Which of these is NOT a cause of the heat inside Earth?
A.) Volcanoes
B.) radioactive decay
C.) gravitational contraction
D.) bombardment by asteroids

Answer: Electromagnetic waves are not like sound waves because they do not need molecules to travel. This means that electromagnetic waves can travel through air, solid objects and even space. This is how astronauts on spacewalks use radios to communicate. Radio waves are a type of electromagnetic wave.

Explanation:

Answer:

Electromagnetic waves can travel in vacuums.

Explanation:

Scientists use different types of telescopes to find and study supernovas. Some telescopes use visible light to observe the supernova's colors, while others study the X-rays and gamma rays dispersed in the explosion. These electromagnetic waves are used because electromagnetic waves can travel in vacuums, like space, whereas sounds waves cannot. In addition, the electromagnetic spectrum travels at the speed of light (much faster than sound waves), can be absorbed, and are not created by physical vibrations.

Answer:

See explanation below.

Explanation:

You just need to show that the ratio of all elements within the compound is always the same. The easiest way to do this is to divide everything by the lowest mass in each group:

[tex]34.92 C : 5.87H : 46.56O \rightarrow \frac{34.92}{5.87} C : \frac{5.87}{5.87}H : \frac{46.56}{5.87}O \rightarrow 6C : 1H : 8O\\\\0.4471 C : 0.0751H : 0.5962O \rightarrow \frac{0.4471}{0.0751} C : \frac{0.0751}{0.0751}H : \frac{0.5962}{0.0751}O \rightarrow 6C : 1H : 8O\\[/tex]

**Please keep in mind that this ratio is DIFFERENT from the stoichiometric ratio of the elements within the compound and does not tell you the empirical formula. The ratio just says there are 6g of C for every 1g of H and 8g of O. It does NOT mean the empirical formula is C6HO8.

C₃₃H₂₄N₆O₆ is the molecular formula of the large molecule of tryptophan (which is a derivative of tryptophan molecule)

Explanation:

For the large tryptophan molecule we have been given the empirical formula C₁₁H₁₂N₂O₂. The molecular formula will be (C₁₁H₁₂N₂O₂)ₐ which have the molar mass of 612 g/mol.

Now we calculate the molar mass of (C₁₁H₁₂N₂O₂)ₐ:

molar mass of (C₁₁H₁₂N₂O₂)ₐ = (12 × 11 + 1 × 12 + 14 × 2 + 16 × 2) × a

molar mass of (C₁₁H₁₂N₂O₂)ₐ = 204a g/mol

Now to find "a" we do the following calculus:

204 × a = 612

a = 612 /204

a = 3

The molecular formula of large molecule of tryptophan will be:

(C₁₁H₁₂N₂O₂)₃ = C₃₃H₂₄N₆O₆

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532 mg of hemoglobin

Explanation:

The concentration of hemoglobin in the blood is 15.2 g/dL. It we transform the g in mg and the dL in mL we have the value for the concentration to be 15200 mg / 100 mL.

Knowing the concentration we devise the following reasoning:

if there are         15200 mg of hemoglobin in 100 mL of blood

then there are            X mg of hemoglobin in 3.5 mL of blood

X = (15200 × 3.5) / 100 = 532 mg of hemoglobin

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Taking into account the definition of mass per volume concentration and the change of units, 532 milligrams of hemoglobin are in  every 3.50 mL of the patient's blood.

You know that the concentration of hemoglobin in the blood is 15.2 [tex]\frac{g}{dL}[/tex]. So, in first place, you need to change units: the g in mg and the dL in mL.

You know that 1 dL= 100 mL and 1 g= 1000 mg. Then:

[tex]\frac{15.2 g}{dL}=\frac{15.2*1000 mg}{100 mL} =152 \frac{mg}{mL}[/tex]

Then you can apply the following rule of three: if 1 mL contains 152 mg of hemoglobin, 3.5 mL contains how much mass of hemoglobin?

[tex]mass of hemoglobin =\frac{3.5 mLx 152 mg}{1 mL}[/tex]

mass of hemoglobin= 532 mg

Finally, 532 milligrams of hemoglobin are in  every 3.50 mL of the patient's blood.

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Answer:n creating a table from a dataset that does not have a column and a row, the most important thing that you have to ... The answer to your question is C. column headers.

Explanation:

Answer:

column 1: they are solids that form crystals.

column 2: Are liquid solutions.

Explanation:

Crystals are solids, some of them can have viscosity like glass.

Liquid solutions, are formed by some ions dissolved in water, so they can have a definite volume and could be a liquid that is nonviscous because they are dissolved in water.

Hope this info is useful.

Answer:

The frog has 4 toes on each foot in the front, and 5 toes on each foot in the back.

Explanation:

Answer:

3.0x1p^24 molecules H2O=____5____ mol H2O​

Explanation:

We une the number of Avogadro:

6, 02 x 10 ^23 molecules------- 1 mol

3, 01 x 10 ^24 molecules----x=

x= (3, 01 x 10 ^24 moleculesx 1 mol)/6, 02 x 10 ^23 molecules)

x= 5 mol

The element with the electronic configuration 1s²2s²2p⁶3s²3p⁶4s²3d¹104p⁶5s²4d¹105p⁵ is Iodine (I).

The electronic configuration provided, 1s²2s²2p⁶3s²3p⁶4s²3d¹104p⁶5s²4d¹105p⁵, corresponds to the element Iodine (I). Iodine is a member of the halogen group, situated in group 17 of the periodic table. This halogen is commonly known for its use in antiseptics and as a necessary component of the human diet.

Group 7A (or VIIA) of the periodic table are the halogens: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). The name "halogen" means "salt former", derived from the Greek words halo- ("salt") and -gen ("formation").

Final answer:

The electron configuration corresponds to the element iodine (I), which is located in group 17 of the periodic table and has an atomic number of 53.

Explanation:

The electron configuration given in the question corresponds to an element's distribution of electrons across different orbitals. The full configuration is:

1s²2s²2p⁶3s²3p⁶4s²3d¹4p⁶5s²4d¹5p⁵

When assessing this electronic arrangement, we look at the last energy levels or shells being filled, which are 5s, 4d, and 5p. By looking at the periodic table, we can match this configuration to an element.

Considering that the 5p sublevel contains 5 electrons, we look at the p-block of the periodic table, in the fifth period (row). Counting in from the left of the p-block (taking into account the s-block and d-block orbitals which come before in the period), we find that the element iodine (I) matches this electronic configuration.

Therefore, the last electron enters the 5p subshell, and with 5 electrons in 5p subshell, confirms that the element is iodine (I).

Iodine is located in group 17, which comprises the halogens, and it has an atomic number of 53. Thus, the name of the element with the given electron configuration is iodine.

Answer:

The solubility of a substance can be increased by increasing the amount of solvent in a solution.

Explanation:

Two ways by which the rate of dissolving for substance can be increased.

1 By increasing the temperature of the solution: Increase in temperature will in turn increase the entropy or disorder or randomness of the solute molecules in a solution thus increasing the rate of dissolving the substance in that solution.

2 By increasing the volume of the solution : increase in the volume of the solution by adding more solvent can also increase the dissolving rate of a specific substance in a solution.

Answer:

space between particles

Explanation:

Properties of gases:

Molecule of gases randomly move everywhere and occupy all available space.

Gases don't have definite volume and shape and take the shape and volume of container in which it present.

Their densities are very low as compared to the liquid and solids.

Gas molecules are at long distance from each other therefore by applying pressure gases can be compressed.

The very weak inter molecular forces are present between gas molecules.

Properties of Liquid:

Liquid have definite volume but don,t have definite shape.

Their densities are high as compared to the gases but low as compared to the solids.

In liquid, molecules are close to each other and have greater inter molecular forces as compared to the gas molecules.

Properties of solids:

Solids have definite volume and shape.

In solids molecules are tightly pack and very close to each other.

Their melting and boiling point are every high.

The densities of solids are also very high as compared to the liquid and gas.

There are very strong inter molecular forces are present between solid molecules.

Answer:

Formaldehyde is highly soluble in water.

Explanation:

Formaldehyde is the simplest of the aldehydes (R−CHO) it is an organic compound which occurs naturally with the formula H−CHO. . The IUPAC name of formaldehyde is methanal.

Formaldehyde  at room temperature is a colorless gas and the liquid is invisible or like white-water. Formaldehyde has an irritating and very pungent like odour. Formaldehyde is very soluble in water.

Now according to Henry's constant law (3 × 10-5 kPa·m3/mol) Formaldehyde will be very unlikely to volatilize from water.and hence, Formaldehyde is considered to be highly soluble in water.

Answer:

Atom is the smallest particle of matter.

Elements are made up of same atoms.

Atom consist of electron, proton and neutron.

Explanation:

Atom was first discovered by John Dalton.

word "Atom" came from Greek word, that means something that could not split. he explained that atom is indivisible particle.

In the end of 18th century J.J. Thomson put forward a new concept of atom. he said that atom have negative charged particles called electrons but overall atom is neutral.

In 1909 Rutherford with his students discovered positive charged particles and nucleus and said that it is in the center of atom.

He explain a model of atom and said that electrons revolve around a hard core in the center called nucleus.

In 1913 Niels Bohr  explains the atomic spectra and put forward the concept of shells and sub-shells.

So overall Structure of an Atom is

Atom has a specific atomic mass and atomic number

Atomic number = number of protons or electron

Atomic mass = number of protons +  number of neutrons in nucleus.

Answer:

A.) A substance that oxidizes another substance

Explanation:

An oxidizing agent always oxidize another substance by either accept electron, removing electronegative elements or adding electropositive elements to the substance.

Answer:

The answer for this question is option D

"Nuclei " are called as building blocks of the universe.

Option: D

Explanation:

Smallest unit of this universe was considered to be an atom but “Rutherford 's Nuclear Model of Atom” in 1911 discovered nucleus which is small and heavy positively charged body present in center of atom. An atom also have extra nuclear part which is space around nucleus, where electrons (negative charged) are distributed. Nucleus is contained with protons (positive charged) and neutrons (neutral) which are definitely very smaller than nuclei but as a building unit or block of the universe nuclei is considered.  

To find the Cl- concentration of the dilute solution, calculate the moles of MgCl2 in the original solution, use stoichiometry to determine the moles of Cl-, and divide by the volume to find its concentration.

To determine the concentration of Cl- in the dilute solution, we can use the concept of mole ratios. First, we calculate the number of moles of MgCl2 in the original solution by multiplying the volume of the solution by its concentration. Then, we use the stoichiometry of the equation to determine the number of moles of Cl-. Finally, we divide the number of moles of Cl- by the volume of the dilute solution to find its concentration.

Moles of MgCl2 = volume of solution (L) x concentration of MgCl2 (mol/L)

Moles of Cl- = Moles of MgCl2 x 2 (from the balanced equation)

Concentration of Cl- = Moles of Cl- / volume of dilute solution (L)

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Answer:

Number of moles = 1.97 mol

Explanation:

Given data;

Number of moles of I₂ = ?

Mass = 500.0 g

Solution:

Number of moles = mass/ molar mass

Molar mass of  I₂ = 253.8 g/mol

Number of moles = 500 g / 253.8 g/mol

Number of moles = 1.97 mol

Final answer:

Chemistry tests like blood tests for plasma analysis generally use tubes containing K2EDTA, followed by centrifuging. Urinalysis, on the other hand, uses disposable test strips without prior sample preparation.

Explanation:

Chemistry tests that are not stat (immediate) are typically drawn in various types of tubes depending on the tests to be carried out. For tests that require plasma, blood samples are usually collected into tubes containing K2EDTA and then centrifuged to obtain plasma.

The plasma samples may sometimes be quenched with methanol before analysis. This is different from urinalysis, where physicians often use disposable test strips to measure the amounts of various substances in a patient's urine, without the need for any preparation before analysis. The diverse techniques and sample preparations in clinical chemistry underscore the importance of tailoring collection methods to specific tests, allowing for accurate and comprehensive diagnostic assessments in medical laboratories.

Answer:

The total energy required is 121.56 kJ

Explanation:

The energy required to heat a m = 40g sample of ice is calculated using the following information:

The specific heat of ice =[tex]s_{ice}[/tex] = 2.108 J/g-K

The specific heat of water =[tex]s_{water}[/tex] = 4.187 J/g-K

The specific heat of steam = [tex]s_{steam}[/tex] = 1.996 J/g-K

The latent heat of fusion for ice = L = 336 kJ/kg

The latent heat of vaporisation = l = 2260 kJ/kg

The latent heat of fusion is the amount of energy required to change one kg of ice into water without a change in temperature.

Firstly, we find the energy required to change the temperature of 40 g of ice from -10°C to 0°C.

[tex]Energy\:required=ms_{ice}\Delta T\\ \Delta T\:is\:the\:change\:in\:temperature\\Energy\:required=40\times2.108\times(0-(-10))=40\times2.108\times10=843.2J[/tex]

Then, the energy required to convert 40g of ice at 0°C to water at 0°C.

[tex]Energy\:required=mL=40\times336=13440J[/tex]

Then, the energy required to convert water at 0°C to water at 100°C.

[tex]Energy\:required=ms_{water}\Delta T=40\times4.187\times(100-0)=40\times4.187\times100=16748J[/tex]

The energy required to convert water at 100°C to steam at 100°C.

[tex]Energy\:required=ml=40\times2260=90400J\\[/tex]

The energy required to convert steam at 100°C to steam at 105°C.

[tex]Energy\:required=ms_{steam}\Delta T=40\times1.996\times(105-100)=399.2J[/tex]

Total Energy required = 843.2 + 13440 + 16748 + 90400 + 399.2 = 121560.4J = 121.56 kJ

Answer:

Points of acceleration:

1. When female bear goes quickly

2. After becoming tired, when she becomes slow

3. When she changes direction from east to north

4.When she slows down when she reaches the river bed

5. When she turns around

6.When she increases speed to travel southwest to return home

7. When she comes to a stop at home

Explanation:

1. When she is going quickly she is increasing her velocity thus positively accelerating

2. When she becomes slow, she is having negative acceleration.

3. When there is a change in direction of velocity there is an acceleration.

4. Again negative acceleration when she comes to a stop at the river bed

5. Turning around to the southwest direction requires acceleration

6. To increase the velocity to reach home, positive acceleration

7. To decrease the velocity to stop upon reaching home, negative acceleration

Answer:

a: 1st paragraph from the left side indicates Newton's first law.

b:, 2nd paragraph from the left side indicates Newton's third law.

c: 1st paragraph from right side indicates Newton's first law.

d: 2nd paragraph from right side indicates Newton's second law.

Explanation:

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

Final answer:

To calculate the volume of 40g of sugar, divide the mass by the substance's density, which is not provided in the question. An example calculation with a hypothetical density of 1.59 g/cm³ gives a volume of approximately 25.16 cm³.

Explanation:

The volume of a substance can be calculated using its mass and density. To calculate the volume of 40g of sugar, we need to know the density of sugar. Unfortunately, the density is not provided in the question. However, we can use the method of conversion once the density is known. If the density of sugar was, for example, 1.59 g/cm3 (which is hypothetical in this case), the volume would be calculated as follows:

Volume = Mass / Density

Volume = 40g / 1.59 g/cm³

Volume ≈ 25.16 cm³

Ensure to substitute the correct density value of sugar in the same units to get the accurate volume.

Taking into account the definition of calorimetry, the specific heat of the unknown substance is 0.96 [tex]\frac{calories}{gC}[/tex].

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where

In this case, you know:

Replacing in the expression to calculate heat exchanges:

-12 calories= c× 2.50 g× (-5 C)

Solving:

-12 calories÷ [2.50 g× (-5 C)]= c

0.96 [tex]\frac{calories}{gC}[/tex]= c

Finally, the specific heat of the unknown substance is 0.96 [tex]\frac{calories}{gC}[/tex].

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The specific heat of the substance is 0.96 cal/g°C, calculated by rearranging the formula q = mcΔT and substituting the known values for heat transferred, mass, and change in temperature.

The formula for calculating the specific heat (c) of a substance is:

q = mcΔT

where:

To find the specific heat, rearrange the formula to solve for c:

c = q / (mΔT)

In this example, the given values are:

Plugging in these values gives:

c = -12 cal / (2.50 g x -5°C)

c = 12 cal / (12.5 g°C)

c = 0.96 cal/g°C

The specific heat of the substance is therefore 0.96 cal/g°C.

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Answer:

CBrClF₂  

Explanation:

You list the halogens in alphabetical order and  use a subscript 2 to show that there are two F atoms.

The formula is CBrClF₂.

The name of the compound is bromochlorodifluoromethane.

Answer:

1. Robert Bunsen hence being called the bunsen burner. 2. William Kirchhoff

Explanation:

Answer:

Theoretical yield of Ca₃(PO₄)₂ = 19.67 g

Percent yield of Ca₃(PO₄)₂ = 11.4 %

Explanation:

Data given

Potassium Phosphate  K₃PO₄  = 30.00 g

calcium nitrate Ca(NO₃)₂ of 0.25 M  = 100.0 mL

Reaction given:

        2K₃PO₄(s) + 3Ca(NO₃)₂(aq) --------->  Ca₃(PO₄)₂(s) + 6KNO₃(aq)

Solution :

Part A :

To find the theoretical yield of Calcium phosphate

Look at the reaction :

             2K₃PO₄(s) + 3Ca(NO₃)₂(aq) ---------> Ca₃(PO₄)₂(s) + 6KNO₃(aq)

               2 mol          3 mol                               1 mol                6mol

 So,

2 mol of  2K₃PO₄ give 1 mole of Ca₃(PO₄)₂

if we represent mole in mass then

Molar Mass of K₃PO₄ =  3(39) + 31 + 4(16)

Molar Mass of K₃PO₄ =  212 g/mol

and

Molar mass of Ca₃(PO₄)₂  =  [ 3(40) + 2((31) + 4(16))]

Molar mass of Ca₃(PO₄)₂  =  [ 120 + 62 + 96] = 278 g/mol

Molar mass of Ca₃(PO₄)₂ = 278 g/mol

Now, if we write it in grams

  2K₃PO₄(s)    +      3Ca(NO₃)₂(aq) ---------> Ca₃(PO₄)₂(s)    +     6KNO₃(aq)

   2 mol                    3 mol                               1 mol                      6mol

  2 mol ( 212 g/mol)                                         1 mol (278 g/mol)

   424 g                                                               278 g

So from the above information we come to know that

    424 g of K₃PO₄ gives 278 g of Ca₃(PO₄)₂

then 30 g will give how much Ca₃(PO₄)₂ Calcium phosphate

Apply unity formula

    424 g of K₃PO₄ ≅ 278 g of Ca₃(PO₄)₂

       30 g of K₃PO₄ ≅ x g of Ca₃(PO₄)₂

By doing cross multiplication and rearranging the above values

      x g of Ca₃(PO₄)₂ = 278 g x  30 g / 424 g

      x g of Ca₃(PO₄)₂ = 19.67 g

So,

30 g of K₃PO₄ will give 19.67 g Ca₃(PO₄)₂ theoretically.

Theoretical yield of Ca₃(PO₄)₂ = 19.67 g

Now,

Part B :

To find percent yield of Ca₃(PO₄)₂

Solution

Data given:

       Actual yield of Ca₃(PO₄)₂ = 2.25 g

       Theoretical yield of Ca₃(PO₄)₂ = 19.67 g

Formula to be used:

         Percentage yield = Actual yield/ theoretical yield x 100 %

Put values in Above formula

       Percent yield = 2.25 g / 19.67 g x 100 %

       Percent yield =  0.1144 / 100 %

      Percent yield = 11.4 %

So,

Percent yield of Ca₃(PO₄)₂ = 11.4 %

Answer:

The charges repel each other

Explanation:

Elements of Group 1 and  group 2  in the periodic table contain elements so reactive that they are  never found in the free state

Explanation:

The metals in group 1 of  periodic table consisting of 'alkali metals' which include lithium, potassium, sodium, rubidium, Francium and caesium. They are highly reactive because they have low ionisation energy and larger radius. The group 2 metals consist of 'alkaline earth metals' which include calcium, strontium, barium, beryllium, radium and magnesium.  These alkaline earth metal have +2 oxidation number, hence are highly reactive.

These both group metals are mostly reactive and so are never found in a free state. When they are exposed to air they would immediately react with oxygen. Hence, are stored in oils to avoid oxidation.

Answer:

the process is melting

Explanation:

got it right on edge

Answer:

B) K⁺, Sr²⁺ , O²⁻

Explanation:

Potassium is present in group one. It is alkali metal and have one valance electron.Potassium need to lose its one valance electron and form cation to get complete octet.

That's why it shows K⁺.

Sr is alkaline earth metal. It is present in group two. It has two valance electrons. Strontium needed to lose its two valance electrons and get stable electronic configuration.

When it loses its two valance electrons it shows cation with charge of +2.

Sr²⁺

Oxygen is present in group 16. It has sex valance electrons. It needed two more electrons to complete the octet. That's why oxygen gain two electron and form anion with a charge of -2.

O²⁻