Which of the following expands to fill the container it is in, but can be compressed to a smaller volume when pressure is applied

Your awnser is the awnser B).

Answer:

The correct answer is A) Soil acidity affects plant growth.

Explanation:

What happens when you place a plant in soil and of course add water? The soil helps it grow.

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Final answer:

To convert the height of a column of mercury in a barometer to atmospheric pressure in atm and kPa, divide the height of the column by 760 to get the pressure in atm, and then multiply the atmospheric pressure by 101.325 to get the pressure in kPa.

Explanation:

To convert the height of a column of mercury in a barometer to atmospheric pressure in atm and kPa, we can use the conversion factors. At sea level, the standard atmospheric pressure is 760 mm Hg (millimeters of mercury) or 1 atm. Using this information, we can calculate the atmospheric pressure in atm and kPa.

To convert from mm Hg to atm, divide the height of the column by 760:

Atmospheric pressure (in atm) = 754.3 mm Hg / 760 mm Hg = 0.992 atm.

To convert from atm to kPa, multiply the atmospheric pressure by 101.325 (the number of kilopascals in 1 atm):

Atmospheric pressure (in kPa) = 0.992 atm * 101.325 kPa/atm = 100.45 kPa.

Final answer:

The rate of a reaction is determined by the rate law, which includes the concentration of reactants, the rate constant k, and the reaction orders m and n. These factors must be determined experimentally.

Explanation:

The rate of a reaction can be determined by the rate law which, for a given reaction, may have the form rate = k [A]m [B]n, where [A] and [B] are the molar concentrations of the reactants, k is the rate constant, and m and n are the reaction orders. To determine the rate of a reaction, one needs to know the values of the rate constant k and the reaction orders m and n, which must be obtained experimentally.

The value of the rate constant k is characteristic of the reaction under specific conditions such as temperature and pressure, and though it is independent of the reactant concentrations, it does vary with temperature. The units for k depend on the reaction orders m and n and the desired units for the rate, which are typically moles per liter per second (mol/L/s). For instance, if the concentration units are mol³/L³, then the units for k should adjust accordingly to ensure the rate remains in terms of mol/L/s.

When concentrated  is added to , a white precipitate forms that is 38.7% Ca by mass a net ionic equation is CO₃²⁻ ( aqueous ) + Ca₂²⁻( aqueous ) ⇒ CaCO3 (s)

Chemical element symbols, numbers, and occasionally additional symbols like parentheses, dashes, brackets, commas, and plus and minus signs are used in a chemical formula to represent information about the chemical proportions of the atoms that make up a certain chemical compound or molecule.

Molecular formula:

Na₂CO₃ ( aq ) + CaCl₂ ( aq )  =  CaCO₃ ( s ) + 2 NaCl

Ionic formula:

2 Na+ ( aq ), CO₃²⁻ ( aq ), Ca₂ ( aq ), and 2 Cl⁻ ( aq ) result in CaCO3²⁻ (s) +2 Na+ ( aq ) and 2 Cl⁻ (aq)

Net ionic formula

CO₃²⁻ ( aqueous ) + Ca₂²⁻( aqueous ) ⇒ CaCO3 (s)

Thus, When concentrated  is added to , a white precipitate forms that is 38.7% Ca by mass a net ionic equation is CO₃²⁻ ( aqueous ) + Ca₂²⁻( aqueous ) ⇒ CaCO3 (s)

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Final answer:

The probable reaction between concentrated CaCl₂(aq) and Na₂HPO₄ forms calcium phosphate, Ca₃(PO₄)₂, as a white precipitate. The net ionic equation for the formation of this precipitate is 3Ca²⁺(aq) + 2PO₄³⁺(aq) → Ca₃(PO₄)₂(s). This demonstrates the common ion effect, decreasing the solubility of a sparingly soluble salt.

Explanation:

When concentrated CaCl₂(aq) is added to Na₂HPO₄, it is likely that a precipitation reaction occurs resulting in the formation of calcium phosphate, which is very slightly soluble in water. The white precipitate formed is most probably calcium phosphate, Ca₃(PO₄)₂, which is 38.7% Ca by mass.

The net ionic equation for the reaction that would lead to the formation of this precipitate is:

3Ca²⁺(aq) + 2PO₄³⁺(aq) → Ca₃(PO₄)₂(s)

Through this reaction, we see the common ion effect, which reduces the solubility of calcium phosphate in the presence of additional Ca²⁺ ions provided by the CaCl₂, leading to the precipitation of Ca₃(PO₄)₂.

The diazonium cation formed when cytosine reacts with Nano2 in the presence of HCl is CH+N2+ C-.

The diazonium cation formed when cytosine reacts with Nano2 in the presence of HCl can be represented as:

CH+N2+C-

In this structure, the cytosine molecule donates its amino group (NH2) to the diazonium cation (N2+) while losing a hydrogen ion (H+). The presence of HCl helps in the formation of the diazonium cation.

The given compound is named as propyl octyl ether.

The given compound is CH3 – CH2 – CH2 – O – CH2 – CH2 – CH2 – CH3. To name this compound, we need to identify the longest carbon chain connected to the oxygen atom. In this case, it is an eight-carbon chain, so the parent chain is octane. Since the oxygen atom is connected to the second carbon atom in the chain, the prefix propyl is used. The compound is then named as propyl octyl ether.

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The PΔV work done by the balloon Spirit of Freedom on the surrounding atmosphere, assuming 1.00 atm pressure during inflation, can be calculated using the formula W = -PΔV, resulting in -1.577 x 10¹ Joules after converting the given volume and pressure to scientific units.

The student is asking about the PΔV work done by a helium balloon on the surrounding atmosphere during its inflation. We assume that the atmospheric pressure is constant during the process. The equation for work done during expansion or compression of a gas at constant external pressure is W = -PΔV. Since the external pressure is given as 1.00 atm, and we know the volume change (ΔV), which is 550,000 cubic feet, we can calculate the work done.

First, to use the equation, we should convert the volume from cubic feet to liters, as standard scientific units are preferred. 550,000 cubic feet equals about 15,562,000 liters (since 1 cubic foot equals approximately 28.317 liters). The pressure should also be converted to Pascals (since 1 atm equals 101,325 Pa).

Calculations:

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The radioactive particle, emitted from carbon-14, has a negative charge and is known as a Beta particle.

A beta particle can be described as a high-energy, high-speed electron or positron emitted by the radioactive decay of an atomic nucleus in beta decay. There are β− decay and β+ decay, which produce electrons and positrons respectively. Beta particles have negative charge electrons released by the nucleus on the decay splitting of a neutron.

Beta particles have an energy of 0.5 MeV and a range of about one meter in the air. Beta particles are ionizing radiation but less ionizing than alpha particles. The higher the ionizing effect, the more damage to the living tissue of human tissue.

The beta particle has medium penetrating power and medium ionizing power. Although the beta particles emitted by different radioactive materials vary in energy and this radioactive carbon-14 also emits beta particles.

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The ranking of the flask contents in terms of molar masses is Flask C (CH4), Flask A (H2), Flask B (He)

The ranking of the flask contents in terms of

This ranking is based on the molar masses of the gases. The molar mass of CH4 is 16 g/mol, the molar mass of H2 is 2 g/mol, and the molar mass of He is 4 g/mol.

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To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material, m

Answer: The correct answer is oxygen.

Explanation:

Reactivity is defined as the tendency of an atom to loose or gain electrons.

The reactivity of non-metal increases as we move from left to right in a period and decreases as we move from top to bottom in a group.

The given elements are non-metals as they belong to group 15 and group 16  of the periodic table.

For the given options:

Nitrogen (N): It belongs to Group 15 and Period 2 of the periodic table.

Oxygen (O): It belongs to Group 16 and Period 2 of the periodic table.

Selenium (Se): It belongs to Group 16 and Period 4 of the periodic table.

Sulfur (S): It belongs to Group 16 and Period 3 of the periodic table.

From the given elements, the most reactive element will be oxygen.

Order of reactivity of metals follows:

[tex]\text{Oxygen}>\text{Nitrogen}>\text{Sulfur}>\text{Selenium}[/tex]

Hence, the correct answer is oxygen.

Answer: The correct answer is Option E.

Explanation:

We are given a chemical compound having formula [tex]Ni(CO)_4[/tex]

In 1 mole of the compound, 1 mole of nickel atom, 4 moles of carbon atom and 4 moles of oxygen atom are present.

According to mole concept:

1 mole of a substance contains [tex]6.022\time 10^{23}[/tex] number of particles

Number of carbon atoms in compound = [tex]4\times 6.022\times 10^{23}[/tex]

Number of nickel atoms in compound = [tex]1\times 6.022\times 10^{23}[/tex]

We are given:

Number of carbon atoms = [tex]5.23\times 10^{24}[/tex]

To calculate the number of nickel atoms for given amount of carbon atom, we use unitary method:

When [tex]4\times 6.022\times 10^{23}[/tex] number of carbon atoms are present, then [tex]6.022\times 10^{23}[/tex] number of nickel atoms are also present.

So, when [tex]5.23\times 10^{24}[/tex] number of carbon atoms are present, then [tex]\frac{4\times 6.022\times 10^{23}}{6.022\times 10^{23}}\times 5.23\times 10^{24}=1.31\times 10^{24}[/tex] number of nickel atoms are also present.

Hence, the correct answer is Option E.

The geometry around the nitrogens in the formamidinium ion can be inferred based on principles of molecular geometry, likely exhibiting either trigonal planar or tetrahedral geometry, depending on their specific bonding and hybridization states.

The question asks about the geometry exhibited by the two nitrogens in the formamidinium ion. To answer this, we refer to basic principles of molecular geometry and electron-pair geometry in chemistry. While the formamidinium ion isn't directly analogous to the ammonium ion, NH4+, which exhibits a tetrahedral electron-pair geometry and a tetrahedral molecular structure, we can deduce similarities based on the presence of nitrogen atoms and their bonding characteristics. In general, nitrogen atoms in amides or similar compounds tend to exhibit sp2 or sp3 hybridization, depending on their bonding and lone pairs.

In the case of the formamidinium ion, each nitrogen would likely be surrounded by three regions of electron density (due to bonds or lone pairs), suggesting an approximate trigonal planar geometry around each nitrogen if they exhibit sp2 hybridization, or a tetrahedral geometry if there's additional bonding or lone pairs leading to sp3 hybridization. However, without the explicit Lewis structure presented, it's crucial to consider the context of the ion's structure, including resonance and the role of any lone pairs or charged species in determining final geometry.

Answer: its A

Explanation: i did the test myself so i know its A

Answer: Option (B) is the correct answer.

Explanation:

A state of matter where molecules are held together by strong intermolecular forces of attraction are known as solid substances. As a result, they are unable to move from their initial place but they can vibrate at their mean position.  

Hence, in solid substances the molecules have low kinetic energy.

In liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Thus, we can conclude that water molecules are listed from A to B to C in least to greatest motion.

Answer:

reading the lab manual before class

Explanation:

The laboratory is a highly regulated and controlled environment. Within a laboratory many rules must be followed so that no contamination occurs or deterioration of the experiments being performed in the laboratory. All of this can be intimidating for a first-time student entering the lab, so it is recommended that the student prepare before leaving so that no accidents can occur.

The best way for a student to prepare before going to a lab is to read the lab manual before class. This way, the student knows everything they can do and cannot do inside a laboratory and all the guidelines needed for this environment.

The element Vanadium (V) is expected to have a half-filled 4s subshell due to its unique electron configuration that favors stability, with the configuration shifting to [Ar] 3d54s1 to achieve a half-filled 4s orbital.

An atom expected to have a half-filled 4s subshell is Vanadium (V), with an atomic number of 23. The electronic configuration is [Ar] 3d34s2. However, due to the stability offered by half-filled subshells, one electron from the 4s orbital will move to the 3d subshell, resulting in the configuration of [Ar] 3d54s1, which is half-filled in its 4s subshell.

Other elements like Chromium (Cr) and Copper (Cu) also exhibit adjustments in their electron configurations in favor of stability with either half-filled or fully-filled d subshells. The electron configuration of Cr is [Ar] 3d54s1 and for Cu, it is [Ar] 3d104s1, both deviating from what would be predicted by the Aufbau principle, highlighting the special stability of half-filled and fully-filled subshells.