Which TWO transformations could show that triangle A and triangle B are similar triangles?
Answers
..
...
it's translation and Dilation
Related Questions
Eric plans to rent a car for a day from Easy Car Rental. He has a coupon for 25% off the daily base rate of $40. He will also have to pay an additional $0.15 for each mile he drives. Which expression represents the situation? (m represents the number of miles)
Answers
Answer:
30 + 0.15m
Step-by-step explanation:
base rate = 40(1 − 0.25) = 40(0.75) = 30
per mile = 0.15m
thus,
30 + 0.15m
The correct expression represents the situation is,
⇒ 30 + 0.15m
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
Eric plans to rent a car for a day from Easy Car Rental.
Here, He has a coupon for 25% off the daily base rate of $40.
And, He will also have to pay an additional $0.15 for each mile he drives.
Let m represents the number of miles.
Hence, We can formulate;
⇒ 40 (1 - 0.25) + 0.15m
⇒ 40 × 0.75 + 0.15m
⇒ 30 + 0.15m
Thus, The correct expression represents the situation is,
⇒ 30 + 0.15m
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A teacher reaches into a bag of game pieces containing 5 black pieces, 3 purple pieces, 1 orange piece, and 6 green pieces. He draws 2 pieces, setting aside the first piece before drawing the second. What is the probability that at least one of the drawn pieces is purple
Answers
This would be PP + PW+ PG + PB +WP +GP + BP
= (3/15 × 2/14) + (3/15×1/14)+(3/15×6/14) +(3/15+5/14)+(1/15×3/14) + (6/15× 3/14) + (5/15 × 3/14)
= 6/210 +3/210 +18/210+15/210+3/210 +18/210+ 15/210
= 78/210
= 13/35
Answer:
13/35
Step-by-step explanation:
gradpoint
Consider the diagram. What is the length of segment AB?
Answers
we know that
A median of a triangle is a line segment joining a vertex to the midpoint of the opposing side, bisecting it.
In this problem the line DB is a median of triangle ADC
The line DB is also the altitude of a triangle ADC, because is perpendicular to the side AC
so
AB=BC
we have that
[tex]BC=9\ units[/tex]
therefore
[tex]AB=9\ units[/tex]
the answer is the option
[tex]9[/tex]
Find two consecutive even integers such that the smaller added to threetimes the larger gives a sum of 30.
Answers
x+3x+6=30
4x=24
x=6
x+2=8
The numbers should be 6 and 8.
The two consecutive even integers that satisfy the given condition are 6 and 8. When the smaller one (6) is added to three times the larger one (8), the sum is 30.
The student has asked for help in finding two consecutive even integers such that the smaller added to three times the larger gives a sum of 30. To solve this, let's designate the smaller even integer as x. Since the numbers are consecutive even integers, the next integer will be x + 2.
The equation based on the problem statement will look like this:
x + 3(x + 2) = 30
Expanding the equation gives:
x + 3x + 6 = 30
Combining like terms:
4x + 6 = 30
Subtracting 6 from both sides:
4x = 24
And dividing by 4:
x = 6
Now, the two consecutive even integers can be determined:
The smaller integer is 6, and the larger integer is 6 + 2, which equals 8. Therefore, the two integers are 6 and 8, and if we check:
6 + 3(8) = 6 + 24 = 30, which matches the required sum.
Solve the system of equations using the linear combination method.
{9x+5y=35
{2x+5y=0
Enter your answers in the boxes.
x =_
y =_
Answers
please mark as brainliest
hope it helps
The perimeter of an equilateral triangle with a side of 6 inches is
12 in.
18 in.
36 in.
Answers
Which of the following inequalities is best represented by this graph?
5x + y ≤ 2
5x + y ≥ 2
5x − y ≤ 2
5x − y ≥ 2
Answers
We have then:
5x - y = 2
For x = 0
5 (0) - y = 2
-y = 2
y = -2
For y = 0
5x - 0 = 2
5x = 2
x = 2/5 = 0.4
Therefore the line is:
5x - y = 2
Then, we see that for the point (0, 0)
5x - y ≥ 2
5 (0) - (0) ≥ 2
0 ≥ 2
The inequality is not met, which is correct because this point is not part of the shaded region.
Answer:
The inequality that best is represented by the graph if:
5x - y ≥ 2
Answer:the answer is d
Step-by-step explanation:
5x - y ≥ 2
The band is selling wrapping paper for a fundraiser. Customers can buy rolls of plain wrapping paper and rolls of shiny wrapping paper. The band sold a total of 55 rolls and made $950. If a roll of plain wrapping paper cost $14 and a roll of shiny cost $20, how many rolls of each did they sell ?
Answers
y= # shiny rolls
QUANTITY EQUATION:
x+y=55
COST EQUATION:
$14x + $20y= $950
SOLVE:
Solve for one variable in quantity equation. Substitute that answer in cost equation.
STEP 1:
x+y=55
subtract y from both sides
x= 55-y
STEP 2:
$14x + $20y= $950
14(55-y) + 20y= 950
multiply 14 by all in parentheses
(14*55)+(14*-y) + 20y= 950
770-14y+20y= 950
combine like terms
770+6y= 950
subtract 770 from both sides
6y= 180
divide both sides by 6
y= 30 shiny rolls
STEP 3:
Substitute y answer in either equation to solve for x.
x+y=55
x+30=55
subtract 30 from both sides
x= 25 plain rolls
Hope this helps! :)
The roll of plain wrapping paper sold is 25.
The roll of shiny wrapping paper sold is 30.
What are the linear equations that represent the question?a + b = 55 equation 1
14a + 20b = 950 equation 2
Where:
a = roll of plain wrapping paper sold
b = roll of shiny wrapping paper sold
What is the roll of shiny wrapping paper sold?Multiply equation 1 by 14
14a + 14b = 770 equation 3
Subtreact equation 3 from equation 2
6b = 180
Divide both sides by 6
b = 30
What is the roll of plain wrapping paper sold?
Subtract 30 from 55
55 - 33 = 25
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What is the true solution to 3 in 2 + in 8 = 2 in(4x)
a. x=1
b. x=2
c. x=4
d. x=8
Answers
ln is base e. both sides of the equation are base e so the parts inside the parentheses are equal
x=2
The true solution to [tex]3 log 2+log8 =2log(4x)[/tex] is [tex]x=2[/tex]. The correct option is b. [tex]x=2[/tex].
Given expression is[tex]3 \log 2+\log8 =2\log(4x)[/tex].
We have to calculate the value of [tex]x.[/tex]
Properties of logarithm:We know that,
[tex]n \log m= \log(m)^n[/tex]
and
[tex]\log m + \log n = \log(mn)[/tex]
Solving the equation:
[tex]3 \log 2+\log8 =2\log(4x)[/tex][tex]\log(2)^3+\log8 =\log(4x)^2[/tex]
{using [tex]n \log m= \log (m)^n[/tex]}
[tex]\log8+\log 8= \log 16x^2[/tex]
[tex]\log (8 \times8)=\log16x^2[/tex] {using [tex]log m + log n = log(mn)[/tex]}
Since log is on both sides so it is eliminated from both sides,
[tex]8 \times8=16x^2\\64=16x^2\\[/tex]
[tex]x^{2} =\frac{64}{16}\\x^{2}=4\\x=2[/tex]
Hence the true solution to [tex]3 log 2+log8 =2log(4x)[/tex] is [tex]x=2[/tex].
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If a triangle is an obtuse triangle then it can not be an isosceles triangle.
a. True
b. False
Answers
FALSE
CB = AC
Kathleen has been tracking how fast she walks over the last month and determined that she walks 1 1/4 miles in 2/5 of an hour. Lynn has been tracking how fast she walks over the last few weeks and determined that it takes her 19 minutes and 12 seconds to walk 1 mile. Part A: Write both Kathleen's and Lynn's walking rate in the same format, either miles per hour, miles per minute, minutes per mile, or hours per mile and compare their rates to each other. Part B: Give a logical argument on why that format was chosen over the other three.
Answers
K: 24 minutes per 2 3/4 miles
L: 19.12 minutes per mile
B:
I chose minutes per mile because it was already being used for one of them so it takes less work.
Select all that have a value of 0.
Answers
Answer:
It's 1,3, and 5.
The functions that have a value of 0 are : [tex]cos(\frac{\pi}{2} ),~sin(0),~tan(\pi)[/tex]
What is function?"It defines a relation between input and output values.""In function for each input there is exactly one output."For given question,
We have been given some trigonometric functions.
We need to find the functions that have a value zero.
[tex]i)~cos(\frac{\pi}{2} )=0\\\\ii)~cos(0)=1\\\\iii)~sin(0)=0\\\\iv)sin(\frac{3\pi}{2} )=-1\\\\v)tan(\pi)=0[/tex]
From above, we can observe that functions [tex]cos(\frac{\pi}{2} ),sin(0)[/tex] and [tex]tan(\pi)[/tex] have a value of zero.
Therefore, the functions that have a value of 0 are : [tex]cos(\frac{\pi}{2} ),~sin(0),~tan(\pi)[/tex]
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The half-life of iodine-123 is about 13 hours. You begin with 52 grams of iodine-123. (a) Write an equation that gives the amount of iodine-123, I , remaining after t hours. Write your answer in the form I ( t ) = a ⋅ b t . Round your answer for b to three decimal places.
Answers
Final answer:
The amount of iodine-123 remaining after t hours can be expressed as I(t) = 52 · 0.945^t, where the constant 0.945 is calculated using the half-life of 13 hours.
Explanation:
The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms to decay. For iodine-123, which has a half-life of approximately 13 hours, we can use an exponential decay model to express the amount of iodine-123 remaining after t hours.
The decay formula is generally given by I(t) = I0e-kt, where I0 is the initial amount, k is the decay constant, and t is time. However, the question asks us to express the equation in the form of I(t) = a · bt, which is another common representation for exponential decay.
To find the value of b, we know that after one half-life, b13 = 1/2. Thus, b = (1/2)1/13.
Let's calculate b: b = (0.5)1/13 ≈ 0.945 (rounded to three decimal places).
Since we start with 52 grams of iodine-123, our initial amount (a) is 52. Therefore, the equation for the amount of iodine-123 remaining after t hours is:
I(t) = 52 · 0.945t
The equation to calculate the amount of iodine-123 remaining after t hours is I(t) = a * b^t, where a is the initial amount of iodine-123, b is the decay constant, and t is the time in hours. The decay constant can be calculated using the formula b = 0.693 / t1/2, where t1/2 is the half-life of iodine-123. In this case, the half-life is 13 hours.
Explanation:The equation that gives the amount of iodine-123 remaining after t hours can be written as:
I(t) = a * b^t
Where:
I(t) is the amount of iodine-123 remaining after t hoursa is the initial amount of iodine-123b is the decay constant, which can be calculated using the half-life formulat is the time in hoursTo calculate the decay constant b, we can use the formula:
b = 0.693 / t1/2
where t1/2 is the half-life of iodine-123. In this case, the half-life is 13 hours, so:
b = 0.693 / 13 = 0.053
Therefore, the equation becomes:
I(t) = a * 0.053^t
Round the value of b to three decimal places, so b = 0.053.
An equiangular triangle can never be scalene. true or false?
Answers
The given statement "An equiangular triangle can never be scalene." is true.
What is an equiangular triangle?An equiangular triangle is a triangle that has three equal angles.
What is a scalene triangle?A scalene triangle is a triangle that has three unequal sides.
Therefore, a scalene triangle has three different angles.
Therefore, an equiangular triangle and scalene triangle are two completely different triangles.
Hence, an equiangular triangle can never be a scalene triangle.
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Bonnie wants to make a picture frame for a 5 x 8-inch photo. What is the area of the frame if the frame is 1 inch thick? square inches
Answers
Explanation:
1) Measure of the picture: 5 in x 8 in
2) The frame can be splited into 4 rectangular figures:
Two of 10 in * 1 in = 2 * 10 in^2 = 20 in^2
Two of 5 in * 1 in = 2 * 5 in^2 = 10 in^2
3) The total area of the frame is 20 in^2 + 10in^2 = 30 in^2
4) You can also see that the dimensions of the picture with the frame are 10 in * 7 in, which leads to an area of 10 in * 7 in = 70 in^2.
So, if you subtract the are of the picture, you will have the are of the frame.
Area of the picture = 5 in * 8 in = 40 in^2
Area of the frame = total area - area of the picture = 70 in^2 - 40 In^2 = 30 in^2.
Which confirms the previous calculation.
The area of the frame if the frame is 1 inch thick will be 30 inch².The area of the frame is found as the product of the length and breadth of the frame.
What is the area?The space filled by a flat form or the surface of an item is known as the area.
If the frame is 1 inch thick then the total area is found as;
The area of the rectangular picture is;
[tex]\rm A = 5 \times 8 \\\\\rm A =40 \ inch^2 \\\\[/tex]
The total area of the frame is found as;
Area of frame = Total area - area of the picture
Area of frame =70 -40
Area of frame = 30 inch²
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An initial investment of $200 is now valued at $350. The annual interest rate is 8% compounded continuously. The equation mc022-1.jpg represents the situation, where t is the number of years the money has been invested. About how long has the money been invested? Use a calculator and round your answer to the nearest whole number.
Answers
Answer:
7 years
Step-by-step explanation:
An initial investment of $200 is now valued at $350.
The annual interest rate is 8% compounded continuously.
Formula:
[tex]A=Pe^{rt}[/tex]
Where,
A is amount, A=350
P is principle, P=200
R is rate of interest, r=0.08
t is time, t=?
Substitute the value into formula
[tex]350=200e^{0.08\cdot t}[/tex]
[tex]e^{0.8t}=1.75[/tex]
Taking ln both sides
[tex]0.08t = ln(1.75)[/tex]
[tex]t=6.99\approx 7[/tex]
Hence, 7 years ago money was invested.
Answer:
Its 7 years
Step-by-step explanation:
Michelle and Andrea are walking laps for charity. The amount of money, y, that each girl raises for a certain number of laps, x, is shown in the tables below. Michelle mc020-1.jpg Andrea mc020-2.jpg Which statement explains who will raise $100 with the fewest number of laps? Michelle will, because the slope of the line described by the data in her table is the greatest. Andrea will, because the slope of the line described by the data in her table is the greatest. Michelle will, because her number of laps are increasing at a faster rate. Andrea will, because her number of laps are increasing at a slower rate
Answers
Michelle's graph has a slope of 3/2 which equals 1.5
Andrea's graph has a slope of 5/4 which equals 1.25
Hope this helps ;)
Answer:
The answer would be a im sure
Step-by-step explanation:
Find the area of the shaded portion in the square (assuming the center point of each arc is the corresponding central point of the line and the arcs intersect at the center point of the circle)
Answers
Answer:
The answer is 2. hope it helps!
Step-by-step explanation:
Answer: The area of the shaded portion is [tex](\pi-2)~\textup{sq. units}.[/tex]
Correct option is 2.
Step-by-step explanation: We are given to find the area of the shaded portion in the figure.
Since, the centre point of each arc is the corresponding central point of the line and the arcs intersect at the centre point of the circle,
so let us divide the figure into four equal parts, one of them is square ABCD as shown in the attached figure.
The area of the square ABCD will be
[tex]A_{ABCD}=\left(\dfrac{1}{2}\times 2\right)^2\\\\\\\Rightarrow A_{ABCD}=1~\textup{sq. units}.[/tex]
Now, area of the shaded portion inside the square ABCD will be
[tex]A_s=2\times \textup{area of the quarter circle with radius 1 unit}}-\textup{area of square ABCD}\\\\\Rightarrow A_s=2\times \left(\pi\times \left(\dfrac{1}{2}\right)^2\right)-A_{ABCD}\\\\\\\Rightarrow A_s=2\times\left(\dfrac{\pi}{4}\right)-1\\\\\\\Rightarrow A_s=\left(\dfrac{\pi}{2}-1\right)~\textup{sq. units}.[/tex]
Since all the four squares are identical in the attached figure, so the required area of the total shaded portion in the figure is
[tex]A=2\times\left(\dfrac{\pi}{2}\right)\\\\\\\Rightarrow A=(\pi-2)~\textup{sq. units}.[/tex]
Thus, the area of the shaded portion is [tex](\pi-2)~\textup{sq. units}.[/tex]
The correct option is 2.
How do I solve and graph this?
Answers
3x - 6 ⩾ y
now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".
if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,
3(4) - 0 ⩾ 6
12 - 0 ⩾ 6
12 ⩾ 6
is 12 really greater or equals to 6? well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.
now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.
check the picture below.
Which three lengths CANNOT be the lengths of the sides of a triangle?
Question 2 options:
A. 21 m, 6 m, 10 m
B. 11 m, 11 m, 12 m
C. 23 m, 17 m, 14 m
D. 5 m, 7 m, 8 m
Answers
The sum of two sides of a triangle must be longer than the third side, but 6 + 10 is less than 21, so it cannot be a triangle.
Hope this helps =)
Answer for number 5?
Answers
The formula for Perimeter is P = 2L + 2W
Where L = length; W = width
192 = 2L + 2W
= 2(5x) + 2(3x)
= 10x + 6x
= 16x
192/16 = 16x/16
x = 12
Substitute the values:
192 = 2(5x) + 2(3x)
= 2(5*12) + 2(3*12)
= 2(60) + 2(36)
192 = 192
Find the first six terms of the sequence.
a1 = -4, an = an-1 + 7
-4, 3, 10, 17, 24, 31
-4, 7, 14, 21, 28, 35
3, 10, 17, 24, 31, 38
0, 7, 14, 21, 28, 35
Answers
Answer: A) -4, 3, 10, 17, 24, 31
Step-by-step explanation: To solve the given problem we need to calculate the first six terms of the sequence (starting with a1):
a1=-4
a2=a1+7
a2=-4+7
a2=3
a3=a2+7
a3=3+7
a3=10
a4=a3+7
a4=10+7
a4=17
a5=a4+7
a5=17+7
a5=24
a6=a5+7
a6=24+7
a6=31.
Seven more than half of the cost , c
Answers
Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is also 53. 6f – 1 evaluated at f = 3 is 17. what is 2f + 4f + 2 – 3 evaluated at f = 3?
Answers
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
let's check it
[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
Answer: 17
Step-by-step explanation:
Rene has a coupon for $3.25 off a package of name brand cookies that normally costs $7.89. The store brand cookies coats $5.58. How much will Rene save if she uses her coupon and buys the name brand cookies instead of the store brand cookies? HELP
Answers
Rene will save $0.94 if she uses her coupon and buys the name brand cookies instead of the store brand cookies.
Explanation:To find out how much Rene will save if she uses her coupon and buys the name brand cookies instead of the store brand cookies, we have to first determine how much the name brand cookies will cost after applying the coupon. We subtract the value of the coupon i.e. $3.25 from the original cost of name brand cookies which is $7.89. The result comes out to be $4.64.
To calculate the savings, we now have to subtract the cost of name brand cookies after coupon ($4.64) from the original cost of the store brand cookies ($5.58). Hence, the savings amount to $5.58 - $4.64 which equals $0.94
So, if Rene uses her coupon and buys the name brand cookies instead of the store brand cookies, she will save $0.94.
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A test is worth 140 points. Ten percent of those points are from one short-answer question. How many points is the short-answer question worth?
Answers
140 points x 10% = 140 x 0.1 = 14 points for the short-answer quesion.
The short-answer question worth of 14 points.
What is unitary Method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given:
Total points of test =140
and 10 % of those points are from one short-answer question.
So, the points for short-answer question are
=10 % of 140
=10/100 x 140
=1400/100
=14
Hence, short-answer question worth of 14 points.
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Given: What type of angles are ∠2 and ∠3 are adjacent angles.
Which of the following options describes the adjacent angles in terms of their sum? complementary angles, 90° complementary angles, 180° supplementary angles, 90° supplementary angles, 180°
Answers
_____________________________________________________
Note:
Choices:
_____________________________________________________
[B]: "complementary angles, 180° " ; and:
_____________________________________________________
[C]: "supplementary angles, 90° " ;
_____________________________________________________
can automatically be ruled out ; since by definition:
→ Complementary angles always add up to 90° — NOT 180° ;
and: supplementary angles always add up to 180° — NOT 90° .
_____________________________________________________
Note: "Adjacent angles" refer to "supplementary angles" ; which, by definition add up to 180° . Futhermore, looking at the image provided,
we see that ∠1 and ∠2 are, in fact "adjacent" and that ∠1 and ∠2 comprise the entire portion of a "straight line" (being intersected by a transversal)" ;
and as such; ∠1 and ∠2 are supplementary angles—
and as such—add up to 180° .
(which rules out: Choice [A]: "complementary angles, 90°) ;
→ and demonstrates the correct answer:
______________________________________________________
Answer choice: [D]: "supplementary angles, 180° " .
______________________________________________________
Final answer:
Adjacent angles can be either complementary or supplementary depending on their sum. Complementary angles add up to 90°, while supplementary angles sum to 180°. The term for adjacent angles in terms of their sum is 'supplementary angles', adding up to 180°.
Explanation:
Adjacent angles are two angles that have a common side and vertex, and don't overlap. In terms of their sum, if adjacent angles add up to 90 degrees, they are called complementary angles. If they add up to 180 degrees, they are called supplementary angles. Since the question involves angles ∠2 and ∠3 as adjacent angles but does not provide their specific measures, it's not possible to definitively classify them as complementary or supplementary without additional information. However, the question asks which term describes adjacent angles in terms of their sum. The correct answer is supplementary angles, which have a sum of 180°.
Who worthy the book “I love fractions”
Answers
If three tangents to a circle form an equilateral triangle, prove that the tangent points form an equilateral triangle inscribed in the circle
Answers
Assuming that [tex]FED[/tex] is an equilateral triangle according to the wording of the problem, we have that the angles [tex]\widehat{AFB}=\widehat{BEC}=\widehat{CDA}=60[/tex].
We also know that the circle in green is Inscribed in [tex]FED[/tex].
The following applies to every inscribed circle inside a triangle:
The center of the inscribed circle of a triangle is the intercept of all three angle bisectors of the triangle.
The above theorem implies that the line [tex](FO) [/tex] is an angle bisector because it goes through the vertex F and the center of the inscribed circle.
The previous statement implies that the angle [tex]\widehat{OFB}=30[/tex].
Now let's work on the [tex]OFB[/tex] triangle.
Knowing that [tex]\widehat{OBF}=90[/tex] (because [tex](EF)[/tex] is tangent to the circle at B and [tex]OB[/tex] is a radius of the circle. If you're lost here, remember that a tangent to a circle is always perpendicular to the radius of the circle.) we can then derive that [tex]\widehat{FOB}=180-90-30=60[/tex] (because the sum of the measures of all angles in a triangle is always equal to 180 degrees).
In the same way, we can prove also that:
[tex]\widehat{BOE}=\widehat{EOC}=\widehat{COD}=\widehat{DOA}=\widehat{AOF}=60 degrees[/tex].
Knowing the above we notice that [tex]\widehat{BOC}=\widehat{COA}=\widehat{AOB}=120degrees[/tex].
We're at the last part of our proof here:
Now notice that [tex]\widehat{BOA}[/tex] subtends the same arc on the circle that [tex]\widehat{BCA}[/tex].
According to the inscribed angle theorem, an angle [tex]\theta[/tex] inscribed in a circle is half of the central angle [tex]2\theta[/tex] that subtends the same arc on the circle.
Therefore [tex]\widehat{BCA}=\frac{\widehat{BOA}}{2}=60degrees[/tex]
We can prove in a similar fashion that: [tex]\widehat{CAB}=\widehat{ABC}=60degrees[/tex]
Therefore all the angles of the [tex]ABC[/tex] triangle have a measure of 60 degrees, we conclude then that [tex]ABC[/tex] is equilateral.
negative 1 over 2x + 2 = −x + 7
Answers
.. -1/(2x +2) = -x +7
.. -1 = (2x +2)(-x +7)
.. 2x^2 -12x -15 = 0
And from the quadratic formula
.. x = (12 ±√((-12)^2 -4(2)(-15)))/(2(2))
.. x = 3 ±√16.5
x ≈ -1.062019 or 7.062019