Which quantity or quantities must always be the same on both sides of a chemical equation? (a) the number of atoms of each kind (b) the number of molecules of each kind (c) the number of moles of each kind of molecule (d) the sum of the masses of all substances involved?

Answers

Answer 1

Explanation:

An equation that contains same number of atoms on both reactant and product side is known as a balanced chemical equation.

Also, mass of substances involved and formed in a chemical reaction will be equal.

For example, [tex]2K + Cl_{2} \rightarrow 2KCl[/tex]

Number of K atoms on both reactant and product side are 2.

Number of Cl atoms on both reactant and product side are 2.

Therefore, this equation is balanced.

Also, mass of K = 39.09 g/mol, mass of Cl = 35.45 g/mol.

Sum of reactant molecules = [tex](2 \times 39.09 g/mol) + (2 \times 35.45 g/mol)[/tex]

                                             = 149.08 g/mol

Sum of product molecules = [tex]2 \times (39.09 g/mol + 35.45 g/mol)[/tex]

                                             = 149.08 g/mol

Therefore, masses of atoms involved is same on both reactant and product side.

Thus, we can conclude quantity or quantities that must always be the same on both sides of a chemical equation are as follows.

the number of atoms of each kind.the sum of the masses of all substances involved.
Answer 2

The quantities which must always be the same on both sides of a chemical equation is:

(a) the number of atoms of each kind.

(d) the sum of the masses of all substances involved.

A chemical reaction refers to a chemical process that involves the rearrangement or transformation of the ionic, atomic or molecular structure of a chemical element through the breakdown and formation of chemical bonds in order to produce a new compound.

A chemical equation is typically used to denote or represent a chemical reaction between two or more chemical elements.

A balanced chemical equation is one in which the number of atoms on the reactant (left) side is equal to the number of atoms on the product (right) side.

This ultimately implies that, both the charge on each atom and sum of the masses of the chemical substances in a chemical equation are properly balanced.

Additionally, all chemical equations must be in accordance with the Law of Conservation of Mass because mass can neither be created nor destroyed.

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Related Questions

Which of the following is NOT true about "yield"? a. The value of the actual yield must be given in order for the percent yield to be calculated. b. The percent yield is the ratio of the actual yield to the theoretical yield. c. The actual yield may be different from the theoretical yield because reactions do not always go to completion. d. The actual yield may be different from the theoretical yield because insufficient limiting reagent was used.

Answers

Which of the following is NOT true about "yield"? a. The value of the actual yield must be given in order for the percent yield to be calculated. b. The percent yield is the ratio of the actual yield to the theoretical yield. c. The actual yield may be different from the theoretical yield because reactions do not always go to completion. d. The actual yield may be different from the theoretical yield because insufficient limiting reagent was used.

The correct answer is:
 d. The actual yield may be different from the theoretical yield because insufficient limiting reagent was used.
Final answer:

All the provided statements about 'yield' in chemistry are correct. The yield represents the amount of product from a chemical reaction. Percent yield is calculated using actual and theoretical yields, which can differ due to incomplete reactions or limiting reagents.

Explanation:

Regarding your question about which statement is not true about 'yield', all of the statements you listed are generally correct. Yield in chemistry refers to the amount of product obtained in a chemical reaction. The theoretical yield is the maximum possible amount of product that can be produced from a given amount of reactants. The actual yield is the amount of product actually produced when the chemical reaction is carried out in an experiment.

The percent yield is the ratio of the actual yield to the theoretical yield, expressed as a percentage (statement b). This value indeed requires knowledge of the actual yield (statement a). Both the actual and theoretical yield can differ due to incomplete reaction or inefficient use of limiting reagents (statement c and d).

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The solubilty of a gas is 1.6 g/l at 760 mmhg what is the solubility of the same gas at a pressure of 2.5 atm? assume temperature to be constant

Answers

we are going to use Henry's law:

when C1/P1 = C2/P2

at a constant temperature.

and when the C1 and C2 are the concentration of the gases ( the solubility)

and P1 and P2 is the Pressure 1 and pressure 2 

and when 760 mmHg = 1 atm

so, by substitution:

1.6 g/L / 1 atm = C2 /2.5 atm 

∴C2 = 1.6g/L *2.5atm /1 atm

     = 4 g/L

What volume of 0.45 M LiOH would be needed to neutralize 60.0 mL of 0.15 M Hi?

Answers

Answer is: volume of 0.45 M LiOH is 20 mL.
Chemical reaction: LiOH + HI → LiI + H₂O.
From chemical reaction: n(LiOH) : n(HI) = 1 : 1.
c(LiOH) · V(LiOH) = c(HI) · V(HI).
0.45 M · V(LiOH) = 0.15 M · 60.0 mL.
V(LiOH) = 0.15 M · 60.0 mL / 0.45 M.
V(LiOH) = 20 mL ÷ 1000 mL/L = 0.02 L.
n - amount of the substance.
c - concentration of solution.
Final answer:

To neutralize 60.0 mL of 0.15 M HCl, 20.0 mL of 0.45 M LiOH is required. The neutralization reaction proceeds in a 1:1 molar ratio.

Explanation:

To calculate the volume of 0.45 M LiOH required to neutralize 60.0 mL of 0.15 M HCl, we use the neutralization reaction where LiOH reacts with HCl in a 1:1 molar ratio:

LiOH + HCl → LiCl + H2O

First, calculate the number of moles of HCl:

moles HCl = volume (L) × molarity (M) = 0.060 L × 0.15 M = 0.009 moles

Since the molar ratio is 1:1, 0.009 moles of LiOH will also be needed.

Then, calculate the volume of LiOH solution:

Volume LiOH = moles LiOH / molarity of LiOH = 0.009 moles / 0.45 M = 0.020 L or 20.0 mL

Therefore, 20.0 mL of 0.45 M LiOH is required to neutralize 60.0 mL of 0.15 M HCl.

A group of chemistry students had to identify six white powders. The students used a variety of tests to identify the powders. They computed the density of each powder. They checked to see if any dissolved in water. One of the powders did not dissolve in water and they thought it was cornstarch. Someone knew that cornstarch felt slippery and reacted with iodine. The students put a few drops of iodine on each white powder. One powder turned black; they guessed that it was cornstarch. They heated the powders in a Bunsen burner flame to see if any would melt. One did and they guessed it might be a sugar. Which test result indicated a chemical change had taken place? A) dissolves in water B) feels slippery in water C) melts when heated in a flame D) turns black when iodine is added

Answers

change of states as the change from solid to liquid or liquid to gas are NOT chemical changes.
Solubility is a physical property no a chemical one
D) turns black when iodine is added (this is a chemical change)
D.turns black when iodine is added because other choices are physical like melting, dissolves in water, and 
feels slippery in water

Which acid dissociation constant (ka indicates the weakest acid? 8.5 × 10–3m 1.5 × 10–10m 3.5 × 10–7m 5.1 × 10–5m?

Answers

Answer is: the weakest acid is with Ka = 1.5 × 10⁻¹⁰ M.
Ka is the acid dissociation constant, which quantifies the extent of acid dissociation in water.
The lower is the acid dissociation constant, the weaker is the acid, because concentration of hydrogen ions (H⁺) or hydronium ions (H₃O⁺) is very low.
For some acid, chemical reaction in water: HA(aq) ⇄ A⁻(aq) + H⁺(aq), acid dissociation constant is: Ka = [A⁻]·[H⁺] / [HA].

What about uranium room temperature is it "SOLID LIQUID or GAS)?

Answers

It is a solid 100%............

Bromine dichloride, BrCl2, decomposes to form bromine and chlorine at equilibrium according to the following equation:
2BrCl2(g) + heat ⇌ Br2(g) + 2Cl2(g)
For the following change, how would the reaction shift (toward the products, reactants, or no change)?

The temperature is increased?

Answers

When the equilibrium of the decomposition of bromine dichloride is disturbed by increasing temperature, the reaction shifts towards the reactants according to Le Chatelier's principle.

If the temperature is increased for the decomposition of bromine dichloride, BrCl2, the reaction will shift towards the reactants. According to Le Chatelier's principle, if a chemical system at equilibrium experiences a change in concentration, temperature, volume, or pressure, then the equilibrium shifts to counteract the imposed change and re-establish equilibrium. In this endothermic reaction, heat is absorbed to convert BrCl2 into bromine, Br2, and chlorine, Cl2. Therefore, increasing the temperature adds heat to the system, which will shift the equilibrium towards the reactants (BrCl2) to absorb the excess heat.

Which compound has the same empirical and molecular formula ethyne ethene ethane methane?

Answers

empirical formula is the simplest ratio of whole numbers of components in a compound 
molecular formula is the actual ratio of components in a compound .
the molecular formula for the compounds given are as follows
ethyne  - C₂H₂
ethene - C₂H₄
ethane - C₂H₆
methane - CH₄
the actual ratios of the elements                 simplified ratio
                     C : H                                           C : H
ethyne            2:2                                             1:1
ethene            2:4                                             1:2
ethane            2:6                                             1:3
methane         1:4                                             1:4
the only compound where the actual ratio is equal to the simplified ratio is methane 
therefore in methane molecular formula CH₄ is the same as empirical formula CH₄

If 72.0 grams of aluminum are reacted with 252 grams of hydrochloric acid, how many grams of aluminum chloride are produced by this reaction? 2al(s) + 6hcl(aq) → 2alcl3(aq) + 3h2(g)

Answers

Final answer:

To determine the grams of aluminum chloride produced in the reaction, use the given balanced chemical equation and the molar masses of aluminum and aluminum chloride. Convert the given masses of aluminum and hydrochloric acid to moles and use the stoichiometric ratios to determine the moles of aluminum chloride produced. Finally, convert the moles of aluminum chloride to grams.

Explanation:

To determine the grams of aluminum chloride produced in the reaction, we need to use the given balanced chemical equation and the molar masses of aluminum (Al) and aluminum chloride (AlCl3). The molar mass of Al is approximately 26.98 g/mol, while the molar mass of AlCl3 is approximately 133.34 g/mol.

First, we convert the given masses of aluminum (72.0 g) and hydrochloric acid (252 g) to moles using their respective molar masses. Using the ratios from the balanced chemical equation, we can then determine the moles of aluminum chloride produced.

Starting with 72.0 g of Al:

72.0 g Al * (1 mol Al / 26.98 g Al) * (2 mol AlCl3 / 2 mol Al) * (133.34 g AlCl3 / 1 mol AlCl3) = 398.908 g AlCl3

Therefore, approximately 398.908 grams of aluminum chloride are produced.

A chart that organizes elements by their chemical properties and increasing atomic number is the

Answers

Periodic table!

The periodic table organizes elements by their chemical properties (mainly through vertical columns known as groups) and increasing atomic number. 


a 4 kilogram cat is resting on top of a bookshelf that is 3 meters high what is the cats gravitational potential energy relative to the floor if the acceleration due to gravity is 9.8m/s A.7j B. 29j C.12j D.118j

Answers

GPE = mgh

Where GPE is gravitational potential energy (J), m is the mass ob the object (kg), g is acceleration due to gravity (m/s²) and h is the height (m)

m = 4 kg
g = 9.8 m/s²
h = 3 m

By substitution,
GPE =  4 kg x 9.8 m/s² x 3 m
        = 117.6 J
        ≈ 118 J

Hence, the answer is D

Submarines sometimes make a "pinging" sound to determine the depth of an object in the ocean. This process is called
A. sonar.
B. radar.
C. refraction.
D. diffraction

Answers

The answer is A.

A: Sonar

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sonar is the correct answer

When the pressure that a gas exerts on a sealed container changes from 22.5 psi to psi the temperature changes from 110 c to 65.0 c

Answers

Gay- Lussacs law states that the pressure of a gas is directly proportional to temperature for a fixed amount of gas at constant volume.
therefore P/T = k
where P - pressure , T - temperature and k - constant 
[tex] \frac{P1}{T1} = \frac{P2}{T2} [/tex]
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - temperature in kelvin - 110 °C + 273 = 383 K
T2 - 65.0 °C + 273 = 338 K
substituting these values in the equation 

[tex] \frac{22.5 psi}{383 K} = \frac{P}{338K} [/tex]
P = 19.9 psi 
new pressure is 19.9 psi

Answer:

19.9 psi

Explanation:

Question 4 if 0.587 g of nickel metal reacts with 1.065 g of chlorine gas, what is the empirical formula of the nickel chloride product? ni2cl3 ni3cl2 nicl3 nicl nicl2

Answers

The answer is NiCl3.
Solution:
We can convert the masses of the elements to the number of moles using their atomic masses:
     moles of Ni = 0.587g Ni * 1mol Ni/58.6934g Ni = 0.01000 mol
     moles of Cl = 1.065g Cl * 1mol Cl/35.453g Cl = 0.030040 mol

We divide the number of moles of each element by the lowest number of moles. In this case, we divide by 0.01000:
     0.01000 mol Ni / 0.01000 = 1
     0.030040 mol Cl / 0.01000 = 3.004 ≈ 3

We can now write the empirical formula of nickel chloride using these values as the subscript for each element: NiCl3

The empirical formula of nickel chloride, given the masses of nickel and chlorine, is c) NiCl₃

Determining the Empirical Formula of Nickel Chloride

To determine the empirical formula of nickel chloride from the given masses of nickel (0.587 g) and chlorine (1.065 g), follow these steps:

Convert the mass of each element to moles:

Nickel (Ni): 0.587 g ÷ 58.69 g/mol = 0.0100 mol

Chlorine (Cl): 1.065 g ÷ 35.45 g/mol = 0.0300 mol

Determine the simplest whole number ratio:

Nickel: 0.0100 mol ÷ 0.0100 mol = 1

Chlorine: 0.0300 mol ÷ 0.0100 mol = 3

Write the empirical formula: Hence, the simplest ratio of Nickel to Chlorine is 1:3, making the empirical formula NiCl₃

To find the number of protons, neutrons, and electrons in a particular atom, you must know the mass number and the atomic number of the atom

Answers

Atomic number shows the number of protons and electrons in an atom.
Number of neutrons = mass number - atomic number.

What is the molarity of a salt solution that is made from 31.0 grams of ca3(po4)2 placed in a volumetric flask and filled to the 2 liter line with distilled water?

Answers

The molarity is 31.0 * x / 2, such that x is the molar mass of Ca₃(PO₄)₂

Use the periodic table to answer the questions: Which is the correct electron configuration for sodium (Na)?

1s22s22p62d1

1s22s22p63s1

1s22p63d3

Answers

I am pretty sure the answer is 1s22s22p63s1

Answer: The correct answer is [tex]1s^22s^22p^63s^1[/tex]

Explanation:

Electronic configuration is defined as the configuration in which total number of electrons are represented which are present in an element.

Number of electrons are determined by the atomic number of that element.

Atomic number of Sodium = 11

Electronic configuration of sodium element (Na) : [tex]1s^22s^22p^63s^1[/tex]

Hence, the correct answer is [tex]1s^22s^22p^63s^1[/tex]

Which of the following is a natural cause of wildfires

Answers

Hi there!

A natural cause of wildfires can be lightning. When lightning strikes in larger areas it can cause fires more easily.

Hope this helps you!

~DL

Answer:

lightning

Explanation:

Natural fires are generally started by lightning, with a very small percentage started by spontaneous combustion of dry fuel such as sawdust and leaves. On the other hand, human-caused fires can be due to any number of reasons. Some classifications include smoking, recreation, equipment, and miscellaneous.

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Which energy source has been developed and improved by chemists?

Answers

nuclear hope this helps

Answer:Explained

Explanation:

The following energy has been developed and improved by chemists

Nuclear energy coal gasgasolineEthanolKerosene Propane

Anything which includes chemical reaction has been developed by chemists to utilize the hidden energy.For example Nuclear energy

If proper reactions and controlled environment is given then a huge amount of energy can be generated from Radioactive elements.

The smallest piece of a compound that retains characteristics of a compound is

Answers

The smallest piece of a compound that retains characteristics of a compound is a molecule.

Which is not true of radioactive half-life? radioactive half-life is increased by heating the isotope. independent of the physical or chemical form of the isotope. the time required for the level of radioactivity in a sample to be cut in half. independent of the amount of radioactive material present?

Answers

The wrong one is 
radioactive half-life is increased by heating the isotope.

Answer:

"Radioactive half-life is increased by heating the isotope" is not true.

Explanation:

The radioactive half-life is the time required for half of any given amount of a substance (or isotope), to undergo radioactive decay.

This radioactive decay does not depend on the physical form of the substance nor it depends on the temperature.

List the information you need to find how many milliliters of a stock solution of 2.00m mgso4 you would need to prepare 100.0 ml of 1.00m mgso4

Answers

we can use the dilution equation when preparing diluted solutions from concentrated solutions
c1v1 = c2v2
where c1 is concentration and v1 is volume of the concentrated solution
c2 is concentration and v2 is volume of the diluted solution prepared
substituting these values in the equation 
2.00 M x V = 1.00 M x 100.0 mL 
V = 50.0 mL 
50.0 mL of concentrated solution should be taken and filled up to 100.0 mL to prepare a 1.00 M solution
Final answer:

To determine how many milliliters of a stock solution are needed to prepare a given volume of a diluted solution, one can use the dilution formula 'M1V1 = M2V2’. In this case, you'd need 50.0 ml of the stock solution to prepare 100.0 ml of a 1.00m MgSO4 solution.

Explanation:

To find out how many milliliters of a stock solution of 2.00m MgSO4 you would need to prepare 100.0 ml of 1.00m MgSO4, you can use the formula M1V1 = M2V2, where M1 is the molarity of the initial solution, V1 is the volume of the initial solution, M2 is the molarity of the final solution, and V2 is the volume of the final solution.

Firstly, we substitute the given values into the formula. M1 is our initial molarity (2.00m), V1 is what we're trying to find, M2 is our final molarity (1.00m) and V2 is our final volume (100.0 ml). By rearranging the formula, we get V1 = (M2 * V2) / M1.

The calculation step becomes: V1 = (1.00m * 100.0 ml) / 2.00m = 50.0 ml. Therefore, you would need 50.0 milliliters of the stock solution to prepare 100.0 ml of a 1.00m MgSO4 solution.

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Identify the brønsted base in the forward reaction hpo2− 4 (aq) + hno3(aq) ⇀↽ no− 3 (aq) + h2po− 4 (aq). 1. h2po− 4 (aq) 2. hno3 3. hpo2− 4 4. no− 3

Answers

Final answer:

The Brønsted base in the forward reaction HPO4²-(aq) + HNO3(aq) ⇀↽ NO3¯ (aq) + H2PO4¯ (aq) is HPO4²-(aq) because it accepts a proton in this reaction.

Explanation:

To identify the Brønsted base in the reaction HPO4²-(aq) + HNO3(aq) ⇀↽ NO3¯(aq) + H2PO4¯(aq), let's recognize the definitions of a Brønsted-Lowry base and acid.

A Brønsted base is a proton (H+) acceptor, whereas a Brønsted acid is a proton donor. In the forward reaction, HNO3 donates a proton; making it the Brønsted acid. The species that accepts the proton is HPO4²-. Therefore, HPO4²- is the Brønsted base in the forward reaction of this equilibrium.

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In the reaction, HPO₄²⁻ is the Brønsted base as it accepts a proton from HNO₃. HNO₃ acts as the Brønsted acid. Therefore, option 3: HPO₄²⁻ is correct.

In the forward reaction HPO₄²⁻ (aq) + HNO₃ (aq) ⇄ NO₃⁻ (aq) + H₂PO₄⁻ (aq), we need to identify the Brønsted base.

A Brønsted base is defined as a substance that can accept a proton (H⁺). In this reaction:

HPO₄²⁻ is acting as a Brønsted base because it accepts a proton from HNO₃ to form H₂PO₄⁻.  HNO₃ acts as a Brønsted acid since it donates a proton.

So, the correct answer is option 3: HPO₄²⁻.

Complete Question.

Identify the Brønsted base in the forward reaction HPO₄²⁻ (aq) + HNO₃(aq) ⇄ NO₃⁻ (aq) + H₂P0₄⁻ (aq).

1. NO₃⁻

2. H₂PO₄⁻ (aq)

3. HPO₄²⁻

4. HNO₃

3L of nitrogen gas is heated from 20°C to 80°C. What is the new volume of the gas, if pressure remains constant?

Answers

Answer:
             The volume increases to 3.61 L.

Solution:
               According to Charle's Law, " At constant pressure and mass the volume of gas is directly proportional to the applied temperature".

For initial and final states of a gas the equation is,

                                           V₁ / T₁  =  V₂ / T₂
Solving for V₂,
                                           V₂  =  V₁ T₂ / T₁    ----- (1)

Data Given;
                   V₁  =  3 L

                   T₁  =  20 °C + 273  =  293 K

                   T₂  =  80 °C + 273  =  353 K

Putting values in eq. 1,

                                           V₂  =  (3 L × 353 K) ÷ 293 K

                                           V₂  =  3.61 L

Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles. Record in the appropriate blanks.

Answers

A=0.5
B=0.25
C=0.125
D=0.015625
E=0.00390625

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, [tex] 0.5^{n} [/tex]

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

An aqueous solution of an unknown quantity of a nonelectrolyte solute is found to have a freezing point of −0.58°c.what is the molal concentration of the solution?

Answers

Final answer:

The molal concentration of the aqueous solution with a freezing point of -0.58°C is 0.312 mol/kg, calculated using the formula for freezing point depression and the molal freezing-point depression constant for water.

Explanation:

To determine the molal concentration of the solution based on the given freezing point depression, we use the formula ΔTf = Kf × m, where ΔTf is the change in freezing point, Kf is the molal freezing-point depression constant for water, and m is the molality of the solution.

For water, Kf is -1.86°C/m. The change in freezing point (ΔTf) can be calculated as the difference from water's normal freezing point, 0°C, to the solution's freezing point, which is -0.58°C. Thus, ΔTf = 0°C - (-0.58°C) = 0.58°C.

Plugging the values into the equation:

ΔTf = Kf × m
0.58°C = (-1.86°C/m) × m
m = 0.58°C / -1.86°C/m
m = 0.312 mol/kg

Therefore, the molal concentration of the solution is 0.312 mol/kg.

Consider the reaction below. CO(g) + Cl2(g) « COCl2(g) What is the most likely effect to the forward reaction if there is an increase in pressure on this reaction? The reactant surface area increases. The reaction rate decreases. The reaction is not affected at all. The reaction stops completely.

Answers

Answer: the reaction rate of the forward reaction increases (although it is not among the options shown).

Explanation:

1) The equation given is:

CO (g) + Cl₂ (g)  ⇄ COCl₂ (g)

2)  The forward reaction is:

CO (g) + Cl₂ (g)  → COCl₂ (g)

3) The stoichiometry is 1 mole + 1 mole → 1 mole

4) Analysis and conclusion:

The effect of change in the conditions of an equilibrium is foreseen using Le Chatelier's principle.

Le Chatelier's principle states that a system in equilibrium will act trying to compensate the distress applied to the system.

In this case, the distress is increase in pressure.

To compensate the increase in pressure the system must act by reducing the number of moles in the system. Since the forward reaction implies the conversion of two moles of reagents into one mole of product, the more the forward reaction progress the less the number of moles will be present in the system and so the more the compensation of the increase in pressure. So the forward raction is favored by the increase in pressure.

Favoring the forwar reaction means that its rate will incrase,

Answer:

The reaction rate decreases.

Explanation:

Tritium (31h) is an isotope of hydrogen that is sometimes used to make the hands of watches glow in the dark. the half-life of tritium is 12.3 years. after 49 years, approximately how much of the original tritium remains?

Answers

The answer IS 6.25%.  Tritium (31h) is an isotope of hydrogen that is sometimes used to make the hands of watches glow in the dark. the half-life of tritium is 12.3 years. after 49 years, approximately 6.25% of the original tritium remains?

Answer:

6.31%

Explanation:

In order to solve this, you need to use the expression to calculate half life, which is the following:

C = Co e^-t λ  (1)

Where:

C: concentration after t has passed

Co: initial concentration

t: time that has passed

λ: lambda which relation half life time

λ this can be calculated with the following expression:

λ = ln2 / t(1/2)   (2)

So, let's calculate λ first and then, the concentration. In this case, we will assume that we begin with a concentration at 100%.

The value of lambda is:

λ = ln2 / 12.3

λ = 0.0564

Now, let's use (1) to calculate the concentration after 49 years:

C = 100 e^ (-49 * 0.0564)

C = 100 e^(-2.7636)

C = 6.31 %

And this will be the tritium remaining after 49 years

In which substance does phosphorus have a +3 oxidation state

Answers

Options are as follow,

A. P₄O₁₀
B. PCl₅
C. Ca₃(PO₄)₂
D. KH₂PO₃

Answer;
            The correct option is Option-D (KH₂PO₃).

Explanation:
                   Oxidation number of Phosphorous is calculated as,

As the normal oxidation number of K is +1, H is +1 and O is -2 so,

                                       KH₂PO₃  =  0

0 shows that the molecule is neutral. Now puttion values of all elemnts except P,
 
                                  (+1) + (+1)₂ + P + (-2)₃  =  0

                                  +1 + 2 + P - 6  =  0

                                  +3 + P - 6  =  0

                                  +3  + P  =  +6

                                  P  =  +6 - 3

                                  P  =  +3
Final answer:

Phosphorus has a +3 oxidation state in tetraphosphorus hexaoxide (P4O6) and phosphorous acid (H3PO3).

Explanation:

Phosphorus exhibits different oxidation states in various substances. When it comes to a +3 oxidation state, phosphorus(III) oxide, also known as tetraphosphorus hexaoxide (P4O6), is the substance where phosphorus has a +3 oxidation state. This compound can be formed when white phosphorus is carefully burned in limited oxygen. Additionally, another compound where phosphorus has a +3 oxidation state is phosphorous acid, H3PO3, which can be obtained by the slow dissolution of phosphorus(III) oxide in cold water.

Phosphorus also forms hydrides, such as diphosphorus tetrahydride (H2P-PH2) and tetraphosphorus trisulfide (P4S3), which exhibit phosphorus in atypical oxidation states including the +3 state.

Light striking a mirror at a 50° angle will be reflected at an angle _____.

Answers

Equal TO 50 degree because angle of incidence is equal to angle of reflection.

Answer:

equal to 50 degress

Explanation:

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