You have a bag full of 17 marbles. of those marbles, 3 are black. what is the probability that a marble chosen is not black? brainly

Answers

Answer 1
(17-3)/17=14/17
-----------------------
Answer 2
Total number of marbles = 17
Total number of marbles that are not black = 17 - 3 = 14

P(not black) = 14/17

Answer: 14/17

Related Questions

Conduct a chi-squared test of independence on the data presented in data set
d. assume equal probabilities of fe for each cell and make sure to report all relevant statistics, including the value of χ2 obtained, the critical value and your decision as to whether to reject the null hypothesis .

Answers

What's a chi-squared?

PLZ HELP ASAP WRITE STANDERED EQAUTION OF A CIRCLE

Answers

The generic equation of the circle is:
 (x-xo) ^ 2 + (y-yo) ^ 2 = r ^ 2
 Where,
 (xo, yo): coordinate of the center of the circle
 r: radius of the circle.
 Substituting values we have:
 (x-9.2) ^ 2 + (y + 7.4) ^ 2 = (5/3) ^ 2
 Rewriting:
 (x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
 Answer:
 
The equation of the circle is:
 
(x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9
r = 5/3
C(9.2, -7.4)

r^2 = (x-h)^2 + (y-k)^2
(5/3)^2 = (x - 9.2)^2 + (y + 7.4)^2

A, B, C, and D have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. Which sentence about the points is true?

A, B, C, and D lie on the same line.
AB and CD are perpendicular lines.
AB and CD are parallel lines.
AB and CD are intersecting lines but are not perpendicular.
AC and BD are parallel lines.

Answers

For this case we observe that the lines AB (red) and CD (purple) are cut at one point.
 We observe that the slopes of both lines are different (they are not reciprocal opposites).
 Therefore, the lines are not perpendicular.
 Answer:
 
AB and CD are intersecting lines but are not perpendicular.
 
See attached image.

Answer:

AB and CD are intersecting lines but are not perpendicular.

See attached image.

Step-by-step explanation:

What is the probability of rolling an even number or a prime number on a number cube? Write as a fraction in simplest form.

Answers

Final answer:

The probability of rolling an even number or a prime number on a six-sided die is 5/6, considering the unique favorable outcomes of 2, 3, 4, 5, and 6 against the total possible outcomes.

Explanation:

The question asks, "What is the probability of rolling an even number or a prime number on a number cube?" To answer this, first identify the outcomes on a six-sided die which are even and those that are prime.

Even numbers on a die: 2, 4, 6. Prime numbers on a die: 2, 3, 5. Notice that 2 is both even and prime, and it only needs to be counted once. Therefore, the unique favorable outcomes are 2, 3, 4, 5, 6.

The die has a total of 6 sides, making the total number of possible outcomes 6. The probability of rolling an even number or a prime number is therefore the number of favorable outcomes (5) divided by the total number of outcomes (6), which simplifies to 5/6.

hat is the sum of the geometric series in which a1 = 3, r = 4, and an = 49,152?
Hint: an = a1(r)n − 1, where a1 is the first term and r is the common ratio.

Sn = −65,535
Sn = 16,383
Sn = 13,120
Sn = 65,535

Answers

Final answer:

To find the sum of the geometric series, we use the formula: Sn = a1 * (r^n - 1) / (r - 1). Substituting the given values and solving, we find that the sum is 16,383.

Explanation:

To find the sum of a geometric series, we can use the formula Sn = a1 * (r^n - 1) / (r - 1), where Sn is the sum of the series, a1 is the first term, r is the common ratio, and n is the number of terms.

In this case, a1 = 3, r = 4, and an = 49,152. We can use the formula to find n, which is the exponent.

49,152 = 3 * (4^n - 1) / (4 - 1)

49,152 = 3 * (4^n - 1) / 3

16,384 = 4^n - 1

4^n = 16,385

n = log4(16,385)

n ≈ 7

Now, we can substitute the values into the formula for Sn.

Sn = 3 * (4^7 - 1) / (4 - 1)

Sn = 3 * (16,384 - 1) / 3

Sn = 3 * 16,383 / 3

Sn = 16,383

Therefore, the sum of the geometric series is 16,383. So the correct answer is Sn = 16,383.

The correct answer is [tex]\( S_n = 65,535 \)[/tex].

To find the sum of a geometric series, you can use the formula:

[tex]\[ S_n = a_1 \frac{(r^n - 1)}{r - 1} \][/tex]

Where:

- [tex]\( S_n \)[/tex] is the sum of the series,

- [tex]\( a_1 \)[/tex] is the first term,

- [tex]\( r \)[/tex] is the common ratio,

- [tex]\( n \)[/tex] is the number of terms.

Given [tex]\( a_1 = 3 \), \( r = 4 \), and \( a_n = 49,152 \)[/tex], we need to find [tex]\( n \)[/tex]. The formula for the [tex]\( n^{th} \)[/tex] term in a geometric series is [tex]\( a_n = a_1 \times r^{(n-1)} \)[/tex]. In this case, [tex]\( 49,152 = 3 \times 4^{(n-1)} \)[/tex]

Let's solve for n:

[tex]\[ 4^{(n-1)} = \frac{49,152}{3} \][/tex]

[tex]\[ 4^{(n-1)} = 16,384 \][/tex]

[tex]\[ n-1 = \log_4(16,384) \][/tex]

[tex]\[ n-1 = 7 \][/tex]

[tex]\[ n = 8 \][/tex]

Now that we have [tex]\( n = 8 \)[/tex], we can use it in the sum formula:

[tex]\[ S_n = 3 \frac{(4^8 - 1)}{4 - 1} \][/tex]

[tex]\[ S_n = 3 \frac{(65,536 - 1)}{3} \][/tex]

[tex]\[ S_n = 3 \frac{65,535}{3} \][/tex]

[tex]\[ S_n = 65,535 \][/tex]

Therefore, the correct answer is [tex]\( S_n = 65,535 \)[/tex].

Hey can you please help me posted picture of question

Answers

true true true true true
The answer is True.

A compound event is one in which there is more than one possible outcome. It is also defined as a probabilistic event with two or more favorable outcomes. For example, when you throw a die (singular for dice), it is called a simple event. On the other hand, when you throw a dice, it is known as a compound event. 

If ∆XYZ = ∆KLM, then < Y = Please help due today

Answers

ΔXYZ must correspond to ΔKLM, so the angles must as well

∠X = ∠K
∠Y = ∠L
∠Z = ∠M

So ∠Y = ∠L

I hope this helps!

The sum of the squares of two numbers is 18. the product of the two numbers is 9. find the numbers.

Answers

A graph shows the two numbers are either (3, 3) or (-3, -3).

Answer:

x=3 y=3

Step-by-step explanation:

The sum of the squares of two numbers is 18, and the product of those two numbers is 9, you just need to create an equation:

So the sum of the squares is 18, the first number will be represented as X and the second as Y:

[tex]x^{2}+ y^{2} =18[/tex]

And the other one is that the product of the two numbers is 9:

[tex]xy=9[/tex]

We have a system of equations here, we clear X from the first one:

[tex]x=\frac{9}{y}[/tex]

And instert that value of x in the first one:

[tex]x^{2}+ y^{2} =18\\(\frac{9}{y} )^{2}+ y^{2} =18\\81=y^2(18-y^2)\\y^4-18y^2+81=0\\(y^2-9)(y^2-9)=0\\Y^2-9=0\\y^2=9\\y=3[/tex]

By solving this equation we get that the first number is 3.

The second number is solved by inserting the value of Y into one of the equations, in this case we will use the second:

[tex]xy=9\\x=\frac{9}{y} \\x=\frac{9}{3} \\x=3[/tex]

So we get that x and y are both 3.

Q#2 Graph the relation in the table.Then use the vertical-line test.Is the relation a function

Answers

For this case we have the following table:
 x     y
 -1     3
  1    -1
  2     2
  1     3
 We observe that the graph shown in the question shows a scattering of points that do not obey any behavior of known function.
 Therefore, the table does not represent any function.
 Answer:
 The table does not represent a function.
The graph of the relation between x and y is as shown in attached figure

By applying the vertical line test we find that the relation is not a function because there are two points which are (1,-1) , (1,3) have the same value of x with different values of y which contradicts with with the rule of function.


If i know a real root of f(x) = x3 -6x2 + 11x – 6 is neither 1, even, or negative, a good guess would be?

Answers

A good guess for the real root of the polynomial [tex]f(x) = x^3 - 6x^2 + 11x - 6[/tex] that is neither 1, even, nor negative, would be a positive odd integer such as 3 or 5, considering the constraints and the Rational Root Theorem.

The real root of the cubic equation [tex]f(x) = x^3 - 6x^2 + 11x - 6[/tex] that is neither 1, even, nor negative would most likely be a positive odd number (since all positive even numbers are, by default, also excluded). Considering the smallest odd numbers greater than 1 are 3 and 5, and given that we're working with integers, a good guess for the real root would be either 3 or 5. However, one can apply the Rational Root Theorem which states that any rational root, expressed in its lowest form p/q, must have p as a factor of the constant term and q as a factor of the leading coefficient. In this case, the possible rational roots could be

divisors of 6 (constant term) over divisors of 1 (leading coefficient), which gives us only divisors of 6 itself

since the leading coefficient is 1. Among those divisors, the ones that fit the criteria of being neither 1, even, nor negative, would be 3 or positive odd integers.

7.
Find the amount of the payment for the sinking fund.

Amount Needed: $58,000

Years Until Needed: 2

Interest Rate: 6%

Interest Compounded: Semiannually


$13,863.74

$8,620.68

$28,155.52

$13,258.22

Answers

SFF = (r/n)/{(1+r/n)^nt-1} ------- where SFF = Sinking fund factor, r = Annual interest rate, n= number of payments per year, t = number of years

Substituting,
SFF = (0.06/2)/{(1+0.06/2)^2*2 -1} = 0.239

PMT = A*SFF = 58,000*0.239 = $13,863.57 ---- The closest answer is $13,863.74

Together, two people earn $28,000. One earns $2,000 more than the other. How much is the smaller income?

$30k
$26k
$14k
$13k

Answers

look at this:

2x+$2,000=$28,000
2x=$28,000-$2,000
2x=$26,000
x=26,000 divided by 2
x=$13,000

P1 +P2= 28 .     ----Equation 1
P1+2= P2 .       -------Equation 2 .          I abbreviate the thousands of $ 

Using substitution
P1+(P1+2)=28
2P1 +2=28
P1=13
then substitute into equation 2 we get
13+2=p2
P2=15

Therefore one is $15,000
and the other is 13,000

Smaller is 13,000!!!

Enrique earns 101010 points for each question that he answers correctly on a geography test. Write an equation for the number of points, yyy Enrique scores on the test when he answers xxx questions correctly.

Answers


[tex]y = 101010 \times x[/tex]

In the question it must be 10 instead of 101010, y instead of yyy and x instead of xxx.

Since, Enrique earns 10 points for each question that he answers correctly on a geography test.

We have to write an equation for the number of points, 'y' Enrique scores on the test when he answers 'x' questions correctly.

So, Number of points scored = Points scored for one question [tex] \times [/tex] Number of questions answered correctly.

So, Number of points scored = [tex] 10 \times x [/tex]

[tex] y=10 \times x [/tex]

y = 10x is the required equation.

Each gallon of shingle stain covers 120 square feet. How many gallons should you buy to cover 658 square feet?

Answers

you need to divide 658 by 120 because you know one gallon covers 120 square feet.

5.483 gallons bought to cover 658 square feet.

What is Unitary Method?

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

Each gallon of shingle stain covers 120 square feet.

We have to find gallons should be bought to cover 658 square feet.

We have to perform division

= 658/120

= 5.483 gallons

Hence, 5.483 gallons bought to cover 658 square feet.

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Hey can you please help me posted picture of question

Answers

The probability of a certain event occurring is calculated by the number of event over the total sample space. In this scenario, there is only one die with 6 faces. Therefore, the sample space is equal to 6. 

Of the six faces numbered 1 to 6, there is only one five. The probability therefore of rolling a die and getting a five is equal to 1/6. This approach is the theoretical. Hence, the answer to this item is the first option, A Theoretical. 
This might help you the empirical probability of an event is given by number of times the event occurs divided by the total number of incidents observed. Theoretical probability on the other hand is given by the number of ways the particular event can occur divided by the total number of possible outcomes.

So basically if you think about it the answer is Empirical. 

Ples help me find slant assemtotes
this one is different because it isn't a rational function



find the slant assemtotes of [tex](y+1)^2=4xy[/tex]
the equation can be rewritten using the quadratic formula as [tex]y=2x-1 \pm \sqrt{x^2-x}[/tex]

ples find slant assemtotes and show all work
thx

Answers

A polynomial asymptote is a function [tex]p(x)[/tex] such that

[tex]\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0[/tex]

[tex](y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}[/tex]

Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form [tex]p(x)=ax+b[/tex].

Ignore the negative root (we don't need it). If [tex]y=2x-1+2\sqrt{x^2-x}[/tex], then we want to find constants [tex]a,b[/tex] such that

[tex]\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0[/tex]

We have

[tex]\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}[/tex]
[tex]\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}[/tex]
[tex]\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}[/tex]

since [tex]x\to\infty[/tex] forces us to have [tex]x>0[/tex]. And as [tex]x\to\infty[/tex], the [tex]\dfrac1x[/tex] term is "negligible", so really [tex]\sqrt{x^2-x}\approx x[/tex]. We can then treat the limand like

[tex]2x-1+2x-ax-b=(4-a)x-(b+1)[/tex]

which tells us that we would choose [tex]a=4[/tex]. You might be tempted to think [tex]b=-1[/tex], but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of [tex]b[/tex], we have to solve for it in the following limit.

[tex]\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0[/tex]

[tex]\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2[/tex]

We write

[tex](\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}[/tex]

Now as [tex]x\to\infty[/tex], we see this expression approaching [tex]-\dfrac12[/tex], so that

[tex]-\dfrac12=\dfrac{b+1}2\implies b=-2[/tex]

So one asymptote of the hyperbola is the line [tex]y=4x-2[/tex].

The other asymptote is obtained similarly by examining the limit as [tex]x\to-\infty[/tex].

[tex]\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0[/tex]

[tex]\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0[/tex]

Reduce the "negligible" term to get

[tex]\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0[/tex]

Now we take [tex]a=0[/tex], and again we're careful to not pick [tex]b=-1[/tex].

[tex]\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0[/tex]

[tex]\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2[/tex]

[tex](x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}[/tex]

This time the limit is [tex]\dfrac12[/tex], so

[tex]\dfrac12=\dfrac{b+1}2\implies b=0[/tex]

which means the other asymptote is the line [tex]y=0[/tex].

which means the other asymptote is the line .

A laterally loaded single pile is shown below. use the elastic pile solutions (based on the winkler's model) to calculate the displacement and rotation at pile head ????. assume free headed condition. pile length ???? = 30 ft; young's modulus ???????? = 3 × 10 6 psi; ????ℎ = 30 lb/in3 ; and the eccentricity ???? = 60 in.

Answers

the pile length 10=30ft.young modulus 180=3×10 6 psi. 178.579673h =30 lb/in3 and the eccentricity 1.667 yrds =60 inch

HELP PLEASE
Determine the missing statements and reasons for the following proof.

Answers

Reasons:
Reason 3: Congruent supplements theorem

Statements:
Statement 4: Angle 1 is congruent with angle 2

Answer: Option D:
Reason 3: Congruent supplements theorem.
Statement 4: Angle 1 is congruent with angle 2
Final answer:

In a mathematical proof, missing statements and reasons are usually concluded from the given statements and the relevant geometric postulates or theorems. They could include establishing the congruency of angles or declaring the parallelism of lines.

Explanation:

Without the concrete steps of the proof or the reasoning proposed, it is difficult to provide the exact missing statements and reasons. However, in a general mathematical proof, common reasons used include 'definition of congruent angles', 'definition of parallel lines', 'alternate interior angles theorem', etc.

For instance, if we have a proof that involves stating two angles are congruent, the missing statement might be 'Angle A is congruent to Angle B', and the missing reason could be 'Definition of Congruent Angles' or 'Angle Bisector Theorem', if an angle bisector comes into the picture.

Another missing statement might be 'Segment AB is parallel to Segment CD', with the reason being 'Corresponding Angles Postulate', or 'Alternate Interior Angles Theorem', if the proof involves parallel lines.

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while watching a football game, Lin Chow decided to list yardage agained as positive integers and yardage lost as negative integers. after this plays, Lin recorded 14, -7, and 9. what was the net gain or lost?

Answers

To find the net loss or gain add all three integers (14 + -7 + 9) to get 16. This is your net gain because it is positive.

K+1=3k-1 what us the answer

Answers

So let's get k on one side:
2k = 2
Divide by 2:
k = 1

If you want to check your work:
1 + 1 = 3 - 1 
2 = 2
You have to find what the varible k stands for in this case

Josiah has 3 packs of toy animals. Each pack has the same number of animals. Josiah gives 6 animals to his sister stephanie. Then josiah has 9 animals left.how many animals were in each pack?

Answers

let the number of animals in each pack be x.
Total number of animals will be 3x
after Josiah gave 6 animals to his sister the remaining animals were:
3x-6=9
thus sloving for x we have:
3x-6=9
add 6 on both sides
3x-6+6=9+6
3x=15
divide both sides by 3
(3x)/3=15/3
x=5
Answer: 
There were 5 animals in each pack

k+1=3k-1 please show me the correct steps to solve this problem

Answers

k + 1 = 3k - 1     |-3k
-2k + 1 = -1    |-1
-2k = -2    |:(-2)

k = 1

a coin is tossed , then a number 1-10 is chosen at random.what is the probability of getting heads then a number less than 4?

Answers

Probability of sequences can be calculated by multiplying the chance of the first event by the chance of the second, and so on.

The probability of tossing a coin and getting heads is 50%, or 0.5, and the probability of selecting a number less than four from 1-10 is 40%, or 0.4.

The overall probability can then be expressed as:

0.5 x 0.4 = 0.2 or 20%

There is a twenty percent chance that a heads would be tossed and a number less than four selected.

Jorge owes his father $60. After raking the lawn for the month, he has paid him $12, $8, and $9. How much money does Jorge still has owes his father?

Answers

12 + 8 + 9 = 29

60 - 29= 31

Jorge owes his father $31

The probability that a student correctly answers on the first try (the event
a.is p(a) = 0.2. if the student answers incorrectly on the first try, the student is allowed a second try to correctly answer the question (the event b). the probability that the student answers correctly on the second try given that he answered incorrectly on the first try is 0.5. find the probability that the student answers the question on the first or second try.
a.0.90
b.0.40
c.0.10
d.0.70
e.0.60

Answers

Note that the two events are mutually exclusive. If the question is answered correctly on the first try, there's no need to give it another attempt. So [tex]\mathbb P(A\cap B)=0[/tex].

We're given that [tex]P(A)=0.2[/tex] and [tex]P(B\mid A^C)=0.5[/tex]. From the first probability, we know that [tex]P(A^C)=1-0.2=0.8[/tex]. By definition of conditional probability,


[tex]\mathbb P(B\mid A^C)=\dfrac{\mathbb P(B\cap A^C)}{\mathbb P(A^C)}[/tex]
[tex]\implies\mathbb P(B\cap A^C)=0.5\cdot0.8=0.4[/tex]

We're interested in the probability of either [tex]A[/tex] or [tex]B[/tex] occurring, i.e. [tex]\mathbb P(A\cup B)[/tex]. Apply the inclusion-exclusion principle, which says

[tex]\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)-\mathbb P(A\cap B)[/tex]

We know the probability of intersection is 0, and we know [tex]\mathbb P(A)[/tex]. Meanwhile, by the law of total probability, we have

[tex]\mathbb P(B)=\mathbb P(B\cap A)+\mathbb P(B\cap A^C)=\mathbb P(B\cap A^C)[/tex]

so we end up with

[tex]\mathbb P(A\cup B)=0.2+0.4=0.6[/tex]

The probability that the student answers the question on the first or second try is 0.60.

Given

P(A) = 0.2

[tex]\rm P(B|A^c)=0.5[/tex].

What is conditional probability?

The conditional probability of an event is when the probability of one event depends on the probability of occurrence of the other event.

When two events are mutually exclusive.

Then,

[tex]\rm P(A\cap B)=0[/tex]

The first probability is;

[tex]\rm P(A^C)=1-0.2=0.8[/tex]

Therefore,

The probability that the student answers the question on the first or second try is;

[tex]\rm P(A\cup B)= P(A) +P(B)-P(A \cap B)\\\\ P(A\cup B)= P(A) +P(B|A^C) \times P(A^C)-P(A \cap B)\\\\ P(A\cup B)= 0.2+0.5 \times 0.8 -0\\\\P(A\cup B)=0.2+0.40\\\\ P(A\cup B)=0.60[/tex]

Hence, the probability that the student answers the question on the first or second try is 0.60.

To know more about Conditional probability click the link given below.

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What is the domain of the function g(x) = 52x? x > 0 x < 0 all real numbers all positive real numbers

Answers

g(x) = 52x

The domain: all real numbers.

Answer: all real numbers

Step-by-step explanation:

The given function is : [tex]g(x) = 52x[/tex], which is polynomial function with degree one.

The domain of a function is the set of all values for x for which the function must be defined.

We know that the domain of a polynomial is the entire set of real numbers because for any real number r the polynomial function exists.

Therefore, the domain of the given function [tex]g(x) = 52x[/tex] is the set of real numbers.

Solve for y.



a.10
b.12
c.15
d.18

Answers

If angle ABC is 90°, then angle CBD is 90°:

Angle ABD=90°
3x°=90°
3x=90
Solving for x:
3x/3=90/3
x=30

Angle CBD=90°
(2x+3y)°=90°
2x+3y=90
x=30
2(30)+3y=90
60+3y=90
Solving for y:
60+3y-60=90-60
3y=30
3y/3=30/3
y=10

Answer: Option a. 10

 


The answer will most likely be A

The hypotenuse of an isosceles right triangle is 14 sqrt 2. How long is each leg of the triangle?

Answers

Each leg is 14 because the hypotenuse of an isosceles right triangle is the length of either of its legs times the square root of 2. So each leg is 14 because both legs are equal in an isosceles triangle
Hope this helps!

Answer:

14

Step-by-step explanation:

Let the legs of the triangle each have length $x$ (they are equal because it is an isosceles right triangle). Then

x^2 + x^2 = (14√2)^2 = 14^2 × (√2)^2 = 14^2 × 2, so x^2 = 14^2. Given that x must be positive, we have x = 14. So, the value of each leg is 14

(Hope this helped you!)

a company that manufactures and ships canned vegetables is designing boxes in the shape of rectangular prisms to meet specific requirements. The vegetables are packed into cans that are 3 inches in diameter and 5 inches in height. Company regulations state that boxes must be filled in with two layers of 12 cans each, and be completely closed with no overlapping material. What is the smallest amount of cardboard needed to meet the company's requirements

Answers

In order to find the smallest amount of cardboard needed, you need to find the total surface area of the rectangular prism.

Therefore, you need to understand how the cans are positioned in order to find the dimensions of the boxes: two layers of cans mean that the height is
h = 2 · 5 = 10 in

The other two dimensions depend on how many rows of how many cans you decide to place, the possibilities are 1×12, 2×6, 3×4, 4×3, 6×2, 12×1. 
The smallest box possible will be the one in which the cans are placed 3×4 (or 4×3), therefore the dimensions will be:
a = 3 · 3 = 9in
b = 3 · 4 = 12in

Now, you can calculate the total surface area:
A = 2·(a·b + a·h + b·h)
   = 2·(9·12 + 9·10 + 12·10)
   = 2·(108 + 90 + 120)
   = 2·318
   = 636in²

Hence, the smallest amount of carboard needed for the boxes is 636 square inches.

Answer:

636

Step-by-step explanation:

trust

which number correctly completes this equation 3/4%x75= A. 0.255 B. 0.5625 C. 2.55. D. 5.626

Answers

3/4% × 75

3/4 of a percent is .0075.

0.0075 times 75 = 0.5625

The answer is B) 0.5625.
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