Worker A earns $9.50 per widget produced, produces 7 widgets per day, and works 5 hours per day. Worker B earns $8.80 per widget produced, produces 9 widgets per day, and works 8 hours per day. Which of these statements is true?

Answer:

the answer is 40 i had it on USATestPrep

Step-by-step explanation:

ion need one lml

Let's consider the equation of parabola, y = a·(x - α)·(x - β)

where α, β are the x-intercepts.

From the given graph, the y-intercept is (0, -3).

From the given graph, the x-intercept are (-1, 0) and (3, 0) i.e. α = -1, β = 3.

So the equation of parabola would be now, y = a·(x + 1)·(x - 3)

We can plug the y-intercept (0, -3) in the equation to find value of 'a'.

-3 = a·(0+1)·(0-3)

-3 = -3a

a = 1

So the equation of parabola would be now, y = (x + 1)·(x - 3) = x² - 2x - 3

Comparing it with y = ax² + bx + c

The x-coordinate of vertex would be, [tex] x = \frac{-b}{2a} = \frac{-(-2)}{2(1)} =\frac{2}{2} = 1 [/tex]

the y-coordinate of vertex would be, y = (1)² - 2(1) - 3 = -4.

Hence, vertex would be (1, -4).

The measure of the third angle is; 28 degrees.

An angle requires two straight line/ line segments/rays, such that they're connected on one of their endpoints.

The point of their joint is called vertex of that angle.

Those two line segments forming it are called arms of that angle.

The angle is the degree of rotation that it will take for the moving side to go from initial side to the position it is currently on.

Let the third angle be x

Given that One angle of a triangle measures 12 degrees. the second angle's measurements is five times the third.

We know that in a triangle the angles add up to 180 degrees.

so, 12 + 5x + x = 180.

Then we get

6x =168

x =28 degrees.

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Answer:

The value of cosine is [tex]\cos \theta=-\frac{20}{29}[/tex].

Step-by-step explanation:

It is given that an angle θ with the point (−20, −21) on its terminating side.

It means the right angle triangle is formed in third quadrant where length of the perpendicular is 21 and the base is 20.

According to the Pythagoras theorem,

[tex]hypotenuse^2=base^2+perpendicular^2[/tex]

[tex]hypotenuse^2=(20)^2+(21)^2[/tex]

[tex]hypotenuse^2=400+441[/tex]

[tex]hypotenuse^2=841[/tex]

Taking square root both the sides.

[tex]hypotenuse=\sqrt{841}[/tex]

[tex]hypotenuse=29[/tex]

In a right angled triangle,

[tex]\cos \theta=\frac{base}{hypotenuse}[/tex]

[tex]\cos \theta=\frac{20}{29}[/tex]

θ lie in the third quadrant and cosine is negative in third quadrant.

[tex]\cos \theta=-\frac{20}{29}[/tex]

Therefore the value of cosine is [tex]\cos \theta=-\frac{20}{29}[/tex].

Answrer

Option (a) is correct .

i.e  take 10% of $85

Reason

As given

15% and 10% on a $100 item i.e first applied 15 % discount on $ 100 and than apply 10% discount .

15 % is written in the decimal form

[tex]= \frac{15}{100}[/tex]

= 0.15

Amount becomes when 15 % discount on$100 = 100 - 0.15 × 100

                                                                              = 100 - 15

                                                                              = $ 85

Now apply 10 % discount on $ 85.

10 % is written in the decimal form

[tex]= \frac{10}{100}[/tex]

= 0.1

Amount becomes when 15 % discount on$100 = 85- 0.1 × 85

                                                                              = 85 - 8.5

                                                                              = $ 76.5

Therefore the option (a) is correct about the  successive discounts of 15% and 10% on a $100 item is $76.5 .

Formula: H(t) = 56t – 16t^2  

H(t) = - 16t^2 + 56t

A.      What is the height of the ball after 1 second? H (1) = 56(1) – 16(1) ^2 = 40 pt.

B.      What is the maximum height? X = - (56)/2(- 16) = 1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.

C.      After how many seconds will it return to the ground? – 16t^2 + 56t = 0   - 8t =0 t = 0

-          8t (2 + - 7) = 0     2t – 7 = 0  t = 7/2   Ans: 3.5 seconds

The maximum height achieved by the ball is 49 meters at time  t = 7/4 seconds.

The time dependent function is the function whose values vary with change in time. For example - f(t) = 3t + 5.

Given is a ball is thrown straight up with a initial velocity of 56 ft/s. The height (h) , of the ball (t) seconds after it is thrown is given by the formula h(t) = 56t - 16t²

The given function is -

h[t] = 56t - 16t²

Now, for maximum height -

dh/dt = 0

d/dt ( 56t - 16t²) = 0

d/dt (56t) - d/dt (16t²) = 0

56 - 16 d/dt (t²) = 0

56 - 16 x 2t = 0

56 = 32t

t = 56/32

t = 7/4 seconds

Now, at t = 7/4 seconds, the height is maximum. Substituting the value

t = 7/4 seconds, we get -

h(7/4) = 56 x 7/4 - 16 x 49/16

h(7/4) = 14 x 7 - 49

h(7/4) = 98 - 49

h(7/4) = 49 meters

Therefore, the maximum height achieved by the ball is 49 meters at time  t = 7/4 seconds.

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Answer:

False

Step-by-step explanation:

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Answer:

the answer is 10

Answer:

Step-by-step explanation: 8 inches

Answer:

B) -7x + 7y= -49

Step-by-step explanation:

Using the general equation for a line

y=mx+b

where m is the slope (positive if the line goes up from left to right and negative is it goes down from left to right)

and b is the point where the line crosses the y-axis

By th graph we can see that the line goes up from left to right, so the slope is positive, and that it crosses the y axis in -7, b= -7 and x is positive.

Solving for y in all the options

A) y = -x

B) y = x - 7

C) y = -x +7

D) y= x+7

the option that describes the line in the graph is B) -7x + 7y= -49 since when clearing for y we get y = x - 7 wich has a positive slope, and has an interception b = -7.