The frequency of the photons is equal to 1.22 ×10¹³ Hz and lies in the infrared region of the electromagnetic spectrum.
What is the frequency?The frequency of the photons or light can be described as the number of oscillations in one second. The frequency possesses S.I. units per second or Hertz.
The relationship between momentum (p), frequency (ν), and speed of light (c) is:
p = hν/c
ν = pc/h
Given, the momentum of the photons, p = 2.7 ×10⁻²⁹ Kg.m/s
The speed of light, c = 3×10⁸ m/s
The plank's constant, h = 6.626 ×10⁻³⁴ Js
The frequency of the photons can determine from the above-mentioned relationship:
ν = (2.7 × 10⁻²⁹).( 3 × 10⁸)/ 6.626 × 10⁻³⁴
ν = 1.22 × 10¹³ Hz
Therefore, the frequency of the photons is 1.22 × 10¹³ Hz and lies in the infrared region of the spectrum.
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How does natural selection result in adaptations in a species
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 ev . part a what is the maximum kinetic energy of the photoelectrons when light of wavelength 295 nm falls on the same surface? emax =?
which formula represents Snell's law
Snell's law is used for refraction of light
it is used to find the relation between refractive index of two medium and angle of incidence and angle of refraction.
As per this formula
[tex]n_1 sin\theta_i = n_2 sin\theta_r[/tex]
here [tex]n_1[/tex] = refractive index of first medium
[tex]n_2[/tex] = refractive index of second medium where light go after refraction
[tex]\theta_i[/tex] = angle of incidence
[tex]\theta_r[/tex] = angle of refraction
H e l p.. I have no idea what any of this is, what is the first step of the hydrogen fusion process
How many photons per second are emitted by the antenna of a microwave oven if its power output is 1.00 kw at a frequency of 2515 mhz?
To determine the number of photons emitted per second by the antenna of a microwave oven, we need to use the formulas for energy per photon and number of photons.
Explanation:The number of photons emitted by the antenna of a microwave oven can be calculated using the formula:
Number of photons = (Power output / Energy per photon) x frequency
To find the energy per photon, we can use the formula:
Energy per photon = Planck's constant x frequency
Given that the power output is 1.00 kW and the frequency is 2560 MHz, we can convert these values to SI units and calculate the number of photons emitted per second.
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Approximately 6.01 x 10²⁶ photons per second are emitted by the antenna of the microwave oven.
To determine the number of photons emitted per second by a microwave oven, we can use the formula:
Number of Photons per Second (N) = Power Output (P) / Energy per Photon (E)
Given:
Power Output (P) = 1.00 kW (or 1000 W)Frequency (f) = 2515 MHz (or 2.515 x 10⁹ Hz)First, find the energy per photon (E) using the equation:
E = h * f
where h is Planck's constant (6.626 x 10⁻³⁴ Js) and f is the frequency.
Substitute the values:
E = 6.626 x 10⁻³⁴ Js * 2.515 x 10⁹ Hz
E = 1.665 x 10⁻²⁴ J
Next, calculate the number of photons per second:
N = P / E
N = 1000 W / 1.665 x 10⁻²⁴ J
N ≈ 6.01 x 10²⁶ photons per second
Therefore, the antenna of the microwave oven emits approximately 6.01 x 10²⁶ photons per second.
¿Cuál es la velocidad promedio de un hombre que camina 70m con una rapidez de 1m/s y luego corre 70m con una rapidez de 3m/s?
Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open, has the same frequency as the second harmonic of pipe
a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)
A cello string 0.75 m long has a 220 hz fundamental frequency. find the wave speed along the vibrating string. answer in units of m/s.
Which lists the amplitudes of sound waves from these sources in order from greatest to least?
busy roadway, kids whispering, average home
chainsaw, diesel truck, rustling leaves
kids whispering, vacuum cleaner, jet airplane
library, conversational speech, music from speaker
The correct answer is option B which is a chainsaw, diesel truck, rustling leaves.
Explanation:The amplitude of the sound wave is the maximum displacement of the particles from their resting position.Higher the amplitude means high sound.So the sound of a chainsaw is high, so its amplitude will be great and after that the amplitude of diesel truck is high and rustling leaves have the lowest amplitude.Answer:
B
Explanation:
Edge :)
What real-world examples show no work begin done? Can you think of examples other than resisting the force of gravity?
Answer:
Explanation:
The work done is defined as the product of force in the direction of displacement and the displacement.
Work done = force x displacement x Cos Ф
Where, Ф be the angle between force and the displacement vectors.
Work may be positive, negative or zero depending on the values of angle Ф.
The work done is zero when force is zero or displacement is zero or angle Ф is 90 degree.
So, when we apply a force on a body and body does not displace, then the work done is zero.
What's the pressure and temp of 6694 meters high
Bats can detect small objects such as insects that are of a size on the order of a wavelength. if bats emit a chirp at a frequency of 69.3 khz and the speed of sound waves in air is 330 m/s, what is the smallest size insect they can detect? give your answer in mm (millimeters)
What is a correct way to measure wavelength
The most common natural fiber found at a crime scene, and thus forensically insignificant (unless it is of a unique color)
Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The length of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.
Answer: Days and nights are equal in length everywhere.
Explanation:
Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.
A car has two horns, one emitting a frequency of 199 hz and the other emitting a frequency of 203 hz. what beat frequency do they produce?
The beat frequency produced by two horns emitting frequencies of 199 Hz and 203 Hz is 4 Hz.
The question is regarding the production of beat frequency when two horns with different frequencies sound together. The two horns have frequencies of 199 Hz and 203 Hz, respectively.
To calculate the beat frequency, you subtract the smaller frequency from the larger frequency:
fbeat = |f1 - f2|
fbeat = |203 Hz - 199 Hz|
fbeat = 4 Hz
This means that the beat frequency produced by the two car horns is 4 Hz.
What happens when a person’s immune system is very weak?
a) The patient’s blood is unable to clot so he or she must take medication.
b) The patient is able to fight off more infections than normal.
c) The patient is unable to fight the infections a healthy person could resist.
d) The patient is unable to take antibiotics and must get a flu shot.
When a person's immune system is very weak, their body may be unable to fight off pathogens and diseases that a healthy immune system can resist. This can lead to increased risk of illness and vulnerability to infection.
(Option C)
Explanation:Immunodeficiency occurs when the immune system is not working properly, generally because one or more of its components are inactive. As a result, the immune system may be unable to fight off pathogens or cancers that a normal immune system would be able to resist. Immunodeficiency may occur for a variety of reasons.
The body's immune system would not be able to fight off pathogens like bacteria with fewer white blood cells. This can increase the risk of illness in HIV patients.
The person's immune system would not be able to distinguish self and non-self. This would make the person very vulnerable to infection.
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The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?
At what speed does the classical momentum, p=mv, give an error, when compared with the relativistic momentum, of 1.35 % ?
To calculate the speed at which the classical momentum gives an error compared to the relativistic momentum, we need to find the ratio of the two different momenta. This can be done by solving for the velocity using the given equations and approximations.
Explanation:The classical momentum, p=mv, gives an error when compared with the relativistic momentum. The error can be calculated by finding the ratio of the relativistic momentum to the classical momentum. In this case, the error is 1.35%. To find the velocity at which this error occurs, we need to solve for the velocity using the given equations and approximations.
(a) Find the momentum of a 1.00 × 10⁹ kg asteroid heading towards the Earth at 30.0 km/s.
(b) Find the ratio of this momentum to the classical momentum. (Hint: Use the approximation that y = 1+(1/2)v²/c² at low velocities.)
An elephant can hear sound with a frequency of 15 hz. what is the wavelength of this wave if the speed of sound in air is 343 m/s?
The wavelength of a sound wave with a frequency of 15 Hz and a speed of sound in air of 343 m/s is approximately 22.87 meters.
Explanation:To calculate the wavelength of the sound wave, we can use the formula:
Speed of sound (v) = wavelength (λ) x frequency (f)
Given that the frequency of the sound wave is 15 Hz and the speed of sound in air is 343 m/s, we can substitute these values into the formula to solve for the wavelength:
343 m/s = λ x 15 Hz
Dividing both sides of the equation by 15 Hz, we get:
λ = 343 m/s / 15 Hz = 22.87 meters (rounded to two decimal places)
Therefore, the wavelength of the sound wave is approximately 22.87 meters.
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A cyclist is going in the positive x-direction at 9m/s. A car initially at rest, accelerates for the first 10 seconds, then it goes with a constant velocity. If the car reaches the cyclist after 15 seconds from the moment the car started moving, find: (a) The acceleration of the car during the first 10 seconds, (b) The velocity of the cyclist with respect to the car when the car reaches the cyclist
What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes
Assume that you have two objects, one with a mass of 10 kg and the other with a mass of 18 kg, each with a charge of −0.027 c and separated by a distance of 9 m. what is the electric force that these objects exert on one another? answer in units of n.
Final answer:
Using Coulomb's law, the electric force between two objects with charges of – 0.027 C each and separated by 9 m is 81 N. The force is repulsive since the charges are alike.
Explanation:
To calculate the electric force between two objects using Coulomb's law, one needs to know the charges on the objects and the distance separating them. Coulomb's law is represented by the formula F = k * |q1 * q2| / r2, where F is the force between the charges, k is Coulomb's constant (9.0 × 109 N·m2/C2), q1 and q2 are the amounts of the charges, and r is the distance between them.
In this case, with both objects having a charge of – 0.027 C and separated by a distance of 9 m, the electric force F is calculated as follows:
F = (9.0 × 109 N·m2/C2) * |(– 0.027 C) * (– 0.027 C)| / (9 m)2
Since the charges are like charges, the force will be repulsive and we can ignore the negative sign for the purposes of calculating magnitude:
F = (9.0 × 109 N·m2/C2) * (0.027 C * 0.027 C) / (81 m2) = 9.0 × 109 * 0.000729 / 81 = 8.1 × 101 N
Thus, the electric force between the two objects is 81 N acting to push them apart.
When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at speed v. if the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed?
Answer:
The sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.
Explanation:
The sound wave is a property of the air, which means that the speed of the object producing sound does not matter to the sound of the waves, that is, they are always going to be the same.
So the sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.
In Figure 18.8 the grounding wire is removed first, followed by the rod, and the sphere is left with a positive charge. If the rod were removed first, followed by the grounding wire, would the sphere be left with a charge? Account for your answer.
If the charged rod is removed before the grounding wire, the sphere will not retain a net charge because any excess charge will flow back to ground. Only if the grounding wire is removed while the rod is still present does the sphere retain an excess charge.
Explanation:If the grounding wire is removed after the charged rod is taken away, the sphere would be left with no net charge. This is because during the process of charging by induction, if the rod is removed first, any excess charge on the sphere would have the opportunity to redistribute evenly across its surface. Since the sphere was initially neutral and the grounding wire is still connected, the excess charge would flow to the ground, effectively bringing the sphere back to a neutral state.
On the other hand, as described in your references, if the grounding wire is removed first while the charged rod is still present, the sphere retains an excess of electrons. This happens because by breaking the ground connection while the sphere is still influenced by the nearby positive charge of the rod (which repels the electrons), the redistributed electrons are trapped on the sphere, thus leaving the sphere negatively charged. When the positive rod is finally removed, the sphere remains negatively charged because the extra electrons have no path to escape.
A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the highest frequency associated with this portion of the spectrum? (c = 3.00 × 108 m/s)
The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm is 7.50 × 10^14 Hz.
Explanation:The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm can be determined using the formula c = fλ, where c is the speed of light. In this case, the wavelength is given as 200 nm to 400 nm. Converting the wavelength to meters, we find that it corresponds to 2.00 × 10-7 m to 4.00 × 10-7 m. Using the formula, we can rearrange it to solve for the frequency, f = c/λ. Plugging in the values, we get the highest frequency as 7.50 × 1014 Hz.
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Two small objects each with a net charge of +q exert a force of magnitude f on each other: we replace one of the objects with another whose net charge is +4q: the original magnitude of the force on the +q charge was f; what is the magnitude of the force on the +q charge now?
Light of wavelength 600 nm illuminates a diffraction grating. the second-order maximum is at angle 39.5 ∘. part a how many lines per millimeter does this grating have?
The number of lines per millimeter that the grating has is : ≈ 530 lines
Given data :
light wavelength = 600 nm
second order maximum angle ( x ) = 39.5°
order of maximum = 2
Determine the number of lines the grating will haveWe will apply diffraction equation
[tex]d*sinx = m*wavelength[/tex] --- ( 1 )
where : d = spacing of lines, x = 39.5°, m = 2
Insert values into equation ( 1 ) above
d * Sin ( 39.5 ) = 2 * 600 * 10⁻⁹
therefore ; d = 1.88656 * 10⁻⁶ m
Final step : determine the number of lines per mm
Number of lines per mm
= 0.001 / d
= 0.001 / (1.88656 * 10⁻⁶ ) ≈ 530 lines
Hence we can conclude that The number of lines per millimeter that the grating has is ≈ 530 lines
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When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99863 s. what is the change in acceleration (in m/s2) due to gravity at its new location?
What are three benefits of being assertive and what are three tips to help you develop an assertive style of communication? (Site 1)