Answer:
P = 80.922 KW
Explanation:
Given data;
Length of load arm is 900 mm = 0.9 m
Spring balanced read 16 N
Applied weight is 500 N
Rotational speed is 1774 rpm
we know that power is given as
[tex] P = T\times \omega[/tex]
T Torque = (w -s) L = (500 - 16)0.9 = 435.6 Nm
[tex]\omega[/tex] angular speed [tex]=\frac{2 \pi N}{60} [/tex]
Therefore Power is
[tex]P =\frac{435.6 \time 2 \pi \times 1774}{60} = 80922.65 watt[/tex]
P = 80.922 KW