A mass weighing 13 lb stretches a spring 4.5 in. The mass is also attached to a damper with coefficient Y. Determine the value of Y for which the system is critically damped. Assume that g = 32 ft/s^2.

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = [tex]P(A)=0.42[/tex]

The probability that the days are cloudy and rainy = [tex]P(A\cap B)=0.41[/tex]

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

[tex]P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762[/tex]

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy  = 0.9762

the probability that a randomly selected day in January will be rainy if it is cloudy is approximately 97.62%.

The question asks us to find the probability that a day will be rainy given that it is cloudy. From the information provided, we know that in this city, 42% of the days in January are cloudy, and 41% are both cloudy and rainy. To find the probability that it is rainy given that it is cloudy, we use the concept of conditional probability.

The formula for conditional probability is P(A|B) = P(A u2229 B) / P(B), where P(A|B) is the probability of A given B, P(A \\u2229 B) is the probability of both A and B occurring, and P(B) is the probability of B occurring.

Let A be the event that it is rainy and B be the event that it is cloudy. Therefore, P(A|B) = P(A u2229 B) / P(B) = 0.41 / 0.42 = 0.9762 or 97.62%.

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy is approximately 97.62%.

Answer:

The payment would be $ 897.32.

Step-by-step explanation:

Since, the monthly payment of a loan is,

[tex]P=\frac{PV(r)}{1-(1+r)^{-n}}[/tex]

Where, PV is the present value of the loan,

r is the monthly rate,

n is the total number of months,

Here,

PV = $170,000,

Annual rate = 4 % = 0.04

So, the monthly rate, r = [tex]\frac{0.04}{12}=\frac{1}{300}[/tex]  ( 1 year = 12 months )

Time in years = 25,

So, the number of months, n = 12 × 25 = 300

Hence, the monthly payment of the debt would be,

[tex]P=\frac{170000(\frac{1}{300})}{1-(1+\frac{1}{300})^{-300}}[/tex]

[tex]=897.322628506[/tex]

[tex]\approx \$ 897.32[/tex]

Answer:

Step-by-step explanation:

Given data

principal P = $10000

rate (r) = 6.5%

to find out

amount in account and the interest earned after one year, five, years, ten years, and 20 years

solution

we know the formula for compounds interest continuously i.e.

amount = principal [tex]e^{rt}[/tex]     ..............1

and

compounds interest annually i.e.

amount = principal [tex](1+r/100)^{t}[/tex]  ..................2

here put value principal rate and time period 1, 5 10 and 20 years

and we get the  amount for each time period        

than for interest = amount - principal we get interest    

as that we calculate all value

i put all value in table here

Final answer:

To calculate the future value of two accounts both starting with $10,000 at a 6.5% interest rate, one compounding annually and the other continuously, we use the formulas for annual and continuous compounding to compare the total amount and interest earned over 1, 5, 10, and 20 years. The continuous compounding results in higher amounts as shown in the provided table.

Explanation:

To compare the growth of two accounts with an initial deposit of $10,000 at an annual interest rate of 6.5%, with one account compounding annually and the other compounding continuously, we can use the following formulas:

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money).
r = the annual interest rate (in decimal form).
n = the number of times that interest is compounded per year.
t = the time in years.
e = the base of the natural logarithm, approximately equal to 2.71828.

To make the calculations for both accounts after 1, 5, 10 and 20 years, we will round all values to the nearest dollar and not include dollar signs as per the student's request.

Annual Compounding

Here, n is 1 since interest compounds once per year.

Continuous Compounding

Using the formula for continuous compounding, we do not need a value for n.

Let's look at the calculations:

TimeAnnual Compounded AmountContinuous Compounded AmountInterest Earned (Annual)Interest Earned (Continuous)1 year$10,695$10,709$695$7095 years$13,612$13,747$3,612$3,74710 years$18,504$18,907$8,504$8,90720 years$34,262$35,861$24,262$25,861

From the table, we can conclude that continuous compounding results in a higher total amount and interest earned over time compared to annual compounding for the same interest rate.

Answer:

g(2y) = 8y^2 -3

Step-by-step explanation:

g(x)=2 x^2   -3

Let x=2y

g(2y) = 2 (2y)^2 -3

         = 2 (4y^2)  -3

         = 8y^2 -3

Answer:

The absolute minimum value of the function over the​ interval [0,7] is -18.

Step-by-step explanation:

The given function is

[tex]f(x)=x^2-6x-9[/tex]

Differentiate f(x) with respect to x.

[tex]f'(x)=2x-6[/tex]

Equate f'(x)=0  to find the critical points.

[tex]2x-6=0[/tex]

[tex]2x=6[/tex]

[tex]x=3[/tex]

The critical point is x=3.

Differentiate f'(x) with respect to x.

[tex]f''(x)=2[/tex]

Since f''(x)>0 for all values of x, therefore the critical point is the point of minima and the function has no absolute maximum value.

3 ∈ [0,7]

Substitute x=3 in the given function to find the absolute minimum value.

[tex]f(3)=(3)^2-6(3)-9[/tex]

[tex]f(3)=9-18-9[/tex]

[tex]f(3)=-18[/tex]

Therefore the absolute minimum value of the function over the​ interval [0,7] is -18.

The maximum value of the function f(x) = x² - 6x - 9 over the interval [0, 7] is 2, which occurs at x = 7, and the minimum value is -9, which occurs at both x = 0 and x = 3.

The function given is f(x) = x² - 6x - 9. To find the maximum and minimum values of this function over the interval [0, 7], we first need to find the critical points of the function. These occur where the derivative of the function is zero or undefined. The derivative of f(x) is f'(x) = 2x - 6. Setting this equal to zero and solving for x gives x = 3. Since this value is within our interval, it is a critical point of the function.

Next, we evaluate the function at the endpoints of the interval and at our critical point. We have f(0) = -9, f(3) = -9, and f(7) = 2. This shows that the maximum value of the function over the interval is 2, which occurs at x = 7, and the minimum value is -9, which occurs at both x = 0 and x = 3.

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Answer:

The monthly payment is $3583.63 ( approx )

Step-by-step explanation:

Given,

The total cost of the home = $1,250,000

There is a downpayment of $400,000,

Thus, the present value of the loan, PV =  1250000 - 400,000 = $ 850,000

Annual rate = 3 % = 0.03,

So, the monthly rate, r = [tex]\frac{0.03}{12}=\frac{1}{400}[/tex]

And, time ( in years ) = 30

So, the number of months, n = 12 × 30 = 360

Hence, the monthly payment of the loan,

[tex]P=\frac{PV(r)}{1-(1+r)^{-n}}[/tex]

[tex]=\frac{850000(\frac{1}{400})}{1-(1+\frac{1}{400})^{-360}}[/tex]

[tex]=3583.6342867[/tex]

[tex]\approx \$3583.63[/tex]

Answer:

y=4 sin(4x)

Step-by-step explanation:

So you are given y(0)=0.  This means when x=0, y=0.

So plug this in:

0=c1 cos(4*0)+c2 sin(4*0)

0=c1 cos(0)   +c2 sin(0)

0=c1 (1)          +c2 (0)

0=c1               +0

0=c1

So our solution looks like this after applying the first boundary condition:

y=c2 sin(4x).

Now we also have y(pi/8)=4.  This means when x=pi/8, y=4.

So plug this in:

4=c2 sin(4*pi/8)

4=c2 sin(pi/2)

4=c2 (1)

4=c2

So the solution with the given conditions applies is y=4 sin(4x) .

Testing:

y'=16 cos(4x)

y''=-64 sin(4x).

y''+16y=0

-64 sin(4x)+16(4 sin(4x))

-64 sin(4x)+64 sin(4x)

0

So the solution still works.

The solution of the differential equation y'' + 16 y = 0 is,

y = 4 sin4x

Here,

The second-order differential equation is,  y'' + 16y = 0.

And, y = c₁ cos 4x + c₂ sin 4x  is a two-parameter family of solutions of the second-order DE y'' + 16y = 0.

We have to find the solution of the differential equation that satisfies the given side conditions,   y(0) = 0, y(π/8) = 4.

What is Differential equation?

A differential equation is a mathematical equation that relates some function with its derivatives.

Now,

y = c₁ cos 4x + c₂ sin 4x is a two-parameter family of solutions of the second-order DE y'' + 16y = 0.

Apply given conditions y(0) = 0,   y(π/8) = 4 on y = c₁ cos 4x + c₂ sin 4x.

We have given y(0) = 0,

This means x = 0, y = 0

So put this in  y = c₁ cos 4x + c₂ sin 4x.

We get,

0 = c₁ cos 4*0 + c₂ sin 4*0

0 = c₁

c₁ = 0

Hence equation become,

y = c₂ sin4x

And, y(π/8) = 4 , this means that x = π/8 , y = 4

So put in equation y = c₂ sin4x we get,

4 = c₂ sinπ/2

c₂ = 4

Hence, the solution become after putting the value of c₁ = 0 and c₂ = 4,

y = c₁ cos 4x + c₂ sin 4x

y= 4 sin4x

So, The solution of the differential equation y'' + 16 y = 0 is,

y = 4 sin4x

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Answer:

(44)₁₆

Step-by-step explanation:

to convert it into hexa decimal we have select four pair of binary digit

(1000100)₂→(?)₁₆

  100  0100

to solve this we have to no the decimal conversion of

0100 which is '4'

so,

conversion of (1000100)₂→(44)₁₆

Answer:

9.6 is one such number

Step-by-step explanation:

There are infinitely many.

If we are looking at decimals which I think that might be easier here, you are looking for ones that terminate or repeat (same pattern over and over).

So we are looking for a number between 9.5 and 9.7 that is a decimal that either terminates or repeats.

That number could be 9.6.  That one is probably the easier one to see.

There are many more like these possibilities:

1)  9.6

2) 9.5001

3) 9.51

4) 9.54

5) 9.669

Answer:

9.57

Step-by-step explanation:

Because 9.56763865854637984..... (rounded 9.57) It is irrational because it has no pattern

The first and second derivatives of the given functions can be found using the chain rule of differentiation. The slope of the curve can be determined using these derivatives and to find out where the curve is concave upwards, the second derivative should be greater than zero.

To find the first and second derivatives dy/dx and d2y/dx2, we first need to use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outside function multiplied by the derivative of the inside function.

For dy/dx = dy/dt * dt/dx. Since y = cos(t), dy/dt = -sin(t). And since x = cos(2t), dx/dt = -2sin(2t). Thus, dy/dx = [-sin(t)] / [-2sin(2t)].Now, let's find d2y/dx2 which is the derivative of dy/dx with respect to x. So, d2y/dx2 = d/dx (dy/dx). Here, please use the quotient rule and chain rule again for differentiation.

For a curve to be concave upward, the second derivative needs to be greater than zero. So, you need to set your second derivative function greater than zero and solve for t within the given interval 0 < t < π.

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The first derivative is  [tex]\frac{dy}{dx} =\frac{1}{2cos(t)}[/tex] , and the second derivative is [tex]\frac{d^2y}{dx^2} = \frac{-1}{4cos^2tsin(2t)}[/tex]. The curve is concave upward in the interval (0, π/2).

We begin by finding the derivatives of x and y with respect to t.

Given x = cos(2t), differentiate to get:

[tex]\frac{dx}{dt} = -2sin(2t)[/tex]

Given y = cos(t), differentiate to get:

[tex]\frac{dy}{dt} = -sin(t)[/tex]

Using the chain rule,

[tex]\frac{dy}{dx} =\frac{dy}{dt} \frac{dt}{dx} = -sin(t) \cdot \frac{(-1)}{2sin(2t)} = \frac{1}{2cos(t)}[/tex]

Next, we need to find d²y/dx².

Start by finding the derivative of dy/dx with respect to t:

Given, [tex]\frac{dy}{dx} =\frac{1}{2cos(t)}[/tex] differentiate to get:

[tex]\frac{d(\frac{dy}{dx}) }{dt} = \frac{sin(t)}{2cos^2t}[/tex]

Using the chain rule again:

[tex]\frac{d^2y}{dx^2}= \frac{\frac{d(\frac{dy}{dx})}{dt} }{\frac{dx}{dt}} = \frac{-1}{4cos^2tsin(2t)}[/tex]

To determine where the curve is concave upward, we need d²y/dx² > 0.

Since sin(2t) is periodic, we look for values of t where sin(2t) is positive.

This is true for the interval (0, π/2). Thus, the curve is concave upward in the interval (0, π/2).

Answer:

The he cosine of the angle between the planes is [tex]\frac{14}{11\sqrt{6}}[/tex].

Step-by-step explanation:

Using the definition of the dot product:

[tex]\cos\theta =\frac{\overrightarrow{a}\cdot \overrightarrow{b}}{|\overrightarrow{a}||\overrightarrow{b}|}[/tex]

The given planes are

[tex]-1x+3y+1z=0[/tex]

[tex]5x+5y+4z=-4[/tex]

The angle between two normal vectors of the planes is the same as one of

the angles between the planes. We can find a normal vector to each of the

planes by looking at the coefficients of x, y, z.

[tex]\overrightarrow{n_1}=<-1,3,1>[/tex]

[tex]\overrightarrow{n_2}=<5,5,4>[/tex]

[tex]\overrightarrow{n_1}\cdot \overrightarrow{n_2}=(-1)(5)+(3)(5)+(1)(4)=14[/tex]

[tex]|n_1|=\sqrt{(-1)^2+(3)^2+(1)^2}=\sqrt{11}[/tex]

[tex]|n_2|=\sqrt{(5)^2+(5)^2+(4)^2}=\sqrt{66}[/tex]

The cosine of the angle between the planes

[tex]\cos\theta =\frac{\overrightarrow{n_1}\cdot \overrightarrow{n_2}}{|\overrightarrow{n_1}||\overrightarrow{n_2}|}[/tex]

[tex]\cos\theta =\frac{14}{\sqrt{11}\sqrt{66}}[/tex]

[tex]\cos\theta =\frac{14}{11\sqrt{6}}[/tex]

Therefore the cosine of the angle between the planes is [tex]\frac{14}{11\sqrt{6}}[/tex].

To find the cosine of the angle between two planes, calculate the dot product of their normal vectors.

To find the cosine of the angle between two planes, we need to determine the normal vectors of the planes and then calculate the dot product of the two normal vectors. The dot product of two vectors is equal to the product of their magnitudes and the cosine of the angle between them.

Given the planes -x+3y+z=0 and 5x+5y+4z=-4, the normal vectors are (-1,3,1) and (5,5,4) respectively.

Calculating the dot product of the two normal vectors, we get: (-1)(5) + (3)(5) + (1)(4) = 0. Therefore, the cosine of the angle between the planes is 0.

Answer:

Option A. (19, 4,370)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem

The relationship between the number of calories that Chad burns (y-axis) with respect to the number of times he works out (x-axis) represent a proportional variation

so

[tex]y=kx[/tex]

we have that

[tex]k=230[/tex] ----> the constant is equal to the slope

substitute

[tex]y=230x[/tex] ----> linear equation that represent the situation

If a point lie on the graph, the the point must satisfy the linear equation

Verify each case

case A) (19,4,370)

For x=19, y=4,370

substitute in the equation

[tex]4,370=230(19)[/tex]

[tex]4,370=4,370[/tex] ----> is true

therefore

The point lie on the graph

case B) (18,3,960)

For x=18, y=3,960

substitute in the equation

[tex]3,960=230(18)[/tex]

[tex]3,960=4,140[/tex] ----> is not true

therefore

The point does not lie on the graph

case C) (18,4,730)

For x=18, y=4,730

substitute in the equation

[tex]4,730=230(18)[/tex]

[tex]4,730=4,140[/tex] ----> is not true

therefore

The point does not lie on the graph

case D) (19,3,960)

For x=19, y=3,960

substitute in the equation

[tex]3,960=230(19)[/tex]

[tex]3,960=4,370[/tex] ----> is not true

therefore

The point does not lie on the graph

Answer:

It would be A

Step-by-step explanation:

its not the same for everyone but the number is (19, 4,370)

Answer:

44.72 Vanilla

24.08 Chocolate

Step-by-step explanation:

26% of 172 choose vanilla

14% of 172 choose chocolate

Answer with Step-by-step explanation:

A 3 foot wide brick sidewalk is laid around a rectangular swimming pool.

The outside edge of the sidewalk measures 30 feet by 40 feet.

Length of swimming pool=(30-3-3) feet

                                          =24 feet

Breath of swimming pool=(40-3-3) feet

                                         = 34 feet

Perimeter of swimming pool=2(24+34) feet

(since perimeter of rectangle=2(l+b) where l is the length and b is the breath of the rectangle)

Perimeter of swimming pool=116 feet

Hence, Perimeter of swimming pool is:

116 feet

To find the perimeter of the swimming pool, subtract twice the width of the 3 feet sidewalk from the total length and width of the area, which is 40 and 30 feet respectively. This gives you the length and width of the pool. Then, add these dimensions together and multiply by 2 to find the perimeter, which is 116 feet.

The subject of your question involves the concept of perimeter in math. To find the perimeter of the swimming pool itself, we need to subtract the width of the sidewalk from the total length and width measurements. Since the sidewalk is 3 feet wide and it is built around the pool, we need to account for this on both sides of the length and the width.

First, you subtract twice the width of the sidewalk from both the length and the width of the total area, which includes the pool and the sidewalk. So, the length of the pool would be 40 feet (total length) - 2*3 feet (two widths of the sidewalk) = 40 feet - 6 feet = 34 feet.

Similarly, the width of the pool would be 30 feet (total width) - 2*3 feet (two widths of the sidewalk) = 30 feet - 6 feet = 24 feet.

Then, you add the length and the width together and multiply by 2 to find the perimeter. The perimeter of the swimming pool would therefore be 2 * (34 feet + 24 feet) = 2 * 58 feet = 116 feet.

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Answer:

The future value = $1780

Step-by-step explanation:

* Lets explain the formula of the future value

- Future Value of an annuity is used to determine the future value of a

 stream of equal payments.

- The future value of an annuity formula can also be used to determine

  the number of payments, the interest rate, and the amount of the

  recurring payments

- The future value formula is [tex]FV=\frac{PMT}{i}(1-\frac{1}{(1+i)^{n}})[/tex]

 where:

# FV = Future Value of the annuity

# PMT= Payment amount  

# i = Annual interest rate  

# n = Number of payments

* Lets solve the problem

- n = 27

- i = 0.04

- PMT = $109

- To find FV lets use the formula above

∵ n = 27 , i = 0.04 , PMT = 109

∴ [tex]FV=\frac{109}{0.04}(1-\frac{1}{(1+0.04)^{27}})[/tex]

∴ [tex]FV=2725(1-\frac{1}{(1.04)^{27}})=1779.9248[/tex]

∴ FV = 1779.92 ≅ 1780

∴ The future value = $1780

The future value is calculated using the formula FV = PMT * [(1+i)^n - 1] / i. With a regular payment of $109, an interest rate of 0.04, and 27 periods, you can compute the future value.

The future value (FV) of an annuity can be calculated using the formula: FV = PMT * [(1+i)^n - 1] / i, where PMT is the regular payment, i is the interest rate, and n is the number of periods. In this case, the interest rate (i) is 0.04, the number of periods (n) is 27, and the regular payment (PMT) is $109. Plugging these values into the formula, we get FV = $109 * [(1+0.04)^27 -1] / 0.04. After performing these computations, you can find the future value (FV).

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Step-by-step explanation:

a). Let [tex]x^{2}+y^{2}=4[/tex]

     [tex]y^{2}=4-x^{2}[/tex]

Now since [tex]y^{2}[/tex] is a square of an integer, its value is [tex]\geq[/tex] 0.

Therefore, [tex]4-x^{2}[/tex] ≥ 0, since x is an integer

where [tex]4-x^{2}[/tex] = 1,2,3,...

and x = 1

But as x = [tex]\sqrt{2}, \sqrt{3}[/tex],... cannot be integer

∴ [tex]y^{2}=4-x^{2}[/tex]

   [tex]y^{2}=4-1[/tex]

   [tex]y = \sqrt{3}[/tex]

              = 1.732      which is not an integer

Thus, any positive integer cannot be written as the sum of the squares of the two integers.

b). Let n be an integer

∴ [tex]3(n^{2}+2n+3)-2n^{2}[/tex]

On solving we get,

 [tex]3n^{2}+6n+9-2n^{2}[/tex]

 [tex]n^{2}+6n+9[/tex]

 [tex]n^{2}+3n+3n+9[/tex]

 [tex]n(n+3)+3(n+3)[/tex]

  [tex](n+3)(n+3)[/tex]

  [tex](n+3)^{2}[/tex]

which is a perfect square

Hence proved.

Answer:

Step-by-step explanation:

a). Let

Now since  is a square of an integer, its value is  0.

Therefore,  ≥ 0, since x is an integer

where  = 1,2,3,...

and x = 1

But as x = ,... cannot be integer

∴

             = 1.732      which is not an integer

Thus, any positive integer cannot be written as the sum of the squares of the two integers.

b). Let n be an integer

∴

On solving we get,

which is a perfect square

Hence proved.

Explained the mean, median, and standard deviation for a sample of CFOs' salaries in the electronics industry.

Mean: To find the mean, you add up all the salaries and divide by the number of salaries. For the CFOs, the mean salary is $544,773.

Median: To find the median, you arrange the salaries in order and find the middle value. For the CFOs, the median salary is $546,000.

Standard Deviation: The standard deviation measures the dispersion of data. For the CFOs, you can calculate it using the given formula to be approximately $29,534.

Answer:

Is correct.

Step-by-step explanation:

If you don't write the n and t in the left part of the set (before the : ) we assume that are fixed.

(t, infinity) = {[tex]x \in \mathbb{R} : t<x<\infty, t\in \mathbb{R}[/tex]}

(0,1/n) =  {[tex]x \in \mathbb{R} : 0<x<\frac{1}{n}, n\in \mathbb{N}[/tex]}

Answer:

7.16.

Step-by-step explanation:

The variance is ∑ (x - m)^2 / N   and the standard deviation is the square root of this.

m is the mean of the data . Here it is  82.14.

Construct a table:

x    (x - m)     (x - m)^2

73    -9.14       83.54

76     -6.14      37.70

79      -3.14        9.86

82      -0.14        0.02

84       1.86        3.46  

84        1.86        3.46

97       14.86    220.82

Total:             358.86

Variance =  358.86 / 7 =  51.27

Standard deviation = √51.27 = 7.16.

Answer:

a) Confidence interval is (182.86,203.54).

b) (i) Yes, 200 bips is a true mean as it lie in the interval.

(ii) No, 210 bips is not a true mean as it doesn't lie in the interval.

Step-by-step explanation:

Given : A researcher studied the radioactivity of asbestos. She sampled 81 boards of asbestos, and found a sample mean of 193.2 bips, and a sample standard deviation of 49.5 bips.

To find : (a) Obtain the 94% confidence interval for the mean radioactivity. (b) (i) According the interval that you got, is 200 bips a plausible value for the true mean? (ii) What about 210 bips?

Solution :

a) The confidence interval formula is given by,

[tex]\bar{x}-z\times \frac{\sigma}{\sqrt{n}} <C.I<\bar{x}+z\times \frac{\sigma}{\sqrt{n}}[/tex]

We have given,            

The sample mean [tex]\bar{x}=193.2[/tex] bips

s is the standard deviation [tex]\sigma=49.5[/tex] bips

n is the number of sample n=81

z is the score value, at 94% z=1.88

Substitute all the values in the formula,

[tex]193.2-1.88\times \frac{49.5}{\sqrt{81}} <C.I<193.2+1.88\times \frac{49.5}{\sqrt{81}}[/tex]

[tex]193.2-1.88\times 5.5 <C.I<193.2+1.88\times 5.5[/tex]

[tex]193.2-10.34 <C.I<193.2+10.34[/tex]

[tex]182.86 <C.I<203.54[/tex]

Confidence interval is (182.86,203.54).    

b) (i) According the interval [tex]182.86 <C.I<203.54[/tex]

200 bips a plausible value for the true mean as it lies in the interval.

(ii) 210 bips not lie in the confidence interval so it is not a true mean.

To obtain the 94% confidence interval for the mean radioactivity, use the formula: CI = X ± (Z * σ / √n). The 94% confidence interval for the mean radioactivity is (181.05, 205.35). To determine if a value is plausible, check if it falls within the confidence interval.

To obtain the 94% confidence interval for the mean radioactivity, we'll use the formula:

CI = X ± (Z * σ / √n)

Where X is the sample mean, Z is the z-score corresponding to the desired confidence level, σ is the sample standard deviation, and n is the sample size.

For a 94% confidence level, the z-score is approximately 1.88. Plugging in the values:

CI = 193.2 ± (1.88 * 49.5 / √81) = 193.2 ± 12.15

The 94% confidence interval for the mean radioactivity is (181.05, 205.35).

(b) (i) To determine if 200 bips is a plausible value, we check if it falls within the confidence interval. Since 200 is within the interval (181.05, 205.35), it is a plausible value. (ii) Similarly, we check if 210 bips falls within the interval. Since 210 is not within the interval, it is not a plausible value.

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Answer:

Step-by-step explanation:

Answer: There are 676 three-letter strings that begin with J .

Step-by-step explanation:

The number of letters in  English Alphabet = 26

If first letter is fixed as J , then the number of ways to make 3 letters strings [repetition is allowed ] is given by :-

[tex]1\times26\times26=676[/tex]

(The first place is occupied by J and the rest of the two place has 26 ways of getting any letter)

Now, there are 676 three-letter strings that begin with J .

First solve the congruence [tex]13y\equiv1\pmod{330}[/tex]. Euclid's algorithm shows

330 = 25 * 13 + 5

13 = 2 * 5 + 3

5 = 1 * 3 + 2

3 = 1 * 2 + 1

=> 1 = 127 * 13 - 5 * 330

=> 127 * 13 = 1 mod 330

so that [tex]y=127[/tex] is the inverse of 13 modulo 330. Then in the original congruence, multiplying both sides by 127 twice gives

[tex]127^2\cdot13^2x\equiv127^2\cdot5^2\pmod{330}\implies x\equiv127^2\cdot5^2\equiv403,225\equiv295\pmod{330}[/tex]

Then any integer of the form [tex]x=295+330n[/tex] is a solution to the congruence, where [tex]n[/tex] is any integer.

Final answer:

Using the Chinese Remainder Theorem, the final solution to the congruence is x = 9 + 330k, where k is an integer.

Explanation:

To solve the congruence 169x ≡ 25 (mod 330), we can use the Chinese Remainder Theorem. First, we factor 330 into its prime factors: 330 = 2 × 3 × 5 × 11. Next, we solve the congruences 169x ≡ 25 (mod 2), 169x ≡ 25 (mod 3), 169x ≡ 25 (mod 5), and 169x ≡ 25 (mod 11) separately.

For the congruence 169x ≡ 25 (mod 2), since 169 ≢ 1 (mod 2), we can ignore it. For the congruence 169x ≡ 25 (mod 3), we can rewrite it as x ≡ 1 (mod 3). For the congruence 169x ≡ 25 (mod 5), we can rewrite it as 4x ≡ 0 (mod 5), and since gcd(5, 4) = 1, we can divide both sides by 4 to get x ≡ 0 (mod 5). Lastly, for the congruence 169x ≡ 25 (mod 11), we can rewrite it as 5x ≡ 3 (mod 11), and solve for x which will give us x ≡ 9 (mod 11).

Using the Chinese Remainder Theorem, we can combine these solutions to get x ≡ 9 (mod 330). Therefore, the solution to the congruence is x = 9 + 330k, where k is an integer.

Before you do anything, you have to find [tex]c[/tex] such that [tex]f_{X,Y}(x,y)[/tex] is a proper joint density function. Doing the math, you'll find that [tex]c=2[/tex].

Now, determine the marginal densities:

[tex]f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_{-x}^x2(x^2-y^2)e^{-2x}\,\mathrm dy[/tex]

[tex]\implies f_X(x)=\dfrac83x^3e^{-2x}[/tex]

[tex]f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\int_0^\infty2(x^2-y^2)e^{-2x}\,\mathrm dx[/tex]

[tex]\implies f_Y(y)=\dfrac12-y^2[/tex]

a. Then the density of [tex]X[/tex] conditioned on [tex]Y=y[/tex] is

[tex]f_{X\mid Y}(x\mid Y=y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\dfrac{4(x^2-y^2)e^{-2x}}{1-2y^2}[/tex]

b. The density of [tex]Y[/tex] conditioned on [tex]X=x[/tex] is

[tex]f_{Y\mid X}(y\mid X=x)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\dfrac{3(x^2-y^2)}{4x^3}[/tex]

and so the distribution of [tex]Y[/tex] conditioned on [tex]X=x[/tex] is

[tex]F_{Y\mid X}(y\mid X=x)=\displaystyle\int_{-\infty}^uf_{Y\mid X}(y\mid X=x)\,\mathrm du[/tex]

[tex]F_{Y\mid X}(y\mid X=x)=\begin{cases}0&\text{for }y<-x\\\frac{2x^3+3x^2y-y^3}{4x^3}&\text{for }-x\le y\le x\\1&\text{for }y>x\end{cases}[/tex]

To find the conditional probability density of X, given Y=y>0, use Bayes' theorem. To find the conditional probability distribution of Y, given X=x, integrate the joint density over the range of y values.

To find the conditional probability density of X, given Y=y>0, we need to calculate the conditional density fX|Y(x,y). This can be done using Bayes' theorem. First, find the marginal density of Y by integrating the joint density over the range of y values:

fY(y) = ∫f(x,y) dx = c(e^(-2y) - e^(-2y)/3)

Then, use Bayes' theorem to find the conditional density:

fX|Y(x,y) = f(x,y)/fY(y) = 4(x^2-y^2)e^(-2x)/(1-2y^2)

To find the conditional probability distribution of Y, given X=x, we need to calculate the conditional distribution FY|X(y|x). This can be found by integrating the joint density over the range of y values:

FY|X(y|x) = ∫f(x,y) dy = 3/4(x^2-y^2)

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Answer:

[tex]comp_{\vec{a}}\vec{b}=0.11 [/tex]

[tex]proj_{\vec{a}}\vec{b}=\left ( \frac{4}{81},\frac{7}{81},\frac{-4}{81} \right )[/tex]  

Step-by-step explanation:

a=(4,7,-4) b=(3,-1,1)

Scalar projection of b onto a

[tex]comp_{\vec{a}}\vec{b}=\frac{a\cdot b}{|a|}[/tex]

[tex]a\cdot b=\left ( 4\times 3 \right )+\left ( 7\times -1 \right )+\left ( -4\times 1 \right )=1[/tex]

[tex]|a|=\sqrt{4^2+7^2+4^2}=9[/tex]

[tex]comp_{\vec{a}}\vec{b}=\frac{a\cdot b}{|a|}=\frac{1}{9}\\\Rightarrow comp_{\vec{a}}\vec{b}=0.11 [/tex]

Vector projection of b onto a

[tex]proj_{\vec{a}}\vec{b}=\frac{a\cdot b}{|a|^2}\cdot a[/tex]

[tex]\frac{a\cdot b}{|a|}=\frac{1}{9}[/tex]

[tex]\frac{a\cdot b}{|a|^2}\cdot a=\frac{1}{81}\left ( {4},{7},{-4} \right )[/tex]

[tex]proj_{\vec{a}}\vec{b}=\left ( \frac{4}{81},\frac{7}{81},\frac{-4}{81} \right )[/tex]  

The scalar projection of vector b onto vector a is calculated as 1/9 and the vector projection is calculated as (4/81, 7/81, -4/81).

The scalar projection of vector b onto a is calculated as the dot product of b and a divided by the magnitude of a.

So, first we calculate a.b = (4*3) + (7*-1) + (-4*1) = 12 - 7 - 4 = 1.

The magnitude of a is the square root of the sum of squares of its components, √(4^2 + 7^2 + -4^2) = √81= 9.

Therefore, the scalar projection is 1/9.

For vector projection, we multiply the scalar projection by the vector a divided by its magnitude, essentially scaling the a vector by the scalar projection.

This gives us (1/9) * (4/9, 7/9, -4/9) = (4/81, 7/81, -4/81).

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Answer:

$3316 should be invested.

Step-by-step explanation:

Since, the amount formula in compound interest is,

[tex]A=P(1+r)^t[/tex]

Where, P is the principal amount,

r is the rate per period,

t is the time in years,

Here,

A = $ 60,000,

r = 10.5% = 0.105

t = 29 years,

By substituting value,

[tex]60000=P(1+0.105)^{29}[/tex]

[tex]P=\frac{60000}{1.105^{29}}=\$3316.23415377\approx \$3316[/tex]

Hence, $ 3316 should be invested.

Answer:  The probability that both televisions work : 0.5329

The  probability at least one of the two televisions does not​ work : 0.4671

Step-by-step explanation:

Given : The total number of television : 11

The number of defective television : 3

The probability that the television is defective : [tex]p=\dfrac{3}{11}\approx0.27[/tex]

Binomial distribution formula :-

[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where P(X) is the probability of getting success in x trials, p is the probability of success and n is the total trials.

If two televisions are randomly​ selected, then the probability that both televisions work:

[tex]P(0)=^2C_0(0.27)^0(1-0.27)^{2-0}=(1)(0.73)^2=0.5329[/tex]

The probability at least one of the two televisions does not​ work :

[tex]P(X\geq1)=1-P(0)=1-0.5329=0.4671[/tex]

Answer:

The surface area of a cone of radius r and height h not equal​ to one-third the surface area of a cylinder with the same radius and​ height.

Relationship is [tex]S_c=(\frac{\sqrt{(r+h)}}{2h})S_C[/tex]

Step-by-step explanation:

Given : The volume of a cone of radius r and height h is​ one-third the volume of a cylinder with the same radius and height.

To find : Does the surface area of a cone of radius r and height h equal​ one-third the surface area of a cylinder with the same radius and​ height?

If​ not, find the correct relationship. Exclude the bases of the cone and cylinder.

Solution :

Radius of cone and cylinder is 'r'.

Height of cone and cylinder is 'h'.

The volume of cone is [tex]V_c=\frac{1}{3}\pi r^2 h[/tex]

The volume of cylinder is [tex]V_C=\pi r^2 h[/tex]

[tex]\frac{V_c}{V_C}=\frac{\frac{1}{3}\pi r^2 h}{\pi r^2 h}[/tex]

[tex]V_c=\frac{1}{3}V_C[/tex]

i.e. volume of cone is one-third of the volume of cylinder.

Now,

Surface area of the cone is [tex]S_c=\pi r\sqrt{(r+h)}[/tex]

Surface area of the cylinder is [tex]S_C=2\pi rh[/tex]

Dividing both the equations,

[tex]\frac{S_c}{S_C}=\frac{\pi r\sqrt{(r+h)}}{2\pi rh}[/tex]

[tex]\frac{S_c}{S_C}=\frac{\sqrt{(r+h)}}{2h}[/tex]

[tex]S_c=(\frac{\sqrt{(r+h)}}{2h})S_C[/tex]

Which clearly means [tex]S_c\neq \frac{1}{3}S_C[/tex]

i.e. The surface area of a cone of radius r and height h not equal​ to one-third the surface area of a cylinder with the same radius and​ height.

The relationship between them is

[tex]S_c=(\frac{\sqrt{(r+h)}}{2h})S_C[/tex]

A counter example would be the number 2.

2 is a prime number, because it only has two factors ( itself and 1)

Yet 2 is also an even number, because it can be exactly divided by two.

So the number 2 proves that not every prime number is odd.

Answer:70

Step-by-step explanation:

Given

total of  7 friends need to be divided in two groups with 3 member each and  1 leader

leader can be chosen out of 7 person in [tex]^7C_1[/tex] ways

And 3 person out of remaining 6 persons in [tex]^6C_3[/tex] ways

thus a total of [tex] ^7C_1\times ^6C_3[/tex]  ways is possible

If order is not matter then

[tex]\frac{140}{2} [/tex] ways are possible