1/7-3(3/7n-2/7)
I need help solving this problem...

Answers

Answer 1
Final answer:

To solve the expression 1/7 - 3(3/7n - 2/7), distribute the 3 to the terms inside the parentheses, simplify the expression inside the parentheses, and combine like terms to get the simplified form of 7n - 1/7.

Explanation:

To solve the expression 1/7 - 3(3/7n - 2/7), we need to follow the order of operations which is Parentheses, Exponents, Multiplication and Division (from left to right), and finally Addition and Subtraction (from left to right).

First, distribute the 3 to the terms inside the parentheses: 1/7 - (9/7n - 6/7).

Next, simplify the expression inside the parentheses: 1/7 - 9/7n + 6/7.

Finally, combine like terms by subtracting and adding the fractions: 7n - 1/7.

So, the simplified form of the expression 1/7 - 3(3/7n - 2/7) is 7n - 1/7.

Answer 2

Final answer:

The algebraic expression 1/7 - 3(3/7n - 2/7) can be simplified by distributing the -3 and combining like terms to yield a final expression of 1 - 9/7n.

Explanation:

The student is asking for help in solving an algebraic expression. The problem given is 1/7 - 3(3/7n - 2/7). To solve this, we need to apply the distributive property and then simplify the expression. Here's how we can solve it step by step:

Distribute the -3 to the terms inside the parenthesis: -3 * (3/7)n = -9/7n and -3 * (-2/7) = 6/7.

The expression now becomes 1/7 - 9/7n + 6/7.

Combine like terms, which are the constant fractions: 1/7 + 6/7 = 7/7 = 1.

The final simplified expression is 1 - 9/7n.


Related Questions

The sum of $3,000 is deposited into an account paying 10% annually. If $1,206 is withdrawn at the end of years 1 and 2, how much then remains in the account?"

Answers

What we have so far: 
INITIAL CASH AMOUNT IN THE BANK: USD3,000
ANNUAL INCREASE OF THE CASH AMOUNT IN THE BANK: 10%
YEARS THE CASH STAYED IN THE BANK: 2 years.
AMOUNT WITHDRAWN AT THE END OF YEAR 1: USD1,206
AMOUNT WITHDRAWN AT THE END OF YEAR 2: USD1,206

First, we need to solve for YEAR 1:
FOR YEAR 1: 
Initial Deposit * Annual Increase Rate = Annual Increase
3,000 * 0.10 = Year 1's Annual Increase
Year 1's  Annual Increase = USD300
∴The YEAR 1'S ANNUAL INCREASE IS USD300.
∴The NEW AMOUNT is now USD3,300.

BUT NOT SO FAST! After the year, you took out USD1,206.
New Amount - USD1,206 = Year 1 Amount
3,300 - 1,206 = Year 1 Amount
Year 1 Amount = USD2094
∴The YEAR 1 AMOUNT which will carry over to YEAR 2 is USD2094.

Now, let us solve for the REMAINING BALANCE.
FOR YEAR 2's Annual Increase: 
YEAR 1 AMOUNT * Annual Increase = Year 2's Annual Increase
2094*0.10 = Year 2's Annual Increase
Year 2's Annual Increase = USD209.4
∴The YEAR 1'S ANNUAL INCREASE IS USD209.4.
∴The NEW AMOUNT is now USD2,303.4.

But you took out USD1,206
USD2,303.4 - USD1,206 = Remaining Balance
Remaining Balance = USD1097.4

∴The Answer is: USD1097.4

"The amount remaining in the account after the withdrawals at the end of years 1 and 2 is $1,818.

To solve this problem, we will calculate the amount in the account at the end of each year, taking into account the interest earned and the withdrawals made.

1. At the end of the first year, the account earns 10% interest on the initial $3,000 deposit. The calculation is as follows:

 [tex]\[ \text{Amount at the end of year 1}[/tex] = 3000 \times (1 + 0.10) = 3000 \times 1.10 = 3300 \]

2. At this point, $1,206 is withdrawn from the account, leaving:

 [tex]\[ \text{Amount after withdrawal at the end of year 1}[/tex]= 3300 - 1206 = 2094 \]

3. This remaining amount then earns 10% interest for the second year:

 [tex]\[ \text{Amount at the end of year 2} = 2094 \times (1 + 0.10) = 2094 \times 1.10 \][/tex]

4. At the end of the second year, another $1,206 is withdrawn:

[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 \][/tex]

5. To find the exact amount, we calculate the interest earned in the second year and then subtract the withdrawal:

 [tex]\[ \text{Interest earned in year 2} = 2094 \times 0.10 = 209.4 \][/tex]

 [tex]\[ \text{Amount after interest in year 2} = 2094 + 209.4 = 2303.4 \][/tex]

[tex]\[ \text{Amount after withdrawal at the end of year 2} = 2303.4 - 1206 = 1097.4 \][/tex]

However, there seems to be an error in the calculation. Let's correct it:

[tex]\[ \text{Amount after withdrawal at the end of year 2} = 2094 \times 1.10 - 1206 \][/tex]

 [tex]\[ \text{Amount after withdrawal at the end of year 2} = 2303.4 - 1206 \][/tex]

 [tex]\[ \text{Amount after withdrawal at the end of year 2} = 1097.4 \][/tex]

This is not the correct final amount. We need to correctly calculate the amount after the second withdrawal:

[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 \][/tex]

 \[tex][ \text{Amount after withdrawal at the end of year 2} = 2303.4 - 1206 \][/tex]

 [tex]\[ \text{Amount after withdrawal at the end of year 2} = 1097.4 \][/tex]

Upon re-evaluating the calculation, we find that the correct amount after the second withdrawal is:

[tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 \][/tex]

 [tex]\[ \text{Amount after withdrawal at the end of year 2} = 2294.4 \][/tex]

[tex]\[ \text{Amount after withdrawal at the end of year 1} = 3300 - 1206 = 2094 \][/tex]

 [tex]\[ \text{Amount after withdrawal at the end of year 2} = (2094 \times 1.10) - 1206 = 2294.4 \][/tex]

An isosceles triangle has area of 125 ft. If the base is 16 ft, what is the length of each leg? Round your answer to the nearest tenth

Answers

Final answer:

To find the length of each leg of an isosceles triangle with an area of 125 ft² and a base of 16 ft, we first calculate the height and then apply the Pythagorean Theorem. The length of each leg is approximately 17.6 ft.

Explanation:

The question asks about finding the length of each leg of an isosceles triangle given the area and the base. To solve this, we use the formula for the area of a triangle, A = 1/2 × base × height, and apply the Pythagorean Theorem since the height creates a right triangle with the leg of the isosceles triangle and half of the base.

First, we find the height using the given area, A = 125 ft² and base, b = 16 ft. The formula rearranges to height = 2A / base, giving us height = 2(125) / 16 = 15.625 ft.

Next, using the Pythagorean Theorem, a² + b² = c², we let a represent half of the base (8 ft), b be the height (15.625 ft), and c be the leg of the triangle. Solving for c, we find c ≈ 17.6 ft, rounded to the nearest tenth.

Using the graph below, find the missing value to complete the t-chart.
the chart:

x y
-3 5
0 -1
2 ?

A. -3
B. 5
C. 3
D. -5

Answers

Answer:

I THINK THE ANSWER IS A

Step-by-step explanation:

BECAUSE IF YOU SEE THEN IT WILL NOT BE B BECAUSE IT WENT DOWN AND IF YOU  LOOK IT UP IT WILL BE A

Answer: you answer would be -5

Step-by-step explanation:

Go to the origin and count to the right to places. Then count downwards towards the line and count the number. In this case you move down 5 so it is -5. So count down (or up) towards the line and however many you went that’s your answer (remember up and right are both positive, and down and left are both negative.)

What is the overtime rate for a mail carrier who regularly earns $9.80 an hour?

Answers

Assuming that the mail carrier earns 1.5x usual for overtime like Normal workers it should be $14.7

The overtime rate for a mail carrier earning $9.80 per hour is calculated as one and a half times the regular rate, resulting in an overtime pay of $14.70 per hour.

The question is asking for the overtime rate for a mail carrier earning a regular hourly wage of $9.80. In the United States, the standard overtime rate is typically one and a half times the employee's regular hourly pay for any hours worked beyond 40 in a workweek. Therefore, to calculate the overtime rate for a mail carrier earning $9.80 per hour, the following calculation is performed:

Regular hourly wage times 1.5 = Overtime rate

$9.80 times 1.5 = $14.70 per hour

How do I calculate the volume of a circle?

Answers

A circle is a plane figure that has zero volume by definition. No calculation is required.

_____
The volume of a sphere is given by the formula
[tex] V = \frac{4 \pi}{3} r^{3} [/tex]

Fill in the value for the radius and evaluate the expression.

A circle, being 2-dimensional, does not have volume.

To clarify, a circle is a 2-dimensional shape and therefore does not have a volume. However, if you intended to calculate the volume of a 3-dimensional shape such as a sphere or a cylinder that has a circular base, here are the steps:

Volume of a Cylinder

The formula for the volume of a cylinder is:

V = πr²h

Volume of a Sphere

The formula for the volume of a sphere is:

V = 4/3 πr³

a bag contains 1p 2p and 5p coins .3/8 of the bag are 1p coins.there are as many 5p coins than 1p coins in the bag . there are 640 cois in total. work out the number of 2p coins in the bag

Answers

The number of 2p coins in the bag is 160

How to get the number of 2p coins

Assuming:

the number of 1p coins is xthe number of 2p coins is y and the number of 5p coins is z.

According to the given information:

x = 3/8 * 640 = 240

z = x = 240

total number of coins is 640.

x + y + z = 640

plugging in the values

240 + y + 240 = 640

y + 480 = 640

y = 160

what are the points of intersection of the lines below 2x-y=10 y=-4x+2

Answers

This is like a system:

2x-y=10
y=-4x+2

Use substitution method:

2x-(-4x+2)=10
y=-4x+2

2x+4x-2=10
y=-4x+2

6x-2=10
y=-4x+2

6x=12
y=-4x+2

x=2
y=-4(2)+2

The points of intersection are: x=2 and y=-6.

Find the area of a circle circumscribed about an equilateral triangle whose side is 18 inches long.

Answers

we know that

the Area of a circle=pi*r²
the length of a radius of circle circumscribed about an equilateral triangle is
r=b*(√3)/3
where
b---------> length of a side equilateral triangle-------> 18 in
then
r=18*(√3)/3=10.39 in

A=pi*(10.39)²=108*pi=339.29 in²

the answer is 339.29 in²

In triangle XYZ,XY=15,YZ=21, and XZ=27. What is the measure of angle Z to the nearest degree?

Answers

Final answer:

Using the Law of Cosines, we find that the cosine of angle Z is approximately 0.6333, and therefore, angle Z in triangle XYZ is approximately 51° when rounded to the nearest degree.

Explanation:

To find the measure of angle Z in triangle XYZ, with sides XY = 15, YZ = 21, and XZ = 27, we can use the Law of Cosines. The Law of Cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. In our case, we can find the cosine of angle Z by the equation:

cos(Z) = (XY² + XZ² - YZ²) / (2 · XY · XZ)

Plugging in the values, we get:

cos(Z) = (15² + 27² - 21²) / (2 · 15 · 27)

Calculating further:

cos(Z) = (225 + 729 - 441) / (810)

cos(Z) = 513 / 810

cos(Z) = 0.6333

The next step is to find the angle whose cosine is 0.6333. We can use a calculator to find the inverse cosine:

Z = cos⁻¹(0.6333)

Hence, the measure of angle Z to the nearest degree is approximately:

Z ≈ 51°

The measure of angle Z is approximately 70 degrees (rounded to the nearest degree).

To find the measure of angle Z in triangle XYZ, you can use the Law of Cosines. The formula is:

[tex]\[ c^2 = a^2 + b^2 - 2ab \cos(C) \][/tex]

where:

- c is the side opposite the angle you want to find (in this case, side XZ),

- a and b are the other two sides (XY and YZ),

- C is the angle opposite side c.

In this case, let C be the angle Z, and a = XY = 15, b = YZ = 21, and c = XZ = 27.

[tex]\[ 27^2 = 15^2 + 21^2 - 2(15)(21) \cos(Z) \][/tex]

Now, solve for cos(Z):

[tex]\[ 729 = 225 + 441 - 630 \cos(Z) \][/tex]

[tex]\[ 630 \cos(Z) = 441 - 225 \][/tex]

[tex]\[ 630 \cos(Z) = 216 \][/tex]

[tex]\[ \cos(Z) = \frac{216}{630} \][/tex]

[tex]\[ \cos(Z) \approx 0.343 \][/tex]

Now, find the angle Z:

[tex]\[ Z = \cos^{-1}(0.343) \][/tex]

[tex]\[ Z \approx 70.18 \][/tex]

So, the measure of angle Z is approximately 70 degrees (rounded to the nearest degree).

Which triangle is it ?

Answers

The answer is: The first triangle. The reasons are shown below:

 1. All the triangles are rigth triangles, because they have an angle of 90°. So, let's calculate the others angles of the first one:

 Tan(α)^-1= opposite leg/adjacent leg

 Opposite leg=5
 Adjacent leg=5√3

 Tan(α)^-1= 5/5√3
 Tan(α)^-1=30°

 2. Let's calculate the other angle:

 Tan(α)^-1= opposite leg/adjacent leg

 Now, the opposite leg will be 5√3 and the adjacent leg will be 5. Then:

 Tan(α)^-1= 5√3/5
 Tan(α)^-1=60°

 As you can see, the angles of first triangle are: 30°,60° and 90°. 

Suppose that Bangladesh, India, Pakistan, and Nepal are economically interdependent. The following table shows the exports and imports of each country, with all monetary values given in millions of equivalent US dollars. Country of Origin Exporting to... Amount ($ 2007-13-04-00-00_files/i0260000.jpg 1,000,000) Bangladesh India 2,817 Bangladesh Pakistan 2,369 Bangladesh Nepal 3,039 India Bangladesh 2,023 India Pakistan 3,462 India Nepal 2,184 Pakistan Bangladesh 3,201 Pakistan India 2,336 Pakistan Nepal 2,338 Nepal Bangladesh 2,707 Nepal India 3,363 Nepal Pakistan 2,332 Based on the information in the table, assuming that these four countries trade strictly within the group, what is the value of the greatest trade balance in this group? a. $841 million b. $847 million c. $8,402 million d. $8,516 million

Answers

The answer is A. $841 million

1. Total trade between Bangladesh and other three nations which are India , Pakistan, Nepal= 2,817  +  2,369  + 3,039=$ 8,225

2. Total trade between India and other three nations which are Bangladesh  , Pakistan, Nepal= 2,023 +3,462 + 2,184=$7669

3.  Total trade between Pakistan and other three nations which are Bangladesh,India, Nepal=3,201 + 2,336 +2,338= $7875

4. Total trade between Nepal and other three nations which are Bangladesh,India, Pakistan=2,707 +3,363+2,332 = $ 8402

The greatest trade is between Nepal and other three nations which are Bangladesh,India, Pakistan=2,707 +3,363+2,332 = $ 8402→→Option (C)



The following stem-and-leaf plot represents the scores earned by Mr. Roberts's class on their most recent science test.

What is the median of the scores?
78
80
81
86

Answers

First we need to count the total number scores. This can be done from the stem and leaf plot. The total number of scores are 19. The total number of values is odd, so the median position will be:

[tex] \frac{19+1}{2}=10th [/tex]

Thus the 10th score is the median score for the class of Mr. Robert. The 10th score from the stem and leaf plot is 81.

Thus 81 is the median score of Mr. Robert's Class. 

Answer:

im pretty sure its 81

Step-by-step explanation:

What is 0.0371 × 10000?

Answers

The answer to this mathmatical problem is 371
Since we are multiplying 0.0367 x 10000, you would move the decimal over 4 times to the RIGHT (only move the decimal to the left when dividing)

Your answer would then be: 367

Hope that helps explain a little bit better! Good luck. :)

at a certain time of day a person 6 ft tall cast a 4 ft shadow how long is the shadow cast by ba 21 ft tree at the same time?

Answers

Use the cross products rule. 6/4 = 21/x. You will get 6x = 84. Divide both sides by 6 to get x = 14 feet.

What are two pair fractions with common denominators for 3/5 and 3/4

Answers

the cheap answer is, you simply "grab the denominator of one and multiply it times the other's top and bottom", so let's do so,

[tex]\bf \cfrac{3}{5}\cdot \cfrac{4}{4}\implies \cfrac{12}{20}\qquad \qquad \qquad \qquad \qquad \cfrac{3}{4}\cdot \cfrac{5}{5}\implies \cfrac{15}{20}[/tex]

Tom  and Arnold both leave the internet cafe at the same time, but in opposite directions. If Tom travels 9mph and Arnold travels 16mph, how long until they are 200 miles apart?

Answers

x = hours walking
9x + 16x = 200
25x = 200
x = 8 hours
Hello There! ;)

Work:
First, we create our equation right so its...
9x + 16x = 200
25x = 200

Then, we can just divide 25/200
Which is 8

Answer:
x= 8 h or hours.

Hoping this helps you!
-Arianna

Which of the following is an odd function?

g(x) = x2
g(x) = 5x – 1
g(x) = 3
g(x) = 4x

Answers

An odd function is symmetrical about the origin: g(-x) = -g(x).

The 4th selection is appropriate.

Answer:

g(x) = 4x is an odd function.

Step-by-step explanation:

A function g(x) is odd if it satisfies that, for all x we have g(-x) = -g(x). Then,

[tex]g(x) =x^2[/tex] is not an odd function beacuse only give positive values, then for example if x= 2

[tex]g(-2) =(-2)^2 = 4 \neq -4 = -g(2)[/tex].

g(x) = 5x-1 is not an odd function. I'll also give you a counterexample: for x=1 we have

g(-1) = 5(-1)-1 = -6 ≠ -4 = -(5-1) = -g(1).

g(x) = 3 is not an odd function. I'll also give you a counterexample: for x=1 we have

g(-1) = 3 ≠ -3 = -g(1).

Finally, g(x) = 4x is an odd function because for all x we have g(-x) = -g(x):

g(-x) = 4(-x) = -4x = -g(x).

What can be determined about this data set before finding the range or the interquartile range? 19, 25, 35, 38, 41, 49, 50, 52, 99

Answers

Given:
19, 25, 35, 38, 41, 49, 50, 52, 99

Just upon looking at the data set, I can determine that there is an OUTLIER. An outlier is a point that is distant from other points.

The outlier in this data set is number 99.

These data set has the following five number summary:
1) minimum number - 19
2) 1st quartile - 30
3) 2nd quartile or median - 41
4) 3rd quartile - 51
5) maximum number - 99

Interquartile range = q3 - q1 → 51 - 30 = 21 

To determine if an observation point is an outlier, we need to determine the lower fence and the upper fence.

lower fence = q1 - 1.5(iqr)
lower fence = 30 - 1.5(21) → 30 - 31.5 = -1.5

upper fence = q3 + 1.5(iqr)
upper fence = 51 + 1.5(21) → 51 + 31.5 = 82.50

Any number outside the lower fence, -1.5, and upper fence, 82.50, is an OUTLIER. 

99 is beyond the upper fence. Thus, it is an outlier.


The data has an outlier, but the interquartile range will not change. The answer is c

Please answer this question and give give a detailed answer. Brainliest to who ever answers first and gets it correct

Answers

Try this option:
note, that ∠GFB=∠CBH=117° (AD||EG!) and ∠x=∠CFG.
For ∠CFG: ∠CFG=117-∠CFB=117-42=75°

Answer: 75°

Assume the method dosomething has been defined as follows: public static void dosomething (int[] values, int p1, int p2) { int temp = values[p1]; values[p1] = values[p2]; values[p2] = temp; } what does the method do?3

Answers

First step is to analyze input and output variables:INPUT:list of integers with name "values"integer with name "p1"integer with name "p2"OUTPUT:there is no output variable as in declaration of a method there is void
ANALYSIS:"int temp = values[p1]"this line creates variable "temp" which is integer. then this line goes to the list "values" and takes value that is at position "p1" and stores it into variable "temp"
"values[p1] = values[p2]"this line goes to the list "values" and takes value that is at position "p2" and stores it into variable that is at position "p1"
"values[p2] = temp"this line takes value of the variable "temp" and stores it into list values at position "p2"
Short explanation:this code replaces values of the list at between positions p1 and p2

donna received a $70 gift card for a coffee store. she used it in buying some coffee that cost $7.84 per pound. after buying the coffee, she had $30.80 left on her card. how many pounds of coffee did she buy?

Answers

P= pounds of coffee

$70 minus the price per pound times the number of pounds equals the amount left on the card ($30.80).

$70 - $7.84p= $30.80

subtract 70 from both sides
-7.84p= -39.20

divide both sides by -7.84
p= 5 pounds of coffee

Hope this helps! :)
Hello!

Let's solve this step by step!
So, we know that after Donna will have $30.80 remaining after buying a certain number of pounds, and we also know that each pound of coffee costs $7.84.

Subtract the amount that will be left from the gift card.

70 - 30.80 = 39.2

Now, divide this by the cost per pound.

39.2 ÷ 7.84 = 5

A N S W E R:

Donna bought 5 pounds of coffee.

Good day!

a population of 140000 grows 4% per year for 16 years. How much will the population be after 16 years?

Answers

At the end of the Year 1 the population will be = 110,000 + 4% of 110,000 =P1At the end of the Year 2 the population will be=P1+ 4% of P1= 110,000 + 4% of 110,000 + 4% of (110,000 + 4% of 110,000) =  110,000 +  4% of (110,000+ 110,000 + 4% of 110,000) =  110,000 + 2*4% of 110,000 + (4%)2  of 110,000= P2At the end of the Year 3 the population will be= P2+ 4% of P2= 110,000 +2* 4% of 110,000 + (4%)2 of 110,000 + 4% of [ 110,000 +2* 4% of 110,000 + (4%)2 of 110,000] = 110,000 +2* 4% of 110,000 + (4%)2 of 110,000 + 4% of 110,000 + 2* (4%)2 of 110,000 + (4%)3 of 110,000 =110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000 =P3At the end of the Year 4 the population will be= P3+ 4% of P3=110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000 +4% of [110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000] =110,000 +4* 4% of 110,000 + 6*(4%)2 of 110,000+4* (4%)3 of 110,000+ (4%)4 of 110,000 Now if we substitute n for 110,000 and r for 4% yearly rate of increase, we can rewrite,Before Year 1, at Year 0, the population, P0= n = n(1+r)0At the end of the Year 1 the population , P1= n+rn= x(1+r)1At the end of the Year 2 the population , P2= n+2rn+r2n =n(1+2r+r2)=n(1+r)2At the end of the Year 3 the population , P3= n+3rn+2r2n+r3n=n(1+3r+3r2+r3)=x(1+r)3At the end of the Year 4 the population , P4= n+4rn+6r2n+4r3n+r4n=n(1+r)4.
.
.
.
.
.
At the end of the Year n the population , Px=n+nrx+(x-1)r2n+(x-2)r3n+...........+(x-x+2)r(x-1)x+(x-x+1)rxn=n(1+r)x.....At the end of the Year 16 the population , P16= n+16rn+15r2n+14r3n+.............+3r14n+2r15n+r16n=n(1+r)16 Thus under given condition of rate of growth, the Population P(x) at xth year will be P(x)=n(1+r)x Therefore, a population of 110,000 growing at 4% per year, in 16 years will be= 110,000(1+4/100)16= 110,000(1.04)16=206027.93702999115428132473599427≈206028

I hope this is helpful. I found the solution on the internet. Hope you have a good day and bye.

the longest side of an acute isosceles triangle is 8 centimeters . rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides?

Answers

Answer: greater than 5.7 cm

Explanation:

1) The acute angle is restricted to an upper bound of to 90°, i.e. the greatest value of an acute angle must be less than 90°.

2) the smaller the acute angle the longer the two congruent sides of the isosceles triangle, the greater the acute angle the shorter the two congruent sides.

3) Find the lower bound of the two congruent sides by using the upper bound of the acute angle.

4) when the angle is 90°, you can use the Pytagorean theorem

c^2 = a^2 + b^2

c = 8 cm, a = b

c^2 = 2a^2

8^2 = 2a^2

2a^2 = 64

a^2 = 64/2

a^2 = 32

a = √32

a = 5.7 cm

5.7 cm is the lower bound of the length of the two small sides, therefore, the length of the two small sides has to be greater than 5.7 cm

Answer:5.7 cm

Step-by-step explanation:

Just took the test.

what is the maximum volume of water a hamster bath can hold with a depth of 1 2/3, a length of 2 1/3 inches, and a width of 2 inches?

Answers

The volume is 70/9 or 7 7/9.
=========================================
[tex] \frac{5}{3} \times \frac{7}{3} \times \frac{2}{1} = \frac{70}{9} [/tex]
[tex] \frac{70}{9} = 7 \frac{7}{9}[/tex]
[tex]l \times w \times h = v[/tex]

Answer:

[tex]V=7\frac{7}{9} cubic inches[/tex]

Step-by-step explanation:

Given: The length of the hamster bath is [tex]2\frac{1}{3}[/tex] inches, width is 2 inches and the depth is  [tex]1\frac{2}{3}[/tex] inches.

To find: The maximum volume of water a hamster bath can hold.

Solution: It is given that The length of the hamster bath is [tex]2\frac{1}{3}[/tex] inches, width is 2 inches and the depth is  [tex]1\frac{2}{3}[/tex] inches, then the volume is given as:

[tex]V=l{\times}w{\times}d[/tex]

Substituting the given values, we have

[tex]V=2\frac{1}{3}{\times}2{\times}1\frac{2}{3}[/tex]

[tex]V=\frac{7}{3}{\times}2{\times}\frac{5}{3}[/tex]

[tex]V=\frac{70}{9}[/tex]

[tex]V=7\frac{7}{9} cubic inches[/tex]

Therefore, the maximum volume is [tex]7\frac{7}{9} cubic inches[/tex].

What is the order of 5x10^4 , 7x10^-5 , 3x10^-9 , 8x10^4 from least to greatest?

Answers

Answer:

[tex]3\times10^{-9},7\times 10^{-5},5\times 10^4,8\times10^4[/tex]

Step-by-step explanation:

We want to order ; [tex]5\times 10^4,7\times 10^{-5},3\times10^{-9},8\times10^4[/tex] from least to greatest.

Observe that all these numbers are in standard form.

We can order them based on the exponents.

[tex]-9<\:-5<\:4[/tex]

Since two numbers have the same exponent of 4, we need to use the multiplier to order the last two(5<8).

From least to greatest we have;

[tex]3\times10^{-9}\:<\:7\times 10^{-5}\:<\:5\times 10^4\:<\:8\times10^4[/tex]

The numbers in ascending order from least to greatest are 3x10²-9, 7x10²-5, 5x10²4, 8x10²4

To order the numbers from least to greatest, to compare the values of the numbers without the powers of 10 first and then consider the powers of 10.

Given numbers:

5x10²

7x10²-5

3x10²-9

8x10²4

Step 1: Compare the numbers without the powers of 10:

The numbers without the powers of 10 are: 5, 7, 3, and 8.

Step 2: Arrange the numbers in ascending order based on their values:

3, 5, 7, 8

Step 3: Now, consider the powers of 10:

The powers of 10 are: 10²4, 10²-5, 10²-9, and 10²4.

Since all the powers of 10 are positive, larger powers of 10 indicate larger numbers.

Step 4: Combine the results from Steps 2 and 3 to get the final order:

3x10²-9, 7x10²-5, 5x10²4, 8x10²4

To know more about ascending here

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Answers

C = 2 pi r
C = 2 x 3 x 2
C = 12 units

answer
A. 12 units
Circumference = 2(pi)r
C= 2(3.14)(2)
C= 12.56

ANSWER: the best estimate is A) 12

Hope this helps! :)

Kareem lives 4/10 of mile from the mall.Write two equivalent fraction that show what fraction of mile Kareem lives from the mall

Answers

They want two fractions that are equivalent to 4/10.

1) We can simplify 4/10 by dividing both #s by 2.

4/10 ÷ 2/2= 2/5

2) We can increase both #s by multiplying each by both by the same number. I choose the number 2 (bit this works with any number as long as you increase both numerator and denominator by the same amount).

=4/10 * 2/2
=(4*2)/(10*2)
=8/20

Two equivalent fractions are 2/5 and 8/20.

Hope this helps! :)

Emma is going camping. Each side triangle on her tent is 5 feet tall. The square base is 4 feet wide. What is the surface area of her tent?

Answers

1. The tent has the shape of a square pyramid. Therefore, to solve this problem, you must apply the formula for calculate its surface area, which is:

 A=2bs+b²

 "A" is the surface area of the square pyramid.
 "b" is the side length of the square base (b=4 feet).
 "s" is the slant of the face (s=5 feet).

 2. When you substitute these values into the formula for calculate the area of the square pyramid (A=2bs+b²), you obtain:

 A=2bs+b²
 A=2(4 feet)(5 feet)+(4 feet)²
 A=2(20 feet²)+16 feet²
 A=40 feet²+16 feet²
 A=56 feet²

 What is the surface area of her tent?

 The answer is: The surface area of her tent s 56 feet².

What equation results from completing the square and then factoring? x^2 + 24x = 33

Answers

Answer:

[tex](x+12)^2=177[/tex]

Step-by-step explanation:

We have been given an equation: [tex]x^2+24x=33[/tex].

To complete the square we change the left hand side of the equation to a perfect square trinomial. For this we add [tex](\frac{b}{2})^2[/tex] to both sides of equation, where b is the coefficient of x.

We can see that coefficient of x for our given equation is 24. So we will add [tex](\frac{24}{2})^2=12^2=144[/tex] to both sides of our equation.

[tex]x^2+24x+144=33+144[/tex]

[tex]x^2+24x+144=177[/tex]

Let us factor left side of our equation as the square of  binomial.

[tex](x+12)^2=177[/tex]

Therefore, our resulting equation will be [tex](x+12)^2=177[/tex].

Answer: (x+12)^2=177

Step-by-step explanation:

What are the intercepts of the line?





A.


x-intercept:-8 ; y-intercept:0


B.


x-intercept:0 ; y-intercept:


C.


x-intercept:-8 ; no y-intercept:


D.


no x-intercept: ; y-intercept:-8

Answers

The answer should be D because it only crosses Y at -8 and doesn't cross X

Answer:

D cause it crosses at -8

Step-by-step explanation:

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