Which regular polygon would have each of its interior angles measure 120°? hexagon heptagon octagon nonagon?

Answers

Answer 1
Hexagon.
____________

Related Questions

Write (3n)^3 without exponents

Answers

(3n)³
= (3n)×(3n)×(3n)
= 27 × n × n × n

Answer:

Without exponents, we can write the term as:  [tex]27(n)(n)(n)[/tex]

Step-by-step explanation:

The given term is :

[tex](3n)^{3}[/tex]

This can be written as:

[tex](3n)(3n)(3n)[/tex]

= [tex]27n^{3}[/tex]

= [tex]27(n)(n)(n)[/tex]

Hence, without exponents, we can write the term as:  [tex]27(n)(n)(n)[/tex]

WHAT IS THE VALUE OF X

Answers

check the picture below.

[tex]\bf \stackrel{(x+4)+1}{(x+5)}(x+4)=\stackrel{(x+1)+11}{(x+12)}(x+1)\implies x^2+9x+20=x^2+13x+12 \\\\\\ 9x+20=13x+12\implies 8=4x\implies \cfrac{8}{4}=x\implies 2=x[/tex]

use the graph of y=sin theta to find the value of 2theta for theta = pi/4 radians

Answers

we have that
y=sin x

for x=2theta
theta = pi/4 radians
so
x=2*pi/4-----> x=pi/2

using a graph tool
see the attached figure

for x=pi/2
y=sin pi/2------> y=1

the solution is
1

28 - 2(5a - 3) = 47


A. -1.3

B. 1.3

C. -2.5

D. 8.1

Answers

if you work it out, you get -10 a=13. and to get the final answer you divide each side by 10, leave you with the answer... a = -1.3

line AB is tangent to circle O at A. The diagram is not drawn to scale.

If AO=21 and BC=14, what is AB?

Answers

AO = 21
BC = 14
OC = radius of the circle = AO = 21
∴ OB = OC + CB = 21 + 14 = 35
Line AB is tangent to circle O at A
∴ AB is perpendicular to AO
∴ Δ OAB is a right triangle at A
Applying Pythagorean theorem
∴  OB² = AO² + AB²
∴ AB² = OB² - AO² = 35² - 21² = 1225 - 441 = 784
∴ AB = √784 = 28

What is the value of x?

a. 7
b. 7√2
c. 14
d. 14√2

Answers

Note that sin 45 deg = opposite side  /  hypotenuse.

                                  1               7sqrt(2)
Here, sin 45 deg = ----------- = --------------
                                sqrt(2)             x

Cross multiplying, we get x = 7 [sqrt(2) ]^2 = 7(2) = 14 (answer)

A rancher has 4000 ft. of fence for constructing a rectangular corral that is divided into 3 equal sections. one side of the corral will be bounded by his barn and needs no fencing. what are the dimensions of the corral that will maximize the area? what is the area of the corral?

Answers

Let x and y be the sides of the rectangular corral. Therefore,
Area, A = x*y = xy

Additionally, let the side bordering the barn be x. Then,
Circumference, C = x+y+y = x+2y = 4000 ft => x = 4000 - 2y

Substituting for x in the area equation,

A = (4000-2y)y = 4000y - 2y^2

For maximum area, dA/dy = 0

Then,
dA/dy = 4000 - 4y = 0 => 4000 = 4y => y = 4000/4 = 1000 ft

And x = 4000 - 2y = 4000 - 2*1000 = 4000 - 2000 = 2000 ft

The  dimensions of the corral are: 2000 ft by 1000 ft.

Area, A = xy = 2000*1000 = 2000,000 ft^2

Identify the value that is NOT in the range of the piece-wise function.


A. -3


B. 1


C. 3


D. -1

Answers

Hello!

Since the point (2, 1) is not shaded it is not involved in the answer

The answer is B)1

Hope this helps!
the answer is -3
 looking at the graph, none of the lines drawn on the graph are at Y= -3
 (the lowest dot on the graph is -2)

Help please ! A B Or C

Answers

Answer:

B) 46

Step-by-step explanation:

What you have to do here is plug in the numbers 2, 3, 4, and 5 in for i in the equation and then add the sums together:

3(2) + 1 = 7

3(3) + 1 = 10

3(4) + 1 = 13

3(5) + 1 = 16

Add those together and they equal 46

Bob bought 3 packs of model cars. He gave 4 cars to Ann.Bob has 11 model cars left how many model cars were in each pack.

Answers

There are 5 model cars per pack. 

3 packs at 5 cars per pack = 15 cars. If he gives the 4 cars away to Ann, he's left with 11 cars like the problem says. 

How much greater is the median number of pairs of shoes in the inventory at the Golf pro Shop than the median number of pairs of shoes in the inventory at the Tennis Pro Shop?

Answers

I think 40-20=20
It seem a bit to easy, I don't know if I'm right
Hi there!!


Your answer is 20.


Since A = 40 and B = 20

Subtract 40 by 20  to get 20 (40 - 20 = 20)




Hope I Helped
   

The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?
(3, 4)
(3, 5)
(30, 401)
(30, 501)

Answers

We just have to plug t=10 into the formulas for the coordinates of the point. And we find that x(10) = 3*10=30 and y(10)=4*100+1=401. The answer is (30, 401)

hurry pls need help look at picture below

Answers

V = S*h
h = V/S = 250*pi / 50*pi = 5 m 

Rovide an appropriate response.4) assume that adults have iq scores that are normally distributed with a mean of 100 and a standard deviation of 15 (as on the wechsler test). find the iq score separating the top 14% from the others. 4)

Answers

9484 hope i helped u

How many combinations of four books can be made from eight different books? 24 70 1,680?

Answers

Answer:

70

Step-by-step explanation:

four books can be made from eight different books

4 books to be chosen from 8 books

The order does not matters so we use Combination.

four books can be made from eight different books, so we find 8C4

[tex]nCr= \frac{n!}{r!(n-r)!}[/tex]

[tex]8C4= \frac{8!}{4!(8-4)!}[/tex]

[tex]8C4= \frac{8!}{4!(4)!}[/tex]

[tex]8C4= \frac{8*7*6*5*4!}{4!(4)!}=70[/tex]

Answer:

70

Step-by-step explanation:

Geometry A Problem! Help! Line AC

Answers

the formula is:  (AB +BC) * BC = EC*DC
 now fill in the numbers that are given:

(AB +6)*6 = 12*5

(AB+6)*6 = 60

6AB +36 = 60

6AB = 24

AB = 24/6

AB = 4

AC = AB +BC
AC = 4 + 6

AC = 10


x 0 2 4 6 8 f(x) 15 15.5 17 19.5 23 Write the quadratic function that corresponds to the given table of values in standard form, f(x) = ax2 + bx + c, where a, b and c are constants.

f(x)=ax^2+bx+c

Answers

f(x)=ax^2=bx=c is the answer

Answer with Step-by-step explanation:

We are given that:

f(x)=ax²+bx+c

also at x=0 f(x)=15

Putting x=0 in f(x)

a×0+b×0+c=15

c=15

now, f(2)=15.5

⇒ a×2²+b×2+c=15.5

⇒ 4a+2b+15=15.5

⇒ 4a+2b=0.5  -------(1)

f(4)=17

⇒ a×4²+b×4+c=17

⇒ 16a+4b+15=17

⇒ 16a+4b=2     --------(2)

equation (2)- 2×equation(1)

⇒ 16a+4b-8a-4b=2-2×0.5

⇒ 8a=2-1

⇒ 8a=1

⇒ a=1/8

a=0.125

Putting value of a and c in equation (1)

⇒ 4×0.125+2b=0.5

⇒ 0.5+2b=0.5

⇒ 2b=0

b=0

Hence

a=0.125

b=0

c=15

and f(x)=0.125x²+15

What is the range of the function y = -x2 + 1?

Answers

Final answer:

The range of the function y = -x^2 + 1 is all real numbers less than or equal to 1, represented as ]-∞, 1].

Explanation:

The range of the function y = -x^2 + 1 refers to the set of all possible values that y can take as x varies over all real numbers. Since the function is a downward-opening parabola (due to the negative coefficient of x^2), the maximum value of y is at the vertex of the parabola. The vertex, in this case, occurs at x=0, which gives us the maximum y value of y = 1. As x moves away from zero in either direction, the value of y decreases and approaches negative infinity. Hence, the range of this function is ]-∞, 1], or all real numbers less than or equal to 1.

Solve 3/10 n-3 1/5 = -1 1/5

Answers-
A.n =-12 2/3
B.n = 6 2/3
C.n = 8
D.n = -6/25

Answers

3/10 n-3 1/5=-1 1/5
convert mixed numbers to a improper fractions:3 1/5=16/5
[tex] \frac{3}{10}n- \frac{16}{5}=-1* \frac{1}{5}[/tex]
convert mixed numbers to a improper fractions:1 1/5=6/5
[tex] \frac{3}{10}n- \frac{16}{5}=- \frac{6}{5} [/tex]
add 16/5 to both sides
[tex] \frac{3}{10}- \frac{16}{5}+ \frac{16}{5}=- \frac{6}{5}+ \frac{16}{5} [/tex]
simplify 
3/10 n=2
multiply both sides by 10
[tex]10* \frac{3}{10}n=2*10 [/tex]
simplify 
3n=20
divide both sides by 3
[tex] \frac{3n}{5}= \frac{20}{3} [/tex]
simplify 
[tex]n= \frac{20}{3} [/tex]
Hope this helps

Answer: B. n = 6 2/3

Hope this helps!

In how many ways can 3 identical emeralds 2 identical diamonds and 2 different opals be arranged in a row in a display case

Answers

They can be arranged in 210 ways.

The arrangement of n objects where n₁ is one kind, n₂ is a second kind, and n₃ is a third kind is given by

[tex]\frac{n!}{n_1!\times n_2!\times n_3!}[/tex]

There are 7 total gems; 3 of the first kind, 2 of the second kind and 2 of the third kind:

[tex]\frac{7!}{3!2!2!} = 210[/tex]

They can be arranged in 210 ways.

We have given that, 3 identical emeralds 2 identical diamonds and 2 different opals

What is the arrangement of n object  where n₁ is one kind, n₂ is a second kind, and n₃ is a third kind?

The arrangement of n objects where n₁ is one kind, n₂ is a second kind, and n₃ is a third kind is given by

[tex]\frac{n!}{n_1!*n_2!*n_3!}[/tex]

The total number of gems =7

3 of the first kind, 2 of the second kind and 2 of the third kind

Therefore, we get

[tex]\frac{7!}{2!*2!*3!}=210[/tex]

Therefore ,they can be arranged in 210 ways.

To learn more about the arrangement visit:

https://brainly.com/question/6032811

An angle measuring between 90° and 180° is called _____. A.obtuse B.acute C.straight D.small

Answers

Answer: A) Obtuse

Reason/Explanation:
An obtuse angle is more than 90 degrees, but less than 180.


-DustinBR

OBTUUUUUUUUUUUUUUUUUUUUUSE

(6a −? )5a =? a2 − 35a

Answers

(6a - 7)5a = 30a^2 - 35a
Answer:
5a(6a-7) = 30a² - 35a

Explanation:
Before we begin, remember the following:
a(b+c) = ab + bc

Now for the given:
Assume that the first question mark is x and that the second question mark is y.

The expression now becomes:
(6a-x) * 5a = ya² - 35a
Distribute the 5a over the bracket and equate it with the right-hand side as follows:
5a(6a) - 5a(x) = ya² - 35a
30a² - 5ax = ya² - 35a

By comparison:
30a² = ya² ..............> This means that y = 30
-5ax = -35a
-5x = -35
5x = 35
x = 35/5
x = 7

Based on the above, the expression is:
5a * (6a-7) = 30a² - 35a

Hope this helps :)

What is the slope of the line shown on the graph?

Answers

The slope would be 2/5 , good luck !
The slope to would be 2/5

Use graphing calculator to solve system the equations in the interval from 0+2pi.round to the nearest hundredth. 7cos 2t=3

Answers

The solutions of the trigonometric equation are approximately 0.56, 2.58, 3.71 and 5.72, all in concordance with the results found beside the analytical approach.

How to solve trigonometric equations

Trigonometric functions are periodic functions, cosine function has a standard period of 2π radians. There are two approaches to solve the expression given, an analytical one and a graphical one. Now we proceed to show each approach:

Analytical method

Now we proceed to apply algebraic handling and inverse trigonometric functions to solve the expression for t:

7 · cos 2t = 3

cos 2t = 3/7

2 · t = cos⁻¹ (3/7)

There are two solutions:

2 · t₁ ≈ 0.359π + 2π · i  ∨   2 · t₂ ≈ 1.641π + 2π · i

t₁ ≈ 0.180π + π · i   ∨ t₂ ≈ 0.821π + π · i

t₁₁ ≈ 0.180π ∨ t₁₂ ≈ 1.180π ∨ t₂₁ ≈ 0.821π ∨ t₂₂ ≈ 1.821π

The solutions of the trigonometric equations in [0, 2π] are approximately 0.18π, 0.82π, 1.18π and 1.82π.

Graphical approach

First, we add the definition of the following two functions (f(x) = 7 · cos 2t and g(x) = 3) and plot in the calculator through a graphing tool. The solutions of this trigonometric function are the points of intersection of the two functions.

According to the image attached below, the solutions of the trigonometric equation are approximately 0.56, 2.58, 3.71 and 5.72, all in concordance with the results found beside the analytical approach.

To learn more on trigonometric equations: https://brainly.com/question/23948746

#SPJ1

 

Suppose that the measure of the minor arc BD is 172°. Find m BCD. (I need help on all questions in picture)

Answers

Arc BCD will 188 degrees :

the circle is 360 and BD+BCD=360

so BCD=360-172=188

Factor this expression completely and then place the factors in the proper location. Note: Place factors alphabetically!

mn - 4m - 5n + 20

Answers

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

[tex] mn - 4m - 5n + 20 [/tex]

2. The first thing you must do to factor the expression is to group the terms, as following:

[tex] (mn-4m)+(-5n+20) [/tex]

3. Now, choose the greatest common factor of each group:

[tex] m(n-4)-5(n-4) [/tex]

4. Now, you need to factor the expression by factoring out the [tex] n-4 [/tex]

[tex] (m-5)(n-4) [/tex]

The answer is: [tex] (m-5)(n-4) [/tex]

A spherical gas tank has a 10 foot diameter when filled with propane it provides 358,000,000 BTUs how many BTUs does 1 cubic foot of propane yield? Round to the nearest thousand

Answers

Volume of the spherical tank will be given by:
V=4/3πr³
thus the volume of the tank will be:
V=4/3×π×(10/2)³=523.59877756~523.6 ft³
Given that 523.6 ft³ can hold 358,000,000 BTUs of propane, the amount that 1 ft³ will be given by:
[total amount]/[total volume]
=358,000,000/523.6
=683,728.0367 BTUs/ft³
=684,000 BTUs/ft³ (in thousand)

The number of BTUs does 1 cubic foot of propane yield is 684,000 BTUs/ft³ (in thousand)

Calculation of the number of BTUs:

Since we know that

The volume of the spherical tank is

[tex]V=4\div 3\pi r^3[/tex]

Now the volume of the tank will be:

[tex]V=4\div 3\times \pi \times (10/2)^3[/tex]

=523.59877756

= 523.6 ft³

Now the number should be

= [total amount] ÷ [total volume]

=358,000,000 ÷ 523.6

=683,728.0367 BTUs/ft³

= 684,000 BTUs/ft³ (in thousand)

Therefore, The number of BTUs does 1 cubic foot of propane yield is 684,000 BTUs/ft³ (in thousand)

Learn more about the number here: https://brainly.com/question/17954964

During the first part of a​ trip, a canoeist travels 96 miles at a certain speed. the canoeist travels 15 miles on the second part of the trip at a speed 5 mph slower. the total time for the trip is 4 hrs. what was the speed on each part of the​ trip?

Answers

This problem is a problem using 
d = r * t
First part of the trip
d = 96 miles
r = ??
t = ??

Second part of the trip
d = 15 miles
r = r - 5
t = 4 - t

Solve for r first.
96/r + 15/(r - 5) = 4 hours                multiply through by r and r - 5
96(r - 5) + 15r  = 4*(r - 5)(r)             Remove the brackets on the left
96r - 480 + 15r = 4*r*(r - 5)             Collect like terms on the left.
111r - 480 = 4r(r - 5)                        Remove the brackets on the right.
111r - 480 = 4r^2 - 20r                     Bring the left side over to the right side.
0 = 4r^2 - 20r - 111r + 480               Collect like terms.
0 = 4r^2 - 131r + 480

The only way I could do this was to use the quadratic equation.

[tex]\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} [/tex]

a = 4

b = - 131

c = 480

[tex]\text{x = }\dfrac{ -(-131) \pm \sqrt{(-131)^{2} - 4*4*480 } }{2*4} [/tex]
[tex]\text{x = }\dfrac{ 131 \pm \sqrt{(17161) - 7680 } }{8} [/tex]
[tex]\text{x = }\dfrac{ 131 \pm \sqrt{9481 } }{8} [/tex]
[tex]\text{x = }\dfrac{ 131 \pm 97.37  }{8} [/tex]

x = (131 + 97.38)/8
x = 28.55
x = (131 - 97.37)/8
x = 4.20

4.2 isn't going to work because the slower speed has to be larger than 5, otherwise you will get a negative speed (as this solution will give), so 4.20 is an extraneous solution.

r = 28.55 for the first  part of the trip and
r = 23.55 for the second part of the trip.

Check.
Let's see if the times add up to 4
d/r = t
96/28.55 = 3.36
15/22.75 = 0.64

The times do = 4, so the rates are correct.

Answers
r1 = 28.55 for the 96 mile trip.
r2 = 23.55 for the 15 mile trip.

Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at each point.

A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3.

Answers

There is a vertical asymptote at x = 0 (because the denominator becomes 0). We need to further analyze the behavior at x = 3 to see if it's a hole (cancellation) or the function is continuous there (Option A or B might be the answer).

Step 1: Identify Potential Discontinuities

A rational function (like f(x)) is discontinuous when its denominator is zero. So, we need to find the values of x that make the denominator 0:

Denominator = 4x^2 - 12x = 0

Factor the denominator: 4x(x - 3) = 0

This gives us two possible values for x: x = 0 and x = 3.

Step 2: Verify Discontinuity Type at Each Point

Check if the function is defined (has a value) at these points.

x = 0: If we plug x = 0 in the original function, we get 0/0, which is indeterminate. This suggests a potential vertical asymptote at x = 0.

x = 3: If we plug x = 3 in the original function, the expression doesn't become 0/0. The function might have a hole or be continuous at x = 3.

Step 3: Analyze for Holes (Optional):

To further investigate x = 3, we can try to simplify the function by factoring the numerator (possible because the denominator is already factored). If the simplification gets rid of the term that causes the 0/0 at x = 3, it creates a hole.

can someone please help!!

Answers

yes what do you need help with?
I attached a screenshot with the question

Triangle (1):
The given triangle is a right-angled triangle. This means that the Pythagorean theorem can be applied.
This theorem is as follows:
(hypotenuse)² = (side1)² + (side2)²
Now, for the given we have:
side1 = t
side2 = 12
hypotenuse = 13
Substitute in the above formula and solve for t as follows:
(13)² = t² + (12)²
t² = (13)² - (12)²
t² = 25
t = ±√25
either t = 5 ..........> accepted value
or t = -5 ........> rejected as side length cannot be negative

Triangle (2):
The given triangle is a right-angled triangle. This means that the Pythagorean theorem can be applied.
This theorem is as follows:
(hypotenuse)² = (side1)² + (side2)²
Now, for the given we have:
side1 = 6
side2 = 9
hypotenuse = x
Substitute in the above formula and solve for x as follows:
x² = (6)² + (9)²
x² = 117
x = ±√117
either x = 3√13 ........> accepted value
or x = -3√13 ...........> rejected as side length cannot be negative

Hope this helps :)
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