y equals x + z + 5 Z equals -3 y - 3 2x minus y equals negative 4 How can i solve using 3 variable systems of equation

Answers

Answer 1
To solve a set of linear equations in 3 variables, you need 3 equations. As far as I can tell, you have 2 equations here, so the best you can do is write expressions for 2 of the variables in terms of the third.

If you have
  x +z +5z = -3y -3
  3x -y = -4
Then you can rewrite as
  x = -1.5 -0.6z
  y = -0.5 -1.8z

_____
You can get this by any of the usual methods of solving linear equations. Just treat the system as two equations in x and y with the z terms on the right side of the equal sign:
  x +3y = -3 -6z
  3x -y = -4

Related Questions

78 million in scientific notation

Answers

[tex]=78\cdot1,000,000=78\cdot10^6=7,8\cdot10^7[/tex]

Answer:

[tex]78\ million=7.80\times 10^7[/tex]

Step-by-step explanation:

A number N can be written in scientific notation as :

[tex]N=p{\circ}0\times 10^q[/tex]

Where

p is the any real number

q is any integer

Here, the given number is 78 million. Firstly, we must know meaning of 1 million.

Since, [tex]1\ million=10^6[/tex]

[tex]78\ million=78.0\times 10^6[/tex]

To convert the above number in scientific notation, we can shift the decimal before 8 such that,

[tex]78\ million=7.80\times 10^7[/tex]

Hence, this is the required solution.

Trip bought an icecream cone that is 4 inches tall with a radius of 2 inches

Answers

check the picture below.

keeping in mind that in 1 US ounce there are 1.805 in³, then in 35 ounces there are 63.175 in³, and in 3 oz there are 5.415 in³.

so the volume of the cone content alone will be, the 63.175 in³ when filled up, minus the topping and minus the 5.415 in³ from the cookie shell.

[tex]\bf \stackrel{\stackrel{volume}{\textit{when filled up}}}{63.175}~~-~~\stackrel{\stackrel{volume}{\textit{of hemisphere}}}{\cfrac{2\pi r^3}{3}} ~~-~~\stackrel{\stackrel{volume}{\textit{of cookie shell}}}{5.415} \\\\\\ \stackrel{\stackrel{volume}{\textit{when filled up}}}{63.175}~~-~~\stackrel{\stackrel{volume}{\textit{of hemisphere}}}{\cfrac{2\pi (2)^3}{3}} ~~-~~\stackrel{\stackrel{volume}{\textit{of cookie shell}}}{5.415}\\\\\\ 63.175-\cfrac{16\pi }{3}-5.415[/tex]

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the probabilities. Find the probability of pulling three green marbles out with replacement

Answers

[tex] |\Omega|=25\cdot24\cdot23=13800\\
|A|=5\cdot4\cdot3=60\\\\
P(A)=\dfrac{60}{13800}=\dfrac{1}{230}\approx0.4\% [/tex]

The probability of an event is calculated as = [tex] \frac{Favorable outcomes}{Total number of outcomes} [/tex]

Here, the total number of outcomes = 12 red marbles + 8 blue marbles + 5 green marbles

So, total marbles = 25 marbles

Number of favorable or green marbles = 5 marbles

Probability of three green marbles if drawn with replacement = [tex] \frac{Number of favorable or green marbles}{Total number of marbles} [/tex] ×[tex] \frac{Number of favorable or green marbles}{Total number of marbles} [/tex] × [tex] \frac{Number of favorable or green marbles}{Total number of marbles} [/tex]

Probability of three green marbles if drawn with replacement = [tex] \frac{5}{25} [/tex] × [tex] \frac{5}{25} [/tex] × [tex] \frac{5}{25} [/tex]

Probability of three green marbles if drawn with replacement = [tex] \frac{1}{125} [/tex]

I don't understand this problem can you help?

Answers

Comment
The question is the same as drawing a Black marble. That's one way to look at it. Another is to draw a gray and then subtract that probability of not drawing a gray. I'll do both. Choose the one that is clearest in your mind.

Method One
Total number of marbles = 21 + 11 = 32 marbles of both colors. Probability of drawing a black marble = 
P(B) = P(~gray) = 11 / 32

Method Two
A. Find the probability of drawing a gray marble.
There are 21 gray marbles and 32 total
P(G) = Number of Gray's / total
P(G) = 21 / 32
P(~G) = 1 - 21/32
P(~G) = 32/32 - 21/32
P(~G) = 11/32  <<<< Answer

Use a calculator to find the mean and standard deviation of the data. Round to the nearest tenth. 6, 7, 19, 7, 18, 7

Answers

Answer:

The mean is 10.7 and the standard deviation is 5.6.

Step-by-step explanation:

To find the mean, add together all of the data and divide by the number of data points:

(6+7+19+7+18+7)/6 = 64/6 = 10.7

To find the standard deviation, subtract each data point from the mean, square them and find the sum:

(6-10.7)²+(7-10.7)²+(19-10.7)²+(7-10.7)²+(18-10.7)²+(7-10.7)²

=(-4.7)²+(-3.7)²+(8.3)²+(-3.7)²+(7.3)²+(-3.7)²

=22.09+13.69+68.89+13.69+53.29+13.69 = 185.34

Next divide this by 6, the number of data points:

185.34/6 = 30.89

Lastly, take the square root:

√30.89 = 5.6

John plays a game in which he throws a baseball java questions

Answers

Which statement correctly describes these electric field lines?

Q # 15 find the volume of the sphere

Answers

C IS THE CORRECT ANSWER


[tex]4 \times 5 \times 5 \times 5 \times \pi \times \frac{1}{3} = \frac{500\pi}{3} \\ = \frac{1570}{ 3} = 523.33[/tex]


good luck
The volume of a is found by using the formula;

Area = (4/3)πr³
Where r ⇒ radius of the sphere
            π=3.14

Area = (4/3)× 3.14 ×5³
        =523.33333 in³

To the nearest cubic, the  answer is 523 in³

You scored the following grades on your first three math tests: 71, 78, 81. You only have one test remaining. What is the highest possible test average you can get?

Answers

Assuming the highest score for a test is 100.

Highest possible total scores for 4 tests = 71 + 78 + 81 + 100 = 330

Highest possible average score for 4 tests = 330 ÷ 4 = 82.5

Answer: 82.5
The answer is 82.5 Hope this helps

Which equation represents a hyperbola with a center at (0,0), a vertex at (0,60), and a focus at (0,-65)

Answers

Answer:

So for everybody in the future, a clarification is d)y^2/60^2 -x^2/25^2=1

Ans: [tex]\( \frac{y^2}{60^2} - \frac{x^2}{25^2} = 1 \)[/tex]

The standard form equation of a hyperbola with the center at the origin (0,0), a vertical axis, a vertex at (0, a), and a focus at (0, c) is given by:

[tex]\[\frac{y^2}{a^2} - \frac{x^2}{b^2} = 1\][/tex]

where [tex]\(c\)[/tex] is the distance from the center to the focus, and [tex]\(b\)[/tex] is related to [tex]\(a\) and \(c\)[/tex] by the equation [tex]\(c^2 = a^2 + b^2\)[/tex].

In your case, the center is at (0,0), the vertex is at (0,60), and the focus is at (0,-65). The distance from the center to the focus is [tex]\(c = 65\)[/tex], and the distance from the center to the vertex is [tex]\(a = 60\)[/tex]. Using the relationship [tex]\(c^2 = a^2 + b^2\)[/tex], we can find b:

[tex]\[65^2 = 60^2 + b^2\][/tex]

Solving for b:

[tex]\[4225 = 3600 + b^2\][/tex]

[tex]\[b^2 = 625\][/tex]

[tex]\[b = 25\][/tex]

Now, substitute [tex]\(a\), \(b\), and \((h, k) = (0, 0)\)[/tex] into the standard form equation:

[tex]\[\frac{y^2}{60^2} - \frac{x^2}{25^2} = 1\][/tex]

So, the equation of the hyperbola is:

[tex]\[\frac{y^2}{3600} - \frac{x^2}{625} = 1\][/tex]

[tex]\( \frac{y^2}{60^2} - \frac{x^2}{25^2} = 1 \)[/tex]

Which of the following points are more than 5 vertical units away from the point left-parenthesis 0 comma negative 2 right-parenthesis? Choose all that apply. (2 points) left-parenthesis 6 comma negative 2 right-parenthesis left-parenthesis negative 8 comma negative 2 right-parenthesis left-parenthesis 0 comma negative 8 right-parenthesis left-parenthesis 0 comma 4 right-parenthesis

Answers

right-parenthesis left-parenthesis 0 comma negative 8 

Given point is (0, -2).

Given options are A(6, -2); B(-8, -2); C(0, -8); D(0, 4).

It says to select the options that are more than five units vertically away from the given point.

"Vertically away" means the x-coordinate would be same and y-coordinate would be shifted up or down.

Since it says to shift more than five units vertically away, so we must have :-

y > -2 + 5 or y < -2 - 5.  

Therefore, y > 3 or y < -7.

Hence, option C and D are correct i.e. (0, -8) and (0, 4).

The service plan for edith's cell phone charges her $29.50 a month for 300 minutes and 10¢ a minute for each additional minute over the 300 minutes. if edith uses 400 minutes this month, how much money will she have to pay?

Answers

No matter how much or little she talks, she'll pay at least $29.50 a month. This is for 300 minutes, meaning she's 100 minutes over the maximum (400 - 300).  We then multiply this amount by 0.10 and add it to 29.50. To write this as an equation, it would be 29.50 + x0.10 where x is the number of minutes over 300. In this case 29.50 + (100)0.10 = 29.50 + 10 = $39.50

Please please help me with this

Answers

n=1→an=a1 (first term)=16 (on the graph for n=1)→First term = 16
n=2→an=a2 (second term) = 4 (on the graph for n=2)→Second term = 4

ratio=(Second term)/(First term)=a2/a1=4/16
Simplifying the fraction dividing the numerator (4) by 4 and the denominator (16) by 4:
ratio=(4/4)/(16/4)→ratio=1/4

Answer: Option A. First term = 16, ratio = 1/4

25 pt question amd will mark brainliest

Answers

Hello!

The angles are supplementary meaning they add to 180°

a + 2a + 3 = 180

Combine like terms

3a + 3 =  180

Subtract 3 from both sides

3a = 177

Divide both sides by 3

a = 59

the answer is 59°

Hope this helps!
The two angles labeled are alternate corresponding.

These angle are supplementary.

use the following equation to solve for a.

2a + 3 + a = 180

Solve for a now.

3a + 3 = 180
3a = 177
a = 59

Hope this helps :)

Estimate the probability that if the company books 225 persons. not enough seats will be available. 1-.81^225

Answers

Simply the expression.

1-.81^225 = 1

What is the equation of the line that passes through the points (-1,2) and (6,3) in slope intercept form

Answers

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ &&(~ -1 &,& 2~) &&(~ 6 &,& 3~) \end{array} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-2}{6-(-1)}\implies \cfrac{3-2}{6+1}\implies \cfrac{1}{7} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=\cfrac{1}{7}[x-(-1)]\implies y-2=\cfrac{1}{7}(x+1) \\\\\\ y-2=\cfrac{1}{7}x+\cfrac{1}{7}\implies y=\cfrac{1}{7}x+\cfrac{1}{7}+2\implies y=\cfrac{1}{7}x+\cfrac{15}{7}[/tex]

Answer:

Step 1: Choose (x1, y1). (6,3)

Step 2: x2= -1 y2=2

Step 3: 1/7

Step 4: b= 15/7

What is the equation of the line in slope-intercept form?

B) y=1/7x+15/7

Step-by-step explanation:

The bold numbers are the answers.

( I need mo pts)

Suppose the spread of a direct contact disease in a school is modeled by the exponential function P(t) =
2,000
1 + e3 − t
where P(t) is the total number of people infected after t hours. What does 2,000 represent in equation?
A) the rate at which the disease spreads
B) the number of the people in the school
C) the expected change in number of people infected
Eliminate
D) the total number of people infected after t hours

Answers

B. The number of people in the school, in an exponential function, the first number should always be the initial amount.

if 3 m equals 12 what is the value of 6(m-1)

Answers

find m in the first equation:
3m = 12
divide both sides by 3:
m = 12/3
m = 4

now yo know m so replace m with 4 in the second equation:

6(m-1) = 6(4-1)
do the subtraction inside the parenthesis first
6(4-1) = 6(3)

now multiply 6 and 3:  6 x 3 = 18

find the value of q in the following system so that the solution to the system is(4,2) 3x-2y=8
2x+3y=Q

Answers

we have that
3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2

the solution is the point (4,2)
in the equation 2 substitute the value of
x=4
y=2
so
2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14

the answer is
Q=14

1. demand for product
2. example of fixed cost buyer's
3. sales receipts
4. credit discount
5. example of variable cost
6. moves slow-moving goods
7. business upturn
8. used for business expansion
9. depends on prime rate
10. assures profit on item sold

2/10, net 30
credit
interest rate
workers' wages
revenue
recovery
rent
markdown
markup
buyer's willingness to pay

Answers

1. demand for product       buyer's willingness to pay .   
2. example of fixed cost buyer's ----rent
3. sales receipts 
4. credit discount 
5. example of variable cost 
6. moves slow-moving goods ---markdown
7. business upturn 
8. used for business expansion 
9. depends on prime rate
10. assures profit on item sold       markup     

2/10, net 30 
credit 
interest rate
 workers' wages
revenue 
recovery


Answer:

Interest rate - 9

Revenue - 3

Recovery - 7

Markdown - 6

Buyer's willingness to pay - 1

Markup - 10

Worker's wages - 5

2/10 net 30 - 4

Credit - 8

Rent - 2

Step-by-step explanation:

Just did this on odyssey

A 25-foot-long footbridge has two diagonal supports that meet in the center of the bridge. Each support makes a 65∘ angle with a short vertical support.

What is the length x of a diagonal support, to the nearest tenth of a foot?

x≈_____ feet

Answers

Consider the diagram. From SOH CAH TOA, you know that
  sin(65°) = (12.5 ft)/x
  x = (12.5 ft)/sin(65°)
  x ≈ 13.8 ft

Answer:

13.

Step-by-step explanation:

Please help me understand this.

Answers

Number of tiles in blue ring = 6
Number of tiles in yellow ring = 12
Number of tiles in blue ring = 18

Observe the terms, they are forming an Arithmetic series as each term is 6 more than the previous term. We are to find the number of tiles in 30th ring, which will be the 30th term of the A.P.

So,

30th term of AP = 1st term +(30 - 1) x Common Difference
30th term of AP = 6 + 29 x 6 = 180

Thus, there will be 180 tiles in the 30th ring of white tiles

which of the following best describes the English expression the product of two and a number minus eleven

Answers

That expression would usually be interpreted to mean
  2n -11

_____
It is somewhat ambiguous, so could also be interpreted to mean
  2(n -11)

Wording could be changed to remove the ambiguity, if one were interested in doing that.

Which number is not in scientific notation?

A: 1.10 ⋅ 103
B: 4.0 ⋅ 1016
C: 7.03 ⋅ 10−2
D: 350 ⋅ 102

Answers

the anser would be c fo it to be in scientific notation you have to have an exponet

The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 4 miles south of the City Center. The park is 3 miles east and 5 miles north of the Center. How far is it from the mall to the park to the nearest tenth of a mile/12482564/8273204d?utm_source=registration

Answers

The park is a total of 3+3 = 6 miles east of the mall, and 4+5=9 miles north of it. The Pythagorean theorem tells you the straight-line distance in miles is
  √(6² +9²) = √117 ≈ 10.8

If y varies inversely as the square of x, and y=7/4/ when x=1, find y when x=3

Answers

y varies inversely as the square of x. So we can write the relation between x and y as:

[tex]y= \frac{k}{ x^{2} } [/tex]

where k is a constant of proportionality. It is given that y = 7/4 when x = 1.
Using these values, we can write:

[tex] \frac{7}{4}= \frac{k}{1} \\ \\ k= \frac{7}{4}[/tex]

So, now the equation in terms of x and y can be written as:

[tex]y= \frac{7}{4 x^{2} } [/tex]

We are to find y when x = 3. So we can write:

[tex]y= \frac{7}{4(9)}=\frac{7}{36} [/tex]

Thus, for x= 3 value of y will be 7/36

Two positive numbers have a difference of four and a product of 96 what are the numbers

Answers

Answer:
The two positive numbers are 12 and 8

Explanation:
The first phrase in the sentence tells us the difference between numbers equals 4, which can be represented a - b = 4

The second phrase tells us when multiplied together, it equals 96, which can be represented by the ab = 96, or a(b) = 96

So, first step is to list the factors of 96. I prefer to list them as pairs:
1, 96; 2, 48; 3, 32; 4, 24; 6, 16; and 8, 12

Now we plug each these pairs into the first equation to see if they satisfy the equation.

96 - 1 = 95               24 - 4 = 20
95 > 4                      20 > 4

48 - 2 = 46               16 - 6 = 10
46 > 4                       10 > 4

32 - 3 = 29               12 - 8 = 4
29 > 4                       4 = 4

Because a = 12 and b = 8 satisfies both equations that represent the given sentence, the two positive numbers are 12 and 8.

Complete the inequality. 9% ___ 0.4

Answers

9% is less than 0.4. 0.4 is really 4/10 which is 40% 40 is greater than 9 therefore 9% is less than 0.4! So your answer is 9%<0.4! I hope this helped!

Quadrilateral ABCD is an isosceles trapezoid. If AB || CD, AB = m + 6, CD = 3m + 2, BC = 3m, and AD = 7m - 16, solve for m.

A.) 2
B.) 3
C.) 4
D.) 5

Answers

Answer:

C.) 4

Step-by-step explanation:

we are given ABCD is an isosceles trapezoid

AB || CD

AB = m + 6

CD = 3m + 2

BC = 3m

AD = 7m - 16

Since, ABCD is an isosceles trapezoid

so, two sides must be equal

[tex]BC=AD[/tex]

now, we can plug values

[tex]3m=7m-16[/tex]

now, we can solve for m

[tex]3m-7m=7m-16-7m[/tex]

[tex]-4m=-16[/tex]

Divide both sides by -4

and we get

[tex]m=4[/tex]

Answer:

M= 4

Step-by-step explanation:

In Ms. Dole's class, students received grades of 87, 72, 99, 93, and 84 on yesterday's quiz. What was the mean of the quiz grades?

Answers

Hello!

The mean is the average of the numbers

To find the average you add them all up and divide the sum by the amount of numbers added

87 + 72 + 99 + 93 + 84 = 435

Divide the sum by the amount of numbers added

435 / 5 = 87

The answer is 87

Hope this helps!
The mean of a set of numbers is the average of all the numbers

To find the average, or the mean, the numbers must be added together and then the sum is divided by the total amount of numbers in the set.

87 + 72 + 99 + 93 + 84 = 435
435 / 5 = 87

The mean of the quiz grades is 87

43 coins, no nickels, $4.51 equal amount amount of pennies and dimes, how many of each coin

Answers

Set up
Let the dimes = d
Let the pennies = p
Let the quarters = q

Equations
You cannot mean that the pennies and dimes have equal numbers. That would mean that each had 21.5 members. Now could you mean that the dime and penny amount could be the same with 43 coins that total 4.00. Four dollars means that you need 40 dimes alone. It must mean that you are including quarters. 

p + d + p = 43          (1)
p = d                        (2)
p +10d +25q = 451  (3)

Note how this last equation = was derived. You have to multiply the dimes by 10 and he quarters by 100 and the total by 100 to get the numbers all in pennies.

Put the results of 2 into 1.
2p  + q = 43                   (4)  
You need to modify equation 3 as well.
p + 10p + 25q = 451
11p + 25q  = 451           (5)

Solve the new equations
2p +  q = 43               (4)
11p + 25q = 451        (5)

Multiply 4 by 25
25(2p- + q = 43)
50p + 25q = 1075     (6)  Subtract (5) from (6)
11p + 25q = 451
39p = 624                        Divide by 39
p = 624 / 39
p = 16

Since the pennies and dimes are equal there are 16 dimes
p + d + q = 43
16 + 16 + q = 43
32 + q = 43
q = 11

Check
16 + 10*16 + 11*25 = ?
16 + 160 + 275  = ?
451 = ?

Nice problem. Thanks for posting.
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