Answers
The negative charge should be placed 41 m from +1.0 C charged object
Further explanationElectric charge consists of two types i.e. positively electric charge and negatively electric charge.
There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
[tex]\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }[/tex]
F = electric force (N)
k = electric constant (N m² / C²)
q = electric charge (C)
r = distance between charges (m)
The value of k in a vacuum = 9 x 10⁹ (N m² / C²)
Let's tackle the problem now !
Given:
Q₁ = +1.0 C
Q₂ = +2.0 C
R₁ = x
R₂ = 100 - x
q = -1.0 × 10⁻³ C
Unknown:
x = ?
Solution:
In order to produce a total force = 0, the electric forces acting on this negative charge must be in the opposite direction and equal in magnitude.
We assume the distance of this negative charge to the positive charge +1.0 C is x, then:
[tex]F_1 = F_2[/tex]
[tex]k\frac{Q_1q}{R_1^2} = k\frac{Q_2q}{R_2^2}[/tex]
[tex]\frac{Q_1}{R_1^2} = \frac{Q_2}{R_2^2}[/tex]
[tex]\frac{1}{x^2} = \frac{2}{(100 - x)^2}[/tex]
[tex]\sqrt{\frac{1}{x^2}} = \sqrt{\frac{2}{(100 - x)^2}}[/tex]
[tex]\frac{1}{x} = \frac{\sqrt{2}}{100 - x}[/tex]
[tex]100 - x = \sqrt{2}x[/tex]
[tex]x + \sqrt{2}x = 100[/tex]
[tex]x ( 1 + \sqrt{2} ) = 100[/tex]
[tex]x = \frac{100}{1 + \sqrt{2}}[/tex]
[tex]x = 100(\sqrt{2} - 1) ~ m[/tex]
[tex]x \approx 41 ~ m[/tex]
Learn moreThe three resistors : https://brainly.com/question/9503202A series circuit : https://brainly.com/question/1518810Compare and contrast a series and parallel circuit : https://brainly.com/question/539204Answer detailsGrade: High School
Subject: Physics
Chapter: Static Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces
Related Questions
The work function (φ) for a metal is 7.40×10-19 j. what is the longest wavelength of electromagnetic radiation that can eject an electron from the surface of a piece of the metal
Answers
To determine the longest wavelength of electromagnetic radiation that can eject an electron from the metal, one can use the equation E = hc / λ, where E equals the work function, h is Planck's constant, c is the speed of light, and λ is the wavelength. Rearranging it as λ = hc / φ and putting the given value of work function and constant values, one can find the required wavelength.
Explanation:To calculate the longest wavelength of electromagnetic radiation that can eject an electron from the surface of the metal, we need to use the equation which describes the relationship between the energy of a photon (E) and its wavelength (λ). This equation is:
E = hc / λ
Where:
E is the energy of the photon (which is equal to the work function φ in this case), h is Planck's constant (6.63 x 10-34 Js), c is the speed of light (3 x 108 m/s), and λ is the wavelength.
Given the work function φ (7.40×10-19J) and other constant values, we can rearrange this formula to calculate λ:
λ = hc / φ
The result will give you the longest wavelength of electromagnetic radiation that can eject an electron from the metal surface.
Learn more about Electromagnetic radiation and work function here:https://brainly.com/question/10759891
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The longest wavelength of electromagnetic radiation that can eject an electron from the surface of a piece of the metal is [tex]2.69 \times 10^{-7}\)[/tex] meters.
We use the photoelectric effect equation:
[tex]\[ E = h \nu \][/tex]
where [tex]\( E \)[/tex] is the energy of the photon, [tex]\( h \)[/tex] is Planck's constant, and [tex]\( \nu \)[/tex] is the frequency of the radiation.
The energy of the photon must be at least equal to the work function [tex](\( \phi \))[/tex] of the metal for the electron to be ejected. Therefore, we have:
[tex]\[ E = \phi \][/tex]
[tex]\[ h \nu = \phi \][/tex]
Since [tex]\( \nu = \frac{c}{\lambda} \)[/tex], where [tex]\( c \)[/tex] is the speed of light and [tex]\( \lambda \)[/tex] is the wavelength of the radiation, we can rewrite the equation as:
[tex]\[ h \frac{c}{\lambda} = \phi \][/tex]
Solving for [tex]\( \lambda \)[/tex], we get:
[tex]\[ \lambda = \frac{h c}{\phi} \][/tex]
Given that [tex]\( h = 6.626 \times 10^{-34}\)[/tex] Js (Planck's constant), [tex]\( c = 3.00 \times 10^8\)[/tex] m/s (speed of light), and [tex]\( \phi = 7.40 \times 10^{-19}\)[/tex] J (work function), we can plug in these values to find [tex]\( \lambda \)[/tex]:
[tex]\[ \lambda = \frac{6.626 \times 10^{-34} \text{ Js} \times 3.00 \times 10^8 \text{ m/s}}{7.40 \times 10^{-19} \text{ J}} \][/tex]
[tex]\[ \lambda = \frac{1.9878 \times 10^{-25} \text{ Jm/s}}{7.40 \times 10^{-19} \text{ J}} \][/tex]
[tex]\[ \lambda = 2.6862 \times 10^{-7} \text{ m} \][/tex]
An atomic nucleus has a charge of +40e. an electron is 10-9 m from the nucleus. what is the force on the electron?
Answers
[tex]F=k_e \frac{(-e)(+40e) }{r^2} =8.99\cdot 10^9 Nm^2C^{-2} \frac{(-1.6\cdot 10^{-19}C)(6.4\cdot 10^{-18}C)}{(10^{-9}m)^2} =[/tex]
[tex]=-9.2 \cdot 10^{-9} N[/tex]
which is attractive, since the two charges have opposite sign.
The force on an electron placed 10-9 m away from a nucleus with a charge of +40e can be calculated using Coulomb's law, considering the charge of the electron and the proton, the distance between them, and Coulomb's constant.
Explanation:The question pertains to the force experienced by an electron in the vicinity of an atomic nucleus with a charge of +40e. To calculate this force, we will use Coulomb's law, which states that the electric force (F) between two point charges is directly proportional to the product of the charges (q1 and q2) and inversely proportional to the square of the distance (r) between them. The formula is given by F = k * |q1 * q2| / r², where k is Coulomb's constant (8.9875 × 10⁹ N⋅m²/C²).
Given that the charge of a proton (and thus the atomic number Z) is +e and the charge of an electron is -e, the force will be attractive, and we can ignore the signs for magnitude calculation. The charge of a proton is e = 1.602 × 10⁻¹⁹ C. For a +40e charge, the total charge is 40 × e. Plug these values, along with the given distance of 10 × 10⁻¹ m into Coulomb's law to compute the force on the electron.
Therefore, the magnitude of the force on the electron by a nucleus with a charge of +40e located 10⁻¹ m away can be calculated using the steps above.
A weight suspended from a spring is seen to bob up and down over a distance of 25 cm twice each second. what is its frequency? answer in units of hz.
Answers
A dog pulls on it's leash with a 10-N force to the left, but doesn't move. Identify the reaction force.
Answers
To grasp how weak this field is, if you wanted to produce it between two parallel metal plates by connecting an ordinary 1.5 v aa battery across these plates, how far apart would the plates have to be?
Answers
The distance between two parallel metal plates to create an electric field equivalent to that inside a 1.5V AA battery can be calculated using the formula E = V/d. Without a specific electric field strength value, the exact distance can't be provided. However, due to the low voltage of the battery, the necessary plate separation would be extremely small.
The question is asking how far apart two parallel metal plates must be to create an electric field equivalent to the electric field within a 1.5V AA battery, given that the electric field is uniform. To find out the distance between the plates, we need to use the formula for electric field strength, E = V/d, where E is the electric field strength, V is the potential difference, and d is the distance between the plates.
Since we know the voltage (V) from the AA battery is 1.5 V and we are looking for d, we can rearrange the formula to d = V/E. However, we don't have the value of the electric field strength E inside the battery. If we had a reference value, for example, electric field magnitude from another setup, we could use it to solve for d. For instance, if we knew that the electric field between two plates with a certain separation was, let's say, 4.50 imes 103 V/m for a 15.0 kV potential difference, we could find their distance and then extrapolate for the 1.5V scenario.
Without specific numbers, we cannot provide the exact distance for the plates. However, it's important to realize that the electric field strength would be very small compared to typical laboratory setups due to the low voltage of the AA battery. Hence, the plates separation would have to be extremely small to match the electric field inside the battery.
the planet jupiter revolves around the sun in a period of about 12 years (3.79 × 108 seconds). what is its mean distance from the center of the sun? the mass of the sun is 1.99 × 1030 kilograms.
Answers
A = Ac = v^2/R
so m A = Mjupiter v^2/R (toward sun)
F = G Msun MJupiter /R^2 (toward sun)
so
G Msun/R^2 = v^2/R
G Msun = v^2 R
Time around = circumference /v
T = 2 pi R/v
so
v = 2 pi R/T
v^2 = (2pi)^2 R^2/T^2
so
G Msun = (2 pi)^2 R^3/T^2
(which by the way is Kepler's Third Law)
so
R^3 = G Msun T^2/(2 pi)^2
G is 6.67*10^-11
so
R^3 = 6.67*10^-11*1.99*10^30*14.36*10^16 /39.48
R^3 = 4.828*10^35
= .4828 * 10^36
so
R = .784 * 10^12 = 7.84 * 10^11 meters
The mean distance between the center of the Jupiter and the center of the Sun is "7.85 x 10¹¹ m"
The force of gravitation between the Sun and Jupiter must be equal to the centripetal force between them, for the equilibrium revolution of Jupiter around the Sun.
[tex]Centripeta\ Force\ on\ Jupiter = Gravitational\ Force\ of Attraction\ \\\\\frac{M_{Jupiter}v^2}{r} = \frac{GM_{Jupiter}M_{Sun}}{r^2}\\\\v^2 = \frac{GM_{Sun}}{r}\ -------- eqn(1)\\\\[/tex]
where,
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
[tex]M_{Sun}[/tex] = Mass of Sun = 1.99 x 10³⁰ kg
r = mean distance between the center of the Jupiter and the Sun = ?
v = linear speed of the Jupiter around the Sun = [tex]\frac{Circumference\ of Jupiter's\ Path}{Time\ Period\ of\ Revolution}[/tex]
[tex]v = \frac{2\pi r}{3.79\ x\ 10^8\ s}\\\\v^2 = \frac{4\pi^2 r^2}{14.36\ x\ 10^{16}\ s^2}[/tex]
Using the values in eqn (1), we get:
[tex]\frac{4\pi^2 r^2}{14.36\ x\ 10^{16}\ s^2} = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{r}\\\\r^3 = \frac{(14.36\ x\ 10^{16}\ s^2)(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{4\pi^2}\\\\r = \sqrt[3]{4.83\ x\ 10^{35}\ m^3}[/tex]
r = 7.85 x 10¹¹ m
Learn more about centripetal force and gravitational force here:
https://brainly.com/question/14021112?referrer=searchResults
https://brainly.com/question/16613634?referrer=searchResults
The attached picture shows the relationship between the centripetal force and the gravitational force acting on a planet (Jupiter) revolving around the sun.
Bats use ultrasound in echolocation. This sound is characterized by _____.
A. low frequency
B. low amplitude
C. high frequency
D. high amplitude
Answers
Hope this helps :)
Answer:
C. high frequency
Explanation:
Bats use high frequency sound waves -ultra sound (20 to 200 kHz) to locate their prey via a technique -echolocation. The produce these sound waves and when the waves reflect from a prey nearby, they are able to estimate the size, position and speed of their prey. The human hearing range is up to 20 kHz, so we can hear the sound produced by some of the bats.
In which of the following is no work done A.climbing stairs B.lifting a book C.pushing a shopping cart D.none of the above
Answers
The correct answer is D. none of the above. In all of the given options, work is done.
Explanation:The correct answer is D. none of the above. In all of the given options, work is done.
A. Climbing stairs: When you climb stairs, you are doing work against gravity. You are exerting a force to move your body against the force of gravity.B. Lifting a book: When you lift a book, you are also doing work against gravity. You are exerting a force to move the book against the force of gravity.C. Pushing a shopping cart: Pushing a shopping cart requires you to apply a force to move the cart, which is considered work.D. None of the above: This option is incorrect because work is done in all of the given options.Learn more about Work and force here:https://brainly.com/question/758238
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Solar-powered cars use energy from the Sun to work. A panel on the car absorbs light energy from the Sun, which then generates an electric current. This electric current, in turn, allows the car to move. Which shows the correct order of energy transformations that take place in a solar-powered car?
Answers
In a solar-powered car, solar energy is converted to electrical energy by solar cells, which is then used to power an electric motor and generate mechanical energy for the car to move.
Explanation:The correct order of energy transformations in a solar-powered car is:
Solar energy from the Sun is converted into electrical energy by solar cells on the car's panel.Electrical energy is then used to power an electric motor.Mechanical energy is generated from the movement of the electric motor, allowing the car to move.For example, when sunlight hits the solar panel, the photovoltaic cells in the panel absorb the energy and generate an electric current. This electric current is used to power the motor, which converts electrical energy into mechanical energy that powers the car's movement.
Question 4 of 10 (1 point) Jump to Question: Choose the word that best completes this sentence. A personal fall arrest system is the most ________ type of fall arrest in construction. A. Common B. Expensive C. Necessary D. Useful
Answers
is the most logical answer to me
Answer:
A. Common
Explanation:
A personal fall arrest system is the most common type of fall arrest in construction. Personal fall arrest systems are used as protection for OSHA workers who work on construction sites and are exposed to vertical drops of six feet or more. These systems consist of a body harness, anchorage and connector.
A baby is born with an extra chromosome in each of its cells. Which of the following is responsible for this condition?
A.Albinism
B.Mutations
C.Segregation
D.Gene therapy
Answers
(B) MUTATIONS ARE RESPONSIBLE FOR THIS
Answer:
Mutation is correct
Explanation:
People are able to hear footsteps because the sound made by a foot hitting the floor travels through the air to reach their ears. is this absorption or transmission
Answers
Answer: The correct answer is transmission.
Explanation:
Sound is a form of energy. The energy that survives the transfer is called the sound transmission. If the energy gets absorb then the sound is not heard to the listener. In this case, the absorption will occur.
People are able to hear footsteps because the sound made by a foot hitting the floor travels through the air to reach their ears. In this case, the sound transmission will occur as the footsteps can be heard. It means that the energy is transferred here.
Find the Voltage drop (in mV) across an 46.6 m long copper wire with diameter of 1.11 mm and with 47.6 miliAmps of current running through it. (The resistivity of copper at room temperature is 1.68×10-8 Ohm×meter). Express the answer (only numerical value) to the nearest whole number.
Answers
[tex]R= \frac{\rho L}{A} [/tex]
The diameter d of the wire is [tex]d=1.11 mm=1.11 \cdot 10^{-3} m[/tex], so the cross sectional area is
[tex]A=\pi ( \frac{d}{2} )^2=9.7 \cdot 10^{-7} m^2[/tex]
Now, using [tex]L=46.6 m[/tex] and [tex]\rho=1.68 \cdot 10^{-8} \Omega m[/tex], we can calculate the resistance:
[tex]R= \frac{\rho L}{A}= \frac{(1.68 \cdot 10^{-8} \Omega m)(46.6 m)}{9.7 \cdot 10^{-7}m^2} =0.807 \Omega [/tex]
And now we can calculate the voltage drop across the resistor, by using Ohm's law, since we know the current flowing through it: [tex]I=47.6 mA=47.6 \cdot 10^{-3} A[/tex]
[tex]V=IR=(47.6 \cdot 10^{-3} A)(0.807 \Omega)=0.038 V=38 mV[/tex]
Anna is conducting an experiment to determine how weather affects cell phone reception. She is trying to decide the best way to conduct her experiment in order to collect meaningful data. Which of the following experiments would help Anna collect the best data? A. Test different cell phones in different locations on days with clear weather. B. Test different cell phones in different locations on days with rainy weather. C. Test a cell phone's reception in one location with clear weather and in another location with rainy weather. D. Test a cell phone's reception in the exact same location under various atmospheric conditions.
Answers
Answer:
D. Test a cell phone's reception in the exact same location under various atmospheric conditions
Explanation:
Components of an experiment:
Independent variable:
A manipulated variable, in an experiment or study, whose presence or degree incurs a change in the dependent variable.
Dependent variable:
A variable which is being studied in the experiment and is supposed to change with respect to the independent variable.
Control variable:
Control variable includes the variables which are of no concern in the experiment and must be constant so that they do not interfere with the results of the experiment. Change in control variable might affect the results of an experiment.
In Anna's experiment, the independent variable is the atmospheric conditions. The dependent variable is cell phone reception that will change according to the atmospheric conditions. All other things related to the experiment are control variables like cellphone, location of the cell phone. Both of these must stay constant to collect the best data.
Hence, the best option is D.
Answer:
D. Test a cell phone's reception in the exact same location under various atmospheric conditions
Explanation:
You are the juror of a case involving a drunken driver whose 1041 kg sports car ran into a stationary 1928 kg station wagon stopped at a red traffic light. the cars stuck together and slid with locked wheels for 12.0 m before coming to rest. the coefficient of sliding friction on the dry road was 0.60. estimate the speed of the sports car when it hit the station wagon.
Answers
2. Find the acceleration due to friction:
F = m*a = μ * m * g => a = μ * g = 0.6 * 9.81
3. Find the time it took the two cars stuck together to slide 12m:
x = 0.5*a*t²
t = sqrt(2*x / a) = sqrt(2 * x / (μ * g) )
4. Find the initial velocity of the two cars:
v = a*t = μ * g * sqrt(2 * x / (μ * g) ) = sqrt( 2 * x * μ * g)
5. Use the initial velocity of the two cars combined to find the velocity of the sports car. Momentum must be conserved:
m₁ mass of sports car
v₁ velocity of sports car before the crash
m₂ mass of station wagon
v₂ velocity of station wagon before the crash = 0
v velocity after the crash
m₁*v₁ + m₂*v₂ = (m₁+m₂) * v = m₁*v₁
v₁ = (m₁+m₂) * v / m₁ = (m₁+m₂) * sqrt( 2 * x * μ * g) / m₁
v₁ = 33.9 m/s
Which term is used to describe water that is evaporated, polluted, or used by crops? A. degenerated B. consumptive C. controlled D. processed
Answers
Explanation:
"Consumptive use" is the term used in the field of Water Science to define "the part of water withdrawn that is evaporated, given off by plants, used by crops, consumed by humans or livestock, or otherwise removed from the immediate water environment. It is also referred as water consumed." Hence the correct answer is (b) Consumptive.
A child sitting 1.20 m from the center of a merry-go-round moves with a speed of 1.35 m/s. (a) calculate the centripetal acceleration of the child.
Answers
a = V² / r
Where V is the speed and r the radius of the circle (distance to the center)
a = (1.35 m/s)² / 1.2m = 1.519 m/s²
response to an unconditioned stimulus that occurs naturally without learning is known as a(n) __________ response.
A.
neutral
B.
conditioned
C.
reconditioned
D.
unconditioned
Answers
The response to an unconditioned stimulus that occurs naturally without learning and involuntarily triggers reaction is known as an unconditioned response. For example, you smell your favorite food while being cook may make you instantly feel hungry.
Answer:
the answer is c
Is the force that earth exerts on you larger, smaller, or the same as the force you exert on it?
Answers
if it's smaller then u will sink into the ground!
Which of the following occurs at the SLOWEST rate? A) deposition B) earthquake C) flood D) landslide
Answers
Because An Earthquake occurs rather quickly, same as a flood or a landslide.
Hope this has helped!
A dam is a structure built across a river to hold back the river's water. The flow of water through a dam is controlled by gates. When the gates are closed, water is held at a greater height than it would otherwise occupy.
The water has_________ energy when the gates are closed due to its height. This energy is transformed into _______energy when the gates open and the water begins to flow downward.
Answers
This should be correct
potential is the first one kinetic is the second
The chemical equation shown represents photosynthesis. Carbon dioxide plus A plus light with a right-pointing arrow towards B plus oxygen. The arrow has an x above it. What is the role of substance B in photosynthesis?
It stores chemical energy.
It converts light into chemical energy.
It traps light energy from the atmosphere.
It cools the atmosphere by changing into vapor.
Answers
Radioactive carbon, or C-14, is used to date fossil remains. When C-14 decays, as seen in the nuclear equation, it produces what nuclide of nitrogen? A) N-7 B) N-13 C) N-14 D) N-15
Answers
C-14 --> N-14 + e- + (ve)
where e- is an electron and (ve) is an electron-type antineutrino.
Basically, when the carbon nucleus (atomic number: 6, mass number: 14) decays, a neutron of the nucleus converts into a proton (therefore, the mass number remains the same, 14, but the atomic number increases by 1, therefore it becomes nitrogen) and releases an electron-antineutrino pair.
So, the correct answer is C), N-14.
Answer:
the answer is c
Explanation:
i did it on usatestprep
Your car burns gasoline as you drive up a large mountain. What energy transformation is the car performing?
Answers
Answer:
Explanation:
According to the conservation of energy, energy can neither be created nor be destroyed but can transform from one form to another.
The form of energy is converted into another form is called the transformation of energy.
Here, the chemical energy of the gasoline is converted into kinetic energy of the car.
How fast (in rpm) must a centrifuge rotate if a particle 6.00 cm from the axis of rotation is to experience an acceleration of 113000 g's? if the answer has 4 digits or more, enter it without commas,
e.g. 13500?
Answers
[tex]a=113000 g=113000 \cdot 9.81 m/s^2[/tex]
This corresponds to the centripetal acceleration of the motion, which is related to the angular speed [tex]\omega[/tex] of the particle and its distance r from the axis by the relationship
[tex]a= \omega ^2 r [/tex]
In our problem, [tex]r=6 cm=0.06 m[/tex], so we can solve for [tex]\omega[/tex]:
[tex]\omega = \sqrt{ \frac{a}{r} } = \sqrt{ \frac{113000 \cdot 9.81 m/s^2}{0.06 m} }=4298 rad/s [/tex]
However, we must convert it into rpm (revolution per minute).
We know that 1 rad corresponds to [tex]( \frac{1}{2 \pi} )[/tex] revolutions, while [tex]1 s = \frac{1}{60} min[/tex]. So we the conversion is[tex]\omega = 4298 rad/s \cdot ( \frac{1}{2\pi} rev/rad )( 60 s/min)=41067 rpm[/tex]
A motorist is traveling at 20 m/s. He is 60 m from a stoplight when he sees it turn yellow. Is reaction time, before stepping on the brake, is 0.50 s. What steady acceleration (slowing down) while braking will bring him to a stop right at the light?
Answers
V₀ = final velocity which is 0 m/s
V₁ = initial velocity which is 20 m/s
x = distance which is 60-(0.5 x 20) =50m
this is because his reaction time is 0.5 sec so he traveled 10m before stepping on the break paddle.
a= (V₀-V₁) / 2x
= (0-20) / 2*50
= -0.2m/s
the negative is because it is a deceleration speed hence it is 0.2m/s
Final answer:
A motorist traveling at 20 m/s and located 60 m from a yellow stoplight needs a steady deceleration of 4 m/s², after a reaction time of 0.50 s, to stop precisely at the light.
Explanation:
A motorist is traveling at 20 m/s and is 60 m from a stoplight when it turns yellow. The motorist's reaction time is 0.50 s before stepping on the brake. We need to calculate the steady acceleration (slowing down) required to stop the car right at the light.
First, calculate the distance covered during the reaction time. Since the car continues at its initial speed during the motorist's reaction time, the distance covered is:
D_{reaction} = v × t = 20 m/s × 0.50 s = 10 m
This means the remaining distance to be covered under deceleration is 60 m - 10 m = 50 m.
Next, we use the kinematic equation v^2 = u^2 + 2as, where
v = final velocity (0 m/s, since the car stops),
u = initial velocity (20 m/s),
a = acceleration,
s = distance covered under deceleration (50 m).
Rearranging the equation for a, we get:
a = (v^2 - u^2) / (2s) = (0^2 - 20^2) / (2 × 50) = -400 / 100 = -4 m/s².
Therefore, a steady deceleration of 4 m/s² would be necessary for the motorist to stop right at the stoplight.
Which memory system provides us with a very brief representation of all the stimuli present at a particular moment?
Answers
Your answer is the sensory memory.
Sensory memory is very short term. It retains your memory on the first impression and works with the five senses like see, taste, and sight, to keep the image in your mind after processed by stimuli.
Hope this helps!
In a hydraulic system, piston 1 has a surface area of 100 cm2, and piston 2 has a surface area of 900 cm2. A force of 150 N is exerted on piston 1 of the hydraulic lift. What force will be exerted on piston 2?
Answers
[tex]p_1 = p_2[/tex] (1)
The relationship between the pressure applied p, the force applied F and the surface A is
[tex]p= \frac{F}{A} [/tex]
So we can rewrite (1) as
[tex] \frac{F_1}{A_1}= \frac{F_2}{A_2} [/tex]
And from this, we can find the magnitude of the force exerted on piston 2, F2:
[tex]F_2 = A_2 \frac{F_1}{A_1}=(900 cm^2) \frac{150 N}{100 cm^2}=1350 N [/tex]
Water is to be pumped to the top of a building that is 366 m high. If the density of water is 1.00 x 10^3 kg/m^3, what amount of pressure is needed in the water line at the base of the building to raise the water to this height?
a.
1.26 x 10^6 Pa
b.
3.59 x 10^6 Pa
c.
5.39 x 10^6 Pa
d.
2.84 x 10^6 Pa
Answers
The gravitational potential energy at the top will be gh. where: h- height and g - acceleration due to gravity
Applying energy conservation principle which is P/d = ghTherefore, P = hgd = 366 * 9.8 * 1000 = 3586800 pascal or 3.59 x 10^6 Pa which is B.
If a boat and its riders have a mass of 900 kg and the boat drifts in at 1.4 m/s how much work does sam do to stop it?
Answers
[tex]K_i = \frac{1}{2} mv_i^2 = \frac{1}{2}(900 kg)(1.4 m/s)^2=882 J [/tex]
After Sam stops it, the final kinetic energy of the boat+rider is
[tex]K_f = 0 J[/tex]
because its final velocity is zero.
For the law of conservation of energy, the work done by Sam is the variation of kinetic energy of the system:
[tex]W=K_f-K_i =0-882 J=-882 J[/tex]
where the negative sign is due to the fact that the force Sam is applying goes against the direction of motion of the boat.
Sam does 1260 J of work to stop the boat.
The work done by Sam to stop the boat is equal to the change in kinetic energy of the boat.
Work = ΔKE
[tex]Work = KE_f - KE_i\\\\\\Work = 0 - \dfrac{1}{2}mv_i^2\\\\Work = -\dfrac{1}{2}(900 kg)(1.4 m/s)^2\\\\\\Work = -1260 J[/tex]
The negative sign indicates that the work is done by the boat on Sam.
We know that the mass of the boat and its riders is 900 kg. We also know that the initial velocity of the boat is 1.4 m/s. The final velocity of the boat is 0 m/s, since the boat stops. We can use the equation for kinetic energy to calculate the change in kinetic energy of the boat. The change in kinetic energy is equal to the work done by Sam to stop the boat. The work done by Sam is equal to -1260 J.
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