Which substance cannot be broken down by a chemical change?

A) butanal
B) propene
C) gold
D) water

Answers

Answer 1

The substance that cannot be broken down by chemical change is [tex]\boxed{{\text{C) gold}}}[/tex].

Further Explanation:

Substance is the pure form of matter while a combination of atoms or molecules is termed as a mixture.

Types of substances:

1. Element

The simplest form of substance that cannot be further decomposed by any chemical means is called an element. Carbon, sulfur, and cobalt are some of the examples of elements.

2. Compound

When two or more different elements are held together by chemical methods, compounds are formed. These can further be decomposed into their corresponding constituents. The properties of compounds are very different from those of their constituent elements. NaCl, [tex]{\text{C}}{{\text{H}}_{\text{4}}}[/tex] and [tex]{{\text{H}}_{\text{2}}}{\text{O}}[/tex] are examples of compounds.

A) Butanal [tex]\left( {{{\text{C}}_4}{{\text{H}}_8}{\text{O}}} \right)[/tex] is made up of four carbon atoms, eight hydrogen atoms, and an oxygen atom so it is a compound. Therefore it can be broken down by chemical change.

B) Propene [tex]\left( {{{\text{C}}_{\text{3}}}{{\text{H}}_{\text{6}}}} \right)[/tex] is made up of three carbon atoms and six hydrogen atoms so it is a compound. Therefore it can be broken down by chemical change.

C) Gold [tex]\left( {{\text{Au}}} \right)[/tex] is an element so it is present in its simplest form. Therefore it cannot be broken down by chemical change.

D) Water [tex]\left( {{{\text{H}}_{\text{2}}}{\text{O}}} \right)[/tex] is made up of one oxygen and two hydrogen atoms so it is a compound. Therefore it can be broken down by chemical change.

Learn more:

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Answer details:

Grade: High School

Subject: Chemistry

Chapter: Elements, compounds, and mixtures

Keywords: substance, butanal, propene, gold, water, element, compound, chemical change, decomposed, simplest form, NaCl, CH4, carbon, sulfur, cobalt.

Answer 2
Final answer:

Gold, being an element, cannot be broken down further by a chemical change whereas butanal, propene, and water, being compounds, can be.

Explanation:

The substance which cannot be broken down by a chemical change is gold. This is because gold is an element. Elements are pure substances that are made from a single type of atom and cannot be broken down further by chemical methods. On the other hand, butanal, propene, and water are all compounds, which are substances formed when two or more chemical elements are chemically bonded together. Compounds can be decomposed into simpler substances, or their constituent elements, by chemical change.

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Related Questions

Coal power plants burn large amounts of coal, c(s), in an o 2 ​ (g) atmosphere to generate electricity. the chemical reaction responsible for producing this energy is shown below: c(s) + o 2 ​ (g) → co 2 ​ (g) determine the volume of co 2 ​ in liters produced when 100 metric ton of c(s) is completely burned in an o 2 ​ atmosphere. the density of co 2 ​ is 1.98 kg/m 3 (1 metric ton = 1000 kg; 1 m 3 = 1000 l)

Answers

Answer is: volume of carbon dioxide is 1,84·10⁸ l.
Chemical reaction: C + O₂ → CO₂.
m(C) = 100 t · 1000 kg/t = 100000 kg 
m(C) = 100000 kg · 1000 g/kg = 10⁸ g.
n(C) = m(C) ÷ M(C).
n(C) = 10⁸ g ÷ 12 g/mol.
n(C) = 8,33·10⁶ mol.
From chemical reaction: n(C) . n(CO₂) = 1 : 1.
n(CO₂) = 8,33·10⁶ mol.
m(CO₂) = 8,33·10⁶ mol · 44 g/mol.
m(CO₂)  = 3,66·10⁸ = 3,66·10⁵ kg.
V(CO₂) = 3,66·10⁵ kg ÷ 1,98 kg/m³ = 1,84·10⁵ m³.
V(CO₂) = 1,84·10⁵ m³ · 1000 l/m³ = 1,84·10⁸ l.

#1: What is the charge on an electrically neutral atom of hydrogen?

A. 1

B. 0

C. +1

D. +2
**My answer: B. 0

Answers

my answer is B.The electrical charge of the hydrogen atom is thought to be exactly zero. This is a consequence of the apparent equality of the magnitude of the electrical charges of the electron and the proton, and their opposite sign. The electrical charge of neutral atoms has been measured to be zero, with an uncertainty of something like 10^(-20) e, where e is the elementary charge.

#1: At STP, how many molecules of nitrogen gas are in 22.4 L?

A. 6.022 × 10^22

B. 6.022 × 10^23

C. 6.022 × 10^24

D. 6.022 × 10^25

**my answer: B

is that right?? @aaronq :)

Answers

At STP, 1 mol = 22.4

1 mol = 6.022 X 10^ 23

so your answer is right it is B 6.022 X 10^ 23

Water exists on other planets in the solar system. Life exists only on Earth because water exists as a _____ on Earth. liquid solid vapor gas

Answers

. Life exists only on Earth because water exists as a gas on earth
Hello!

Water exists on other planets in the solar system. Life exists only on Earth because water exists as a liquid on Earth.

Why?

The boiling point of water is 100 °C and the freezing point is 0 °C. A normal temperature on Earth is 25 °C, meaning that water is generally found in the liquid state on Earth.

Liquid water is essential for life because it is at the same time an essential molecule for photosynthesis (the basis of all energy processes needed for life), and a medium where nutrients and waste circulate in living beings.

Have a nice day!

What two elements comprise most of a nebula? question 5 options: hydrogen and helium hydrogen and nitrogen oxygen and hydrogen carbon and hydrogen helium and lithium?

Answers

hydrogen and helium and the most abundant elements in a nebula.

Which form of co2 transport accounts for the greatest amount of co2 transported in blood?

Answers

The greatest amount of CO2 transported in blood is in the form of bicarbonate in plasma. Most of the carbon dioxide is converted into bicarbonate with the help of carbonic anhydrase which is an enzyme. This enzyme converts carborn dioxide and water into bicarbonate and hydrogen ions. The bicarbonate in plasma accounts for about 70% of CO2.

In the reaction of aluminum bromide with ionized sodium bromide which compoiund is the lewis acid

Answers

The answer is A) Aluminum Bromide 
hope this helps :)

Answer:

Aluminium bromide

Explanation:

Thinking process:

The aluminium bromide has the following structure:

[tex]AlBr_{3}[/tex]

The compound is a Lewis acid.

Aluminium bromide has a vacant p-orbital so it accepts a lone pair of electrons and acts as a Lewis acid.

Sodium bromide, on the other hand, donates electrons and acts as a Lewis base like this:

[tex]AlBr_{3} + Br^{-} = AlBr^{-} _{4}[/tex]

Thus, clearly the bromide ion is a base, and it donates electrons.

For a reversible reaction where the substrate and product are in equilibrium, what will occur if an enzyme is added?

Answers

Answer: Nothing; the reaction will stay at equilibrium

There is no change in concentration at equilibrium because the rate of product formed is equal to the rate of product breakdown. When an enzyme is added, the rate of product formed and breaks will be increased. This will not shift the equilibrium because the rate of reaction is increased in both ways.

Of a non-volatile solute is dissolved in 365.0 g of water. the solute does not react with water nor dissociate in solution. assume that the resulting solution displays ideal raoult's law behaviour. at 70°c the vapour pressure of the solution is 231.16 torr. the vapour pressure of pure water at 70°c is 233.70 torr. calculate the molar mass of the solute (g/mol).

Answers

by using this formula of vapor pressure:
Pv(solu)= n Pv(water) 
when we have Pv(solu)=231.16 torr & Pv(water)= 233.7 torr
from this formula, we can get n (mole fraction of water) by substitution:
231.16 = n * 233.7
∴ n(mole fraction of water) = 0.99
so mole fraction of solution = 1 - 0.99 = 0.01
when no.of moles of water = mass weight / molar weight
                                             = 365g / 18g/mol = 20 moles
Total moles in solution =  moles of water / mole fraction of water
                                      = 20 / 0.99 =20.2
no. of moles of the solution= total moles in solution- moles of water
                                              = 20.2 - 20 = 0.2 moles
when we assumed the mass weight of the solution = 16 g (missing in your question should be given)
∴ molar mass = mass weight of solute / no. of moles of solute
                        = 16 g / 0.2 mol = 80 g/mol
 

How do scientists measure the strength of acids and bases describe this scale?

Answers

They use a pH meter. The scale is called pH scale, any value below 7 is acidic

At 22 °c an excess amount of a generic metal hydroxide m(oh)2 is mixed with pure water. the resulting equilibrium solution has a ph of 10.30. what is the ksp of the salt at 22 °c?

Answers

The balanced reaction equation:
M(OH)2 ↔ M^2+ + 2(OH)^-

and when the Ksp = [M^2+][OH-]^2
when PH + POH = 14
∴ POH = 14-10.3= 3.7 
and when POH = - ㏒ [OH-]
 3.7 = -㏒[OH-]
∴[OH] = 2x10^-4 
and when [M^2+] = 1/2[OH-]
∴[M^2+] = (2x10^-4) / 2 = 0.0001 M
So, by substitution in Ksp formula:
∴Ksp = (0.0001 * (2x10^-4)^2 = 4x10^-12

1.985 x 10⁻¹²

Further explanation

Given:

 At 22°C an excess amount of a generic metal hydroxide M(OH)₂ is mixed with pure water. The resulting equilibrium solution has a pH of 10.30.

Question:

What is the Ksp of the salt at 22°C?

The Process:

Step-1

Because the pH is above 7, we convert it to pOH.

[tex]\boxed{ \ pH + pOH = 14 \ } \rightarrow \boxed{ \ pOH = 14 - pH \ }[/tex]

pOH = 14 - 10.30

Hence, the pOH value is 3.70.

Step-2

We use the pOH to get the [tex][OH^-].[/tex]

[tex]\boxed{ \ pOH = -log[OH^-] \ } \rightarrow \boxed{ \ [OH^-] = 10^{-pOH} \ }[/tex]

[tex]\boxed{ \ [OH^-] = 10^{-3.70} \ }[/tex]

Therefore, [tex]\boxed{ \ [OH^-] = 1.995 \times 10^{-4} \ molar \ }[/tex]

Step-3

Let us write the chemical equation in equilibrium of ions.:

[tex]\boxed{ \ Mg(OH)_2 \rightleftharpoons Mg^{2+} + 2OH^- \ }[/tex]

Notice that based on comparison of the coefficients, then [tex]\boxed{ \ [Mg^{2+}] = \frac{1}{2}[OH^-] \ }[/tex]

[tex]\boxed{ \ [OH^-] = 1.995 \times 10^{-4} \ M \ }[/tex][tex]\boxed{ \ [Mg^{2+}] = \frac{1}{2} \times 1.995 \times 10^{-4} = 9.975 \times 10^{-5} \ M \ }[/tex]

Step-4

The Ksp expression:

[tex]\boxed{ \ K_{sp} = [Mg^{2+}][OH^-]^2 \ }[/tex]

Let's calculate the Ksp value.

[tex]\boxed{ \ K_{sp} = [1.995 \times 10^{-4}][9.975 \times 10^{-5}]^2 \ }[/tex]

Thus, the Ksp is [tex]\boxed{ \ 1.985 \times 10^{-12} \ }[/tex]

Learn more  Write the equilibrium constant for the reaction  https://brainly.com/question/10608589Calculating the pH value of weak base https://brainly.com/question/9040743About electrolyte and nonelectrolyte solutions https://brainly.com/question/5404753

Keywords: Ksp, equilibrium, pH, pOH, metal hydroxide, M(OH)₂, pure water, the chemical equation, ions,

Write a balanced chemical equation for the standard formation reaction of solid mercury(ii) oxide .

Answers

Final answer:

The standard formation reaction for solid mercury (II) oxide is Hg (s) + 1/2 O2 (g) → HgO (s), involving the transformation of elemental mercury and oxygen into the compound.

Explanation:

The standard formation reaction refers to the formation of 1 mole of a compound directly from its elements in their standard states. For mercury (II) oxide, the elements in their standard states are mercury (Hg) and oxygen (O2.

The standard formation reaction for solid mercury (II) oxide is:

Hg (s) + 1/2 O2 (g) → HgO (s)

Note that Hg is in its solid elemental state, while O2 is in its gaseous elemental state, which are their respective standard states at room temperature and one atmospheric pressure.

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The balanced chemical equation for the standard formation reaction of solid mercury(II) oxide is: [tex]2Hg(l) + 1O_2(g) \rightarrow 2HgO(s)[/tex] . This involves mercury in its liquid state and oxygen in its gaseous state forming one mole of HgO.

To answer the question, "Write a balanced chemical equation for the standard formation reaction of solid mercury(II) oxide," we need to understand and apply the concept of standard formation reactions.

A standard formation reaction describes the formation of one mole of a compound from its elements in their standard states. For mercury(II) oxide (HgO), the elements mercury (Hg) and oxygen ([tex]O_2[/tex]) in their standard states are needed.

The balanced chemical equation for the formation of solid mercury(II) oxide is:

[tex]2Hg(l) + 1O_2(g) \rightarrow 2HgO(s)[/tex]

Here are the steps to write this equation:

Identify the reactants in their standard states: mercury (liquid Hg) and oxygen (gas [tex]O_2[/tex]).Write a chemical equation for the formation of one mole of HgO.Balance the equation. Since HgO contains one mercury and one oxygen atom, we need one mole of Hg and one-half mole (i.e., one atom) of [tex]O_2[/tex].

This equation represents the standard formation of mercury(II) oxide.

Select the compounds below that are covalent: AuBr3 B2H6 HCl Ca3(PO4)2 MnO2 Sn(SO4) NH3 Al(OH)3 NO2 S2F4

Answers

covalent  bond  is  a  bond  between  two  non  metal   and   it  involve  sharing   of  electrons  between  the  non    metals.  in  the  compounds  above  the one  which  are  covalent  include  the   following
B2H6,  HCl,  NH3, NO2  and  S2F4  since  their  bond  involve  between  two  non  metals

Answers:

B2H6

HCl

Sn(SO4)

NH3

Al(OH)3

NO2

S2F4

I did the quiz, it's correct.

What is the difference between two atoms of carbon having the same number of neutrons?
a. nothing
b. the number of protons
c. the number of electrons
d. there may be differences in how they react with oxygen 2. (10 pt) what is the difference between an atom of silver and an atom of gold?
a. one is new and the other is old.
b. their net electrical charges are different.
c. their atomic masses are different.
d. more people would rather have one gold atom than a lot of gold?

Answers

b)The number of protons.
c) their atomic masses are different.

Which of the following activities will contribute most to changing climate and global warming? Paddling a canoe, driving a car, skiing down a mountain, riding a bike

Answers

If you're talking about increasing global warming, then driving a car would be the answer. If you're trying to help, riding a bike is probably the best.

Answer: driving a car

Driving a car will contribute most to changing climate and global warming due to the emission of particles and gases generated from incomplete combustion of fuel in the vehicle. These gases includes carbon dioxide, carbon monoxide, hydrogen sulfides these gases can contribute to the  increase in the global temperatures. These can contribute to drastic fluctuations of the climates such as dry and hot climatic conditions.

Select the correct electron configuration for boron. (Atomic number 5)

Answers

Boron is 5th element in periodic table. It has the electronic configuration 1s², 2s² 2p¹. Where, the last three electrons are called valence electrons.

What is boron?

Boron is 5th element in periodic table. It is classified in 13th group of p-block in periodic table. Boron is known as metalloid based on its properties.

Metalloids are  elements showing properties intermediate to that of gases and metals. Other metalloids are silicon, arsenic etc.

The electronic configuration of en elements representing the filling of two electrons from lower energy levels to higher energy levels. each element have characteristic electronic configuration.

Boron have total 5 electrons in which 2 are inner electrons and three electrons are filled in the outermost shell hence its electronic configuration is written as 1s², 2s² 2p¹.

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In plants, the first product of carbon fixation is the three-carbon compound 3-pga formed in the calvin cycle. 2. when such plants close their stomata on hot, dry days to conserve water, builds up in the leaf and is added to rubp in place of co2. a two-carbon product of this reaction is broken down to co2, consuming atp and generating no sugar. 3. the apparently wasteful process described in sentence 2 is called . 4. in plants, co2 is first fixed into a four-carbon compound, which moves into bundle-sheath cells and releases co2 to the calvin cycle. 5. in plants, stomata are open at night, and co2 is first fixed into a four-carbon compound, which releases co2 to the calvin cycle during the day. 6. in all three types of plants, the enzyme brings co2 into the calvin cycle.

Answers

Final answer:

The Calvin cycle is a process of carbon fixation in plants, where CO₂ is turned into organic molecules using RuBisCO. C3 plants experience photorespiration under high O₂ conditions due to closed stomata in dry weather, while C4 and CAM plants have adaptations to more efficiently fix CO₂.

Explanation:Calvin Cycle and Carbon Fixation in Plants

In plants, the Calvin cycle is significant for carbon fixation during photosynthesis. During this cycle, CO₂ is incorporated into organic molecules in the chloroplast's stroma through three main stages: fixation, reduction, and regeneration. The enzyme RuBisCO catalyzes the first major step of the Calvin cycle, where CO₂ and RuBP combine to form a six-carbon compound that quickly splits into two molecules of 3-phosphoglyceric acid (3-PGA), a three-carbon compound.

During hot and dry conditions, some plants (C3 plants) close their stomata to conserve water, leading to a rise in O₂ compared to CO₂ inside the leaf. This causes RuBisCO to add O₂ to RuBP instead, leading to a process called photorespiration, in which a two-carbon molecule is produced, is broken down to CO₂, and ATP is used without generating sugar—considered a wasteful process by some. Alternatively, C4 plants fix CO₂ into a four-carbon compound in a separate compartment to overcome low CO₂ concentrations and shuttle this compound to bundle-sheath cells, where it releases CO₂ for fixation by RuBisCO.

Additionally, cam plants open stomata at night to fix CO₂ into a four-carbon compound, storing it until daylight when it releases CO₂ for the Calvin cycle, adapting to arid conditions. All three types of plants ultimately depend on RuBisCO to incorporate CO₂ into the Calvin cycle to produce sugars needed for growth and energy storage.

In photosynthesis, the Calvin Cycle initiates carbon fixation, producing the three-carbon compound 3-phosphoglycerate (3-PGA). On hot, dry days, plants close stomata to conserve water, leading to the buildup of oxygen and the wasteful process of photorespiration. Some plants adopt C4 or CAM pathways to optimize carbon fixation and minimize water loss. In the C4 pathway, CO2 is first fixed into a four-carbon compound, while in CAM plants, this occurs at night. Despite these adaptations, all plant types rely on the enzyme RuBisCO to bring CO2 into the Calvin Cycle, driving the synthesis of organic molecules essential for plant growth.

1. In the Calvin Cycle, the first product of carbon fixation is the three-carbon compound 3-phosphoglycerate (3-PGA). This process occurs in the stroma of chloroplasts during photosynthesis.

2. When plants close their stomata on hot, dry days to conserve water, oxygen (O2) builds up in the leaf and is added to ribulose-1,5-bisphosphate (RuBP) in place of carbon dioxide (CO2). This process is called photorespiration. A two-carbon product, glycolate, is formed and later broken down to CO2, consuming ATP and generating no sugar.

3. The apparently wasteful process described in sentence 2 is called photorespiration. While it consumes energy and does not contribute to sugar production, it is considered wasteful because it counteracts the efficiency of the Calvin Cycle in fixing carbon.

4. In certain plants, CO2 is first fixed into a four-carbon compound, oxaloacetate, through the C4 pathway. This compound moves into bundle-sheath cells, where it releases CO2 to the Calvin Cycle. This adaptation enhances the efficiency of carbon fixation, especially in conditions with high temperatures and intense sunlight.

5. In CAM (Crassulacean Acid Metabolism) plants, stomata are open at night, and CO2 is first fixed into a four-carbon compound, malate. This compound releases CO2 to the Calvin Cycle during the day, allowing plants to reduce water loss by opening stomata during cooler nighttime hours.

6. In all three types of plants (C3, C4, and CAM), the enzyme ribulose-1,5-bisphosphate carboxylase/oxygenase (RuBisCO) brings CO2 into the Calvin Cycle. RuBisCO catalyzes the initial step of carbon fixation by incorporating CO2 into RuBP, initiating the synthesis of organic molecules in the Calvin Cycle.

what is the correct order of colors from a prism

Answers

The colors are separated into the rainbow colors of red, orange, yellow, green, blue, indigo and violet (I always remember ROY G BIV to remember the colors).

Hope this helps! :)

A student is told that both energy and mass must be conserved in every chemical reaction. She measures the mass of Hydrochloric acid and a zinc strip separately. She then places the zinc strip into the acid and bubbles form as the zinc looks like it disappears. The combined mass afterward is less than the original. Which of these can explain this result?

Answers

Conservative mass states that the sum of the mass of the products produced must be equal to that of the reactants. The combined mass is less as the gas was evolved.

What is the conservation of mass?

The law of mass conservation is about the conservation of the energy and the mass of the chemical involved in the reaction. It states that the combined mass of the products of the reaction is always conserved to that of the chemical reactants.

The mass of the reaction was reduced compared to the mass of the reactants as during the acidification of the zinc strip hydrogen gas bubbles were released that had some of the mass.

Therefore, the formation of the gas depicts that the gas had some of the mass that escaped in the atmosphere.

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Final answer:

The conservation of mass principle dictates that the total mass of the products equals the total mass of the reactants in a chemical reaction. The observed mass loss in the student's experiment is due to the unmeasured hydrogen gas produced, not a violation of mass conservation. Balancing chemical equations reflects this law of conservation.

Explanation:

The experiment involving the reaction between zinc and hydrochloric acid showcases the law of conservation of mass. Despite the observation that the combined mass appears to be less after the reaction, it is likely due to the gas produced (hydrogen gas in this case) escaping the system, which was not taken into account when measuring the mass afterward. According to the law of conservation of mass, the total mass of the products in a chemical reaction must equal the total mass of the reactants. The missing mass corresponds to the hydrogen gas that was not captured or measured after the reaction.

Furthermore, although there is a transfer of energy and the resulting substances may have different physical and chemical properties, this does not affect the mass conservation principle. For instance, when magnesium metal reacts with oxygen to form magnesium oxide in a sealed vessel, the total mass remains unchanged before and after the reaction, demonstrating the conservation of mass.

It is crucial in chemistry to ensure that chemical equations are balanced, as this reflects the conservation of matter, where the number of atoms of each element in the reactants equals the number of atoms of each element in the products.

Water molecules form which type of bond with other water molecules?
a. disulfide bridges
b. covalent bonds
c. hydrogen bonds
d. ionic bonds
e. van der waals bonds

Answers

I believe the answer is C, hydrogen bonds. A water molecule consist of two hydrogen atoms bonded to an oxygen atom, and a bent overall structure. Water molecules can only form hydrogen bonds between the partially positively charged hydrogen atoms in water molecules and a partially negatively charged atom in another molecules say oxygen in another water molecule.

What would be the resulting molaritybof a solution made by dissolving 17.8 g of LiF in enough water to make a 915-millimeter solution?

Answers

Answer: Molarity of solution is 0.751 M. 

Reason:
Given: weight of solute (LiF) = 17.8 g, volume of solution = 915 ml = 0.915 l

We know that,
Molarity = [tex] \frac{\text{weight of solute (g)}}{\text{Molecular weight X Volume of solution(l)}} [/tex]

Molecular Weight of LiF = 25.9 g/mol. 

∴, Molarity = [tex] \frac{17.8}{25.9X0.915} [/tex]
                 = 0.751 M

Answer:

0.751 M

Explanation:

Given:

Mass of LiF (solute), m = 17.8 g

Volume of water (solvent), V = 915 ml = 0.915 L

Formula:

Molar mass of LiF = 25.9 g/mol

[tex]Molarity = \frac{moles of solute}{Volume of solution}[/tex]

[tex]Moles LiF= \frac{Mass}{Molar Mass} = \frac{17.8 g}{25.9 g/mol} = 0.6873 moles[/tex]

[tex]Molarity = \frac{0.6873 moles}{0.915 L} = 0.751 moles/L[/tex]

_________ 1. an allotrope of carbon that is soft and can be used as a lubricant is ______.
a. silicon
b. diamond
c. sand
d. graphite _________ 2. the process by which a solid changes directly to a gas without first becoming a liquid is called ______.
a. condensation
b. ionization
c. sublimation
d. evaporation _________ 3. in the gaseous state ______ form diatomic covalent molecules.
a. noble gasses
c. alkaline earth metals
b. alkali metals
d. halogens _________ 4. when hydrogen reacts with the active metals, it ______.
a. shares electrons
c. loses one electron
b. gains one electron
d. loses two electrons _________ 5. different forms of the same element that have different properties because of different atom arrangements are called ______.
a. allotropes
b. carbonsc. silicons
d. graphites _________ 6. at room temperature, most metals are ______.
a. liquids
b. solids
c. radioactive
d. gases _________ 7. an allotrope of carbon that is hard and is often used in jewelry is ______.
a. silver
b. diamond
c. quartz
d. graphite _________ 8. metals can be used as wire because they are ______.
a. ductile
b. malleable
c. shiny
d. alloys _________ 9. the ______ often occur in nature as uncombined elements.
a. alkaline earth metals
c. actinide series
b. alkali metals
d. transition elements

Answers

1. An allotrope of carbon that is soft and can be used as a lubricant is d. graphite.
Graphite is the most stable allotrope of carbon under standard conditions (pressure and temperature). In graphite carbon atoms have sp2 hybridization, because of that graphite has ability to conduct electricity and heat.

2. The process by which a solid changes directly to a gas without first becoming a liquid is called c. sublimation.
Sublimation is an endothermic process. For example dry ice (carbon(IV) oxide in solid state) is used because of sublimation in nightclubs, fog machines, at theaters, haunted house attractions.

3. In the gaseous state d. halogens form diatomic covalent molecules.
Halogen diatomic molecules (17 group in the periodic table, halogen means "salt producing) in the gaseous state in room temperature are fluorine (F₂) and chlorine (Cl₂). Both molecules have single covalent bond and they are very reactive.

4. When hydrogen reacts with the active metals, it b. gains one electron.
Active metals are I group of Periodic table of elements (alkaline metals). Alkaline metals are lithium, sodium, rubidium, potassium, cesium. They have low ionization energy and lose one electron very easy. Compounds with hydrogen with this metals are called hydrides.

5. Different forms of the same element that have different properties because of different atom arrangements are called a. allotropes.
Carbon has many allotropes, but two most important are graphite and diamomd. Graphite has sp2 and diamond has sp3 hybridization of carbon atoms, because of that graphite conduct electricity and diamond not.

6. At room temperature, most metals are b. solids.
Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.
They also form crystal lattice and because of that has high melting points.

7. An allotrope of carbon that is hard and is often used in jewelry is b. diamond.
In diamond carbon atoms are arranged in the face centered cubic crystal structure called a diamond lattice.
Diamond has very strong covalent bonds between carbon atoms and because of that it has the highest hardness and thermal conductivity of any bulk substance. 

8. Metals can be used as wire because they are a. ductile.
Ductility is a measure of a material's (in this example metal) ability to undergo deformation before rupture. For example gold is very ductile and can be drawn into a monoatomic wire.
Malleability is a material's ability to deform under compressive stress.

9. The d. transition elements often occur in nature as uncombined elements.
Uncombined elements are in elemental form and do not attache with other elements. Several transition elements (metals) like gold, silver, rhodium, palladium and platinum are unreactive and are resistant to oxidation and corrosion.


A large weather balloon requires plenty of helium gas in order to ascend into the atmosphere to take measurements. If the balloon has a volume of 100,000 liters, about how many moles of helium gas would be required to fill the balloon to a pressure of 1 atm and a temperature of 27 degrees C?

A. 531 moles
B. 1394 moles
C. 4063 moles
D. 5280 moles

Answers

The equation PV=nRT. where P is the pressure in atmospheres, V is the volume in liters, n the moles , T the temperature in kelvin and R is the ideal gas constant. Temperature = 27 +273 = 300 K, R= 0.08206
Thus, n =PV/RT
             = ( 1 ×100,000)/(300×0.08206)
             = 4062.0684
             ≈ 4063 Moles
Therefore, about 4063 moles would be required

The transition metals are located in what block of the periodic table
S block
P block
D block
F block

Answers

Located in the D block
Final answer:

Transition metals are positioned in the D block of the periodic table. They possess unique characteristics such as higher conductivity and flexibility in oxidation states, making them of great utility.

Explanation:

The transition metals are found in the D block of the periodic table. These elements, which include familiar metals like iron, copper, and silver, have unique chemical and physical properties that make them particularly useful. For instance, they're often good conductors of heat and electricity, and many of them exhibit a range of oxidation states in their compounds. Besides, they are also noted for their ability to form complex compounds.

Learn more about transition metals here:

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I am confused. Can yall help me answer this question? Also if you do, please show your work.
KOH + HCl →
If 30mL of 0.5M KOH is needed to neutralize 2M HCl, what was the volume of the acid?

Answers

Answer is: volume of the acid is 0,075 L.
Chemical reaction: KOH + HCl → KCl + H₂O.
V(KOH) = 30 mL · 0,001 L/mL = 0,3 L.
c(KOH) = 0,5 M = 0,5 mol/L.
c(HCl) = 2 M = 2 mol/L.
V(HCl) = ?
From chemical reaction n(KOH) : n(HCl) = 1 : 1.
n(KOH) = n(HCl).
c(KOH) · V(KOH) = c(HCl) · V(HCl).
0,5M · 0,3 L = 2M · V(HCl).
V(HCl) = 0,075 L.

One brand of laundry bleach is an aqueous solution containing 4.00% sodium hypochlorite (naocl) by mass. you may want to reference (pages 586 - 592) section 13.5 while completing this problem. part a what is the molarity of this solution? (assume a density of 1.02 g/ml.)

Answers

Answer is: molarity of this solution is 0,55 mol/l.
If we use 100 ml of solution:
V(solution) = 100 ml ÷ 1000 ml/l = 0,1 l.
ω(NaClO) = 4,00% = 0,04.
d(solution) = 1,02 g/ml.
m(solution) = V(solution) · d(solution).
m(solution) = 100 ml · 1,02 g/ml.
m(solution) = 102 g.
m(NaClO) = ω(NaClO) · m(solution).
m(NaClO) = 0,04 · 102 g = 4,08 g.
n(NaClO) = m(NaClO) ÷ M(NaClO).
n(NaClO) = 4,08 g ÷ 74,44 g/mol = 0,055 mol.
c(NaClO) = 0,055 mol ÷ 0,1 l = 0,55 mol/l.

Answer:  B. 0.599

Explanation: If you are using usatestprep 8^)

A hot air balloon is filled with 1.35 × 106 l of an ideal gas on a cool morning (11 °c). the air is heated to 127 °c. what is the volume of the air in the balloon after it is heated? assume that none of the gas escapes from the balloon.

Answers

Answer:
Volume = 1.901 * 10^6 liters

Explanation:
We will assume that the pressure of the gas is kept constant.
Charles's law states that: "At constant pressure, the volume of a given mass of gas is directly related to its temperature in kelvin."
This means that:
V1 / T1 = V2 / T2
where:
V1 is the initial volume = 1.35 × 10^6 liters
T1 is the initial temperature = 11 + 273 = 284 degrees kelvin
V2 is the final volume that we want to find
T2 is the final temperature = 127 + 273 = 400 degrees kelvin

Substitute with the givens in the above equation to get the final volume as follows:
V1 / T1 = V2 / T2
(1.35 × 10^6) / (284) = V2 / (400)
V2 = 400 * [(1.35 × 10^6) / (284)]
V2 = 1.901 * 10^6 liters

Hope this helps :)

From the Charle's law V1/T1=V2/T2
V1= 1.35 ×10^6 L
T1= 11 +273 = 284 K
T2 = 127+273 = 400 k 
Therefore, V2 = V1T2/T1
                       = (1.35 ×10^6 × 400)/284

                       = 1.901 ×10^6 Liters

Which is not possible based on the characteristics of fluids? allowing 5 liters of compressed air to expand to a volume of 100 liters filling a balloon using helium gas from a pressurized tank compressing 2 liters of water into a 1-liter volume compressing 10 liters of oxygen gas into a 1-liter volume?

Answers

The question presents 4 scenarios in which one does not agree with the properties of fluids, so we will look at each option:

"Allowing 5 L of compressed air to expand to a volume of 100 L"

Gaseous mixtures will follow the gas law of PV = nRT. If a 5 L volume of gas were to expand to 100 L, the system would simply decrease significantly in pressure to make up for the increased volume. Therefore, this scenario is allowed.

"Filling a balloon using helium gas from a pressurized tank"

In this scenario the gas is in a container with a very high pressure, and the helium is moving to a balloon which is a container of a much lower pressure. Gas will certainly move from an area of high pressure to an area of low pressure, therefore, this scenario is allowed.

"Compressing 10 L of oxygen gas into a 1 L volume"

Again, following PV = nRT, a 10 L volume of oxygen that is compressed to 1 L will simply result in a system of much higher pressure to make up for the decreased volume, and this scenario is allowed.

"Compressing 2 L of water into a 1 L volume"

While gases can certainly be compressed into smaller volumes or expand into greater volumes, the same is not necessarily true for pure liquids. A 2 L volume of water cannot be compressed to fit into a 1 L container as the pure liquid has a finite volume. Therefore, the correct answer is: Compressing 2 L of water into a 1 L volume

Answer:

compressing 2 liters of water into a 1-liter volume

Explanation:

Match each root with its meaning. (5 points) 1. Grad/gress 2. Ject 3. Meter 4. Junct 5. Loc a. Place b. To throw c. Measure d. To step e. To join

Answers

1. To step
2. To throw
3. Measure
4. To join
5. Place

Answer:

what he said

Explanation:

During surgery, a patient receives 6.0 pt of plasma. how many milliliters of plasma were given? express the volume in milliliters to two significant figures.

Answers

The patient received 2839.059mL.

Answer : The volume of plasma given to the patient were, [tex]2.8\times 10^{3}ml[/tex]

Explanation :

As we are given that a patient receives 6.0 pints of plasma. Now we have to calculate the volume in milliliters.

As we know that, 1 pints is equal to 473.176 milliliters.

As, 1 pints = 473.176 milliliters

So, 6.0 pints = [tex]\frac{473.176milliliters}{1pint}\times 6.0pints=2839.056milliliter[/tex]

The volume in milliliters to two significant figures is, [tex]2.8\times 10^{3}ml[/tex]

Therefore, the volume of plasma given to the patient were, [tex]2.8\times 10^{3}ml[/tex]

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