the direction of motion 

component of force in x direction = 9.70N cos 111 = -3.48 N
component of force in y direction = 9.70 sin 111 = 9.06 N

Adding the two = -3.48 x 3.30 m + 9.06N x 5.20 m

= 11.484 + 47.112

= 58.60 Joules

Calculate the frequency of a water wave that has a wavelength of 0.5 m and a speed of 4.0 m/s

Answers

Answer:

f = 8 Hz

Explanation:

Wavelength of wave = 0.5 m

Speed of wave = 4 m/s

Frequency = ?

Solution:

Formula:

f = v/λ

f = frequency

v = speed

λ = wavelength

Now we will put the values in formula.

f = v/λ

f = 4 m/s / 0.5 m

f = 8 s⁻¹

s⁻¹ = Hz

f = 8 Hz

The frequency of the water wave has a wavelength of 0.5 meters and a speed of 4 m/s will be equal to 8 Hz.

What is Wavelength?

The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space.

Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).

The wavelength is more frequently described in nanometers (nm), which are units of 10-9 m, or angstroms, which are units of 10-10 m, for infrared (IR), visible light (UV), and gamma radiation.

As per the given information provided in the question,

The wavelength, λ = 0.5 m

Speed, v = 4.0 m/s

Frequency, F = v/λ

F = 4/0.5

F = 8 Hz.

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which group in the periodic table is known as salt farmers?

carbon family

copper family

helium family

halogen family

Answers

Which group in the periodic table is known as salt formers?

 The correct option is the last one: Halogen family.

 You can find the halogen or "salt formers" in the group 17 of the periodic table. These are:

 - Fluorine.
 -Chlorine.
 - Bromine.
 - Iodine.
 - Astatine.

 All of them are non-metallic elements and they have 7 electrons.

The group in the periodic table known as salt farmers is the halogen family, which consists of fluorine, chlorine, bromine, iodine, and astatine.

The group in the periodic table known as salt farmers is the halogen family. The term 'halogen' comes from Greek roots meaning 'salt forming.' This group consists of the elements fluorine, chlorine, bromine, iodine, and astatine, which are all found in Group 17 of the periodic table. They react readily with metals to form salts, such as sodium chloride (table salt) and calcium chloride (road salt).

Halogens are known for forming compounds with metals to create salts.These elements are very reactive and can be found in Group 17.Examples of halogen compounds include sodium chloride (NaCl) and calcium chloride (CaCl₂).

In contrast, the carbon family (Group 14), the copper family (transition elements), and the helium family (noble gases) do not have these properties.

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