Which of the following graphs shows a negative linear relationship with a correlation coefficient, r, relatively close to -1
Answers
The graph that shows a negative linear relationship that has a correlation coefficient, r, that is closer to -1 is: B. graph B.
What is a Negative Linear Relationship Graph?A graph that shows a negative linear relationship has a trendline that slopes downwards from your left to the right.
The closer the data points are to each other along the trendline in a negative linear graph, the closer the correlation coefficient, r, is to -1.
Therefore, the graph that shows a negative linear relationship and has a correlation coefficient, r, that is closer to -1 is: B. graph B.
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Related Questions
Dan uses a compass to draw an arc from Q, as shown. He wants to construct a line segment through R that makes the same angle with line segment QR as line segment PQ.
first chart
Which figure shows the next step to construct a congruent angle at R?
Charts 2 3 4 & 5
Answers
Answer:
Chart 2.
Step-by-step explanation:
In the figure Dan has constructed an angle at point Q.He wants to cinstruct an angle ar point R which is congruent to angle made at point Q.To construct the angle at point R Dan needs to draw an arc at point R .He will put the compass on point R and draw an arc .This is shown in the figure 2.
The figure is added below.
Please help confused
Answers
add the numbers in the set and divide by the quantity of numbers:
9 + 15 + 22 + 45 + 50 +60 + 65 = 266
266 / 7 = 38
the mean = 38
the absolute deviation is subtracting the number from the mean: ( all numbers are positive)
38 - 9 = 29
38 - 15 = 23
38-22 = 16
45-38 = 7
50 -38 = 12
60-38 = 22
65-38 = 27
Graph 12x-9y=36 please???
Answers
Answer:
The graph for 12x-9y=36 is given below
Step-by-step explanation:
The graph for 12x-9y=36 is given below.
[tex]12x-9y=36\\\frac{12x}{36}+\frac{9y}{-36}=1\\\frac{x}{3}+\frac{y}{-4}=1[/tex]
So x intercept is 3 and y intercept is -4.
The required graph is shown below which represents the equation 12x - 9y = 36.
To graph the equation 12x-9y=36, we can rearrange it to slope-intercept form, which is y=mx+b, where m is the slope and b is the y-intercept.
First, solve for y by subtracting 12x from both sides and then dividing by -9. This gives us y=-4/3x+4.
Now we can see that the slope is -4/3 and the y-intercept is 4.
To graph this line, we can start at the y-intercept of (0,4) and then use the slope to find another point.
Since the slope is negative, we can move down 4 units (which is the denominator of the slope) and then move to the right 3 units (which is the numerator of the slope) to get another point at (3,0).
We can then draw a straight line through these two points to graph the equation.
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What is the domain of this function?
{x| x > }
Answers
So the domain would be {x | x ≥ 0}
Hope this helps.
{x | x ≥ 0}
_____
The solid dot at (0, 9) indicates x=0 is part of the domain. The arrow at the right end of the line indicates the domain extends to +∞.
How many different ways are there to choose 10 donuts from 20 varieties if at most 4 chocolate donuts are chosen?
Answers
If instead exactly 3 donuts are chocolate, then you have [tex]19^{17}[/tex] ways of choosing the others.
Continuing the pattern, we see that the total number of ways to choose up to 4 chocolate donuts is given by
[tex]\displaystyle\sum_{c=0}^419^{20-c}=19^{20}\sum_{c=0}^419^{-c}[/tex]
which comes out to be
39 678 289 291 775 535 447 366 041
2-2*3+3. What is the correct answer
Answers
________________________________________________________
Note:
_________________________________________________________
2 - 2 * 3 + 3 =
2 - (2 * 3) + 3 =
(2 - 6) + 3 =
-4 + 3 = -1 .
_____________________________________________________
The correct answer is: " -1 " .
_____________________________________________________
How many positive integers $N$ from 1 to 5000 satisfy both congruences, $N\equiv 5\pmod{12}$ and $N\equiv 11\pmod{13}$?
Answers
So, we found that [tex]N=5\cdot13+11\cdot12^2=1649[/tex], but the least positive solution is [tex]1649\equiv89\pmod{\underbrace{156}_{12\cdot 13}}[/tex], and in general we can have [tex]N=89+156k[/tex] for any integer [tex]k[/tex].
Now, since [tex]5000=32\cdot156+8[/tex], or [tex]4992=32\cdot156[/tex], we know that there are 32 possible integers [tex]N[/tex] that satisfy the congruences.
a(3x-8)=b-18x
what is a value?
what is b value?
Answers
a*(3x-8)=b-18x
3ax-8a=18x+b
The only way for this to happen (non-trivially) is if the coefficients of x are equal, and the constant terms are equal
so
3ax=18x-----> 3a=18--------> a=6
-8a=b---------> b=-8*6-------> b=-48
the answer is
a=6
b=-48
A triangular traffic island has a base half as long as its height. The island has an area of 25 m2 . Find the base and the height.
Answers
Alice collected donations of $50, $125, $10, $210, $50, $24, and $175 for charity. What is the mean of her collections?
Answers
To find the mean you add all the values up and divide the sum by the amount of numbers added
50 + 125 + 10 + 210 + 50 + 24 + 175 = 644
Divide the sum by the amount of numbers added
644 / 7 = 92
The answer is $92
Hope this helps!
Answer:92
Step-by-step explanation:
92
which values of x are solutions of the equation x^3+ x^2-2x=0
Answers
Kendrick travel 2/3 mile to his friend’s house.He cycles 3/4 of his distance and walks the rest of the way.What fraction of a mile did he cycle?
Answers
Jamie mowed 7 lawns. He earned $10, $15, $12, $15, $8, And $15 for six lawns. How much did he earn the seventh time if the mean of the data is 12
Answers
Express this equation in word form:
5 + ( 2 x 6 )
Answers
The parenthesis equation is two times six. Then out of that is 5. So it's 5 plus 2 times six.
-DustinBR
Translate the given statement into an algebraic inequality or compound inequality: The IRS says you are in a certain tax bracket if your taxable income, i, is over $24,500, but not over $59,725.
Answers
This means, the taxable income can be more than $ 24,500 but less than or equal to $ 59,725.
If i represents this taxable income, we can write the inequality as:
$ 24,500 < i ≤ $ 59,725
Answer:
C. your welcome
find any points of discontinuity for each rational function. Sketch a graph. Describe any verticals or horizontal asympyoyes and any holes
(X^2-4)/(X+2)(X^2-49)
Answers
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
To find the points of discontinuity and sketch the graph of the rational function (x^2-4)/(x+2)(x^2-49), we need to determine the values of x that make the denominator equal to zero. We find that x = -2, x = 7, and x = -7 are the points of discontinuity. We can then sketch the graph by plotting the vertical asymptotes at x = -2, x = 7, and x = -7, and determining the behavior of the function on each side of those points.
Explanation:To find the points of discontinuity for the rational function (x^2-4)/(x+2)(x^2-49), we need to determine where the denominator is equal to zero. The denominator has two factors, (x+2) and (x^2-49). Setting each factor equal to zero, we find that x = -2, x = 7, and x = -7. These are the points where the function has vertical asymptotes or holes.
To sketch the graph, we can start by plotting the vertical asymptotes at x = -2, x = 7, and x = -7. Next, we can examine the sign of the function on each side of the vertical asymptotes to determine the behavior of the graph. Finally, we can plot any holes in the graph at the corresponding x-values.
Additionally, we should determine if there are any horizontal asymptotes. For rational functions, horizontal asymptotes occur when the degree of the numerator is less than or equal to the degree of the denominator. In this case, the degree of the numerator is 2 and the degree of the denominator is 3, so there is no horizontal asymptote.
ABC has coordinates of A(–5, –7), B(6, –3), and C(2, 7). Find the coordinates of its image after a dilation centered at the origin with a scale factor of 2.
Answers
A' = 2A = (-10, -14)
B' = 2B = (12, -6)
C' = 2C = (4, 14)
The coordinates of the image after dilation with a scale factor of 2 are A'(-10, -14), B'(12, -6), C'(4, 14).
Explanation:Your question involves geometry and specifically, dilation transformations. A dilation is a transformation that moves each point along the ray from the center of dilation to the point. The number given as the scale factor tells you how much to move. In this case, we are asked to dilate the given points with a scale factor of 2 centered at the origin (0,0).
So, each coordinate of the original triangle should be multiplied by 2. Let's find each coordinate after dilation:
A: -5*2, -7*2 = A'(-10, -14)B: 6*2, -3*2 = B'(12, -6)C: 2*2, 7*2 = C'(4, 14)So, the coordinates of the image after a dilation with a scale factor of 2 are A'(-10, -14), B'(12, -6), and C'(4, 14).
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Using the law of cosines, a=2.2
Use your answer above to find m<B, to the nearest degree. m<B=__
Answers
Explanation:
1) Law of cosines:
In a triangle with sides a, b, c whose opposite angles are, respectively, A, B and C, the law of cosines states:
b² = a² + c² - 2 (a)(c) cos (B)
2) In the triangle of the figure you have
b = 4.0
B = ?
a = 2.2
c = 3.7
⇒ (4.0)² = (2.2)² + (3.7)² - 2 (2.2) (3.7) cos(B)
⇒ 16 = 4.84 + 13.69 - 16.28cos(B)
⇒ 16.28 cos(B) = 4.84 + 13.69 - 16 = 2.53
⇒ cos(B) = 2.53 / 16.28
⇒ X = arccos(2.53 / 16.28 ) = 81.06° ≈ 81°
Answer:
81
Step-by-step explanation:
Help!!!!!!!!!!!!!!!!
Answers
∠y + 56 + 51 = 180
To find y, simplify, isolate and simplify again to get y. Remember, what you do to one side, you do to the other.
∠y + 107 = 180
∠y + 107 (-107) = 180 (-107)
∠y = 180 - 107
∠y = 73°
A triangle is = 180°. With this knowledge, you can find ∠x (the last angle).
Plug in 73° for y
y = 73
73 + 72 + x = 180
Simplify.
x + 145 = 180
isolate the x, subtract 145 from both sides
x + 145 (-145) = 180 (-145)
x = 180 - 145
x = 35°
A) 35° is your answer
hope this helps
Need help on 1-6 please I need to solve for x and I need to get this done.
Answers
1. Sin = Opposite/Hypotenuse
x = 10*sin(40°) ≈ 6.428
2. Sin = Opposite/Hypotenuse
x = arcsin(7/12) ≈ 35.69°
3. Tan = Opposite/Adjacent
x = 18/tan(52°) ≈ 14.063
4. b^2 = a^2 +c^2 -2ac*cos(B)
B = arccos((a^2 +c^2 -b^2)/(2ac)) = arccos((7^2 +13^2 -8^2)/(2*7*13))
B = arccos(11/13) ≈32.20°
5. Same formula.
x = √(a^2 +c^2 -2ab*cos(B)) = √(157-132cos(42°)) ≈ 7.675
6. The ratio of side lengths is the same as the ratio of the sines of the opposite angles.
6/10 = sin(x)/sin(100°)
x = arcsin((6/10)*sin(100°)) ≈ 36.22°
Kim spun the spinner 75 times and got a three 30 times. What is the experimental probability?
Answers
So 30 / 75 = 0.4 = 40%
Hope this helps.
Blue cassests hold 45 min. Of music
Green cassets hold 55 min. Of music
If Niko has 16 cassets containing 830 min. Of music
How many are blue? And how many are green?
Answers
Thus the total number of cassets will be:
b+g=16
hence
g=16-b.......i
The total amount was:
45b+55g=830..ii
plugging i in ii we get:
45b+55(16-b)=830
45b+880-55b=830
simplifying
45b-55b=830-880
-10b=-50
thus
b=5
hence
g=16-5=11
number of blue cassets was 5 and that of green was 11
Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and noticed that it took her the same amount of time as it did to ride 3 miles with the wind. How fast was the wind blowing
Answers
40+2w=60-3w
5w=20
w=4mph
The speed of the wind is 4 mph.
Let, the speed of the wind is W mph.
When Lupe rides with the wind, her effective speed is 20 + W mph, and when she rides against the wind, her effective speed is 20 - W mph.
We are given two pieces of information:
Lupe rode 2 miles against the wind, and it took her the same amount of time as riding 3 miles with the wind.
The time taken to cover a distance is equal to the distance divided by the speed.
Using this information, we can set up two equations:
Time taken against the wind = Time taken with the wind
2 / (20 - W) = 3 / (20 + W)
Now, let's solve for W:
2(20 + W) = 3(20 - W)
40 + 2W = 60 - 3W
5W = 20
W = 20 / 5
W = 4 mph
The speed of the wind is 4 mph.
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In the diagram, the base of the tower is at point H, and the top of the tower is at point F. If the distance from the base of the tower to point G is 7x feet and the distance from the base of the tower to point E is 6x + 12 feet, find GE, the distance across the lake.
A. 84 feet
B.
94 feet
C. 168 feet
D. 186 feet
Answers
This problem can be solved using triangle similarities:
Consider the Pythagorean Theorem with the formula; c^2=a^2+b^2
let: a=height from base to point
b1=base of the first triangle formed
b2-base of the second triangle formed
c1=c2= hypotenuse of the two triangles,
note:
they have equal hypotenuse and share the same height, thus a1=a2
sqrt[(a^2+(7x)^2)]=sqrt[a^2+(6x+12)^2]
sqrt(49x^2) =sqrt[(6x+12)^2]
7x=6x+12
x=12
GE=7x+6x+12
GE=7(12)+6(12)+12
GE= 168 feet
Thus, the answer is:
C. 168 feet
Charles owed $390 to his friend. On the first day Charles paid his friend $12. Each following week the amount Charles paid his friend increased by the same amount. After 10 payments, Charles had paid back the full amount. By how much did each payment increase?
Answers
Amount owe=$390
Payment=$10
Number of payments=10
thus using the formula:
A=P(1+r)^n
plugging the values we get:
390=10(1+r)^10
solving for r we get
39=(1+r)^10
r=0.4425
thus the amount increased by 44.25%
When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.
Answers
[tex]Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution[/tex]
[tex]x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \ 0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \ 0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \ 0[/tex]
[tex]Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}[/tex]
To solve for the positive number when the sum of 5 and three times the number is subtracted from the square of the number to yield zero, set up and solve the quadratic equation x^2 - 3x - 5 = 0 using the quadratic formula.
Explanation:The student has asked for help in finding a positive number when the sum of 5 and three times the number is subtracted from the square of the number, and the result is 0. This involves setting up a quadratic equation and solving for the number.
Let's denote this positive number as 'x'. According to the problem statement, the equation can be written as:
x2 - (5 + 3x) = 0.
We can then expand and simplify this equation:
x2 - 5 - 3x = 0
And, rearrange it into standard quadratic form:
x2 - 3x - 5 = 0
Next, we can either factorize this equation, if possible, or use the quadratic formula to find the value of 'x' that satisfies the equation. Since this equation does not factor neatly, we use the quadratic formula:
x = ∛2 - 4ac) / 2a
In this case, a = 1, b = -3, and c = -5. Plugging these into the quadratic formula, we find the two possible solutions for x. Only the positive solution is relevant since the problem states that the number is positive.
determine the domain of the function h(x)= 9x/x(x^2-36)
Answers
Final answer:
The domain of the function h(x)=9x/x(x²-36) is all real numbers except 0, 6, and -6, because the function is undefined at these points.
In conclusion, the domain of h(x) is x ∈ ℝ, x ≠ 0, x ≠ 6, x ≠ -6.
Explanation:
The question asks to determine the domain of the function h(x) = 9x / x(x² - 36).
The domain of a function consists of all the real numbers x for which the function is defined. In this case, the function will be undefined when the denominator is zero because division by zero is not defined in mathematics.
To find these values, we set the denominator equal to zero and solve the resulting equation:
x(x² - 36) = 0.This can be factored further as x(x - 6)(x + 6) = 0, which gives us the zero points of x = 0, x = 6, and x = -6.
Therefore, the domain of h(x) is all real numbers except 0, 6, and -6.
In conclusion, the domain of h(x) is x ∈ ℝ, x ≠ 0, x ≠ 6, x ≠ -6.
19. # Q Find the missing side length
Answers
the missing is the hypotenuse = √(6² + 8² ) = √100 = 10
The correct answer is the second
Hope this Helped!
;D
Brainliest??
sandra has 5 toy cars .Each toy car has a mass of 8 grams .what is the total mass of all 5 cars?
Answers
Final answer:
The total mass of Sandra's 5 toy cars is calculated by multiplying the mass of one toy car (8 grams) by the total number of cars, resulting in a total mass of 40 grams.
Explanation:
The question requires us to calculate the total mass of Sandra's toy cars. Since each toy car has a mass of 8 grams, we can find the total mass by multiplying the mass of one car by the number of cars, which is 5 in this case. Therefore, the calculation we need to perform is 8 grams times 5, which will give us the total mass of all the toy cars combined.
To solve: 8 grams/car × 5 cars = 40 grams.
Thus, the total mass of all 5 toy cars that Sandra has would be 40 grams.
Please answer this question I need it fast:
Together, Mary Sue and Betty have 603 necklaces. Mary Sue has 115 more necklaces than Betty. How many necklaces does Betty have?
Answers
M = necklaces owned by Mary Sue
B = necklaces owned by Betty
You know that:
M + B = 603
M - B = 115
Therefore, when you have the sum and the difference of two numbers, in order to find the biggest number you have to sum the sum and the difference and divide it by 2, and in order to find the smallest number you have to subtract the difference from the sum and divide it by 2:
M = [(M + B) + (M - B)] ÷ 2
= [603 + 115] ÷ 2
= 359
B = [(M + B) - (M - B)] ÷ 2
= [603 - 115] ÷ 2
= 244
Hence, Mary Sue has 359 necklaces and Betty has 244 necklaces.
Answer:
mary sue: 359, betty; 244
Step-by-step explanation:
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