A company did a quality check on all the packs of nuts it manufactured. Each pack of nuts is targeted to weigh 18.25 oz. A pack must weigh within 0.36 oz of the target weight to be accepted. Find the absolute value inequality that describes the situation and solve it to find the range of rejected masses, x. |x − 18.25| > 0.36; x < 17.89 or x > 18.61 |x − 0.36| + 18.25 > 0; x < 17.89 or x > 18.61 |x − 18.25| > 0.36; x < 18.25 or x > 18.61 |x − 0.36| + 18.25 > 0; x < 18.25 or x > 18.61

The answer would be 8/35

log₅125 = c

[tex]125 = 5^{c}[/tex]

[tex]5^{3} = 5^{c}[/tex]

3 = c

Answer:

log₅125 = c

Step-by-step explanation:

Answer: D) 40%

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Work Shown:

Area of purple rectangle (ignore circular cutout for now) = base*height = 6*12 = 72

I'm assuming the center of the circle is located on the right edge of the purple rectangle. If so, then we can subtract off half the circle's area from the purple rectangle area

Semicircle Area = (pi*r^2)/2 = (pi*3^2)/2 = 14.1371669

Area of purple region = (Rectangle Area) - (Semicircle Area)

Area of purple region = 72-14.1371669

Area of purple region = 57.8628331

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Now divide this area by 144 as this is the total area of the entire largest square (12 by 12 square) to get 57.8628331/144 = 0.401825 which is approximate. This rounds to 0.40 and converts to 40% which explains how I got choice D as the answer

Answer:

That probability is approx. 40%.  See below.

Step-by-step explanation:

That probability is the area of the purple section divided by the total area of the square before coloring purple.

This area of the square is (12 cm)^2, or 144 cm^2.  

Half the area of the circle is pi*(3 cm)^2, or 9*pi cm^2.

Thus, the purple area is (144 cm^2) / 2  - (9/2)*pi cm^2, or (72 - 9*pi/2) cm^2.  This is approx. 57.86.

The ratio of this purple area to the full area of the square is:

57.86 cm^2

--------------------------------- = 0.4 (approximately)

144 cm^2

Answer:

The Coordinate of the vertices of Parallelogram RSTU are R(0,0), S(2,3),T(6,3) and U (4,0).

we have to find the vertices of a point which cuts the side of parallelogram ST  .It is given that line y = x passes through R.

Suppose that it cuts the side ST at M (p,q).

Equation of line passing through T(6,3)and S (2,3) is

[tex]\frac{y-3}{x-2}= \frac{3-3}{6-3}\\\frac{y-3}{x-2} = 0\\y- 3=0[/tex]

it passes through (p,q)∴

∴ q -3 =0     ...........(1)

Line y=x passes through (p,q).

p -q=0

p=q

Equation (1) becomes

p= q=3

So the line y =x cuts TU at M (3,3).

Divide 8 with 1/4

(8)/(1/4)

Flip the second fraction, and change the division into multiplication, then solve

(8)/(1/4) = 8 x 4 = 32

32 is your answer

hope this helps

the answer is 32.  you just divide 8 by 1/4 and you should get 32.

Answer:

1.3x+9

2.1x+4

3.3x+1

Step-by-step explanation:

Area = Base x height:

area =  3 1/2 x 3/4 = 2 5/8 sq. ft.

The answer is the 2nd one.

The answer would be the second one or 2 5/8 sq ft hope that helps

Express everything in US$:

US$: $19

Hong Kong: 150 / 8 = $18.75

SAR: 130/7=$18.57

Euro: 14/0.7=$20

Best price is in SA rand.

Answer:

South African rand

Step-by-step explanation:

Answer:

B) The two functions have the same initial value.

Step-by-step explanation:

Every year there are 14 more ducks. The starting point would be 50 and the equation is:

d = 14*year+50

42,429 rounded to the nearest hundred is 42,400.

42,429 rounded to the nearest hundred is 42,400, as the tens digit (2) is less than 5, so we round down.

The question is asking to round the number 42,429 to the nearest hundred. To do this, we look at the tens place, which is 2. If the tens digit is 4 or lower, we round down; if it is 5 or higher, we round up. In this case, the digit is lower than 5, so we round down. Thus, 42,429 rounded to the nearest hundred is 42,400.

The values of x and y is 2 and 17 respectively.

We need to find the value of x and y.

A parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

Now, x+2=4

⇒x=2

y-5=12

⇒y=17

Therefore, the values of x and y is 2 and 17 respectively.

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Answer: Part A = (100% - 80%)P = 35, Part B = 140

Step-by-step explanation:

Percentage:  Like + Don't like = 100%

                     80%  + Don't like = 100%

                   -80%                         -80%

                                  Don't like = 20%

People: 20% of Patrons = Don't Like

             0.20  x Patrons = 35

          ÷ 0.20                   ÷ 0.20    

                           Patrons = 175

Now, let's write the equation we used to get that answer:

Let P represent the total number of patrons, then the equation is:

 (100% - 80%)P = 35

= (1.00 - 0.80)P = 35

=       0.20P     = 35

 =             P      = 175

Part B:  

80% of Patrons = Like

0.80  x    175      = Like

         140            = Like

The best estimate of r on the scatter plot  is (b) -0.65

From the question, we have the following parameters that can be used in our computation:

The image of the scatter plot

On the scatter plot, we can see that

The points roughly appear to be on a straight line

Also, we can see that

As the x values increases the y values decreases

This represents a [negative linear] association

Because of the rough relationship, the closest estimate is (b) -0.65

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Answer:

Yes, thirty six and nine thousandths is greater than four tenths

Step-by-step explanation:

Thirty six and nine thousandths greater then four tens

Thirty six is 36

nine thousandths  is 9 times 1/1000 is equal to 0.009

Thirty six and nine thousandths =[tex]36+0.009= 36.009[/tex]

four tenths is 4 times 1/10 is equal to 0.4

now we compare 36.009 and 0.4

36 is greater than 0.4

So, 36.009 is greater than 0.4

Yes, thirty six and nine thousandths is greater than four tenths

​(x²-y²)² + (2xy)² = (x²+y²)²

Find the missing x- and y-values and Pythagorean triples using the identity given

A Pythagorean triple consists of three positive integers a, b, and c, that satisfy the equation from the Pythagorean theorem, thus, a² + b² = c², such triple is commonly written (a,b,c).​

​We are given the equation : (x²-y²)² + (2xy)² = (x²+y²)² since this, we have :

​a = (x²-y²)

​b = (2xy)

​c = (x²+y²)

​Question 1)

X Value = 4​

​Y Value = 3

​Pythagorean triples: ?

We can replace the values of x and y, to determine a, b and c.​

​a = (x²-y²) = (4²-3²) = 16-9 = 7

​b = (2xy) = (2*4*3) = 24

c = (x²+y²) = (4²+3²) = 16+9 = 25​

​Answer 1 : Pythagorean triples : (7,24,25)

Question 2) ​

​X Value = 5

Y Value = ?​

Pythagorean Triples: (9,40,41)​

​Now we have a, b, and c, to determine Y

​b = (2xy) = 40

Y = 40/2x = 40/2*5 = 40/10 = 4​

Answer 2 : Y = 4​

​Question 3)

X Value = ?​

Y Value = 3​

Pythagorean Triples: (27,36,45)​

Now we have a, b, and c, to determine X​

b = (2xy) = 36​

​X = 36/2y = 36/2*3 = 36/6 = 6

​Answer 3 : X = 6

Question 4)​

​X Value = 7

Y Value = 5​

​Pythagorean Triples: ?

We can replace the values of x and y, to determine a, b and c.​

a = (x²-y²) = (7²-5²) = 49-25 = 24​

b = (2xy) = (2*7*5) = 70​

c = (x²+y²) = (7²+5²) = 49+25 = 74​

Answer 4 : Pythagorean triples : (24,70,74)​

Hope this helps!​​​​​

​[tex]\textit{\textbf{Spymore}}[/tex]​​​​​​​

By using the given identity and substituting known values of x and y, we can find missing x or y values and compute the Pythagorean triples. For instance, when x=4 and y=3, the Pythagorean triple is (7,24,25). Similarly, we can find missing triples or variables for other sets.

This question pertains to the topic of Pythagorean triples and their relationship with a given identity. A Pythagorean triple consists of three positive integers (a, b, c), such that a2 + b2 = c2. Inserting known values of x and y into the identity provided can help us find the Pythagorean triples.

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Answer:

so what’s the answer

Step-by-step explanation:

The slope formula:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (4, 9) and (6, 1).

Substitute

[tex]m=\dfrac{1-9}{6-4}=\dfrac{-8}{2}=-4[/tex]

Answer : 167 milliliters of the 10% solution and 333 milliliters of 4% solution

A laboratory employee is mixing a 10% saline solution with 4% saline solution. How much of each solution is needed to make 500 milliliters of a 6% solution.

Let x represent the milliliters  of 10% saline solution  

Total ml of solution is 500 ml

so 500-x represents the milliliters of 4% saline solution

The equation becomes

ml of 10% solution + ml of 4% solution = 500ml of 6%

10x  + 4(500-x) = 500 * 6

10x + 2000 - 4x = 3000

6x + 2000 = 3000

Subtract 2000 on both sides

6x = 1000

so x= 166.666... Hence x = 167 ml

So 167 ml is mixed with 10% of saline solution

500-x represents the milliliters  of 4% saline solution

Replace x with 167

500 - 167 = 333 milliliters  of 4% saline solution

So answer is  

167 milliliters of the 10% solution and 333 milliliters of 4% solution

It's not possible to determine if Grafton's data collection was fair or not based on the provided information, as the question lacks details like the size of the sample used and where the sample was taken from. Accurate and representative data collection is a critical part of conducting a study.

Based on the data provided in the question, it's not possible to say whether Grafton picked the data fairly or not. The principles of statistics tell us that for data to be considered fair, it must be representative of the population being studied. In the context of the question, this means that for the data to be considered fair, it must accurately represent the car owning population. The question, however, does not provide enough information for us to make this determination.

For example, we don't know the sample size that Grafton used, where the sample was taken from, or any information about the population the data is supposed to represent. Without this additional data, we cannot determine if the data collection was biased or not. Remember, data collection is a crucial part of conducting a valid study and it's important to ensure that the sample used is unbiased and representative of the whole population.

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Answer:

B

Step-by-step explanation:

Therefore a geometric figure labeled CD would be a segment and the correct answer is B)

[tex]-7(3x-7)+21x\geq50\qquad|\text{use distributive property}\\\\(-7)(3x)+(-7)(-7)+21x\geq50\\\\-21x+49+21x\geq50\\\\(-21x+21x)+49\geq50\\\\49\geq50\ FALSE\\\\Answer:\ \text{a - no solution}[/tex]

Answer: Ruhana and her team should refurbish 15 tv sets and 20 dvd players each week to minimize the cost.

Step-by-step explanation:

For the given situation let the number of tv sets be x and number of dvd players be y.

Now we have to minimize the cost as it costs $75 to refurbish a tv set and $40 to refurbish a dvd player.

i.e. Minimize z=75x+40y

it gives subject to the constraints

4x+2y≥100......(1)(100 hours each week. It takes 4 hours to refurbish a tv set and 2 hours to refurbish a dvd player.)

x+y≥35.......(2)(weekly sales target is to refurbish at least 35 tv sets or dvd players.)

To plot equation (1) we need to find coordinates of points lying on line (1)

put x=0 gives 2y=100⇒y=50

put y=0 gives 4x=100⇒x=25

So we got points (0,50) and(25,0) for (1)..............(3)

Similarly for equation (2)

put x=0 gives y=35

put y=0 gives x=35

So we got points (0,35) and(35,0) for (2).................(4)

with the help of (3) and (4) we plot the following graph (assume x≥0 and y≥0)

The unbounded feasible region determined by constraints gives the corner points as A(0,50),B(15,20)and C(35,0).

from  we get the value of z is minimum at point B (15,20) .

hence we got our optimal solution at B (15,20), where x is the number of tv sets and y is the number of dvd players  .

therefore Ruhana and her team should refurbish 15 tv sets and 20 dvd players each week to minimize the cost.

Answer: Look at photo

Step-by-step explanation:

Answer: [tex]a^{2} = \frac{16}{625}[/tex]

Step-by-step explanation:

[tex]a = (\frac{2}{5})^{2}[/tex] ÷ [tex](\frac{9}{5})^{0}[/tex]

[tex]a = (\frac{2}{5})^{2}[/tex] ÷ 1

[tex]a = (\frac{2}{5})^{2}[/tex]

[tex](a)^{2} = ((\frac{2}{5})^{2})^{2}[/tex]

[tex]a^{2} = (\frac{2}{5})^{4}[/tex]

[tex]a^{2} = \frac{2^{4}}{5^{4}}[/tex]

[tex]a^{2} = \frac{16}{625}[/tex]

Please find attached photograph for your answer.

[tex]H-F=\left[\begin{array}{ccc}198&201\\176&172\\256&267\end{array}\right]-\left[\begin{array}{ccc}234&245\\198&187\\312&345\end{array}\right]\\\\=\left[\begin{array}{ccc}198-234&201-245\\176-198&172-187\\256-312&267-345\end{array}\right]\\\\=\left[\begin{array}{ccc}-36&-44\\-22&-15\\-56&-78\end{array}\right]\\\\Answer:\ \boxed{A}[/tex]

Step 1. Subtract 3 from both sides

2|7x - 4| = 51 - 3

Step 2. Simplify 51 - 3 to 48

2|7x - 4| = 48

Step 3. Divide both sides by 2

|7x - 4| = 48/2

Step 4. Simplify 48/2 to 24

|7x - 4| = 24

Step 5 Break down the problem into these 2 equations

7x - 4 = 24

-(7x - 4) = 24

Step 6. Solve the 1st equation: 7x - 4 = 24

x = 4

Step 7. Solve the 2nd equation: -(7x - 4) = 24

x = -20/7

Step 8. Collect all solutions

x = -20/7,4

The answer is C.

Answer:

B because eaxh section either repeats itself or is close to repeating its previous part

Step-by-step explanation:

the answer is 20 HOPE THIS HELPS lol

Answer:the answer is 20