why did the author include this selection
Infectious agents, such as viruses, bacteria, and fungi, can all
Answer: cause disease.
Explanation: Although not all viruses, bacteria, and fungi are bad, there is at least one kind of each of these infectious agents that can cause disease.
Anxiety,panic ,poor coordination ,nausea , increased body temperature and delusions are common side effects of
Stimulants
Depressants
Hallucinogens
hallucinogens i just finished this test
WILL MARK BRAINLIEST
What type of energy is present in water at the top of a hydroelectric dam?
Wildfires
Human activity
Seed dispersal by wind
Insects, bees, and wasps
Which energy is not drive from is not drive from descend from the sun, and the options are optional, and nuclear energy option B. In wind energy, option C by biomass energy option G. Ocean wave energy. And from the option A B c. D, correct option is of that is nuclear technology, So the correct option is of China for problem seven.
Edwin Hubble discovered in 1929 that the distances to far away galaxies were generally proportional to their redshifts.
This was seen as strong evidence in favor of....
A) relic radiation
B) the radio spectrum
C) the Big Bang theory
D) steady-state theories
The First Great Awakening in America began in the 1730s and lasted until the 1760s. Which group would have been most influenced by the First Great Awakening?
ANSWER:
The "First Great Awakening in America" began in the 1730s and lasted until the 1760s. American Revolutionists would have been "most influenced" by the "First Great Awakening".
EXPLANATION:
First Great Awakening in America during 1730's pulled way rituals and hierarchy that made Christianity delicate. American revolutionists like Jonathan Edward and George Whitefield made speeches that resulted in vast audience to opt for religious conversion during First Great Awakening.When people can better understand and consider the ideas and perspectives of others, they are better equipped to participate meaningfully in our society.
What are three forms of radiation that come from the sun
The difference between two numbers 2.when each number is rounded to the nearest hundred , the difference between them is 100. What Numbers Could these be?
The numbers could be (149, 151) or (249, 251), differing by 2, and rounding to 100 and 200,respectively.
Let's denote the two numbers as [tex]\( A \) and \( B \).[/tex]
1. The difference between the two numbers is 2:
[tex]\[ |A - B| = 2 \][/tex]
2. When each number is rounded to the nearest hundred, the difference between them is 100.
Step-by-Step Solution:
**Step 1: Understanding the rounding impact**
When a number is rounded to the nearest hundred, it falls within the range of the midpoint between two hundreds. For example:
- Any number from 50 to 149 rounds to 100.
- Any number from 150 to 249 rounds to 200.
- And so on.
**Step 2: Establishing conditions based on rounding**
We know the rounded difference is 100, so the rounded values of ( A ) and ( B ) must differ by 100. Let's denote the rounded values as [tex]\( A_r \)[/tex] and [tex]\( B_r \):[/tex]
[tex]\[|A_r - B_r| = 100\][/tex]
**Step 3: Analyzing the ranges for [tex]\( A \) and \( B \)[/tex] **
Given the possible ranges for rounding:
• If A rounds to Ar and B rounds to Br, the actual values A and B must be within +-50 of their
respective rounded values.
Potential Cases:
[tex]1. \( A_r = 100 \) and \( B_r = 200 \):\\ - For \( A \): \( 50 \leq A < 150 \)\\ - For \( B \): \( 150 \leq B < 250 \)[/tex]
[tex]2. \( A_r = 200 \) and \( B_r = 300 \):\\ - For \( A \): \( 150 \leq A < 250 \)\\ - For \( B \): \( 250 \leq B < 350 \)[/tex]
Step 4: Solving for exact numbers**
Since the difference between ( A ) and ( B ) is 2, we test within these ranges:
Case 1: ( A ) in [50, 150) and ( B ) in [150, 250)
- Assume ( A ) is at the upper end of its range and ( B ) just 2 units more.
[tex]\[ B = A + 2 \][/tex]
- Since ( B ) must round to 200 and \( A \) to 100:
[tex]\[ 50 \leq A < 150 \quad \text{and} \quad 150 \leq B < 250 \][/tex]
Check a specific example:
- Let ( A = 149 ) (rounds to 100)
- Then ( B = 149 + 2 = 151 ) (rounds to 200)
Thus, ( A = 149 ) and ( B = 151 ) is one solution.
Case 2: ( A ) in [150, 250) and ( B ) in [250, 350)
- Assume ( A) is at the upper end of its range and ( B \) just 2 units more.
B = A + 2
- Since ( B ) must round to 300 and ( A ) to 200:
[tex]\[ 150 \leq A < 250 \quad \text{and} \quad 250 \leq B < 350 \][/tex]
Check a specific example:
• Let A 249 (rounds to 200)
• Then B 249 4- 2 251 (rounds to 300)
Thus, A = 249 and B= 251 is another solution.
Conclusion
The pairs (A, B) that satisfy the conditions are:
• (149, 151)
• (249,251)
These pairs of numbers differ by 2 and, when rounded to the nearest hundred, differ by 100.