Wildfires are _______.
a.
a human source of air pollution
b.
a natural source of air pollution
c.
both a natural and human source of air pollution
d.
none of the above

The correct answer is:    [C]:

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             →  " the Coriolis effect " .

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Hope this helps!

       Best wishes!

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Option 3: By removing hydrogen because of fluorine's attraction to hydrogen's nucleus.

The reaction of ethene and halogen generally breaks the carbon-carbon double bond and substitution of halogen on carbon takes place, this is known as halogenation reaction. This is in the case of reaction of ethene with chlorine, bromine and iodine. In the case of fluorine,  due to high electronegativity it get attracts to the nucleus of hydrogen and form hydrogen fluorine gas. Therefore, halogentaion reaction do not take place in the case of ethene and iodine.

Ethene explosively reacts with fluorine to form carbon and hydrogen fluoride gas. The reaction is as follows:

[tex]CH_{2}CH_{2}+2F_{2}\rightarrow 2C+4HF[/tex]

Positron emission = emission of a positron and a neutrino when a proton is convert into a neutron. The total number of particles in the nucleus doesn't change, -1 proton +1 neutron

It's a spontaneous reaction for some nucleus.

eg:

Positron = e+

Neutrino=ve

O-15 --> N-15 + e+ +ve

Electron capture= A nucleus absorb an electron while a proton is convert in a neutron and emit a neutrino. The total number of particles in the nucleus doesn't change, -1 proton +1 neutron

eg:

Al-26 +e- --> Mg-26 + ve

Electron capture and positron emission are two mechanisms to explain the decay of some unstable isotopes. Electron capture is usually observed when the energy difference between the initial and final state is low. Mainly because of the larger amount of kinetic energy need for the expulsion of two particles with the positron emission mechanism.

Answer:

C: Single replacement

Explanation:

The energy produced by a hydrogen fuel cell that uses 1kg of hydrogen to produce a certain amount of water can be calculated using Einstein's mass-energy equivalence principle (E=mc²). Because the converted mass is approximately 1 kg, the energy produced is approximately 9 × 10⁶ Joules.

The question is asking how much energy a hydrogen fuel cell produces if it uses 1kg of hydrogen to produce a certain amount of water. Hydrogen fuel cells work through an electrochemical reaction of hydrogen and oxygen, producing water and energy.

The energy production can be calculated through E=mc², Einstein's mass-energy equivalence principle. Here, 'E' is energy, 'm' is mass, and 'c' is the speed of light. According to the data provided, the mass converted into energy is the difference between the initial hydrogen mass (1 kg) and the mass of the water produced (1.10 x 10-11 kg), which is approximately 1 kg. Therefore, the energy produced would be E=mc² = 1 kg × (3 × 10⁸ m/s)² = 9 × 10⁶ Joules.

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Answer:

a). lever and wedge

Explanation:

The two simple machines that are used in a pair of scissors are --

Lever and a wedge

i). Lever : A lever is a type of a simple machine that contains a long bar which is pivot at a point which is fixed. This fix point is known as the fulcrum of the lever.

ii). Wedge : A wedge is also a type of a simple machine which has two planes inclined to each other and that can move. It is generally used for cutting.

The graph that best demonstrates the general relationship between mass and temperature, similar to the trend of thermal energy absorbed by sand and water samples, is the first graph on the left.

The first graph on the left shows a negative correlation between mass and temperature, indicating that as mass increases, the temperature decreases.

This relationship often reflects how larger masses require more thermal energy to achieve the same temperature increase, which is a typical trend observed in thermal energy absorption experiments with different materials like sand and water.

The other graphs (middle and right) show no correlation and a positive correlation respectively, which do not align with the expected trend.

To determine a star's temperature, measuring its absorption spectrum or emission spectrum is best, as the Doppler shifts within the lines of the spectrum hint at the star's temperature. Option C, D is correct.

The colors and spectral classes obtained from these spectra can help estimate the star's temperature. The spectrum of a star reveals the specific wavelengths of light that the star emits or absorbs.

The emission spectrum reveals the wavelengths of light a star emits, which we can use to estimate the star's temperature. Similarly, by analyzing the absorption spectrum, which consists of dark lines superimposed on the continuous spectrum of the star, temperature can also be inferred.

The absorption spectrum is specifically of interest because the precise measurement of the width of absorption lines allows for determining the temperature; these Doppler shifts in the absorption lines are prominent and easier to detect, compared to shifts in the continuous spectrum.

Hence, C. D. is the correct option.

The complete question is:

If you wanted to determine the temperature of a star which measurement would you maker ?

A) Refraction

B) Doppler shift

C) emission spectrum

D) absorption spectrum

Answer:

Explanation

Answer:

Astatine  are halogens only

Nitrogen  are non metals only

Krypton (Kr) is noble gas only

Chlorine (Cl):  halogen

Sulfur (S)  non metals only

Explanation:

Answer: The correct answer is : 2) Ammonia

Amine :

These are organic compound which are derivatives of ammonia (NH₃) gas . In Amine one or more Hydrogen atom in ammonia are replaced by carbon atom.

The general structure of ammonia as bond between N and carbon . Number of carbons may vary from 1 to 4 .(Image attached )

Example : CH₃-NH₂ , CH₃-NH-CH₃

2) Amides :

These are organic compound in which the Hydroxyl (OH) group of carboxylic acid (COOH) is replaced by amino group (NH₂) . SO they are derivatives of carboxylic group but since they also have amino group , so they can be said as derivatives of ammonia . (image attached )

Example : CH₃-CO-NH2 , CH₃-CO-NH-CH₃ .

Hence it can be said that Amine and Amide are derivaties of ammonia (NH₃)

Amines and amides are derivatives of ammonia. They are formed by a process called substitution in which hydrogen atoms from the ammonia molecule are replaced by other functional groups.

Amines and amides are derivatives of ammonia. These molecules are both derived from ammonia by a process called substitution, where one or more of the hydrogen atoms in ammonia is replaced by other functional groups. For example, in an amine, one or more of the hydrogen atoms is replaced by an alkyl or aryl group. In an amide, one of the hydrogens in ammonia is replaced by a carboxyl group. This substitution leads to the properties that make amines and amides unique.

Learn more about Amines here:

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To calculate the molarity of the sucrose solution, you first find the total volume of the solution, then calculate the number of moles of sucrose, and finally divide the moles of sucrose by the volume of the solution in liters. The molarity of the given sucrose solution ends up being approximately 2.67 M.

The molarity of a solution, expressed in moles of solute per liter of solution (mol/L), is calculated by first determining the total volume of the solution. Given the density (1.34 g/mL) and the mass of the solution (211.4 g sucrose + 100 g water = 311.4 g), the volume of the solution is found by dividing total mass by the density: 311.4 g / 1.34 g/mL = 232.39 mL or 0.232 L.

Next, we find the number of moles of sucrose, which is the mass of sucrose divided by its molar mass: 211.4 g / 342 g/mol = 0.618 moles.

From these calculations, the molarity can then be calculated as moles of sucrose divided by the volume of the solution in liters: 0.618 mol/0.232 L = 2.67 M.

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The molarity of the solution is calculated by dividing the moles of sucrose by the volume of the solution. The moles of sucrose is found by dividing the mass of sucrose by its molar mass, and the volume of the solution is calculated from the total mass of the solution and its density. The calculated molarity of the solution is 2.66 M.

The question is asking for the molarity of the solution. Molarity (M) is a measure of concentration and is calculated by taking the amount of solute (in moles) divided by the volume of the solution (in liters). In this case, we know the mass of the solute (sucrose) and its molar mass, so we can calculate the moles of sucrose in the solution using these values. The mass of sucrose is 211.4 g and the molar mass is 342 g/mol, so the number of moles of sucrose is 211.4 g / 342 g/mol = 0.618 moles.

Next, we need to determine the volume of the solution. We know that the density of the solution is 1.34 g/mL and that 1 mL is equal to 1 cm^3. From the problem, we know that there are 211.4 g sucrose + 100 g water = 311.4 g in the solution. Therefore, the volume of the solution is 311.4 g / 1.34 g/mL = 232.24 mL, which converts to 0.23224 L. Now, we can calculate the molarity by dividing the moles of sucrose by the volume of the solution: 0.618 moles / 0.23224 L = 2.66 M.

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C. The design would not be cost-efficient; the plane would require more fuel due to increased thrust from higher drag.

Adding protrusions to the wings of an airplane, such as fuel pods and missiles, will likely result in increased drag, impacting the speed, fuel efficiency, stability, maneuverability, and safety of the airplane.

The likely drawback to adding protrusions to the wings, such as fuel pods, water tanks, and missiles, is increased drag. Drag is the resistance encountered by an object when it is moving through a fluid, such as air. Any protrusions on the wings will create extra surfaces that disrupt the smooth flow of air over the wings, resulting in increased drag.

Increased drag can have several negative effects on the airplane. It can reduce the airplane's speed and fuel efficiency, making it less economical to operate. Additionally, increased drag can make the airplane less stable and maneuverable, affecting its handling and safety.

Therefore, while the extra storage may be beneficial, the increased drag is a likely drawback of this design.

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Ethyl alcohol is the solvent in this mixture because it is the substance present in a larger volume and has dissolved the water.

The substance that is the solvent in a mixture is the one that makes up the majority of the solution and is responsible for dissolving the other substance (solute). In this case, the water is poured into the beaker containing ethyl alcohol, and it's mentioned that there are 600 mL of ethyl alcohol in the beaker.

Therefore, ethyl alcohol is the solvent in this mixture because it is the substance present in a larger volume and has dissolved the water. Water is the solute in this case, as it has been added to the ethyl alcohol. The fact that water is a polar compound is not relevant in determining which substance is the solvent; the solvent is typically the substance in greater quantity in the solution.

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The weight of an object with a mass of 40 kilograms on the Moon would be 66.8 Newtons, as weight is calculated by multiplying the mass by the lunar gravitational acceleration of 1.67 m/s².

If the mass of an object on Earth is 40 kilograms, and assuming that mass does not change regardless of location, this mass would remain the same on the Moon. However, since weight is a measure of the force of gravity on an object, it will vary depending on the gravitational pull of the body it is on. The gravitational acceleration on the Moon is 1.67 m/s². Therefore, on the Moon, the weight of a 40 kg object would be calculated as follows:

Weight on the Moon = mass × moon's gravitational acceleration

Weight on the Moon = 40 kg × 1.67 m/s²

Weight on the Moon = 66.8 N (Newtons)

So, if an object has a mass of 40 kilograms, its weight on the Moon would be 66.8 Newtons.

Answer:

D

Explanation: