A dam is a structure built across a river to hold back the river's water. The flow of water through a dam is controlled by gates. When the gates are closed, water is held at a greater height than it would otherwise occupy.

The water has_________ energy when the gates are closed due to its height. This energy is transformed into _______energy when the gates open and the water begins to flow downward.

Answers

Answer 1
Potential is the first blank and kinetic is the second blank. 

This should be correct
Answer 2

potential is the first one kinetic is the second


Related Questions

How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v? express your answer both in joules and electron volts?

Answers

The work done by the electric field in moving a proton from +125V to -55V is -expressed as -180 electron volts (eV).

Using the relationship between work (W), charge (q), and electric potential difference (V).

The charge of a proton is +1.602 × 10^-19 coulombs (elementary charge, e), and the potential difference
V is the final potential minus the initial potential.

So, we compute the potential difference first:

V = V_final - V_initial = (-55V) - (+125V) = -180V

Then, we calculate the work done:

W = q
V = (1.602
10^-19 C)
(-180 V) = -2.8836
10^-17 joules

The negative sign indicates that the electric field is doing work against the electric potential. To express the work in electron volts, remember that 1 eV = 1.602
10^-19 joules:

W (in eV) = W (in joules) / (1.602
10^-19 joules/eV)
= (-2.8836
10^-17 joules) / (1.602
10^-19 joules/eV) = -180 eV

Which type of simple machine is pictured here?
1. wedge
2. inclined plane
3. lever
4. wheel and axel

THANK YOU I NEED THIS DONE BY 10:30 2/23/2018

Answers

Answer: This thing is a lever

Explanation: There isn't a picture, but I took the K12 class, so yeah

Final answer:

The simple machine with a rod fixed to the center of a wheel is a wheel and axle, which is a type of lever used to multiply applied force.

Explanation:

The simple machine pictured that consists of a rod fixed to the center of a wheel is known as a wheel and axle. This device is actually a form of lever where the force applied to the wheel results in a greater force being applied to the axle. It exemplifies how simple machines can be used to multiply or augment a force that we apply. The mechanical advantage is calculated by dividing the radius of the wheel by the radius of the axle.

The use of air bags in cars reduces the force of impact by a factor of 110.(The resulting force is only as great.) What can be said about how the airbag changed the duration of the collision?

Answers

The variation of momentum (= the impulse) of the car during the impact is
[tex]\Delta p = F \Delta t[/tex]
[tex]\Delta p [/tex] does not change whether the car has an airbag or not, because 
[tex]\Delta p = m\Delta v[/tex]
and 1) the mass of the car is always the same 2) the change in velocity of the car is always the same,

so if [tex]\Delta p[/tex] is constant and F is reduced by a factor 110, then [tex]\Delta t[/tex] (the duration of the collision) must be increased by a factor 110 with the airbag.

the answer is C. it increases by a factor of 110, i got 100 on the test

I need help with this asap please

A water wave vibrates up and down four times each second, the distance between two successive crests is 5 meters, and the height from the lowest part to the highest part of the wave is 2 meters.
a. What is the frequency of the wave in hertz?
b. What is the period of the wave in seconds?
c. What is the speed of the wave in meters per seconds?
d. What is the amplitude of the wave in meters?

Answers

ITs c because its looking for how fast it goes or how far it goes 
Final answer:

The frequency of the wave is 4 Hz, the period is 1/4 seconds, the speed is 20 m/s, and the amplitude is 2 meters.

Explanation:

a. The frequency of the wave can be calculated by counting the number of complete vibrations in one second. In this case, the wave vibrates up and down four times each second, so the frequency is 4 Hz.

b. The period of the wave is the time it takes for one complete vibration. It can be calculated by taking the reciprocal of the frequency. In this case, the period is 1/4 seconds.

c. The speed of the wave can be determined by multiplying the frequency by the wavelength. Since the distance between two successive crests is 5 meters, the speed of the wave is 20 m/s.

d. The amplitude of the wave is the height from the lowest part to the highest part of the wave. In this case, the amplitude is 2 meters.

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Determine the tension developed in the cable ab required to support the traffic light, which has a mass of 19 kg . take h = 3.5 m.

Answers

Final answer:

The tension in the cable AB required to support the traffic light with a mass of 19 kg is equal to the weight of the traffic light, calculated as 186.2 N by multiplying the mass by the acceleration due to gravity.

Explanation:

To determine the tension in the cable AB required to support the traffic light with a mass of 19 kg, we need to use the concept that the tension must balance the weight of the traffic light. Since the traffic light is in equilibrium (not moving), the net force acting on it must be zero.

The weight of the traffic light (W) can be calculated using the formula W = m × g, where m is the mass of the traffic light and g is the acceleration due to gravity (which is approximately 9.8 m/s2 on the surface of the Earth).

Calculating the weight: W = 19 kg × 9.8 m/s2 = 186.2 N.

Now, since we are dealing with a situation where only one cable is mentioned and there are no angles provided, we assume the cable is vertical, and therefore, the tension in cable AB is simply the weight of the traffic light, which is 186.2 N.

A 616 g block is released from rest at height h0 above a vertical spring with spring constant k = 540 n/m and negligible mass. the block sticks to the spring and momentarily stops after compressing the spring 23.3 cm. how much work is done (a) by the block on the spring and (b) by the spring on the block? (c) what is the value of h0? (d) if the block were released from height 2h0 above the spring, what would be the maximum compression of the spring?

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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​ ampere. What is the resistance of the radio A radio operating at 3.0 volts and a constant temperature draws a current of 1.8 x 10​ -4​ circuit?

Answers

The resistance of the radio circuit is 16.7 kΩ.

To calculate the resistance of the radio circuit when it operates at 3.0 volts and draws a current of 1.8 x 10-4 amperes, we can use Ohm's Law, which states that Resistance (R) equals Voltage (V) divided by Current (I), or R = V/I. Plugging in the given values, R = 3.0 V / (1.8 x 10-4 A), we find that the resistance is approximately 16,666.67 Ω, or 16.7 kΩ when rounded to three significant digits. When dealing with electrical circuits, it is important to understand concepts like resistance, voltage, and current, as they are fundamental to analyzing and predicting the behavior of the circuit.

what is the definition of work when net force is parallel to the distance?

Answers

Work in general is given by W=F·d where F is the force vector and d is the displacement vector.  The dot symbol is the dot product which is a measure of how parallel two vectors are.  It can be replaced by the cosine of the angle between the two vectors and the vectors replaced by their magnitudes.  If F and d are parallel then the angle is zero and the cosine is unity.  So in this case work can be defined as the product of the magnitudes of the force and distance:
W=Fd

A ferris wheel of radius r speeds up with angular acceleration α starting from rest. part a find an expression for the velocity of a rider after the ferris wheel has rotated through angle δθ.

Answers

The expression for the angular acceleration is:
[tex]\alpha = \frac{\Delta \omega}{\Delta t} [/tex]
where [tex]\Delta \omega = \omega-\omega _0[/tex] is the variation of the angular velocity, with [tex]\omega _0[/tex] being the starting velocity (which in our problem is zero), and [tex]\Delta t[/tex] being the time interval. So we can write the angular velocity after an angle [tex]\delta \theta[/tex] as
[tex]\omega (\delta \theta) = \alpha \Delta t[/tex]
We also know the relationship between tangential velocity, v, and the angular velocity v:
[tex]v=\omega r[/tex]
with r being the radius of the wheel. Substituting [tex]\omega[/tex] into the previous equation, we can write an expression for v:
[tex]v(\delta \theta )= \alpha r \Delta t [/tex]

The expression for the velocity of a rider on the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex] is given by:

[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]

To find the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex], we can use kinematic equations for rotational motion.

The kinematic equation relating angular displacement [tex](\( \delta \theta \))[/tex], initial angular velocity [tex](\( \omega_0 \))[/tex], angular acceleration [tex](\( \alpha \))[/tex], and time [tex](\( t \))[/tex] is:

[tex]\[ \delta \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \][/tex]

Since the Ferris wheel starts from rest, [tex]\( \omega_0 = 0 \)[/tex], so the equation simplifies to:

[tex]\[ \delta \theta = \frac{1}{2} \alpha t^2 \][/tex]

We're interested in finding the angular velocity [tex](\( \omega \))[/tex] after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex]. To find [tex]\( \omega \)[/tex], we can use the kinematic equation relating angular displacement, initial angular velocity, angular acceleration, and final angular velocity:

[tex]\[ \omega^2 = \omega_0^2 + 2 \alpha \delta \theta \][/tex]

Since [tex]\( \omega_0 = 0 \)[/tex], this equation simplifies to:

[tex]\[ \omega^2 = 2 \alpha \delta \theta \][/tex]

Taking the square root of both sides:

[tex]\[ \omega = \sqrt{2 \alpha \delta \theta} \][/tex]

This gives us the angular velocity of the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex].

However, to find the velocity of a rider at a particular point on the Ferris wheel, we need to convert this angular velocity to linear velocity. The linear velocity [tex](\( v \))[/tex] is related to the angular velocity [tex](\( \omega \))[/tex] by the equation:

[tex]\[ v = r \omega \][/tex]

Where:

- v is the linear velocity.

- r is the radius of the Ferris wheel.

So, substituting the expression for [tex]\( \omega \)[/tex] into this equation:

[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]

This is the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex].

A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s.(a) find the vector position of the particle at any time t (where t is measured in seconds).

Answers

Final answer:

To find the vector position of the particle at any time t, use the kinematic equation r(t) = r0 + vit + 0.5at2. Plug in the values for the initial velocity and acceleration to get the position function.

Explanation:

Given that at time t, the particle has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector vi = 9.00î m/s, we can find the vector position of the particle at any time t using the kinematic equations.

The position function is given by:

r(t) = r0 + vit + 0.5at2

Plugging in the values, we have:

r(t) = 0 + (9.00î m/s)(t) + 0.5(2.00ĵ m/s2)(t2)

So, the vector position of the particle at any time t is r(t) = 9.00tî + t2ĵ - t2 km.

After walking across a carpeted floor in socks, Jim brings his finger near a metal doorknob and receives a shock. what does that demonstrate

Answers

static electricity, And a human completing a circuit. 

Electric forces can act at a distance


A proton beam in an accelerator carries a current of 130 μa. if the beam is incident on a target, how many protons strike the target in a period of 17.0 s?

Answers

The current intensity is the product between the total charge that flows through a certain point (in our case, the target) in a time interval [tex]\delta t[/tex]:
[tex]I= \frac{Q}{\Delta t} [/tex]
We know the current, [tex]I=130 \mu A=130 \cdot 10^{-6} A[/tex], and the time interval, [tex]\Delta t=17 s[/tex], so we can find the total charge:
[tex]Q=I \Delta t= 2.21 \cdot 10^{-3}C [/tex]

The total charge Q is the product between the number of protons N and the charge of each protons, e, which is [tex]e=1.6 \cdot 10^{-19}C[/tex]:
[tex]Q=Ne[/tex]
we can  re-write the equation solving for N, so we can find the number of protons striking the target in 17 s:
[tex]N= \frac{Q}{e}= \frac{2.21 \cdot 10^{-3}C}{1.6 \cdot 10^{-19}C} =1.38 \cdot 10^{16} [/tex]

Final answer:

Using the formula relating current, charge, and time, approximately 1.38 × 10^16 protons strike a target when 130 μA of current is directed at the target for 17.0 seconds.

Explanation:

To determine how many protons strike the target in 17.0 seconds with a current of 130 μA (microamperes), we must understand the relationship between electric current, charge, and the quantity of charged particles. Current (I) is defined as the amount of charge (Q) passing through a point in a circuit per unit of time (t), mathematically described by the equation I = Q/t. Given that each proton carries a charge of approximately 1.6 × 10-19 C (coulombs), we can find the total charge that strikes the target over 17.0 seconds and subsequently calculate the number of protons involved.

First, convert the current from microamperes to amperes: 130 μA = 130 × 10-6 A. Then, use I = Q/t to find the total charge Q: Q = I × t = (130 × 10-6 A) × 17.0 s = 2.21 × 10-3 C. Finally, calculate the number of protons by dividing the total charge by the charge of a single proton: Number of protons = Q / charge of one proton = (2.21 × 10-3 C) / (1.6 × 10-19 C/proton) ≈ 1.38 × 1016 protons.

Therefore, approximately 1.38 × 1016 protons strike the target in a period of 17.0 seconds.

A ball is tossed from an upper-story window of a building. the ball is given an initial velocity of 7.90 m/s at an angle of 18.0° below the horizontal. it strikes the ground 4.00 s later. (a) how far horizontally from the base of the building does the ball strike the ground? 30.04 correct: your answer is correct. m (b) find the height from which the ball was thrown. incorrect: your answer is incorrect. work only with the vertical components of these quantities. this part of the problem is then a 1-dimensional free-fall example. m (c) how long does it take the ball to reach a point 10.0 m below the level of launching? s

Answers

In order to solve the problem, let's write the equations of motion first. Let's take the x-axis as the horizontal direction, and the y-axis on the vertical direction (pointing downward). Calling [tex]v_0=7.9 m/s[/tex] the initial velocity, and [tex]\alpha=18^{\circ}[/tex] the angle below the horizontal, the equations of motion are
[tex]S_x(t)=v_0 cos (\alpha )t[/tex]
[tex]S_y(t)=v_0 sin (\alpha ) t+ \frac{1}{2}gt^2 [/tex] 
where [tex]g=9.81 m/s^2[/tex] is the gravitational acceleration.

(a) To find the distance covered by the ball horizontally, we must simply calculate Sx at the time the ball hits the ground (t=4.0 s):
[tex]S_x(4.0s)= 7.9 m/s \cdot cos (18^{\circ}) \cdot 4.0s=30.05 m[/tex]

(b) The height from which the ball was thrown is the value of Sy at 4.0s, which is the distance covered by the ball before hitting the ground:
[tex]S_y(4.0 s)=7.9 m/s \cdot sin(18^{\circ}) \cdot 4.0s + \frac{1}{2}(9.81 m/s^2)(4.0s)^2=88.24 m [/tex]

(c) To calculate how long does it take to the ball to reach 10.0 m below the initial point, we have to find the time at which Sy(t)=10.0 m. This means we must solve the following equation:
[tex]10.0m = v_0 sin (\alpha ) t + \frac{1}{2} gt^2 [/tex]
Using the data of the problem, we can solve this equation. We find two solutions for t: one is negative, so we can neglect it. The second one, which is the solution of the problem, is t=1.19 s.

A uniform rod XY of weight 10.0N is freely hinged to a wall at X. It is held horizontal by a force F acting from Y at an angle 30° to the horizontal, as shown.

What is the value of F? 
A- 5.0 N B- 8.7cm C- 10.0cm D-20.0cm

Answers

I think the answer is A or B

What does the Energy Independence and Security Act of 2007 mandate? A. more use of fossil fuels
B. more use of heavy cars
C. more fuel efficient cars

Answers

Answer: C

 

The Energy Independence and Security Act of 2007 mandates the use of more fuel efficient cars where car manufacturers are required to boost fleet wide gas mileage to 35 mp (14.8 km/l) by 2020 in order to help reduce petroleum consumption. It encourages the increase in fuel economy standards for passenger cars. Thus, promote production of fuel-efficient vehicles.  Additionally, the act also support the use of electric transportation technology. 

The answer is C. more fuel efficient car.s

Maglev trains, like the one shown in the picture, use magnet fields to travel up to 600 miles per hour. Magnets on the bottom of the train and on the tops of the rails have similar magnetic poles. Based on properties of magnets, how do these magnets affect the train?

Answers

They cause the levitation of the train.
In fact, magnets with same polarity repel each other. So, the magnets on the tops of the rails repel the magnets on the botton of the train: this repulsive force is strong enough to win the weight of the train, and the train levitates in air. As a consequence, the frictional forces acting on the train are very small compared to the forces experienced by normal trains (that should win the frictional forces of the railway), and therefore this Maglev train can reach a huge speed.

the 2 magnetic fields repel eachother

Two identical charges are separated by a distance d. If the distance between them is increased to 3d, what will happen to the force of repulsion between them? A) It will be one-ninth the original force. B) It will be one-third the original force. C) It will be nine times the original force. D) It will be three times the original force.

Answers

Answer:

A

Explanation:

If the distance between them is increased to 3d then the force of repulsion between them is,  It will be one-ninth the original force

What is electric force ?

The force of repulsion between two identical charges is given by Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:

F = k x (q₁ x q₂) / d²

where F is the force of repulsion, q₁ and q₂ are the magnitudes of the charges, d is the distance between the charges, and k is the Coulomb constant.

When the distance between the charges is increased to 3d,

the force of repulsion will decrease,

since the denominator in the above equation will increase.

Specifically, the force will become one-ninth the original force, since the square of 3 is 9.

So the answer to the question is (A) It will be one-ninth the original force.

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The absolute pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa. At what depth does this pressure occur? Assume that atmospheric pressure is 1.01 x 10^5 Pa. and the density of the water is 1.00 x 10^3 kg/m^3

Answers

The general formula for absolute pressure is:

[tex] P_{total} = P_{atm} + (rgh)[/tex]

Where: [tex] P_{total} [/tex] = Absolute pressure
             [tex] P_{atm} [/tex]  = atmospheric pressure
             r = density
             g = [tex] 9.8 \frac{m}{{s^2}} [/tex]
             h = depth

We can use this formula to derive our formula for h:

[tex] P_{total} = P_{atm} + (rgh)[/tex]      transpose atmospheric pressure
[tex] P_{total} - P_{atm} [/tex] =  [tex](rgh)[/tex]     transpose r and g

[tex] P_{total} [/tex] - [tex] P_{atm} [/tex]
-------------------------      = h
         rg

Now let us input our given into our new formula:

3.52 x  [tex] 10^{5}[/tex] - 1.01 x [tex] 10^{5}[/tex]
----------------------------------------              = h
1.00 x [tex] 10^{3} [/tex] x 9.8 [tex] \frac{m}{ s^{2} } [/tex]   

[tex] \frac{2.51 x {10^5}}{9.8 x {10^3} \frac{m}{s^2}} = h [/tex]

[tex] 25.61 m = h [/tex]



Final answer:

The depth at which the pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa is 24.29 meters.

Explanation:

The depth at which the pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa can be calculated using the formula:

Pressure = atmospheric pressure + density of water * gravitational acceleration * depth

In this case, the atmospheric pressure is 1.01 x 10^5 Pa, the density of water is 1.00 x 10^3 kg/m^3, and the gravitational acceleration is 9.8 m/s^2. We can rearrange the equation to solve for depth:

Depth = (pressure - atmospheric pressure) / (density of water * gravitational acceleration)

Plugging in the values, we get:

Depth = (3.51 x 10^5 Pa - 1.01 x 10^5 Pa) / (1.00 x 10^3 kg/m^3 * 9.8 m/s^2)

Depth = 24.29 meters

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The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the table (as shown). the winner of the competition wants to know if he has broken the world record for the break shot of 32 mph (about 14.3 m/s). if the winner\'s ball landed a distance 4.65 m from the table edge, calculate his break shot speed.

Answers

Compute first for the vertical motion, the formula is:

y = gt²/2 

0.810 m = (9.81 m/s²)(t)²/2 

t = 0.4064 s 


whereas the horizontal motion is computed by: 

x = (vx)t 

4.65 m = (vx)(0.4064 s) 

4.65 m/ 0.4064s = (vx)

(vx) = 11.44 m / s
So look for the final vertical speed. 

(vy) = gt 

(vy) = (9.81 m/s²)(0.4064 s) 

(vy) = 3.99 m/s 


speed with which it hit the ground: 

v = sqrt[(vx)² + (vy)²] 

v = sqrt[(11.44 m/s)² + (3.99 m/s)²] 

v = 12.12 m / s

You make a u turn in your car, what provides the centripetal force on the car and on you

Answers

Newton's first and third laws

The correct answer is the frictional force.


In fact, the centripetal force is the force that keeps the car in circular motion, and it points toward the centre of the circular trajectory. The frictional force between the tyres of the car and the road provides the centripetal force that keeps the car in the turn: in fact, without the friction (e.g. on an icy road), the car would not be able to make the turn at the same speed.

A monatomic ideal gas expands slowly to twice its original volume, doing 370 j of work in the process. part a find the heat added to the gas if the process is isothermal.

Answers

The first law of thermodynamics says that the variation of internal energy [tex]\Delta U[/tex] of a gas is equal to the amount of heat Q supplied to the gas minus the work W done by the gas:
[tex]\Delta U = Q-W[/tex]

The variation of internal energy of a gas is:
[tex]\Delta U = \frac{3}{2} n R \Delta T [/tex]
As it can be seen, it depends only on the variation of temperature [tex]\Delta T[/tex]. Since for an isothermal process [tex]\Delta T=0[/tex], then [tex]\Delta U=0[/tex]. This means that the first law of thermodynamics becomes
[tex]Q=W[/tex]
and since the work done is 370 J, then the amount of heat is also 370 J: [tex]Q=370 J[/tex].

In the process of nuclear fusion, large amounts of energy, at temperatures of approximately 120 million Kelvin, are required to join two nuclei into a single, heavier nucleus. Why does the process of fusion require so much energy in order to take place?

Answers

The reason for this huge amount of energy is that the nuclear fusion requires two nuclei to come close enough to be within the range of the strong nuclear interaction, which is responsible for the fusion. But in order to come so close, the two nuclei have to overcome the electrostatic repulsion between them, which becomes stronger as they get closer. In fact, considering two nuclei of hydrogen (two protons), the barrier that  they have to overcome to reach a distance r is equal to the electric potential energy:
[tex]U=k \frac{q^2}{r} [/tex]
And since the range of the nuclear strong interaction is very short, r must be very small, and so the amount of energy required U can be huge.

Which phrase best describes matter? A. Matter is made of atoms and is too small to see. B. Matter is solid and heavy. C. Matter has mass and takes up space. D. Matter has volume and takes up space.

Answers

And the answer is C. Matter it has mass and it takes up spaces.  

Hopes it helped you.

-Charlie

At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?

Answers

Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
[tex]\ln( \frac{K_2}{K_1} ) = \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2} ) [/tex]
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
[tex] \frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2} )=12.38 [/tex]
And so
[tex]\ln( \frac{K_2}{K_1})=12.38 [/tex]
And using [tex]K_1=6.1\cdot 10^{-8} s^{-1}[/tex] , we find K2:
[tex]K_2=K_1 e^{12.38}=0.0145 s^{-1}[/tex]


what are the inner planets relative distance from the Sun

Answers

Closer than the outer planets, inside the Asteroid Belt between Mars and Jupiter.

There are two types of planets as classifieds by astronomers in our solar system.

The classification is based on the asteroid belt present in our solar system.

These are named as - [1] inner planets

                                    [2]outer planets

The inner planets are the planets which are  very close to the sun and present before the asteroid belt starting from sun.

The outer planets which are present after the asteroid belt are Jupiter,Uranus,Neptune and Pluto[if we consider Pluto as a planet]

There are four planets considered as inner planets. These are arranged from closest to the farthest as Mercury,Venus,Earth ad Mars.

The distance of Mercury from the sun is 57.91 million km

The distance of Venus from sun is 108.2 million km

The distance of Earth from sun  is 149.6 million km

Finally the distance of Mars from the sun is 227.9 million km


which theory of plate movements involves magma rising all the way from the lower mantle to spread apart plates

Answers

Hot plumes is the answer

Answer:

hot plumes

Explanation:

Two large parallel conducting plates are 17 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. an electrostatic force of 2.9 ✕ 10-15 n acts on an electron placed anywhere between the two plate (neglect fringing). (a) find the electric field at the position of the electron.

Answers

The electrostatic force acting on a charge q is given by
[tex]F=qE[/tex]
where E is the electric field's intensity.

In our problem, the particle is an electron, so its charge is [tex]q=e=-1.6 \cdot 10^{-19}C[/tex]. We know the intensity of the force, so we can find the magnitude of the electric field at the point where the electron is located:
[tex]E= \frac{F}{q}= \frac{2.9\cdot 10^{-15}N}{-1.6 \cdot 10^{19}C}=-1.8 \cdot 10^4 N/C [/tex]
where the negative sign means that the force and the electric field have opposite direction, because the charge is negative.

What is most likely to happen to light that hits an opaque object?
A. All of the light passes through the object.
B. None of the light passes through the object.
C. Most of the light disappears.
D. Some of the light passes through the object.

Answers

B. is the answer.

C is not correct because the light is actually reflected off of an opaque object.

When the light hits an opaque object, none of the light will pass through the object. Hence, option B is correct.

What is light?

Electromagnetic radiation that the human eye can detect as light. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than roughly 1 1011 meter, electromagnetic radiation occurs throughout a very broad range of wavelengths.

The wavelengths of light that are visible to humans fall into a very small range within that wide spectrum, ranging from about 700 nanometers for red light to roughly 400 nm for violet light.

Infrared and ultraviolet are two spectral bands that are close to the visible region and are repeatedly alluded to as light as well.

Anything that doesn't let any light through is opaque. Instances of opaque materials include concrete, wood, and metal.

To know more about Light:

https://brainly.com/question/15200315

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A large jet flying overhead is low enough so that a man on the ground can hear its engines. The man sees the jet before he hears the engines because

Answers

Because the speed of light through air is more than 800 thousand times faster than the speed of sound through air. So the sight of anything reached him well before the sound of it.

Determine which heat transfers below are due to the process of conduction. I) You walk barefoot on the hot street and it burns your toes. II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned. III) A flame heats the air inside a hot air balloon and the balloon rises. IV) A boy sits to the side of a campfire. He is 10 feet away, but still feels warm.

Answers

Answer:

I) You walk barefoot on the hot street and it burns your toes.

II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.

Explanation:

In conduction mode of heat transfer we know that the energy is transferred from one system to other system due to direct contact of two bodies

Here due to this direct contact the energy is transferred via a given solid or liquid medium

In this type of heat transfer medium particles will remain in its own position only the energy is transferred.

So here we can say the correct answer will be

I) You walk barefoot on the hot street and it burns your toes.

II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.

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