A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called

The answer is Condensation

Answer:

4.014 g of water

Explanation:

An internet search for your question tells me that the chemical equation is:

So first we use PV=nRT to calculate the moles of hydrogen gas produced:

0.993 atm * 5.50 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

Now we convert mol H₂ to mol H₂O and finally to grams of water:

0.223 mol H₂ * [tex]\frac{1molH_{2}O}{1molH_{2}}*\frac{18g}{1molH_{2}O}[/tex] = 4.014 g H₂O

Answer:

8

Explanation:

just did the quiz

There are 8 atoms of oxygen in the chemical formal 2Ca(CIO[tex]_2[/tex])[tex]_2[/tex]. Atoms are incredibly tiny, measuring typically 100 picometers across.

A particle called an atom has a nucleus made up of neutrons and protons that is encircled by an electron cloud. The fundamental unit of the chemical components is the atom, and the protons in an atom serve as a means of differentiating one chemical element from another.

Every atom with 11 protons, for instance, is sodium, while any atom with 29 protons becomes copper. The element's isotope is determined by the amount of neutrons in it.

Atoms are incredibly tiny, measuring typically 100 picometers across. Over a thousand carbon atoms make up an average human hair. Because it's smaller than the visible light spectrum's smallest wavelength, people cannot view atoms using standard microscopes. There are 8 atoms of oxygen in the chemical formal 2Ca(CIO[tex]_2[/tex])[tex]_2[/tex].

Therefore, there are 8 atoms of oxygen in the chemical formal 2Ca(CIO[tex]_2[/tex])[tex]_2[/tex].

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Answer:

B. A chemical reaction

Explanation:

A chemical equation describes the sequence and amounts of a chemical reaction

In the formation of one molecule of aluminum oxide (Al2O3), a total of 6 electrons are transferred from two aluminum atoms to three oxygen atoms to maintain electrical neutrality.

The formation of one molecule of aluminum oxide (Al2O3) involves the transfer of electrons between aluminum atoms and oxygen atoms. Each aluminum atom loses three electrons, becoming Al3+ ions, while each oxygen atom gains two electrons to become O2- ions. To maintain electrical neutrality, the compound must have equal numbers of positive and negative charges.

Therefore, to form one molecule of Al2O3, two aluminum atoms (2 Al) will lose a total of 6 electrons (2 Al × 3 e-), and three oxygen atoms will gain a total of 6 electrons (3 O × 2 e-) during the electron transfer process. The complete transfer involves 12 electrons changing places but, in effect, the number of electrons transferred is the total on one side of the reaction which is 6.

Answer: acid + base → salt + water

Explanation: Neutralization is a type of double displacement reaction in which exchange of ions take place. Neutralization is a chemical reaction between an acid and a base where ions exchange and lead to formation of salt and water.

[tex]HCl(aq)+NaOH(aq)\rightarrow NaCl(aq)+H_2O[/tex]

HCl is an acid which donates [tex]H^+[/tex] ions when dissolved in water. [tex]NaOH[/tex] is base which donates [tex]OH^-[/tex] ions when dissolved in water. They combine to form [tex]NaCl[/tex] which is salt and [tex]H^+[/tex] and [tex]OH^-[/tex] ions combine to form water [tex]H_2O[/tex].

Answer:

No, potassium chloride will not dissolve completely. Only 28.15 g of potassium chloride will get dissolved.

Explanation:

Amount od potassium chloride added to 50 g of boiling water = 250.0 g

The solubility of potassium chloride in boiling water is 56.3 g/100 g water.

Amount of potassium chloride soluble in 100 g of boiling water = 56.3 g

Amount of potassium chloride soluble in 1 g of boiling water = [tex]\frac{56.3 g}{100}[/tex]

Amount of potassium chloride soluble in 50.0 g of boiling water :

[tex]\frac{56.3 g}{100}\times 50.0 g=28.15 g[/tex]

Amount of potassium chloride left undissolved = 250.0 g - 28.15 g = 221.85 g

28.15 g of potassium chloride will dissolve and remaining 221.85 g og potassium chloride will not.

Answer : The correct answer is 96.68 yrs

Radioactivity Decay :

it is a process in which a nucleus of unstable atom emit energy in form of radiations like alpha particle , beta particle etc .

Radioactive decay follows first order kinetics , so its rate , rate constant , amount o isotopes can be calculated using first order equations .

The first order equation for radioactive decay can be expressed as :

[tex] ln \frac{N}{N_0} = - k*t [/tex] ----------- equation (1)

Where : N = amount of radioisotope after time "t"

N₀ = Initial amount of radioisotope

k = decay constant and t = time

Following steps can be used to find time :

1) To find deacy constant :

Decay constant can be calculated using half life . Decay constant and half life can be related as :

[tex] T _\frac{1}{2} = \frac{ln2}{k} [/tex] ---------equation (2)

Given : Half life of Strontium -90 = 28.8 years

Plugging value of [tex] T_\frac{1}{2} [/tex] in above formula (equation 2) :

[tex] 28.8 yrs = \frac{ln 2}{ k } [/tex]

Multiply both side by k

[tex] 28.8 yrs * k = \frac{ln 2 }{k} * k [/tex]

Dividing both side by 28.8 yrs

[tex] \frac{28.8 yrs * k}{28.8 yrs} = \frac{ln 2}{28.8 yrs} [/tex]

(ln 2 = 0.693 )

k = 0.0241 yrs⁻¹

Step 2 : To find time :

Given : N₀ = 10.3 ppm N = 1.0 ppm k = 0.0241 yrs⁻¹

Plugging these value in equation (1) as :

[tex] ln (\frac{1.0 ppm}{10.3 ppm} ) = - 0.0241 yrs^-^1 * t [/tex]

[tex] ln (0.0971 ) = -0.0241 yrs ^-^1 * t [/tex]

(ln 0.0971 = - 2.33 )

Dividing both side by - 0.0241 yrs⁻¹

[tex] \frac{-2.33}{-0.0241 yrs^-^1} = \frac{-0.0241 yrs^-^1 * t}{-0.0241 yrs^-^1} [/tex]

t = 96.68 yrs

Hence the concentration of Strontium-90 will drop from 10.3 ppm to 1.0 ppm is 96.68 yrs

96.9 years

Given:

Question:

How many years would pass before the strontium-90 concentration would drop to 1.0 ppm?

The Process:

In the calculations of half-lives, the expressions are the following:

[tex]\boxed{ \ N = \frac{N_o}{2^n} \ }[/tex]

where [tex]\boxed{ \ n = \frac{t}{t_{1/2}} \ }[/tex] are used. In these expressions;

Step-1: find out the number of half-lives (n)

[tex]\boxed{ \ N = \frac{N_o}{2^n} \ } \rightarrow \boxed{ \ 2^n = \frac{N_o}{N} \ }[/tex]

[tex]\boxed{ \ 2^n = \frac{10.3}{1.0} \ }[/tex]

[tex]\boxed{ \ 2^n = 10.3 \ }[/tex]

[tex]\boxed{ \ n \cdot \ln{2} = \ln{10.3} \ } \rightarrow \boxed{ \ n = \frac{\ln{10.3}}{\ln{2}} \ }[/tex]

We get n = 3.364572

Step-2: find out in how many years would pass before the strontium-90 concentration would drop to 1.0 ppm

[tex]\boxed{ \ n = \frac{t}{t_{1/2}} \ } \rightarrow \boxed{ \ t = n \times t_{1/2} \ }[/tex]

t = 3.364572 x 28.8

t = 96.9

Thus in 96.9 years will pass before the concentration of strontium-90 will drop to 1.0 ppm.

- - - - - - - - - -

Notes:

The half-life of radioactive decay is the period of time required for half of the initial amount of the substance to disintegrate. The shorter the half-life of radioactive decay, the higher the rate of radioactive decay and the more radioactivity. The half-life is the characteristic property of each element.

The volume percent % (v/v) of an isopropyl alcohol solution made by dissolving 135 ml of isopropyl alcohol in 745 ml of water is 15.34%. It's calculated by dividing the volume of the alcohol by the total volume of the solution, then multiplying by 100%.

The question asks for the volume percent % (v/v) of an isopropyl alcohol solution made by dissolving 135 ml of isopropyl alcohol in 745 ml of water. The volume percentage (v/v) is commonly used to express the concentration of a solution. It's calculated by the volume of the solute divided by the volume of the solution, then multiplied by 100%.

In this case, the solute is the isopropyl alcohol, and the solution is the mixture of isopropyl alcohol and water. The volume of the solute (alcohol) is 135 ml, and the total volume of the solution is 745 ml (water) + 135 ml (alcohol) = 880 ml.

Therefore, the volume percent (v/v) of the isopropyl alcohol is given by (135 ml / 880 ml) * 100% = 15.34%, rounded to two decimal places.

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The molarity of the solution is 0.279 M.

To find the molarity of the solution, we need to calculate the number of moles of glucose and the volume of the solution in liters. The molarity is defined as moles of solute per liter of solution.

First, we calculate the number of moles of glucose:

Moles of glucose = mass of glucose / molar mass of glucose

Moles of glucose = 5.10 g / 180 g/mol = 0.028 moles

Next, we calculate the volume of the solution in liters:

Volume of solution = 100.5 ml / 1000 = 0.1005 L

Finally, we plug in the values into the molarity formula:

Molarity = moles of glucose / volume of solution

Molarity = 0.028 moles / 0.1005 L = 0.279 M

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Final answer:

The combustion of 1.00 mol of CH4 produces 44.01 grams of CO2, as one mole of methane combusts to create one mole of carbon dioxide, and the molar mass of CO2 is 44.01 g/mol.

Explanation:

The mass of CO2 produced by the combustion of 1.00 mol of CH4 can be calculated by looking at the balanced chemical equation:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)

From the equation, it is clear that one mole of methane (CH4) produces one mole of carbon dioxide (CO2) upon combustion. To convert moles of CO2 to grams, we use the molar mass of CO2, which is 44.01 g/mol.

Calculation:

1.00 mol CH4 × (44.01 g CO2 / 1 mol CO2) = 44.01 g CO2

Therefore, the combustion of 1.00 mol of CH4 will produce 44.01 grams of CO2.

Final answer:

The reaction where Sn⁴⁺(aq) gains electrons to form Sn²⁺(aq) is a reduction process, making the correct answer to the question 'd) reduction' within an oxidation-reduction reaction.

Explanation:

The given chemical equation is Sn⁴⁺(aq) + 2e⁻ → Sn²⁺ (aq), which represents a type of reaction where the oxidation state of tin (Sn) is changing. When an element gains electrons during a reaction, it is undergoing a process known as reduction. Since tin is gaining two electrons, going from a +4 oxidation state to a +2 oxidation state, this reaction is best described as a reduction process within an oxidation-reduction reaction. This transformation signifies a shift towards a lower oxidation state, indicating a reduction in the oxidation number of tin atoms. Such reactions, where oxidation states change, are fundamental in various chemical processes, underpinning diverse phenomena in both natural and synthetic contexts.

Answer:

false

Explanation:

Final answer:

Thermal expansion is the increase or decrease in size of a body due to a change in temperature. Solid metals undergo greater thermal expansion than liquids. This is because the closely packed atoms or molecules in solid metals are pushed farther apart by the increase in temperature, resulting in a larger size for the whole body.

Explanation:

Thermal expansion: Thermal expansion is the increase, or decrease, of the size (length, area, or volume) of a body due to a change in temperature. It occurs in all dimensions - length, area, volume - and is not limited to solid metals. However, solid metals undergo greater thermal expansion than liquids do. The increased thermal expansion in solid metals can be attributed to their closely packed atoms or molecules, which are pushed farther apart by the increase in temperature, resulting in a larger size for the whole body.

The Arrhenius theory limits acids and bases to those that produce hydrogen or hydroxide ions in aqueous solutions, making ammonia a base only when it reacts with water and not recognizing it as an inherent base due to its structure. The Brønsted-Lowry theory overcomes this limitation by including substances like ammonia that accept hydrogen ions, further expanded by the Lewis model where ammonia can donate an electron pair.

The Arrhenius theory is limited in its definition of acids and bases because it requires the presence of hydroxide ions in the formula of bases and hydrogen ions in the formula of acids. This aspect of the theory does not account for substances like ammonia (NH3) which do not release hydroxide ions directly into solution.

Ammonia becomes a base according to the Arrhenius model only by its reaction with water where it forms ammonium (NH4+) and hydroxide (OH-) ions. Water donates a hydrogen ion to the ammonia, making water the Brønsted-Lowry acid and ammonia the Brønsted-Lowry base. Thus, ammonia is a base in the Arrhenius sense only when dissolved in water, and reveals the limitations because it does not contain hydroxide in its structure.

In the broader Brønsted-Lowry theory, ammonia is clearly a base since it accepts a hydrogen ion from a water molecule. Similarly, the Lewis model recognizes ammonia as a base since it can donate a pair of electrons to a hydrogen ion.

The position of equilibrium for the reaction involving nitric acid will lie far to the right, favoring the production of HNO3 and OH-(aq). This is due to HNO3 being a strong acid and fully ionizing in water, while NO3- is a weak base.

The question you asked is about the position of equilibrium for the reaction NO3-(aq) + H2O(l) ↔ HNO3(aq) + OH-(aq). Nitric acid, HNO3, is known to be a very strong acid that is 100% ionized in water. Given that HNO3 is a strong acid, its conjugate base NO3- is a weak base and has a much lower tendency to gain a proton than water (H2O) has to lose one. This means the reaction will lie very far to the right, favoring the production of HNO3 and OH-(aq).

This behavior is consistent with the concept known as the leveling effect, which indicates that strong acids in water are fully ionized to form hydronium ions (H3O+) and their corresponding anions, and thus cannot exist in aqueous solution as anything stronger than the hydronium ion. In this case, HNO3 will ionize in water to give H3O+ and NO3-, showing that NO3- will not readily recombine with H+ to form HNO3 again. The equilibrium is clearly on the side of dissolving nitric acid (HNO3) into its ions.