Answer:
D does not implies that the sequence is divergent. All others statements do.
Step-by-step explanation:
Statement D: "[tex](a_n)[/tex] has both an increasing subsequence and a decreasing subsequence" does not necessarily implies that the sequence is divergent. For example, let [tex](a_n)[/tex] the sequence given by:
[tex]a_n=\frac{1}{n}[/tex] if n is odd
[tex]a_n=-\frac{1}{n}[/tex] if n is even
We can see that the subsequence [tex]a_{2n-1}[/tex] is a decreasing sequence (the subsequence given by odd indexes). And the subsequence [tex]a_{2n}[/tex] is an increasing sequence (the subsequence given by even indexes).
However, [tex](a_n)[/tex] is a convergent sequence with limit zero.
kindly solve using the second shifting theorem. thanks. please include explanation that I can understand. many thanks. L[t^2 u(t – 3)] -3)]
Answer:
[tex]\dfrac{2}{s^3}e^{-3s}\ +\ \dfrac{6}{s^2}e^{-3s}\ +\ \dfrac{9}{s}e^{-3s}\ -\ \dfrac{3}{s}[/tex]
Step-by-step explanation:
Given polynomial,
[tex]f(t)\ =\ t^2.u(t-3)\ -\ 3[/tex]
we can write above polynomial as
[tex]f(t)\ =\ (t-3+3)^2.u(t-3)\ -\ 3[/tex]
[tex]=\ ((t-3)^2\ +\ 2\times 3\times (t-3)\ +\ 3^2).u(t-3)-3[/tex]
[tex]=\ (t-3)^2.u(t-3)\ +\ 6(t-3).u(t-3)\ +\ 9.u(t-3)\ -\ 3[/tex]
Now, we have to calculate the Laplace of above polynomial
according to shifting property of Laplace transform, we can write
[tex]f(t-t_0)\ =\ F(s).e^{-st_0}[/tex]
So, we can write the Laplace transform of above polynomial as
[tex]L[f(t)]\ =\ L[(t-3)^2.u(t-3)\ +\ 6(t-3).u(t-3)\ +\ 9.u(t-3)\ -\ 3][/tex]
[tex]=\ \dfrac{2}{s^3}e^{-3s}\ +\ \dfrac{6}{s^2}e^{-3s}\ +\ \dfrac{9}{s}e^{-3s}\ -\ \dfrac{3}{s}[/tex]
So, the Laplace transform of the given polynomial will be[tex]\ \dfrac{2}{s^3}e^{-3s}\ +\ \dfrac{6}{s^2}e^{-3s}\ +\ \dfrac{9}{s}e^{-3s}\ -\ \dfrac{3}{s}[/tex]
Suppose that a worker in Country A can make either 10 iPods or 5 tablets each year. Country A has 100 workers. Suppose a worker in Country B can make either 2 iPods or 10 tablets each year. Country B has 200 workers. A bundle of goods that Country A could not make would be:
Answer:
A bundle of goods that Country A has are 1000 iPods and 500 Tablets.
Step-by-step explanation:
Country A can produce either iPods and Tablets.
Total man power Country A has 100 workers.
As per information in the question w
100 worker make either ipod or 100 worker make tablets
1 worker can produce 10 iPods.
Therefore
100 workers can produce (100 * 10) = 1000 iPods.
on the other hand
1 worker can produce 5 tablets.
Therefore
100 workers can produce (100 * 5)= 500 Tablets
Thus,
A bundle of goods that Country A has are 1000 iPods and 500 Tablets.
193 meters in 2 seconds = meters in 1 minute
Answer:
The required answer is 5790 meters in 1 minute.
Step-by-step explanation:
Consider the provided information.
193 meters in 2 seconds = meters in 1 minute
193 meters in 2 seconds can be written as:
193 meters = 2 seconds
There are 60 seconds in 1 minute. To convert 2 seconds to 1 minute multiply both the sides by 30.
30 × 193 meters = 30 × 2 seconds
5790 meters = 60 seconds
5790 meters = 1 minute (As we know 60 seconds = 1 minute)
This can be written as:
5790 meters in 1 minute.
Hence, the required answer is 5790 meters in 1 minute.
What does frequency refer to as it pertains to a frequency histogram? а. Proportion b. Count C. Mean d. Variance
Answer:
(a) PROPORTION.
Step-by-step explanation:
A relative frequency histogram has bars whose height is equal to either the proportion of cases that are between the upper and lower bounds of the bar.
The relative frequency in a relative frequency histogram refers to PROPORTION.
A relative frequency histogram is a graph that has the same shape and the same horizontal scale as the corresponding frequency histogram. The difference is that the vertical scale measures the relative frequencies (percentages or proportions).
Hence, option (a) is right option.
Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E5 should be mixed with 6000 gal of E10 to make an E9 mixture?
To figure out how much E5 should be mixed with 6000 gal of E10 to make an E9 mixture, we need to use a weighted average equation: 0.10*6000 + 0.05*X = 0.09 * (6000 + X). Solving this equation will provide the required amount of E5 gasoline.
Explanation:To solve this problem, we use a technique known as a weighted average. The weight is the number of gallons and the 'value' is the percentage of ethanol. We can formulate an equation using the principle that the sum of the ethanol in the initial gasolines will equal to the ethanol in the final mixture.
Let's denote by X the needed amount of E5 gasoline. Therefore, the total ethanol before mixing would be 0.10*6000 (from the E10 gasoline) + 0.05*X (from the E5 gasoline). After mixing, the total ethanol will be 0.09 (6000 + X).
Equating these two gives us 0.10*6000 + 0.05*X = 0.09 * (6000 + X). Solving this equation will give the needed amount of E5 gasoline.
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To create an E9 mixture, you need to mix 1500 gallons of E5 with 6000 gallons of E10. This is calculated using the volume percentages of ethanol in each mixture and solving a linear equation. The final mixture will contain 9% ethanol.
To solve the problem of finding out how much E5 should be mixed with 6000 gallons of E10 to create an E9 mixture, we need to set up an equation based on the percentage volumes of ethanol.
Let's denote the amount of E5 to be added as x (in gallons).
E10 contains 10% ethanol and 90% gasoline. Therefore, in 6000 gallons of E10, the amount of ethanol is:
0.10 × 6000 = 600 gallons of ethanol.E5 includes 5% ethanol and 95% gasoline. Therefore, in x gallons of E5, the amount of ethanol is:
0.05 × x gallons of ethanol.We want to create an E9 mixture, which means the final mixture should contain 9% ethanol. The total volume of the final mixture will be:
6000 + x gallons.The amount of ethanol in the final mixture can be represented as:
(600 + 0.05x) gallons of ethanol.This amount should be 9% of the total final volume:
0.09 × (6000 + x) = 600 + 0.05xSolving for x:
0.09(6000 + x) = 600 + 0.05x540 + 0.09x = 600 + 0.05x0.09x - 0.05x = 600 - 5400.04x = 60x = 1500Therefore, you need to mix 1500 gallons of E5 with 6000 gallons of E10 to create an E9 mixture.
Is .13 less than .32
Yes, .13 is less than .32
Which of the following completes the statement?
In the number 45,569, the 5 in the hundreds place is ______ the 5 to its left.
A. the same value as
B. 1/10 the value of
C. 10 times the value of
D. 100 times the value of
Answer:
B. 1/10 the value of
Step-by-step explanation:
In our base-10 place-value number system, the place value of a number is multiplied by 10 when it moves 1 place to the left. It is multiplied by 1/10 when it moves 1 place to the right.
A digit has 1/10 the value of the same digit one place to its left.
Answer: B
Step-by-step explanation:
xy′ = √(1 − y2 ), y(1) = 0
Answer:
The particular solution is [tex]y=\sin (\ln|x|)[/tex] .
Step-by-step explanation:
The given differential equation is
[tex]xy'=\sqrt {1-y^2}[/tex]
It can be written as
[tex]x\frac{dy}{dx}=\sqrt {1-y^2}[/tex]
Use variable separable method to solve the above equation.
[tex]\frac{dy}{\sqrt {1-y^2}}=\frac{1}{x}dx[/tex]
Integrate both sides.
[tex]\int \frac{dy}{\sqrt {1-y^2}}=\int \frac{1}{x}dx[/tex]
[tex]\sin^{-1} y=\ln|x|+C[/tex] .... (1)
It is given that y(1)=0. It means y=0 at x=1.
[tex]\sin (0)=\ln|1|+C[/tex]
[tex]0=0+C[/tex]
[tex]0=C[/tex]
The value of constant is 0.
Substitute C=0 in equation (1) to find The required equation.
[tex]\sin^{-1} y=\ln|x|+0[/tex]
Taking sin both sides.
[tex]y=\sin (\ln|x|)[/tex]
Therefore the particular solution is [tex]y=\sin (\ln|x|)[/tex] .
An astronaut with a mass of 80.70 kg is standing still on the surface of the Mars (Mars has an acceleration due to gravity of 3.80 m / s^2). How many pounds force is she exerting on the martian surface?
Answer:
Force, F = 68.93 pounds
Step-by-step explanation:
Given that,
Mass of the astronaut, m = 80.70 kg
Acceleration due to gravity on Mars, [tex]a=3.8\ m/s^2[/tex]
The force acting on him is given by using second law of motion as :
[tex]F=m\times a[/tex]
[tex]F=80.70\ kg\times 3.8\ m/s^2[/tex]
F = 306.66 N
Since, 1 newton = 0.224 pound
F = 306.66 N = 68.93 pounds
So, 68.93 pounds force she exerts on the martian surface. Hence, this is the required solution.
Aspirin tablets generally contain 325 mg of aspirin. How many such tablets may be prepared from 5 kg of aspirin?
Answer:
15,384 such tablets may be prepared from 5 kg of aspirin
Step-by-step explanation:
The problem states that aspirin tablets generally contain 325 mg of aspirin. And asks how many such tablets may be prepared from 5 kg of aspirin.
Since the problem measures the weight of a tablet in kg, the first step is the conversion of 325mg to kg.
Each kg has 1,000,000mg. So
1kg - 1,000,000mg
xkg - 325mg.
1,000,000x = 325
[tex]x = \frac{325}{1,000,000}[/tex]
x = 0.000325kg
Each tablet generally contains 0.000325kg of aspirin. How many such tablets may be prepared from 5 kg of aspirin?
1 tablet - 0.000325kg
x tablets - 5kg
0.000325x = 5
[tex]x = \frac{5}{0.000325}[/tex]
x = 15,384 tablets
15,384 such tablets may be prepared from 5 kg of aspirin
Around 15,385 tablets of aspirin can be created from 5 kilograms of aspirin, using the assumption that one tablet typically contains 325 milligrams of aspirin.
Explanation:This question requires a basic understanding of the conversion from kilograms to milligrams. 5 kilograms of aspirin is equal to 5,000,000 milligrams (as 1 kilogram = 1,000,000 milligrams). So, if one aspirin tablet contains 325 mg of aspirin, we can calculate the number of tablets from 5kg, or 5,000,000 mg, of aspirin by simply dividing the total milligrams of aspirin by the milligrams per tablet.
To calculate:
Number of tablets = Total mass / Mass per tablet
= 5,000,000 mg / 325 mg/tablet
So, roughly 15,385 tablets of aspirin can be produced from 5 kg of aspirin.
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Describe the variable Yr_Built. Choose the correct answer below. A. The variable Yr_Built is quantitative, with units years. B. The variable Yr_Built is an identifier variable. C. The variable Yr_Built is categorical and ordinal. D. The variable Yr_Built is categorical and nominal.
Answer:
A. The variable Yr_Built is quantitative, with units years.
Step-by-step explanation:
Since, Yr_Built means the year built, Also year has a numerical value like 2008, 2000, 1865, etc.
So, it is quantitative.
Further, Data is said to be quantitative if it has a numerical value.
Categorical data is that data which has categories. For example, Gender: It has two categories Female and Male.
The data which as ordering is called ordinal data. Example, Bad, Average, Good.
Identifier Variable is the variable that is used for identity. Example, Employee No., etc.
Estimate the sum. Use benchmarks with decimal parts of 0, 0.25, 0.50, or 0.75.
2.52+4.03
A. 6.50
B. 6.75
C. 7
A 1L solution containing 25,000 units of heparin must run at 30mL/hr. How much heparin is administered per hour?
Answer:
750 units
Step-by-step explanation:
As given in question,
speed of solution = 30 mL/hr
1 L of solution contains heparin = 25000 units
=> 1000 mL of solution contains heparin = 25000 units
[tex]=>\ \textrm{1 mL of solution contains heparin}\ =\ \dfrac{25000}{1000}\ units[/tex]
= 25 units
Hence, 30 mL of solutions contains heparin = 30 x 1 mL of solution contains heparin
= 30 x 25
= 750 units
Hence, heparin administered per hour = 750 units
Final answer:
To find the amount of heparin administered per hour at a rate of 30mL/hr in a 1L solution with 25,000 units, calculate the concentration in units/mL and multiply by the hourly rate. This results in 750 units of heparin administered per hour.
Explanation:
To calculate the amount of heparin administered per hour when the infusion rate is 30mL/hr, use the given total units of heparin in the 1L solution. Since there are 25,000 units in 1L (1,000 mL), we can find the amount per mL and then multiply by the hourly rate.
First, calculate the units per mL:
Units per mL = Total units / Total volume
Units per mL = 25,000 units / 1,000 mL
Units per mL = 25 units/mL
Next, calculate the units delivered per hour:
Units per hour = Units per mL * Infusion rate (mL/hr)
Units per hour = 25 units/mL * 30 mL/hr
Units per hour = 750 units/hr
Therefore, 750 units of heparin are administered per hour.
A breath analyzer, used by the police to test whether drivers exceed the legal limit for blood alcohol percentage while driving, is known to satisfy P ( A | B ) = P ( A c | B c ) = p where A is the event "breath analyzer indicates that legal limit is exceeded" and B is the event "driver's blood alcohol percentage exceeds legal limit." On Saturday night, about 5% of all drivers are known to exceed the limit. If we want P ( B | A ) to equal 0.9, what value of p should we use, rounded to 4 decimal places? Group of answer choices
To find the value of 'p' that satisfies the equation, we use Bayes' theorem and substitute the given values into the equation.
Explanation:In this question, we need to find the value of p which satisfies the equation P(A|B) = P(A' | B'), where A is the event 'breath analyser indicates that legal limit is exceeded' and B is the event 'driver's blood alcohol percentage exceeds legal limit.'
We are given that approximately 5% of all drivers exceed the legal limit for blood alcohol percentage while driving, which means P(B) = 0.05.We are also given that we want P(B|A) = 0.9. Using Bayes' theorem, we can write:Therefore, the value of p that should be used, rounded to 4 decimal places, can be calculated using the above steps.
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what geometric postulates justifies the statement below
If AB is congruent to CD and CD is congruent to EF, then AB
iscongruent to EF.
Answer: Transitive property of congruence.
Step-by-step explanation:
Transitive property of congruence is similar to transitive property of equality , it says that if a is congruent to b and b is congruent to c , then a is congruent to c.
Given statement : If AB is congruent to CD and CD is congruent to EF, then AB is congruent to EF.
Here a= AB , b= CD and c= EF
Therefore, the geometric postulates justifies given the statement must be Transitive property of congruence.
For what side length(s) is the area of an equilateral triangle equal to 30 cm?? Only enter the number, in centimeters, rounded to two decimal places. A cm ►
Answer: The sides length are 8.32 cm
Step-by-step explanation:
An equilateral triangle has all his sides of the same lenght, so we assume that the triangle has an L lenght in his sides.
The area of a triangle is [tex]Area = \frac{base * height}{2}[/tex] where the base is L, the Area is 30 and an unknown height.
To determine the height, we cut the triangle in half and take one side. By simetry, one side has a base of [tex]\frac{L}{2}[/tex], a hypotenuse of L and a the unknown height.
Then we apply the Pythagoras theorem, this states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, or, [tex]hypotenuse = \sqrt{c^{2} + c^{2} }[/tex] Where one c is [tex]\frac{L}{2}[/tex] and the other is the height.
Then we find one of the c of the equation wich will be the height.
[tex]height = \sqrt{hypotenuse^{2}-base^{2} }[/tex]
[tex]height = \sqrt{ L^{2} -\frac{L}{4} ^{2}}\\height = \sqrt{\frac{ 3L^{2}}{4} } \\\\height = \frac{\sqrt{3}L }{2}[/tex]
Finally, we use the triangle area mentioned before an find the value of L.
[tex]30 = \frac{L*\frac{\sqrt{3}L }{2} }{2} \\\\L = \sqrt{\frac{120}{\sqrt{3} } } \\\\L = 8.32 cm[/tex]
If A=W/(m2-°C), B=m2, C=°C and D = A x B x C, what are the units of D?
Answer:
[tex]\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
Step-by-step explanation:
We are given that A=[tex]\frac{W}{m^2-C^{\circ}}[/tex]
B=[tex]m^2[/tex]
C=[tex]C^{\circ}[/tex]
We are given that [tex]D=A\times B\times C[/tex]
We have to find the unit if D
Substitute the values then we get
[tex]D=\frac{W}{m^2-C^{\circ}}\times m^2\times C^{\circ}=\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
[tex]D=\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
Hence, units of D=[tex]\frac{Wm^2C^{\circ}}{m^2-C^{\circ}}[/tex]
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
2x1 + 3x2 − x3 = 14
x1 + 2x2 + x3 = 4
5x1 + 9x2 + 2x3 = 7
1 0 -5 16
0 1 3 -6
0 0 0 -19
Incorrect
Answer:
The reduced row-echelon form of the linear system is [tex]\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right][/tex]
Step-by-step explanation:
We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:
Interchange two rowsMultiply one row by a nonzero numberAdd a multiple of one row to a different rowTo find the reduced row-echelon form of this augmented matrix
[tex]\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right][/tex]
You need to follow these steps:
Divide row 1 by 2 [tex]\left(R_1=\frac{R_1}{2}\right)[/tex][tex]\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right][/tex]
Subtract row 1 from row 2 [tex]\left(R_2=R_2-R_1\right)[/tex][tex]\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right][/tex]
Subtract row 1 multiplied by 5 from row 3 [tex]\left(R_3=R_3-\left(5\right)R_1\right)[/tex][tex]\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right][/tex]
Subtract row 2 multiplied by 3 from row 1 [tex]\left(R_1=R_1-\left(3\right)R_2\right)[/tex][tex]\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right][/tex]
Subtract row 2 multiplied by 3 from row 3 [tex]\left(R_3=R_3-\left(3\right)R_2\right)[/tex][tex]\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right][/tex]
Multiply row 2 by 2 [tex]\left(R_2=\left(2\right)R_2\right)[/tex][tex]\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right][/tex]
Divide row 3 by −19 [tex]\left(R_3=\frac{R_3}{-19}\right)[/tex][tex]\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right][/tex]
Subtract row 3 multiplied by 16 from row 1 [tex]\left(R_1=R_1-\left(16\right)R_3\right)[/tex][tex]\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right][/tex]
Add row 3 multiplied by 6 to row 2 [tex]\left(R_2=R_2+\left(6\right)R_3\right)[/tex][tex]\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right][/tex]
Everyone in a group is being assigned a secret code of 3 characters. The first character must be a letter and the second and third are numbers which can not be the same. How many possible codes can be made? O A. 46 O B. 126 C. 2340 O D. 2600
Answer: C. 2340
Step-by-step explanation:
Hi!
The first character is a letter. There are 26 letters in the alphabet. For each letter you choose a two digit number, but you cannot repeat the digits. There are 100 (0 to 99) two digit numbers, and you have to discard 00, 11, 22, 33, 44, 55, 66, 77, 88, 99. Those are the 10 numbers with repeated digits.
So, for each letter, you have any of 90 possible numbers. The answer is then 26*90 = 2340
The amount of garbage, G, in tons per week, produced by a city with population p, measured in thousands of people, is given by G = f ( p ) The town of Tola has a population of 50,000 and produces 14 tons of garbage each week. Express this information in terms of the function f
Answer: [tex]G=f(50)=14[/tex]
Step-by-step explanation:
Given : The amount of garbage, G, in tons per week, produced by a city with population p, measured in thousands of people, is given by G = f(p).
Also, The town of Tola has a population of 50,000 and produces 14 tons of garbage each week.
Then, the expression in terms of the function G will be :-
[tex]G=f(50)=14[/tex]
(1/2) (10t) = 50,000
Answer: The value of t become 10000.
Step-by-step explanation:
Since we have given that
[tex]\dfrac{1}{2}\times 10t=50000[/tex]
We need to find the value of t from the above expression:
first we divide 10t by 2 to get 50000.
[tex]\dfrac{10t}{2}=50000\\\\5t=50000\\\\t=\dfrac{50000}{5}\\\\t=10000[/tex]
Hence, the value of t become 10000.
Find the inverse of 12 modulo 19
Answer:
8 is the modular inverse of 12 mod 19 since 12*8 mod 19 ≡ 1.
Step-by-step explanation:
We need to find the inverse of 12 modulo 19.
[tex]12^{-1}(\text{ mod 19})[/tex]
If a is an integer and m is modulo, then the modular multiplicative inverse of a modulo m is an integer b such that
[tex]a\times b\equiv 1(\text{ mod m})[/tex]
Substitute different values of b and check whether that remainder is 1 after modulo 19.
At b=1,
[tex]12\times 1\equiv 12(\text{ mod 19})[/tex]
At b=2,
[tex]12\times 2\equiv 5(\text{ mod 19})[/tex]
At b=3,
[tex]12\times 3\equiv 17(\text{ mod 19})[/tex]
At b=4,
[tex]12\times 4\equiv 10(\text{ mod 19})[/tex]
At b=5,
[tex]12\times 5\equiv 3(\text{ mod 19})[/tex]
At b=6,
[tex]12\times 6\equiv 15(\text{ mod 19})[/tex]
At b=7,
[tex]12\times 7\equiv 8(\text{ mod 19})[/tex]
At b=8,
[tex]12\times 8\equiv 1(\text{ mod 19})[/tex]
Therefore, 8 is the modular inverse of 12 mod 19 since 12*8 mod 19 ≡ 1.
The Social Security Administration increased the taxable wage base from $106,800 to $110,100. The 6.2% tax rate is unchanged. Joe Burns earned over $120,000 each of the past two years.
a.
What is the percent increase in the base?(Round your answer to the nearest hundredth percent.)
Percent increase
%
b.
What is Joe’s increase in Social Security tax for the new year?(Round your answerto the nearest cent.)
Increase in social security tax
$
Answer:
The Social Security Administration increased the taxable wage base from $106,800 to $110,100.
A:
The percent increase in the base =
[tex]\frac{110100-106800}{106800}\times100=3.09[/tex]%
B:
Previous year tax = [tex]0.062\times106800=6621.60[/tex] dollars
This year tax = [tex]0.062\times110100=6826.20[/tex] dollars
Increase in tax = [tex]6826.20-6621.60=204.60[/tex] dollars
Hence, Joe’s increase in Social Security tax for the new year is $204.60.
The taxable wage base increased by 3.09%. The additional amount that Joe will pay in Social Security tax due to this increase is $204.60.
Explanation:The percent increase in the base can be found by subtracting the old base from the new base, dividing the difference by the old base, and finally multiplying by 100 to convert to a percentage. So, the percent increase is: ((110,100 - 106,800) / 106,800 ) * 100 = 3.09%.
To calculate Joe's increase in Social Security tax, you need to determine the taxable increase, which is the difference between the new and old taxable wage bases, and then multiply this amount by the tax rate. For Joe, the taxable increase is $3,300 (110,100 - 106,800). Therefore, Joe's increase in Social Security tax is: 3,300 * 6.2% = $204.60.
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What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)?
Answer:
Step-by-step explanation:
Let's remember the equation of a line:
y = mx + b
m: slope (we know it's 3)
b: the y-intercept
So far, we have y = 3x + b, now we need to find b.
Replacing y and x for the given points (-3,-5):
-5 = 3*(-3) + b
-5 = -9 + b
b = -5 + 9
b = 4
The equation of the line that passes through the point (-3,-5) with a slope of 3 is y = 3x + 4
Answer:
y = 3x + 4
Step-by-step explanation:
A web page design firm has two designs for an online hardware store. To determine which is the more effective design, the firm uses one page when on a mobile platform and a second page when on a desktop. For each visit, the firm records the amount spent by the visitor and the amount of time visiting the site. Complete parts (a) through (c) below (a) What is the explanatory variable in this study? Is it qualitative or quantitative? O A. The explanatory variable is the amount spent by the visitor. This explanatory variable is quantitative. O B. The explanatory variable is the web page design. The explanatory variable is qualitative. ° C. The explanatory variable is the amount of time visiting the site. This explanatory variable is quantitative O D. The explanatory variable is the age group. This explanatory variable is qualitative. (b) What are the two response variables? For each response variable, state whether it is qualitative or quantitative. Select all that apply. □ A- One response variable is the amount spent by the visitor. This response variable is quantitative. B. One response variable is the web page design. This response variable is qualitative. C. One response variable is the age group. This response variable is qualitative D. One response variable is the amount of time visiting the site. This response variable is quantitative. (c) Explain how confounding might be an issue with this study. Choose the correct answer below d A. Since there are two response variables in this study, they may interact, causing the results to be misleading or incorrect. B. Since there is only one explanatory variable, and two response variables, the explanatory variable will not affect both response variables equally, resulting in misleading results O C. Since the designs are being tested with two different age groups, preferences depending on the age group may affect the response variables for those groups. O D. Since the variables are not all quantitative or all qualitative, they may interact, causing the results to be misleading or incorrect.
The explanatory variable is the web page design. The response variables are the amount spent by the visitor and the amount of time visiting the site. Confounding could be an issue if other factors are not accounted for.
Explanation:(a) The explanatory variable in this study is the web page design. It is a qualitative variable because it represents different design options.
(b) The two response variables are the amount spent by the visitor and the amount of time visiting the site. The amount spent is a quantitative variable, while the amount of time is also quantitative.
(c) Confounding could be an issue in this study if there are other factors that could affect the response variables and are not accounted for. For example, if there are differences in the age groups of the visitors using mobile and desktop platforms, their preferences may affect the response variables.
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4. Mary is reviewing her algebra quiz. She has determined that one of her solutions is incorrect. Which one is it? A. 2x + 5 (x-1) 9, X 2 B. p - 3(p-5) 10, p 2.5 C. 4 y +3 y 28, y 4 E. t - 2t - 3t 32, t 8
Answer:
E. t - 2t - 3t =32, t=8
Step-by-step explanation:
A. 2x + 5 (x-1)= 9, X= 2 it's ok because
[tex]2x+5(x-1)=9\\ 2x+5x-5=9\\ 7x=14\\ x=2[/tex]
B. p - 3(p-5)= 10, p= 2.5 it's ok as well because
[tex]p-3(p-5)=10\\ p-3p+15=10\\ -2p=-5\\ p=\frac{-5}{-2} \\ p=2.5[/tex]
C. 4 y +3 y=28, y=4 also it's ok because
[tex]4y+3y=28\\ 7y=28\\ y=\frac{28}{7} \\ y=4[/tex]
E. t - 2t - 3t =32, t=8 it's not ok because
[tex]t-2t-3t=32\\-4t=32\\t=\frac{32}{-4} \\t=-8[/tex]
a (-) is missing!
Final answer:
After reviewing the solutions provided by Mary, we can conclude that the incorrect solution is Option E, where the solution should be t = -8 instead of the provided answer t = 8.
Explanation:
Mary is reviewing her algebra quiz and needs to determine which one of her solutions is incorrect. We must go through each option and verify the results given.
Option A
2x + 5(x - 1) = 9, solution X = 2.
First, expand the equation: 2x + 5x - 5 = 9.
Then combine like terms: 7x - 5 = 9.
Next, add 5 to both sides: 7x = 14.
Finally, divide by 7: x = 2.
This solution is correct.
Option B
p - 3(p - 5) = 10, solution p = 2.5.
First, expand the equation: p - 3p + 15 = 10.
Then combine like terms: -2p + 15 = 10.
Next, subtract 15 from both sides: -2p = -5.
Finally, divide by -2: p = 2.5.
This solution is correct.
Option C
4y + 3y = 28, solution y = 4.
First, combine like terms: 7y = 28.
Then, divide by 7: y = 4.
This solution is correct.
Option E
t - 2t - 3t = 32, solution t = 8.
First, combine like terms: -4t = 32.
Next, divide by -4: t = -8.
This solution is incorrect because the given answer is t = 8. The correct answer should be t = -8.
Team A and Team B play each other in a best out of 7 tournament. So the team that wins 4 games first wins the tournament. How many possible sequences are there for team A to win? Examples: AAAA, AAABA, AABAA, etc.
Answer: There 64 possible sequences in which team A wins
Step-by-step explanation:
Hi!
The sequences in which team A wins, are the ones with at least 4 A's.
Sequences with 4, 5, 6 or 7 A's. To calculate how many of each type exist, we use the formula of combinations. If you select K objects from a set of N objects, there are C(N, K) possibilities, give by the formula:
[tex]C(N,K) = \frac{N!}{K! (N-K)!)}[/tex]
Then the total M number of sequences in which team A wins is:
[tex]M = C(7,7) + C(7,6) + C(7,5) + C(7,4) = 1 + 7 +21+35 = 64[/tex]
If there are 2.54 centimeters in 1 inch, how many centimeters are in 500 inches
Answer: There are 196.85 cm in 500 inches.
Step-by-step explanation:
Since we have given that
1 inch = 2.54 centimeters
We need to find the number of centimeters are in 500 inches.
Since 1 inch = 2.54 centimeters
1 inch = [tex]\dfrac{1}{2.54}\ cm[/tex]
500 inches = [tex]\dfrac{500}{2.54}=196.85\ cm[/tex]
Hence, There are 196.85 cm in 500 inches.
To convert 500 inches to centimeters, use the conversion factor 2.54 cm = 1 inch. Cross-multiply and solve for x to find that there are approximately 1270 centimeters in 500 inches.
Explanation:To convert inches to centimeters, we use the conversion factor 2.54 cm = 1 inch. In this case, we have 500 inches, so we can set up the following proportion:
We can cross-multiply and solve for x:
Calculating x, we find that there are approximately 1270 centimeters in 500 inches.
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A nurse infuses a dose in 50 minutes. She needs to infuse the dose at a 20% faster rate. How much time does she need ?
Answer: She would need 40 minutes to infuse a dose.
Step-by-step explanation:
Since we have given that
Number of minutes a nurse takes to infuse a dose = 50 minutes
Rate faster by 20%
So, if the initial rate = 100%
After increasing the rate,
rate becomes 100%-20% = 80%
So, Number of minutes taken to infuse a dose now is given by
[tex]\dfrac{80}{100}\times 50\\\\=0.8\times 50\\\\=40\ minutes[/tex]
Hence, she would need 40 minutes to infuse a dose.
ANSWER PLEASE ITS AN EMERGENCY. COULD SOMEONE ALSO HELP WITH OTHER QUESTIONS TOO?ILL GIVE BRAINLIEST
Angle G and Angle K are complementary angles.
The measure of Angle K is 5 times the measure of Angle G.
Find the measures of Angle G and Angle K.
Measure of Angle G =
degrees.
Measure of Angle K =
degrees.
Answer:
angle k:75
angle g:15
Step-by-step explanation: