Which of the following decreases the dissolving rate of a solid in water?

Answer:

how large a magnetic field would you experience = 8.16 x 10∧-4T

Explanation:

I = 20KA = 20,000A

r = 4.9 m

how large a magnetic field would you experience =  u.I/2πr

how large a magnetic field would you experience = (4π x10∧-7) × 20000/2π × 4.9

how large a magnetic field would you experience = 8.16 x 10∧-4T

Answer: 8.16*10^-4 T

Explanation:

Given

Current of the lightening bolt, I = 20 kA

Distance from the strike of the lightening bolt, r = 4.9 m

To solve, we use the formula

B = [μ(0) * I] / 2πr, where

B = magnetic field of the lightening

μ = permeability constant = 4π*10^-7 N/A²

I = current of the lightening

r = distance from the lightening strike

B = [(4 * 3.142*10^-7) * 20*10^3] / (2 * 3.142 * 4.9)

B = (12.568*10^-7 * 20*10^3) / 6.284 * 4.9

B = 0.025 / 30.79

B = 8.16*10^-4 T

The magnetic field to be experienced would be 8.16*10^-4 T large

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

Answer:They established the laws of planetary motion.(option B)

Answer:

They established the laws of planetary motion

Explanation:

i did it on edge

Answer:

option (b)

Explanation:

mass of proton, mp = m

mass of deuteron, md = 2m

charge on proton, qp = q

charge on deuteron, qd = q

The magnetic force on the charged particle when it is moving is given by

F = q v B Sinθ

where, θ is the angle between the velocity and magnetic field.

Here, θ = 90°

Let v is the velocity of both the particle when they enters in the magnetic field.

The force on proton is given by

Fp = q x v x B ...... (1)

The force on deuteron is

Fd = q x v x B .... (2)

Divide equation (1) by equation (2)

Fp / Fd = 1

Thus, the ratio of force on proton to the force on deuteron is 1 : 1.

Thus, option (b) is correct.

Answer:

Explanation:

Given that,

Initial speed of the girl is

u = 1.4m/s

Height she is going is

H = 2.45m

Incline plane she will pass to that height

L = 12.4m

Mass of girl and bicycle is

M=60kg

Frictional force that oppose motion is

Fr = 41N

Speed at lower end of inclined plane

V2 = 6.7m/s

Work done by the girl when the car travel downward

Using conservation of energy

K.E(top) + P.E(top) + work = K.E(bottom) + P.E(bottom) + Wfr

Where Wfr is work done by friction

Wfr = Fr × d

P.E(bottom) is zero, sicne the height is zero at the ground

K.E is given as ½mv²

Then,

½M•u² + MgH + W = ½M•V2² + 0 + Fr×d

½ × 60 × 1.4² + 60×9.8 × 2.45 + W = ½ × 60 × 6.7² + 41 × 12.4

58.8 + 1440.5 + W = 1855.1

W = 1885.1 —58.8 —1440.5

W = 355.8 J

Answer:

Explanation:

Given that,

Current in wire is

I = 10A

And the current makes an angle of 30° with respect to the magnetic field

Then, θ = 30°

And the magnetic field is

B = 0.3 T

Length of the wire is

L = 0.5m

Force on the wire F?

The force on the wire in calculated using

F = iL × B

Where

The magnitude of the cross produce of L and B is

L × B = LB•Sinθ

Then, force becomes

F = iLB•Sinθ

F = 10 × 0.5 × 0.3 × Sin30

F = 0.75 N

The force on the wire is 0.75 Newton

Answer:

The magnitude of the magnetic force on the wire is 0.75 N

Explanation:

Given;

current in the wire, I = 10 A

angle of inclination to magnetic field, θ = 30°

magnetic field strength, B = 0.30-T

length of the wire, L = 0.50-m

The magnitude of magnetic force acting on the wire is given as;

F = BILSinθ

where;

B is magnetic field strength

I is the current in the wire

L is length of the wire

θ is the angle of inclination

F = 0.3 x 10 x 0.5 x sin(30)

F = 0.3 x 10 x 0.5 x 0.5

F = 0.75 N

Therefore,  the magnitude of the magnetic force on the wire is 0.75 N

Final answer:

To find the magnitude of the emf induced in the loop after 8.00 seconds has passed since the circumference started to decrease, we can use Faraday's law of electromagnetic induction. We calculate the rate of change of magnetic flux through the loop based on the changing area of the loop, and then determine the magnitude of the emf induced in the loop. The emf induced is -253.30 V, indicating that the induced current flows in a direction that opposes the change in magnetic flux.

Explanation:

To find the magnitude of the emf induced in the loop after 8.00 seconds has passed since the circumference started to decrease, we can use Faraday's law of electromagnetic induction. According to Faraday's law, the emf induced in a loop is equal to the rate of change of magnetic flux through the loop. In this case, as the loop shrinks, its area decreases, resulting in a decrease in magnetic flux.

We know that the circumference of the loop is decreasing at a constant rate of 15.0 cm/s. Using the formula for the circumference of a circle, we can determine the radius of the circle at the given time: r = C / (2*pi), where C is the circumference and pi is a mathematical constant approximately equal to 3.14159. Substituting the given values, we get r = 168 cm / (2*3.14159) = 26.79 cm.

Next, we can calculate the area of the loop as a function of time using the equation A = pi*r^2. Substituting the value of the radius at 8.00 seconds, we get A = 3.14159 * (26.79 cm)^2 = 2252.68 cm^2.

Since the magnetic field is perpendicular to the loop and uniform in magnitude, we can calculate the rate of change of magnetic flux as: dPhi/dt = B*dA/dt, where B is the magnitude of the magnetic field and dA/dt is the rate of change of the area.

Finally, we can calculate the magnitude of the emf induced in the loop as: EMF = -dPhi/dt. The negative sign indicates that the induced current flows in a direction that opposes the change in magnetic flux. Substituting the given values, we get EMF = -0.900 T * (2252.68 cm^2) / 8.00 s = -253.30 V.

Answer:

First of all note that The magnetic field produced by the vertical wire will be into on the right hand side and it will be out of the page on the left hand side

Assuming that the electron beam is coming from the right hand side of the page parallel to the wire, The direction of the velocity vector(V) is left and the direction of magnetic field due the wire(B) is into the page. If u use right hand rule, you will get the direction downwards but as the formula also depends on q , the charge on electron is negative .Therefore the direction will be inverted i.e Upwards.

If you assume the electron beam coming from left hand side.Then also u will get the same answer.

So, the angle α between the velocity of the electron and the magnetic field of the wire is 90°.

Explanation:

For an electron traveling parallel to a wire carrying an upward direction current, the angle between its velocity and the magnetic field of the wire, according to the right-hand rule, is 90 degrees.

The setting of this problem involves a vertical wire carrying an upward direction current and an electron traveling parallel to it. According to the right-hand rule in magnetism, which states that if your thumb points in the direction of the current, then your fingers will curl in the direction of the magnetic field, the magnetic field of the wire would form concentric circles around the wire.

For an electron traveling parallel to the wire, according to this rule, it would be always at a right angle or 90 degrees to the magnetic field as it moves along the circumference of these imaginary concentric circles. Therefore, the angle alpha (ααalpha) between the velocity of the electron and the magnetic field of the wire is 90 degrees.

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Answer:

Explanation:

Given that,

Mass support is

M = 0.95g= 0.95/1000 = 0.00095kg

Radius of circle R = 0.205mm

r = 0.205/1000 = 0.000205m

Then, area of the circle can be determined using

A = πr²

A = π × 0.000205²

A = 1.32 × 10^-7 m²

From pressure definitions

Pressure = Force / Area

The force is perpendicular to the area

Force = weight = mg

F = mg = 0.00095 × 9.8

F = 9.31 × 10^-3 N

Then,

Pressure = Force / Area

P = F/A

P = 9.31 × 10^-3 / 1.32 × 10^-7

P = 70,530.30 N/m²

Since 1 pascal = 1 N/m²

Then,

P = 70,530.30 Pascals

To find the pressure exerted by the phonograph needle, multiply the weight of the needle by the gravitational constant to get the force, calculate the area of the needle tip using the given radius, and divide the force by the area using the pressure formula P = F / A.

The pressure exerted by the needle on the record can be calculated using the formula for pressure P = F / A, where F is the force (in this case the weight of the needle) and A is the area over which the force is applied (in this case the area of the needle tip).

First, you need to convert the weight of the needle into a force. Since weight is a force caused by gravity acting on a mass, you can find it by multiplying the mass of the needle by the acceleration due to gravity (g = 9.8 m/s²). So, F = 0.95 g * 9.8 m/s². However, you need to convert grams to kilograms (as 1g = 0.001kg). Hence, F = 0.95 * 0.001 kg * 9.8 m/s².

Next, you find the area of the very tip of the needle. Since the tip is circular, we use the formula for the area of a circle, A = πr², where r is the radius of the needle tip. Substituting r = 0.205 mm = 0.205 * 10^-3 m (since 1mm = 10^-3m) into the formula will give you the area.

Finally, substitute F and A into the formula P = F / A to find the pressure.

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Answer with Explanation:

We are given that

Velocity of uranium=v=0.94 c

Speed of piece A relative to the original nucleus=[tex]u'_A=0.43c[/tex]

Speed of piece B relative to the original nucleus=[tex]u'_B=0.34c[/tex]

Velocity of piece A observed by observer

[tex]u_A=\frac{u'_A+v}{1+\frac{u'_A v}{c^2}}[/tex]

Substitute the values

[tex]u_A=\frac{0.43c+0.94c}{1+\frac{0.43c\times 0.94c}{c^2}}[/tex]

[tex]u_A=\frac{1.37c}{1+0.4042}=0.98c[/tex]

Velocity of piece B observed by observer

[tex]u_B=\frac{0.34c+0.94c}{1+\frac{0.34c\times 0.94c}{c^2}}[/tex]

[tex]u_B=\frac{1.28c}{1+0.3196}[/tex]

[tex]u_B=0.97 c[/tex]

The velocity of piece A and piece B as measured  by an observer in the laboratory are not same.

Final answer:

A longitudinal wave, like a transverse wave, has properties of amplitude, frequency, wavelength, and speed. These characteristics define the wave's physical behavior and are related by the equation v = fλ, where 'v' is wave speed, 'f' is frequency, and 'λ' is wavelength. Option 2 is correct.

Explanation:

Like a transverse wave, a longitudinal wave has amplitude, frequency, wavelength, and speed. Both types of waves have these fundamental properties, but the way they propagate through mediums is different. In longitudinal waves, the particles of the medium move parallel to the wave's direction of travel, while in transverse waves, particles move perpendicular to the direction of the wave's travel. An example of a transverse wave is a wave on a string, like when playing a guitar. In contrast, sound waves in air are longitudinal waves.

The wavelength (λ) is the distance between adjacent identical parts of the wave, which can be considered from one compression to the next in the case of longitudinal waves. Wave speed (v) is the rate at which the wave travels through the medium. The frequency (f) is the number of wave cycles that pass a given point per unit time, and amplitude refers to the maximum displacement from the equilibrium position within the wave cycle.

It's important to remember that all these properties are related: the speed of a wave is given by the product of its frequency and wavelength (v = fλ).

The complete question is:

You are driving along a highway at 35.0 m/s when you hear the siren of a police car approaching you from behind at constant speed and you perceive the frequency as 1340 Hz. You are relieved that he is in pursuit of a different driver when he continues past you, but now you perceive the frequency as 1300 Hz. What is the speed of the police car? The speed of sound in air is 343m/s.

Answer:

V_s = 30 m/s

Explanation:

The change in frequency observation occur due to doppler effect is given by the equation;

f_o = [(V ± V_o)/(V ∓ V_s)]f_s

Where;

f_o is observed frequency

f_source is frequency of the source

V is speed of sound

V_o is velocity of the observer

V_s is velocity of the source

Now, When the police is coming to you , you hear a higher frequency and thus, we'll use the positive sign on the numerator and negative sign on denominator.

Thus,

f_o = [(V + V_o)/(V - V_s)]f_s

Plugging in relevant values, we have;

1340 = [(343 + 35)/(343 - V_s)]f_s

1340 = [(378)/(343 - V_s)]f_s - - (eq1)

when the police is passing you , you hear a lesser frequency, and thus, we'll use the negative sign on the numerator and positive sign on denominator. thus;

f_o = [(V - V_o)/(V + V_s)]f_s

Plugging in the relevant values to get;

1300 = [(343 - 35)/(343 + V_s)]f_s

1300 = [(308)/(343 + V_s)]f_s - - eq2

Divide eq2 by eq1 with f_s canceling out to give

1340/1300 = [(378)/(343 - V_s)]/[(308)/(343 + V_s)]

V_s = 30 m/s

Answer:

Δx = 3.477 x 10⁻³ m = 3.477 mm

Explanation:

The distance between two consecutive dark fringes is given by the following formula, in Young's Double Slit experiment:

Δx = λL/d

where,

Δx = distance between two consecutive dark fringes = ?

λ = wavelength of light = 4.9 x 10² nm = 4.9 x 10⁻⁷ m

L = Distance between slits and screen = 2.2 m

d = slit separation = 0.31 mm = 0.31 x 10⁻³ m

Therefore,

Δx = (4.9 x 10⁻⁷ m)(2.2 m)/(0.31 x 10⁻³ m)

Δx = 3.477 x 10⁻³ m = 3.477 mm

The distance (in mm) between the first and second dark fringes of the

interference pattern is 3.477 mm

This is calculated by using the formula in Young's Double Slit experiment:

Δx = λL/d

where,

Δx = distance between two consecutive dark fringes which is unknown

λ which is wavelength of light = 4.9 x 10² nm = 4.9 x 10⁻⁷ m

L which is distance between slits and screen = 2.2 m

d which is slit separation = 0.31 mm = 0.31 x 10⁻³ m

We then substitute them into the equation

Δx = (4.9 x 10⁻⁷ m ×2.2 m)/(0.31 × 10⁻³ m)

Δx = 3.477 x 10⁻³ m = 3.477 mm

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Answer:

d) The proper time interval depends upon the speed of the observer

Explanation:

Proper time is the time as measured by a clock moving with the body in motion.

The proper time interval between two events on a world line is the change in proper time, and it depends on the events and the world line connecting them, and also on the motion of the clock between the events.

Answer:

Electric potential is associated with electric fields due to static charges but not with induced electric fields.

Explanation:

An electric potential is the amount of work needed to move a unit charge from a reference point to a specific point inside the field without producing an acceleration. Typically, the reference point is the Earth or a point at infinity. Induced electricity is as a result of changing magnetic flux linkage (no charge is involved)

Electric potential is related to the electrostatic field created by static charges and is given by V = kQ/r; it is not related to induced electric fields or magnetic fields because they are nonconservative.

Electric potential is associated with electric fields due to static charges but not with induced electric fields.

This is because electric potential is defined for conservative fields, such as those produced by static charges, where the potential difference is related to the work done in moving a charge between two points in the field.

For point charges, the electric potential is given by the equation V = kQ/r, which clearly illustrates that electric potential depends on the charge and the distance from it.

On the other hand, induced electric fields are produced by changing magnetic fields and are nonconservative.

Nonconservative fields do not have a well-defined electric potential because the work done to move a charge can vary depending on the path taken, unlike the work done in a conservative electrostatic field.

Therefore, electric potential cannot be associated with induced electric fields or magnetic fields.

Answer:

Explanation:

a.

AIM :

TO STUDY HOW VELOCITY OF WAVES ON THE STRING DEPENDS ON THE STRING'S TENSION.

APPARATUS:

Oscillator, long strings , some masses( to create tension in string) and the support ( rectangular wooden piece).

EXPERIMENTAL SETUP:

1. Measure the length of the string and mass of the weights used.

2. Connect one end of string to the oscillator.

3. Place the support below string on table such that the string is in same line without touching table.

4. After the support, the string should hang freely.

5. The other end of string is connected with some small measured masses which should be hanging.

PROCEDURE:

1. Note down the length of string and mass of weights.

2. Adjust the frequency in the oscillator which creates standing waves in the string.

3. Start from lower frequency and note down the lowest frequency at which mild sound is heard or when string forms one loop while oscillating.

4. Calculate the wavelength using of waves using length of string.

5. Calculate the velocity using frequency and wavelength.

6. Calculate linear mass density.

8. Repeat the procedure with different masses.

7. plot a graph with tension in y axis and linear mass density in x axis.

8. Find slope and compare with velocity.

Linear mass density

µ = m/l(kg-1)

tension

T = m x 9.8N

wave length

ƛ = 2L

b.

We can analyze the data by comparing slope of the graph, tension Vs linear mass density with velocity which is constant for constant length.

Write the slope value in terms of value of velocity and find the relationship between velocity and string's tension.

The expected result is

slope = v²

T ∝ V²

Answer:

The temperature reported by a thermometer is never precisely the same as its surroundings

Explanation:

In this experiment to determine the specific heat of a material the theory explains that when a heat interchange takes place between two bodies that were having different temperatures at the start, the quantity of heat the warmer body looses is equal to that gained by the cooler body to reach the equilibrium temperature. This is true only if no heat is lost or gained from the surrounding. If heat is gained or lost from the surrounding environment, the temperature readings by the thermometer will be incorrect. The experimenter should therefore keep in mind that for accurate results, the temperature recorded by the thermometer is similar to that of the surrounding at the start of the experiment and if it differs then note that there is either heat gained or lost to the environment.

When measuring the specific heat of a material, it is crucial to remember that thermometers require time to come into equilibrium with their surroundings for accurate temperature measurements. This ensures that the temperature readings accurately represent the material's temperature, which is essential for precise specific heat calculations.

The statement, "It may take a few minutes for a thermometer to come into equilibrium with its surroundings," is arguably the most helpful to keep in mind when conducting an experiment to measure the specific heat of a material. This principle is essential because it underlines the importance of allowing time for a thermometer to accurately reflect the temperature of the material it is measuring. Thermal equilibrium is a critical concept in thermodynamics, emphasizing that for accurate temperature measurement, both the thermometer and the material being tested must reach a state where no net heat flow occurs between them. This ensures that the temperature reading is actually representative of the material's temperature, rather than being influenced by initial differences in temperature between the thermometer and the material.

Understanding this concept is vital when measuring specific heat because specific heat calculations rely on accurate temperature measurements before and after a heat transfer occurs. If the thermometer does not accurately reflect the material's temperature due to inadequate time for equilibrium, the calculated specific heat could be significantly off.

To determine Paul's speed, we must calculate the net work done on him using the work-energy theorem. This includes the work done by Susan and the work done against friction. Paul’s speed after being pulled 3.0 m is approximately 1.96 m/s.

Solving this problem involves understanding the work-energy theorem and forces. First, let's calculate the work done. The work done by the force Susan applies (W1) is the product of the tension (T), the distance (d), and the cosine of the angle (θ). W1 = T * d * cos(θ) = 30N * 3.0m * cos(30) = 77.94J.

Next, the work done against friction (W2) is the product of the frictional force and the distance, which is µmgd. Here, µ is the coefficient of friction (0.20), m (10kg) is the mass of the baby, g (9.8m/s2) is the acceleration due to gravity, and d is the distance (3.0 m). W2 = µmgd = 0.20 * 10kg * 9.8m/s2 * 3.0m = 58.8J.

According to the work-energy theorem, the net work done on an object is equal to the change in its kinetic energy. Therefore, the final kinetic energy (and thus the final speed) of Paul will be the initial kinetic energy plus the net work done on him. His initial speed is assumed to be zero, hence the initial kinetic energy is zero. The net work done on him is W = W1 - W2= 77.94J - 58.8J = 19.14J. Setting this equal to the final kinetic energy, (1/2)mv2, allows us to solve for the final speed, v = sqrt((2 * W)/m) = sqrt((2 * 19.14J)/10kg) = 1.96 m/s approximately.

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Answer:

The answer is: c. It does not move

Explanation:

Because the gravitational force is characterized by being an internal force within the Earth-particle system, in this case, the object of mass M. And since in this system there is no external force in the system, it can be concluded that the center of mass of the system will not move.

As the object is dropped at a constant downward force, the center mass of the object-Earth system does not move.

In the absence of an external force, the center mass of the object-Earth system will remain constant as the object fall to the ground.

The force of attraction on the object above the surface of the Earth is given as;

[tex]F = \frac{Gm_1 m_2}{R^2}[/tex]

where;

Thus, as the object is dropped at a constant downward force, the center mass of the object-Earth system does not move.

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Answer:

the density of a blue block is ___twice _____ the density of a red block.

Explanation:

If both blocks have the same mass, then the block with the lesser volume will be more densely packed when compared to the block with the larger volume. This is because the molecules are more closely packed.

Check the image below for detailed calculations for proof

If the blue block and red block have the same mass but different volumes - specifically, the blue block's volume is half that of the red block - then the density of the blue block is twice that of the red block.

Given the blocks weigh the same, their masses are equal. Density is defined as mass per unit volume (mass/volume), meaning the density is influenced by both the mass and the volume of an object. As the red and blue blocks have different volumes, their densities must be different if their masses are the same.

In the case of the blue block and the red block, the blue block has half the volume of the red block but the same mass. Thus, because the blue block's volume is half that of the red block but the mass is the same, the density of the blue block is twice the density of a red block, not half. This is because the proportion of mass to volume in the blue block is larger than in the red block. In other words: Density of blue block = 2 * Density of red block.

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Answer:

Explanation:

d.All of the above

Final answer:

All the listed devices -- bathroom scale, spring scale, and force sensor -- can be used to measure force. Bathroom and spring scales measure the weight of an object, which is a force, and display it typically in kilograms after calibration while force sensors provide direct measurement in newtons.

Explanation:

Devices that can be used to measure force include a bathroom scale, a spring scale, and a force sensor. All of these devices measure force, which can be the weight of an object (the force due to gravity acting on the object). A bathroom scale, for example, measures the normal force exerted by a person standing on it and gives a reading in kilograms by dividing the force in newtons by the acceleration due to gravity (9.80 m/s2). However, it is calibrated to display mass. A spring scale uses the extension of a spring under load to measure force which is typically indicated in newtons or pounds. Lastly, a force sensor is a more general device that can directly measure the force exerted on it in newtons and is often used for more precise scientific measurements.

If you stood on a bathroom scale in an elevator, the reading would change depending on the elevator's motion. The scale would display a higher value when the elevator starts moving upward (accelerating) due to the increase in the normal force. However, when the elevator moves at a constant speed, the scale would read your normal weight as no additional normal force is required once you're moving at constant velocity.

Answer:

Intensity will be equal to [tex]3.07\times 10^{-6}W/m^2[/tex]

Explanation:

We have given power P = 197 kW = 197000 watt

Distance R = 101 km

Area of the hemisphere will be [tex]A=2\pi R^2[/tex]

[tex]A=2\times 3.14\times 101000^2=6.4\times 10^{10}m^2[/tex]

We have to find the intensity

Intensity is equal to [tex]I=\frac{P}{A}[/tex]

[tex]I=\frac{1.97\times 10^5}{6.4\times 10^{10}}=3.07\times 10^{-6}W/m^2[/tex]

So intensity will be equal to [tex]3.07\times 10^{-6}W/m^2[/tex]

Answer:

The linear mass  density is of the string  [tex]\mu= 5.51*10^{-3} kg / m[/tex]

Explanation:

    From the question we are told that

            The distance between wall and pulley is [tex]d = 0.405m[/tex]

            The mass on the hook is [tex]m = 25.4\ kg[/tex]

            The frequency of oscillation is  [tex]f = 261.6 Hz[/tex]

    Generally, the frequency of oscillation is mathematically  represented as

            [tex]f = \frac{1}{2d} \sqrt{\frac{T}{\mu} }[/tex]

Where T is the tension mathematically represented as

                T = mg

Substituting values

             [tex]T = 25.4 *9.8[/tex]

                [tex]=248.92N[/tex]

   [tex]\mu[/tex] is the mass linear density

Making  [tex]\mu[/tex] the subject of the formula above

            [tex]\mu = \frac{T}{(2df)^2}[/tex]

Substituting values

         [tex]\mu = \frac{248.92}{(2 * 0.405 * 261.6)^2}[/tex]

           [tex]\mu= 5.51*10^{-3} kg / m[/tex]

Answer:

0.005550 Kg/m

Explanation:

The picture attached below shows the full explanation

To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:

[tex]\frac{F}{L} = \frac{kl_1l_2}{d}[/tex]

Here,

F = Force

L = Length

k = Coulomb constant

I =Each current

d = Distance

Force of the wire one which is located along the line y to 0.47m is [tex]305*10^{-6}N/m[/tex] then we have

[tex]l_2 = \frac{F}{L} (\frac{d}{kl_1})[/tex]

[tex]l_2 = (305*10^{-6}N/m)(\frac{0.470m}{(2*10^{-7})(25A))})[/tex]

[tex]l_2 = 28.67A[/tex]

Considering the B is zero at

[tex]y = y_1[/tex]

[tex]\frac{kI_2}{2\pi y} =\frac{kI_1}{2\pi y_1}[/tex]

[tex]\frac{(4\pi*10^{-7})(28.67)}{2\pi (y_1)} = \frac{(4\pi *10^{-7})(25)}{2\pi (0.47-y_1)}[/tex]

[tex]y_1 = 0.25m[/tex]

Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m

Answer:

1.04m

Explanation:

the distance is determined by the diameter of the trajectory.

you can find the radius of the trajectory by using the following formula:

[tex]r=\frac{m_cv}{qB}[/tex]

mc : mass of the Big C = 0.303kg/mol/(6.02*10^{23}/mol)=5.03*10^{-25}kg

v: velocity of the ion = 50000m/s

B: magnetic constant = 0.3T

q: 1.6*10^{-19}C

By replacing you obtain:

[tex]r=\frac{(5.03*10^{-25}kg)(50000m/s)}{(1.6*10^{-19}C)(0.3T)}=0.52m[/tex]

the diameter wiil be:

d=2r=1.04m

the ion strikes the detector from 1.04m to the entrance of the spectrometer

The Florida Snow ions strike the spectrometer detector after travelling through a semicircle trajectory will be "1.04 m" far.

According to the question,

Big C's mass, [tex]m_c[/tex] = [tex]\frac{0.303}{6.02\times 10^{23}}[/tex]

                             = 5.03 × 10⁻²⁵ kg

Ion's velocity, v = 50000 ms

Magnetic constant, B = 0.3 T

Charge, q = 1.6 × 10⁻¹⁹ C

We know that,

→ r = [tex]\frac{m_c v}{qB}[/tex]

or,

The radius, r = [tex]\frac{5.03\times 10^{-25}\times 50000}{1.6\times 10^{-19}\times 0.3 }[/tex]

                     = 0.52 m or,

Diameter, d = 2 × r

                     = 2 × 0.52

                     = 1.04 m

Thus the above approach is correct.  

Find out more information about spectrometer here:

https://brainly.com/question/12975133

Answer:

Explanation:

Given that,

Distance between speaker

L = 4.5m

Minimum intensity at L1 = 0.21m

Speed of sound is

V = 340m/s

A. Frequency of sound f?

The path difference Pd

Distance from the first speaker when you are 0.21m away

d1 = 2.25 + 0.21 = 2.46m

Distance from the second speaker when you move 0.21m closer

d2 = 2.25—0.21 = 2.04m

So, path difference is

Pd = ∆d = d1 — d2

Pd = 2.46—2.04 = 0.42m

Using the destructive interference condition

∆d = (m + ½)λ

m = 0,1,2,3....

When m= 0

∆d = ½λ

0.42 = ½λ

λ = 0.84

Then, using wave equation

v = fλ

Then, f = v / λ

f = 340 / 0.84

f = 404.76Hz

B. Incorrect question

If he is to remain at his initial positions then it is 0.21m from the center.

Then,

Constructive interference is given as

∆d = mλ

Where m = 0,1,2,3

So when m= 1

∆d = λ

And we already got the path difference to be 0.42m

So, ∆d = λ

λ = 0.42

So, applying wave equation

V = fλ

F = v/λ

F = 340/0.42

F = 809.52 Hz

But if we are to use the data given in part B

0.35m from the center..

Following the same principle as part A, the path difference will be 0.35

Therefore, since ∆d = λ

Then, λ = 0.35

So, f, = v/λ

F = 340 /0.35

F = 971.43 Hz

Answer:

see the attachment

Explanation:

In frequency spectrum there is no change in value of frequency of signal. However, The amplitude of signal after modulation increases. The fourier transform of sinwct is

1/2(F(w+wc) - F(w-wc))

For 2sinwct, the fourier transform is,

(F(w+wc) - F(w-wc))

In frequency domain, in AM only amplitude changes. Frequency remains same

Answer:

22.38 m

Explanation:

Using,

T = 2π√(L/g)................... Equation 1

Where T = period of the oscillation, L = Length of the pendulum,/Height of the tower. g = acceleration due to gravity .

Make L the subject of the equation

L = gT²/(4π²)..................... Equation 2

Given: T = 9.49 s, g = 9.8 m/s², π = 3.14

Substitute into equation 2

L = 9.8(9.49²)/(4×3.14²)

L = 22.38 m

Hence the height of the tower = 22.38 m

Answer:

a) The speed of the ball is 2.47 m/s (in -x direction)

b) The speed of the block, both just after the collision is 1.236 m/s (in +x direction)

Explanation:

Please look at the solution in the attached Word file.