You illuminate a slit of width 0.0675 mm with light of wavelength 711 nm and observe the resulting diffraction pattern on a screen that is situated 2.21 m from the slit. what is the width, in centimeters, of the pattern\'s central maximum?

Answers

Answer 1

In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by
[tex]y= \frac{n \lambda D}{a} [/tex]
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern
[tex]\lambda[/tex] is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit

In our problem,
[tex]a=0.0675 mm=6.75 \cdot 10^{-5} m[/tex]
[tex]\lambda=711 nm = 7.11 \cdot 10^{-7} m[/tex]
[tex]D=2.21 m[/tex]

And the distance of the first minimum (n=1) from the center of the pattern is
[tex]y= \frac{n \lambda D}{a}= \frac{(1) (7.11 \cdot 10^{-7} m)(2.21 m)}{6.75 \cdot 10^{-5} m}=2.33 \cdot 10^{-2} m =2.33 cm [/tex]

The problem asks for the width of the pattern's central maximum. This will be equal to the distance between the first minimum on one side and the first minimum on the other side, so it will be equal to twice the distance we just found:
[tex]\Delta y_{max} = 2 y = 2\cdot 2.33 cm= 4.66 cm[/tex]

Related Questions

you drop a glass on the floor and it shattters chemical or physical change ?

Answers

This describes a physical change. The glass shattering changes its physical shape and appearance only, as it retains its chemical composition.

This is Physical change.

Hope this helps!

What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?

Answers

Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.

v = momentum ÷ m
= (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s

kinetic energy = (mv∧2)÷2
= (9.1×10∧-31 × 1,153,846.154∧2) ÷2
= (1.21154×10∧-18) ÷ 2
= 6.05769×10∧-19 J

Answer:

K = 6.02 × 10⁻¹⁹ J

Explanation:

The momentum (p) of an electron is its mass (m) times its speed (v).

p = m × v

v = p / m = (1.05 × 10⁻²⁴ kg.m/s) / 9.11 × 10⁻³¹ kg = 1.15 × 10⁶ m/s

We can find the kinetic energy (K) using the following expression.

K = 1/2 × m × v²

K = 1/2 × 9.11 × 10⁻³¹ kg × (1.15 × 10⁶ m/s)²

K = 6.02 × 10⁻¹⁹ J

Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the milky way galaxy (which is around 300km/s). suppose the star was actually moving toward the earth at a more reasonable 300km/s. what wavelength λ would the 656.46-nm line move to? use 299,792km/s for the speed of light. express your answer in nanometers to five significant figures.

Answers

According to Doppler Effect, an observer at rest will perceive a shift in the wavelength or frequency of the radiation emitted by a source in movement.This shift is given by the formula:
[tex] \frac{ \lambda - \lambda_{0} }{ \lambda_{0} } = \frac{-v}{c} [/tex]

where:
[tex] \lambda[/tex] = observed wavelength
[tex] \lambda_{0}[/tex] = wavelength at rest
v = speed of source (positive if towards the observer, negative if away from the observer)
c = speed of light

Therefore, we can solve for the observed wavelength:
[tex]\lambda = \lambda_{0} (\frac{-v}{c}) + \lambda_{0} \\ \lambda = \lambda_{0} (1 - \frac{v}{c})[/tex]

Substituting the given data:
[tex]\lambda = 656.46 (1 - \frac{300}{299792})[/tex]
= 655.80 nm

Hence, the observed wavelength of the line would be 655.80 nm. Note that this value is smaller than the one at rest, which means that we have a blue-shift, as expected for an approaching source.

The hydrogen line at 656.46 nm shifts to about 655.80 nm if a star is traveling 300 km/s toward Earth.

Using the Doppler Effect to Determine the Wavelength Shift

First, note the speed of light: c = 299,792 km/s.Original wavelength of the hydrogen line: λ₀ = 656.46 nm.Star's velocity towards Earth: v = -300 km/s (negative because the star is approaching).

Use the Doppler shift formula for wavelengths:

[tex]\[\lambda = \lambda_0 \sqrt{\frac{c - v}{c + v}}\][/tex]

Plugging in the values:

[tex]\[\lambda = 656.46 \, \text{nm} \sqrt{\frac{299,792 - 300}{299,792 + 300}}\][/tex]

Calculate the ratio:

Ratio = √(299,492 / 300,092) ≈ √(0.998)

Evaluate the square root:

[tex]\[\frac{299,492}{300,092} \approx 0.998\][/tex][tex]\[\sqrt{0.998} \approx 0.999\][/tex]

Compute the shifted wavelength:

[tex]\[\lambda \approx 656.46 \, \text{nm} \times 0.999\][/tex] ≈ 655.80 nm

The 656.46-nm line would shift to approximately 655.80 nm if the star were moving towards Earth at 300 km/s.

Complete question:

Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm. Even at such low fractions of the speed of light these stars are moving quite quickly (thousands of kilometers a second) compared to the standard velocity dispersion in the Milky Way galaxy (which is around 300 km/s). Suppose the star was actually moving toward the earth at a more reasonable 300 km/s. What wavelength I would the 656.46-nm line move to? Use 299, 792 km/s for the speed of light. Express your answer in nanometers to five significant figures.

Calculate the weight ofa 58 kg astronaut on the moon where g=1.6 m/s2

Answers

weight = (mass) x (gravity)

On the moon, gravity = 1.6 m/s² .

The astronaut, with his mass of 58 kg, weighs

(58 kg) x (1.6 m/s²) = 92.8 newtons (about 21.1 pounds)

On the Earth, gravity = 9.8 m/s² .

The astronaut, with his mass of 58 kg, weighs

(58 kg) x (9.8 m/s²) = 568.4 newtons (about 127.9 pounds)

A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. calculate the time in which the ball will reach the ground.

Answers

The ball moves by uniformly accelerated motion, and its vertical position at time t is described by the following law
[tex]y(t) = h+v_0t - \frac{1}{2}gt^2 [/tex]
where
[tex]h=4.21 m[/tex] is the initial height from which the ball starts its motion
[tex]v_0=1.53 m/s[/tex] is the initial velocity of the ball
[tex]g=9.81 m/s^2[/tex] is the gravitational acceleration

The time in which the ball reaches the ground is the time t at which the vertical position y(t) becomes zero:
[tex]0= h + v_0 t - \frac{1}{2}gt^2[/tex]
Which means
[tex]0=4.21 + 1.53 t - 4.9 t^2 [/tex]

whose solutions are:
[tex]t=-0.78 s[/tex]
[tex]t=1.10 s[/tex]
Neglecting the negative solution (since it has no physical meaning), we can say that the ball reaches the ground after 1.10 s.

The time in which the ball will reach the ground is about 1.10 s

Further explanation

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about Kinematics.

We will solve it in the following way

Given:

initial speed = u = 1.53 m/s

initial height = H = 4.21 m

Unknown:

time taken = t = ?

Solution:

[tex]H = ut - \frac{1}{2}gt^2[/tex]

[tex]-4.21 = 1.53t - \frac{1}{2}(9.8)t^2[/tex]

[tex]-4.21 = 1.53t - 4.9t^2[/tex]

[tex]4.9t^2 - 1.53t - 4.21 = 0[/tex]

We will solve the above equation using the following quadratic function formula:

[tex]t = \frac{1.53 + \sqrt{1.53^2 - 4(4.9)(-4.21)}}{2(4.9)}[/tex]

[tex]t \approx 1.10 ~ s[/tex]

Learn moreVelocity of Runner : https://brainly.com/question/3813437Kinetic Energy : https://brainly.com/question/692781Acceleration : https://brainly.com/question/2283922The Speed of Car : https://brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

On a dry day, just after washing your hair to remove natural oils and drying it thoroughly, run a plastic comb through it. Small bits of paper will be attracted to the comb. Explain why.

Answers

When the surface of the comb rubs on your hair, the comb is electrically charged. When the comb comes close to the paper, the charge on the comb causes charge separation on the paper bits. Since paper is neutral, positive and negative charges are equivalent. The charge on the comb charges the area of the bit of paper nearest the comb to the opposite. Thus, the bits of paper become attracted to the comb.

Final answer:

A plastic comb can attract small bits of paper due to the electrostatic charge created by friction. This effect is reduced in moist air as humidity conducts the charge away.

Explanation:

When a plastic comb is run through hair, it can attract small bits of paper. This is due to the electrostatic charge that is created by friction when the comb is dragged against the hair. The comb becomes negatively charged as electrons are transferred from the hair to the comb, resulting in an electrostatic force that can attract neutral objects, such as pieces of paper.

If you repeat the experiment in a moist environment, such as a bathroom after a shower, you may observe that the electrostatic effect is reduced. This is because water molecules in the air increase the humidity, which conducts the charge away, thereby neutralizing the electrostatic effect more rapidly than in dry air.

Torn paper may be more effective than cut paper because the tearing process can create more irregularities and protrusions on the edges of the paper, providing more opportunities for the electric force to act upon these points compared to the relatively smooth edges of cut paper.

Earth is closest to the sun at what part of its orbit?

Answers

Earth is closest to the sun at the point in its orbit called the "perihelion" .

Our planet passes that point in its orbit sometime during the first few days
of January.

Here the dates of perihelion passage in 2018 and the next few years.
The times are Central Daylight Time (Chicago & Dallas time).

2018 January 2, 2018 11:34 pm
2019 January 2, 2019 11:19 pm
2020 January 5, 2020 1:47 am
2021 January 2, 2021 7:50 am
2022 January 4, 2022 12:52 am

These are the moments when the Earth will be
CLOSEST to the sun in its orbit.

A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are released simultaneously, and the only force that affects their motions is the electrostatic force of attraction that applies to the other. Which particle reaches the origin first? Give your reasoning.

Answers

The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.

Final answer:

The electron will reach the origin first due to its greater acceleration, which is a result of its much smaller mass compared to the proton, despite the forces on both particles being equal in magnitude.

Explanation:

The question is asking which particle, a proton at x = -d or an electron at x = +d that are released simultaneously under the influence of electrostatic force, will reach the origin first. According to Newton's second law, force equals mass times acceleration (F = ma). Because the proton and the electron have equal and opposite charges, the magnitude of the force acting on them due to their electrical interaction will be the same. However, the mass of the proton is much greater than that of the electron, resulting in much smaller acceleration for the proton. Consequently, the electron, given its smaller mass and therefore larger acceleration, will reach the origin first.

A battery charger delivers a current of 5.8 a for 2.9 h to a 12-v storage battery. what is the total charge that passes through the battery in that time

Answers

The current is defined as the amount of charge Q that flows through a given point of a circuit in a given time [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t}[/tex]

In our problem, the time interval considered is
[tex]\Delta t= 2.9 h = 10440 s[/tex]
while the current is
[tex]I=5.8 A[/tex]
Therefore, if we re-arrange the previous equation, we can calculate the amount of charge that passes through the battery in that time:
[tex]Q=I \Delta t=(5.8 A)(10440 s)=6.05 \cdot 10^4 C[/tex]

Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 9.0 m whose uniform depth is 1.9 m . express your answer using two significant figures.

Answers

The relative pressure at the bottom of a column of fluid is given by
[tex]p_r = \rho g h[/tex]
where
[tex]\rho[/tex] is the fluid density
g is the gravitational acceleration
h is the height of the column of fluid

At the bottom of the swimming pool, h=1.9 m, and the water density is
[tex]\rho = 1000 kg/m^3[/tex], therefore the relative pressure is
[tex]p_r = (1000 kg/m^3)(9.81 m/s^2)(1.9 m)=1.86 \cdot 10^4 Pa[/tex]

To find the absolute pressure, we must add to this the atmospheric pressure, [tex]p_a[/tex]:
[tex]p= p_r + p_a= 1.86 \cdot 10^4 Pa + 1.01 \cdot 10^5 Pa =1.2 \cdot 10^5 Pa[/tex]

The measurement of an exoplanet's radius is measured in units compared to ________.

the Sun's radius
planet Earth's radius
planet Jupiter's radius
the moon's radius

Answers

the eaths radius is the correct answer, if you need proof look at nasa's website

Planet Earth's radius

Thermodynamics is the study of the relationship between thermal energy and mass. other forms of energy. types of engines. temperature.

Answers

Thermodynamics is a branch of physics concerned with heat and temperature and their relation to other forms of energy and work. The behavior of these quantities is governed by the four laws of thermodynamics, irrespective of the composition or specific properties of the material or system in question. The laws of thermodynamics are explained in terms of microscopic constituents by statistical mechanics. Thermodynamics applies to a wide variety of topics in science and engineering, especially physical chemistry, chemical engineering and mechanical engineering.

Other forms of energy.

If a muon is traveling at 70% of the speed of light, how long does it take to decay in the observer's rest frame (i.e., what is the observed lifetime τμ of the muon)? express your answer in microseconds to two significant figures.

Answers

The muon lifetime in the muon reference frame is
[tex]\tau_0 = 2.2 \mu s[/tex]

In the observer's rest frame, the muon lifetime is instead given by
[tex]\tau = \gamma \tau_0[/tex]
where
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } } [/tex] is the relativistic factor, with v being the muon speed and c the speed of light.

Since the muon is traveling at 70 % of the speed of light,
[tex]v=0.70 c[/tex]
and the relativistic factor is
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{(0.70 c)^2}{c^2} } }=1.4 [/tex]

Therefore, the muon lifetime in the observer's rest frame is
[tex]\tau = \gamma \tau_0 = (1.4)(2.2 \mu s)=3.1 \mu s[/tex]

Answer:

Observed lifetime [tex]= 3.0\mu s[/tex]

Explanation:

The lifetime of muon in the muon’s reference frame.

[tex]t^{_{0}}=2.2\mu s[/tex]

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

Here the

[tex]\gamma =\dfrac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

[tex]\gamma[/tex] is the relativistic factor.

V = Speed of muon

C = Speed of light

The muon’s speed of 70% of light speed.

Hence,

[tex]V=\dfrac{70}{100}C[/tex]

V = 0.7C

[tex]=\dfrac{1}{\sqrt{1-\frac{(0.7C)^2}{C^2}}}[/tex]

[tex]=\dfrac{1}{\sqrt{1-0.49}}[/tex]

[tex]=\dfrac{1}{\sqrt{0.51}}[/tex]

[tex]=\dfrac{1}{0.71}[/tex]

= 1.4

The lifetime of muon in observer’s rest frame.

[tex]t=\gamma t_{0}[/tex]

[tex]t=1.4\times 2.2\mu s[/tex]

[tex]t=3.0\mu s[/tex]

Further explanation:

The muon is a lepton which decays to form an electron or positron. The lifetime of the muon is 2.20 microseconds. The muon lifetime in the muon reference frame is .

But the observed lifetime [tex]= \gamma =\frac{1}{\sqrt{1-\frac{V^2}{C^2}}}[/tex]

Learn more:

1. Speed of muon https://brainly.com/question/10048817 (answer by skyluke89)

2. Muon https://brainly.com/question/13198853 answer by skyluke89 )

Keywords: Muon, Speed of light, life time.

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

Answers

C)a powerful magnet.

Answer:

C) a powerful magnet

Explanation:

The electric current running through the wire coil in an electric motor exerts force directly onto A) the battery. B) an aluminum axle. C) a powerful magnet. D) a rubber insulator.

when current is pass to the coil, an electromagnetic force field is produced. The electromagnetic force field produced then have an impact on the magnet which drives the shaft to move

Apply: what will be the total resistance and current in a parallel circuit with a 15-volt battery and three 10-ohm resistors? test your answers with the gizmo.

Answers

1) Total resistance

the total resistance of a circuit with n resistors in parallel is given by
[tex] \frac{1}{R_{eq}} = \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} [/tex]
where [tex]R_i[/tex] are the single resistances.

In our circuit, we have 3 resistors of [tex]10.0 \Omega[/tex] each, so the total resistance of the circuit is given by
[tex] \frac{1}{R_{eq}}= \frac{1}{10 \Omega}+ \frac{1}{10 \Omega}+ \frac{1}{10 \Omega}= \frac{3}{10 \Omega} [/tex]
which means a total resistance of
[tex]R_{Eq} = \frac{10 \Omega}{3}=3.33 \Omega [/tex]

2) Current in the circuit

The current in the circuit can be found by using Ohm's law:
[tex]I= \frac{V}{R_{Eq}} [/tex]
where V is the voltage of the battery and Req is the total resistance we found before. By using V=15 V, we find
[tex]I= \frac{15 V}{3.33 \Omega}=4.5 A [/tex]

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

To calculate the total resistance in a parallel circuit with three resistors of 10 ohms each, we use the formula for parallel resistance:

[tex]\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}[/tex]

Substituting the values:

1/Rtotal = 1/10 + 1/10 + 1/10

1/Rtotal = 3/10

Therefore, Rtotal = 10/3 = 3.33 ohms

Next, we calculate the total current using Ohm's Law:

I = V/Rtotal

Given the battery voltage is 15 volts:

I = 15/3.33 ≈ 4.50 amps

The total resistance in the parallel circuit with three 10-ohm resistors and a 15-volt battery is approximately 3.33 ohms. The total current through the circuit is approximately 4.50 amps.

Marie notices that most of her friends have MP3 players that are all made by a certain brand. She wants one, too, but not just any MP3 player. Marie wants to buy the exact same brand that her friends have. She thinks this is the way to fit in. Which term describes why Marie only wants a certain brand of MP3 player

Answers

the term is conformity

Picturing the way a volcano erupts to remember how a volcano functions is called a. Visualizing c. Keywording b. Categorizing d. All of these

Answers

the answer is A visual

Making a mental picture of the way a volcano erupts to remember how a volcano functions is called visualization.

What is visualization?

Visualization is the process whereby a person makes or forms a mental picture of a particular situation or occurrence in order to better understand that occurrence.

Picturing the way a volcano erupts to remember how a volcano functions is a process of visualization.

A mental picture of the volcano is made by the individual.

Therefore, Picturing the way a volcano erupts to remember how a volcano functions is called visualization.

Learn more about visualization at: https://brainly.com/question/1569390

#SPJ2

Which forces tend to slow down an object

Answers

The answer is "friction and air resistance" gravity does some of the work by keeping the object from floating away, but friction and air resistance does the biggest part. Friction is how rough the ground it meaning on tile, dirt, grass, etc... that would slow down the object and air resistance is the gravity pushing on the object also making it stop.

Hope this helps!

The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine the velocity of the block when it descends 0.5 m.

Answers

V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is
T = 1/2 I₀w² + 1/2mAVA²

= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s

Final answer:

To find the velocity of a 20-kg block descending 0.5 m, use conservation of energy, equating the potential energy lost by the block to the kinetic energy gained by the block and the rotational kinetic energy of the spool. Determine kinetic energy and rotational energy using the block's mass, spool's radius of gyration, and their shared velocity.

Explanation:

To determine the velocity of the 20-kg block after it descends 0.5 m, we can use the principles of conservation of energy. The system consists of a spool and a block, and since the block is descending, gravitational potential energy is being converted into kinetic energy and rotational energy of the spool.

We know that the potential energy (PE) lost by the block is equal to the kinetic energy (KE) gained by the block plus the rotational kinetic energy (RKE) gained by the spool:

PE = KE + RKE

PE of the block = m·g·h, where m is the mass of the block, g is the acceleration due to gravity (9.81 m/s2), and h is the height descended (0.5 m).

KE of the block = 1/2 m·v2, where v is the velocity of the block we want to find.

RKE of the spool = 1/2 I·ω2, with I being the moment of inertia of the spool and ω the angular velocity. Since the spool and the block are connected, ω = v / r, where r is the radius of the spool.

Using the radius of gyration ko, the moment of inertia I for the spool is I = mspool·ko2. By substituting all these expressions into the energy conservation equation and solving for v, we can find the velocity of the block.

Learn more about Conservation of Energy here:

https://brainly.com/question/35373077

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A printer is connected to a 1.0 m cable. if the magnetic force is 9.1 × x10-5 n, and the magnetic field is 1.3 × 10-4 t, what is the current in the cable

Answers

The magnetic force on a current-carrying wire due to a magnetic field is given by
[tex]F=ILB[/tex]
where
I is the current
L the wire length
B the magnetic field strength

In our problem, L=1.0 m, [tex]F=9.1 \cdot 10^{-5} N[/tex] and [tex]B=1.3 \cdot 10^{-4}T[/tex], so we can re-arrange the formula to find the current in the wire:
[tex]I= \frac{F}{LB}= \frac{9.1 \cdot 10^{-5} N}{(1.0 m)(1.3 \cdot 10^{-4} T)} =0.7 A [/tex]

A canister containing air has a volume of 85 cm 3 and a pressure of 1.45 atm when the temperature is 310 k. what is the pressure when the volume is increased to 180 cm 3 and the temperature is reduced to 280 k?

Answers

We can solve the problem by using the ideal gas law, which states:
[tex]pV=nRT[/tex]
where
p is the gas pressure
V is the volume
n is the number of moles
R is the gas constant
T is the absolute temperature

The initial conditions of the gas in the problem are:
[tex]p=1.45 atm =1.47 \cdot 10^5 Pa[/tex]
[tex]V=85 cm^3 = 85 \cdot 10^{-6} m^3[/tex]
[tex]T=310 K[/tex]
So we can use the previous equation to find the number of moles of the gas:
[tex]n= \frac{pV}{RT}= \frac{(1.47 \cdot 10^5 Pa)(85 \cdot 10^{-6} m^3)}{(8.31 J/mol K)(310 K)} =4.9 \cdot 10^{-3} mol [/tex]

The final conditions of the gas are:
[tex]V=180 cm^3 = 180 \cdot 10^{-6} m^3[/tex]
[tex]T=280 K[/tex]
and since the number of moles didn't change, we can find the final pressure by using again the ideal gas law:
[tex]p= \frac{nRT}{V}= \frac{(4.9 \cdot 10^{-3} mol)(8.31 J/mol K)(280 K)}{180 \cdot 10^{-6} m^3}=0.63 \cdot 10^5 Pa [/tex]

If a chromosome on unfolds itself how is transcription enhanced

Answers

Sorry that I'm late the answer is the DNA region is easily accessible

Jupiter‘s great red spot is believed to be a

Answers

The Great Red Spot is an anticyclonic (high pressure) storm that rotates around the planet at about 22°.

Cyclonic storm -gradpoint

Discuss five ways human activity has accelerated soil erosion

Answers

Answer:

road erosion, house construction, steep slope cultivation, tourism development, and animal trampling.

Explanation:

Rebekah finds that a solution of sugar in water has a volume of 1.32 fl. oz. How should she report this amount using the metric system? (1 fl. oz. = 29.6 mL)

Answers

its D i just finished the test

39.1 mL is correct answer

In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10×10−2 s from a position in which its plane is perpendicular to earth's magnetic field to one in which its plane is parallel to the field. the magnitude of earth's magnetic field at the lab location is 5.30×10−5 t .

Answers

I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
[tex]\epsilon = -N \frac{\Delta \Phi}{\Delta t} [/tex]
where
N is the number of turns in the coil
[tex]\Delta \Phi[/tex] is the variation of magnetic flux through the coil
[tex]\Delta t[/tex] is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
[tex]\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb[/tex]
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
[tex]\Phi_f = 0[/tex]

Therefore, we can calculate now the induced emf by using the first formula:
[tex]\epsilon = -N \frac{\Delta \Phi}{\Delta t}=- (250) \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V[/tex]

Which step in an investigation of arson helps insurance claims the most?

Answers

The step in an investigation of arson that help the insurance claims the most is the samples of ignition sources or the processing of evidence at the scene. The people with the insurance claims are careful in gathering investigation data for they will used it as a basis for their claim.

Answer:

Since it is for insurance purposes, inventory would be required.

Explanation: inventory is needed to file a claim. Also, I took the test and got it correct ;)

How long can the body maintain an anaerobic burst of energy

Answers

The body can maintain anaerobic burst energy takes thirty seconds to around two minutes.
We have aerobic energy and anaerobic energy. Aerobic energy is used when there is a lot of intake of oxygen into the body. While anaerobic lacks oxygen to the body for example short sprint.
Aerobic respiration is being utilized in the body whenever oxygen cannot be delivered to the muscle when contraction in needed.

What is the resistance of a 1500 w ( 120 v) hair dryer?
b. what is the current in the hair dryer when it is used?

Answers

a) power = IV
From ohms law. I =V/R
So, Power = VV/R

Therefore, R (resistance) = VV ÷ Power

R = (120×120) ÷ 1500
= 9.6 ohs.

b) From ohm's law, V=IR
So, I = V/R
= 120 ÷ 9.6
= 12.5 A

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

(a) The resistance of the hairdryer will be 9.6 ohms.

(b)the current in the hairdryer will be 12.5 A.

When all physical parameters and temperature are constant,

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law

V=IR

(a)

The following data are given as

P = 1500 w

v = 120 v

The power generated in the hairdryer

[tex]\rm{P = vI}\\\\I=\frac{P}{v} \\\\I=\frac{1500}{120}\\\\I=12.5 A}[/tex]

To obtained the resistance

[tex]\rm R=\frac{v}{I} \\\\\rm R=\frac{120}{12.5} \\\\R= 9.6 ohm}[/tex]

Hence the resistance of the hairdryer will be 9.6 ohms.

(b)

The Equation of Ohm's Law

V=IR

[tex]\rm I =\frac{V}{R} \\\\\rm I =\frac{120}{9.6}\\\\\ I= 12.5 A[/tex]

Hence the current in the hairdryer will be 12.5 A.

To learn more the ohm's law refer to the link;

https://brainly.com/question/796939

What potential increase vac must an electron be accelerated through if the most energetic photon it can emit will scatter off of a stationary electron at an angle ϕ=60∘ with wavelength 8.4×10−12m?express your answer in kilovolts to two significant digits?

Answers

Referring to Compton scattering
Δλ = h/m₀c (I- cos Ф)
λ' =λ = (0,0242×10⁻¹⁰) (1- cos 60°)
λ= λ' -(0.0242 × 10⁻¹⁰) (1- cos 60°)

7.19 ˣ 10⁻¹²m

The increased potential is given by
Vₐc = hc/eλ = 6.625 × 10 ⁻³⁴ J,s) ( 3× 10⁸ m/s ( 1.6 ˣ 10 ⁻¹⁰C)
(7.19 ˣ 10⁻¹²m)

173kV.

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