The angle of the force is [tex]51.1^{\circ}[/tex]
Explanation:
To solve this problem, we can apply Newton's second law along the horizontal direction of motion of the suitcase:
[tex]\sum F_x = ma_x[/tex]
where
[tex]\sum F_x[/tex] is the net force along the x-axis
m is the mass of the suitcase
[tex]a_x[/tex] is the acceleration along the x-axis
The suitcase is moving at constant speed, so the acceleration is zero:
[tex]a_x=0[/tex]
Therefore the net force must also be zero:
[tex]\sum F_x = 0[/tex] (1)
We have two forces acting along the horizontal direction:
- The component of the push (forward) in the horizontal direction, [tex]F cos \theta[/tex], with
F = 43 N
[tex]\theta[/tex] = angle of the force with the horizontal
- The force of friction, [tex]F_f = 27 N[/tex], backward
So the net force can be written as
[tex]\sum F_x = F cos \theta - F_f[/tex] (2)
Combining (1) and (2),
[tex]F cos \theta - F_f = 0[/tex]
And so we can find the angle:
[tex]\theta = cos^{-1}(\frac{F_f}{F})=cos^{-1}(\frac{27}{43})=51.1^{\circ}[/tex]
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What is Snell law of refraction
Answer:
Snell's law tells us the degree of refraction and relation between the angle of incidence, the angle of refraction and refractive indices of given pair of media. We know that light experiences the refraction or bending when it travels from one medium to another medium. Snell's law predicts the degree of the bend.
Explanation:
Final answer:
Snell's law expresses the relationship between the incidence and refraction angles and the indices of refraction of two media, represented by the equation n₁ sin θ₁ = n₂ sin θ₂.
Explanation:
Snell's law describes the relationship between angles and indices of refraction when light passes from one transparent medium to another.
It is an essential concept in the study of optics and can be mathematically expressed as n₁ sin θ₁ = n₂ sin θ₂, where n₁ and n₂ are the refractive indices of the first and second medium, respectively, and θ₁ and θ₂ are the angles of incidence and refraction.
This law is named after the Dutch mathematician Willebrord Snell who described it in 1621, but it was also discovered by the Arabian physicist Ibn Sahl in the 10th century.
Through thorough experiments, it became evident that light rays change direction due to the differing speeds of light in various media, a concept Snell himself was not aware of but was able to confirm through the refractive indices.
Naoki's bicycle has a mass of 10 kg. If Naoki sits on her bicycle and starts pedaling with a force of 176.9 N, causing an acceleration of 2.9 m/s2, what is Naoki's mass?
Answer: 51kg
Explanation:
Mass of the bicycle = 10 kg
Total force exerted = 176.9N
acceleration = 2.9 m/s2
Naoki's mass = ?
Total mass = mass of the bicycle + Naoki's mass
Recall : Force = mass x acceleration
Total force exerted = Total mass x acceleration
Let the Total mass be y , that is
176.9 = y x 2.9
176.9/2.9 = y
Therefore :
y = 61
Therefore , the total mass is 61kg , but the mass of the bicycle is 10kg , therefore , Naoki's mass = 61 - 10
= 51kg
The mass of Naoki is 51 kg.
Explanation:
According to second law of motions from Newton, external unbalanced force applied on an object will be equal to the product of mass and acceleration of the object.
As Naoki is sitting on a bicycle, the combined mass will be acting on the acceleration leading to the force of 176.9 N. So, the total mass of Naoki and bicycle can be determined from the mathematical representation of Newton’s second law of motion as below:
[tex]\text {Force}=\text {Mass} \times \text {Acceleration}[/tex]
Thus,
[tex]\text { Total Mass }=\frac{\text { Force }}{\text { Acceleration }}[/tex]
[tex]\text { Total Mass }=\frac{176.9}{2.9}=61 \mathrm{kg}[/tex]
As the mass of the bicycle is given as 10 kg, so subtract the mass of the bicycle from the total mass to obtain the mass of Naoki.
Thus, mass of Naoki is
Total Mass-Mass of bicycle = Mass of Naoki
61-10 = 51 kg
So, the mass of Naoki is 51 kg.
You measure the voltage difference of a circuit to be 5 V and the resistance to be 1,000 ohms.
What is the current in the circuit?
Answer:
The current in the circuit will be [tex]5\times 10^{-3}\ Ampere[/tex].
Explanation:
Given:
Voltage difference = V = 5 V
Resistance = R = 1000 ohms
To Find:
Current, I = ?
Solution:
Ohm's Law:
Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.
i.e I ∝ V
∴ V = I × R
Where, I = current
V = voltage
R = resistance
Substituting the values of V and R we get
∴ 5 = I × 1000
[tex]I = \frac{5}{1000} \\I=0.005\ Ampere\\I=5\times 10^{-3}\ Ampere[/tex]
Therefore, the current in the circuit will be [tex]5\times 10^{-3}\ Ampere[/tex].
The current in the circuit can be found using Ohm's Law (I=V/R). The given values for voltage and resistance result in a current of 5 milliamperes.
Explanation:The subject matter in the question falls under the field of Physics, particularly Electricity. The problem is asking for the current in a circuit, based on given values for voltage and resistance. One can solve this by employing Ohm's Law, which describes the relationship between voltage (V), resistance (R), and current (I). Ohm's Law is represented by the formula I = V/R.
Substituting the given values into the formula, the current I is calculated as 5V / 1000Ω, which equals 0.005 Amperes, or 5 Milliamperes (mA). Thus, the current flowing in the circuit is 5 mA.
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Which statements apply to theories? Check all that apply.
A theory is a factual statement.
B theory is well-tested and widely accepted.
C theory is an explanation.
D theory cannot be revised or replaced.
E theory can help predict future events.
the answer is b,c, and e
Answer:
BCE
Explanation:
A student rapidly rubs the palms of both hands
together, after eating lunch. Which sequence
correctly describes the energy transformations that
occur?
a. chemical mechanical heat
b. mechanical heat chemical
c. heat mechanical chemical
d. mechanical nuclear heat
Answer:
Option a
Explanation:
The action of the rapid rubbing of the hands are a result of chemical reaction and responses that takes place inside our body.
When we rub our hands together, that shows the mechanical motion of the body or we can say that while rubbing hands chemical energy gets converted to mechanical energy (here, Kinetic energy).
While rubbing, due to friction, heat is produced and hence we can say that this mechanical energy has transformed to heat energy.
Thus the conversion here is from chemical to mechanical to heat energy.
Nichrome has a --------------melting piont
Answer:
Nichrome has __High__melting piont
Hope this helps
Answer:
high melting point
Nichrome is consistently silvery-grey in colour, is corrosion-resistant, and has a high melting point of about 1,400 °C (2,550 °F).
Explanation:
what is the net force if you push a cart to the right with 5N of force, and a friend pushes the cart to the left with 5N of force?..
Answer: 0 newtons
Explanation: If you push a cart to the right with 5 newtons of force to the right and a friend pushes the cart 5 newtons to the left, there will be no motion.
To understand this further, take a look at the image I provided. I provided two arrows one of the left and on on the right. If two people are pushing on the cart with the same amount of force, the net force will be 0 so it will be a balanced force. When we have a balanced force, there's no motion.
A plank rests on top of the axles of two identical wheels. Each wheel's outer radius is 0.25 meters and each wheel's axle has radius 0.05 meters. If the wheels roll 1.00 meter from their original position, how much does the plank move from its original position?
Assume that there is no slipping anywhere, and that the plank does not tip.
Answer:
0·2 m
Explanation:
The distance by which the axle of the wheel is rotated must be the same as the distance travelled by the plank, as it is mentioned that there is no slipping anywhere because if the distance is not same then there will be slipping between them as friction will be acting
Let the angle by which the wheel is rotated when it rolls by 1 m be β
∴ 1 = (outer radius of the wheel) ×β
1 = 0·25 × β
∴ β = 4 radians
The angle by which the wheel's axle is rotated will be the same as the angle rotated by the wheel as both are attached
∴ Wheel's axle will also be rotated by an angle β = 4 radians
Distance by which the axle of the wheel will get rotated = (radius of wheel's axle) × β
= 0·05 × 4 =0·2 m
∴ Plank will move from original position by 0·2 m
How much tension must a rope withstand if it is used to accelerate a 1700-kg car
horizontally at 0.50 m/s^2 ? Ignore friction.
What tension would be required to accelerate
it vertically at the same rate?
Increasing which two things would increase gravitational potential energy?
Answer:
Mass and height
Explanation:
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about [tex]9.8 m/s2.[/tex]
Which is represented as;
[tex]PE_g=mgh[/tex]
[tex]PE_g[/tex] stands for gravitational potantial energy,
m stands for mass of object,
g is the gravitational constant and
h is the height.
Here we see that mass of object and height is directly proportional to the gravitational potential energy.
That means increasing in mass and height will result in increasing gravitational potential energy.
Most of the Earth's volume is contained in the
A. mantle
B.
crust
C.
inner core
D.
outer core
Most of the Earth's volume is contained in the "mantle". The correct answer would be option (A).
What is a mantle?The mantle is a layer of semi-solid rock that lies between the Earth's thin crust and its liquid outer core. The mantle is approximately 2,900 kilometers (1,800 miles) thick and makes up about 84% of the Earth's total volume.
The crust, mantle, and core are the three coatings of the Earth. The crust is made up of minerals and solid rocks. The mantle lies under the crust and is largely made up of solid rocks and minerals, but it is punctured by pliable patches of semi-solid magma.
It is composed primarily of silicate rocks and is considered to be the source of the Earth's heat and most of its volcanic activity.
The mantle also plays a key role in plate tectonics, which is the theory that explains the movement of the Earth's continents and ocean floor.
Thus, the correct answer would be option (A) mantle.
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Which of these is a landform created due to erosion by glaciers? Delta Horn Sandbars Spit
Answer:
The answer is option B, horn.
Explanation:
The landform horn was formed because when glaciers erode down to form a sharp peak which is called a horn. All of the other options are false because none of those land forms are formed because of the erosion of glaciers
Answer:
i think a delta
Explanation:
I might be wrong but I think it leaves behind a delta.
if you travel for three hours of a speed of 30 km/h, how far will you go?
Answer:
90km
Explanation:
every hour you travel 30km and you are traveling 3 hours 30×3
how does mass speed and gravity affect potential and kinetic energy
Answer:
The formula for potential energy is, P.E = mgh joules
The formula for kinetic energy is K.E = ½ mv² joules
Explanation:
The total mechanical energy of the system is the sum of the K.E and the P.EThe potential energy of the system is associated with the position of the object from the ground.The formula for potential energy is,P.E = mgh joules
The kinetic energy of the object is associated with the velocity of the object.The formula for kinetic energy is,K.E = ½ mv² joules
From the above equation, it is clear that the P.E is dependent on the mass and acceleration due to gravity. The P.E is the product of mass, acceleration due to gravity and height of the object from the ground.Whereas the K.E is dependent on the mass and the velocity of the object. The kinetic energy does not depend on the acceleration due to gravity.A person runs 5 km North and then turns west and travels for 7 km then turn south for 2 km it takes a person 4 hours to make the journey what is the persons distance, speed, displacement and velocity
1) Distance: 14 km
2) Speed: 3.5 km/h
3) Displacement: 7.6 km at [tex]23.2^{\circ}[/tex] north of west
4) Velocity: 1.9 km/h at [tex]23.2^{\circ}[/tex] north of west
Explanation:
1)
Distance is a scalar quantity, and it corresponds to the total length of the path covered by an object during its motion, regardless of its direction.
Here we have the following motion:
[tex]d_{y1}=5 km[/tex] North
[tex]d_x = 7 km[/tex] west
[tex]d_{y2}=2 km[/tex] south
So, the distance covered is:
[tex]d=d_x + d_y = 5 + 7 +2 = 14 km[/tex]
And since it is a scalar, distance has no direction.
2)
Speed is a scalar quantity telling "how fast" an object is moving. It is calculated as:
[tex]speed=\frac{d}{t}[/tex]
where:
d is the distance
t is the time taken
In this problem, we have
d = 14 km (distance)
t = 4 h (time taken)
Substituting,
[tex]speed=\frac{14 km}{4 h}=3.5 km/h[/tex]
And since it is a scalar, it has no direction.
3)
Displacement is a vector quantity connecting the initial position to the final position of motion. The magnitude is the short distance in a straight line between the initial and final position of motion.
Here we have the following motions:
[tex]d_{y1}=5 km[/tex] North
[tex]d_x = 7 km[/tex] west
[tex]d_{y2}=2 km[/tex] south
So the net displacement in the north-south direction is
[tex]d_y = 5 - 2 = 3 km[/tex] North
[tex]d_x, d_y[/tex] are at right angle, so they form the sides of a right triangle, of which the hypothenuse corresponds to the displacement. Therefore, we can find the magnitude of the displacement by using Pythagorean's theorem:
[tex]d=\sqrt{d_x^2+d_y^2}=\sqrt{7^2+3^2}=7.6 km[/tex]
And the direction is given by
[tex]\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{3}{7})=23.2^{\circ}[/tex] north of west.
4)
Velocity is a vector quantity, given by:
[tex]velocity=\frac{d}{t}[/tex]
where
d is the displacement
t is the time taken
In this problem, we have
d = 7.6 km (displacement)
t = 4 h (time taken)
So, the velocity is
[tex]velocity=\frac{7.6 km}{4h}=1.9 km/h[/tex]
And being a vector, velocity has also a direction, which is the same of the displacement: so, [tex]23.2^{\circ}[/tex] north of west.
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If the skater has more mass of 60kg, what is her gravitational potential energy at the top of the 4m high half pipe?
2352 Joules is the “Gravitational potential energy” that a skater has.
Explanation:
"Gravitational potential energy" of an object is defined as the energy stored in the object which is at a height. Everybody at a height has some energy that is calculated by using the potential energy formula. Mathematically, "Gravitational potential energy" (GPE) is mass (m) times acceleration due to gravity (g) times height (h) of an object. Therefore, GPE = m × g × h.
From the given question,
Mass of the skater is 60 kg
The height at which skater is located is 4 m
“g” is acceleration due to gravity 9.8 [tex]m/s^2[/tex]
Substitute the given values in the GPE = m × g × h
Gravitational potential energy = 60 × 9.8 × 4
Gravitational potential energy = 2352 J .
Allison needs to graph the yearly average snowfall in Alaska. She should use a:
A)bar graph
B)line graph
Answer: Line graph
Explanation:
Allison needs to graph the yearly average snowfall in Alaska. She should use a:
pie chart
pictograph
bar graph
line graph
A rock is dropped from a cliff.
What will eventually happen to the rock's motion?
A. Gravity will cause the rock to slow down before it reaches Earth.
B. Air resistance will cause the rock to accelerate as it falls.
C. The rock will continue falling until Earth exerts a contact force on the rock.
D. Friction will cause the rock to continue in its state of motion.
Answer:
C
Explanation:
A 70kg runner begins his slide into second base while moving at a speed of 4m/s. The coefficient of friction between him and the ground is .7. He slides so his speed is 0 just as he reaches the base. How much work is done by friction?
The work done by friction is -560 J
Explanation:
According to the work-energy theorem, the work done by the force of friction on the runner is equal to his change in kinetic energy. Therefore:
[tex]W=\frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
where
W is the work done by friction
m is the mass of the runner
v is his final velocity
u is the initial velocity
Here we have:
m = 70 kg is the mass
u = 4 m/s is the initial velocity
v = 0 is the final velocity
Solving for W,
[tex]W=0-\frac{1}{2}(70)(4)^2=-560 J[/tex]
And the sign is negative because the direction of the force of friction is opposite to the motion of the runner.
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d) A wire carrying a current of 10A and 2m in length is placed in a field of flux density
0. 15T. Calculate the force on the wire if it is placed:
i) At 300
to the field
ii) Along the field (4 mks)
1) The force on the wire is 1.5 N
2) The force on the wire is zero
Explanation:
1)
The force experienced by a current-carrying wire in a magnetic field is given by
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the magnetic flux density
[tex]\theta[/tex] is the angle between the direction of the wire and of the field
In this part of the problem we have
I = 10 A
L = 2 m
B = 0.15 T
[tex]\theta=30^{\circ}[/tex]
Substituting, we find
[tex]F=(10)(2)(0.15)(sin 30^{\circ})=1.5 N[/tex]
2)
As before, the force experienced by the wire is
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the magnetic flux density
[tex]\theta[/tex] is the angle between the direction of the wire and of the field
In this case, however, the angle between the wire and the field is
[tex]\theta=0^{\circ}[/tex]
And therefore
[tex]sin 0^{\circ} = 0[/tex]
which means that the wire does not experience any force. In fact, the force experienced by the wire is zero when the wire is parallel to the field (such as in this case) and maximum when the wire is perpendicular to the field.
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What is used to measure heat?
change in temperature
constant temperature
constant specific heat
change in specific heat
Answer:
change in temperature
Answer:
Change in temperature
Explanation:
did this on edge yesterday and that was the answer
2057 Q.No. 9 a A typical car weighs about 1200 N. If the
coefficient of rolling friction is ur = 0.015. What horizontal
force is needed to make the car move with constant speed of
72 km/h on a level road? Also calculate the power developed
by the engine to maintain this speed.
Ans. 18 N, 360 W
Answer:
18N & 360W
Explanation:
Here,
Velocity of car (v) = 72 ∗ 1000 / 60∗60 = 20m/s
weight of car = 1200N
We have,
μr = Fs / R
Fs = μr ∗ R = 0.015 ∗ 1200 = 18N
Power developed by the engine = 18 ∗ 20 =360W
Hope this helps!!! Bluetooth is a technology that allows wireless devices to communicate data and information to each other. For example, a wireless pair of headphones can play music from a smart phone without a physical connection. However, the technology must be low energy enough not to cause damage to the people using the device. Additionally, the wavelengths used in bluetooth technologies should not be visible. The waves associated with bluetooth technology are most similar to which wave type below?
A) X-rays
B) red light
C) radio waves
D) UV radiation
Answer: Option C. Radio waves
Explanation:
Bluetooth technology primarily uses radio waves, a type of low-energy and invisible electromagnetic radiation, to enable wireless communication between devices.
Explanation:Bluetooth is a technology that enables wireless devices to communicate with each other by transferring data and information. This is accomplished using low-energy radio waves. Among the wave types listed in your options, Bluetooth devices primarily use radio waves to establish communication. Radio waves are a form of electromagnetic radiation, similar to X-rays, red light and UV radiation, but are distinguished by their longer wavelength and lower frequency, which gives them their low energy characteristics. Because of their low energy, they are non-ionizing and safe to use. Also, radio waves are invisible to the human eye which meets the visibility requirement for Bluetooth technology.
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Find the change in volume for a metallic dental filling due to the difference between body temperature (37.0°C) and the temperature of the ice cream you ate (-6.2°C). The initial volume of the filling is 21.0 mm3, and its expansion coefficient is α = 42.0 × 10−6 K−1
Answer:
The change in volume for a metallic dental filling due to the temperature difference is 0.1143 mm.
Explanation:
Given:
Temperature of the body is, [tex]T_1=37\ \°C[/tex]
Temperature of the ice-cream is, [tex]T_2=-6.2\ \°C[/tex]
Initial volume of the filling is, [tex]V=21.0\ mm^3[/tex]
Coefficient of thermal expansion is, [tex]\alpha =42.0\times 10^{-6}\ K^{-1}[/tex]
We know that the coefficient of volume expansion is related to thermal expansion as:
[tex]\gamma=3\alpha=3\times 42.0\times 10^{-6}=126\times 10^{-6}\ K^{-1}[/tex]
Now, change in volume for a metallic dental filling is given as:
[tex]\Delta V=V\gamma(T_1-T_2)\\\Delta V=21\times 126\times 10^{-6}(37-(-6.2))\\\Delta V=2646\times(37+6.2)\times 10^{-6}\\\Delta V=2646\times 43.2\times 10^{-6}\\\Delta V=0.1143\ mm^3[/tex]
Therefore, the change in volume for a metallic dental filling due to the temperature difference is 0.1143 mm.
The changes in volume for a metallic dental filling due to the difference between body temperature will be 0.1143 mm.
What is thermal expansion?The expansion of any material due to the thermal application is known as thermal expansion.
The given data in the problem is;
Δv is the change in the volume =?
T₂ is the body temperature = 37.0°C
T₁ is the temperature of ice cream you ate (-6.2°C)
α is the expansion coefficient= 42.0 x 10⁻⁶ K⁻¹ mm
The coefficient of the volume expansion is given by;
[tex]\gamma = 3 \alpha \\\\ \gamma = 3 \times 42.0 \times 10^{-6} \\\\ \gamma = 126 \times 10^{-6}[/tex]
The change in the volume due to the thermal expansion is given by;
[tex]\triangle v = V \gamma (T_2-T_1) \\\\ \triangle v = 21 \times 126 \times 10^{-6} (37-(-6.2))\\\\ \triangle v = 2646 \times (37+6.2)\times 10^{-6} \\\\ \triangle v = 0.0143\ mm^3[/tex]
Hence the changes in volume for a metallic dental filling will be -18,62784 mm³.
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Which statement is false?
O Preparations for future situations are helpful to avoid pressured situations.
Once you reach adulthood, you will not experience peer pressure.
Peer pressure is often thought of in negative terms even though it can be positive.
Answer:
Once you reach adulthood, you will not experience peer pressure.
Explanation:
We tend to believe that self-control comes from within, but many of our attitudes depend as much on friends and family as on ourselves. That's because at any stage of our life (even the adult stage) our friends and our family have the power to influence us, sometimes that influence is good and sometimes bad, it's up to us to reason about them.
The people around us have the power to make us fat, consume more alcohol, worry less about the environment and expose ourselves to the sun without proper protection, among many other things.
It is not simply about peer pressure, where you deliberately act in a certain way to suit the group. It is, in fact, largely an unconscious attitude. Without your awareness, your brain is constantly picking up cues from people around you to dictate your behavior. And the consequences can be serious.
Answer:
its B :)
Explanation:
In the following reaction, what element is made?
Answer:
The correct answer is option A).
Explanation:
The given reaction is a nuclear reaction.
We know that in a nuclear reaction , the indices on both the sides are conserved , i.e the total number of nucleons (A) and the total number of protons (Z) should be the same on the L.H.S and the R.H.S-
Total number of nucleons on L.H.S = 241+4 = 245.
Total number of nucleons on R.H.S = A+1
∴ A+1 = 241+4 = 245
∴ A=244
Total number of protons on L.H.S = 95+2 = 97.
Total number of protons on R.H.S = Z+0
∴ Z+0 = 97.
Z = 97.
Thus the element having A=244 and Z=97 should be the product of this nuclear reaction.
∴ ₉₇²⁴⁴Bk (option A) should be the required product of this reaction.
A person absentmindedly walks off the edge of a tall cliff. They will fall 50 m into either
deadly rocks or a safe lake below the cliff. The lake is 12 meters away from the edge of
the cliff
If the person walks off the cliff at a constant velocity of 3.8 m/s.
will they survive? (yes or no) How far did they go?
The man can survive, and he lands 12.1 m from the base of the cliff (into the lake)
Explanation:
The motion of the person is equivalent to the motion of a projectile, which consists of two separate motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
We start by analyzing the vertical motion, to find the time it take for the person to reach the ground level. We can use the following suvat equation:
[tex]s=ut+\frac{1}{2}gt^2[/tex]
where
s = 50 m is the vertical distance covered (the height of the cliff)
u = 0 is the initial vertical velocity
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
t is the time of flight
Solving for t,
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(50)}{9.8}}=3.19 s[/tex]
The person moved horizontally at a constant speed of
[tex]v_x = 3.8 m/s[/tex]
So, the horizontal distance covered by the man during his flight will be
[tex]d_x = v_x t = (3.8)(3.19)=12.1 m[/tex]
So, the man will land on the lake (which starts from 12 m), so he can survive.
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Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N what is the coefficient of friction between a walk in the ground
The coefficient of friction is 0.363
Explanation:
There are two forces acting on the scooter in the horizontal direction:
- The applied force, F = 1850 N, forward
- The frictional force, [tex]F_f[/tex], backward
Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:
[tex]F-F_f = 0\\F_f = F = 1850 N[/tex]
The frictional force can be written as
[tex]F_f = \mu R[/tex] (1)
where
[tex]\mu[/tex] is the coefficient of friction
R is the normal reaction of the ground on the scooter
For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:
[tex]R = W = mg[/tex]
where
m = 520 kg is the mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Substituting into (1),
[tex]F_f = \mu mg = 1850 N[/tex]
and solving for [tex]\mu[/tex],
[tex]\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363[/tex]
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An elevator has a weight of 14,700 N and has an acceleration of –0.30 m/s2. The free-body diagram shows the forces acting on the elevator.
A free body diagram with 2 force vectors. One vector is pointing up, labeled F Subscript t Baseline. The second vector is shorter pointing down, labeled F Subscript g Baseline.
To the nearest whole number, what is the force of tension, Ft, acting on the elevator?
14250. I just took it
Answer:
14,250 N
Explanation:
Weight = 14,700 N
Acceleration = -0.30m/s²
[tex]Acceleration = -0.30m/s2[tex]Weight=Fg\\\\Fg=mg\\\\Fg=14,700N\\m=?\\g=9.8m/s^{2} \\\\14,700N=m(9.8m/s^{2} ) \\\\14,700N/9.8ms^{2} =1500kg(mass)\\\\m=1500kg\\a=-0.30m/s^{2}\\\\f=ma\\f=(1500kg)(-0.30m/s^{2} )\\=-450N (net force)\\\\-450N=-14,700N+(Ft)\\14,250N=Ft[/tex]
In which situation is the object experiencing unbalanced forces?
Question 1 options:
A. A box resting on a horizontal floor
B. A car slowing as it reaches a stop light
C. A car with its cruise control set to 50 mph
D. A rocket sitting on the launch pad
B. A car slowing as it reaches a stop light
Explanation:
According to Newton's second law, the net force exerted on an object is equal to the product between its mass and its acceleration:
[tex]F=ma[/tex]
where
F is the net force
m is the mass of the object
a is its acceleration
This means that when an object is experiencing unbalanced forces ([tex]F\neq 0[/tex]), it must have a non-zero acceleration. Therefore, let's analyze the different options:
A. A box resting on a horizontal floor --> FALSE. Here the acceleration is zero, so no unbalanced forces.
B. A car slowing as it reaches a stop light --> TRUE. Since the car is slowing down, its velocity is changing, so the acceleration is non-zero and there are unbalanced forces.
C. A car with its cruise control set to 50 mph --> FALSE. Here the velocity is constant, so no acceleration and no unbalanced forces.
D. A rocket sitting on the launch pad --> FALSE. Here the rocket is stationary, so no acceleration, and no unbalanced forces.
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An object experiences unbalanced forces when the resultant force on it is non-zero. A car slowing as it reaches a stop light experiences unbalanced forces due to the brakes exerting a force, causing it to decelerate. Hence, the correct answer is B. A car slowing as it reaches a stop light.
In the question, we are asked to determine in which situation an object is experiencing unbalanced forces. An object experiences unbalanced forces when the resultant force acting on it is non-zero, leading to a change in its motion. If we analyze the options given:
A box resting on a horizontal floor is not experiencing unbalanced forces, because it is at rest and there are no net forces acting to change its state of motion (assuming no frictional losses).A car slowing as it reaches a stop light is experiencing unbalanced forces because the brakes are exerting a force opposite to the direction of motion, causing the car to decelerate.A car with its cruise control set to 50 mph is travelling at a constant velocity, indicating that the forces are balanced.A rocket sitting on the launch pad is not experiencing unbalanced forces if it is stationary and not in the process of takeoff.Therefore, the correct answer is B. A car slowing as it reaches a stop light, because this is when it is experiencing a net force that is causing a change in its motion.