You invest $230 to start a sandwich stand and decide to charge $4.25 per sandwich. How much money will you make if you sell 75 sandwiches?

Answer:

a. strong positive is the answer.

Step-by-step explanation:

The following shows the correlation between the length of a person's hand span and how many jolly ranchers they can pick up with one hand.  

There is a strong positive correlation between the two things. We can see the scatter plot moving up as the hand span increases, the number of jolly ranchers they can pick up also increases.

Calulate limits:

limx→∞(1x−2(−3x2+7x+1))=−∞

limx→−∞(1x−2(−3x2+7x+1))=∞

Thus, there are no horizontal asymptotes.

For Oblique Asymptote:

Do polynomial long division (−3x2+7x+1)/(x-2)=−3x+1+3/(x−2)

The rational term approaches 0 as the variable approaches infinity.

Thus, the slant asymptote is y=−3x+1y=−3x+1.

There is a 94.25% probability that a bill for veterinary services costs between $42 and $133 in this local animal hospital, based on calculating Z-scores for $42 and $133 and finding the difference between probabilities.

The question pertains to the concepts of statistics, specifically the normal distribution which often appear in situations describing natural phenomena and social behavior. To solve this, we need to calculate the Z-scores for both values given and then look those Z-scores up in a standard normal distribution table, or use a calculator or software that can do this.

A Z-score is a statistical measurement that describes a value's relationship to the mean of a group of values. It's measured in terms of standard deviations from the mean.

If X is a random variable from a normal distribution with mean (µ) and standard deviation (σ), the Z-score is calculated by the formula Z = (X - µ)/σ.

For X =$42, Z1 = ($42 - $88)/$24 = -1.92 and for X=$133, Z2=($133-$88)/$24 = 1.88.

The probability that one bill for veterinary services costs between $42 and $133 equals the probability for Z values falling between -1.92 and 1.88. Refer to the standard normal distribution table or a calculator for the corresponding probabilities. The probability for Z1 equals approximately 0.0274, probability for Z2 equals approximately 0.9699. The required probability is then P(Z1

So, "there's a 94.25% chance that a bill for veterinary services costs between $42 and $133 in this local animal hospital".

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The time take him to grade 35 essays is, 5.6 hours.

Any relationship that is always in the same ratio and quantity which vary directly with each other is called the proportional.

Given that;

A teacher grades 25 students essays in 4 hours.

And, To find the time take him to grade 35 essays.

Now, Let us assume that,

Time take him to grade 35 essays is, x

Hence, We get;

25 / 4 = 35 / x

Solve for x;

x = 35 × 4 / 25

x = 5.6 hours

Thus, the time take him to grade 35 essays is, 5.6 hours.

Learn more about the proportion visit:

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To find the equilibrium price and quantity, we set the demand to be equal to the supply, solve for x, and substitute the value back into the demand equation to find the equilibrium price.

The given equation is:

p = -0.00054x + 9, where p is the unit price in dollars and x is the number of discs demanded.

The total monthly cost for pressing and packaging x copies is given by:

c(x) = 600 + 2x - 0.00002x^2

To find the equilibrium price and quantity, we need to find the point where the demand equals the supply. In this case, the demand is represented by the equation p = -0.00054x + 9 and the supply is represented by the equation c(x) = 600 + 2x - 0.00002x^2.

To solve for the equilibrium price and quantity, we set the demand equals the supply:

-0.00054x + 9 = 600 + 2x - 0.00002x^2

This equation can be solved by rearranging and solving for x:

0.00002x^2 + 2.00054x - 591 = 0

Using the quadratic formula, we can find the values of x that satisfy this equation:

x = (-2.00054 ± sqrt(2.00054^2 - 4*0.00002*(-591))) / (2*0.00002)

After calculating, we find two possible values for x, which are approximately x_1 = 13727.927 and x_2 = -0.036. However, since the quantity demanded cannot be negative, we discard the negative value.

The equilibrium quantity is approximately 13728.

To find the equilibrium price, we substitute the value of x into the demand equation:

p = -0.00054(13728) + 9

p is approximately equal to $1.53.

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Answer:

4,17,13,7

Step-by-step explanation:

i got it right :)

To assist Hugo in organizing patron pet ownership into a two-way frequency table, calculations were made to determine the number of patrons with both a dog and a cat, leading to a complete frequency table illustrating pet ownership among 41 patrons.

Hugo, the veterinarian, is attempting to organize patron pet ownership information into a two-way frequency table. First, let's establish the total number of patrons which is 41. Since 20 patrons do not have a dog, it implies that 41 - 20 = 21 patrons have a dog. Of the 41 patrons, we know that 17 have a cat. Also, 7 patrons have neither a dog nor a cat. To create the two-way frequency table, we need to figure out how many patrons have both a dog and a cat.

To find the number of patrons with both pets, we add the number of patrons without pets to those with dogs and then subtract from the total number of patrons, which gives us 41 - 20 + 7 = 28. However, since this number includes all dog owners, we need to subtract those who only have dogs and no cats, which gives us 28 - (41 - 17) = 28 - 24 = 4 patrons with both a dog and a cat.

With these calculations, we can now fill out the two-way frequency table:

Patron\PetDogNo DogTotalCat41317No Cat17724Total212041

Note: The sum of the numbers for dog owners and non-dog owners must equal the total number of patrons, and the same applies for cat ownership.

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Answer:

We can find out the missing pieces by the below explanation,

Here, the given equation,

[tex]-27 = 4x^2 - 24x[/tex]

Step 1 :

[tex]-27=4(x^2-6x)[/tex]

Step 2 :

[tex]-27+36=4(x^2-6x+9)[/tex]

Step 3 :

[tex]9=4(x-3)^2[/tex]

Step 4 :

[tex]\frac{9}{4}=(x-3)^2[/tex]

Step 5 :

[tex]\pm \frac{3}{2}=x-3[/tex]

Step 6 :

[tex]x=3\pm \frac{3}{2}[/tex]

Let the amounts of Turkey Jennifer bought be [tex] T [/tex] pounds and that of Cheese be [tex] C [/tex] pounds.

From the given information,

[tex] 6.35T+4.75C=17.13\\
T+C=3 [/tex]

Solving the above two equations together,

[tex] 6.35T+4.75(3-T)=17.13\\
(6.35-4.75)T+4.75*3=17.13\\
1.6T=2.88\\
T=\frac{2.88}{1.6}\\
T=1.8
[/tex]

Thus, Jennifer bought [tex] 1.8\;pounds [/tex] of Turkey and [tex] 3-1.8=1.2\;pounds [/tex] of Cheese.

Answer:

[tex]0.362-0.045<p<0.362+0.045[/tex]

Step-by-step explanation:

It is given that When 415 junior college students were surveyed, 150 said they have a passport, then sample proportion will be:

Sample proportion=[tex]\frac{150}{415}=0.362[/tex]

Then, [tex]ME=1.96\sqrt{\frac{0.362{\times}0.638}{415}}[/tex]

=[tex]1.96\sqrt{\frac{0.230}{415}[/tex]

=[tex]1.96(0.023)[/tex]

=[tex]0.045[/tex]

Therefore, at 95% confidence interval, the proportion of junior college students that have a passport is:

[tex]0.362-0.045<p<0.362+0.045[/tex]

The values for which the two stock prices are the same are approximately x ≈ -1.405 and x ≈ 11.405.

To find the values for which the two stock prices are the same, we need to set the equations for the prices equal to each other and solve for x.

Equation for the first stock: C = 14 + 12x - x^2

Equation for the second stock: C = 2x + 30

Setting the two equations equal: 14 + 12x - x^2 = 2x + 30

Rearranging the equation and combining like terms: x^2 - 10x - 16 = 0

Using the quadratic formula to solve for x: x = (-b ± sqrt(b^2 - 4ac))/(2a)

Plugging in the values: x = (-(-10) ± sqrt((-10)^2 - 4(1)(-16)))/(2(1))

Simplifying: x = (10 ± sqrt(100 + 64))/2

Calculating: x = (10 ± sqrt(164))/2

Approximate values: x ≈ (10 ± 12.81)/2

Therefore, the two stock prices are the same for x ≈ -1.405 and x ≈ 11.405.