Which one of the following anti-hypertensive drugs may cause postural hypotension?
a. Propanolol
b. Hydrochlorothiazide
c. Losartan

Answer:

The most frequently damaged tissues are the skin and mucosa, which causes the body to activate a repair process consisting of the following steps:

1- Inflammation: This process involves the cells of the immune system, white blood cells, antibodies, lymphatics. All these cells work together, once the vessels expand, they act producing an inflammation process where coinside these cells eliminating necrotic tissue, bleeding and coagulation is formed.

2- Organization: In this step, the clot begins to form in granulation tissue that is a tissue composed of several elements and that goes from the central part of the lesion to the periphery. In this stage new capillaries grow, fibrolastic tissues are formed that produce growth factors and collagen fibers.

3- Regeneration: A superficial epithelial tissue begins to grow under the granulation tissue. As the underlying fibrous tissue matures and becomes fibrous until it finally resembles the adjacent skin. Finally forming a fully regenerated epithelium.

Answer:

Formalin.

Explanation:

Formalin is a mixture if formaldehyde and water. 37% formalin is commonly used in the market. The formula of formaldehyde is HCHO.

Formalin acts as a strong disinfectant and can cause tissue hardening. Hence, Formalin is used to preserve the biological specimen and a specimen can be sent for permanent section.

Thus, the correct answer is option (C).

Answer:

A) Epithelial

Explanation:

There are different kind of epithelial tissues, and depending on its clasification it could have different functions. For example the connective tissue has simple squamous epithelium. The digestive tract has a columnar epithelium. So the epithelial tissue has different functions: protection, regulation a secretion and those functions could help or improve the function of the different systems.

The incorrect relationship between a tissue and its general function is a) Epithelial : digestion. Epithelial tissue's primary functions include protection, absorption, secretion, and sensation detection, not digestion.

The relationship between a tissue and its general function that is not correct is: a) Epithelial : digestion. Epithelial tissue primarily covers and lines the body's surfaces, internal cavities, and passageways, and it forms certain glands. It has key roles in protection, absorption, secretion, and sensation detection but not directly in digestion. Connective tissue is known for providing support to the body and holding tissues together. Muscle tissue is involved in body movement through its ability to contract. Finally, nervous tissue controls the body by transmitting electrical signals through nerve impulses, allowing communication between different body regions. Looking back at the question's options, the function of digestion is not a primary function of epithelial tissue; therefore, option a) is the incorrect relationship between a tissue and its function.

Answer: C) Broad ligament

Explanation:

A ligament can be define as a fibrous connective tissue which links bone to bone.

The ligaments present in the female reproductive tract are the structures which supports the internal female genitalia covered by the bony pelvis.

A broad ligament is a ligament which is associated with the female reproductive organs.

It exhibit a layer of peritoneum membrane, that is associated with ovaries, fallopian tubes and uterus.

The broad ligament is divides into three regions:

1. Mesometrium: It covers the uterus. In the broad ligament it is the largest subsection.

2. Mesovarium: It originate from the posterior surface of the broad ligament and connects to the hilum of the ovary. It does not cover the entire surface of the ovary.

3. Mesosalpinx: It originates from the mesovarium superiorly and encloses the fallopian tubes.

Answer: C) Resistance to air flow increases due to the increase in cross-sectional diameter

Explanation:

As, resistance to air flow increased due to the increased in cross sectional diameter is not true because resistance offer by an individual alveolus is more than that it offered by the medium size bronchi but the number of alveoli is much more as compared. In fact that the maximum resistance to airflow is encountered in the medium sized bronchi.

The statement C is incorrect. Resistance to airflow actually decreases in the respiratory tract from the bronchi to the alveoli because the total cross-sectional area increases due to the vast number of alveoli. It's the combined area of these many airways that is critical, not the size of each individual one.

The student's question is related to the structural changes that happen in the respiratory tract as one progresses from the medium bronchi to the alveoli. Therefore, the correct statement that is not true of the respiratory tract from medium bronchi to the alveoli is c. Resistance to airflow does not increase due to the increase in cross-sectional diameter. In fact, the resistance decreases because the total cross section area of the bronchi and bronchioles increases as you move down the respiratory tract.

This is due to the fact that, as we move from the bronchi to the alveoli, the total number of airways increases drastically, making the combined cross-sectional area of the respiratory tract larger. Therefore, despite each individual bronchiole being smaller, the total cross-sectional area is much larger, leading to decreased resistance.

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Answer:

The immune response to infection, of whatever kind, is vital for human survival. At its core lies the cells, and enzymes, as well as chemical components, that will activate these responses, the innate, and the acquired immune response.

Although still under lots of study, and science finding new things in this complex system, the order of the steps in which the system is activated, roughly, is this:

1. C. You cut yourself and bacteria enter the wound.

2. F. A dendrite near the cut phagocytizes some bacteria and uses MHC proteins to present exogenous antigens from the destroyed bacteria on its surface

3. A. The antigen-presenting macrophage and some of the bacteria, enter the lymph and float down a lymph vessel to the lymph node, where T cells are awaiting to recognize it and act.

4. E. Helper T cells at the lymph node use their T cell receptors to bind the antigens on the surface of the dendrite and bacteria. This triggers the helper T cells to reproduce, differentiate and release cytokines and other elements that increase inflamation and activate other immune cells.

5. G. Also, B cells at the lymph node use their B cell receptors to bind to the antigens on the surface of the bacteria and dendrite. These B cells also bind to the cytokines being produced. This triggers the B cells to reproduce and start making antibodies. They also trigger cytotoxic T cells CD4 and CD8 differentiation and activation.

6. B. All the elements produced flow through the blood, activating other immune responses and migrate them towards the site of infection. Because of the inflammation, and thanks to the cytokines and protoinflammatory elements, more cells are activated and they can penetrate the inflammed tissue.

7. D. Through the actions of the antibodies, cytokines, chemicals, and different actions of the cells, phagocytes, and cytotoxic T cells are finally able to destroy the invading bacteria and kill all infected tissue as well, leaving behin scar tissue at the site of the wound, and both B and T cells activate their memory capacity, so that if a new infection by that microorganism happens again, the response will be much faster and efficient.

This is a very broad organization of the immune response.

The adaptive immune response begins with bacterial entry and progresses through antigen presentation, T cell activation, B cell activation, antibody production, and immune defense against pathogens, culminating in infection control.

The adaptive immune response involves a series of events that occur in a specific sequence to combat infections. Here's the order in which these events take place:

Cut and Bacterial Entry (c): The immune response begins when you sustain a cut, and bacteria enter the wound.

Phagocytosis and Antigen Presentation (f): Dendritic cells near the cut site phagocytize some of the bacteria. They then present the antigens from the ingested bacteria on their surface using major histocompatibility complex (MHC) proteins.

Lymphatic Drainage (a): The antigen-presenting dendritic cells and some bacteria enter the lymphatic system and travel through lymph vessels to nearby lymph nodes.

Activation of Helper T Cells (e): Within the lymph node, helper T cells recognize the antigens presented by dendritic cells. This recognition triggers helper T cells to reproduce and release cytokines.

Activation of B Cells (g): B cells in the lymph node encounter both antigens on the dendritic cell's surface and the cytokines released by helper T cells. This dual stimulation prompts B cells to proliferate and produce antibodies.

Activation of Cytotoxic T Cells (g): Cytotoxic T cells are also stimulated by the cytokines released by helper T cells. These activated cytotoxic T cells start to replicate.

Antibody-Mediated Response (d): Antibodies produced by B cells are released into the bloodstream. These antibodies bind to and neutralize, opsonize, or agglutinate the bacteria at the site of infection. This enhances the ability of phagocytic cells from the innate immune system to eliminate the bacteria. Additionally, cytotoxic T cells kill infected body cells.

Inflammation and Recruitment (b): Inflammatory responses triggered by the innate immune system allow immune cells, including those activated by the adaptive response (cytotoxic T cells), to enter the infected tissue and combat the infection more effectively.

In summary, the adaptive immune response is a highly orchestrated process involving antigen presentation, activation of helper T cells, B cell activation and antibody production, cytotoxic T cell activation, and the subsequent immune defense against pathogens. These events work in concert to eliminate infections and promote the body's recovery.

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Answer:

The AV valves will not close properly.

Explanation:

Papillary muscles are located on the heart ventricles. These muscles are attached with the cusps of the tricuspid valve. They cover almost 10% mass of the heart.

Papillary muscles helps in the contraction of heart. If these muscles fail to contract, the atrioventricular valves will remain open and does not close properly. This will disturb the functioning of heart.

Thus, the correct answer is option (b)

Answer:

(A). heparinized saline.

Explanation:

Femoral popliteal surgery can be defined as medical procedure, which is used for the treatment of femoral artery disease. The chemical hemostatic agent that is used during femoral popliteal surgery is heparinized saline.

Heparin is an anticoagulant, which blocks blood clotting. Like other surgeries, popliteal bypass surgery also increases chances of formation of blood clots. Hence, heparinized saline is used for prevention of occlusion or clotting during femoral bypass.

Thus, the correct answer is option (A).

Answer:

Billroth II

Explanation:

Duodenal ulcer is a peptic ulcer that occurs at the upper portion of the small intestine of an individual. Symptoms associated with peptic ulcer are nausea, stomach pain and heartburn.

Billroth II is an medical surgery in which the jejunum is connected to the upper curvature of stomach. This surgery is used to treat the duodenal ulcers of the patient.

Thus, the correct answer is option (A).

Answer:

E78.5

Explanation:

Hyperlipidemia is the conditions having abnormally elevated levels of  lipids or lipoproteins in blood. Hyperlipidemias is of two types: primary and secondary.

Primary hyperlipidemia is due to genetic causes usually, while the secondary hyperlipidemia may arises due to other causes like diabetes.

E78.5 is a billable ICD-10-CM code which is be used to indicate the diagnosis for the reimbursement purposes.

On October 1, 2018, 2019 edition of ICD-10-CM E78.5 became effective.

The ICD-10 code for unspecified hyperlipidemia is E78.5.

Explanation of Hyperlipidemia

Hyperlipidemia refers to elevated levels of lipids (fats) in the blood, which can include cholesterol and triglycerides. Understanding hyperlipidemia is essential because it is a significant risk factor for cardiovascular diseases and can lead to complications such as heart attacks and strokes.

Types of Hyperlipidemia

Hyperlipidemias can be classified based on the specific lipoproteins affected. Here are some notable types:

Type I - Hyperlipoproteinemia: Characterized by elevated chylomicrons due to a deficiency of lipoprotein lipase. It is very rare.

Type II - Familial Hypercholesterolemia: Can be further divided into:

Type III - Dysbetalipoproteinemia: This involves high levels of intermediate-density lipoproteins (IDL).

Type IV - Hypertriglyceridemia: Characterized by high triglyceride levels.

Importance of Diagnosis

Accurate coding (like E78.5 for unspecified hyperlipidemia) is important for medical records and insurance claims. It helps healthcare professionals identify patients at risk and guide treatment strategies, such as lifestyle changes or medications that might be necessary to lower lipid levels.

If you have any further questions regarding hyperlipidemia or its implications, feel free to ask!

Answer:

Coracoid process.

Explanation:

The coracoid process serves to stabilize the shoulder joint. It also serves as the origin and insertion of muscles and ligaments, including the following:

-coracoacromial ligament

-coracohumeral ligament

-coracobrachialis ligament

-Short head of biceps brachii muscle

Answer:

The answer is D: Decreased fluid in the alveoli and interstitial spaces of the lungs.

Explanation:

Pulmonary edema is the accumulation of fluid in the lungs, which produces an alteration of respiratory function that can be manifested among others by:

- Tachypnea

- Panting

- Chest pain

- Coldness and paleness.

- Bluish lips .

- Tachycardia.

- Anxiety and restlessness.

Answer:

The answer is A: ventricles are in systole

Explanation:

When the ventricular contraction begins for the outflow of blood to the great vessels, an increase in intraventricular pressure occurs, when it exceeds the pressure of the aorta on the left side and the pulmonary on the right, it results in the opening of the semilunar valves giving rise to the ejection of blood from the heart until the ventricles begin to relax. subsequently the valves are closed and another period of relaxation begins.

The event that does not occur when the semilunar valves are open is that the ventricles are in diastole; they are actually in systole at this time. And in the exercise question, the false statement is that blood travels through the bicuspid valve to the left atrium; instead, it flows from the left atrium to the left ventricle.

Among the options given, when the semilunar valves are open:

Therefore, the event that does not occur when the semilunar valves are open is option (d), ventricles are in diastole.

Concerning the exercise question, the false statement is option (b). Blood actually travels through the bicuspid valve (also known as the mitral valve) from the left atrium to the left ventricle, not the other way around.

Answer:

The correct answer is opsonin.

Explanation:

When an antibody or molecule that promotes or increases phagocytosis by marking dead cells for recycling or marking an antigen is called Opsonin. Opsonization is a mechanism in which apoptotic cells or microbes are chemically altered to have a strong drawing ability to the surface receptors of the cell on phagocytes and NK cells.

Opsonization also aids phagocytosis by signal cascades from receptors present on the cell surface. Cell membranes have a negative charge that prevents two cells to come closer but after binding opsonin, it boosts the kinetics of the phagocytosis by interacting with cell receptors That overcome the negative charge of the cell membranes.

Thus, the correct answer is opsonin.

Answer:

At the base of the epithelial tissues is a layer of extracellular tissue that is known as the basement membrane. Whose main function is sustain and variable thickness.

Its layers are:

Basal lamina = composed in turn, by the lucida lamina and the dense lamina. Adipocytes, muscle cells and nerves are often found at the level of this lamina.

Reticular lamina = composed of denser and reticular fibers as well as a large number of proteins. It is also known as external lamina.

6. The radius is distal

Answer: 1. external, 2. paralel and distal, 3. proximal, 4. posterior, 5. anterior, 6. distal, 7. proximal.

Explanation:

1. The radius is paralel to the ulna in its external portion. It means it is located far from the body in an anatomical position, where the hands are with the palms facing forward.

2. The ribs are located parallel to the clavicle and descending towards the lower part of the body. Because they are moving away from the clavicle they are said to be distal to it.

3. The femur is proximal to the tibia, because it is located in the nearest portion of the "center of the body". It is attached to the hip. The tibia is attached to the femur, so tibia is distal to it.

4. The vertebral column is posterior to the sternum. Posterior, refers to something that is in the back or at the bottom in anatomical terminology. The vertebral column is in the back of the sternum.

5. The clavicle is anterior to the scapula. Anterior, refers to something that is in the front or at the top. The clavicle is in the front of the body and the scapula is on the back.

6. The radius is distal to the humerus. Distal, refers to "distance". It refers to sites that are located far from a specific area, almost always, the center of the body. In this case, the humerus is attached to the body first forming part of the joint of the shoulder; the radius is far from the shoulder, or the center of the body, so, it is located distal to the humerus.

7. The sternum is proximal to the ribs. Proximal, means closer to the center (trunk of the body) or the point of attachment to the body. The ribs are attached to it.

The radius is external to the ulna.

The ribs are parallel and distal to the clavicle.

The femur is  proximal to the tibia.

The vertebral column is posterior to the sternum.

The clavicle is anterior to the scapula.

The radius is distal to the humerus.

The sternum is proximal to the ribs.

Bones are hard, composed of calcium. They protect the organs of the body.

Radius and ulna are the bones of the hand.

Ribs present in the thoracic cavity protect lungs and heart.

Femur and tibia are bones of the leg.

The clavicle is the collar bone present under the neck.

Thus, the correct options are 1. External, 2. Parallel and distal, 3. Proximal, 4. Posterior, 5. Anterior, 6. Distal, 7. Proximal.

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In an enzyme-catalyzed reaction, substrates bind in the enzyme's active site and enzymes are not consumed by the reaction. The shape of the enzyme undergoes slight changes during the reaction, but products do not bind in the active site. Instead, they are released once the reaction is complete.

When an enzyme catalyzes a reaction, substrates indeed bind in the active site (a). This is because the active site is a unique part of the enzyme that has a specific shape and chemistry for binding substrates and catalyzing their conversion to products. However, products do not typically bind in the active site (b), they are usually released once the reaction is complete. In terms of the enzyme's shape (c), it is generally thought to be flexible and undergoes a slight change during the catalytic cycle, this is known as the "induced fit" model. Finally, the enzyme is not consumed in the reaction (d). Although it participates in the reaction, it does not permanently change or consumed, meaning that it can catalyze the same reaction many times over.

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In enzyme-catalyzed reactions, substrates bind in the active site, the enzyme's shape can change, and the enzyme is not consumed by the reaction.

When an enzyme catalyzes a reaction, the substrate(s) indeed bind in the active site (option a). This is because the active site of an enzyme is the specific region where the substrate interacts and where the catalysis of the reaction occurs. Option b is incorrect since products typically do not bind in the active site – they are released once the reaction is complete. As for option c, this is also incorrect because the shape of the enzyme can slightly change in a process known as induced fit to aid in catalysis. Lastly, option d is incorrect because, in general, the enzyme is not consumed by the reaction. Instead, it can be used repeatedly to catalyze the same reaction with other substrate molecules.

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Answer:

The correct answer will be option E- an action potential in the post synaptic neuron.

Explanation:

The excitatory postsynaptic potential or EPSP is the change in the membrane potential or voltage due to the opening of the sodium voltage-gated channels.

The opening of the Na⁺ voltage-gated channels leads to the influx of the Na⁺ ions inside the cells which causes the depolarization of the postsynaptic cells. This depolarization leads to the generation of the action potential in the cell which can be transmitted further.

Thus, option E is the correct option.

Answer:

ADH is produced by the hypothalamus in the brain and stored in the posterior pituitary gland at the base of the brain. ADH is normally released by the pituitary in response to sensors that detect an increase in blood osmolality (number of dissolved particles in the blood) or decrease in blood volume.

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ADH is produced with the aid of the hypothalamus in the mind and stored in the posterior pituitary gland at the base of the mind. ADH is typically launched with the aid of the pituitary in response to sensors that come across a boom in blood osmolality (number of dissolved particles inside the blood) or lower in blood extent.

A hormone that allows blood vessels to constrict and allows the kidneys to manipulate the quantity of water and salt inside the frame. This enables the manipulation of blood strain and the quantity of urine this is made.

A decrease in blood volume or low blood stress, which takes place throughout dehydration or a hemorrhage, is detected by way of sensors (baroreceptors) inside the coronary heart and big blood vessels. those stimulate anti-diuretic hormone release.

it is a hormone made by using the hypothalamus within the mind and saved inside the posterior pituitary gland. It tells your kidneys how plenty water to conserve. ADH constantly regulates and balances the quantity of water in your blood. Higher water attention will increase the extent and pressure of your blood.

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Answer:

The answer is D: Stratified layering

Explanation:

The transitional epithelium is characterized by presenting more capacity to change both pressure and volume by changing its appearance; For example, their more superficial cells become flat if the duct is full or they can become cubic if the duct is empty. It is composed of three layers of main cells (superficial, middle and basal) that allow each of them to carry a specific function.

Answer:

The answer is C: Q-T interval

Explanation:

The measurement of the Q-T interval shows the time in which the ventricular myocardium takes to depolarize during a cardiac cycle, of ventricular filling and emptying, if this time is prolonged the heart enters cardiac arrhythmia.

Answer:

The hypodermis is the last layer of the skin, it belongs to the integumentary system, it is also known as subcutaneous tissue. It consists mainly of loose connective tissue and stored fat. The following structures are found in the hypodermis:

-sweat glands

-Lymphatic vessels

-Surface blood vessels

-Cutaneous nerves

The hypodermis constitutes the bulk of the body fat deposit and its thickness varies depending on the nutritional status of each person

Explanation:

Answer:

Stylohyoid muscle.

Explanation:

Stylohyoid muscle is in the shape of a slender muscle that lies superiorly and posteriorly to the diagastric muscle. This muscle is innervated by the facial nerve.

Stylohyoid muscle is originated by the styloid process and inserted in the temporal bone of the organism. This muscle is inserted just superior to the hyoid muscle.

Thus, the answer is stylohyoid muscle.

Answer:

Any of the healthcare professions, physician, nurse, or any other, are difficult enough just when taking into account schooling. When a person decides to go into these medical fields, whichever it may be, without enthusiasm, the amount of studying and preparation alone, will overwhelm them.

But once in the field, once working, a medical professional, of any field, faces nothing more and nothing less, than having the safety and integrity of human beings in their lives, from conception, to their natural death. That fact can become even more overwhelming for a professional, and without enthusiasm, this effect will come much faster, and have dire consequences.

So, enthusiasm helps a medical professional advance on the job, by providing the necessary motivation to face any and all obstacles, regardless of which they may be, and focus on improving skills, because the professional wishes, thanks to motivation, to grow professionally, and be better professionally. That´s how enthusiasm will help a medical professional advance on the job.

Answer:

A, stirrups

Explanation:

Patient positioning is not an easy task but very important while preparing for surgery.  A prone position is one when the patient lies facing the ground. The patient is usually turned into the prone position from the supine position ( the patient lies facing the ceiling).

The thighs and knees of the patient are cradled in a boot-type stirrups. This is used to make the patient completely unmovable during the surgery. The knees should also be padded to avoid any discomfort for the patient.  

Answer:

Nonrheumatic mitral (valve) insufficiency

I34.0 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.

Explanation:

ICD-10 code for mitral valve regurgitation: I05.8

In the International Classification of Diseases, 10th Revision (ICD-10), the code I05.8 is used to represent mitral valve regurgitation. ICD-10 codes are alphanumeric codes that are used to classify and categorize medical conditions, diseases, and other health-related issues for the purpose of medical billing, coding, and statistical analysis. The code I05.8 specifically falls under the category of "Other rheumatic heart diseases," and it is used to identify cases of mitral valve regurgitation that are due to rheumatic heart disease.

It's important to note that ICD-10 codes provide a standardized way of documenting and communicating medical conditions, making it easier for healthcare providers, insurance companies, and researchers to accurately classify and track various health conditions. The use of specific codes like I05.8 helps ensure accurate and consistent recording of medical information, which is essential for medical record keeping, patient care, and healthcare management. When diagnosing and documenting medical conditions, healthcare professionals use the appropriate ICD-10 codes to convey specific information about the condition, its cause, and other relevant details.

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Answer:

The answer is B: systoic pressure minus diastolic pressure

Explanation:

Pulse pressure is the difference between systolic blood pressure minus diastolic blood pressure and is a characteristic sign of arterial elasticity. Pulse pressure and wave morphology indicate the elasticity of the arteries.

Pulse pressure is calculated as the difference between systolic pressure and diastolic pressure, which provides insight into the health of an individual's arteries.

The correct answer is option B which is the pulse pressure is the systolic pressure minus the diastolic pressure. When you measure your blood pressure, it involves two measurements: systolic blood pressure (the higher number and the first one that is mentioned) and diastolic blood pressure (the lower number and second one). The pulse pressure is the difference between these two numbers which provides information about the health of your arteries.

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Answer:

C, saliva

Explanation:

Epstein-Barr Virus (EBV) causes a disease called mononucleosis. It is also called a 'kissing disease' because the virus is most commonly passed through saliva.

It is the most known human herpes virus. Once infected, a person develops symptoms like of a mild cold, with a slight fever, fatigue, rash and the swelling of glands in the neck.

The virus is found in saliva, blood and semen. It can stay active in the body for months or even years without presenting any visible symptoms.

Answer:

The correct answer will be:

1.  Acetylcholine binds to receptors on the motor end plate

2. Chemically-regulated ion channels open, causing depolarization

3  End plate potentials trigger action potential(s).

4. Transverse tubules convey potentials into the interior of the cell

5. Ca++ is released from the sarcoplasmic reticulum

6. Ca++ binds to troponin, pulling on tropomyosin

7. Binding sites on actin are uncovered, allowing myosin to bind and carry out power strokes

8. Force increases.

9. Ca++ is pumped (re-sequestered) into the sarcoplasmic reticulum

10.  Force decreases.

Explanation:

The muscle contraction is a highly controlled mechanism which begins at the neuromuscular junction with the release of the acetylcholine neurotransmitter. This neurotransmitter causes the depolarization of the membrane by binding to the receptors of the motor end plate which generates an action potential. This action potential is transmitted via T-tubules from sarcolemma to the sarcoplasmic reticulum.  

The sarcoplasmic reticulum releases calcium ions which binds to the troponin protein. This troponin removes the protein tropomyosin from the actin causing the rotation of the tropomyosin exposing the binding sites for myosin. The myosin binds to the actin using energy from the ATP which pulls the actin causing contraction. Another ATP binds the myosin head which weakens the bond between myosin and actin which releases the myosin which decreases the force between them decreases and the muscles relax.