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Answer: Gabriel Andral, a French professor, and William Addison, an English doctor both informed the first classifications of white blood cells.
Cervical pregnancies are extremely rare. Women undergoing cervical pregnancies often experience unusual vaginal bleeding. In extreme cases, they may require a hysterectomy (removal of the uterus). Why do you think the symptoms and risk occurs with this type of ectopic pregnancy?
Answer:
Ectopic pregnancy can cause the burst of fallopian tube. If previous ectopic pregnancy occured then again onset of this type of pregnancy may lead to life threatening bleeding. Having the abdominal surgery before may also proved as a risk.
Answer:
PLATO ANSWER
Explanation:
Bleeding would occur because the baby is growing near the vaginal canal, which leads to the outside of the body. The cervix is the bottom portion of the uterus, so if the uterus is damaged, the entire uterus may need to be removed.
An action potential releases neurotransmitter from a neuron by opening which channels?
Answer:
Calcium channels.
Explanation:
The arrival of action potential at the presynaptic neuron, cause the opening of Ca+ channels, at the presynpatic neuron membranes. This leads to influx of Ca+ . The latter caused the Acetycholine contained vesicles in the presynaptic neuron to migrate to the tip of the presynaptic neurons, and fused with the neuronal membrane to empty their contents into the synaptic cleft.
Plants keep runoff water from reaching aquifers. What happens to most of this water?
Answer&Explanation:
Most of water become absorbed and transpired(process by which plant loose water through leaves) or by guttation(loss of water inform of drops especially during night which appears as dew through hydathodes)
According to the article, how does human activity affect the availability of food for deer populations? What result does this have on the deer populations? It's a timed test so please hurry if you can!!
Answer:
its b i just did this so she can get brainliest
however you speel it lol
Explanation:
Which of the following is an example of sustainability?
A) cutting down all the trees in a forest without replanting any
B) consuming more cattle than are being born
C) recycling a metal can so it can be reused
D) leaving the lights on in a room you are not in
Answer:
C
Explanation:
Recycling a metal can so it can be reused.
The statement that is an example of sustainability is; "recycling a metal can so it can be reused".
Sustainability is the fact that resources are used in a way in which they can be replaced in order to enable their continuous use and a continued availability of resources.
The statement that is an example of sustainability is; "recycling a metal can so it can be reused". Recycling reduces the stress placed on he environment by extracting new resources from the environment.
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Cells grown in the laboratory are mixed with a charged dye molecule that is unable to pass through the plasma membrane. If a ligand is added to the cells, the dye is observed entering the cells. What type of receptor did the ligand bind to on the cell surface
Answer: ion channel receptor
Explanation:
Ion channel receptors appear to be multimeric proteins in the plasma membrane. Growing of these proteins organise itself to form a pore or passage which extends from one side of the membrane to the other.
when the ligand is added to the cells, ion channel receptors allows the dye to enter into the cell.
Some scientists feel that dinosaurs became extinct when a cloud of dust and gas kept sunlight from penetrating the atmosphere for a long period of time. Based on what you now know about photosynthesis, is this a reasonable conclusion? Support your answer.
Answer:
Yes, it is a reasonable conclusion.
Explanation:
The long lasting gas that kept sunlight from penetrating the atmosphere was the key factor that promote a disturbance on the chain food. Without sunlight, plants could not produce their own energy, therefore they could not resist to this environment condition and die. That way, the herbivores could not feed and die as well. Also the carnivore could not survive because their supply of food of herbivores are not alive anymore. This scenario would promote a mass extinction of every dinosaur.
Most theory testing is done on weird people means __________
Answer:
Most participants are Western, educated, industrialized, rich, and democratic.
In cats, being awesome (A) is dominant to being average (a), and being bashful (B) is dominant to being boring (b). A male cat that is homozygous dominant for the A trait and heterozygous for the B trait is mated with a female cat that is homozygous recessive for both. Both the A and B traits assort independently from one another. What is the probability that they will have an offspring who is heterozygous for both traits? Choose 1 answer:
(Choice A)
50%
(Choice B)
100%
(Choice C)
0%
(Choice D)
25%
The probability that both cats described will have an offspring who is heterozygous for both traits is 50%.
Explanation:
When a cat awesome and bashful is crossed with a cat average and boring, it is a crossing where two traits are taken into account that will be segregated independently by the parents, and the result will be produced by the analysing the genotypes and making crossing in a punnett square.
The genotypes are given as for male cats AA Bb and for female cats aa bb. The crossing is done based on punnett square and it is denoted as
Alleles AB Ab
ab AaBb Aabb
ab AaBb Aabb
The offspring is AaBb awesome and bashful(it is heterozygous for two traits 50%) whereas in Aabb awesome and blashful( it is heterozygous for trait A and homozygous for trait B).
Thus The probability that both cats described will have an offspring who is heterozygous for both traits is 50%.
The probability that they will have an offspring who is heterozygous for both traits in this cat with being awesome (A) is dominant to being average (a), and being bashful (B) is dominant to being boring (b) -is - 50%
Cross between two independent assorted allele
In cats, being awesome (A) is dominant to being average (a), and being bashful (B) is dominant to being boring (b). Here the cross is between A male cat that is dominant for the A trait and heterozygous for the B trait is mated with a female cat that is wild type for recessive for both
Male cat - AA Bb
Female cat - aa bb
Cross - AA Bb x aa bb
Gametes: AB, Ab and ab
Punntte:
AB Ab
ab AaBb Aabb
A trait probability for a heterozygous trait is 1 or 100%
For b trait, the probability of heterozygous trait is 50% or 1/2
So the total probability is 50%
= 50%
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The LPS, or endotoxin, of Neisseria gonorrhoeae is slightly different from most Gram-negative organisms because of the absence of repeating O-antigens; hence, it is called LOS instead of LPS. How could LOS be a major virulence factor for Neisseria gonorrhoeae
Answer:
Neisseria gonorrhoeae the human pathogen that causes the sexually transmitted disease (STD) gonorrhea and is commonly transmitted by exchanging needles through the use of medications or by infected blood products.
LOS is a major virulence factor in Neisseria gonorrhoeae, since LOS causes autolysis during infection and the release of LOS endotoxin damages the host cells is the main cause of most gonorrhoea symptoms including greater frequency or urgency of urination, swelling or redness at the opening of the penis, and swelling or pain in the testicles..
The nurse is providing instructions to the mother of a child with human immunodeficiency virus infection regarding immunizations.
Which statement by the mother indicates an understanding of the immunization schedule?
1. "The hepatitis B vaccine is not to be given to my child."
2. "My child will receive all the vaccines like any other child."
3. "Family members in the household need to receive the influenza vaccine."
4. "Blood tests are needed before any immunizations are given to my child."
Answer:
Family members in the household need to receive the influenza vaccine."
Explanation:
Human Immunodeficiency virus (HIV) can cause acquired immunodeficiency syndrome AIDS, which is a viral disease which can destroy lymphocyte , thereby increasing susceptibility to infection and malignancy. A child with human immunodeficiency virus (HIV) infection will receive the same immunizations as other children, apart from live vaccines. All household members will also receive the influenza vaccine. Blood tests prior to immunizations are unnecessary and inaccurate.
Answer:
3.Family members in the household need to receive the influenza vaccine.
Explanation:
The nurse provides home care instructions to the parent of a child with acquired immunodeficiency syndrome (AIDS), she gave instructions that
1.The inactivated influenza vaccine will be given yearly.
The nurse anticipates that which laboratory study will be prescribed for the infant
2. p24 antigen assay
The nurse should make which most appropriate response to the mother that
3. Most children infected with HIV develop symptoms within the first 9 months of life, and some become symptomatic sometime before they are 3 years old
How do the properties of water support life on earth?
Answer:
hrydrogen and oxygen formed water
Explanation:
Is there such thing as a heterozygous dominant / recessive? My biology teacher put a question saying to solve a punnet square with a heterozygous dominant parent and a homozygous recessive parent. I don't think it's possible to solve this because I have done my research and still not able to find out if there is such thing as a heterozygous dominant. I think my teacher is tricking me, is there such thing as a heterozygous dominant? Please let me know, thank you!!!!
E. coli cells grown on 15N medium are transferred to 14N medium and allowed to grow for two more generations (two rounds of DNA replication). DNA extracted from these cells is centrifuged. What density distribution of DNA would you expect in this experiment? E. coli cells grown on 15N medium are transferred to 14N medium and allowed to grow for two more generations (two rounds of DNA replication). DNA extracted from these cells is centrifuged. What density distribution of DNA would you expect in this experiment?
one high-density and one intermediate-density band
one low-density and one intermediate-density band
one high-density and one low-density band
one intermediate-density band
Answer:
The correct answer is "one low-density and one intermediate-density band".
Explanation:
The 15N medium contains 15N, a heavy isotope of nitrogen. DNA synthesized by E. coli growing in 15N medium will be of high-density. If the E. coli culture is transferred to a 14N medium, after two rounds of DNA replication, one low-density and one intermediate-density band will be observed in an experiment of centrifugation. This result supports the semiconservative model of DNA replication, where half of the DNA population will be a mixture of 15N-14N DNA corresponding to a intermediate-density band, while the other half is a 14N-14N light density DNA.
E. coli cells grown on 15N medium and transferred to 14N medium would exhibit one high-density band and one low-density band in the centrifugation process of extracted DNA.
Explanation:In this experiment, E. coli cells were first grown on a 15N medium, which contains a heavy isotope of nitrogen. The DNA in these cells would have a high density. When the cells were transferred to a 14N medium and allowed to undergo two rounds of DNA replication, the newly synthesized DNA strands would be lighter in density since the new nitrogen in the medium is lighter. Therefore, after centrifugation, you would expect to see one high-density band corresponding to the old DNA and one low-density band corresponding to the newly synthesized DNA.
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Essential amino acids are those that:
A. include minerals such as calcium and iron.
B. cannot be synthesized biochemically and must be taken in through the diet.
C. can only be found in plants.
D. provide essential vitamins
plsssss helppp I need it in your own words and not copy and pasted pls
Variation in a trait is a required condition for natural selection to act on a population for that trait. Assuming a population of organisms only started with only one form of a trait, what are two ways variation in the trait could be introduced into the population? Explain your answer.
Mutation and genetic recombination through sexual reproduction are two ways variation in a trait can be introduced into a population.
Mutation: Mutations are spontaneous changes in the DNA sequence that can lead to new alleles, creating genetic variation.
- These mutations can occur due to errors in DNA replication, exposure to mutagens like radiation or certain chemicals, or even through transposons, which are DNA sequences that can move around within the genome.
- Mutations can result in new traits or alter existing ones, contributing to variation within a population. For example, a mutation may lead to a change in fur color in mammals or the production of a new enzyme that confers a survival advantage.
Genetic Recombination through Sexual Reproduction: Sexual reproduction involves the combination of genetic material from two parent organisms, resulting in offspring with unique combinations of alleles.
- During meiosis, the process by which sex cells (gametes) are formed, homologous chromosomes exchange genetic material through crossing over. This process results in genetic recombination, where alleles from different parents are shuffled and passed on to offspring.
- Additionally, fertilization combines genetic material from two different individuals, further increasing genetic diversity in the population. This genetic recombination introduces variation in traits, allowing for natural selection to act upon them.
An ecologist hypothesizes that predation by a particular owl species is the major factor controlling the population of a particular rabbit species. If this is the case, which of the following population effects could be expected in this rabbit-owl pair?
A) A fall in the owl population should cause a fall in the rabbit population.
B) A fall in the rabbit population should cause an increase in the owl population.
C) An increase in the diseases in the rabbit population should not change the owl population.
D) An increase in the owl population should cause a fall in the rabbit population.
D) An increase in the owl population should cause a fall in the rabbit population.
In homeotic mutants: Group of answer choices one body structure is missing. one body structure has been changed into another. one body structure has been duplicated. one body structure has significantly increased in size. the organism is infertile.
Explanation:
In homeotic mutants, one body structure has been changed into another
Homeotic genes provide identity of organ and they become permanently switch off after completion of their workIn Drosophila, these genes are tightly regulated by the activity of polycomb genes and is present in two patches, one path constitute antennapedia complex whereas another patch constitute bithorax complexAntennapedia complex expresses in the second thorax segment and is responsible for the formation of legsBesides formation of thorax legs it also expresses in the area of headA mutation in antennapedia lead to the formation of legs on the place of antennaFinal answer:
In homeotic mutants, a mutation in Hox genes can result in the transformation of one body structure into another, such as legs growing where antennae should be in the Antennapedia mutant of the fruit fly.
Explanation:
In homeotic mutants, one body structure has been changed into another. This can occur due to the mutation in the Hox genes, which are a subset of homeotic genes. Hox genes play a crucial role in determining the layout of body structures during embryonic development. For instance, a mutation in these genes can result in the appearance of one organ or appendage in place of another. An example is the Antennapedia mutant where a fruit fly had legs growing from its head instead of antennae.
Therefore, in the given choices, the phenotype most likely to result from a Hox gene mutation would be an appendage growing in an inappropriate location, such as legs where antennae should be. These mutations have significant implications since they can alter basic body plans and structures, which make these genes very important from an evolutionary and developmental viewpoint.
A child with Duchenne muscular dystrophy is to receive prednisone as part of his treatment plan.
After teaching the child's parents about this drug, which statement by the parents indicates the need for additional teaching?
A) "We should give this drug before he eats anything."
B) "We need to keep a close eye for possible infection."
C) "The drug should not be stopped suddenly."
D) "He might gain some weight with this drug."
Answer:
The preferable option will be - A.
A. "We should give this drug before he eats anything."
Explanation:
Prednisone can be used for the treatment of Duchenne muscular dystrophy disease. Prednisone is a corticosteroid and can cause gastric upset, for that the medicine should be given with food to reduce this risk. The drug has some side effects such as weight gain, osteoporosis, and mood changes. The drug may also cause some infections, so the parents need to monitor the child closely for any changes. Treatment should not be stopped abruptly due to the risk of acute adrenal insufficiency.What occurs after cytokinesis is completed at the end of meiosis i?
Answer:
Meiosis II begins
Explanation:
After the cells split in two, the genetic material splits again, resulting in half of the chromosomes, as part of the meiosis II process
Answer:
Two haploid cells are formed.
What might be a consequence of global warming for fishes living in a pond?
Answer:
Global warming is resulting in climate change, which is influencing almost all the life found on the planet, however, with the change in climate, the fishes thriving in aquatic bodies like ponds have to face various challenges.
As it is known that warm water exhibit less tendency to carry dissolved oxygen in comparison to cooler water. Thus, with the influence of global warming, water bodies like lakes, ponds, rivers, and oceans are going through a phenomenon called deoxygenation. Therefore, with the warming of the planet Earth, the aquatic bodies like ponds possess less tendency to contain oxygen in the dissolved state, thus, diminishing the tendency of the fishes to use oxygen for the process of respiration.
A biologist conducts an experiment designed to determine whether a particular type of molecule is transported into cells by simple diffusion, facilitated diffusion, or active transport. He collects the following information: 1) The molecule is very small. 2) The molecule is polar. 3) The molecule can accumulate inside cells even when its concentration inside the cell initially is higher than it is outside the cell. 4) Cells use up more energy when the molecule is present in the environment around the cells than when it is not present. The biologist concludes that the molecule moves across cell membranes by facilitated diffusion. Do you agree with his conclusion?
Answer:
No, this is not a facilitated diffusion but an Active transport process.
Explanation:
This is an active transport process because -
The molecules are moving against the concentration gradient from higher concentration to lower concentration. It is using up energy. The energy is stored in the form of ATP. To move across the concentration gradient ATP is needed.So, we can say that the whole experiment undergoes the Active transport process.
Final answer:
No, the biologist's conclusion is incorrect; the described properties suggest that the molecule is transported across cell membranes by active transport, not facilitated diffusion.
Explanation:
The conclusion drawn by the biologist does not appear to be correct based on the information provided. When considering the information given:
The molecule is polar and small in size.It can accumulate inside cells even when its concentration inside the cell is higher than outside, suggesting movement against the concentration gradient.More energy is used by cells when the molecule is present, indicating an energy-requiring process.These observations are not consistent with facilitated diffusion which is a form of passive transport requiring no energy and occurs down a concentration gradient. Instead, the characteristics described fit active transport, where molecules move against a concentration gradient with the use of energy (ATP).A 29 year old baseball player whose head is hit by a high speed baseball is brought to an emergency room. Physical examination and radiogram reveal fracture of the temporal bone and damage to the lesser petrosal nerve. Which of the following conditions could occur as a result of injury to the lesser petrosal nerve?
A. Lack of lacrimal secretion
B. Lack of submandibular gland secretion
C. Lack of parotid gland secretion
D. Constriction of the pupil
E. Ptosis of the upper eyelid
Answer:
C. Lack of parotid gland secretion
Explanation:
Based on the scenario being described within the question it can be said that this injury could cause a lack of parotid gland secretion. This is because parasympathetic preganglionic fibers that exist within the lesser petrosal nerve go into the otic ganglion, here they start to synapse which causes posterior parasympathetic fibers to join the auriculotemporal nerve which therefore supply the parotid gland for secretion of saliva. Which may otherwise not happen if the petrosal nerve is damaged.
Which of the following is true regarding cephalization?
a. Although most predatory vertebrates demonstrate cephalization, herbivores and other prey animals do not (as cephalization is thought to have evolved specifically in predators).
b. All multicellular organisms demonstrate cephalization, including both cnidarians and bilaterians.
c. The eyes of owls, the noses of bloodhounds, and the ears of bats could all be considered examples of cephalization (as each of these structures are associated with specialized sensory neurons, specific cranial ganglia and nerves).
d. Cephalization first appeared in the last common ancestor of cnidarians and bilaterians; it is not the result of convergent evolution.
e. Cephalization was initially believed to have evolved to assist in "backward" motion, as many organisms possess sensory organs at both their anterior and posterior ends.
Answer:
The correct answer is option c. "The eyes of owls, the noses of bloodhounds, and the ears of bats could all be considered examples of cephalization (as each of these structures are associated with specialized sensory neurons, specific cranial ganglia and nerves)".
Explanation:
Cephalization is a term used to describe the tendency of multiple organisms of developing a head region where the mouth, sense organs and different nerves can be concentrated. Since cephalization involves nerves, sensory neurons and specific cranial ganglia, the term include structures that are attached to the head. For instance, the eyes of owls, the noses of bloodhounds, and the ears of bats are all considered part of cephalization.
Which of the following is TRUE concerning cancer cells? A. They do not exhibit density-dependent inhibition when growing in culture. B. They stop dividing after the first checkpoint in the cell cycle. C. They are not subject to cell cycle controls. D. A and C only E. A, B, and C
Answer:
Cancer cells D. A and C only. A. They do not exhibit density-dependent inhibition when growing in culture and C. They are not subject to cell cycle controls
Explanation:
When Cancer cells stop dividing, they do so at random points in the cell cycle, not as it is said in option B, after the first checkpoint in the cell cycle. They are not subject to cell cycle controls; and they do not exhibit density-dependent inhibition when growing in culture. The thing is that, in cancer, the genetic control of cell division is altered.
Cancer cells do not exhibit density-dependent inhibition when growing in culture, and are not subject to the usual cell cycle controls. They bypass the checkpoints in a cell's life cycle that would normally regulate cell division, leading to uncontrolled growth.
Explanation:The TRUE statement concerning cancer cells is D. A and C only. Option A is accurate as cancer cells do not exhibit density-dependent inhibition when growing in culture. In normal cells, density-dependent inhibition prevents cells from becoming too densely packed and growing uncontrollably, however, cancer cells do not adhere to this regulation and continue dividing even when they are in close contact with each other. This results in the formation of a tumor.
Option C is also true. Cancer cells are not subject to regular cell cycle controls. Normally, internal controls called checkpoints monitor the cell cycle to regulate cell division. There are three major checkpoints during a cell cycle: one near the end of G₁, a second at the G₂/M transition, and the third during metaphase. However, with cancer cells, these checkpoints become nonfunctional due to mutations altering the cell-cycle control. This enables the cells to continue dividing in an uncontrolled way, leading to tumorous growth.
Option B is incorrect, cancer cells do not necessarily stop dividing after the first checkpoint in the cell cycle. Instead, they bypass these checkpoints and keep proliferating.
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Normally, in corn, genes for waxy and virescent kernel appearance are in the same chromosome. In a certain stock, however, it was found that these two genes are in different chromosomes.
Which chromosomal aberration would explain this?
A) translocation
B) inversion
C) duplication
D) deletion
Answer:
Translocation
Explanation:
Changes occur to the nuclear material from time to time. These changes are referred to as MUTATIONS. A mutation is a change in the nucleotide sequence of a gene. Mutations are of different types depending on how it occurs.
According to this question, the kind of mutation/abberation described is TRANSLOCATION. Translocation is a kind of chromosomal abnormality in which one segement of a chromosome containing certain genes breaks off and reattaches to a different chromosome.
This is the case in this question regarding the genetic composition of corns where genes for waxy and virescent kernel appearance occur in the same chromosome. It was found out that, in a stock of corn, these two genes are now on different chromosomes. This means that a segment of the chromosome containing one of the genes broke off and got reattached to a different chromosome. Hence, TRANSLOCATION MUTATION has occurred in this stock of corn.
. If a person comes in contact with this same virus years later, what does our body produce to get rid of or kill the virus
If a person comes in contact with this same virus years later, our body produces antibodies to get rid of or kill the virus
Explanation:
When a person is infected by a virus, the infected person's body develops antibodies as an immune response to act against the virus. Antibodies are produced as part of humoral immunity.
Antibodies work by neutralizing the viral activity, agglutination, phagocytosis or by complement system.
Antibodies are protein compounds which can recognize the invading pathogens and attack them.
Antigens or viral proteins in the virus leads to the production of antibodies in the host's body.
The specific antibodies triggers innate immune response upon detecting specific viral antigens when infected and will help the body to get rid of or kill the virus.
What is a classification division
Answer:
see the explanation
Explanation:
A classification or division essay groups objects, people, or events into categories by the characteristics that they share. Usually the writer begins with a group of people or things and then separates them into subgroups or types. There are a several steps to writing an effective division or classification essay.
Which of the following is a natural driver of climate change?(1 point)
solar radiation
changes in land use
emissions of gases from products
burning fossil fuels
Final answer:
The natural driver of climate change is solar radiation. Option A
Explanation:
The natural driver of climate change among the options provided is solar radiation. Solar radiation from the sun is a major source of energy for our planet, and it plays a crucial role in regulating our climate.
When the sun's rays reach the Earth, they warm the planet's surface. This warmth is then radiated back into the atmosphere as heat. However, certain gases in the atmosphere, called greenhouse gases, trap some of this heat, creating a greenhouse effect that keeps our planet warm enough to support life.
In contrast, the other options mentioned - changes in land use, emissions of gases from products, and burning fossil fuels - are not natural drivers of climate change. They are human activities that contribute to the release of greenhouse gases and hence, the acceleration of climate change.
Losses of usable energy between successive trophic levels in an ecosystem are best accounted for by _________
Answer:
The 2nd law
Explanation:
Answer:
The second law of thermodynamics
Explanation: