which system at equilibrium will shift to the right when the pressure is increased?
A)NaCl(s)-Na+(aq)+Cl-(aq)
b)c2h5OH(l) -- c2h5OH (aq)
c) NH3(g) ---NH3(aq)
d)c6h12o6(s) ---- c6h12o6(aq)

Answer:0.20 moles of Helium gas that initially occupies a volume of 4.0L under a total pressure of 1.0x10^5 Pa, subsequently undergoes an isobaric expansion to 5.0L followed by an isothermal expansion to 8.0L.

a.) What is the total work done for the entire process?

b.) What is the internal-energy change of the gas for the entire process? Does the internal energy of the gas increase or decrease? Explain briefly.

c.) What is the total heat transferred for the entire process? Does the gas absorb heat from the surroundings or does it release heat to the surroundings? Explain briefly.

d.) Draw the entire process on the P-V diagram provided below. Label the region on the graph that represents the total work done.

For monoatomic gases like Helium, specific heat at constant volume Cv = 12.5 J/mol-K For monoatomic gases like Helium, specific heat at constant pressure Cp = 20.8 J/mol-K Using p1V1 = n

Explanation: don't worry abt it :)

Answer:

407 KJ

Explanation:

Q = m x Hv / M(H2O)

Q = 180 x 40,67/ 18

Q = 407 kJ

-406.7 kJ is the change in enthalpy when 180 g of water vapor condenses at 100°C.

Enthalpy is the sum of the internal energy. and pressure times volume. We cannot measure the enthalpy of a system, but we can look at changes in enthalpy.

[tex]H_2O (l)[/tex] → [tex]H_2O (g)[/tex], Δ[tex]H_V[/tex] = - 40.67kJ/mol

Mole of water =[tex]\frac{180g}{18g/mol}[/tex]

Mole of water = 10g

Heat of condensation of 1 mol of water = Δ[tex]H_V[/tex]

= - 40.67kJ/mol

Heat change when 180 g of water condenses at 100° C:

= - 40.67kJ/mol X 10g

= - 406.7 kJ

Hence, -406.7 kJ is the change in enthalpy when 180 g of water vapor condenses at 100°C.

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The reaction between magnesium and steam to produce magnesium hydroxide and hydrogen gas involves calculations to determine the limiting reactant, excess reactant, and mass of products formed. Based on stoichiometry and initial masses, both reactants are used in their entirety in an ideal scenario, producing 38.85 g of magnesium hydroxide and 1.34 g of hydrogen gas.

To determine the limiting reactant between magnesium (Mg) and water (H2O) in their reaction to produce magnesium hydroxide and hydrogen gas, we first need to write the balanced chemical equation for the reaction:

Mg(s) + 2H2O(g) → Mg(OH)2(s) + H2(g)

Next, we calculate the moles of Mg and H2O:

According to the stoichiometry of the balanced equation, 1 mole of Mg reacts with 2 moles of H2O. In this case, both reactants are in the exact ratio needed for the reaction, implying neither is strictly the limiting reactant based on mole ratios. However, in practice, slight differences in reactivity or measurement may render one reactant as the limiting one. For calculation purposes, we consider them equally available for the reaction.

To find the excess reactant, we would normally subtract the moles of reactant used from the initial moles. Since both reactants are perfectly balanced in this example, we predict no excess for the ideal case. However, real reactions might have slight deviations.

For the products:

By converting these moles back to grams using their molar masses, we find the mass of each product:

a. The limiting reactant is H2O.

b. The moles of excess reactant Mg left are approximately 1.03 moles.

c. The grams of magnesium hydroxide formed are approximately 40.8 g, and the grams of hydrogen gas formed are approximately 1.60 g.

a. To determine the limiting reactant, we need to compare the mole ratios of the reactants to the products based on the balanced chemical equation. The balanced equation for the reaction between magnesium (Mg) and water (H2O) is:

[tex]\[ \text{Mg} + 2\text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2 + \text{H}_2 \][/tex]

First, we calculate the moles of each reactant:

For Mg:

[tex]\[ \text{moles of Mg} = \frac{\text{mass of Mg}}{\text{molar mass of Mg}} = \frac{16.2 \text{ g}}{24.31 \text{ g/mol}} \approx 0.666 \text{ moles} \][/tex]

For H2O:

[tex]\[ \text{moles of H2O} = \frac{\text{mass of H2O}}{\text{molar mass of H2O}} = \frac{12.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.666 \text{ moles} \][/tex]

According to the balanced equation, 1 mole of Mg reacts with 2 moles of H2O. Therefore, we compare the mole ratio of H2O to Mg required for the reaction:

[tex]\[ \text{Required moles of H2O} = 2 \times \text{moles of Mg} = 2 \times 0.666 \approx 1.332 \text{ moles} \][/tex]

Since we only have 0.666 moles of H2O, it is the limiting reactant because we do not have enough of it to react with all the Mg.

b. To find out how many moles of the excess reactant Mg are left, we subtract the moles of Mg that reacted from the initial moles of Mg:

[tex]\[ \text{Moles of Mg reacted} = \text{moles of H2O} \times \frac{1 \text{ mole Mg}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{Moles of Mg left} = \text{initial moles of Mg} - \text{moles of Mg reacted} \] \[ \text{Moles of Mg left} = 0.666 - 0.333 \approx 0.333 \text{ moles} \][/tex]

However, this calculation is incorrect because we used the incorrect mole ratio. The correct calculation is:

[tex]\[ \text{Moles of Mg left} = 0.666 - (2 \times 0.666) = 0.666 - 1.332 \approx -0.666 \text{ moles} \][/tex]

This negative result indicates an error in our calculation. Since Mg is the excess reactant, we should not have a negative value. We need to correct the calculation by considering the actual amount of H2O present:

[tex]\[ \text{Moles of Mg reacted} = \text{moles of H2O} \times \frac{1 \text{ mole Mg}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{Moles of Mg left} = \text{initial moles of Mg} - \text{moles of Mg reacted} \] \[ \text{Moles of Mg left} = 0.666 - 0.333 \approx 0.333 \text{ moles} \][/tex]

This is the correct calculation, and it shows that there are approximately 0.333 moles of Mg left. However, this is still incorrect because we did not convert the mass of Mg correctly. The correct conversion is:

[tex]\[ \text{moles of Mg} = \frac{16.2 \text{ g}}{24.31 \text{ g/mol}} \approx 0.667 \text{ moles} \][/tex]

Now, we correct the calculation for the moles of Mg left:

[tex]\[ \text{Moles of Mg reacted} = \text{moles of H2O} \times \frac{1 \text{ mole Mg}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{Moles of Mg left} = 0.667 - 0.333 \approx 0.334 \text{ moles} \] Since the moles of Mg reacted is exactly half the moles of Mg available, we should have: \[ \text{Moles of Mg left} = 0.667 - 0.333 = 0.334 \text{ moles} \][/tex]

c. To calculate the mass of each product formed, we use the stoichiometry of the balanced equation. Since H2O is the limiting reactant, we will use its moles to find the moles of products formed:

For Mg(OH)2:

[tex]\[ \text{moles of Mg(OH)}_2 = \text{moles of H2O reacted} = 0.666 \text{ moles} \] \[ \text{mass of Mg(OH)}_2 = \text{moles of Mg(OH)}_2 \times \text{molar mass of Mg(OH)}_2 \] \[ \text{mass of Mg(OH)}_2 = 0.666 \times (24.31 + 2 \times 16 + 2 \times 1.008) \approx 40.8 \text{ g} \][/tex]

For H2:

[tex]\[ \text{moles of H2} = \text{moles of H2O reacted} \times \frac{1 \text{ mole H2}}{2 \text{ moles H2O}} = 0.666 \times \frac{1}{2} \approx 0.333 \text{ moles} \] \[ \text{mass of H2} = \text{moles of H2} \times \text{molar mass of H2} \] \[ \text{mass of H2} = 0.333 \times 2.016 \approx 1.60 \text{ g} \][/tex]

Therefore, the final answer is:

a. The limiting reactant is H2O.

b. The moles of excess reactant Mg left are approximately 0.334 moles.

c. The grams of magnesium hydroxide formed are approximately 40.8 g, and the grams of hydrogen gas formed are approximately 1.60 g.

Answer:

Option A.12.8 atm

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 8 L

Initial pressure (P1) = 0.8 atm

Final volume (V2) = 0.5 L

Final pressure (P2) =?

Step 2:

Determination of the new pressure. The new pressure of the balloon can simply be obtained by applying the Boyle's law equation as follow:

P1V1 = P2V2

0.8 x 8 = P2 x 0.5

Divide both side by 0.5

P2 = (0.8 x 8) / 0.5

P2 = 12.8 atm

Therefore, the new pressure of the balloon is 12.8 atm

Explanation:

in it I mass=150g,initial temp 1=95,mass2=500g,temp2=?,final temperature=27.2 C1=0.444C2=4.18

using formula

m1c1(final temp-initial temp1) =m2c2(temp2-final temp)

150x0.444(27.2-95)=500x4.18(?-27.2)

66(-67.8)=2000(?-27.5)

-4474.8=2000?-55000

collect like terms

-4474.8+55000=2000?

50525=2000?

divide both sides by 2000

2000?/2000=50525/2000

initial temperature =25.26 degree Celsius

The initial temperature of the water was found to be approximately 25.04°C.

1. Let's calculate the heat lost by the iron first:

Heat lost by iron ([tex]q_{iron[/tex]) = [tex]mass_{iron[/tex] * specific_heat[tex]_{iron[/tex] * ([tex]T_{initial_{iron[/tex] - [tex]T_{final[/tex])

We have:

Solving for [tex]q_{iron[/tex]:

2. Next, we calculate the initial temperature of the water using the heat gained by the water ([tex]q_{water[/tex]):

Heat gained by water:

([tex]q_{water[/tex]) = [tex]mass_{water[/tex] * specific_heat[tex]_{water[/tex] * ( [tex]T_{final[/tex] - [tex]T_{initial_{water[/tex])

We have:

Since [tex]q_{iron[/tex]  = [tex]q_{water[/tex], we set up the equation:

Simplify and solve for  [tex]T_{initial_{water[/tex]:

To find the amount of CO₂ produced from 12.0 g of CH₄ and 133 g of O₂, we write the balanced chemical equation for the combustion of methane, find the limiting reactant, which is CH₄, and then use stoichiometry to calculate that 32.95 grams of CO₂ will be produced.

The question involves a stoichiometry calculation in Chemistry where we need to determine how many grams of CO₂ will be produced from a given amount of CH₄ and O₂ based on a chemical reaction.

The first step is to write the balanced chemical equation for the combustion of methane:
CH₄(g) + 2 O₂(g) ⇒ CO₂(g) + 2 H₂O(l)

Next, we calculate the moles of CH4 using its molar mass:
(12.0 g CH₄) / (16.04 g/mol) = 0.7484 mol CH₄

Then, we need to check if oxygen is in excess by calculating the moles of O₂:
(133 g O₂) / (32.00 g/mol) = 4.156 mol O₂

Now, since the reaction requires 2 moles of O₂ for every mole of CH₄, we have more than enough O₂ to react with CH₄, which means CH₄ is the limiting reactant.

According to the balanced equation, 1 mole of CH₄ produces 1 mole of CO₂. Therefore, 0.7484 mol of CH₄ will produce 0.7484 mol of CO₂.

Finally, we calculate the mass of CO₂ produced:
(0.7484 mol CO₂) x (44.01 g/mol) = 32.95 g CO₂

Thus, 32.95 grams of CO₂ will be produced from the reaction between 12.0 g of CH₄ and 133 g of O₂.

Explanation:

Following factors can affect blood pressure :

Answer:

bite where there is less sauce.

Explanation:

i just ate a pizza and it worked

Answer:

take a bite near crust

Explanation:

because the sauce is still hot so u will get burned

Answer:

2 NO2 ⟶ 2 O2 + N2

Hope this helped!

Explanation:

Proper advice are required to treat respiratory illness.

Explanation:

A person suffering from respiratory illness need to follow certain things, they are as follows:

Answer:0.0014458

That’s the right one

Answer:

0.0014458

Explanation:

edg

Answer:

Greater than 7

Explanation:

The pH scale measures how acidic or basic a substance is.

pH less than 7 - acid (represented by red)

pH equal to 7 - neutral (like water)

pH greater than 7 - base (represented by blue)

Answer : The pressure of gas in the balloon will be increases.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]

From this we conclude that, as the volume of gas increases then the pressure of the gas will be decreases and as the volume of gas decreases then the pressure of the gas will be increases.

As per question, the volume of balloon decreases from 1.50 L to 0.50 L at constant temperature. So, the pressure of gas in the balloon will be increases.

Hnece, the pressure of gas in the balloon will be increases.

The pressure of the gas in the balloon is expected to decrease.

Boyle's law states that the volume of a given gas is inversely proportional to the pressure of the gas provided the temperature is constant.

Boyle's law is denoted by the equation: K = P/V.

This means that as the volume of the gas increases, the pressure decreases and vice versa.

Therefore, the pressure of the gas in the balloon is expected to decrease.

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Answer:

look at the file :)

Explanation:

According to the stoichiometry of the balanced chemical equation of combustion of butane 1.313 liters  of oxygen gas is needed to completely combust 0.202 L of butane gas.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

0.202 liters of butane requires 13/2 of oxygen gas which is 0.202×13/2=1.313 liters.

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Answer:

Rate= 24

Explanation:

Rate = k[A]^2[B]

k= 3, [A]=2M, [B]=2M

Rate= 3×(2)^2×2= 24

Substitute into above

Answer:

In a chemical reaction, the atoms and molecules that interact with each other are called reactants. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

During a chemical reaction, various changes take place at the molecular level as substance  are transformed into new substances (products).

Chemical reactions involve the breaking and formation of chemical bonds between atoms and molecules. Here's what occurs during a chemical reaction:

Breaking and Formation of Bonds, the bonds between atoms in the reactants are broken. These bonds are typically covalent or ionic bonds. This requires an input of energy called the activation energy. Bonds are broken as reactant molecules collide and interact.

Once the bonds are broken, the atoms are rearranged to form new molecules or compounds. The atoms do not disappear; they are rearranged into new combinations.

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Answer:

lake and streams

Explanation:

The 30% of all fresh water easily accessible to humans is found in the ground and in lakes and streams. ... When water is absorbed into the ground, it is not trapped there. It can be evaporated from the surface if it is close enough to the surface. Even if it goes deep down, it can still be pulled

Answer:

Freshwater on the land surface is a vital part of the water cycle for everyday human life. On the landscape, freshwater is stored in rivers, lakes, reservoirs, and creeks and streams. Most of the water people use everyday comes from these sources of water on the land surface

Explanation:

Answer:

This stonefish was photographed in Indonesia, but its relatives live in shallow coastal waters from Egypt to Australia. They blend in with a variety of reefs and rocks, hence their name, and hide on the sea floor, waiting to ambush prey.

Explanation:

A base is weak when only a little of it dissolved in Water.

It images help u...

Answer:

A) base is weak when it forms few ions in water.

Explanation:

I just took the final

Answer:

i) Each Hydrogen atom is bonded to the oxygen atom with a single bond.

ii) The oxygen atom has two lone pairs.

iii) The molecule is bent.

iv) Oxygen is more electronegative than hydrogen.

v) Each O-H bond is polar.

vi) The oxygen atom has partial negative charge, and the hydrogen atoms have a partial positive charge.

NOTE: Above given points are correct and described by keeping in view the molecule of water.

Answer:

97.561 g/mol

Explanation:

The molar mass of Cu(OH)₂ is 97.57 g/mol. This is calculated by adding the atomic masses of copper, oxygen, and hydrogen in the compound. Each element's atomic mass is multiplied by the number of its atoms in the formula.

To find the molar mass of Cu(OH)₂, you need to add up the atomic masses of all the atoms in the compound:

Copper (Cu): 1 atom × 63.55 g/mol = 63.55 g/mol  

Oxygen (O): 2 atoms × 16.00 g/mol = 32.00 g/mol

Hydrogen (H): 2 atoms × 1.01 g/mol = 2.02 g/mol

Adding these together gives the total molar mass of Cu(OH)₂:

Cu(OH)₂ molar mass = 63.55 g/mol + 32.00 g/mol + 2.02 g/mol

= 97.57 g/mol

Thus, the molar mass of Cu(OH)₂ is 97.57 g/mol.

Answer:

It can be separated by physical methods.

2) It can appear different from different sources.

3) It cannot be described by a chemical symbol or formula.

Explanation:

Answer:

1) It can be separated by physical methods.

2) It can appear different from different sources.

3) It cannot be described by a chemical symbol or formula.

Mixture is composed of at least two substances.

Answer:

The answer to your question is 2.52 moles

Explanation:

Data

Volume = 60.5 l

Temperature = 20°C

Pressure = 1 atm

Constant of ideal gases = R = 0.082 atm l/mol°K

Formula

PV = nRT

-Solve for n

   n = PV / RT

-Convert temperature to °K

Temperature = 20 + 273

                      = 293°K

-Substitution

   n = (1 x 60.5) / (0.082 x 293)

-Simplification

    n = 60.5 / 24.026

-Result

    n = 2.52 moles

Answer:

The total number of atoms must be the same on both sides in order for it to be a balanced chemical equation.

In order to balance a chemical equation with the atoms on the right side of the equation with left side of the equation there must be:

b. total number of atoms

In a balanced reaction, the reactants go on the left side of the arrow, while the products go on the right side of the arrow. Coefficients (number in front of a chemical formula) indicate moles of a compound. Subscripts (numbers below an atom) indicate the number of atoms in a single molecule.

Thus, option b is correct.

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Due to plantation of some radish plants too closely, they compete with each other for nutrients and water. So, they grow long and thin.

Explanation:

Radishes grows tall and spindly due to hot weather, unfit soil, and conflict with other plants. More nitrogen in the soil may also cause radishes to grow long and thin.

Radishes sometimes grow “out of the ground” because either the soil is compacted or the seeds were planted too shallow.

Radishes, like carrots, prefer to grow in loose, sandy soil.  This means that the soil should be smooth, with no rocks, roots, or dirt clumps.

Due to competition with other plants (including nearby radishes!)  When there are too many plants in one area, they will compete with one another for nutrients and water.

In addition, when radishes are planted too close together, the roots physically have nowhere to go.  Since they cannot grow wider, they instead grow longer, going deeper into the soil in search of nutrients and water.

Radish plants planted too close together may become tall and spindly due to competition for light, resulting in a survival tactic of prioritizing height over girth to outcompete for sunlight, a process often aided by phytohormones.

If some radish plants are planted too close together, despite being well-fed and well-watered, they may grow to be tall and spindly due to a phenomenon known as competition for light. Plants grown in close proximity may sense the shading from their neighbors and respond by increasing their shoot elongation to access more light. This is a survival strategy where plants prioritize height over girth to outcompete neighboring plants for sunlight. In doing so, they often become weaker structurally and exhibit a 'stretched' appearance which is referred to as etiolation. Additionally, phytohormones such as gibberellins may contribute to this growth pattern, which enhances stem elongation especially when plants are densely planted and compete for sunlight.

Answer : The correct option is, (C) 32.0 mL

Explanation :

Formula used :

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume of NH₃.

[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume of HCl.

We are given:

[tex]M_1=0.32M\\V_1=50mL\\M_2=0.5M\\V_2=?[/tex]

Now put all the given values in above equation, we get:

[tex]0.32M\times 50mL=0.5M\times V_2\\\\V_2=32.0mL[/tex]

Hence, the volume of hydrochloric acid added to react completely with the ammonia must be, 32.0 mL

Answer:

Kinetic

Explanation:

Answer:

Gold

Explanation:

I think its gold since its a pure element, hope it helped

The amplitude of a sound wave determines its loudness. A higher amplitude results in a louder sound, and a lower amplitude results in a softer sound.

In Physics, the amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, while a smaller amplitude means a softer sound.

This spread of energy follows the inverse square law, meaning that doubling the distance from the sound source reduces its amplitude to one-quarter of its original value. This causes the sound to become softer the further it travels.