The ability of small insects to walk on water is due to surface tension, which results from cohesive forces among water molecules. This tension creates a thin 'skin' at the water's surface that can support the weight of light objects, such as insects.
The ability of small insects to walk on the surface of still water can be best explained by the phenomenon of surface tension. Surface tension is created due to the cohesive forces between water molecules at the liquid-air interface. This cohesion results in a thin 'skin' forming at the surface, which can support the weight of small insects like water striders. These insects distribute their weight over their long legs, ensuring that the force they exert is less than the surface tension holding the water molecules together, allowing them to effectively 'walk' on water.
An example of this can be seen when a paper clip or a thin razor blade is carefully placed on the surface of water without sinking, demonstrating the strength of surface tension.
How many electrons are in an electrically neutral atom of boron? A) 3 B) 5 C) 6 D) 8
Answer:
B. five electrons
Explanation:
When the metallic body of a car is moved into a painting chamber, a mist of electrically neutral paint is sprayed around the car. when the car is given a sudden electric charge, the mist is attracted to it, and the car is quickly and uniformly painted. what does the phenomenon of polarization have to do with this?
Polarization is the phenomenon that allows electrically neutral paint particles to be attracted to a charged car's surface during the painting process.
Explanation:The phenomenon of polarization is related to the process of car painting in a few ways. When the metallic body of the car is moved into the painting chamber, the paint is sprayed as a mist of electrically neutral particles. However, when the car is given a sudden electric charge, the mist of paint particles becomes polarized, meaning they acquire positive or negative charges.
The electric charge on the car creates an electric field around it, and the polarized paint particles are attracted to the opposite charge on the car. This attraction causes the paint particles to quickly and uniformly coat the car's surface.
Overall, polarization allows the electrically neutral paint mist to be attracted to the charged car, resulting in efficient and uniform painting.
It takes a person one half hour to run 6 kilometers at a constant rate along a straight-line path. What is the velocity of the person?
a boat travels in a straight path that is 25 . west of north which describes the values of the west and north components of the boat's displacement ?
Both components are positive numbers.
Both components are negative numbers.
The west component is a negative number, and the north component is a positive number.
The west component is a positive number, and the north component is a negative number.
Answer:
C on edge
Explanation:
Suppose a heat source generates heat at a rate of 87.0 w (1 w = 1 j/s). how much entropy does this produce per hour in the surroundings at 27.4 °c? assume the heat transfer is reversible.
During one year, eight moose in a population died and two moose were born. Three moose immigrated from another population and five emigrated to find mates.
What was the population growth during this year?
-8 hope it helps i just took the test
Eddie the eagle, british olympic ski jumper, is attempting his most mediocre jump yet. after leaving the end of the ski ramp, he lands downhill at a point that is displaced 72.1 m horizontally from the edge of the ramp. his velocity just before landing is 33.0 m/s and points in a direction 30.0$^\circ$ below the horizontal. neglect any effects due to air resistance or lift. what was the magnitude of eddie's initial velocity as he left the ramp?
Eddie's initial velocity as he left the ramp is calculated as 28.61 m/s
Explanation:This physics problem involves two-dimensional motion or projectile motion. We can solve it by using the principles of conservation of energy and kinematics. The final horizontal velocity (vxf) can be calculated using the final velocity (v) and the angle (θ) below the horizontal through the formula vxf = v * cos(θ), which in this case gives us 33 * cos(30°) = 28.6 m/s. Since there's no horizontal acceleration involved in Eddie's jump, the initial horizontal velocity (vxi) equals the final horizontal velocity (vxf), hence vxi = 28.6 m/s.
Now, we can use the horizontal displacement (Δx) and vxi to calculate the total time of flight using the formula Δx = vxi * t, so the time of flight (t) = Δx / vxi = 72.1 m / 28.6 m/s = 2.52 s. Finally, using the time of flight, final vertical velocity (vyf), and the acceleration due to gravity (g), we can find the initial vertical velocity (vyi) using the formula vyf = vyi + g * t. Substituting the given values, we get - 33 * sin(30) = vyi - 9.8 * 2.52, which gives us vyi = -1.1 m/s.
As the last step, we find the magnitude of the initial velocity from the resultant of its vertical and horizontal components using the Pythagorean theorem: vi = sqrt[(vxi^2) + (vyi^2)], which comes out to be sqrt[(28.6^2) + (-1.1^2)] = 28.61 m/s.
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Isabel’s first car had a manual stick shift. After many years of driving an automatic car, she needs to use her sister’s car, which also has a stick shift. Isabel takes a few minutes to get used to shifting gears. Which memory system is she using to recall this information?
Final answer:
Isabel is using her implicit procedural memory, a form of long-term memory responsible for automatic skills, to recall how to use a manual stick shift after primarily driving an automatic car.
Explanation:
Isabel is utilizing her implicit procedural memory to recall how to shift gears in a stick shift car after having driven an automatic vehicle for many years. Procedural memory is a form of long-term memory that enables people to perform tasks without conscious awareness of the learned skills, such as riding a bike, typing on a keyboard, or driving. In this case, Isabel's ability to revert to using a manual stick shift despite the extended use of an automatic car illustrates the durability and automaticity of procedural memory.
You are in a hot air balloon (yes, another balloon problem!) rising from the ground at a constant velocity of 2.00 m/s upward. to celebrate the takeoff, you open a bottle of champagne, expelling the cork with a horizontal velocity of 6.60 m/s relative to the balloon. when opened, the bottle is 5.90 m above the ground. what is the initial speed of the cork, as seen by your friend on the ground?
The surface gravity on jupiter is about three times as much as the surface gravity on earth. this means
What is a property of a transparent object? A. Almost all of the light rays that reach it are scattered. B. Almost all of the light rays that reach it are absorbed. C. Almost all of the light rays that reach it are reflected. D. Almost all of the light rays that reach it pass through it.
What is the frequency of a wave that has a wave speed of 20 m/s and a wavelength of 0.20 m
The steel pipe is filled with concrete and subjected to a compressive force of 80 kn. determine the average normal stress in the concrete and the steel due to this loading. the pipe has an outer diameter of 100 mm and an inner diameter of 50 mm. est = 200 gpa, ec = 30 gpa.
The stress on the steel is 3.88mPa and the stress on the concrete is 1.94mPa
Data;
Compressive force = 80knouter diameter = 100m = 0.1minner diameter = 50mm = 0.05mSummation of Forces[tex]\sum f_y = 0 = Pst + Pc - \delta 0 = 0...equation(i)\\\delta st = \delta c\\[/tex]
We can solve for Pst and Pc
[tex]\frac{Pst * L}{\pi/4 * (0.1^2 - 0.05^2) * 200*10^9} = \frac{Pc * L}{\pi/4 * (0.05)^2 * 30*10^9}\\ 0.075Pst = 1.5Pc\\Pst = 20Pc...equation(ii)\\[/tex]
From equation(i) and (ii)
[tex]Pst + Pc + 0 = 80\\Pst = 20Pc\\20Pc + Pc = 80\\21Pc = 80\\Pc = \frac{80}{21} \\Pc = 3.81kN[/tex]
Let's solve for Pst
[tex]Pst = 20Pc\\Pst = 3.81 * 20\\Pst = 76.2kN[/tex]
Normal StressThe normal stress between the concrete and steel can be calculated as
The stress on the steel[tex]\sigma st = \frac{Pst}{A} \\\sigma st = \frac{76.2*10^3}{\frac{\pi }{4} * (0.1^2 * 0.05^2}\\\sigma st = 3.88mPa[/tex]
The stress on the concrete[tex]\sigma c=\frac{3.81*10^3}{\frac{\pi }{4}* (0.05)^2 } \\\sigma c = 1.94mPa[/tex]
The stress on the steel is 3.88mPa and the stress on the concrete is 1.94mPa
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The position of a 55 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. determine the velocity at t=0.40s. express your answer in meters per second to two significant figures.
The velocity of the oscillating particle at [tex]t=0.4\,{\text{s}}[/tex] is [tex]\boxed{1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] or [tex]\boxed{1.5\times{{10}^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .
Further Explanation:
The position of the oscillating mass is given by:
[tex]x\left(t\right)=\left({2.0\,{\text{cm}}}\right)\cos\left({10t}\right)[/tex]
Here, [tex]x\left(t\right)[/tex] is the position of the particle at time [tex]t[/tex] during the oscillation.
The velocity of the oscillating particle is defined as the rate of change of the position of the body. Thus, it can be expressed as the first derivative of the position of the body while it is oscillating.
The velocity of the particle can be expressed as:
[tex]\boxed{v=\frac{{dx\left(t\right)}}{{dt}}}[/tex]
Substitute the equation of the position in above expression.
[tex]\begin{aligned}v&=\frac{d}{{dt}}\left({\left({2.0\,{\text{cm}}}\right)\cos\left({10t}\right)}\right)\\&=-\left({2.0\,{\text{cm}}}\right)\sin\left({10t}\right)\\\end{aligned}[/tex]
Now, we are to obtain the velocity of the oscillating particle at time [tex]t=0.4\,{\text{s}}[/tex] . So, substitute [tex]0.4[/tex] for [tex]t[/tex] in above equation of velocity.
[tex]\begin{aligned}v&=-\left({2.0\,{\text{cm}}}\right)\sin\left({10\times0.4\,{\text{rad}}}\right)\\&=-2.0\times\left({-0.75}\right)\\&=1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]
The velocity of the oscillating particle in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] while it oscillates is given as:
[tex]\begin{aligned}v&=1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\left({\frac{{1\,{\text{m}}}}{{100\,{\text{cm}}}}}\right)\\&=1.5\times{10^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]
Thus, the velocity of the oscillating particle at [tex]t=0.4\,{\text{s}}[/tex] is [tex]\boxed{1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] or [tex]\boxed{1.5\times{{10}^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .
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Answer Details:
Grade: College
Subject: Physics
Chapter: Oscillation
Keywords:
Position, 55g particle9t, oscillating mass, velocity at, t=0.40 s, position of particle, rate of change of position, x(t)=(2.0 cm)cos(10t).
Why is it important to practice a presentation?
A. To use large type and images
B. To plan the wardrobe
C. To point out the use of each medium
D. To ensure the smooth flow of the presentation
Answer: D. To ensure the smooth flow of the presentation.
Explanation:
A presentation is a narratative explanation of a topic. A practice of presentation is required before presenting it in the front of the audience. It will help in maintaining the desired flow and sequence of the content which an author want to present in a systematic way. It will help in reducing faults and breaks in the conversation.
A rock of mass m is thrown horizontally off a building from a height h. the speed of the rock as it leaves the thrower's hand at the edge of the building is v0, as shown. m h v0 m what is the kinetic energy of the rock just before it hits the ground? 1. kf = 1 2 m v2 0 2. kf = 1 2 m v2 0 − m g h 3. kf = 1 2 m v2 0 + m g h 4. kf = m g h − 1 2 m v2 0 5. kf = m g h
[tex]K_f=mgh+\frac{1}{2}mv_o^2[/tex]
Given information:
A rock of mass m is thrown horizontally off a building from a height h
As, the total energy of rock at the time of leaving the thrower's hand is the sum of gravitational potential energy and the initial kinetic energy.
[tex]E=U_i+K_i\\E=mgh+(1/2)mv_0^2[/tex]
As, the height from the ground decreases, the potential energy before hitting the ground is zero and the total final energy is just kinetic energy:
[tex]E=K_f[/tex]
As, the law of conservation of energy states the total final energy must be equal to the initial energy.
Hence, the final kinetic energy will be
[tex]K_f=mgh+\frac{1}{2}mv_o^2[/tex]
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You are holding a block of wood with dimensions 3 cm 6 cm 9 cm on the palm of your hand. Which side must be touching your hand for you to experience the greatest force?
The size of the gravitational force depends on the mass of the objects involved. The greater the mass, the greater the gravitational force.
The normal force of weight will not differ for different placements but the force of pressure applied to the surface of your hand is per unit area.
Since, Pressure is equal to the ratio of Force per unit area.
Thus, the side with the smallest area i.e. 3 cm x 6 cm will exert the most pressure on your hand.
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A car with mass m traveling at speed v has kinetic energy k. what is the kinetic energy of a second car that has the same mass m and twice the speed of the first car? k 1.4 k 2 k 4 k
Answer:
the kinetic energy of the second car would be D. 4k
Explanation:
took the test
Myth: An organism's kingdom only describes physical characteristics.
Fact:
Evidence:
The kingdom of an organism does not only describe physical characteristics. It is evident by that plant and animal kingdom are classified on the basis of photosynthetic ability.
Kingdom:
In classification kingdom is the highest in the hierarchy. A kingdom includes the organism of similar classes.
For Example: plant and animal kingdom
Plant Kingdom:
It includes the multicellular organisms who have cell wall and produce glucose using Photosynthesis. Such as Bryophytes, Pteridophytes, and gymnosperms.Animal Kingdom:
This includes the the organisms with cell membrane only. They rely o others for their nutrition. Such as mammals and fishesTherefore, the fact is that the organism's kingdom does not only describes physical characteristics.
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A gas in a cylinder with a moveable piston has an initial volume of 89.2 ml . if we heat the gas from 35 âc to 153 âc, what is its final volume (in ml)? express the volume to three significant figures and include the appropriate units.
A small air plane's takeoff speed is 30 m/s. With constant acceleration it takes 150 m of runway to become airbourne. How long does it take to become airbourne?
A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance that the spaceship is from the earth?
Question 25 options:
The gravitational pull of the earth is constant and therefore the gravitational pull on would not change.
As the distance from the earth decreases, the gravitational pull on the spaceship would decrease.
There is no gravity on the moon and therefore only the earth will exert gravitational force on the spaceship.
As the distance from the earth increases, the gravitational pull on the spaceship would decrease.
The distance from the sun to the Earth is 1.5 x 1011 m. How long does it take for light from the sun to reach the earth? Give your answer in seconds
it actually takes 500 seconds if you do the math properly but when converted to min 500 sec is 8 min and 20 sec
If we do the arithmetic correctly, it truly takes 500 seconds, but when we translate it to minutes, it takes 8 minutes and 20 seconds.
What is Time?Time is the ongoing progression of existence and things that happen in what seems to be an irrevocable order from the past, present, and forward into the future.
The four identical dimensions that make up the cosmos are put together to form a single, four-dimensional manifold that is properly called spacetime. Any physical item that is positioned at many points in time has a unique temporal component for each of those periods.
Time is calculated by dividing the distance which is travelled by the speed
For above given example,
the speed of the light is expressed as [tex]3*10^8 m/s[/tex]
Distance of earth from the sun is [tex]1.5 * 10^1^1[/tex] meters.
Thus, Time= Distance of the Earth/ Speed of the light
Time= [tex]1.5* 10^1^1 m[/tex]/ [tex]3*10^8m/s[/tex]
Time = [tex]0.5*10^1^1* 10^-^8\\0.5*10^3\\0.5*1000\\[/tex]
Time= 500seconds which is equals to 8 minutes and 20 seconds.
Thus, it takes 500 seconds for light to travel from the sun to the earth.
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Resistors in parallel together contain less resistance than resistors in series together. Create an analogy to explain this phenomena and post it here.
Resistors in parallel act like a multi-lane highway which eases traffic, reducing the total electrical resistance compared to individual resistors. This is unlike resistors in series, which increase the total resistance like a single congested road.
When resistors are connected in parallel, the total resistance is lower than any individual resistor in the network. This phenomenon can be understood with a simple analogy: imagine a highway with multiple lanes. If only one lane is open, the traffic (current) has only one path to travel, leading to congestion (high resistance). Now, if all lanes (multiple resistors in parallel) are open, traffic can distribute across them, easing congestion (lowering resistance). The more lanes there are, the less the traffic is slowed down, analogous to the way adding resistors in parallel decreases the total resistance. In contrast, if you had a single long road (resistors in series), the traffic would have to follow one after another, which leads to increased congestion or resistance.
Furthermore, the formula for calculating total resistance for parallel resistors demonstrates that the total resistance (Rp) is always less than the smallest resistor's resistance in the network. By providing multiple paths for the electric current, the circuit allows for more current to flow without increasing resistance, different from a series setup where the total resistance is simply the sum of all resistor values.
In a uranium fission reaction the uranium splits into 2 smaller atoms an energy. Where did the energy come from?
Mutations are avoided during replication because DNA polymerase is able to _____?
A.) repair itself
B.) repair the DNA
C.) encode a message
D.) add more codes
Meanwhile DNA construction, maximum DNA polymerases "review their performance," getting the bulk of mis-paired bases in a method called proofreading. Shortly after DNA synthesis, any left mis-paired bases can be identified and substituted in a procedure called mismatch repair. If DNA gets destroyed, it can be fixed by different mechanisms, including chemical repeal, excision restoration, and double-stranded break repair.
Give three ways you experience normal force throughout your day.
Answer: Static friction, sliding fiction, fluid fiction, and rolling friction
Explanation: static friction (friction that acts upon unmoving objects), sliding fiction (friction that occurs between two objects sliding past each other), fluid friction (is the force that resists motion when fluid is involved)and the last one is rolling friction (the force between a rolling object and a surface).
what is the gravitational potential energy of a 150 kg object suspended 5m above the Earth's surface
The gravitational potential energy of the object is 7350 J.
Explanation:The gravitational potential energy of an object suspended above the Earth's surface can be calculated using the equation:
PE = mgh
where PE is the gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height above the Earth's surface.
In this case, the mass of the object is 150 kg and the height is 5 m. Plugging these values into the equation:
PE = 150 kg * 9.8 m/s² * 5 m = 7350 J
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A ball is thrown at a 60.0° angle above the horizontal across level ground. it is thrown from a height of 2.00 m above the ground with a speed of 23.7 m/s and experiences no appreciable air resistance. the time the ball remains in the air before striking the ground is closest to
The time the ball remains in the air before striking the ground is closest to 4.20 seconds.
To find the time the ball remains in the air before striking the ground, we can use the equations of motion. Since the ball is thrown at an angle above the horizontal, we'll need to analyze both the horizontal and vertical components of its motion separately.
Given:
- Initial velocity [tex](\(v_0\))[/tex] = 23.7 m/s
- Launch angle[tex](\(\theta\))[/tex] = 60.0°
- Initial height (h) = 2.00 m
First, we'll find the horizontal and vertical components of the initial velocity:
Horizontal component: [tex]\(v_{0x} = v_0 \cdot \cos(\theta)\)[/tex]
Vertical component: [tex]\(v_{0y} = v_0 \cdot \sin(\theta)\)[/tex]
[tex]\[v_{0x} = 23.7 \, \text{m/s} \cdot \cos(60.0^\circ)\]\\v_{0x} \approx 23.7 \, \text{m/s} \cdot \frac{1}{2}\]\\v_{0x} \approx 11.85 \, \text{m/s}\]\\v_{0y} = 23.7 \, \text{m/s} \cdot \sin(60.0^\circ)\]\\v_{0y} \approx 23.7 \, \text{m/s} \cdot \frac{\sqrt{3}}{2}\]\\v_{0y} \approx 20.57 \, \text{m/s}\][/tex]
Now, let's find the time it takes for the ball to reach the maximum height using the vertical motion equation:
[tex]\[v_y = v_{0y} - g \cdot t\][/tex]
At the maximum height, the vertical velocity[tex](\(v_y\))[/tex] becomes zero. So:
[tex]\[0 = v_{0y} - g \cdot t_{\text{max}}\][/tex]
Solving for [tex]\(t_{\text{max}}\):[/tex]
[tex]\[t_{\text{max}} = \frac{v_{0y}}{g}\]\\t_{\text{max}} = \frac{20.57 \, \text{m/s}}{9.8 \, \text{m/s}^2}\]\\t_{\text{max}} \approx 2.10 \, \text{s}\][/tex]
Now, let's find the total time the ball is in the air. We know that the time to reach maximum height and the time to fall from maximum height to the ground are equal due to symmetry (neglecting air resistance). Therefore, the total time in the air is twice the time to reach maximum height:
Total time in the air [tex]\( = 2 \times t_{\text{max}}\)[/tex]
[tex]\[ \text{Total time in the air} \approx 2 \times 2.10 \, \text{s} \]\\ \text{Total time in the air} \approx 4.20 \, \text{s} \][/tex]
So, the time the ball remains in the air before striking the ground is closest to 4.20 seconds.
A particular battery lasts 14.5 hours. what percentile is its lifetime on?
The battery with a lifetime of 14.5 hours is at the 40.13th percentile in terms of battery lifetimes, assuming a normal distribution with a mean of 15 hours and a standard deviation of 2 hours.
Certainly, to find the percentile of the battery's lifetime, we'll use the Z-score formula and then refer to the standard normal distribution table. Let's assume a normal distribution with a mean (μ) of 15 hours and a standard deviation (σ) of 2 hours. The battery's lifetime is X = 14.5 hours.
The Z-score is calculated as:
Z = (X - μ) / σ
Substitute the values:
Z = (14.5 - 15) / 2 = -0.25
Now, we need to find the percentile associated with this Z-score. Looking up -0.25 in the standard normal distribution table, we find that the corresponding percentile is approximately 40.13%.
The question probable may be:
What is the percentile of a battery's lifetime with a mean (μ) of 15 hours and a standard deviation (σ) of 2 hours when its actual lifetime is X = 14.5 hours? Use the Z-score formula and the standard normal distribution table to determine the percentile associated with the Z-score of -0.25.
This battery's lifetime falls in the 22.66th percentile.
The lifetime of a battery is normally distributed with a mean (μ) of 16 hours and a standard deviation (σ) of 2 hours. To find what percentile a particular battery lasting 14.5 hours falls into, we need to calculate its Z-score.
The Z-score is given by:
[tex]Z = \frac{X- \mu}{\sigma}[/tex]
where X is the observed value.
The Z-score of the given battery is:
Z = [tex]\frac{14.5 - 16}{2}[/tex] = [tex]\frac{-1.5}{2}[/tex] = - 0.75
According to the Z-table, a Z-score of - 0.75 corresponds to a cumulative probability of approximately 0.2266.
This means that 14.5 hours is at the 22.66th percentile.
Thus, the lifetime of a particular battery lasting 14.5 hours falls at the 22.66th percentile of the lifetime distribution.
The complete question is:
The lifetime of a battery in a certain application is normally distributed with mean μ = 16 hours and standard deviation σ = 2 hours.
Activities:
What is the probability that a battery will last more than 19 hours?Find the 10th percentile of the lifetimes.A particular battery lasts 14.5 hours. What percentile is its lifetime on?What is the probability that the lifetime of a battery is between 14.5 and 17 hours?