Answer:
a)There are [tex]7,2236*10^{26}[/tex] possible different passwords.
b)There are [tex]3,0784*10^{19}[/tex] possible different passwords.
Step-by-step explanation:
a) Each character of the string could be any of the 10 numerals or 21 letters, that means, each character may be any of these 31 different options.
If the password had only one character, there would be 31 different possible passwords, if it were a two characters string, there would be [tex]31^{2}=961[/tex], because in the first place we can place any of the 31 characters, and then in the second place, we can do the same, we are asked of combinations without taking into account order of the characters.
A generalized form, to know how many different passwords we can make of n characters is [tex]31^{n}[/tex].
If we have more than one possible lengths, we add those cases, in our case, we have 14 thru 18 characters, all that could be filled by any of the 31 possible characters.
[tex]\[\sum_{i=14}^{18}31^{i} =31^{14}+31^{15} +31^{16}+31^{17}+31^{18}=7,2236*10^{26} \\\][/tex].
b) If each password must contain at least 15 numerals, that means the minimum length of a password is 15 now.
We proceed the same as the a) point, but taking into account that for 15 characters, there is not 31 possible characters anymore, but 10.
Doing each individual length:
[tex]Passwords_{length=15} =10^{15}[/tex]
That is because we would multiply 10 possible options by the next possible 10 options and so on 15 times.
[tex]Passwords_{length=16} =10^{15}*31[/tex]
Now, for the sixteenth character, we multiply by the now 31 possible options.
[tex]Passwords_{length=17} =10^{15}*31^{2} \\Passwords_{length=18} =10^{15}*31^{3}[/tex]
For lengths 17 and 18, we do similar stuff, multiplying by 31 for each new character.
To know all the possible combinations, we add the combinations for each length:
[tex]\sum_{i=15}^{18}Passwords_{lenght=i}=3,0784*10^{19}[/tex]
We can see there is approximately 7 orders of magnitude less with the restriction than there is without it.
Prove that the square of any even number is always a multiple of 4.
Answer and Explanation:
To prove : The square of any even number is always a multiple of 4.
Proof :
The even numbers is defined as number end with 0,2,4,6,8 or the even number are multiple of 2.
Let the general even number be '2n'.
Squaring the number [tex](2n)^2=2^2\times n^2[/tex]
[tex](2n)^2=4n^2[/tex]
As 4 is the multiple of n².
So, If we square any even number it is always a multiple of 4.
For example,
[tex]2^2=4=4\times 1\\4^2=16=4\times 4\\6^2=36=4\times 9\\8^2=64=4\times 16[/tex]
Hence proved.
Solve each of the following equations for x. (a) 5x-7=28 (b) 12-5x= x+30 (c) 5(x+2)= 1-3x
Зx-y=-5 X+2y=3
Answer:
(a) 7
(b) -3
(c) [tex]-\frac{9}{8}[/tex]
(d) -1
Step-by-step explanation:
(a) 5x - 7 = 28
5x = 28 + 7
5x = 35
⇒ x = 7
(b) 12 - 5x = x + 30
-5x = x + 30 - 12
-5x = x + 18
-5x - x = 18
-6x = 18
⇒ x = -3
(c) 5(x+2) = 1 - 3x
5x + 10 = 1 - 3x
5x = 1 - 3x - 10
5x + 3x = -9
8x = -9
⇒ x = [tex]-\frac{9}{8}[/tex],
(d) Given system of equations,
Зx-y = -5 ------(1),
x + 2y = 3 ----(2),
Equation (2) + 2 equation (1),
x + 6x = 3 - 10⇒ 7x = -7 ⇒ x = -1
Find the area of the triangle
Answer:
A ≈ 14.079 square units
Step-by-step explanation:
Area of a triangle is one half the base times the height.
A = ½ bh
A = ½ (10) (2x)
A = 10x
We need to find the value of x.
Starting with the triangle on the left, use Pythagorean theorem to find the length of the base.
(3x)² = (2x)² + a²
9x² = 4x² + a²
a² = 5x²
a = x√5
Repeat for the triangle on the right:
(x + 6)² = (2x)² + b²
x² + 12x + 36 = 4x² + b²
b² = -3x² + 12x + 36
The two bases add up to 10:
a + b = 10
Subtract a from both sides, then square both sides:
b = 10 − a
b² = 100 − 20a + a²
Substitute and simplify:
-3x² + 12x + 36 = 100 − 20(x√5) + 5x²
0 = 64 − (12 + 20√5) x + 8x²
0 = 2x² − (3 + 5√5) x + 16
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ (3 + 5√5) ± √((-(3 + 5√5))² − 4(2)(16)) ] / 2(2)
x = [ (3 + 5√5) ± √(9 + 30√5 + 125 − 128) ] / 4
x = [ (3 + 5√5) ± √(6 + 30√5) ] / 4
x ≈ 1.4079, 5.6823
If we substitute 5.6823 into our a and b equations, we find that a = 12.706 and b = 7.322, which add up to 20.028, not 10.
So x ≈ 1.4079.
Therefore the area is:
A ≈ 14.079
How many possible ways are there to fill in answers to a
quizwith five multiple choice questions when the choices are a, b,
andc?
Answer: There are 15 possible ways to fill in answers .
Step-by-step explanation:
Given : The number of multiple choice questions = 5
The total number of choices for each question {a, b,
and c} = 3
Now by using the fundamental principle of counting , the number of possible ways to fill in answer is given by :-
[tex]5\times3=15[/tex]
Therefore, there are 15 possible ways to fill in answers .
One-half liter of solution for intravenous infusion contains 2 g of drug. How many milliliters of the solution would contain 0.5 mg of drug?
Final answer:
To find out how many milliliters of the solution would contain 0.5 mg of the drug, we can set up a proportion using the given information. The solution would contain 0.125 mL of the drug.
Explanation:
To find out how many milliliters of the solution would contain 0.5 mg of the drug, we need to set up a proportion using the given information. We have 2 g of the drug in one-half liter of solution, so the concentration is 4 g/L. We can convert milligrams to grams by dividing by 1000. By setting up the proportion, we have:
4 g/L = 0.5 mg/x mL
Cross-multiplying, we get:
4 g * x mL = 0.5 mg * 1 L
Converting mg to g and mL to L:
4 * x = 0.5 / 1000
x = (0.5 / 1000) / 4
x = 0.000125 L
Since there are 1000 mL in 1 L, we can convert the answer:
x = 0.000125 L * 1000 mL/L
x = 0.125 mL
The United States has 435 members of the House of Representatives in Congress. If there are 325.7 million people in the country, what the ratio of members to the people? (Write your answer in scientific notation with 2 digits after the decimal.) рrt sex V8
Answer:
[tex]1.36\times 10^{-6}:1[/tex]
Step-by-step explanation:
We have been given that the United States has 435 members of the House of Representatives in Congress. There are 325.7 million people in the country.
To find the ratio of members to the people, we will find compare both numbers.
1 million equals 1,000,000.
[tex]\text{325.7 million}=325.7\times 1,000,000[/tex]
[tex]\text{325.7 million}=3257,000,000[/tex]
Ratio of members to the people:
435: 3257,000,000
[tex]0.0000013355848941:1[/tex]
[tex]1.3355848941\times 10^{-6}:1[/tex]
[tex]1.36\times 10^{-6}:1[/tex]
Therefore, our required ratio would be [tex]1.36\times 10^{-6}[/tex] members per person.
(a) How many prime numbers are (b) How many prime numbers are also abundant numbers?
Answer:
a) There are infinite prime numbers, b) All prime numbers are also abundant numbers
Step-by-step explanation:
To prove a) let's first prove that if n divides both integers A and B then also divides the difference A-B
If n divides A and B, there are integers j, k such that
A = nj and B= nk,
So
A-B= nj - nk = n(j-k)
But j-k is also an integer, which means that n divides also A-B
Now, to prove that there are infinite prime numbers , we will proceed with Reductio ad absurdum.
We will suppose that there are only a finite number of primes and then arrive to a contradiction.
Suppose there are only n prime numbers,
{p1,p2,... pn}
then take P=p1.p2...pn the product of all of them
and consider P+1
If P+1 is prime the proof is complete for P+1 is not in the list.
if P+1 is not prime then by the Fundamental Theorem of Arithmetic there is a prime in the list that must divide P+1, let's say pk
Then pk also divides P+1-P=1 which is a contradiction because no prime divides 1.
b) To prove this, recall that an abundant number is a number for which the sum of its proper divisors is greater than the number itself.
Given that a prime number P is only divided by P and 1, the sum of its divisors is P+1 which is greater than P. So P is abundant
Determine if each statement would relate to a lean manufacturing system or a traditional manufacturing system.
a. Employees are cross-trained for several machines in one division.
b. Management emphasizes that defects should not occur.
c. Products are manufactured based upon estimated sales.
Answer:
answered
Step-by-step explanation:
A)lean
B)lean
C)traditional
In Lean manufacturing system works are done reduce inventory levels below what would be found in a traditional manufacturing system. The company does so by reducing batches into smaller batch sizes rather than large batch sizes. Goods are produced through product cells rather than departments.
Within-batch wait time is time that product waits in a product cell for the other products in a batch, it is calculated by multiplying the value-added time per unit by number of other products ,one less the total batch size
1. In a college, each student ID card is linked with a unique 5-digit pin from the set {0,1,2,3,4,5,6,7,8,9}. A) Find the number of ID cards possible. B) Find the number of ID cards possible if the 5-digit number is an odd number? C) Recalculate A&B if the digits are not allowed to be repeated
The total number of ID cards possible without repeating digits is 10 x 9 x 8 x 7 x 6 = 30,240.
In a college, the number of ID cards possible can be found by calculating the number of possible options for each digit in the 5-digit pin.
Since each digit can be any number from the set {0,1,2,3,4,5,6,7,8,9}, there are 10 options for each digit. Therefore, the total number of ID cards possible is 10 x 10 x 10 x 10 x 10 = 100,000.
If the 5-digit number is to be an odd number, then the last digit can only be one of the odd numbers {1, 3, 5, 7, 9}. So there are 5 options for the last digit, and for each of the other four digits, there are still 10 options. Therefore, the total number of ID cards possible with an odd 5-digit number is 10 x 10 x 10 x 10 x 5 = 50,000.If the digits are not allowed to be repeated, then for the first digit, there are still 10 options. But for each of the other four digits, there are now 9 options since one digit has been used already. Therefore, the total number of ID cards possible without repeating digits is 10 x 9 x 8 x 7 x 6 = 30,240.When an object falls through air, there is a drag force that depends on the product of the cross sectional area of the object and the square of its velocity, that is, Fair = CAv2, where C is a constant. Determine the dimensions of C. (Use the following as necessary: M for mass, T for time, and L for length.)
Answer:
[tex]\textrm{Dimension of C }=\ [ML^{-3}T^{0}][/tex]
Step-by-step explanation:
As given in question drag force depends upon the product of the cross sectional area of the object and the square of its velocity
and drag force can be given by
[tex]F=CAv^2[/tex] (1)
It is given that
Dimension of mass = [M]
Dimension of length = [L]
Dimension of time = [T]
So, by using above dimension we can write
the dimension of force,
[tex]F=[MLT^{-2}][/tex]
dimension of cross-section area,
[tex]A=[L^2][/tex]
and dimension of velocity
[tex]v=[LT^{-1}][/tex]
now, by putting these values in equation (1), we will get
[tex]F=CAv^2[/tex]
[tex]=>[MLT^{-2}]=C[L^2][LT^{-1}]^2[/tex]
[tex]=>C=[ML^{-3}T^0][/tex]
Hence, the dimension of constant C will be,
[tex]C=[ML^{-3}T^0][/tex]
The dimensions of C from the expression above is ML^-3
Units and DimensionGiven the function that relates drag force with the cross-sectional area of the object and the square of its velocity expressed as:
[tex]F_{air} = CAv^2[/tex]
Make C the subject of the formula to have:
[tex]C =\frac{F}{Av^2}[/tex]
Given the following dimensions
[tex]M =MLT^{-2}[/tex]
A = L²
v = [tex]LT^{-1}[/tex]
Substitute into the formula. the dimension of C will be given as:
[tex]C=\frac{MLT^{-2}}{L^2L^2T^{ -2}}\\C= ML^{-3}[/tex]
Henc the dimensions of C from the expression above is ML^-3
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A 12-m3 oxygen tank is at 17°C and 850 kPa absolute. The valve is opened, and some oxygen is released until the pressure in the tank drops to 650 kPa. Calculate the mass of oxygen that has been released from the tank if the temperature in the tank does not change during the process.
Answer:
Released oxygen mass: 15.92 kg
Step-by-step explanation:
ideal gas law : P*V=nRT
P:pressure
V:volume
T:temperature
n:number of moles of gas
n [mol] = m [g] /M [u]
m : masa
M: masa molar = 15,999 u (oxygen)
R: ideal gas constant = 8.314472 cm^3 *MPa/K*mol =
grados K = °C + 273.15
P1*V*M/R*T = m1
P2*V*M/R*T = m2
masa released : m1-m2 = (P1-P2) * V*M/R*T
m2-m1 = 200 * 10^-3 MPa * 12 * 10^6 cm^3 * 15.999 u / 8.314472 (cm^3 * MPa/K *mol) * 290. 15 K
m2-m1= 38 397.6 * 10^3 u*mol / 2412.44 = 15916.5 g = 15.9165 kg
The question involves the use of the Ideal Gas Law to calculate the mass of oxygen released from a tank when the pressure drops. The initial and final number of moles of oxygen is calculated using the Ideal Gas Law, then the difference represents the number of moles of oxygen released. Multiplying this by the molar mass of oxygen gives the mass of oxygen released, which is about 255.808 kg.
Explanation:The Ideal Gas Law states that PV=nRT, where P is pressure in Pascals, V is volume in m3, n is the number of moles, R is the Universal Gas Constant (8.31 J/(mol.K)), and T is temperature in Kelvin. From the question, we know the initial and final pressures (P1=850 kPa, P2=650 kPa ), Volume (V=12 m3), and temperature (T=17°C = 290 K).
First, we need to calculate the initial (n1) and final (n2) number of moles using the equation n = PV/RT. Substituting the given values to the equation, we get n1= (850000*12) /(8.31*290)= 34974.48 mol and n2= (650000*12) /(8.31*290)= 26980.38 mol.
So, the mass of oxygen that has been released is the difference between the initial and final moles. It equals to 7994.1 mol. Since the molar mass of oxygen is approximately 32 g/mol, the mass of oxygen that has been released is 7994.1 mol * 32 g/mol = 255808 g or 255.808 kg. So, the mass of oxygen released from the tank is approximately 255.808 kg.
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Karen Price has determined that her net worth is $58,000. She has also determined that the face value of her mortgage is $89,000. She has determined that the face value of the rest of her debt is $18,000. What is Karen's debt-to-equity ratio? Multiple Cholce 184 153 3.22 4.94 0.31
Answer:
A. 1.84
Step-by-step explanation:
We have been given that Karen Price's net worth is $58,000. The face value of her mortgage is $89,000. The face value of the rest of her debt is $18,000.
[tex]\text{Debt to equity ratio}=\frac{\text{Total liabilities}}{\text{Total shareholder's equity}}[/tex]
We know that total liabilities include short term debt and long-term debt.
[tex]\text{Debt to equity ratio}=\frac{\$89,000+\$18,000}{\$58,000}[/tex]
[tex]\text{Debt to equity ratio}=\frac{\$107,000}{\$58,000}[/tex]
[tex]\text{Debt to equity ratio}=1.8448[/tex]
[tex]\text{Debt to equity ratio}\approx 1.84[/tex]
Therefore, Karen's debt-to-equity ratio 1.84 and option A is the correct choice.
Show that if A CB, then A = B ( B A ). Show that if A C B, then A U (B \ A) = B. Show, by example, that for sets A, B, and C, AN B = An C does not imply B = C.
Answer: If A ⊂ B, then A = B \ ( B \ A)
ok, when you do B \ A, you are subtracting all the elements in A∩B from B. So the only elements remaining are those who aren't in A.
If we subtract this of B again, we are subtracting of B all the elements that aren't in A, so the only elements remaining are those who belongs in A.
If A ⊂ B then A U (B \ A) = B.
Again, when you do B \ A you are extracting all the elements that belongs to the A∩B from B. So you are extracting al the elements from A. and when you add all the elements of A again, then you recuperate B.
if AnC = AnC does not imply that B = C.
if A = {1,2}, B = {1,2,3,4,5} and C = {1,2,3}
then AnC = {1,2} and AnB = {1,2} but B and C are different.
Fill in the blank The retail cost of a TV is 40% more than its wholesale cost. Therefore, the retail cost is _times the wholesale cost The retail cost is 1.4 times the wholesale cost. (Type an integer or a decimal
Answer:
Step-by-step explanation:
let whole sale cost=100
retail cost=100+40% of 100=100+40=140
to find the ratio
(retail cost)/(whole cost)=140/100=14/10=1.4
so retail cost=1.4*whole cost
or retail cost is 1.4 times the whole cost.
The retail cost of a TV, which is 40% more than its wholesale cost, is 1.4 times the wholesale cost. For instance, if the wholesale cost is $500, the retail cost would be $700.
The retail cost of a TV is 40% more than its wholesale cost. To find out how many times more the retail cost is compared to the wholesale cost, we need to understand percentage increase calculations.
Let the wholesale cost of the TV be represented by 1 (or 100%). An increase of 40% on this cost means the TV now costs:
1 + 0.40 = 1.40.
Therefore, the retail cost of the TV is 1.4 times the wholesale cost.
For example, if the wholesale cost of a TV is $500, then the retail cost would be:
$500 × 1.4 = $700.
Convert 500 cubic feet to liters
Answer:
500 cubic feet is equal to 14158.4 liters.
Step-by-step explanation:
Since, we know that,
1 square feet = 28.3168 liters,
Thus, the number of liters in 500 cubic feet = 500 × number of liters in 1 square feet
[tex]=500\times 28.3168[/tex]
[tex]=14158.4[/tex]
Therefore, 500 cubic feet is equal to 14158.4 liters.
500 cubic feet is 14158.4 liters.
To convert 500 cubic feet to liters, follow these steps:
Using the conversion factor:
1 ft³ = 28.3168 L
So, to convert 500 cubic feet to liters:
500 ft³ × 28.3168 L/ft³ = 14158.4 L
If A, B, and C are mutually exclusive events with P(A) = 0.21, P(B) = 0.32, and P(C) = 0.43, determine the following probabilities. Round your answers to two decimal places.
(a) P(A U B U C)
(b) P(A n B n C)
(c) P(A n B)
(d) P[(A U B) n C]
By their mutual exclusivity,
[tex]P(A\cup B\cup C)=P(A)+P(B)+P(C)=0.96[/tex]
[tex]P(A\cap B\cap C)=0[/tex]
[tex]P(A\cap B)=0[/tex]
For the last probability, first distribute the intersection:
[tex](A\cup B)\cap C=(A\cap C)\cup(B\cap C)[/tex]
Recall that for two event [tex]X,Y[/tex],
[tex]P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)[/tex]
so that
[tex]P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)-P((A\cap C)\cap(B\cap C))[/tex]
[tex]P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)-P(A\cap B\cap C)=0[/tex]
Solve the following logarithmic equation: In(x +31)-In(4-3x)-5In2 0 x = 2 1 points x= 0 x-0.5 ○ x=0.25 None of the above to save all
Answer:
The solution is [tex]x = 1[/tex]
Step-by-step explanation:
We have the following logarithmic properties:
[tex]ln a + ln b = ln ab[/tex]
[tex]ln a - ln b = ln \frac{a}{b}[/tex]
[tex]n ln a = ln a^{n}[/tex]
We have the following logarithmic equation:
[tex]ln(x + 31) - ln (4-3x) - 5 ln 2 = 0[/tex]
Lets simplify, and try to find properties.
[tex]ln(x + 31) - (ln (4-3x) + 5 ln 2) = 0[/tex]
[tex]ln(x + 31) - (ln (4-3x) + ln 2^{5}) = 0[/tex]
[tex]ln(x + 31) - (ln (4-3x) + ln 32) = 0[/tex]
[tex]ln(x + 31) - ln 32*(4-3x) = 0[/tex]
[tex]ln(x+31) - ln (128 - 96x) = 0[/tex]
[tex]ln \frac{x + 31}{128 - 96x} = 0[/tex]
To eliminate the ln, we apply the exponential to both sides, since e and ln are inverse operations.
[tex]e^{ln \frac{x + 31}{128 - 96x}} = e^{0}[/tex]
[tex]\frac{x + 31}{128 - 96x} = 1[/tex]
[tex]x + 31 = 128 - 96x[/tex]
[tex]97x = 97[/tex]
[tex]x = \frac{97}{97}[/tex]
[tex]x = 1[/tex]
The solution is [tex]x = 1[/tex]
What is the rate of heat transfer required to melt 1-ton of ice at 32 F in 24 hours?
Answer:
3865.74 J/s
Step-by-step explanation:
mass of ice, m = 1 ton = 1000 kg
time , t = 24 hours
latent heat of fusion of ice, L = 334000 J/kg
Heat required to melt, H = m x L
where, m is the mass of ice and L be the latent heat of fusion
So, H = 1000 x 334000 = 334 xx 10^6 J
Rate of heat transfer = heat / time = [tex]\frac{334\times 10^{6}}{86400}[/tex]
Rate of heat transfer = 3865.74 J/s
thus, the rate of heat transfer is 3865.74 J/s.
Show in fact that 1=9m + 20n for some integers m and n
Answer:
[tex]1=9\cdot 9+20\cdpt (-4)=81-80[/tex]
Step-by-step explanation:
The greatest common divisor between 9 and 20 is 1, so we know the equation [tex] 1=9m+20n[/tex] has a solution. A solution can be found either by inspection, or by applying Euclidean algorithm.
By inspection we just list some multiples of 9:
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99
and also list some mutiples of 20:
20, 40, 60, 80, 100, 120
And so we see that we can find a multiple of 9 (81) which is 1 away from a multiple of 20 (80). Which is the solution given at the start.
For the Euclidean algorithm, we should divide the greatest of the two numbers, by the smallest one, and keep track of the remainder:
20 = 9 * 2 + 2
Then we divide 9 by the remainder we got, which is 2:
9 = 2 * 4 + 1
we would continue doing this until getting a remainder of 1 (which we just did). Finally we "solve" for 1, from the last equation:
9 - 2*4 = 1
And then we solve for 2 from the first equation, and plug that in into the previous equation:
20 - 9*2 =2
9 - ( 20 - 9*2)*4 = 1
which does give us the same solution: [tex] 9\cdot 9 +20\cdot (-4)=1[/tex]
How to do exponents a quicker way!! Please help my brother!
Problem 8 - Simple and Compound Interest
At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t
Problem 4 - Simple and Compound Interest
How much would you invest today to have $9500 in 8 years if the effective annual rate of interest is 4%?
Problem 8 - Simple and Compound Interest
At an effective annual rate of interest of 5.3%, the present value of $7425.70 due in t years is $3250. Determine t ?
Answer:
P8) [tex]t=7.02 years[/tex]
P4) Today you have to invest $6941.55
P8) Is the same P8 above
Step-by-step explanation:
P8) First of all, we can list the knowns [tex]VP=7425.70[/tex], [tex]I=3250[/tex] and [tex]i=5.3[/tex]%, so we use [tex]VF=VP+I=7425.70+3250=10675.70[/tex] then we use [tex]t=\frac{ln(VF/VP)}{ln(1+i)}=\frac{ln(10675.70/7425.70)}{ln(1+0.053)} =\frac{0.363}{0.051}=7.02 years[/tex]
P4) First of all, we can list the knowns [tex]VF=9500[/tex], [tex]t=8[/tex] and [tex]i=4[/tex]%, so we use [tex]VP=\frac{VF}{(1+i)^{t} } =\frac{9500}{(1+0.04)^{8} } =6941.55[/tex]
P8) Is the same P8 above
An die (six faces) has the number 1 painted on three of its faces, the number 2 painted on two of its faces, and the number 3 painted on one face. Assume that each face is equally likely to come up. Find a sample space for this experimen
Answer: {1 ,2 ,3 }
Step-by-step explanation:
We know that a sample space is a set of possible occurring oin an experiment.
Given : An die (six faces) has the number 1 painted on three of its faces, the number 2 painted on two of its faces, and the number 3 painted on one face.
We assume that each face is equally likely to come up.
When we toss a dice , then the possible occurring = 1 , 2, 3
Then, the sample space for this experiment will be {1 ,2 ,3 }
Final answer:
Explaining the sample space for an experiment with a die displaying numbers in different frequencies.
Explanation:
An die (six faces) has the number 1 painted on three of its faces, the number 2 painted on two of its faces, and the number 3 painted on one face. The sample space for this experiment would be: {1, 1, 1, 2, 2, 3}.
This means that when you roll the die, the possible outcomes are: 1, 1, 1, 2, 2, 3.
The following data describes the magnitude measurements randomly selected from 6 earthquakes recorded in one year from a location in southern Califormia: 6.6 2.2 18.5 7.0 13.7 5.9 The magnitude is measured by MAG on the Richter scale. What type of the data is the magnitude? a) Continuous numeric b) Discrete numeric c) Continuous categorical d) Nominal categorical
Answer: The magnitude is: a) continuous numeric.
Step-by-step explanation:
The magnitude is a numeric variable because it represents quantities. These are variables that you can measure or count. A numeric variable can be classified into discrete or continuous. In the present problem, the magnitude is a continuous variable. It can take any number within a scale, and you can find infinite values between two values on the scale. For example, you could measure earthquakes of magnitude 2.3, 2.4, 2.5, 2.6… and so on, following a continuous scale.
On the other hand, if the variable is numeric and discrete, it can only take certain finite values. For example, when you count the number of trees per acre. The number of trees will be always an integer. You can find 1, 2, or 3 trees, but you’ll never count 2.5 trees.
Categorical variables don’t represent quantities. They represent attributes. For example, apple colors: green and red.
Northwest Molded molds plastic handles with a variable cost of $1.00 per handle. The fixed cost to run the molding machine is $2560 per week. If the company sells the handles for $3.00 each, how many handles must be molded weekly to break even? What is the profit if 1500 handles are produced and sold?
Answer:
To break even it must be molded 1280 handles weekly.
The profit if 1500 handles are produced and sold is $440
Step-by-step explanation:
To break even, the amount of total cost must be the same as the amount of revenues.
Total Cost is Fixed cost plus unitary variable cost multiplied by the produce quantity.
Total cost= FC + vc*Q
Where
FC=Fixed cost
vc=unitary variable cos
Q=produce quantity
Revenue= Price * Q
Break even FC + vc*Q=Price * Q
Isolating Q
FC=(Price * Q)-(vc*Q)
FC=(Price-vc) * Q
Q= FC/(Price-vc)
Q= $2560/($3.00-$1.00)=1280
If we sold 1500 handles
Profit = Revenue- Total cost =(Price * Q)-(FC + vc*Q)
P=$3.00 *1500-$2560 - $1.00*1500=
P=$4500-$2560-$1500=440
Final answer:
Northwest Molded must sell 1,280 handles to break even, based on their fixed weekly costs of $2,560 and a variable cost of $1.00 per handle with a selling price of $3.00 each. If they produce and sell 1,500 handles, they will make a profit of $440.
Explanation:
To calculate the break-even point for Northwest Molded, we need to determine the number of handles that must be sold to cover the total costs, which include both fixed and variable costs.
The fixed cost to operate the molding machine is $2,560 per week, and the variable cost per handle is $1.00.
Each handle is sold for $3.00. The break-even point is reached when total cost equals total revenue, which can be found using the break-even formula:
Break-even point in units = Fixed costs / (Selling price per unit - Variable cost per unit)
Thus, for Northwest Molded:
Break-even point in units = $2,560 / ($3.00 - $1.00) = $2,560 / $2.00 = 1,280 handles
To calculate the profit for producing and selling 1,500 handles, we need to compute the total revenue and subtract the total costs:
Total Revenue = Selling price per unit × Number of units sold = $3.00 × 1,500 = $4,500
Total Costs = Fixed costs + (Variable cost per unit × Number of units sold) = $2,560 + ($1.00 × 1,500) = $4,060
Profit = Total Revenue - Total Costs = $4,500 - $4,060 = $440
Therefore, in order to break even, Northwest Molded must mold and sell 1,280 handles weekly, and the company would make a profit of $440 if they produced and sold 1,500 handles.
Instructions for a chemical procedure state to mix salt, baking soda, and water in a 20:15:10 ratio by mass. How many grams of water would be required to make a mixture that contains 24 grams of baking soda?
Answer:
16 g of water.
Step-by-step explanation:
salt : baking soda : water = 20 : 15 : 10
If we have 24 g of baking soda that is 24/15 = 8/5 times of 15.
So by proportion the amount of water would be 10 * 8/5 = 16 grams.
The mass of water in the mixture is 16 gm
What is Ratio and Proportion ?When a number is divisible by another number then they can be written in the form of ratio p :q , When two ratios are equal they are said to be in proportion.
It is given that
salt, baking soda, and water in a 20:15:10 ratio by mass are mixed
mixture contains 24 grams of baking soda
Mass of Water = ?
Baking Soda : Water = 15 : 10
Let the mass of water is x
then the ratio is 24 : x
As both these ratios are equal
15 : 10 = 24 : x
15 / 10 = 24 / x
x = 24 * 10 / 15
x = 16 gm
Therefore the mass of water in the mixture is 16 gm.
To know more about Ratio and Proportion
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What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resistance of 24 ohms. (YOU MUST SHOW YOUR WORK)!!
Answer:
The total resistance is [tex]7.0588\Omega[/tex]
Step-by-step explanation:
Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: [tex]R_1=10\Omega [/tex] and [tex]R_2=24\Omega [/tex].
First step: find the total current
For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors ([tex]R_1[/tex] and [tex]R_2[/tex]).
[tex]I_{R_1}=\frac{V_S}{R_1}[/tex][tex]I_{R_2}=\frac{V_S}{R_2}[/tex]The total current is:
[tex]I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}[/tex]
[tex]I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}[/tex]
Now, the total resistance ([tex]R_{TOTAL}[/tex]) would be the voltage divided by the total current:
[tex]R_{TOTAL}=\frac{V_S}{I_{TOTAL}}[/tex]
If you replace [tex]I_{TOTAL}[/tex] by the expression obtained previously, the total resistance would be:
[tex]R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}[/tex]
After simplifying the terms you should get:
[tex]R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}[/tex]
Now, you must replace the values of the resistors:
[tex]R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega [/tex]
Thus, the total resistance is [tex]7.0588\Omega[/tex]
A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s2, and the car has an acceleration of 3.40 m/s2. The car overtakes the truck after the truck has moved 60.0 m. (a) How much time does it take the car to overtake the truck
Answer:
Time take by car to overtake the truck is 7.6 seconds.
Step-by-step explanation:
Given : A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s², and the car has an acceleration of 3.40 m/s². The car overtakes the truck after the truck has moved 60.0 m.
To find : How much time does it take the car to overtake the truck ?
Solution :
According to question,
Taking the origin to be the truck position when it is at rest.
The car overtakes the truck after the truck has moved 60.0 m.
Using the equation to find time,
[tex]x-x_o=v_ot+\frac{1}{2}at^2[/tex]
Where, [tex]x_o=0[/tex] initial distance
[tex]v_o=0[/tex] initial velocity
a= 2.10 m/s² is the acceleration of the truck
x=60 m is the distance truck moved.
Substitute the value in the formula,
[tex]60-0=0(t)+\frac{1}{2}\times 2.10\times t^2[/tex]
[tex]60=1.05\times t^2[/tex]
[tex]t^2=\frac{60}{1.05}[/tex]
[tex]t=\sqrt{\frac{60}{1.05}}[/tex]
[tex]t=7.55[/tex]
Therefore, Time take by car to overtake the truck is 7.6 seconds.
What is buffer and what is dissolve? (4 pts)
Answer:
The buffer is the solution which basically oppose pH change upon the expansion of an acidic or fundamental parts. It can kill limited quantities of included corrosive or base, in this way keeping up the pH of the arrangement generally stable and steady.
Acidic buffer is the arrangements are usually produced using weak acidic nature and also by the sodium salt.
Dissolve is the process of break down is to make a solute go into an solution. Dissolving is likewise called disintegration. Regularly, this includes a strong going into a fluid stage, however disintegration can include different changes too.
For instance, when compounds structure, one strong breaks down into another to frame a strong arrangement.
Food mix A contains 2% fat, and food mix B contains 7% fat. A 20-kilogram diet mix of foods A and B is formed. If x kilograms of food A are used, write an algebraic expression that represents the total number of kilograms of fat in the final food mix. Simplify the expression.
Answer:
The required expression is y = 1.4 - 0.05x
Step-by-step explanation:
Consider the provided information.
Food mix A contains 2% fat and food mix B contains 7% fat.
Let x kilograms of food A are used, in a 20-kilogram mixture.
Thus, 20 - x kilograms of food B are used, in a 20-kilogram mixture.
Now It is given that A contains 2% fat and food mix B contains 7% fat.
2% and 7% can be written as 0.02 and 0.07 respectively. Let represent the total fat with y.
Thus, the required expression is:
y = 2% (x) + 7% (20 - x)
y = 0.02 (x) + 0.07 (20 - x)
y = 0.02x + 1.4 - 0.07x
y = 1.4 - 0.05x
Hence, the required expression is y = 1.4 - 0.05x
What percent of 1600 is 2?
Answer: 0.125%
Step-by-step explanation:
Let 1600 corresponds to the 100% value and 2 is a part of the total 100% value 1600.
The formula to find the percent of a part :_
[tex]\%=\dfrac{\text{Part}}{\text{Total}}\times100[/tex]
Substitute Part= 2 and Total = 1600 in the formula, we get :-
[tex]\%=\dfrac{2}{1600}\times100\\\\\Rightarrow\ \%=\dfrac{1}{8}\%=0.125\%[/tex]
Therefore, 2 is 0.125% of 1600.
Hence, the percent of 1600 is 2 = 0.125%
To find what percent of 1600 is 2, divide 2 by 1600 and multiply by 100, resulting in 0.125%. Thus, 2 is 0.125% of 1600.
To determine what percent of 1600 is 2, you can use the formula for percentage:
Percentage = (Part / Whole) × 100
Here, the part is 2 and the whole is 1600. Plug these values into the formula:
Percentage = (2 / 1600) × 100
First, perform the division:
2 / 1600 = 0.00125
Next, multiply by 100 to convert to a percentage:
0.00125 × 100 = 0.125%
Therefore, 2 is 0.125% of 1600.