Will give brainliest to the correct answer.

Since Amaya ran around a 1 mile track 3 times we can multiply this to find the total distance she traveled (displacement).

3 x 1 = 3 miles traveled.

-----------

Formula: [tex]V_a_v_g~=~\frac{displacement}{change~in~time}[/tex]

-----------

In this question the variables are classified as:

Displacement = 3 miles

Change in Time = 45 minutes

-----------

Now, fill in the expression to solve.

[tex]V_a_v_g~=~\frac{45}{3}\\V_a_v_g~=~15~[/tex]

-----------

Amayas average velocity is 15 minutes per mile.

______

Best Regards,

Wolfyy :)

Average Velocity = (displacement) / (time)

Displacement = distance and direction between the start-point and end-point, no matter what happens in between.

Amaya ran around the track, so she ended in the same place she started. The distance between her start-point and end-point was zero.  So . . .

Average Velocity = zero.

= = = = = = = = = =

Average Speed = (distance covered) / (time to cover the distance)

Amaya's distance = (1 mile/track) x (3 tracks) = 3 miles

Time to cover the distance = (3/4 hour)

Average speed = (3 miles) / (3/4 hour)

Average speed = (3 ÷ 3/4) mi/hr

Average speed = (3 x 4/3) mi/hr

Average speed = 4 miles per hour

Answer:

The distance of the student from the center of the merry-go-round is, r = 1.74 m

Explanation:

Given,

The acceleration of the student in merry go round, a = 3.6 m/s²

The tangential velocity of the student is, v = 2.5 m/s

The acceleration of the merry go round is given by the formula,

                                a = v² / r

Therefore,

                                 r = v² / a

                                    = 2.5² / 3.6      

                                    = 1.74 m

Hence, the distance of the student from the center of the merry-go-round is, r = 1.74 m

If an object is moving to the right in translational equilibrium, it means the sum of all the forces acting on the object is zero indicating a state of balanced forces. Translational equilibrium indicates the body is moving in a straight line at a constant speed or at rest. Equilibrium does not mean the absence of forces, but the balance of forces.

When an object is moving to the right in translational equilibrium, it means it is in a state of steady motion, either at rest or moving at a constant velocity, with no acceleration. This equilibrium occurs when the sum of all the forces acting on the object is zero, indicating the forces are balanced. If we consider three forces acting on the object: F1, F2, and F3, for it to be in translational equilibrium, the vector sum of the three forces must be zero. This can be represented mathematically as: F1 + F2 + F3 = 0. If any of the forces change its magnitude or direction, it would disrupt the equilibrium status.

Translational equilibrium stands for a body moving in a straight line at a constant speed or being at rest, while rotational equilibrium refers to objects rotating at a constant rotation or being steady.

An important point to remember is that an equilibrium state does not necessarily mean the absence of forces but signifies that forces are equally balanced.

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The angular acceleration is [tex]6.25 rad/s^2[/tex]

Explanation:

To solve this problem we can use the equivalent of Newton's second law for rotational motions:

[tex]\tau = I \alpha[/tex] (1)

where

[tex]\tau[/tex] is the torque acting on the body

I is the moment of inertia of the body

[tex]\alpha[/tex] is the angular acceleration

In this problem we have:

[tex]\tau = 450 Nm[/tex] is the torque

The moment of inertia of a solid cylinder about its axis is

[tex]I=\frac{1}{2}MR^2[/tex]

where

M = 100 kg is the mass

R = 1.2 m is the radius

Substituting,

[tex]I=\frac{1}{2}(100)(1.2)^2=72 kg m^2[/tex]

And solving eq.(1) for [tex]\alpha[/tex], we find the angular acceleration:

[tex]\alpha = \frac{\tau}{I}=\frac{450}{72}=6.25 rad/s^2[/tex]

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The gravitational force between the two objects A) It increases.

Explanation:

The gravitational force between two objects is given by:

[tex]F=G\frac{m_1 m_2}{r^2}[/tex] (1)

where

G is the gravitational constant

[tex]m_1, m_2[/tex] are the masses of the two objects

r is the separation between the objects

In this problem, object A and object B are initially at a distance of

r = 100 m

And at that distance, the force between them is

F

Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:

F' > F

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The frequency of the wave is 4 Hz

Explanation:

The relationship between wave, frequency and speed of a wave is given by the equation:

[tex]v=f \lambda[/tex]

where

v is the speed of the wave

f is the frequency

[tex]\lambda[/tex] is the wavelength

For the wave in this problem, we have:

[tex]v=60 cm/s[/tex] is the speed

[tex]\lambda=15 cm[/tex] is the wavelength

Solving the equation for f, we find its frequency:

[tex]f=\frac{v}{\lambda}=\frac{60 cm/s}{15 s}=4 s^{-1} = 4 Hz[/tex]

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Answer:

wind

Explanation:

A steeper incline plane will require more force to move an object up. This is because the component of the gravitational force acting parallel to the incline increases with the steepness, necessitating a greater force to oppose it. The force required to move objects up an incline plane, therefore, increases with the steepness of the incline.

When analyzing an object at rest on an inclined plane, the force of gravity acting on the object is divided into two crucial components - a force acting perpendicular to the plane and a force acting parallel to the plane. The perpendicular force of weight is typically equal in magnitude, but opposite in direction to the normal force. However, the force that impacts the effort needed to move an object up an incline directly is the component of force acting parallel to the plane.

As the slope of an incline plane gets steeper, this parallel component of the gravitational force increases, and it requires more force to oppose this component and move the object up the incline. Therefore, a steeper incline plane will require more force to move an object up.

In simpler terms, think of it as pushing a cart up a steep hill versus a gentle slope - the steeper hill requires more effort, or force, to push the cart up.

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Answer:True

Explanation:

Answer:true

Explanation:because the glass material is template and the wood is natural for SAE convention and normalitation have in chard that glass is more resistive than the wood

In order to have a verified or reliable answer to this question, they should take the watch apart and test the mechanism to see what causes failure.

Answer: Option D

Explanation:

For dropping a similar watch to record results, we need to buy another one. So, it becomes expensive. And, calling the manufacturer will give accurate results, but no knowledge. It is like getting multiple choices by luck.

Consulting senior faculty won’t result in any progress, because they may not have conducted these. So, one should rip off the watch, and study the mechanism, and its limitations.  The testing of mechanism gives the actual results.

Answer: B) Drop a similar watch multiple times and record the results.

Explanation:

In order to have a verified or reliable answer to this question, investigators must drop a similar watch multiple times and record the results. By doing this and repeatedly getting the same result(s), they are able to determine that their answer is in fact true.

*** I would also like to note that I got this question right on a test. Cheers!

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V

V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

Answer: 2352 J

Explanation:

A body's gravitational potential energy [tex]U[/tex] depends on its position and is mathematically expressed as follows:

[tex]U=mgh[/tex]

Where:

[tex]m=60 kg[/tex] is the mass of the skater

[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

[tex]h=4 m[/tex] is the skater's current height

Solving:

[tex]U=(60 kg)(9.8 m/s^{2})(4 m)[/tex]

[tex]U=2352 J[/tex]

Answer:

At the same time.

Explanation:

In the first case ,

intial velocity = 0

displacement = -h

acceleration = -g

Using second equation of motion,

s = ut + .5a[tex]t^{2} \\[/tex]

- h = - 0.5g[tex]t^{2} \\[/tex]

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

In the second case, consider only motion along y axis,

intial velocity = 0 ( all the velocity is along x axis)

displacement = -h ( height is same in both cases)

acceleration = -g

Using second equation of motion,

s = ut + .5a[tex]t^{2} \\[/tex]

- h = - 0.5g[tex]t^{2} \\[/tex]

t = [tex]\sqrt{\frac{2h}{g} }[/tex]

In both cases time is same.

Hence, they will reach the ground simultaneously.

Answer: A resultant vector

Explanation: Addition of two vectors can not be a scalar because vectors have a magnitude and a direction. so that they are explained by means of these two chacteristics. If addition is different from zero it will give a vector.

Answer:

Magnitude 17.85 cm

Angle: 69.36 degrees

Explanation:

Analytical sum of vectors

We have the vector 1 with magnitude 12 cm and angle 45 degrees. We'll find its cartesian components by using

[tex]v1_x=12cos45^o=8.49\ cm[/tex]

[tex]v1_y=12sin45^o=8.49\ cm[/tex]

Now we find the components of v2

[tex]v2_x=8.5cos105^o=-2.2\ cm[/tex]

[tex]v2_y=8.5sin105^o=8.21\ cm[/tex]

To add both vectors, we add their components separately

[tex]\vec{v3}=\vec{v2}+\vec{v1}[/tex]

[tex]v3_x=v1_x+v2_x=8.49\ cm-2.2\ cm=6.29\ cm[/tex]

[tex]v3_y=v1_y+v2_y=8.49\ cm+8.21\ cm=16.7\ cm[/tex]

Magnitude of [tex]\vec{v3}[/tex]:

[tex]\left \| \vec{v3} \right \|=\sqrt{v3_x^2+v3_y^2}[/tex]

[tex]\left \| \vec{v3} \right \|=\sqrt{(6.29)^2+(16.7)^2}[/tex]

[tex]\left \| \vec{v3} \right \|=17.85\ cm[/tex]

Angle of [tex]\vec{v3}[/tex]:

[tex]\theta_3=atan\left ( \frac{16.7}{6.29} \right )=69.36^o[/tex]

Answer:

A. 22 [tex]ms^{-1}[/tex]

B. NO

Explanation:

A.

During a collision , the net external force on the system is zero .

hence , the total momentum of the system can be CONSERVED .

let the mass of frosty and snowflake be m ;

therefore from principle of conservation of momentum ,

[tex]m*v_{F_{i} } +  m*v_{S_{i} } = m*v_{F_{f} } +  m*v_{S_{f} }[/tex]

so ,

[tex]m*25 + m*10 =m*13 +m*x[/tex]

[tex]x = 25+10-13 = 22 ms^{-1}[/tex]

answer for A. 22 [tex]ms^{-1}[/tex]

B.

The collision is NOT ELASTIC.

this is because if it had been elastic , the coefficient of restitution should have been 1 but it isnot i.e

[tex]e =\frac{ v_{F_{f} } - v_{S_{f} } }{ v_{S_{i} } - v_{F_{i} } } \\=\frac{13-22}{10-25} \\=\frac{9}{15} = \frac{3}{5} = 0.6[/tex] ≠ 1

thus it's an inelastic collision.

Answer:

The positively charged ions are called cations and negatively charged ions are called anions.

Explanation:

Answer:Kinetic Energy. Kinetic energy is motion — of waves, molecules, objects, substances, and objects. Chemical Energy is energy stored in the bonds of atoms and molecules.

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Answer:

Chemical Energy

Explanation:

Energy is the ability to perform work, it is usually stored in many forms. A body at rest has potential energy, a car moving has kinetic energy while  boiling water posses thermal energy. Energy is usually transformed from one form to another, it cant be destroyed.

Chemical energy is the type of energy that is stored in the bonds of the atom of chemical substances. This is the potential energy that is released when the bonds of molecules are broken. For example, the human digestive system breaks down a molecule of food and release mechanical energy for our day to day activities.

The energy stored in between bonds of atoms is chemical energy that are released  and converted to another form of energy when it is broken down.

Answer:

S = 108m

Explanation:

According to Second Law of Motion:

S = Vi*t + 0.5*a*t^2

Vi = 21m/s

a = 3m/s^2

t = 4s

Putting all values in Equation

S = 21*4 + 0.5*3*4^2

S = 84 + 24

S = 108m

Answer:  600 kg-m/s

Explanation:

Momentum = mass x velocity

momentum of spaceship 1 = 200 x 2

= 400 kg-m/s

momentum of spaceship 2 = 200 x 2

= 200 kg-m/s

Their combine momentum = 400 + 200 = 600 kg-m/s

The Answer is 600 kg-m/s

The mass of the water is 41.9 g

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by [tex]\Delta T[/tex], according to the equation :

[tex]Q=mC_s \Delta T[/tex]

where :

m is the mass of the substance

[tex]C_s[/tex] is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the change in temperature

In this problem, we have:

Q = 525 J is the amount of heat supplied to the water

[tex]\Delta T = 3^{\circ}C[/tex] is the change in temperature of the water

[tex]C_s = 4.18 J/gC[/tex] is the specific heat capacity of the water

Solving for m, we find the mass of the water:

[tex]m=\frac{Q}{C_s \Delta T}=\frac{525}{(4.18)(3.0)}=41.9 g[/tex]

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Final answer:

Using the specific heat capacity formula, we calculate the mass of water that can have its temperature increased by 3.0° C with the addition of 525 J of heat.

Explanation:

To solve the problem presented, we need to use the concept of specific heat capacity, which is the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius. The specific heat capacity of water is commonly accepted as 4,184 J/kg/
°C. We can use the formula q = mcΔT, where q is the heat added (in Joules), m is the mass of the water (in kilograms), c is the specific heat capacity, and ΔT is the change in temperature (in degrees Celsius).

We are given q = 525 J and ΔT = 3.0°C. We need to find the mass m. Rearranging the formula to solve for m, we get m = q / (cΔT). Substituting the given values:

m = 525 J / (4,184 J/kg/
°C
* 3.0°C)

By calculating this, we find the mass of water that can have its temperature raised by 3.0°C with 525 J of heat.

The final momentum is 120 kg m/s

Explanation:

According to the impuls theorem, the impulse exerted on an object (the product of force applied and time interval) is equal to its change in momentum. Mathematically:

[tex]F \Delta t = \Delta p = p_f - p_i[/tex]

where

F is the average force on the object

[tex]\Delta t[/tex]  is the time interval during which the force is applied

[tex]p_f[/tex] is the final momentum

[tex]p_i[/tex] is the initial momentum

In this problem:

F = 30 N is the force applied

[tex]\Delta t = 4 s[/tex] is the time interval

[tex]p_i = 0[/tex] is the initial momentum, since the object starts from rest

Solving for [tex]p_f[/tex], we find the final momentum:

[tex]p_f = F\Delta t=(30)(4)=120 kg m/s[/tex]

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Answer:

I think the answer is A) Power

Explanation:

Answer:

The answer A. Power

Explanation:

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

[tex]\sum F_x = ma_x[/tex]

where

m is the mass of the block

[tex]a_x[/tex] is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

[tex]a_x = 0[/tex]

So the equation becomes

[tex]\sum F_x = 0[/tex] (1)

The net force here is given by

[tex]\sum F_x = F cos \theta - F_f[/tex] (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

[tex]F cos \theta - F_f = 0\\F_f = F cos \theta = (50)(cos 60^{\circ})=25 N[/tex]

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The magnitude of the air drag is 784 N

Explanation:

When the airman is falling down, there are two forces acting on him:

- The force of gravity, downward, of magnitude

[tex]F=mg[/tex]

where

m = 80 kg is the mass of the airman

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

- The air drag, upward, of magnitude [tex]F_D[/tex], whose value is proportional to the speed of the airman

At the beginning of the fall, the speed is zero, so the air drag is also zero and therefore the airman starts accelerating due to the presence of the force of gravity, which is unbalanced. However, as the airman falls down, he gains speed, so the magnitude of the air drag increases up to a point where it becomes equal to the magnitude of the force of gravity. When this occurs, the airman no longer accelerates and continues its motion at constant velocity, which is called terminal velocity.

Therefore, at terminal velocity, the air drag is equal to the force of gravity on the airman (the weight), so we can write:

[tex]F_D = mg = (80)(9.8)=784 N[/tex]

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Answer:

A windmill. Windmills are used to harness the wind through the motion of the windmills wheels spinning. Usually, windmills are used to grind grain or pump water but now with a more modern version called the wind turbine, we can use the wind to generate energy.

Explanation:

this is one example you could use remember to change it up! :)

Three examples of machines that humans have designed are the lever, pulley, and wheel and axle. They all take advantage of mechanical advantage to reduce the input force needed by spreading the force over a greater distance.

The first machine we can consider is the lever. A lever is a simple machine that provides a mechanical advantage by increasing the distance over which an input force is applied, hence, reducing the input force needed to accomplish the same amount of work. Consider a seesaw; when one side is pushed down with a certain force, the other side goes up.

Another machine is the pulley. It reduces the effort required to lift an object by spreading the work over a longer length of rope. For example, a pulley system used in construction cranes makes it easier to lift heavy loads.

The third machine is the wheel and axle. It gives a mechanical advantage by allowing the user to exert force over a greater distance. An example of this is the use of wheel and axles in bicycles; pedaling covers a long distance but requires less force.

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Answer:

the mass of the object is 10 kg

Explanation:

In the image attached, we can see the free body diagram and using the newton's second law of movement, we will have one equation with one unknown value (the mass of the object).

where:

m [kg]

a [m/s^2]

F [N] or [kg*m/s^2]

Answer:

10kg

Explanation:

The information we have is:

Force: [tex]F=30N[/tex]

acceleration: [tex]a=3m/s^2[/tex]

What we need to know is the mass of the object. For this we can use Newton's second law:

[tex]F=ma[/tex]

Where F is the Force applied, m is the mass of the object, and a is its acceleration.

from this equation we clear for the mass [tex]m[/tex]:

[tex]m=\frac{F}{a}[/tex]

and we substitute the known values:

[tex]m=\frac{30N}{3m/s^2}=10kg[/tex]

The mass of the object is 10kg

The volume of the balloon will halve

Explanation:

Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

[tex]pV=const.[/tex]

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

[tex]p_1 V_1 = p_2 V_2[/tex]

And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:

[tex]p_1 = 101 kPa[/tex] is the initial pressure at sea level (the atmospheric pressure)

[tex]V_1[/tex] is the initial volume

[tex]p_2 = 202 kPa[/tex] is the final pressure

[tex]V_2[/tex] is the final volume

Substituting into the equation, we find:

[tex]V_2 = \frac{p_1 V_1}{p_2}=\frac{(101)V_1}{202}=\frac{V_1}{2}[/tex]

Which means that the volume of the balloon will halve.

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Answer:

[tex]\text { The acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

Explanation:

Mass of the kid 23.7 kg.

[tex]\text { The kid is accelerating down at an angle is } 47.2^{\circ} .[/tex]

[tex]^{\prime \prime} \mathrm{g}^{\prime \prime} \text { acceleration due to gravity is } 9.8 \mathrm{m} / \mathrm{s}^{2}[/tex]

We need to find the acceleration of the kid,

We know that, Parallel force acted on the kid at an angle is

F = m × g × sinθ (F = ma)

m × a = m × g × sinθ

Now, substitute the given values in the above formula to find acceleration of the kid,

[tex]23.7 \times a=23.7 \times 9.8 \times \sin 47.2^{\circ}[/tex]

23.7 × a = 232.26 × 0.733

23.7 × a = 170.24

[tex]a=\frac{170.24}{23.7}[/tex]

[tex]a=7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

[tex]\text { Therefore, acceleration of the kid is } 7.18 \mathrm{m} / \mathrm{s}^{2}[/tex]

Answer:

A

Explanation:

because u are subtracting if this is from flvs that is what i did and it was right

Answer:

A 0.89m

Explanation:

V= fλ

λ= V/f

λ=346/358

λ=0.89m

Answer:

D

Explanation:

The reproduction parts of the plant are in the flower and around it so this would eliminate the plants ablity to reproduce.